Abstract
Let X be a Tychonoff topological space, be the space of real-valued Baire 1 functions on X and be the topology of uniform convergence on compacta. The main purpose of this paper is to study cardinal invariants of . We prove that the following conditions are equivalent: (1) is metrizable; (2) is completely metrizable; (3) is Čech-complete; and (4) X is hemicompact. It is also proven that if X is a separable metric space with a non isolated point, then the topology of uniform convergence on compacta on is seen to behave like a metric topology in the sense that the weight, netweight, density, Lindelof number and cellularity are all equal for this topology and they are equal to . We find further conditions on X under which these cardinal invariants coincide on .
Keywords:
Baire 1 function; quasicontinuous function; topology of uniform convergence on compacta; density; weight; netweight; cellularity MSC:
54C35; 54C08; 54C30
1. Introduction
Let X be a topological space, be the space of continuous functions on X with values in , is a pointwise limit of a sequence from be the space of Baire 1 functions on X with values in . The research of Baire 1 functions began with Baire’s paper [] from 1899, which contains the results of their PhD thesis. Baire themselves conducted a detailed study of real Baire 1 functions on X when .
Let be the topology of uniform convergence on compacta. We prove that the following conditions are equivalent: (1) is metrizable; (2) is completely metrizable; (3) is Čech-complete; and (4) X is hemicompact.
Thus, if X is hemicompact, all cardinal invariants’ cellularity, density, net weight, spread, extent, Lindeloff number, -weight and weight coincide on . We find further conditions on X under which these cardinal invariants coincide on . If X is a separable metric space with a non isolated point, then the topology of uniform convergence on compacta on is seen to behave like a metric topology in the sense that the cellularity, density, net weight, spread, extent, Lindeloff number, -weight and weight are all equal for this topology and they are equal to . If X is an uncountable Polish space, then all these cardinal invariants coincide on and the same result holds also for the space of real-valued quasicontinuous functions.
2. Preliminaries
Denote by the set of positive integers and by the space of real numbers with the usual metric. Let be the space of all continuous functions from a topological space X into a topological space Y. The following notation is used: is a pointwise limit of a sequence from and is an set for every open . The elements of are called functions of the first Baire class, and those of ) are called functions of the first Borel class or measurable functions.
It is known that for any topological space X and any metric space Y []. If , then . An overview of the results regarding the equality can be found in papers [,].
Baire in [] proved that if X is an interval of reals and , then . Lebesgue in [] proved that if X is a metric space and , then .
The following result of Laczkowich will be useful in our paper.
Proposition 1.
[] Let X be a normal space and ; then, .
The following Theorem was proven by Lebesgue for .
Theorem 1.
(cf. (p. 375, []), []) Let X and Y be metric spaces. For , consider the following conditions:
- (1)
- A function f is measurable;
- (2)
- For each , there is a cover of X consisting of closed sets such that , for all .
Then, (2) ⇒ (1) holds. If Y is separable, then (1) ⇒ (2) is true.
Remark 1.
It is easy to verify that Theorem 1 works for any topological space X.
Let X be a Hausdorff topological space. Denote by the family of all nonempty compact subsets of X.
Denote by the topology of uniform convergence on compact sets on . This topology is induced by the uniformity which has a base consisting of sets of the form
where and . The general -basic neighborhood of will be denoted by , where
Denote by the topology of pointwise convergence on . This topology is induced by the uniformity which has a base consisting of sets of the form
where A is a finite set and . The general -basic neighborhood of will be denoted by , where
Of course, the topology of the pointwise convergence on is just the product topology on .
3. Complete Metrizability of
It is known [] that if X is a k-space, then the space of continuous real-valued functions defined on X is a closed set in . However, if X is not a k-space, then does not have to be closed in either.
Example 1.
Let be equipped with the discrete topology and be the Čech–Stone compactification of . Choose . Let and X has the topology inherited from . Every compact set in X is finite. X is not a k-space, since the set is not closed in X and is closed for every . For every , define as follows:
Of course, is a continuous function for every . Let be the function defined as:
It is easy to verify that f is not continuous and the sequence converges to f in . Thus, and is not closed in .
A topological space X is hemicompact [] if in the family of all compact subspaces of X ordered by inclusion there exists a countable cofinal subfamily. Every hemicompact space is -compact, but not vice versa. The space of rationals with the usual topology is a -compact space which is not hemicompact. A locally compact -compact space is hemicompact.
A Hausdorff space X is of pointwise countable type [] if for every point there exists a compact set such that and . Another one is the more general property of being a q-space. This is a space such that for each point there is a sequence of neighbourhoods of that point, so that if for each n, then has a cluster point [].
Since is a topological group, the equivalence 3 ⇔ 4 in the following theorem is known [].
Theorem 2.
Let X be a Tychonoff topological space. Then, the following are equivalent:
- 1.
- The uniformity on is induced by a metric;
- 2.
- The uniformity on is induced by a metric;
- 3.
- is metrizable;
- 4.
- is first countable;
- 5.
- is of pointwise countable type;
- 6.
- is a q-space;
- 7.
- X is hemicompact.
Proof.
Let be a countable cofinal subfamily in with respect to the inclusion. The family is a base of on . Since for every there is with , the family
is a countable base of . Thus, by the metrization theorem in [], is metrizable.
are obvious.
Suppose that is a q-space. Let f be the zero function on X. By assumption, there is a sequence such that if for each , then has a cluster point in . We claim that . Suppose that there is . For each , define a function as follows:
Then, for every ; however, cannot have a cluster point in .
Now, for every , put . We claim that is a cofinal family in with respect to the inclusion. Suppose that this is not true. Thus, there is such that for each there is . For every , let be such that and for every .
Of course, for every , . By assumption, has a cluster point . Then, for every , which is a contradiction since for every . □
Lemma 1.
Let X be a Tychonoff topological space. If a family in is totally bounded, then for every compact set A in X and every , there is a countable family of sets in X such that and for every and for every , diam.
Proof.
Since in is totally bounded, there are functions such that
Let be a countable open cover of , where the diameter of members of this cover is less than . For every , , put . Of course, is an set for every , .
Let be the family of all functions from to . Of course, is countable. For every , put For every , is an set.
Now, put
Of course, . Let ; then, there is such that and thus for every .
Finally, let and let . We show that diam. Let . There is a such that . Since is a subset of , there exists such that . Thus, and . Because , we have that and . Then,
□
Proposition 2.
Let X be a Tychonoff hemicompact topological space. Then, is a closed subset of .
Proof.
Let f be in the closure of in . By Theorem 2, is metrizable. Thus, there is a sequence in which converges to f in . Put . Let be a countable cofinal subfamily in . Let . Apply Lemma 1 on and on every and . For every , we obtain a countable family of sets in X such that , and for every and for every , diam. Put . Then, , is a countable family of sets in X and for every , diam for every . Since converges to f in , diam for every . By Remark 1, the function f is measurable. Since X is a normal space, by Proposition 1, . □
Theorem 3.
Let X be a Tychonoff topological space. Then, the following are equivalent:
- 1.
- is completely metrizable;
- 2.
- is Čech-complete;
- 3.
- X is hemicompact.
Proof.
is obvious. For , it is known that a Čech-complete space is a q-space. By Theorem 2 , X is hemicompact.
For , by Proposition 2, is a closed set in . Since the uniformity on is complete [], is completely metrizable. Thus, is completely metrizable too. □
4. Cardinal Invariants of
We first recall the definitions of cardinal invariants of a topological space Z []. Define the weight of Z as:
the density of Z as:
the cellularity of Z as:
and the network weight of Z as:
They are in general related by the inequalities
The character of a point z in Z is defined as:
and the character of Z is defined as:
To define the -character of Z, we first need a notion of a local -base. If , a collection of nonempty open subsets of Z is called a local -base at z provided that for each open neighborhood U of z, there exists a which is contained in U.
The -character of a point z in Z is defined as:
and the -character of Z is defined as:
To define the -weight of a topological space Z, we first need a notion of a -base. A collection of nonempty open subsets of Z is called a -base [] provided that for each open set U in Z, there exists a which is contained in U. Define the -weight of Z by:
The k-cofinality of a topological space Z is defined as
If , the topological space Z is hemicompact.
In what follows, let X be a Tychonoff topological space. We will consider the cardinal invariants of the space . Because of simplicity, the specification of the topology will be omitted. Since is a topological group, the character and the -character of and the weight and the -weight of coincide [].
First we prove that the character of is equal to the k-cofinality of a topological space X.
Theorem 4.
Let X be a Tychonoff topological space. Then, .
Proof.
First, we show that . It is easy to verify that . It is known that [].
To prove that , let and let be a cofinal subfamily of with . It is easy to verify that the family is a local base at f. □
For a Tychonoff space Z, define the uniform weight of Z []:
Remark 2.
Is known (see []) that , , where is the extent of Z defined as follows:
Theorem 5.
Let X be a Tychonoff topological space. Then, .
Proof.
Let be a cofinal family in such that . It is easy to verify that the family } is a base of the uniformity . Thus, . For every Tychonoff space Z, . Since by Theorem 4 , we have . □
Theorem 6.
If X is locally compact, then .
Proof.
By Remark 2
It suffices to show that . Because X is locally compact, it has a base of relatively compact sets such that . Then, the family of all finite unions of members of is cofinal in and has cardinality . So, . It is known that []. Since , we have □
In the following lemma, the notion of the discrete cellularity introduced in [] is used. To define the discrete cellularity of a topological space Z, we need a notion of a discrete family of subsets of Z. We say that a family of subsets of a topological space Z is discrete if each point has a neighborhood that meets at most one set of the family .
The discrete cellularity of Z is defined as:
Remark 3.
For every topological space Z, and [].
Lemma 2.
Let X be a Tychonoff topological space which contains an infinite compact set. Then, .
Proof.
Let K be an infinite compact set in X. There is a sequence of different points with a cluster point .
Let be disjont open sets such that and . There is such that . Let be disjont open sets such that , , and . Continuing this way, we can show that there is a pairwise disjoint sequence of open sets such that for every .
For every , choose a point . Let denote the set of all functions from to . For every , denote by the set of all where .
Let be such that .
Let be a continuous function defined as follows:
Let be such that . Define function as follows:
Then, is a continuous function.
Let be such that is infinite and let . For every , let .
For every , define . Let . Then, intersect at most one set of . So, is a discrete family of open subsets of , where by we mean the interior of in . □
For a topological space Z, define the Lindelöf degree of Z as:
and the spread of Z as:
If X is hemicompact, then by Theorem 2, is metrizable; thus, all cardinal invariants coincide on . The following theorem gives other conditions on X under which the cardinal invariants coincide on .
Theorem 7.
Let X be a Tychonoff topological space which contains an infinite compact set and let . Then,
Proof.
By Remark 2 and Theorem 5, . By Lemma 2 and Remark 3, . Since other cardinal invariants are between and e, the proof is finished. □
Corollary 1.
Let X be a separable metric space with a non isolated point. Then,
Proof.
Let be a non isolated point in X. Let be a sequence of different points in X which converges to . Then, the set is an infinite compact set in X. Since X is a separable metric space . Thus, by Theorem 7
Since and , the proof is finished. □
Corollary 2.
For every , put . Let be the topological sum of the family . Then,
5. Comparison of Cardinal Invariants of , and for an Uncountable Polish Space
Proposition 3.
Let X be an uncountable Polish space. Then,
Proof.
X is a separable metric space. By Corollary 6.5 in [], X contains a homeomorphic copy of the Cantor space . Let C be a homeomorphic copy of . Then, every point of C is a non isolated point. We can apply Corollary 1. □
Let X and Y be topological spaces. A function is quasicontinuous [] at if for every open set and every open set , there is a nonempty open set such that . If f is quasicontinuous at every point of X, we say that f is quasicontinuous. A survey on quasicontinuous functions can be found in a recent monograph []. Denote by the space of real-valued quasicontinuous functions.
Proposition 4.
Let X be an uncountable Polish space. Then, .
Proof.
If X is an uncountable Polish space, then by Corollary 6.5 in [], X contains a homeomorphic copy of the Cantor space . Using some ideas from [], put
It is easy to verify that F is a closed nowhere dense set in with the cardinality . Thus, X contains a compact nowhere dense set C with a cardinality homeomorphic to F. Using Lemma 6 in [], if X is a pseudometrizable space and C is a closed nowhere dense subset of X, there is a continuous function such that in every neighbourhood V of there are with and . For every subset D of C, define a function as follows: for every , for and for . It is easy to verify that is a quasicontinuous function. For every subset D of C, define . Then, subset of C} is a discrete family of nonempty open sets in with the cardinality . Thus, . □
Proposition 5.
[] Let X be a topological space which contains an infinite compact set and let . Then,
Theorem 8.
Let X be an uncountable Polish space. Then,
Proof.
Use Propositions 4 and 5. □
If X is a topological space with a countable base, then, by [], . Thus, for an uncountable Polish space X, we have
and by [],
If X is not hemicompact, then ; thus, the topology of uniform convergence on compacta on may not behave like a metric topology. The space of irrational numbers equipped with the usual Euclidean topology is an uncountable Polish space, which is not hemicompact.
6. Conclusions and Future Work
The main purpose of this paper is to study cardinal invariants of real-valued Baire 1 functions equipped with the topology of uniform convergence on compacta and compare them with the cardinal invariants of the space of continuous real-valued functions equipped with the topology of uniform convergence on compacta, which were studied in [], and also compare them with the cardinal invariants of the space of quasicontinuous real-valued functions equipped with the topology of uniform convergence on compacta, which were studied in []. We proved that the following conditions are equivalent: (1) is metrizable; (2) is completely metrizable; (3) is Čech-complete; and (4) X is hemicompact.
Thus, if X is hemicompact, all cardinal invariants’ cellularity, density, netweight, spread, extent, Lindeloff number, -weight and weight coincide on . We found further conditions for X under which these cardinal invariants coincide on . If X is a separable metric space with a non isolated point, then the topology of uniform convergence on compacta on is seen to behave like a metric topology in the sense that the cellularity, density, netweight, spread, extent, Lindeloff number, -weight and weight are all equal for this topology and they are equal to . If X is an uncountable Polish space, then all these cardinal invariants coincide on and the same result holds also for the space of real-valued quasicontinuous functions.
We used the usual methods of topology and set theory in the proofs. The theory developed in this paper could be of interest to mathematicians working in fields including topology and functional analysis.
Concerning a future investigation of the space of Baire 1 functions, we plan to study cardinal invariants of equipped with the topology of pointwise convergence and compare them with the cardinal invariants of the space of continuous real-valued functions equipped with the topology of pointwise convergence, which were studied in [].
Author Contributions
Writing—original draft preparation, Ľ.H. and D.H. All authors have read and agreed to the published version of the manuscript.
Funding
This research was funded by Vega 2/0048/21 and APVV 20-0045.
Data Availability Statement
Data sharing is not applicable to this article as no datasets were generated or analyzed during the preparation of the paper. The article describes entirely theoretical research. All results obtained in the paper are original.
Conflicts of Interest
The author declares no conflicts of interest. The funders had no role in the design of the study; in the collection, analyses, or interpretation of data; in the writing of the manuscript; or in the decision to publish the results.
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