Abstract
This paper examines the commutativity of the quotient ring by utilizing specific differential identities in a general ring that contains a semiprime ideal . This study particularly focuses on the role of a multiplicative generalized semiderivation , which is associated with a map , in determining the commutative nature of the quotient ring.
MSC:
16W20; 16W25; 16U70; 16U80; 16N60
1. Introduction
In the study of associative rings, the structure and properties of ideals play a crucial role. Prime and semiprime ideals, in particular, are significant due to their ability to characterize the ring’s behavior.
Let be an associative ring with center Z. A prime ideal in an associative ring is a proper ideal such that for any , if , then either or . A ring is called a prime ring if the zero ideal is a prime ideal, meaning that for any , implies either or .
A semiprime ideal is defined as a proper ideal where for any , if , then . A ring is termed a semiprime ring if the zero ideal is a semiprime ideal, which indicates that the ideal generated by any element squared lies in the ideal if the element itself does.
An additive mapping on is a derivation if for all . The first study on derivations of prime rings was published in 1957 by Posner [1]. Several mathematicians have since generalized the notion of derivation in various ways, leading to the introduction of different kinds of derivations in the literature.
One such generalization is the concept of semiderivations, introduced by Bergen [2]. An additive mapping is a semiderivation if there exists a function , such that
- (i)
- and
- (ii)
for all . If is the identity map, semiderivations reduce to derivations, making semiderivations a broader concept.
In 1991, Bresar [3] introduced the notion of generalized derivations: an additive mapping on is called a generalized derivation associated with a derivation if for all . Similarly, Daif [4] introduced multiplicative derivations by removing the additive condition, defining as a multiplicative derivation if for all . Daif and Tammam El-Sayiad [5] further extended this to multiplicative generalized derivations.
Let S be a nonempty subset of . A mapping from to is called centralizing on S if for all , and commuting on S if for all . This concept has been generalized to -commuting maps: is a -commuting map on S if for all and some .
Daif and Bell in 1992 [6] showed that an ideal I of a semiprime ring is contained in the center of if any of the following conditions are satisfied for all :
In particular, if , then is commutative. This result has been extended by many authors, who have also obtained commutativity results for prime or semiprime rings with derivations satisfying certain polynomial identities (see, e.g., [7,8,9,10,11,12]).
The commutativity of prime and semiprime rings admitting derivations remains an active area of research. Recent approaches involve examining commutativity conditions in quotient rings rather than assuming the ring is prime (see, e.g., [13,14,15,16]).
The principal aim of this study is to explore the definition of semiderivation given by Bergen. Inspired by the notion of multiplicative generalized derivation [17], we introduce the concept of a multiplicative generalized semiderivation. A mapping on is a multiplicative generalized semiderivation if there exists a multiplicative semiderivation associated with a map on , such that
- (i)
- and
- (ii)
for all .
This study aims to investigate identities involving multiplicative generalized semiderivations in semiprime ideals. Since every prime ideal is semiprime, but the converse is not true, examining identities involving multiplicative generalized semiderivations in semiprime ideals is appropriate. We will prove Daif’s theorem and discuss some functional identities, extending and unifying several known results.
2. Main Results
Throughout this paper, will be an arbitrary ring, will be a semiprime ideal of , will be a multiplicative generalized semiderivation associated with a map of , and is an epimorphism on . For any as usual, and will show the associated Lie and Jordan product, respectively. The following expressions will make our work easier for us:
Theorem 1.
Let be a ring admitting a semiprime ideal Y and a multiplicative generalized semiderivation ψ associated with a map θ, and γ be an epimorphism on . If any one of the following conditions is satisfied for all , then for all
- (i)
- ;
- (ii)
- ;
- (iii)
- ;
- (iv)
- ;
- (v)
- ;
- (vi)
- .
Proof.
We are assuming that
Substituting in place of in (1), we obtain
This implies that
Using our hypothesis, we have
Replacing by in the last expression, we obtain
Since is an epimorphism of and using (2), we can write this equation as
Again replacing with in (3), we obtain
By right-multiplying (3) by we obtain
Subtracting (4) from (5), we arrive at
Since is an epimorphism of we have
Writing instead of t in the last equation, we obtain
Based on the semiprimeness of we arrive at
On the other hand, by using as a multiplicative generalized semiderivation of and this equation, we obtain
and so
This completes the proof.
Assume that
Writing instead of in (8), we have
Since is a multiplicative generalized semiderivation of we obtain
Using (8), we obtain
If we put instead of in the last equation, we have
Expanding this equation and using (9), we arrive at
Furthermore, the proof follows directly from Theorem 1, after Equation (3). By applying the same technique, we obtain that for all
Assume that . According to the hypothesis, for all We can easily obtain . Based on the semiprimeness of we arrive at for all and so a contradiction.
Now, we assume that . We also assume that
Replacing with in (10), we obtain
which can be expanded as
This can be written as
Using the hypothesis, this equation reduces to
This expression is identical to Equation (2) in the proof of Theorem 1. By employing similar expressions within the proof of Theorem 1, we can obtain the desired result.
Assume that . If we apply similar operations to those applied in Theorem 1 (iii), a contradiction is obtained. Alternatively, assume that . Based on the hypothesis, we then have
Replacing with in the above equation and using it accordingly, we can easily obtain
By applying the same techniques used after Equation (2) in the proof of Theorem 1, we obtain the required result.
Assume that . If we perform the same operations as in Theorem 1 (iii), a contradiction arises. Thus, assume now that . Based on the hypothesis, we then have
Replacing with in (12) and using this equation accordingly, we find that
This expression is identical to Equation (9) in the proof of Theorem 1. By using expressions similar to those used in the proof of Theorem 1, we can obtain the desired result.
Assume that . If similar operations are performed in Theorem 1 (iii), a contradiction is reached. Now assume that . Based the hypothesis, we then have
Replacing with in (13) and using this equation, we arrive at the following conclusion
Again using the same lines as those used in the proof of Theorem 1, we conclude that for all □
Theorem 2.
Let be a ring admitting a semiprime ideal Y and ψ be a multiplicative generalized semiderivation associated with a map θ, with γ being an epimorphism on . If any one of the following conditions is satisfied for all , then for all
- (i)
- ;
- (ii)
- ;
- (iii)
- ;
- (iv)
- .
Proof.
Assume that . Based on the hypothesis, for all This expression is identical to the one in Theorem 1 . We now assume that . Using our hypothesis, we obtain
Taking instead of within (14), we have
Since is a multiplicative generalized semiderivation of we obtain
which can be written as
Using the hypothesis, we arrive at
Since is an epimorphism of we have
and so
Due to the semiprimeness of we arrive at
On the other hand, we know that according to our hypothesis, and so for all Using the in the last expression, we understand that
and so
The semiprimeness of forces us to conclude that
Taking instead of in (16) and subtracting the relations (16) and (17), we find that
and so
This completes the proof.
Assume that . Based on the hypothesis, for all . This expression is the same as the expression in Theorem 1 (iii). We now assume that . Using our hypothesis, we obtain
and
Subtracting these two equations, we have
and so
Writing instead of in this equation and using it accordingly, we find that
Replacing with in (18) and using (18), we obtain
and so
Similarly, (18) reveals that
Subtracting (19) from (20), we find that
and so
Due to the semiprimeness of , we obtain
Replacing with in this equation and using it accordingly, we obtain
and so
Again using the semiprimeness of , we obtain the required result.
Assume that
Define the map for all is a multiplicative generalized semiderivation associated with a nonzero map of Based on the hypothesis, we have for all Hence, the conclusion is obtained via Theorem 2 .
Using our hypothesis, we obtain
Define the map for all is a multiplicative generalized semiderivation associated with a nonzero map of , such that for all . Using Theorem 2 (ii), we find that for all . □
Theorem 3.
Let be a ring admitting a semiprime ideal Y and ψ be a multiplicative generalized semiderivation associated with a map θ, with γ being an epimorphism on . If any one of the following conditions is satisfied for all , then for all
- (i)
- ;
- (ii)
- ;
- (iii)
- ;
- (iv)
- .
Proof.
We assume that
Writing instead of in (21), we obtain
Using the definition of , we have
Based on the hypothesis, we find that
This expression is exactly the same as Equation (2) in the proof of Theorem 1. By using expressions similar to those used in the proof of Theorem 1, we obtain the desired result.
By using our hypothesis, we obtain
Replacing with in (22) and using this equation, we find that
This expression is exactly the same as Equation (2) in the proof of Theorem 1. By using expressions similar to those used in that proof, we obtain the desired result.
Using our hypothesis, we obtain
Replacing with in (23), we obtain
Since is a multiplicative generalized semiderivation of we obtain
Based on the hypothesis, we find that
This expression is exactly the same as Equation (9) in the proof of Theorem 1. By using expressions similar to those used in that proof, we obtain the desired result.
Theorem 4.
Let be a ring admitting a semiprime ideal Y and ψ be a multiplicative generalized semiderivation associated with a map θ, with γ being an epimorphism on If any of the following conditions are satisfied for all , then for all
- (i)
- ;
- (ii)
- ;
- (iii)
- ;
- (iv)
- .
Proof.
Based on our hypothesis
Taking instead of in (25), we obtain
and so
which can be expanded as
Using (25), we find that
Equation (2) yields the same expression. Similar expressions can be used in the proof of Theorem 1. Thus, the proof is complete.
Let us assume that
Writing instead of in (27) and using (27), we reveal that
Equation (2) yields the same expression. Similar expressions can be used in the proof of Theorem 1. Therefore, the proof is complete.
Theorem 5.
Let be a 2-torsion-free ring with Y being a semiprime ideal of . Suppose that admits a multiplicative generalized semiderivation ψ associated with a map If any of the following conditions are satisfied for all , then θ is a -commuting map on .
- (i)
- ;
- (ii)
- .
Proof.
Assume that . Based on the hypothesis, for all This expression is the same as the one in Theorem 1 . We now assume that . Using the hypothesis, we have
Replacing with in the hypothesis and using the hypothesis, we find that
Again using the hypothesis, we have
Since is an epimorphism of we have
Replacing with , , we have
Applying (32), we have
Since is an epimorphism of we have for all This implies that for all and so for all Hence, we obtain
Assume that . Based on the hypothesis, for all This expression is the same as the expression in Theorem 1 . We now assume that . Using the hypothesis, we have
Replacing with in (33), we obtain
Using the hypothesis, we obtain
Since is an epimorphism of we have
Left-multiplying this equation by for and using it accordingly, we obtain
Based on the hypothesis, we can express the last equation as follows:
Replacing with we have
Taking instead of we obtain
Since is a semiprime ideal of we conclude that
Right-multiplying by in (34), we obtain
Left-multiplying this equation by , we obtain
Since is a semiprime ideal of we conclude that
Subtracting (35) from (36), we find that
This completes the proof. □
Theorem 6.
Let be a -torsion-free ring with Y being a semiprime ideal of . Suppose that admits a multiplicative generalized semiderivation ψ associated with a nonzero multiplicative semiderivation If any of the following conditions are satisfied for all , then θ is a -commuting map on
- (i)
- ;
- (ii)
- .
Proof.
We obtain
Replacing with in (37), we have
Using (37), we see that
Substituting for in the last expression, we have
Since is an epimorphism of we have
Replacing with we obtain
Using the hypothesis and , we have
and so
Writing instead of in (39) and using (39), we find that
Replacing with in (40), we find that
Multiplying (40) on the left by we have
Subtracting (41) from (42), we determine that
that is,
Since is a semiprime ideal of we conclude that
and so is a -commuting map on
Author Contributions
This material is a result of the joint efforts of A.Y.H., Ö.G., E.K.S. and N.u.R. All authors have read and agreed to the published version of the manuscript.
Funding
The authors extend their appreciation to the Deanship of Research and Graduate Studies at King Khalid University for funding this work through the “Large Research Project” scheme under grant number RGP2/293/45.
Data Availability Statement
All data required for this work are included within this article.
Acknowledgments
The authors are greatly indebted to the reviewers for their valuable suggestions and comments, which immensely improved this article.
Conflicts of Interest
The authors declare no conflicts of interest.
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