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Article

Riemann Problem and Elementary Wave Interactions for a Simplified Magnetic Fluid Model

1
Department of Mathematics, Changji University, Changji 831100, China
2
School of Mathematics and Computing Science, Guilin University of Electronic Technology, Guilin 541002, China
*
Author to whom correspondence should be addressed.
Symmetry 2024, 16(11), 1425; https://doi.org/10.3390/sym16111425
Submission received: 3 October 2024 / Revised: 17 October 2024 / Accepted: 22 October 2024 / Published: 25 October 2024
(This article belongs to the Section Mathematics)

Abstract

:
In the present paper, we mainly studied the Riemann problem and wave interaction of a simplified magnetohydrodynamic equation system. Due to the complex Riemann problem and wave interactions in the magnetohydrodynamic equations, most previous studies either did not investigate the interaction of elementary waves or, if they did, lacked supporting numerical experiments. This paper simplifies the magnetohydrodynamic equations using variable substitution. Using the characteristic line method to solve the Riemann problem and elementary wave interaction of the simplified magnetohydrodynamic equations, the form of the solution is more symmetrical and the interaction between waves has also become more regular. The correctness of the results was verified by numerical experiments.

1. Introduction

Magnetogasdynamics plays a significant role in plasma physics and astrophysics [1], and it can be applied to industrial production [2]. According to the laws of conservation of mass, momentum, and energy, the one-dimensional ideal magnetohydrodynamic equations can be expressed in Lagrangian coordinates as follows:
τ t u x = 0 , u t + ( p + B 2 2 μ ) x = 0 , ( E + B 2 τ 2 μ ) t + ( p u + B 2 u 2 μ ) x = 0 .
where τ > 0 , u, p 0 , B = k τ 0 , k > 0 , μ and E = e + u 2 2 represent specific volume, velocity, pressure, magnetic flux density, magnetic permeability, and total energy, respectively, and specific internal energy for polytropic gas satisfies the relation e = p τ γ 1 . For most gases, γ (where 1 < γ < 3 ) is the adiabatic gas constant. When considering the initial value problem of Equation (1), no matter how smooth the initial data, discontinuity may still take place in the solution. In view of the essential feature of quasilinear hyperbolic equations, it is natural to take account of initial data U ( x , 0 ) with discontinuities at certain points. The simplest case, called the Riemann problem, is the Cauchy problem for (1) with initial condition
U ( x , 0 ) = U : = ( τ , u , p ) , x < 0 , U + : = ( τ + , u + , p + ) , x > 0 .
By using the characteristic line method to solve this problem, the conditions for the generation of evacuation waves, shock waves, contact discontinuities, vacuum, and mass concentration phenomena can be obtained.
Y. Hu studied the Riemann problem [3] and found that the projection of the contact discontinuity on the ( p , u ) plane is a straight line parallel to the p-axis. Due to the magnetic field, the result becomes more complex and difficult to analyze. This situation was also observed in the research of other scholars [4,5,6,7,8,9,10,11], indicating that the method of dividing the phase plane by the elementary wave curve is not suitable.
Since the full governing system for magnetohydrodynamics is highly nonlinear and complicated, it is necessary to study the various simplified models. In plasma physics, the sum of pressure and magnetic pressure is referred to as the total pressure, which is also known as the surface force. To simplify the Riemann problem of (1), denoting the F = p + B 2 2 μ as an independent variable, and μ = 1 , the system (1) can be rewritten in the form
τ t u x = 0 , u t + F x = 0 , ( F τ γ 1 + u 2 2 + ( γ 2 ) B 2 τ 2 ( γ 1 ) ) t + ( F u ) x = 0 ,
with the initial data
U ( x , 0 ) = U : = ( τ , u , F ) , x < 0 , U + : = ( τ + , u + , F + ) , x > 0 .
It has been rigorously proven that the projection of the contact discontinuity on the ( F , u ) plane is a point, which implies that the elementary wave curve can be used to divide the phase plane. This paper focus on the elementary wave interactions with the following initial data:
U ( x , 0 ) = U l : = ( τ , u , F ) , x < x 1 , U m : = ( τ m , u m , F m ) , x 1 x x 2 , U r : = ( τ + , u + , F + ) , x > x 2 .
for arbitrary x 1 , x 2 R . There are many conclusions regarding the elementary wave interactions of the hyperbolic system, and readers can view the references for more details.
The rest of this paper is organized as follows. In Section 2, we provide the methods used in this article. In Section 3, we obtain the expressions of the elementary wave curves including the rarefaction wave curves, shock wave curves, and contact discontinuity curves, and then we construct the Riemann solutions for arbitrary initial data. In Section 4, we analyze all possible results of the elementary wave interactions. In Section 5, we use numerical experiments to verify all possible results of elementary wave interactions.

2. Preliminaries

2.1. Characteristic Line Method

The systems of quasilinear hyperbolic equations that often arise in mathematical models formulated to describe nonlinear wave phenomena in various continuum media that result from the balance laws of continuum physics. The simplest model is the equation
u t + f ( u ) x = 0 ,
where f ( u ) is a smooth nonlinear given function defined on an interval I : ( a , b ) R .
We rewrite the equation as u t + f ( u ) u x = 0 and consider the characteristics defined by the following characteristic equations:
d x d t = f ( u ) , d u d t = 0
It is obvious that there exists a family of parallel lines on the ( x , t ) plane that make u invariant. These parallel straight lines are called characteristic lines.

2.2. Lax–Friedrichs Method

The Lax–Friedrichs method is a numerical solution for solving systems of quasilinear hyperbolic equations. The numerical format is
u i n + 1 = 0.5 ( u i + 1 n + u i 1 n ) 0.5 Δ t Δ x ( f ( u i + 1 n ) f ( u i 1 n ) )
The data used in this article will be detailed in Section 5.

3. The Riemann Problem of Simplifying Models

In this section, to reduce the difficulty of analyzing elementary wave interactions, the Riemann problem for Equation (2) has some differences compared to the previous article.
Equation (2) can be rewritten as
1 0 0 0 1 0 F γ 1 ( γ 2 ) k 2 2 ( γ 1 ) τ 2 u τ γ 1 τ u F t + 0 1 0 0 0 1 0 F u τ u F x = 0
It is easy to obtain that λ 0 = 0 , λ ± = ± γ F τ ( γ 2 ) k 2 2 τ 3 . These eigenvalues are real and distinct because F > ( γ 2 ) B 2 2 γ , indicating that Equation (3) is a strictly hyperbolic system. The right eigenvectors are r 0 = ( 1 , 0 , 0 ) T and r ± = ( 1 , λ ± , λ ± 2 ) T . It is obvious that the characteristic field λ 0 is linearly degenerate, which means that the elementary wave associated with it is a contact discontinuity and the characteristic fields λ ± are genuinely nonlinear, meaning that the elementary waves associated with r + and r characteristic fields will be either rarefaction waves or shock waves.
There are piecewise smooth solutions of Equation (3), which are of the form U ( x t ) such that
U ( x , t ) U l , x t < λ ± ( U l ) , U ( x t ) , λ ± ( U l ) x t λ ± ( U r ) , U r , λ ± ( U r ) < x t .
where U = ( τ , u , F ) T , assuming ξ = x t , system (3) becomes
λ d τ = d u , λ d u = d F , λ d ( F τ γ 1 + u 2 2 + ( γ 2 ) k 2 2 ( γ 1 ) τ ) = d ( F u ) .
The expression of the rarefaction wave passing through Q = ( τ , u , F ) can be written as follows:
R ( Q ) : ( F k 2 2 τ 2 ) τ γ = ( F k 2 2 τ 2 ) τ γ , u = u F F 2 τ 3 2 γ τ 2 s ( γ 2 ) k 2 d s ,
and
R ( Q ) : ( F k 2 2 τ 2 ) τ γ = ( F k 2 2 τ 2 ) τ γ , u = u + F F 2 τ 3 2 γ τ 2 s ( γ 2 ) k 2 d s .
Theorem 1.
Across R ( Q ) ( R ( Q ) ), τ τ , F F , u u ( τ τ , F F , u u ) if and only if the wave speed increases from the left state to the right state.
Proof. 
Without the loss of generality, we assume that Q is the left state. For R ( Q ) , it is found that
d λ d τ = γ τ 2 ( F B 2 2 ) + γ 2 ( F B 2 2 ) τ γ τ γ + 2 + 2 k 2 τ 3 + ( 6 2 γ ) B 2 2 τ 2 2 λ > 0 ,
where B = k τ . It is obvious that τ τ since λ ( τ ) λ ( τ ) . According to the first equation of Formula (6), it is found that
F τ = γ ( F k 2 2 τ 2 ) τ γ τ γ + 1 3 k 2 2 τ 2 < 0 , u F = 2 τ 3 2 γ τ 2 F ( γ 2 ) k 2 < 0 ,
so F F and u u . Conversely, τ τ , F F and u u for R ( Q ) . □
Additionally, contact discontinuity J satisfies u = u , F = F and τ τ .
Theorem 2.
The projection of contact discontinuity on the ( F , u ) plane is a point.
For a bounded discontinuity σ ( t ) = x ( t ) , the Rankine–Hugoniot jump conditions are
σ ( t ) τ = u , σ ( t ) u = F , σ ( t ) F τ γ 1 + u 2 2 + ( γ 2 ) k 2 2 ( γ 1 ) τ = [ F u ] .
where [ τ ] = τ τ . From Equation (7), the shock curves satisfy
S ( Q ) : τ ( F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) = τ ( F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) , u = u ( F F ) ( τ τ ) .
and
S ( Q ) : τ ( F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) = τ ( F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) , u = u ( F F ) ( τ τ ) .
Theorem 3.
Across S ( Q ) ( S ( Q ) ), τ τ , F F , u u ( τ τ , F F , u u ).
Proof. 
According to the second equation of Formula (9), [ u ] < 0 , and [ F ] , [ τ ] cannot be positive or negative at the same time. Thus, we have to apply the Lax entropy conditions, so τ τ and F F . Similarly, across S ( Q ) , τ τ , F F , and u u . □
Theorem 4.
The curve R ( Q τ ) is monotonic decreasing and convex in the ( F , u ) plane. The curve R ( Q τ ) is monotonic increasing and concave in the ( F , u ) plane. R ( Q τ ) has an intersection with the u-axis, and R ( Q τ ) has no asymptote. Q τ is the projection of Q on the ( F , u ) plane.
Proof. 
For the curve R ( Q τ ) , τ F < 0 , we can calculate the derivative with respect to F using Equation (6), as follows:
u F = 2 τ 3 2 γ τ 2 F ( γ 2 ) k 2 = 1 λ < 0 , u F F = ( 1 λ ) F = 1 λ 2 ( λ ) F = 1 λ 2 γ τ ( γ F τ 2 + ( γ 2 ) k 2 2 τ 4 ) τ F 2 λ = γ γ ( F B 2 2 ) + 2 B 2 τ F 2 λ > 0 ,
Moreover, it is easy to verify that R ( Q τ ) intersects the u-axis at a point. A similar proof applies to the curve R ( Q τ ) . The proof is completed. □
Theorem 5.
The curve S ( Q τ ) is monotonic decreasing and convex in the ( F , u ) plane. The curve S ( Q τ ) is monotonic increasing and concave in the ( F , u ) plane. S ( Q τ ) has an intersection with the u-axis, and S ( Q τ ) has no asymptote.
Proof. 
The proof for S ( Q τ ) follows similarly, so we must focus on S ( Q τ ) for convenience. From the first equation of Formula (9) and 1 < γ < 3 , it is found that
τ F = τ γ 1 γ + 1 τ F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 = ( γ 1 ) ( τ τ ) + 2 τ ( γ + 1 ) ( F B 2 2 ) + ( γ 1 ) F + 5 γ 2 B 2 < 0 , τ F F = ( τ F F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ( τ γ 1 γ + 1 τ ) ( 1 2 ( 2 γ ) B 2 ( γ + 1 ) τ τ F ) ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) 2 ) = 2 τ F ( 1 ( 2 γ ) B 2 τ F ( γ + 1 ) τ ) F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 > 0 ,
owing to
1 ( 2 γ ) B 2 τ F ( γ + 1 ) τ = ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) ( τ γ 1 γ + 1 τ ) ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ + 2 γ γ + 1 B 2 ( τ γ 1 γ + 1 τ ) ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ + γ 1 γ + 1 τ ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ = ( F + γ 1 γ + 1 F + 4 2 γ γ + 1 B 2 ) ( τ γ 1 γ + 1 τ ) ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ + γ 1 γ + 1 τ ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ = ( F B 2 2 + γ 1 γ + 1 F + 9 3 γ 2 ( γ + 1 ) B 2 ) ( τ γ 1 γ + 1 τ ) ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ + γ 1 γ + 1 τ ( F + γ 1 γ + 1 F + 2 γ γ + 1 B 2 ) τ > 0 .
Then, according to the second equation of Formula (9) and Theorem 3, it is found that
u F = [ τ ] + [ F ] τ F 2 [ F ] [ τ ] > 0 , u F F = τ F + τ F F [ F ] + τ F 2 [ F ] [ τ ] ( [ τ ] + [ F ] τ F ) 2 4 [ F ] [ τ ] < 0 .
Moreover, it is easy to verify that S ( Q τ ) has no asymptote. The proof is completed. □
Summarizing the work above, the ( F , u ) plane can be divided into four regions, as follows (see Figure 1):
Theorem 6.
There are four cases for the Riemann problem.
C a s e 1 . T h e p r o j e c t i o n o f ( τ + , u + , F + ) o n ( F , u ) p l a n e b e l o n g s t o I ( τ , u , F ) + R + ( τ * 1 , u * , F * ) + J + ( τ * 2 , u * , F * ) + R + ( τ + , u + , F + ) ; C a s e 2 . T h e p r o j e c t i o n o f ( τ + , u + , F + ) o n ( F , u ) p l a n e b e l o n g s t o II ( τ , u , F ) + R + ( τ * 1 , u * , F * ) + J + ( τ * 2 , u * , F * ) + S + ( τ + , u + , F + ) ; C a s e 3 . T h e p r o j e c t i o n o f ( τ + , u + , F + ) o n ( F , u ) p l a n e b e l o n g s t o III ( τ , u , F ) + S + ( τ * 1 , u * , F * ) + J + ( τ * 2 , u * , F * ) + R + ( τ + , u + , F + ) ; C a s e 4 . T h e p r o j e c t i o n o f ( τ + , u + , F + ) o n ( F , u ) p l a n e b e l o n g s t o IV ( τ , u , F ) + S + ( τ * 1 , u * , F * ) + J + ( τ * 2 , u * , F * ) + S + ( τ + , u + , F + ) .
where ( τ * 1 , u * , F * ) and ( τ * 2 , u * , F * ) are the intermediate states. Contact discontinuity J will not exist when τ * 1 = τ * 2 , ( τ , u , F ) and ( τ + , u + , F + ) are connected by rarefaction waves and shock waves.

4. The Elementary Wave Interactions

In order for two fundamental waves to interact, they must meet in finite time and space. Due to the fact that the interaction problem of waves can be regarded as a solution of partial differential equations with three initial values, one-dimensional space can be divided into left, middle, and right parts. Once the intermediate state is determined, based on the calculated dispersion wave velocity, shock wave velocity, and contact discontinuity wave velocity in the previous section, as long as the fundamental wave velocity generated in the left and middle parts exceeds that generated in the middle and right parts, wave interaction will occur. The initial data of the elementary wave interactions are as follows:
U ( x , 0 ) = U l : = ( τ , u , F ) , x < x 1 , U m : = ( τ m , u m , F m ) , x 1 x x 2 , U r : = ( τ + , u + , F + ) , x > x 2 .
The middle can be considered right relative to the left, and left relative to the right. Considering the particularity of the middle position relative to the left and right, the elementary wave interactions from the projection of intermediate state ( τ m , u m , F m ) are as follows:
See Figure 2. The projection of left state ( τ l , u l , F l ) is on the curve R ( Q l τ ) or S ( Q l τ ) passing through ( u m , F m ) , and the projection of right state ( τ r , u r , F r ) is on the curve R ( Q r τ ) or S ( Q r τ ) passing through ( F m , u m ) . Therefore,
( τ l , u l , F l ) : ( F l k 2 2 τ l 2 ) τ l γ = ( F m k 2 2 τ m 2 ) τ m γ , u l = u m F l F m 2 τ 3 2 γ τ 2 s ( γ 2 ) k 2 d s , F l < F m ,
( τ l , u l , F l ) : τ l ( F l + γ 2 γ + 1 B l 2 + γ 1 γ + 1 F m ) = τ m ( F m + γ 2 γ + 1 B m 2 + γ 1 γ + 1 F l ) , u l = u m + ( F m F l ) ( τ m τ l ) . F l > F m ,
and
( τ r , u r , F r ) : ( F r k 2 2 τ r 2 ) τ r γ = ( F m k 2 2 τ m 2 ) τ m γ , u r = u m F m F r 2 τ 3 2 γ τ 2 s ( γ 2 ) k 2 d s , F r < F m ,
( τ r , u r , F r ) : τ r ( F r + γ 2 γ + 1 B r 2 + γ 1 γ + 1 F m ) = τ m ( F m + γ 2 γ + 1 B m 2 + γ 1 γ + 1 F r ) , u r = u m ( F r F m ) ( τ r τ m ) . F r > F m ,
The elementary wave will meet another elementary wave and interact if it propagates for a period of time. When the left state ( F , u ) is selected, a backward wave curve through ( F , u ) and a forward wave curve through ( F , u ) can be confirmed by (13) and (14).
Case 1. The projection of left state ( τ l , u l , F l ) is on the curve S ( Q l τ ) (Figure 3).
Via (14), it is found that ( τ m , u m , F m ) is a point on the curve S ( Q τ ) , and when the projection of the right state ( τ r , u r , F r ) is on the curve S ( Q r τ ) , ( τ r , u r , F r ) are on the region I V ; the result of this interaction is S ( Q l τ ) S ( Q l τ ) .
When the projection of the right state ( τ r , u r , F r ) is on the curve S ( Q r τ ) , ( τ r , u r , F r ) are on the region I I ; thus, the result of this interaction is R ( Q l τ ) S ( Q l τ ) .
Case 2. The projection of the left state ( τ l , u l , F l ) is on the curve R ( Q l τ ) (Figure 4).
Via (13), it is found that ( τ m , u m , F m ) is a point on the curve R ( Q τ ) , when the projection of the right state ( τ r , u r , F r ) is on the curve S ( Q r τ ) , ( τ r , u r , F r ) are on the region I I I ; thus, the results of this interaction is S ( Q l τ ) R ( Q l τ ) .
When the projection of the right state ( τ r , u r , F r ) is on the curve S ( Q r τ ) , ( τ r , u r , F r ) are on the region I; the results of this interaction is R ( Q l τ ) R ( Q l τ ) .
Next, consider the interactions involving contact discontinuity.
Case 1. Changes in the ( F , u ) phase plane when τ increases (Figure 5).
Considering the variation in the rarefaction curve and shock curve in the ( u , F ) plane when τ increases, using monotony to solve the problems from the first equation of (6), it is found that
F = ( F k 2 2 τ 2 ) τ γ + k 2 2 τ γ 2 τ γ .
This means that F increases when τ is not changing. According to Theorem 1, this implies that τ will increase when F is not changing. Then, by the second equation of (6), 2 τ 3 2 γ τ 2 F ( γ 2 ) k 2 will increase when F is not changing, so u will increase when F is not changing for R . The same applies for R . For shock curves, by the first equation of (9), it is found that
F = τ ( F + γ 2 γ + 1 B 2 ) τ ( γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) τ γ 1 γ + 1 τ = τ ( F + γ 2 γ + 1 B 2 ) τ ( γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) τ γ 1 γ + 1 τ .
and
τ τ = τ ( F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F ) τ ( F + γ 1 γ + 1 B 2 + γ 1 γ + 1 F ) F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F = τ ( 2 γ + 1 ( F F ) + γ 2 γ + 1 ( B 2 B 2 ) ) F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F = τ ( 2 γ + 1 ( F F ) + γ 2 γ + 1 ( B 2 B 2 ) ) F + γ 2 γ + 1 B 2 + γ 1 γ + 1 F .
This means that F will increase when τ is not changing. According to Theorem 5, this implies that τ will increase when F is not changing. Thus, τ τ will increase when F is not changing. Then, by the second equation of (9), according to Theorem 3, u will decrease when F is not changing. The same applies for S . Therefore, the interactions with contact discontinuity are evident.
Case 2. Changes in the ( F , u ) phase plane when τ decreases (Figure 6).
This situation is similar to the first situation.
Therefore, there are eight cases for elementary wave interactions, as follows:
Theorem 7.
(i)
S ( Q ) + S ( Q ) .
S ( Q ) + S ( Q ) S ( Q l τ ) S ( Q l τ ) .
(ii)
S ( Q ) + R ( Q ) .
S ( Q ) + R ( Q ) R ( Q l τ ) S ( Q l τ ) .
(iii)
S ( Q ) +J.
S ( Q ) +J R ( Q l τ ) S ( Q l τ ) ( τ r > τ m ),
S ( Q ) +J S ( Q l τ ) S ( Q l τ ) ( τ r < τ m ).
(iv)
R ( Q ) + S ( Q ) .
R ( Q ) + S ( Q ) S ( Q l τ ) R ( Q l τ ) .
(v)
R ( Q ) + R ( Q ) .
R ( Q ) + R ( Q ) R ( Q l τ ) R ( Q l τ ) .
(vi)
R ( Q ) +J.
R ( Q ) +J S ( Q l τ ) R ( Q l τ ) ( τ r > τ m ),
R ( Q ) +J R ( Q l τ ) R ( Q l τ ) ( τ r < τ m ).
(vii)
J+ S ( Q ) .
J+ S ( Q ) S ( Q l τ ) R ( Q l τ ) ( τ l > τ m ),
J+ S ( Q ) S ( Q l τ ) S ( Q l τ ) ( τ l < τ m ).
(viii)
J+ R ( Q ) .
J+ R ( Q ) R ( Q l τ ) S ( Q l τ ) ( τ l > τ m ),
J+ R ( Q ) R ( Q l τ ) R ( Q l τ ) ( τ l < τ m ).

5. Results and Discussion

In the previous section, the Riemann problem and elementary wave interactions were discussed. Now, we use a numerical experiment to verify them. To facilitate the calculation of initial values, assuming that γ = 2 , k = 1 in the numerical experiment, we use the Lax–Friedrichs method, where space step d x = 0.0001 and time step d t = 0.000025 , see Table 1.
The initial values given in the table are calculated based on expressions (13)–(16) corresponding to R , S , R , and S .
The initial data are
( τ , u , F ) , x < 0 , ( τ + , u + , F + ) , x > 0 .
From Figure 7a, it can be seen that surface force and velocity increase, while specific volume decreases. According to Theorem 1, R appears. From Figure 7b, it can be seen that surface force and velocity decrease, while specific volume increases. According to Theorem 3, S appears. From Figure 7c, it can be seen that specific volume and velocity increase, while surface force decreases. According to Theorem 1, R appears. From Figure 7d, it can be seen that specific volume and velocity decrease, while surface force increases. According to Theorem 3, R appears. The results in Figure 7 validate the correctness of Section 3.
The initial data of the elementary wave interactions are as follows:
( τ , u , F ) , x < 0.01 , ( τ m , u m , F m ) , 0.01 < x < 0.01 , ( τ + , u + , F + ) , x > 0.01 .
By using the results of Figure 7 and Theorem 2, the initial values can be set to the twelve cases in Theorem 7. As long as time is long enough, the two elementary waves can interact with each other, allowing us to obtain the results of the interaction. The results can be determined based on Theorems 1–3.
From Figure 8a, it can be seen that specific volume first decreases and then increases, velocity continues to decrease, and surface force first increases and then decreases, indicating the generation of S and S . The interaction result is S S S S . Similarly, from Figure 8b, it can be seen that specific volume continues to increase, velocity first increases and then decreases, and surface force continues to decrease. Moreover, there is a point in Figure 8b where velocity and surface force are constants, but specific volume has changed. This means that the interaction result is S R R J S . From Figure 8c, it can be seen that specific volume continues to increase, velocity first increases and then decreases, and surface force continues to decrease. Moreover, there is a point in Figure 8c where velocity and surface force are constants, but specific volume has changed. This means that the interaction result is S J R J S . From Figure 8d, it can be seen that specific volume first decreases and then increases, velocity continues to decrease, and surface force first increases and then decreases. Unlike Figure 8a, there is a point in Figure 8d where velocity and surface force are constants, but specific volume has changed. This means that the interaction result is S J S J S . From Figure 8e, it can be seen that specific volume continues to decrease, velocity first decreases and then increases, and surface force continues to increase. This means that the interaction result is R S S J R . From Figure 8f, since the value of specific volume changes too much, it is replaced by its reciprocal density. It can be seen that density first decreases and then increases, velocity continues to increase, and surface force first decreases and then increases. This means that the interaction result is R R R R . From Figure 8g, it can be seen that specific volume decreases first, then increases and then decreases again, velocity first decreases and then increases, and surface force continues to increase. This means that the interaction result is R J S J R . From Figure 8h, it can be seen that specific volume decreases first, then increases and then decreases again, velocity continues to increase, and surface force continues to increase. This means that the interaction result is R J R J R . From Figure 8i, it can be seen that specific volume continues to decrease, velocity first decreases and then increases, and surface force continues to increase. Moreover, there is a point in Figure 8i where velocity and surface force are constants, but specific volume has changed. This means that the interaction result is J S S J R . From Figure 8j, it can be seen that specific volume first decreases and then increases, velocity continues to decrease, and surface force first decreases and then increases. Moreover, there is a point in Figure 8j where velocity and surface force are constants, but specific volume has changed. This means that the interaction result is J S S J S . From Figure 8k, it can be seen that specific volume increases first, then decreases and then increases again, velocity first decreases and then increases, and surface force continues to decrease. This means that the interaction result is J R R J S . From Figure 8l, it can be seen that specific volume increases first, then decreases and then increases again, velocity continues to increase, and surface force continues to decrease. This means that the interaction result is J R R J R .
Many previous theoretical studies on the equations of magnetohydrodynamics have yielded complex results, and no numerical experiments were conducted to validate the conclusions presented in this article. This article simplifies the form of the equation system by replacing variables, making the expression of the fundamental wave solution simpler. Therefore, the expression can be used to determine the initial values used in numerical experiments. The significance of this approach is as follows: Firstly, the results of numerical experiments can verify the conclusions of this paper (Theorems 6 and 7). Secondly, the model in this article is obtained through the variable transformation method, with the aim of simplifying previous models. The results of numerical experiments can prove the rationality of variable transformation. Finally, the solution of the simplified model in this article is a special case and a supplement to previous research.

6. Conclusions

Most previous studies either did not investigate the interaction of elementary waves or, if they did, lacked supporting numerical experiments. This article makes up for the shortcomings of previous research. By changing variables, the equations of magnetohydrodynamics can be simplified, and the basic wave solution expression of Riemann problems can also be simplified, thereby simplifying the study of wave interactions.
For our future research, we plan to use variable transformation methods to simplify the form of solutions in other complex equations of fluid mechanics.

Author Contributions

Conceptualization, K.Y. and G.L.; methodology, K.Y. and G.L.; software, K.Y. and G.L.; validation, K.Y., S.L. and G.L.; formal analysis, K.Y. and S.L.; investigation, K.Y., S.L. and G.L.; resources, K.Y. and G.L.; data curation, K.Y.; writing—original draft preparation, K.Y. and S.L.; writing—review and editing, G.L.; visualization, G.L.; supervision, G.L. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

No new data were created.

Conflicts of Interest

The authors declare no conflicts of interest.

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Figure 1. ( F , u ) phase divided by four fundamental wave curves starting from the left state.
Figure 1. ( F , u ) phase divided by four fundamental wave curves starting from the left state.
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Figure 2. ( F , u ) phase divided by four fundamental wave curves starting from the intermediate state.
Figure 2. ( F , u ) phase divided by four fundamental wave curves starting from the intermediate state.
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Figure 3. ( F , u ) phasewhen S ( Q l τ ) is generated in the left and middle states.
Figure 3. ( F , u ) phasewhen S ( Q l τ ) is generated in the left and middle states.
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Figure 4. ( F , u ) phasewhen R ( Q l τ ) is generated in the left and middle states.
Figure 4. ( F , u ) phasewhen R ( Q l τ ) is generated in the left and middle states.
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Figure 5. ( F , u ) phase when τ increases.
Figure 5. ( F , u ) phase when τ increases.
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Figure 6. ( F , u ) phase when τ decreases.
Figure 6. ( F , u ) phase when τ decreases.
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Figure 7. The Riemann problem with different initial values. (a) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ + , u + , F + ) = ( 2 , 0 , 1 ) . (b) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ + , u + , F + ) = ( 2 , 0 , 1 ) . (c) ( τ , u , F ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (d) ( τ , u , F ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) .
Figure 7. The Riemann problem with different initial values. (a) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ + , u + , F + ) = ( 2 , 0 , 1 ) . (b) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ + , u + , F + ) = ( 2 , 0 , 1 ) . (c) ( τ , u , F ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (d) ( τ , u , F ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) .
Symmetry 16 01425 g007
Figure 8. Elementary wave interactions with different initial values. (a) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (b) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (c) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 3 , 0 , 1 ) . (d) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1.5 , 0 , 1 ) . (e) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (f) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (g) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 15 , 0 , 1 ) . (h) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1.9 , 0 , 1 ) . (i) ( τ , u , F ) = ( 3 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (j) ( τ , u , F ) = ( 1.5 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (k) ( τ , u , F ) = ( 3 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (l) ( τ , u , F ) = ( 1.5 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) .
Figure 8. Elementary wave interactions with different initial values. (a) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (b) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (c) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 3 , 0 , 1 ) . (d) ( τ , u , F ) = ( 1 , 2 , 5 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1.5 , 0 , 1 ) . (e) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (f) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (g) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 15 , 0 , 1 ) . (h) ( τ , u , F ) = ( 8 , 2 , 0.0625 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1.9 , 0 , 1 ) . (i) ( τ , u , F ) = ( 3 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (j) ( τ , u , F ) = ( 1.5 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 1 , 2 , 5 ) . (k) ( τ , u , F ) = ( 3 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) . (l) ( τ , u , F ) = ( 1.5 , 0 , 1 ) , ( τ m , u m , F m ) = ( 2 , 0 , 1 ) , ( τ + , u + , F + ) = ( 8 , 2 , 0.0625 ) .
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Table 1. Initial data when the intermediate state ( τ m , u m , F m ) is ( 2 , 0 , 1 ) .
Table 1. Initial data when the intermediate state ( τ m , u m , F m ) is ( 2 , 0 , 1 ) .
StateWave TypeInitial Data
τ uF
left R 8−20.0625
S 125
right R 820.0625
S 1−25
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Yu, K.; Li, S.; Li, G. Riemann Problem and Elementary Wave Interactions for a Simplified Magnetic Fluid Model. Symmetry 2024, 16, 1425. https://doi.org/10.3390/sym16111425

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Yu K, Li S, Li G. Riemann Problem and Elementary Wave Interactions for a Simplified Magnetic Fluid Model. Symmetry. 2024; 16(11):1425. https://doi.org/10.3390/sym16111425

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Yu, Kangning, Shuo Li, and Guodong Li. 2024. "Riemann Problem and Elementary Wave Interactions for a Simplified Magnetic Fluid Model" Symmetry 16, no. 11: 1425. https://doi.org/10.3390/sym16111425

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Yu, K., Li, S., & Li, G. (2024). Riemann Problem and Elementary Wave Interactions for a Simplified Magnetic Fluid Model. Symmetry, 16(11), 1425. https://doi.org/10.3390/sym16111425

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