Abstract
In this work, we introduce a mixed type of quadratic-additive (QA) functional equation and obtain its general solution. The objective of this work is to investigate the Ulam–Hyers stability of this quadratic-additive (QA) functional equation in matrix paranormed spaces (briefly, MP spaces) using the Hyers method for the factor sum of norms.
Keywords:
matrix paranormed spaces; Ulam–Hyers stability; quadratic-additive functional equation; Hyers method MSC:
39B82; 39B52; 46L07; 47L25
1. Introduction
The problem of Ulam [1] about the stability of group homomorphisms was originated by the stability problem of functional equations: suppose that A is a group, is a metric group, and . For any , does there exists a such that
holds and which gives a unique homomorphism is such that
for all ? If the answer is affirmative, we can say that the Cauchy equation is stable.
In 1941, Hyers [2] provided the case of approximately additive mapping , where A and are Banach spaces and F satisfies the below Hyers inequality
This proved that the limit
exists with the unique additive mapping , which satisfies
Moreover, if is continuous in for each fixed , then the function B is linear.
The result declared was that the Cauchy functional equation is stable for any pair of Banach spaces. The method that was provided by Hyers formed the additive function called the Direct Method. This is called the stability (Hyers–Ulam stability) of the Cauchy additive functional equation.
Every solution of the following Cauchy additive functional equation
is known as additive. The functional equation
is connected to a symmetric bi-additive. A quadratic function is a name given to each solution of the functional Equation (2). It is widely known that real vector space is quadratic if and only if a single symmetric bi-additive function B exists for all a and . The function B is presumptively assumed by
Skof explored the Ulam–Hyers stability problem for the functional Equation (2) for the mapping between a normed space and a Banach space. The stability results of a cubic-additive functional equation have been established by Jun [3]. Najati [4] has investigated stability of a quadratic-additive, in quasi-Banach spaces. After this, Najati [5] introduced an additive-cubic functional equation and examined its stability for a mapping between two quasi-Banach spaces.
In 2012, Choonkil Park [6] examined the stability of the functional Equations (1) and (2) in paranormed spaces. In 2013, Choonkil Park extended this work to examine (Ref. [7]) the stability results of the functional Equations (1) and (2) and the below Cauchy additive functional inequality
in matrix paranormed spaces. Based on these two works, Murali et al. [8] investigated the stability for the quadratic and cubic functional equations in matrix paranormed spaces. Moreover, Murali et al. [9] investigated the Hyers–Ulam stability of the quartic mappings in the same space. Tamilvanan et al., who developed this work, explored numerous functional equations in various normed spaces [10,11,12].
2. Quadratic-Additive Functional Equation and Its General Solution
We introduce a new mixed type of quadratic-additive (in brief, QA) functional equation:
where , and we obtain its general solution. The main objective of this work is to investigate the Ulam–Hyers stability results of this functional equation in matrix paranormed spaces by using the Hyers method for the factor sum of norms.
We utilize some notions from [7,13] as follows:
- is the set of all -matrices in V;
- is the element, which is 1, and the remaining elements are 0;
- indicates that the -element is 1 and the remaining elements are 0;
- indicates that the -element is a and the remaining elements are 0.
For , ,
We remark that is a matrix normed space if and only if is a normed space for every integer and
holds for all , and all , and that is a matrix Banach space if and only if is a matrix normed space, where V is a Banach space.
Lemma 1.
If an even mapping , which satisfies the functional Equation (3) for all , then the mapping is quadratic.
Proof.
In terms of the evenness of , we obtain . Now, Equation (3) becomes
for all . Replacing by in (4), we have . Now, replacing by in (4), we obtain
for all . Replacing a by in (5), we obtain
for all . Replacing a by in (6), we obtain
for all . Finally, we conclude that, for any non-negative integer l, we obtain
for all . Now, replacing by in (4), we have
for all . Replacing a by in (9), we obtain
for all . Replacing a by in (10), we obtain
for all . Finally, we conclude that, for any non-negative integer i, we obtain
for all . Replacing by in (4), we obtain (2) for all . Therefore, the mapping is quadratic. □
Lemma 2.
If an odd mapping , which satisfies the functional Equation (3) for all , then the mapping is additive.
Proof.
In terms of the evenness of , we obtain . Now, Equation (3) becomes
for all . Now, replacing by in (11), we have . Next, replacing by in (11) and using the oddness of , we obtain
for all . Again, replacing a by in (12), we have
for all . Replacing a by in (13), we obtain
for all . Finally, we conclude that for any non-negative integer l, we have
for all . Now, replacing by in (11), we obtain
for all . Replacing a by in (14), we obtain
for all . Replacing a by in (15), we obtain
for all . Finally, we conclude that for any non-negative integer i, we have
for all . Replacing by in (11), we reach (1) for all . Therefore, the mapping is additive. □
Lemma 3.
A mapping such that and (3) for all if and only if there exist a mapping which is symmetric bi-additive and a mapping which is additive such that for all .
Proof.
Let with satisfy (3). Now, split into an even part and odd part by taking
for all . Clearly, for all . Thus, and satisfy the functional Equation (3). From Lemmas 1 and 2, we obtain that (quadratic) and (additive). Thus, there exists , which satisfies for all . Therefore,
where .
Conversely, suppose that there exist mappings and satisfies
3. Stability Results in Matrix Paranormed Spaces
Here, we take as a matrix Banach space and as a matrix Frechet space. For a mapping , define and by
and
for all and all .
Note that for all .
Theorem 1.
Let with . If an even mapping such that
for all , then there exists a unique quadratic mapping satisfying
for all .
Proof.
Therefore, . Replacing by in (17), we have
for all . From inequality (18), we have
and so
for all . Clearly,
for all and all positive integers with . From (19), the sequence is Cauchy for every .
Since W is complete, the sequence converges. Next, we can define a mapping by
for all . Setting and taking the limit s that tends to ∞ in (19), we have
for all . From inequality (17),
Therefore, . Therefore, the function Q satisfies the functional Equation (3). Hence, the function Q is quadratic. Now, we prove that Q is unique. Consider to be another quadratic function which satisfies the functional Equation (3). Hence,
for all . Thus, for all . This shows that Q is a unique function. By Lemma 2.1 in [5] and (20), we can conclude that
for all . Hence, the proof of the theorem is now completed. □
Theorem 2.
Let with . If an even mapping such that
for all , then there exists a unique quadratic mapping satisfying
for all .
Proof.
Therefore, . Replacing by in (22), we have
for all . It follows from the inequality (23) that we obtain
for all . Replacing a by and dividing by in inequality (23), we obtain
for all . Clearly,
for all and all positive integers with . From (24), the sequence is a Cauchy sequence for all .
Since V is complete, the sequence converges. Next, we can define a mapping by
for all . Now, setting and taking the limit in (24), we have
for all . From inequality (22),
Therefore, . Thus, the function Q satisfies the functional Equation (3). Hence, the function Q is quadratic. Now, we prove that the quadratic function Q is unique. Consider to be another quadratic function which satisfies the functional Equation (3). Hence,
for all . Thus, for all . This proves that the function Q is unique. By Lemma 2.2 in [5] and (25), we can conclude that
for all , which ends the proof. □
Theorem 3.
Let with . If an odd mapping such that
for all , then there exists a unique additive mapping satisfying
for all .
Proof.
Assume that in (26). Then, the inequality (26) becomes
for all . Replacing by in (28), we have
for all . From the inequality (29), we obtain
and so
for all . Replacing a by and multiply by 2 in (30), we obtain
for all . It is easy to show that
for all and all positive integers with . From (31), the sequence is a Cauchy sequence for all .
Since W is complete, the sequence converges. Next, we can define a mapping by
for all . Now, taking and the limit s that tends to ∞ in (31), we arrive at
for all . From inequality (28),
Therefore, . That is, the function A satisfies the functional Equation (3). Thus, the function A is additive. Now, we want to prove that the function A is unique. Consider as another additive function which satisfies the functional Equation (3). Hence,
for all . Thus, for all . This proves that the function A is a unique function. By Lemma 2.1 in [5] and (32), we can conclude that
for all . Hence, the proof of the theorem is now completed. □
Theorem 4.
Let with . If an odd mapping such that
for all , then there exists a unique additive mapping satisfying
for all .
Proof.
Assume that in (33). Then, the equality (33) becomes
for all . Replacing by in (34), we obtain
for all . It follows from the inequality (35) that we obtain
for all . Replacing a by and dividing by 2 in (36), we obtain
for all . It is easy to show that
for all and all positive integers with . From (37), the sequence is a Cauchy sequence for all .
Since V is complete, the sequence converges. Next, we can define a mapping by
for all . Now, setting and taking the limit in (37), we obtain
for all . From inequality (34),
Therefore, . That is, the function A satisfies (3). Hence, the function A is additive. Now, we want to prove that the additive function A is unique. Consider as another additive function which satisfies the functional Equation (3). Hence,
for all . Thus, for all . This shows that A is a unique function. By Lemma 2.2 in [5] and (38), we can conclude that
for all , which ends the proof. □
Proposition 1.
Let with or . Let be a mapping with such that (16) holds for all . Then, there exists a unique quadratic mapping and a unique additive mapping that satisfies
for all .
Proof.
Let us define , where
are even and odd functions, respectively. Hence,
for all . The remaining proof is followed by the results of Theorem 1 and Theorem 3. □
Proposition 2.
Let with or . Let be a mapping with such that (16) holds for all . Then, there exists a unique quadratic mapping and a unique additive mapping such that
for all .
Proof.
Let us define , where
are even and odd functions, respectively. Hence,
for all . The remaining proof is followed by the results of Theorem 2 and Theorem 4. □
4. Illustrative Example
We use a suitable example to show that the functional Equation (3) fails to be stable in the singular situation. In response to Gajda’s excellent example in [14], we give the following counter-example, which demonstrates the instability in Theorem 1 of Equation (3) under specific conditions .
Remark 1.
- (1)
- , for all and .
- (2)
- , for all if the function ψ is continuous.
Example 1.
Let an even mapping defined by
where
Suppose that the function ψ defined in (39) satisfies
for all . We show that there does not exist a quadratic mapping such that
for all where λ and δ are constants.
We can easily find that ψ is bounded by on . If or 0, then
Thus, and
Moreover, for
Thus, the function ψ satisfies the inequality (40). Suppose, on the contrary, that there exists a quadratic mapping which satisfies (41).
From Remark 1, Q must be . Thus, we obtain
However, we have a choice with . If , then for every , we have
which contradicts. Thus, Equation (3) is not stable.
The upcoming counter-example shows the non-stability in a particular condition in Theorem 3 of the functional Equation (3).
Remark 2.
- (1)
- and .
- (2)
- if the function ψ is continuous.
Example 2.
Let an odd mapping defined by
where
Suppose that the function ψ is defined in (43) such that
for all . We show that there does not exist an additive mapping satisfying
where λ and δ are constants.
We can easily find that ψ is bounded by on . If or 0, then
Thus, and
Moreover, for
Thus, the function ψ satisfies the inequality (44). Assume that, on the contrary, there is an additive mapping which satisfies (45).
From Remark 2, A must be . Thus, we have
However, we have the choice of with . If , then for all , and we have
which contradicts. Thus, the functional Equation (3) is not stable.
5. Conclusions
In this work, we have introduced a new dimension to the finite variable QA functional Equation (3) and its general solution for the function was derived. Mainly, Ulam–Hyers stability in the matrix paranormed spaces has been explored by employing the Hyers method for the sum of norms factor of the generalized finite variable QA functional Equation (3).
Author Contributions
Conceptualization, K.T. and S.A.M.; Formal analysis, Y.A. and R.P.A.; Investigation, K.T. and S.A.M.; Methodology, Y.A. and R.P.A.; Writing—original draft, K.T., S.A.M. and Y.A.; Writing—review and editing, K.T., S.A.M., Y.A. and R.P.A. All authors have read and agreed to the published version of the manuscript.
Funding
The authors extend their appreciation to the Deanship of Scientific Research at King Khalid University, Abha, Saudi Arabia, for funding this work through the research group program under grant number RGP.2/211/43.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Conflicts of Interest
The authors declare that they have no conflict of interest.
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