Abstract
The aim of this work is to discuss the existence of solutions to the system of fractional variable order hybrid differential equations. For this reason, we establish coupled fixed point results in Banach spaces.
Keywords:
coupled fixed point theorems; measure of noncompactness; system of variable order hybrid differential equations MSC:
Primary 47H10; Secondary 54H25
1. Introduction
In recent years, integral and fractional differential operators have been popular in mathematical models. However, it is the last one hundred years in which the majority of the fractional problems in scientific application and engineering have been discovered. For instance, the earthquake’s non-linear oscillation can be framed with fractional derivatives [1], and fractional derivatives combined with the fluid dynamic traffic design can eliminate the shortfall originating from the assumption of continuum traffic flow [2]. That is why the differential equation with a fractional order derivative has recently proven to be a strong gadget in the designing of many processes in various areas of engineering and science [3,4,5,6,7,8].
Many physical phenomena look like they display fractional order behavior that changes with space and time. The integrals and derivatives whose order is a function of specific variables catch the attention because of their applied significance in different fields of research, such as: multifractional Gaussian noises [9], mechanical applications [10], FIR filters [11], anomalous diffusion modeling [12]. Furthermore, a physical study based on experimental data of variable-order fractional operators has been examined in [13]. A study comparing variable-order fractional and constant-order models has been looked analyzed in [14]. The current literature about solutions to the problems of fractional differential equations is pretty vast, only a few articles study the existence of solutions to differential equations with variable-order. Particularly, Limpanukorn and Ngiamsunthorn [15] discussed the existence of solution to the following fractional order hybrid differential equation
where and the functions satisfies specific conditions. is the Caputo fractional variable order derivative.
To check the existence of solution, we use fixed point theory, because the problem of the existence of solution usually turns into the problem of finding a fixed point of a particular mapping. Due to this fact, the results of fixed point theory could be implemented to the get results of an operator equation. Equation can be expressed in the form of operator equation
where subspace of a linear space, and are self-mappings. A useful result for the existence of solution to Equation is the Krasnosel’skii [16] fixed point theorem. So many generalizations and improvements of the Krasnosel’skii’s fixed point theorem have been produced, for instance [17,18,19,20,21]. In particular, Amar et al. [17] stated some new fixed point results for operator Equation , where is a weakly compact and weakly sequentially continuous mapping and is either a weakly sequentially continuous nonlinear contraction or a weakly sequentially continuous separate contraction mapping. Motivated by the work of [15], we will discuss the existence of solution to the following system of fractional variable order hybrid differential equations:
where , and are continuous functions satisfies specific conditions. is the Caputo fractional variable order derivative. The system can be expressed in the form
where (subspace of a linear space) or and and .
A useful technique for finding the fixed point of the system is a coupled fixed point theory, which was introduced by Guo and Lakhsmikantham [22]. Bhaskar and Lakhsmikantham [23] were the pioneers who used coupled fixed point theorem for the existence of unique solution to a periodic boundary value problem. Many prominent researchers have taken greater interest regarding the application potential of coupled fixed point theorems.
For the existence of solution to the system , we establish coupled fixed point results in Banach spaces by utilizing the results of Amar et al. [17].
2. Preliminaries
We symbolize by and the set of all real numbers and nonnegative real numbers, respectively, by the set of all positive integers and by the weak closure . Additionally, denote a Banach space, , be the kernel of function and .
Definition 1
([24]). The left Riemann-Liouvillle fractional integral of order of a function is
Definition 2
([25]). The left Caputo fractional derivative of order of a function is
Theorem 1
([24]). Let , where . Then
The axiomatic definition of an MWNC is as below.
Definition 3
([26]). A map is an MWNC in Ξ if for all it satisfies the following axioms:
- (i)
- is non-empty and relatively weakly compact in Ξ;
- (ii)
- (iii)
- (iv)
- (v)
- If is a sequence of weakly closed sets in with and , then .
In applications, the MWNC satisfies some additional handy conditions.
- (vi)
- is relatively weakly compact set;
- (vii)
- (viii)
- (ix)
- (x)
Remark 1.
Let be a measure of noncompactness on a Banach space Ξ, then and define measures of noncompactness in the space , where denotes the natural projections of X.
Throughout this work, ⇀ will denote the weak convergence and → will denote the strong convergence, respectively.
Definition 4.
Let and be two Banach spaces. A function is called weakly continuous if it is continuous with respect to the weak topologies of and .
Definition 5.
Let and be two Banach spaces. An operator is said to be weakly sequentially continuous if, for every sequence with , we have .
Theorem 2
([17]). Let ♌ ∈ ♎. If and are two weakly sequentially continuous mappings such that
- (i)
- is weakly compact;
- (ii)
- is a nonlinear contraction;
- (iii)
Then there exists such that
Theorem 3
([17]). Let ♌ ∈ ♎. If and are two weakly sequentially continuous mappings such that
- (i)
- is weakly compact;
- (ii)
- is a nonlinear contraction;
- (iii)
Then there exists such that
Theorem 4
([17]). Let ♌ ∈ ♎ and be a weakly sequentially continuous mapping and such that
- (i)
- is relatively weakly compact;
- (ii)
- is linear, bounded and there exists such that is a nonlinear contraction;
- (iii)
Then there exists such that
Theorem 5
([17]). Let ♌ ∈ ♎. If and are two weakly sequentially continuous mappings such that
- (i)
- is relatively weakly compact;
- (ii)
- is a nonlinear contraction such that is bounded;
- (iii)
Then there exists such that
Definition 6.
Let X be a non-empty set. Then the mapping has a coupled fixed point , if and .
3. Coupled Fixed Point Theorems
Let be a Banach space and ♌ be a nonempty bounded, convex and closed subset of . Let and . Define , and by
and
Now, since
Thus, to prove that has at least one coupled fixed point in ♌ × ♌, it is sufficient to prove has at least one fixed point in ♌ × ♌. Now utilizing Theorem 4, we present our first result.
Theorem 6.
Let ♌ ∈ ♎ and be a weakly sequentially continuous mapping and such that
- (i)
- is relatively weakly compact;
- (ii)
- is linear, bounded and there exists such that
- (iii)
- If , for some , then
Then has at least one coupled fixed point in ♌ × ♌.
Proof.
Let be a sequence in ♌ × ♌ such that and , where . Then since is weakly sequentially continuous mapping, we have
Thus, is weakly sequentially continuous mapping. To show that is relatively weakly compact, we have
Since is relatively weakly compact, so . Using this fact, we have
Hence is relatively weakly compact. Next, since is linear so for and in , we have
Thus, is linear. Furthermore, since is bounded so there exists such that . Now, for , we have
for all , that is is bounded in .
Now, to show that is a nonlinear contraction, we use induction. Let , , then for and using condition (ii), we have
Assume that is a nonlinear contraction for , that is
Thus, using inequality for , we have
That is is a nonlinear contraction. In general, for any we can write
where with , that is is a nonlinear contraction. Hence for all , is a nonlinear contraction. Consequently, there exists such that is a nonlinear contraction.
Finally, if , for some , then we have to show that . For this, we have
which implies that and , by condition (iii), and hence . Thus, by Theorem 4, there exists at least one fixed point of in ♌ × ♌ and hence there exists at least one coupled fixed point of in ♌ × ♌. □
Utilizing Theorem 5, we establish the following result:
Theorem 7.
Let ♌ ∈ ♎ . If and are two weakly sequentially continuous mappings such that
- (i)
- is relatively weakly compact;
- (ii)
- There exists such that
- (iii)
- If , for some , then
If is bounded, then has at least one coupled fixed point in ♌ × ♌.
Proof.
Since is bounded, so there exists such that Let , then since
so and , that is is bounded. For the rest of the proof see Theorem 6. □
Utilizing Theorem 3, we present the following coupled fixed point result:
Theorem 8.
Let ♌ ∈ ♎ . If and are two weakly sequentially continuous mappings such that
- (i)
- is weakly compact such that for every bounded subset ;
- (ii)
- is a nonlinear contraction;
- (iii)
- If , for some , then
Then has at least one coupled fixed point in ♌ × ♌.
Proof.
Since and are two weakly sequentially continuous mappings, so using the same arguments as in Theorem 6, we can easily show that and are two weakly sequentially continuous mappings. To show that is weakly compact, we have to show that is bounded and is relatively weakly compact for every bounded subset . For this, since is bounded, so there exists such that . Now, for , we have
for all , that is is bounded in ♌ × ♌. Following the same steps as in Theorem 6 we obtain that is relatively weakly compact. Hence is weakly compact.
Next we show that is a nonlinear contraction. For this, using condition (ii), for every and for with , we have
that is is a nonlinear contraction. Finally, if , for some , then following the same steps as in Theorem 6, one can get . Thus, by Theorem 3 there exists at least one fixed point of in ♌ × ♌ and hence there exists at least one coupled fixed point of in ♌ × ♌. □
4. Applications
In this section, we discuss the existence of solution to the system of fractional variable order hybrid differential equations. First we recall the definition of over the interval . Let be a partition of the finite interval , where is a positive integer. Then a piecewise constant function with respect to is defined by
where and is the indicator of the interval with and , that is
First we establish the following lemma:
Lemma 1.
A solution of the fractional variable order differential equation
with initial condition on the interval is
Proof.
First of all apply the left Riemman–Liouville fractional integral operator of order to Equation and using Theorem 1, we can easily deduce that
Apply initial condition, we get
Using the Equation on becomes
Again, using the Equation on becomes
Proceeding the same way the Equation on becomes
□
With the help of Lemma 10, the initial value problem can be reformulated as the system of integral equations:
where and .
Theorem 9.
Assume that the following hypotheses hold.
- There exists positive constants and such that
- is a continuous function such that
- There exists a continuous function such that
- There exist positive constants such that
In addition, if , then the system has a solution.
Proof.
Let . Define by
where with . Then, clearly ♌ is a nonempty convex, bounded and closed subset of X. Now, is a solution of the system if and only if satisfies the system . Thus, finding the existence of solution to the system is equivalent to finding the existence of solution to system . For this, define the operators and by
Thus, the system of integral Equation is transformed into the system of the following operator equations:
We have to show that the system satisfies all the conditions of Theorem 7. First we show that and are two weakly sequentially continuous mappings. For this, let be a sequence with for some , we have to show that . For this, consider
However, , that is and hence . Thus, , that is is a weakly sequentially continuous mapping. Similarly,
However, , that is and hence . Thus, , that is is a weakly sequentially continuous mapping.
Now, we need to show that is relatively weakly compact. By definitions of and , we write For all , we have
We need to show that is bounded and equicontinuous. For and , we have
It follows that is bounded. For equicontinuity of , let and , we have
Since is uniformly continuous on , so for any , there exists such that
Let , then whenever , we have
That is is equicontinuous. Hence by Arzelà–Ascoli’s theorem for any sequence in there is a subsequence such that . Consequently, is relatively weakly sequentially compact. Thus, by Eberlein-Smulian theorem is relatively weakly compact.
Next, we have to verify condition (ii) of Theorem 7. To do this, consider
which implies that
where .
Furthermore, we have to prove condition (iii) of Theorem 7, let such that , by assumptions and , we have
That is and hence . Thus, condition (ii) of Theorem 7 holds. Finally, since , so for and , we have
which implies that , where and hence is bounded. Therefore by Theorem 7, the operator has a coupled fixed point in . Accordingly, the system has a solution in . □
Author Contributions
Conceptualization, writing—original draft preparation, writing—review and editing, supervision, investigation, M.B.Z. and M.S.; methodology, formal analysis, funding acquisition, visualization T.A. and A.M. All authors have read and agreed to the published version of the manuscript.
Funding
This research received no external funding.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Acknowledgments
We are very grateful to the editor and unbiased arbitrator for their prudent interpretation and proposition which refined the excellency of this manuscript. The authors T. Abdeljawad and A. Mukheimer would like to thank Prince Sultan University for the support through the TAS research lab. Also to thank for paying the APC.
Conflicts of Interest
The authors declare no conflict of interest.
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