Abstract
A locally irregular graph is a graph in which the end vertices of every edge have distinct degrees. A locally irregular edge coloring of a graph G is any edge coloring of G such that each of the colors induces a locally irregular subgraph of G. A graph G is colorable if it allows a locally irregular edge coloring. The locally irregular chromatic index of a colorable graph G, denoted by , is the smallest number of colors used by a locally irregular edge coloring of G. The local irregularity conjecture claims that all graphs, except odd-length paths, odd-length cycles and a certain class of cacti are colorable by three colors. As the conjecture is valid for graphs with a large minimum degree and all non-colorable graphs are vertex disjoint cacti, we study rather sparse graphs. In this paper, we give a cactus graph B which contradicts this conjecture, i.e., . Nevertheless, we show that the conjecture holds for unicyclic graphs and cacti with vertex disjoint cycles.
  1. Introduction
All graphs mentioned in this paper are considered to be simple and finite. An edge coloring of a graph is neighbor sum distinguishing if any two neighboring vertices differ in the sum of the colors of the edges incident to them. This notion was first introduced in [] and the following conjecture was proposed there.
Conjecture 1 
(1-2-3 Conjecture). Every graph G without isolated edges admits a neighbor-sum-distinguishing edge coloring with the colors .
This conjecture attracted a lot of interest [,,,,] and for a survey we refer the reader to []. The best upper bound is that every graph without isolated edges admits a neighbor-sum-distinguishing edge coloring with five colors [], but the 1-2-3 Conjecture remains open.
This variant of edge coloring and the 1-2-3 Conjecture motivated the introduction of similar variants of edge coloring. A locally irregular graph is any graph in which the two end vertices of every edge differ in degree. A locally irregular k-edge coloring, or k-liec for short, is any edge coloring of G with k colors such that every color induces a locally irregular subgraph of G. This variant of edge coloring was introduced in []. A third related edge coloring variant is the neighbor multiset-distinguishing edge coloring, where neighboring vertices must have assigned distinct multisets of colors on incident edges. In [], it was established that every graph without isolated edges admits the neighbor multiset-distinguishing edge coloring with four colors. Notice that every locally irregular edge coloring is also a neighbor multiset-distinguishing edge coloring, but the reverse does not have to hold. In order to see that the reverse does not hold, consider the following graph with its edge coloring: G is a 2-path  and edges  and  are colored by 1 and 2, respectively. This is obviously not a locally irregular edge coloring but it is a neighbor multiset-distinguishing edge coloring as  are the (multi)sets of colors at vertices a, b, c, respectively.
In this paper, we focus our attention on locally irregular edge colorings exclusively, and we say a graph is colorable if it admits such a coloring. The locally irregular chromatic index of a colorable graph  denoted by , is the smallest k, such that G admits a k-liec. In [], the family of graphs  has been defined as follows:
- contains the triangle ;
 - if G is a graph from , then a graph H obtained from G by identifying a vertex of degree which belongs to a triangle of with an end-vertex of an even length path or with an end vertex of an odd-length path such that the other end vertex of that path is identified with a vertex of a triangle, also belongs to .
 
Note that every graph  has an odd size. A cactus graph is any graph in which cycles are pairwise edge disjoint. Notice that  is a special family of cacti. Additionally, if we imagine triangles to be vertices and paths attached to vertices of a triangle as edges, we might informally say that G has tree-like structure. For the sake of simplicity, we define a broader family  as the family obtained from  by introducing to it all odd-length paths and all odd-length cycles. Notice that  is a subclass of vertex-disjoint cactus graphs. It was established in [] that a connected graph G is not colorable if and only if . Additionally, the following conjecture on the irregular chromatic index was proposed.
Conjecture 2 
(Local Irregularity Conjecture). For every connected graph , it holds that 
Let us mention some of the results related to Conjecture 2. For general graphs it was first established  [], then it was lowered to  []. For some special classes of graphs Conjecture 2 is shown to hold, namely for trees [], graphs with minimum degree at least  [], k-regular graphs where  [].
In this paper we will show that every unicyclic graph G which does not belong to  admits a 3-liec, thus establishing that Conjecture 2 holds for unicyclic graphs. We will further extend this result to cactus graphs with vertex-disjoint cycles. Finally, we will provide an example of a colorable graph B with  showing that Conjecture 2 does not hold in general.
2. Revisiting the Trees
Since a unicyclic graph is obtained from a tree by adding a single edge to it, we first need to introduce the notation and several important results for trees from []. Additionally, we will establish several auxiliary results for trees, which will be useful throughout the paper.
First, a shrub is any tree rooted at a leaf. The only edge in a shrub G incident to the root we will call the root edge of G. An almost locally irregular k-edge coloring of a shrub  or k-aliec for short, is an edge coloring of G which is either k-liec or a coloring in which only the root edge is not locally irregular (notice that in this case the root edge is an isolated edge of its color, i.e., it is not adjacent to any other edge of the same color). A proper k-aliec is k-aliec which is not a k-liec. The following results for trees were established in [].
Theorem 1. 
Every shrub admits a 2-aliec.
Theorem 2. 
For every colorable tree  it holds that  Moreover,  if 
If an edge coloring uses at most three colors, we will denote those colors by  A 1-liec (resp. 2-liec, 3-liec) of a graph G will be denoted by  (resp. ). A 2-aliec of a shrub G will be denoted by  where a is the color of the root edge in G. Let  be four colors, if  is a 2-liec of G in colors a and  then 2-liec  of G in colors c and d is obtained from  by replacing colors a and b for c and d respectively, i.e.,  if and only if  Particularly, 2-(a)liec  is called the inversion of the 2-(a)liec  where colors a and b are replaced. Moreover, let  be an edge coloring of a graph , for  and let these graphs be pairwise edge disjoint, i.e.,  for any two distinct i and j. For a graph G such that  by  we will denote the edge coloring of G such that an edge e is colored by  if and only if 
For any color of the edge coloring  say a, we define the a-degree of a vertex  as the number of edges incident to v which are colored by a. The a-degree of a vertex v is denoted by  Assume that a vertex  has k neighbors  such that each  is colored by  Then, the sequence  is called the a-sequence of the vertex v. We usually assume that neighbors of v are denoted so that the a-sequence is non-increasing.
Throughout the paper we will use the technique of finding a 2-liec for trees introduced in []. Namely, if T is a tree with maximum degree 5 or more, then T admits a 2-liec according to Theorem 2. Otherwise, if the maximum degree of T is at most  let v be a vertex from T and  all the neighbors of v for  Notice that T consists of k shrubs  starting at  let  denote a shrub with the root edge  and let  denote a 2-aliec of  which exists according to Theorem 1. Recall that  for every  The coloring  is called a shrub-based edge coloring of  We say that a shrub-based coloring  is inversion resistant if neither  is a 2-liec of T nor any of the colorings which can be obtained from  by color inversion in some of the shrubs  Let us now introduce the following lemma which stems from the technique used in [].
Lemma 1. 
Let T be a tree with  and v a vertex from T of degree  Let  be all the shrubs of T rooted at v and let  be a 2-aliec of  If  is a 2-liec of  for every  then the shrub-based coloring  can be inversion resistant in two cases only:
- If and the a-sequence of v by is ;
 - If and the a-sequence of v by is .
 
Proof.  
If  then the shrub-based coloring of T equals  which is 2-liec. If  then  would be a 2-liec of 
If  then the a-degree of v by  is  and inverting colors in one of the shrubs would decrease the a-degree of v to 2. Therefore, the a-sequence of v by  must contain 3 and  Considering the two possibilities  and , we see that  would be 2-liec in both of them. The only remaining possibility is  and it is inversion resistant.
Finally, assume  By a similar consideration as above, we see that the a-sequence of v by  must contain   and  Therefore, we must consider the possibilities  then  then  It is easily seen that only in the case , the shrub-based coloring  is inversion resistant.    □
A spidey is a tree with radius at most two which consists of a central vertex u of degree at least 3 and the remaining vertices have degree at most 2 and are at distance at most 2 from u. Notice that every spidey is locally irregular, hence it admits a 1-liec. We say that a vertex v of a spidey G is a short leg if it is a leaf which is a neighbor of the central vertex of 
Lemma 2. 
Let H be a spidey with a short leg v and let K be a tree. Let G be a graph obtained from H and K by identifying the vertex v with a vertex from  Then, G admits a 3-liec such that all edges of  are colored by a same color.
Proof.  
  
    
      
      
    
  
  
  
    
      
      
    
  
  
Since H is a spidey, H admits a 1-liec, say . Assume first that a tree K is not colorable, i.e., K is an odd-length path. This implies there exists in K an edge  incident with v, such that  is a collection of even paths which, therefore, admits 2-liec  The edge coloring  of G defined by
        
      
        
      
      
      
      
    
        is a 3-liec of 
Assume now that K is a colorable tree. If K admits a 2-liec  then  is a 3-liec of G with the desired property. So, we may assume K is a colorable tree which does not admit a 2-liec. Theorem 2 implies  Let  and let  be all the shrubs of K rooted at  By Theorem 1, each shrub  admits a 2-aliec  where without loss of generality we may assume that  is a proper 2-aliec if and only if  We distinguish the following four cases with respect to 
- Case 1: Notice that and If and then would be a 2-liec of a contradiction. Otherwise, the shrub-based coloring would be a 2-liec of again a contradiction.
 - Case 2: If then is a 2-liec of a contradiction. If then is a 2-liec of a contradiction. If then let be all the neighbors of v in The shrub-based coloring is not a 2-liec only if the a-degree of or by is Without loss of generality we may assume that a-degree of by is but then is a 2-liec of a contradiction.
 - Case 3: In this case, is the only shrub with a proper 2-aliec Let be the neighbor of v in we define the coloring of K as followsNotice that is not a liec of but is a 3-liec of with the desired property that all edges of H are colored by a same color, in this case c.
 - Case 4: Notice that in this case Lemma 1 applies on K and Therefore, the only cases when K does not admit a 2-liec are: i) and the a-sequence of v by the shrub-based coloring is or ii) and the a-sequence of v by is In the first case the coloring is a 3-liec of G such that is colored by the same color c, as it is illustrated in Figure 1. In the other case, the coloring is a 3-liec of G such that is colored by a same color, as it is illustrated in Figure 2. □
 
      
    
    Figure 1.
      A graph  and a vertex v of degree 3 in  (a) the coloring  is not a 3-liec of G; (b) the coloring  is a 3-liec of 
  
      
    
    Figure 2.
      A graph  and a vertex v of degree 4 in  (a) the coloring  is not a 3-liec of G, (b) the coloring  is a 3-liec of 
  
3. Unicyclic Graphs
In this section, we will establish Conjecture 2 for unicyclic graphs. It is already known that there exist colorable unicyclic graphs which do not admit 2-liec, but require three colors in order for edge coloring to be locally irregular, namely cycles of length  for . We will show that such cycles are not an isolated family of unicyclic graphs that require three colors. The main result for unicyclic graphs is established through the following two lemmas in which we will consider separately cases whether the cycle of G is a triangle or not.
Lemma 3. 
Let G be a unicyclic graph with the unique cycle being a triangle. If  then 
Proof.  
Let  be the triangle in G, let  denote the connected component of  which contains  Since  there must exist a vertex  on C such that  is not a pendant even length path, say it is  Let  and let  First notice that both  and  are trees and that  Since  is not a pendant path of even length, it follows that  is not an odd length path, hence it is colorable. Let  be a 3-liec of  Without loss of generality we may assume that  Let H be the subgraph of  induced by all edges incident to  in  We may assume  for every  namely if  this follows from the local irregularity of  otherwise, it follows from Lemma 2 applied on H and every component of  repeatedly.
Let us now consider the graph  and notice that it is a shrub rooted at  with the root edge  By Theorem 1 there exists a 2-aliec  of  If  is a 2-liec, then  is a 3-liec of G. Additionally, if  is a proper 2-aliec of , then  is colorable and let  be a 3-liec of  such that  for every edge  by Lemma 2. We define the edge coloring  of G as follows
        
      
        
      
      
      
      
    
		It is easily seen that  is a 3-liec of     □
Let us now consider unicyclic graphs with larger cycles.
Lemma 4. 
Let G be a unicyclic graph with the unique cycle being of length at least four. If  then 
Proof.  
If G is a cycle, then  implies that G is an even-length cycle and hence admits a 3-liec. So, we may assume G is not a cycle, i.e., at least one vertex from the cycle of G is of degree at least three. Denote the cycle in G by  with  Without loss of generality we may assume that  is the vertex with maximum degree among vertices from  We distinguish the following two cases with respect to 
- Case 1: Let denote the set of all edges incident to in G except the edge and let H denote the subgraph of G induced by The assumption implies so H is a spidey in which every leg is short. Let be the connected component of which contains and let Let be all connected components of Each is a tree, so Lemma 2 can be applied to H and for every . We conclude that there exists a 3-liec of such that for every On the other hand, is a shrub rooted at with the root edge so admits 2-aliec according to Theorem 1.
 
If  is a 2-liec of  then  is a 3-liec of  Additionally, if  is a proper 2-aliec of , then  is colorable and let  be a 3-liec of  such that  for every edge  by Lemma 2. We define the edge coloring  of G as follows
        
      
        
      
      
      
      
    
		It is easily seen that thus defined  is a 3-liec of 
- Case 2: Let be the set of all edges incident to in G and H a subgraph of G induced by Let be the connected component of which contains and let Similarly as in the previous case, there exists a 3-liec of such that for every Notice that since is the vertex with maximum degree among vertices from Now we distinguish two possibilities with regard to
 
If  then  is a shrub rooted in  with the root edge  According to Theorem 1, there exists a 2-aliec  of  If  is 2-liec of  then  is a 3-liec of  Otherwise,  defined by
        
      
        
      
      
      
      
    
        is a 3-liec of 
If  then consider  to be a tree rooted at  which consists of two shrubs  and  the first with the root edge  and the other with the root edge  where  is the only neighbor of  which does not belong to the cycle C. Theorem 1 implies that there exist 2 aliecs  and  of  and  respectively. If both  and  are a 2-liec of the respective shrub, then  is a 3-liec of  If both  and  are a proper 2-aliec of the respective shrub, then  is a 3-liec of  The only remaining possibility is that precisely one of  and  say , is a proper 2-aliec of the respective shrub. In this case we define the coloring  of  as follows
        
      
        
      
      
      
      
    
		Since  it is easily seen that  is a 3-liec of     □
The previous two lemmas yield the following result.
Theorem 3. 
Let G be a unicyclic graph. If  then 
A natural question that arises is whether the bound  is tight, i.e., are there colorable unicyclic graphs which are not 2-colorable. The family of cycles of length  are such graphs, but this family is not an isolated case, there exist other unicyclic graphs which require three colors, for example, the graph from Figure 3. One can assure infinitely many such graphs, for example, by taking longer threads of suitable parity in the given graph.
      
    
    Figure 3.
      A colorable unicyclic graph distinct from cycle which requires 3 colors for locally irregular edge coloring.
  
4. Cacti with Vertex Disjoint Cycles
In this section, we will extend the result from the previous section to cacti with vertex disjoint cycles. We will also show that the result does not extend to all cacti by providing an example of a cactus graph with four cycles which is colorable, but requires 4 colors for a locally irregular edge coloring. This establishes that Conjecture 2 does not hold in general. We first need to introduce several useful notions in order to deal with cacti.
Let G be a cactus graph with at least two cycles, let C be a cycle in G and let u be a vertex from  We say that u is a root vertex of C if the connected component of  which contains u is a cyclic graph. A cycle C of G is a proper end cycle if  contains at most one cyclic connected component. Every cactus graph with vertex disjoint cycles contains at least two proper end cycles, given it is not a unicyclic graph.
Theorem 4. 
Let G be a cactus graph with vertex disjoint cycles. If  then 
Proof.  
The proof is by induction on the number of cycles in  If G is a unicyclic graph, then the claim holds by Theorem 3. Assume that the claim holds for all cacti with fewer than p cycles, where . Let G be a cactus graph with p cycles. We will show that G admits a 3-liec and this will establish the claim of the theorem. Let C be a proper end cycle of G,  the root vertex of  and v the only neighbor of  which belongs to the cyclic component of  Denote the other neighbors of  by  so that  and  belong to the cycle C. In what follows, we distinguish two cases.
		
- Case 1:. Let be the connected component which does not contain v and let Let and
 
Suppose first that  is colorable. Then, it admits a 3-liec  where the edges  and  must be colored by a same color, say color c. Notice that  is a shrub rooted at  with the root edge  By Theorem 1,  admits a 2-aliec . If  is a 2-liec of , then  is a 3-liec of  Otherwise, if  is a proper 2-aliec of  then the restriction of  to  is a 2-liec of that graph. Notice that  does not belong to , so it is colorable and by induction hypothesis it admits a 3-liec  in which edges  and  must be colored by a same color (say color c) since  Now, we infer that
        
      
        
      
      
      
      
    
        is a 3-liec of G.
Suppose now that  is not colorable. Assume first  is not colorable. Notice that  is a unicyclic graph, so if the cycle of  is a triangle, then the assumption that  and  are not colorable would imply , a contradiction. Otherwise, if  is a unicyclic graph on a larger cycle, then it is not colorable only if it is an odd-length cycle. In this case let w be the only neighbor of  distinct from  let  and  Notice that by induction hypothesis  is colorable and admits a 3-liec  for which we may assume  and  Additionally, notice that  is an even length path, so it admits a 2-liec  where we may assume that the edge of  incident to  is colored by  Then  is a 3-liec of 
Suppose now that  is colorable. Since  is not colorable, the edge  of  must belong to an even length path hanging at a vertex of a triangle in  so the graph  contains an odd-length path hanging at a vertex of a triangle, which means  so it is colorable. Therefore, by induction hypothesis  admits a 3-liec  Since  is a leaf in , we may assume that  By Theorem 3,  admits 3-liec  Since the degree of  in  equals two, we may assume that the colors of edges  and  are from  Therefore,  is a 3-liec of G.
		
- Case 2: Let H be the subgraph of G induced by the set of all edges incident to in Denote the connected components of in the following way, let be the component which contains v and the component which contains and . Additionally, let and We may assume is colorable, as otherwise G would contain a proper end cycle which is a triangle with the root vertex of degree 3, which would reduce to the previous case. Let and
 
Suppose first that the tree  is not colorable. This implies that it is an odd-length path. Notice that  as a shrub rooted at  admits a proper 2-aliec  and since it is proper we have  Since  is colorable, by induction hypothesis it admits a 3-liec  where we may assume  Since  is a shrub rooted at  with the root edge  it admits a 2-aliec  If  is a proper 2-aliec of , then
        
      
        
      
      
      
      
    
        is a 3-liec of  Otherwise, if  is a 2-liec of  then let us consider the graph  It is colorable by the same argument as  so it admits a 3-liec  in which  and  must be colored by a same color, say c. Then
        
      
        
      
      
      
      
    
        is a 3-liec of 
Suppose now that  is a colorable tree, so it admits a 3-liec  We may assume that  for every  as this follows either from  or from Lemma 2 applied to  as a spidey and every connected component of  as K. As for  recall that it is colorable, so by induction hypothesis, it has a 3-liec . Since  is a leaf in  we may assume  Let us now consider the graph  Recal that it is a shrub rooted at  with the root edge  Hence, by Theorem 1 the graph  admits a 2-aliec  If  is a 2-liec of  then  is a 3-liec of  Otherwise, we define , and notice that  is a spidey. According to Lemma 2, the graph  admits a 3-liec  such that  for every  We conclude that
        
      
        
      
      
      
      
    
        is a 3-liec of     □
Let us now consider the so called bow-tie graph B shown in Figure 4. This is a cactus graph with four cycles, but in which cycles are not vertex disjoint. This graph is colorable and admits the 4-liec shown in Figure 4, but it does not admit a k-liec for  since the two end vertices of the cut edge must have the degree three in the color of that edge. Hence, for the bow-tie graph B it holds that  We conclude that Conjecture 2 does not hold in general.
      
    
    Figure 4.
      The bow-tie graph B and a 4-liec of it.
  
The consideration of the bow-tie graph gives rise to the following questions: are there any other graphs for which Conjecture 2 does not hold, do all colorable cacti admit a 4-liec, what is the thight upper bound on  of general graphs? We believe the following conjecture holds, which is a weaker form of the Local Irregularity Conjecture.
Conjecture 3. 
Every connected graph G which does not belong to  satisfies 
5. Concluding Remarks
It was established in [] that a graph does not admit a locally irregular edge coloring if and only if it belongs to the family . Additionally, it was further conjectured that all other graphs admit a locally irregular 3-edge coloring, see Conjecture 2. As the conjecture is valid for graphs with large minimum degree and all non-colorable graphs are vertex disjoint cacti, we took direction to study cacti.
In this paper we first consider trees to obtain an auxiliary result, then we considered unicyclic graphs and we established that every unicyclic graph  admits a locally irregular 3-edge coloring as Conjecture 2 claims. Moreover, we have remarked that the bound 3 is tight also on a family of unicyclic graphs, distinct from cycles of the length , for which it was previously known.
We further extended the result to cacti with vertex disjoint cycles, showing that Conjecture 2 also holds for this class of graphs. Then we gave the so called bow-tie graph B in which cycles are not vertex disjoint, which is colorable and admits a 4-liec, but it does not admit a locally irregular 3-edge coloring. This graph is a counterexample for Conjecture 2. So the conjecture does not hold in general, but possibly this is a lonely counterexample. We concluded the paper by conjecturing that all colorable graphs admits a locally irregular 4-edge coloring.  
Author Contributions
Conceptualization, J.S. and R.Š.; methodology, J.S. and R.Š.; investigation, J.S. and R.Š.; writing—original draft preparation, J.S.; software, R.Š. All authors have read and agreed to the published version of the manuscript.
Funding
Both authors acknowledge partial support of the Slovenian research agency ARRS program P1-0383, ARRS projects J1-1692 and J1-3002. The first author also the support of Project KK.01.1.1.02.0027, a project co-financed by the Croatian Government and the European Union through the European Regional Development Fund—the Competitiveness and Cohesion Operational Programme.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Conflicts of Interest
The authors declare no conflict of interest.
References
- Karoński, M.; uczak, T.; Thomason, A. Edge weights and vertex colours. J. Combin. Theory Ser. B 2004, 91, 151–157. [Google Scholar] [CrossRef] [Green Version]
 - Addario-Berry, L.; Dalal, K.; McDiarmid, C.; Reed, B.A.; Thomason, A. Vertex-Colouring Edge-Weightings. Combinatorica 2007, 27, 1–12. [Google Scholar] [CrossRef]
 - Kalkowski, M. A Note on 1,2-Conjecture. Manuscript. Ph.D. Thesis, Adam Mickiewicz University, Poznan, Poland, 2009. [Google Scholar]
 - Przybyło, J. The 1-2-3 Conjecture almost holds for regular graphs. J. Combin. Theory Ser. B 2021, 147, 183–200. [Google Scholar] [CrossRef] [Green Version]
 - Przybyło, J.; Woźniak, M. On a 1,2 Conjecture. Discrete Math. Theor. Comput. Sci. 2010, 12, 101–108. [Google Scholar]
 - Wang, T.; Yu, Q. On vertex-coloring 13-edge-weighting. Front. Math. China 2008, 3, 581–587. [Google Scholar] [CrossRef]
 - Seamone, B. The 1-2-3 Conjecture and Related Problems: A Survey, Technical Report. 2012. Available online: http://arxiv.org/abs/1211.5122 (accessed on 15 September 2021).
 - Kalkowski, M.; Karoński, M.; Pfender, F. Vertex-coloring edge-weightings: Towards the 1-2-3-conjecture. J. Combin. Theory Ser. B 2010, 100, 347–349. [Google Scholar] [CrossRef] [Green Version]
 - Baudon, O.; Bensmail, J.; Przybyło, J.; Woźniak, M. On decomposing regular graphs into locally irregular subgraphs. Eur. J. Combin. 2015, 49, 90–104. [Google Scholar] [CrossRef]
 - Addario-Berry, L.; Aldred, R.E.L.; Dalal, K.; Reed, B.A. Vertex colouring edge partitions. J. Combin. Theory Ser. B 2005, 94, 237–244. [Google Scholar] [CrossRef] [Green Version]
 - Bensmail, J.; Merker, M.; Thomassen, C. Decomposing graphs into a constant number of locally irregular subgraphs. Eur. J. Combin. 2017, 60, 124–134. [Google Scholar] [CrossRef] [Green Version]
 - Lužar, B.; Przybyło, J.; Soták, R. New bounds for locally irregular chromatic index of bipartite and subcubic graphs. J. Comb. Optim. 2018, 36, 1425–1438. [Google Scholar] [CrossRef] [Green Version]
 - Baudon, O.; Bensmail, J.; Sopena, É. On the complexity of determining the irregular chromatic index of a graph. J. Discret. Algorithms 2015, 30, 113–127. [Google Scholar] [CrossRef]
 - Przybyło, J. On decomposing graphs of large minimum degree into locally irregular subgraphs. Electron. J. Combin. 2016, 23, 2–31. [Google Scholar] [CrossRef] [Green Version]
 
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