Abstract
In the present paper we give conditions under which there exists a unique weak solution for a nonlocal equation driven by the integrodifferential operator of fractional Laplacian type. We argue for the optimality of some assumptions. Some Lyapunov-type inequalities are given. We also study the continuous dependence of the solution on parameters. In proofs we use monotonicity and variational methods.
1. Introduction
In this paper, we study the existence of a unique solution to a nonlocal equation
where is a bounded domain with Lipschitz boundary and is a function verifying some suitable conditions. The integrodifferential operator of fractional Laplacian type is defined pointwise by
where the kernel satisfies the following:
- (K1)
- where ;
- (K2)
- there exist and such that for all
A typical example for K is given by . In this case is the so-called fractional Laplacian operator which, up to multiplying by a suitable constant, has the following property:
For this fact and more details on the fractional Laplacian, see [1]. Let us also mention some important works concerning problems with the integrodifferential operator of fractional Laplacian type (i.e., [2,3,4,5,6]).
Recently, a great deal of attention has been focused on the study of non-local elliptical operators, both for pure mathematical research and in view of concrete applications, since these operators arise quite naturally in many different contexts, such as the thin obstacle problem [7], optimization [8], finance [9], phase transitions [10], stratified materials [11], anomalous diffusion [12], crystal dislocation [13], semipermeable membranes and flame propagation [14], conservation laws [15], ultra-relativistic limits of quantum mechanics [16], quasi-geostrophic flows [17], multiple scattering [18], minimal surfaces [19], materials science [20], and water waves [21]. These applications force us to follow Courant and Hilbert (see ([22], p. 227)): “A mathematical problem which is to correspond to physical reality should satisfy the following basic requirements: (1) The solution must exist. (2) The solution should be uniquely determined. (3) The solution should depend continuously on the data (requirement of stability).” In this work we will meet all the above requirements. First we give stipulations on the source f under which the problem has exactly one weak solution. In the proof we use the Minty–Browder theorem. We show that some monotonicity conditions on the source f are optimal. To the best of our knowledge, there are no such optimal results for nonlocal problems. Our approach is based on the work [23]. As a byproduct we obtain some Lyapunov-type inequalities. Next, we show continuous dependence of the solution on parameters. In proofs we use monotonicity and variational methods (see [24,25,26]).
2. Preliminaries
To define our solution space , we define the fractional Sobolev space
where and we restrict it to the subspace
which is a separable Hilbert space under the norm
induced by the inner product
We denote by the topological dual of The critical exponent is defined as , and the embedding is continuous for all and compact for all For define a constant
Here denotes the standard norm in
An element is called a weak solution of problem (1) if where for some and we have
for all .
3. Uniqueness
Now we present conditions under which the problem (1) has exactly one weak solution. Recall that is a Carathéodory function if is continuous for a.a. and is measurable for all For let be such that Note that if then We impose the following assumptions on function :
- (F)
- There exist and such thatfor a.a. and all ;
- (A)
- There exists a measurable such thatfor a.a. and all .
Remark 1.
If the function is a -Carathéodory function, that is, is of class for a.a. and are measurable for all then the inequality (3) is equivalent to
for a.a. and all
Theorem 1.
Let be a Carathéodory function satistying (F) and (A) with such that
where the constant is defined in (2) and . Then the problem (1) has a unique weak solution in and its norm satisfies the following estimation from above
Moreover, if then the constant in (4) is optimal in the sense that there exists with such that the problem (1) with has at least two weak solutions.
Proof.
Clearly, the weak solvability of the problem (1) is equivalent to the solvability of equation in where is defined by
for all Here, denotes the duality brackets for the pair . Note that the second part in the definition of T can be represented in the form where is continuous embedding, is the Nemytskii map, which is continuous by assumption (F) and ([27], Proposition 2.76), and denotes the duality brackets for the pair Hence, the operator T is well defined and continuous.
Now, assumption (A) with the Hölder inequality gives
for all This and (4) show that T is strongly monotone, and so T is strictly monotone and coercive (see ([24], p. 501). Then the equation has a unique solution by the Minty–Browder theorem (see ([24], Theorem 26A)). Moreover, putting in (6) and since we obtain
which gives (5).
Now, let Then Define by
Then Let be a minimizing sequence. Since is homogeneous of degree 0, we can assume without loss of generality that
as Hence, is bounded in Thus we can choose a subsequence (denoted again by the same symbol ) and a function such that in and strongly in The strong convergence in gives us The weak convergence in implies
Then is a minimizer of
Clearly, also minimizes the differentiable functional defined by
Thus for all that is,
for all If we put for all , then is a nontrivial weak solution for problem (1) with for all and . Moreover, Since now the problem (1) is linear, the zero function is a second solution. This proves the theorem. □
Remark 2.
Let us note that if we want to obtain a unique solution by using monotonicy methods with the Minty–Browder theorem, then the operator related to our problem must be strictly monotone, coercive, and continuous. For the operator to be well defined and continuous, we need the assumption (F) that is optimal. For strict monotonicity and coercivity, we need the source f to increase linearly at most, where the coefficient may depend on x. If we treat this coefficient as a function in we have obtained the optimal bound on its p-norm with . Note also that, if with then f satisfies (F) with and which belongs to
Theorem 1 allows us to give Lyapunov-type inequalities for a linear problem
that is, a necessary condition on a for the existence of a non-trivial solution u to the problem (7).
Corollary 1.
Let and If problem (7) has a non-trivial solution, then
and the inequality is optimal if . Moreover, if and M is any positive number, then there exists such that and problem (7) has only a trivial solution.
Proof.
By the first part of Theorem 1, if a in problem (7) satisfies then there is exactly one solution to (7), so it is a trivial one. The optimality follows from the second part of Theorem 1. Now fix and take any Next, choose From properties of Lebesgue spaces we can find a function such that and With such a function, (7) has only trivial solution, by Theorem 1. □
In the notation of [28], we can present this result as follows. For put
and for define the value
Now Corollary 1 takes the following form.
Corollary 2.
Let
- 1.
- ;
- 2.
- for ;
- 3.
- for
Now, applying ([29], Theorem 3.3) we have an estimate from below for with and :
where C depends only on and and is the inner radius of , that is, This and Corollary 2 give us an estimate from below for :
where
If we consider problem (7) driven by the Laplacian operator, is a ball and , then for by ([30], Theorem 2.5). A natural question then arises.
Open problemIs it true thatforand? What is the value offorand?
Remark 3.
Similarly to two-point boundary value problems (see [31]), we say that problem (1) across many resonant points if and the range of , the derivative of f with respect to the second argument, contains many eigenvalues of the differential operator of the problem. By Theorem 1, we can find problems (1) with unique solution, across as many resonant points as we wish. Indeed, for any finite set of eigenvalues we can find containig in its range this set of eigenvalues and such that for some and so problem (7) with this a has a unique weak solution.
4. Continuous Dependence on Parameters
In this section we consider a problem with parameters. For a fixed set and put
The set will be termed the set of admissible parameters. Consider the following problem, which is subject to a parameter
where is a Carathéodory function, that is, is continuous in for a.a. and measurable in x for each
An element is a weak solution of problem (8) if
for all .
We need to modify assumptions (A) and (F) in the following way:
- (Fw)
- There exist and such thatfor a.a. and all
- (Aw)
- There exist a measurable such thatfor a.a. and all .
Note that if f satisfies assumptions () and (), then for a fixed parameter the function f satisfies (F) and (A), and so the problem (8) has a unique weak solution , by Theorem 1. In this case we say that the solution u corresponds to the parameter So, assuming () and (), we define a single-valued solution operator which assigns to any parameter the unique weak solution of problem (8). If is considered to be endowed with the relative topology induced from the topology on we can formulate the following theorem on continuous dependence on parameters.
Theorem 2.
Assuming () and () with such that , the solution operator is continuous.
Proof.
Let be a sequence of admissible parameters convergent in to and let be the unique solution to problem (8) corresponding to the parameter that is, for each Choose any subsequence of . To the end, it is enough to show that has a convergent subsequence.
First, we show that is bounded in . For any define by
that is, the operator defined in the proof of Theorem 1. We have since is the weak solution corresponding to parameter Clearly, for each fixed parameter w, () implies (F), so we can use the proof of Theorem 1. So, using (6) with and we obtain
The boundedness of implies the boundedness of in Hence has a subsequence, denoted again by weakly convergent to some that is,
Since the embedding is compact, we have—up to a subsequence—that
and there exists such that, almost everywhere on and (see ([32], Lemma A.1)). Moreover, since in we have, up to a subsequence, and for a.a. and some Considering all this and our assumptions, we obtain
and
Thus
by Lebesgue’s dominated convergence theorem. A similar argument gives
for all Now, since is the weak solution to problem (8) with parameter we have
for all and all Hence
for all by (9) and (11). This means that is the weak solution to problem (8) corresponding to parameter So by the uniqueness. Next, putting in (12), in (13), and using (10), we obtain
as Additionally, since weakly converges to and is the Hilbert space, we obtain strongly in . This proves the theorem. □
5. Conclusions
In this paper, we discussed the existence of the unique solution for the nonlocal equation, driven by the integrodifferential operator of fractional Laplacian type. We met the Hilbert and Courant requirements which demand not only the existence and uniqueness of the solution but also its continuous dependence on the date. We achieved this by imposing some monotonicity conditions on the source, which are optimal. Applying the obtained result to linear problem (7) led us to the necessary condition for the existence of a non-trivial solution, that is, the Lyapunov-type inequality, which estimates from below for . We also showed that by estimating the p-norm of a from below for we cannot obtain sufficient conditions for the existence of a non-trivial solution. We left as an open problem (with some suggestions for answers) what can be said in the situation when resp.
Funding
This research received no external funding.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Conflicts of Interest
The author declares no conflict of interest.
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