Abstract
We characterize the boundedness and compactness of dual Toeplitz operators on the orthogonal complement of the generalized Fock space. We study the problem when the finite sum of the dual Toeplitz products is compact. Additionally, we also consider when the sum of the dual Toeplitz operators is equal to another dual Toeplitz operator.
MSC:
47B35; 32A37
1. Introduction
For any integer , let be the complex d-space and let be the ordinary volume measure on . For points and in , we write and Let be the family of all holomorphic functions on . Given the real numbers and , the Lebesgue measure is defined by
where is the normalizing constant so that is a probability measure on . Let be the space of measurable functions , such that
The generalized Fock space is denoted by . In particular, is the Fock space when (see [1]). is a Hilbert space under the inner product
For any , there exists a constant C, such that
according to [2] (Corollary 2.9), which implies that each point evaluation is bounded on . Thus, for each , there exists a unique reproducing kernel function , such that
for every . The orthogonal projection is defined by
where is the reproducing kernel in .
For multi-index , we write and . We also write for . Since the weight depends only on , the monomials form an orthogonal basis in . Its integration into spherical coordinates gives
Then, the set is an orthonormal basis for . Using the theory from Aronszajn [3] to compute the reproducing kernel of , we obtain
Given and , as a consequence of [4] (Corollary 2.11), we obtain the following useful estimate
for the positive constants and .
Let be the set of all bounded functions in with a compact support on ; it is easy to show that is dense in by using a similar argument to [5]. Let ; we define the dual Toeplitz operator with the symbol as follows:
where I is the identity operator. If is bounded, then is bounded on . However, may not be bounded when the symbols are more general or even densely defined on . To ensure that the product of two dual Toeplitz operators is well defined, for a given , let be the space of all Lebesgue measurable functions on , such that
Let , and suppose that and for some . By calculating (3), we have
for some positive constant K.
Furthermore, we obtain ; this implies that , and then, is well defined as a function in . Hence, for and , the product is densely defined on and can be expressed as
Let
be the the symbol space. Under pointwise multiplication, becomes an algebra.
Dual Toeplitz operators have been widely studied on the orthogonal complement of classical function spaces. For example, in the Bergman space over the unit disk setting, Stroethoff and Zheng [6] first studied the algebraic and spectral properties of the dual Toeplitz operator. Also, they characterized commuting dual Toeplitz operators. Yu and Wu [7] studied commuting dual Toeplitz operators with harmonic symbols on the orthogonal complement of the Dirichlet space. Chen, Yu and Zhao [8] characterized when two dual Toeplitz operators are commuting and semi-commuting on the orthogonal complement of the harmonic Dirichlet space, where the spectral properties of these operators were also studied. Later, their results were extended to a multiple-variable situation. Kong and Lu [9] characterized the algebraic properties of dual Toeplitz operators on Bergman spaces on a unit ball. Furthermore, they studied when the sum of the products of two dual Toeplitz operators is equal to a dual Toeplitz operator, which yielded the results mentioned above concerning the commutativity or product problem. Ding, Wu and Zhao [10] performed complete characterization for the hyponormality of dual Toeplitz operators with bounded harmonic symbols on the orthogonal complement of the Bergman space over an open unit disk. Lee [11] characterized when the finite sum of products of two dual Toeplitz operators is equal to zero on the orthogonal complement of the Dirichlet space. The corresponding problem for dual Toeplitz operators on the Hardy–Sobolev space and Fock space has also been studied (see [12,13]). For more details on the study of dual Toeplitz operators, please refer to [6,14,15,16,17].
At the beginning of this century, some scholars began to pay attention to the structure of the generalized Fock space and its operators. Bommier-Hato, Engliš and Youssfi [18] proposed criteria for determining the boundedness of the associated Bergman-type projections on the generalized Fock space over . Schneider [19] studied Hankel operators with anti-holomorphic -symbols on generalized Fock spaces in one complex dimension. Bommier-Hato [20] studied the algebraic properties of the Toeplitz operator on the generalized Fock space over . For more details on the generalized Fock space, we refer to [2,21,22,23].
Motivated by the above results, in this paper, we consider similar problems on the orthogonal complements of the generalized Fock space , where m is a positive real number. We generalize the results of [12] to the generalized Fock space . That is, we mainly characterize the finite sum of dual Toeplitz products in another dual Toeplitz operator.
Our main results are as follows.
Theorem 1.
Let be pluriharmonic for and . Then, if and only if if and only if one of the following statement holds:
- (a)
- for all ;
- (b)
- for all ;
- (c)
- There exists for with for all and
The organization of this paper is as follows. In Section 2, the boundedness and compactness of the dual Toeplitz operators are characterized, and the necessary condition for the finite sum of the products of two dual Toeplitz operators to be compact is also considered. Section 3 studies the zero sums of the products of two dual Toeplitz operators with pluriharmonic symbols.
2. Boundedness and Compactness
In this section, we characterize the boundedness and compactness of dual Toeplitz operators with symbols in .
Let , define a function on
where is the Euclidean ball in centered at with radius s, and denotes the characteristic function of . is usually called test function. Set
For each and , by applying the Cauchy–Schwarz inequality, we determine that
and it follows that converges to 0 weakly in as 0. For , the multiplication operator is defined by for .
Lemma 1.
With the notations above, we have and
for and for each .
Proof.
For each , we have
which implies that , and so, . We next show that the limit
holds. Using [24] (Proposition 1.4.9), we determine that
for the constant . Hence,
Let
We determine that the complement set of is a set of measure zero according to Theorem 8.8 of [25].This finishes the proof. □
Given , we define the Hankel operators and with and . The following lemma will be useful in our characterization for the boundedness and compactness of the dual Toeplitz operator.
Lemma 2.
For , we have
for .
Proof.
Note that
for each . Thus,
According to (3), we have
for each . Based on this assumption, we obtain
Therefore,
for each , and this implies that
for by using Lemma 1. □
Recall that is the space of measurable functions f on , such that
Now, we are ready to characterize the boundedness of dual Toeplitz operators on .
Theorem 2.
If , then is bounded on if and only if . In which case, we have .
Proof.
If , then . Suppose that is bounded on . Note that
for all and . Letting and using Lemma 2, we have
for , so that
This completes the proof. □
Corollary 1.
If , then is compact on if and only if .
Corollary 2.
If , then on if and only if .
We consider the relation between the compactness of the finite sums of finite dual Toeplitz products and their symbols.
Theorem 3.
Let for . If is compact on , then .
Proof.
If the dual Toeplitz operators are closely related to Hankel operators, we have
Lemma 2 and (3) determine that
for each . Hence,
for . This means that
according to Lemma 1 again. This completes the proof. □
As a simple application of Theorem 3, we determine that a product of several dual Toeplitz operators with harmonic symbols can be compact only in a trivial case. For harmonic functions for which , at least one must be zero.
Corollary 3.
Let be harmonic; then, the following conditions are equivalent:
- (a)
- is compact;
- (b)
- ;
- (c)
- for some t.
Let denote the space of all linear bounded operators on , and be the set of all operators of the form , where is an integer, and . It follows from Lemma 2 that
for every and .
Lemma 3.
Let for . Then,
for some .
Proof.
As mentioned above, the result is true for . Now, suppose the result holds for ; then,
for some . Note that . □
Proposition 1.
Let . If is compact, then .
Proof.
According to Lemma 3, we have
for some . For , converges to 0 weakly in as . Combining the assumption, Lemma 2, and equality (5), we obtain
□
Remark 1.
The above conclusion holds for bounded symbols. However, we do not know whether it is true for the symbol in .
3. Zero Sum of Products of Dual Toeplitz Operators
In this section, we consider the finite sum of the products of two dual Toeplitz operators on the generalized Fock space, determine when such an operator equals zero, and obtain several applications. Recall that a complex-valued function on is said to be pluriharmonic when its restriction to an arbitrary complex line is harmonic as a function of one complex variable. It is well known that each pluriharmonic function can be decomposed as for some . For the two multi-indices and , the notation denotes that for all . For we assume that .
The following proposition will be very useful in our analysis later on.
Proposition 2.
Let be pluriharmonic. Then, the following statements are equivalent:
- (1)
- for every ;
- (2)
- ;
- (3)
- is constant.
Proof.
It is trival that condition . We are going to prove that . First, assume that holds and write for some . For a multi-index j, we let , where B is the unit ball in . Then, and for every j with . Thus, for every j with . We let be its Taylor series. According to (1) and (2), we have
for every j with and . Thus, for any given j with , the above shows that for every with , which means that for every . So, we determine that holds. Suppose that condition holds. Using (3), for all . It follows that
for every . This shows that (1) holds. □
We let
for .
We now prove the main result of this section.
Proof of Theorem 1.
Write for some . Using (4), we obtain
for every . We note that
according to (1) and (2) for each k. Then, according to Theorem 3, we see that if and only if and holds. Thus, in order to complete the proof, it is sufficient to show that , and are all equivalent.
Implication . By taking in , we determine that holds.
Equivalence . We see from [17] (Theorem 3.2) that holds if and only if there exists for , such that for all and
for all . Writing and for each k, we note that (7) is equivalent to
for each l and all . According to Proposition 2, we know that (8) is equivalent to
for each l. Note that and for each k, so (9) is equivalent to . Hence we conclude that .
Implication . Suppose now that holds. From Proposition 2 and for all , we see that
for all , which shows that holds. This completes the proof of the theorem. □
We now have several consequences of Theorem 1. Firstly, in the special case when , we obtain a more concrete solution in the next corollary. In the course of the proof, we use the well-known complexification lemma:
Lemma 4.
Let Ω be a domain in and assume that Φ is holomorphic on , where . If for all , then on .
Corollary 4.
Let be pluriharmonic and . Then on if and only if and one of the following conditions holds:
- (I)
- ;
- (II)
- ;
- (III)
- ;
- (IV)
- ;
- (V)
- and for some constant .
Proof.
According to Theorem 1, it suffices to prove that of Theorem 1 holds if and only if one of holds. According to Lemma 4, we determine that of Theorem 1 holds if and only if
for all and . First, suppose that (10) holds. Recall that for a pluriharmonic function , if and only if . If , then , and together with (10), we determine that either or for all . Thus, the first case implies that , and hence, holds. According to Proposition 2, the second one implies that holds. Still, if , then for all according to Proposition 2 again, and or holds based on a similar argument.
Next, assume that are not holomorphic. Then, and for some and . According to (10), we have and for all and , where
Therefore, for all and . Notice that according to (10). So, and according to Proposition 2. If , then holds. If , then holds.
For the converse implication, we assume that holds. Then, we use Proposition 2 to determine that (10) holds. □
As a simple application of Corollary 4, we characterize the commutativity of dual Toeplitz operators with pluriharmonic symbols.
Corollary 5.
Let be pluriharmonic. Then, on if and only if one of the following conditions holds:
- (I)
- ;
- (II)
- ;
- (III)
- There exist constants , not both 0, such that is constant on .
Proof.
We take and in Corollary 4, as desired. □
Corollary 6.
Let be pluriharmonic. Then, on if and only if f is constant.
If we take in Corollary 4, we obtain the following corollary.
Corollary 7.
Let be pluriharmonic and . Then on if and only if , and either or .
Author Contributions
Resources, B.X.; Writing—original draft, B.X.; Writing—review & editing, J.D. and C.M.; Funding acquisition, C.M. All authors have read and agreed to the published version of the manuscript.
Funding
This work was supported by the National Natural Science Foundation of China (No. 12161077), the Innovation Fund Project of University in Gansu Province (No. 2021B-192, No. 2021QB-109).
Data Availability Statement
Data are contained within the article.
Conflicts of Interest
The authors declare no conflicts of interest.
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