Abstract
We study the influence of a unit Killing vector field on geometry of Riemannian manifolds. For given a unit Killing vector field on a connected Riemannian manifold we show that for each non-constant smooth function there exists a non-zero vector field associated with f. In particular, we show that for an eigenfunction f of the Laplace operator on an n-dimensional compact Riemannian manifold with an appropriate lower bound on the integral of the Ricci curvature gives a characterization of the odd-dimensional unit sphere . Also, we show on an n-dimensional compact Riemannian manifold that if there exists a positive constant c and non-constant smooth function f that is eigenfunction of the Laplace operator with eigenvalue and the unit Killing vector field satisfying and Ricci curvature in the direction of the vector field is bounded below by is necessary and sufficient for to be isometric to the sphere . Finally, we show that the presence of a unit Killing vector field on an n-dimensional Riemannian manifold with sectional curvatures of plane sections containing equal to 1 forces dimension n to be odd and that the Riemannian manifold becomes a K-contact manifold. We also show that if in addition is complete and the Ricci operator satisfies Codazzi-type equation, then is an Einstein Sasakian manifold.
1. Introduction
Killing vector fields are known to play vital role in influencing the geometry as well as topology of Riemannian manifolds (see [1,2,3,4,5,6,7,8,9,10]) and being incompressible fields play important role in physics (see [11]). If we restrict the length of a Killing vector fields such as constant length, then it severely restricts the geometry of Riemannian manifolds on which they are set. For instance, there are no unit Killing vector fields on even-dimensional spheres . However, there are unit Killing vector fields on odd-dimensional spheres as well on odd-dimensional ellipsoids (see [4,12,13]). Most importantly, on all K-contact manifolds there is a unit Killing vector field called the Reeb vector field (see [12,13]). There are other important structures and special vector fields, which also influence the geometry of a Riemannian manifold (see [14]).
In this paper, we are interested in studying the impact of presence of a unit Killing vector field on the geometry of a connected Riemannian manifold . Our first interesting finding is that for each smooth non-constant function f on M, there is naturally associated a non-zero vector field on M that is orthogonal to (see Proposition 1). Then we consider the associated vector field corresponding to eigenfunction f of Laplace operator on a compact Riemannian manifold corresponding to eigenvalue and show that if the integral of Ricci curvature in the direction of is bounded below by certain bound, forces to be odd and thus gives a necessary and sufficient for to be isometric to the unit sphere (see Theorem 1). A similar characterization of the sphere using the eigenfunction f on a compact n-dimensional with eigenvalue is obtained (see Theorem 2).
Given a unit Killing vector field on a connected Riemannian manifold there is associated skew-symmetric tensor field given by the covariant derivative of , giving a structure on M, where is 1-form dual to . A natural question is under which situation the structure becomes a K-contact structure? We answer this question and find a necessary and sufficient condition in terms of sectional curvatures of plane sections containing (see Theorem 3). We also find conditions under which a Riemannian manifold admitting a unit Killing vector field is an Einstein manifold (see Theorems 4 and 5). Finally, as a by-product of Theorem 3 with an additional condition that the Ricci operator is Codazzi type tensor on a Riemannian manifold that admits a unit Killing vector field , we show that is an Einstein Sasakian manifold (see Corollary 2).
2. Preliminaries
Recall that a vector field on a Riemannian manifold is said to be a Killing vector fields if
where being Lie-derivative of metric g with respect to ; or equivalently,
where ∇ is the Riemannian connection on and is Lie-algebra of smooth vector fields on M. Please note that a parallel vector field is a Killing vector field, we say a Killing vector field is a non-trivial Killing vector field if it is not parallel. For the Killing vector field on an n-dimensional Riemannian manifold , we denote by the smooth 1-form dual to , i.e., , . In addition, we define a skew-symmetric -tensor field by
The curvature tensor field R and the Ricci tensor S of are given by
and
respectively, where is a local orthonormal frame on M.
According to symmetry of the Ricci tensor S, we get a symmetric operator T called the Ricci operator of M and defined by
The scalar curvature of M is given by . Please note that —the gradient of the scalar curvature —satisfies
where is the covariant derivative of T, defined by
Please note that if is a Killing vector field on a Riemannian manifold , then using Equations (2) and (3), we have
From definition of , we see that the smooth 2-form is closed and as a result of using Equation (5), we make a conclusion
Observe that if is a Killing vector field of constant length on a Riemannian manifold , then taking the inner product with in Equation (2), we get , , and as is skew-symmetric, we conclude
For given a smooth function f on a Riemannian manifold the Hessian operator is defined by
which is a symmetric operator with
where is the Laplace operator. The Hessian of f is defined by
Let be a Killing vector field on a Riemannian manifold and be the algebra of smooth functions on M. Then, using Equation (2) and skew-symmetry of the operator , it follows that and that for a smooth function , we have . Thus, we get
Lemma 1.
Let be a unit Killing vector field on a compact Riemannian manifold . Then for a smooth function
Lemma 2.
Let be a unit Killing vector field on a Riemannian manifold . Then
Proof.
Assume that is a unit Killing vector field on a Riemannian manifold . Then, using Equations (2) and (7), we have
Taking the inner product in above equation with and using Equation (9), we deduce
□
Lemma 3.
Let be a unit Killing vector field on a compact Riemannian manifold . Then for a smooth function
Proof.
Please note that the flow of the Killing vector field consists of isometries of the Riemannian manifold, therefore, we have . We use Equation (2) in computing the divergence and get
where is a local orthonormal frame, . Owing to symmetry of T and skew-symmetry of , it follows that and using Equation (4), we conclude . Also, we have
By integrating above equation, the desired result follows. □
As a consequence of Lemma 2, we conclude the following
Corollary 1.
On a hyperbolic space or a Euclidean space, there does not exists a non-trivial unit Killing vector field.
It is well known that the odd-dimensional unit sphere possesses a unit Killing vector field , the Reeb vector field provided by the Sasakian structure on (cf. [12]). In the rest of this section, we shall construct the unit Killing vector field on the sphere , and on odd-dimensional ellipsoids. Treating as real hypersurface of the complex manifold with unit normal and shape operator , where J is the complex structure and is the Euclidean Hermitian metric on . We denote the Euclidean connection on by D and the induced metric and induce Riemannian connection on by g and ∇, respectively. Now, define a unit vector field on the sphere . Then taking covariant derivative in the equation with respect to applying Gauss–Weingarten formulas for hypersurface, we conclude
Define an operator on by , where is the tangential projection of on . Then, it follows that is skew-symmetric operator and above equation on equating tangential and normal components gives
and it follows that is a unit Killing vector field on the sphere . Moreover, if we take a constant unit vector on the complex space and define a smooth function and letting be the tangential projection of the vector on the sphere , we get
Taking covariant derivative in above equation with respect to and using Gauss–Weingarten formulas for hypersurface and noting that , we obtain
that is,
where is the gradient of the smooth function f. We claim that f is non-constant, for if f is constant, then Equation (10) will imply and and that , contrary to the fact that is a unit vector field. Hence, f is a non-constant function and Equation (11) implies that
where is the Laplace operator acting on f.
Consider a smooth function , defined by
where is the Euclidean space and the constant ,
Then is -dimensional compact hypersurface of the Euclidean space . Let g be the induced metric on the Ellipsoid M as hypersurface of . Consider the vector field on the Euclidean space
it follows that is a Killing vector field on the Euclidean space and its flow consists of isometries of the Euclidean space . Please note that length of is non-constant on the Euclidean space . The function h is invariant under flow (as ) of and the ellipsoid is invariant under the flow , consequently, the vector field is tangent to the hypersurface M and with respect the induced metric g, we have , i.e., is a unit Killing vector field on the compact Riemannian manifold .
3. Characterizations of Spheres
In this section, we use unit Killing vector fields on an n-dimensional compact Riemannian manifold in finding two characterizations of the spheres. First, given a unit Killing vector field on a connected Riemannian manifold , for each smooth non-constant function , we define a vector field by
and call the associated vector field of f with respect to . Please note that the associated vector field is orthogonal to the unit Killing vector field . It is interesting to note that if is non-trivial unit Killing vector field, then for each , the associated vector field is non-zero as seen in the following.
Proposition 1.
Let be a unit non-trivial Killing vector field on a connected Riemannian manifold . Then for each non-constant function the associated vector field is non-zero.
Proof.
Suppose for a non-constant . Then we have
and taking covariant derivative with respect to , we get
As the operator is symmetric and is skew-symmetric, we obtain
that is,
Using Equation (15) in above equation, we get and as M is connected with non-trivial (), we have . This proves and we get a contradiction to the fact that f is a non-constant function. Hence, . □
As seen in above Proposition, for each non-constant function on an n-dimensional connected that admits a non-trivial unit Killing vector field , the associated vector field is non-zero vector field. In the next result, we show that if there exists a smooth non-constant function on an n-dimensional compact and connected that admits a non-trivial unit Killing vector field satisfying and the integral of the Ricci curvature has certain lower bound is necessary and sufficient for to be isometric to the unit sphere , giving a characterization of the unit sphere .
Theorem 1.
Let be a non-trivial unit Killing vector field on an n-dimensional compact and connected Riemannian manifold . Then there exists a non-constant function satisfying and
if and only if, n is odd () and is isometric to the unit sphere .
Proof.
Let be a non-trivial unit Killing vector field and be a non-constant function such that . Then the associated vector field is non-zero vector field and
Note that Equation (16) gives
Integrating, we obtain
where we used . Using and Equation (16), we have , as and are orthogonal and the above integral takes the form
Next, we use Equation (6) to get
and using this equation and Equation (19), in computing , we reach at
Also, we have , i.e.,
Thus, we have
and integrating above equation, we get
On using , and the fact that flow of consists of isometries, we have , and above equation changes to
Also, using , we get
and using the bound in the statement for integral of , we obtain
Thus, by Schwarz’s inequality, we get
for non-constant function f. Hence, is isometric to the unit sphere (cf. [15,16]). Please note that on an even-dimensional compact Riemannian manifold of positive sectional curvature a Killing vector field must have a zero (cf. [17]). As the Killing vector field is unit vector field does not have a zero, we get that n is odd say . Hence, is isometric to the unit sphere .
Conversely, there is a unit Killing vector field on the unit sphere and by Equations (12) and (13) there is a non-constant smooth function f satisfying
Now,
and
Remark 1.
If the equality in the statement of Theorem 1 holds, then following the proof of the Theorem 1, we conclude
Using the Schwarz’s inequality in above equation, we get
and we get the same conclusion as in Theorem 1.
We would like to point that a similar situation is considered in [18].
In the next result we show that for positive constant c, if there is a smooth function satisfying on an n-dimensional compact and connected that admits a non-trivial unit Killing vector field with , and the Ricci curvature has certain lower bound, is necessary and sufficient for to be isometric to the sphere , giving a characterization of the odd-dimensional sphere .
Theorem 2.
Let be a non-trivial unit Killing vector field on an n-dimensional compact and connected Riemannian manifold . Then there exists a non-constant function satisfying for a constant , and the Ricci curvature in the direction of the vector field is bounded below by , if and only if, n is odd () and is isometric to the sphere .
Proof.
Let be a non-trivial unit Killing vector field on such that and be a non-constant function such that and
We have , using Lemmas 2 and 3, we get
Also, we have and using the outcome of , namely
and Lemma 1, we get
Using above equation and Equation (27), we conclude
Using , we get
4. Killing Vector Fields and Sasakian Manifolds
Recall that a -dimensional manifold M is said to have an almost contact metric structure , if
where is a skew-symmetric tensor field, is a unit vector field, is 1-form dual to and g is the Riemannian metric on M (see [12]). An almost contact metric manifold is said to be a contact metric manifold if
If unit vector field of the contact metric manifold is Killing, then it is said to be a K-contact manifold. Also, a contact metric manifold is said to be a Sasakian manifold if
Given a unit Killing vector field on an n-dimensional Riemannian manifold there is naturally associated a skew-symmetric operator on and there is a smooth 1-form dual to . A natural question is when does become a K-contact structure on M? Of course, it requires n to be odd, should satisfy relation similar to almost contact metric structure, namely
and other requirements are automatically met by Equations (2) and (7) (cf. [12,13]). In this section, we answer this question by showing that becomes a K-contact structure on M, if and only if, the Riemannian manifold admitting the unit Killing vector field with sectional curvatures of plane sections containing are constant equal to 1. We also find conditions under which a Riemannian manifold admitting a unit vector field is an Einstein–Sasakian manifold.
Theorem 3.
Let be a unit Killing vector field on an n-dimensional connected Riemannian manifold . Then is a K-contact structure, if and only if, sectional curvatures of the plane sections containing are constant equal to 1.
Proof.
Let be a unit Killing vector field on and be smooth 1-form dual to . Suppose the sectional curvature for a plane section containing . Then, we have
where . Polarizing Equation (28), we get
that is,
This proves that
Now, using Equations (6) and (7), we get
and combining above equation with and Equation (29), we conclude
Also, we have
Hence, is a K-contact structure on M.
The converse is obvious (cf. [12,13]). □
In [3], it was observed that presence of Killing vector field of constant length on with certain sectional curvatures positive and Ricci operator parallel implies is an Einstein manifold. In the next result, we find conditions under which a compact Riemannian manifold admitting a unit Killing vector field is an Einstein manifold.
Theorem 4.
Let be a non-trivial unit Killing vector field on an n-dimensional compact and connected Riemannian manifold , with section curvatures of plane sections containing being positive. If the following conditions are satisfied
then is an Einstein manifold.
Proof.
Let be a non-trivial unit Killing vector field on a compact and connected . Suppose that for a plane section containing and the following conditions hold
Using Lemma 2, we define a vector field orthogonal to by
Taking covariant derivative in above equation with respect to , we get
As the flow of consists of isometries of , we have , i.e.,
and using it with the first equation in Equation (30), we have
Taking the inner product with in above equation and using Equation (7) and , we obtain
that is, the gradient is given by
Using Equation (33) and a local orthonormal frame on M, we compute the and get the following
and using Equations (6) and (34) and Lemma 2, we conclude
Integrating above equation and using the inequality in Equation (30), we have and consequently, Equation (35) implies that is a constant. Hence, Equation (31) implies that , where c is a positive constant because is non-trivial Killing vector field. Taking covariant derivative in the equation while using Equations (2) and (33), we get
that is,
We can bypass the requirements that manifold is compact and the condition (ii) in Theorem 4 by assuming certain vector field is parallel as seen in the following:
Theorem 5.
Let be a non-trivial unit Killing vector field on an n-dimensional complete and connected Riemannian manifold , with section curvatures of plane sections containing being positive. If the vector field is parallel and the Ricci operator T satisfies
then is a compact Einstein manifold.
Proof.
Follow the proof of Theorem 4 up to Equation (35) and use that the vector field is parallel, in view of Equation (34), we get
Taking the inner product with in above equation and using Equation (7), we have , , and we conclude is a constant (as is a non-trivial Killing vector field). Then Equation (35) implies , which gives and as the sectional curvatures of plane sections containing are positive, we get . Following Proof of Theorem 4, we get that is an Einstein manifold. Please note that as and , the Ricci curvature is strictly positive and therefore by Myer’s Theorem is compact. □
Remark 2.
We give two examples, one satisfying conditions in Theorems 4 and 5 and other does not obeying conditions in these theorems.
Example 1.
Consider the sphere . We have seen in the Preliminaries that admits a unit Killing vector field , where ζ is the unit normal and J is the complex structure on the complex space . Moreover, we have (see Equation (10))
where , where is the tangential component of to . The Ricci operator T of is given by
which clearly satisfies
Also, on taking a local orthonormal frame on , we have
and
Consequently, we have
Moreover, we have , i.e., is parallel. Hence, we see that the conditions (i) and (ii) in Theorem 4, as well as both conditions in Theorem 5 hold for the Einstein manifold with unit Killing vector field .
Example 2.
Consider the 3-dimensional ellipsoid defined by
where constant and are Euclidean coordinates on . Then is a compact 3-dimensional Riemannian manifold with g the induced metric as a hypersurface of the Euclidean space . As seen in the Preliminaries there is a unit Killing vector field on given by
We claim that is not an Einstein manifold. Suppose is an Einstein manifold with Ricci tensor and Ricci operator given by
Please note that the curvature tensor field R of the 3-dimensional is given by
that is,
This shows that is space of constant curvature that is a contradiction. Hence, is not an Einstein manifold.
Using Theorem 3 and the condition on Ricci operator being a Codazzi type tensor as in Theorem 5, we get the following result, similar to Theorem 4.1 in [19].
Corollary 2.
Let be a non-trivial unit Killing vector field on an n-dimensional complete and connected Riemannian manifold , with section curvatures of plane sections containing being constant equal to 1. If the Ricci operator T satisfies
then is an Einstein Sasakian manifold.
Proof.
By Theorem 3, we get that is a K-contact manifold, and . Thus, is a constant and by Equation (35), we get and we get on similar lines as in proof of Theorem 5 that is an Einstein K-contact manifold with . Since Ricci curvature is strictly positive we get is compact. Hence, is an Einstein Sasakian manifold (cf. [13]). □
Author Contributions
Conceptualization and methodology, S.D.; formal analysis, O.B.; writing—original draft preparation, S.D. and O.B.; writing—review and editing, S.D. and O.B.; supervision, S.D. and O.B.; project administration. All authors have read and agreed to the published version of the manuscript.
Funding
This research received no external funding.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Acknowledgments
The authors extend their appreciations to the Deanship of Scientific Research, King Saud University for funding this work through research group No (RG-1441-P182).
Conflicts of Interest
The authors declare no conflict of interest.
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