Abstract
For k-Riemann–Liouville fractional integral operators, the Hermite–Hadamard inequality is already well-known in the literature. In this regard, this paper presents the Hermite–Hadamard inequalities for k-Riemann–Liouville fractional integral operators by using a novel method based on Green’s function. Additionally, applying these identities to the convex and monotone functions, new Hermite–Hadamard type inequalities are established. Furthermore, a different form of the Hermite–Hadamard inequality is also obtained by using this novel approach. In conclusion, we believe that the approach presented in this paper will inspire more research in this area.
Keywords:
Hermite–Hadamard inequality; convex functions; green functions; k-Riemann–Liouville fractional operators MSC:
26D15; 26D10; 26A51; 26A33; 41A55
1. Introduction
Convex functions are different from other function classes in that they have many applications in the fields of mathematics, statistics, optimization theory, and applied sciences; and their definition has a geometric interpretation. Additionally, it is one of the fundamental components of inequality theory and has evolved into the main motivating element behind several inequalities. Although there are many areas of mathematical analysis and statistics where convex functions can be applied, the inequality theory has shown to be the most significant one. In this regard, a number of traditional and analytical inequalities, particularly Hermite–Hadamard-, Ostrowski-, Simpson-, Fejér-, and Hardy-type inequalities, have been established [1,2,3].
The definition of the convex function is:
Definition 1.
A function is said to be convex if
holds for all and .
The Hermite–Hadamard inequality, which is the main result of convex functions’ widespread application and excellent geometrical interpretation, has received a lot of attention in fundamental mathematics. Recent years have seen a rapid development in the theory of inequality [4,5,6]. Important inequalities, such as the Hermite–Hadamard inequality, are one of the most important reasons for this development. It is worth reflecting on the fact that the theories of inequality and convexity are closely related to one another. In recent years, several new extensions, generalizations, and definitions of novel convexity have been given, and parallel developments in the theory of convexity inequality, particularly integral inequalities theory, have been emphasized. The Hermite–Hadamard inequality is formally expressed as follows:
Let be a convex function of the interval I of real numbers and with
The inequality in (1) will hold in reverse directions if is a concave function. The Hermite–Hadamard inequality, which is based on geometry, gives an upper and lower estimate for the integral mean of any convex function defined in a closed and limited domain, which includes the endpoints and midpoint of the domain of the function. Due to the significance of this inequality, several variations of the Hermite–Hadamard inequality have been examined in the literature for various classes of convexity, including harmonically convex, exponentially convex, s-convex, h-convex, and co-ordinate convex functions [7,8,9,10].
Inequalities involving fractional integrals are a special focus of the calculus of non-integer order, widely known as fractional calculus. This subject deals with the generalization of integrals and derivative operators. Several definitions are used for fractional integral operators, such as Hadamard integral, the k-Riemann–Liouville fractional integral, Caputo–Fabrizio fractional integral, Riemann–Liouville fractional integral, and conformable fractional integral [11,12,13,14]. By adding new parameters to such fractional integral operators, one can generalize the fractional operators, yielding to the following inequalities: Ostrowski, Grüss, Minkowski, Hermite–Hadamard, and others [15,16,17]. Such generalizations inspire future research to present more novel ideas with unified fractional operators and obtain inequalities involving such generalized fractional operators. In many different branches of research, inequalities relating to fractional integral operators have many practical applications. The theory of fractional calculus is also essential in the solution of many other special function problems, including those involving the solution of integral-differentiable equations, differential equations, and integral equations.
To obtain some remarks and corollaries, it is important for us to remember the preliminary formulae and notations of some well-known Riemann–Liouville and k-Riemann–Liouville fractional integral operators.
Several varieties of fractional integrals have been described in the literature; the most traditional are the Riemann–Liouville fractional integrals, which are defined as follows:
Definition 2
([18]). Let The Riemann–Liouville integrals and of order with are defined by
and
respectively, where Here is
In the case of , the fractional integral reduces to the classical integral.
In [6], Sarıkaya et al. proved the following Hadamard-type inequalities for fractional integrals as follows:
Theorem 1.
Let be a positive function with and If ψ is a convex function on , then the following inequalities for fractional integrals hold:
with
In [19], the k-Gamma function and its properties were introduced by Diaz et al. as follows:
Definition 3.
For , the k-Gamma function is given by
Definition 4.
Let . Then, the k-Gamma function is defined by the following integral form:
Proposition 1.
The k-Gamma function satisfies the following properties:
1.
2.
3.
Theorem 2
([14]). The k-Riemann–Liouville integrals and of order with are defined by
and
The following Hadamard-type inequalities for k-fractional integrals were established by Farid et al. in [20].
Theorem 3.
Let be a positive function with and If ψ is a convex function of , then the following inequalities for k-fractional integrals hold:
with
A different form of Hadamard’s inequality is given in the following theorem:
Theorem 4
([21,22]). Let be positive mapping with and If ψ is a convex function of , then
with
The fact that k-fractional integrals generalize certain varieties of fractional integrals, such as the Riemann–Liouville fractional integral, is their most important component. One may check contemporary publications and books for further information [17,23,24,25,26,27,28]. As a result, in recent years, these fractional operators have been investigated and utilized to expand inequalities of the Hadamard, Grüss, Minkowski, Chebychev, and Pólya–Szegö kinds.
This article aims to present a novel approach to obtain the Hermite–Hadamard inequalities using the k-Riemann–Liouville fractional operator. By using the Green function in this approach, we are able to get several identities involving the k-Riemann–Liouville fractional integral operators. Additionally, we get new Hermite–Hadamard-type inequalities by applying these identities to the convex and monotone functions. Finally, using this novel approach, a different form of the Hermite–Hadamard inequality is obtained.
2. Main Results
In [29], Mehmood et al. established the following Lemma, which will be used to prove our main results:
Lemma 1.
Let and G be the Green function defined on by
Then, any can be expressed as
Proof.
The above equation can be easily obtained by employing the methods of integration by parts in So, the details of the proof are left to interested readers. □
The following theorem gives the Hermite–Hadamard inequality for k-fractional operators. The Hermite–Hadamard inequality has been proved by many researchers for different operators and many new inequalities have thus been obtained. Additionally, many important inequalities have also been established in the theory of inequality using Green’s functions (see [25,26,30,31,32,33]).
Theorem 5.
Let If ψ is a convex function of then we have the following inequalities:
which is the well-known Hermite–Hadamard inequality for k-fractional operators with .
Proof.
Substituting in identity (2), we have
Also, using identity (2), the following calculations are performed:
Hence,
Similarly,
Therefore,
According to the Green function’s definition,
we obtain
and
So, we take
Additionally, note that
This demonstrates that is decreasing. As a result, for all , from .
On the other hand, if then
Therefore,
which demonstrates that is decreasing and and so Consequently, is increasing and Hence, for all Moreover, because is convex.
Taking into account the two situations mentioned above, we may conclude that for all .
The first inequality is derived from (10), as follows:
For the right-hand side of the Hermite–Hadamard inequality, we recall
Let From the above identity, we have
When we set
then, for we obtain
If then we get
which proves that ℑ is increasing. and so we obtain
Similarly, if we take we have
This suggests that ℑ is a decreasing function and and consequently Moreover, because is convex.
Taking into account the two situations mentioned above, we may conclude that for all .
The second inequality is obtained from (10), as follows:
That completes the proof. As a result, Hermite–Hadamard inequality for the k-fractional integral operator is proven again. □
Theorem 6.
Let and . As a result, the following arguments are true:
1 If we choose an increasing function of then we have
2 If we choose a decreasing function of then we have
3 If is a convex function of then
Proof.
Taking absolute values and using triangle inequality on the above identity, utilizing simple calculations, we obtain
So, the inequality of (14) is established. It can be easily determined using the same procedure for inequality (15). Also, to obtain the inequality of (16), we utilize the fact that the convex function is bounded above by since it is defined on the interval As a result, we obtain the inequality (16) from (10) as follows:
□
Remark 1.
In Theorem 6, if we choose then we obtain Theorem 7 in [25].
Theorem 7.
Let and . Then, the following arguments are true:
1 If we choose an increasing function of then we have
2 If we choose an decreasing function of then we have
3 If is a convex function on then
Proof.
which is the required result. □
Taking absolute values on both sides of the above identity and using triangle inequality and as an increasing function, we obtain
Thus, the inequality of (17) is established. The inequality (18) can be determined in a similar way. Finally, for inequality (19), we make use of (13) and the fact that every convex function defined on the interval is bound above by to have
Remark 2.
In Theorem 7, if we take then we have Theorem 5 in [25].
Theorem 8.
Let and . If is a convex function of then we have the following inequalities:
Proof.
Using identity (10), we have
Setting where after some calculation, then we have
In Equation (20), taking the absolute value on both sides and using the convexity of we get
If the necessary simple calculations are made, the desired result is obtained. That is:
□
Remark 3.
By setting in Theorem 8, then we find the result presented (Theorem 9) in [25].
Theorem 9.
Let and . If is a convex function of then we obtain the following inequalities:
Proof.
We begin by recalling the identity given in (13) as follows:
By taking and with we get
If we take the absolute value on both sides and use the convexity of then
which is our required inequality. Thus, the proof is completed. □
Remark 4.
Letting in Theorem 9 gives Theorem 11 in [25].
Theorem 10.
Let and If ψ is a convex function of then we have the following inequalities:
Proof.
First of all, from Definition 2 and utilizing identity (2), we can do the following calculations
Therefore,
In the same way,
Therefore,
So, we take
According to the Green function’s definition, we can write:
and
Hence, if we choose in (25), then we obtain
On the other hand, if we choose in Equation (25), then we have
Since is a convex function of ; therefore, and by using (26) and (27) in (25), we get
which is the left half inequality of (21).
Next, we prove the right half inequality of (21). For this purpose, we take in Equation (2), and we have
When we set
then for we obtain
Therefore
which proves that is increasing. and so we have
Similarly, if we take we get
Hence
This suggests that is a decreasing function and and consequently
Taking into account the two situations mentioned above, we may conclude that for all . Also, because is convex.
Finally, we arrive at the required result. As a result, it is demonstrated that the Hermite–Hadamard inequality for the k-fractional integral operator is a special case. □
3. Conclusions
In this article, we presented a new method to prove the Hermite–Hadamard inequality using the k-Riemann–Liouville fractional integral operators, based on a Green’s function and obtained some new identities for convex and monotone functions. Also, using this new method, a different form of the Hermite–Hadamard inequality was obtained. In particular, we found that utilizing this new approach and the other Green’s functions―G2, G3 and G4 in [29]–different types of integral inequalities can be obtained. In addition to these identities, researchers can also obtain new inequalities for the q-th power of different convexities by using the Hölder and Power-mean inequalities or others (In particular, Theorem 10 can be used). Using this method, new and different identities can be obtained for concave functions. We believe that the new consequences and methods presented in this work will encourage researchers to investigate a more interesting sequel in this field.
Author Contributions
Conceptualization, Ç.Y. and L.-I.C.; Methodology, Ç.Y. and L.-I.C.; Validation, Ç.Y.; Formal analysis, Ç.Y.; Investigation, Ç.Y. and L.-I.C.; Resources, Ç.Y. and L.-I.C.; Writing—original draft, Ç.Y. and L.-I.C.; Writing—review & editing, Ç.Y. and L.-I.C.; Visualization, Ç.Y. and L.-I.C.; Supervision, Ç.Y.; Project administration, Ç.Y. and L.-I.C. All authors have read and agreed to the published version of the manuscript.
Funding
This research received no external funding.
Data Availability Statement
Not applicable.
Conflicts of Interest
The authors declare no conflict of interest.
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