Describing and Interpreting the Space of Classroom Learning in Problem-Solving-Based Mathematics Instruction: Variation as an Analytical Lens
Abstract
:1. Introduction
2. Variation and Space of Learning
3. Problem-Solving-Based Mathematics Instruction
4. Methods
5. Results
5.1. The Space of Learning in Classroom 1
5.1.1. Lesson Structure
5.1.2. Mathematical Tasks Presented to Students
5.1.3. Patterns of Classroom Interaction
- (1)
- T: Why did you add 3 to both sides of the inequality x − 3 > 10?
- (2)
- S: To remove 3.
- (3)
- T: Is it to remove 3 or −3?
- (4)
- S: −3.
- (5)
- T: Why did the inequality sign not change?
- (6)
- S: Because that is the addition rule.
- (7)
- T: You are right. How do you determine the final solution set {14, 15, 16, …}?
- (8)
- S: Because x > 13.
- (9)
- T: Right, but it is also because the given working region (domain) is the set of natural numbers.
Episode | Instructional Activities | Dimensions of Variation |
---|---|---|
Episode 1: Reviewing/Introducing (5 min) | After checking students’ homework given in the previous day’s lesson, the teacher asked: Who can remember what you have learned last period? One student gave a response: We learned about linear equations. She then asked: What is a linear equation? Another student said: That which involves an equal sign. The teacher then said: A linear equation is an equation which can be written as ax + b = 0. She gives two sample linear equations emphasizing that a and b are constants, x is a variable and the value of x is a solution. The teacher announces the title of the lesson: Solving linear inequalities. She then asked: Do you remember the meaning of the signs ? One student gave a response. She then said: An algebraic expression involving one of these mathematical signs is said to be an inequality. | DoV1: General form of linear equation
|
Episode 2: Discussing (teacher-led + whole-class) (20 min) | The teacher wrote the following definition: Definition: An inequality is said to be a linear inequality if it is written in one of the following forms: ax + b < 0, ax + b ≤ 0, ax + b > 0, or ax + b ≥ 0, for a ≠ 0. She then provided examples to support the definition. x + 3 > 0, x + 4 ≤ 0, 2x + 1 < 0 and 3x + 7 ≥ 0 are linear inequalities. She worked on another example from the textbook: Which of the following numbers make the inequality x + 3 < 5 true? (a) −4 (b) −1 (c) 0 (d) 2 (e) 3 She demonstrated how to find solutions by substituting the given numbers. She said: The numbers −4, −1 and 0 make the inequality true. They are solutions to the inequality. There are also other solutions to it. How can we find them? She wrote the addition, subtraction, multiplication and division properties of inequalities on the blackboard. She then demonstrated the properties as follows. and 4 2 and 4 × 3 2 × 3 10 15 and 10 ÷ 5 15 ÷ 5 The teacher then provided the following example: Find the solution set for the inequality x + 4 < 7 in the given regions. (a) Set of whole numbers (b) Set of natural numbers She then found the solution interacting with students. x + 4 < 7 x + 4 − 4 < 7 − 4 x < 3 (a) solution set = {0, 1, 2} in the set of whole numbers (b) solution set = {1, 2} in the set of natural numbers | DoV3: General form of linear inequalities
DoV5: Properties of inequality
DoV7: Solution of inequalities within a specified set |
Episode 3: Discussing (group work + teacher-led demonstration) (20 min) | The teacher provided the following textbook examples: Find the solution set of each of the following inequalities. (a) x − 2 5, x is a whole number (b) 2x 10, x is a natural number (c)x 3, x is in {0, 1, 2, …, 20} (d) x + 1, x is in {1, 2, 3, … } The teacher demonstrated all the examples to the whole class. (a) x − 2 5 (b) x − 2 + 2 5 + 2 x 7 S.S = {8, 9, 10, …} S.S = {1, 2, 3, 4} (c) x 3 (d) 4(x) 4(3) x 12 S.S = {13, 14, 15, …, 20} S.S = { } | DoV8: Applying the addition property of inequalities DoV9: Applying the multiplication property of inequalities DoV10: Applying the division property of inequalities DoV7: Solution of inequalities within a specified set |
Episode 4: Practicing (15 min) | She provided the following exercises from the textbook for the students to work first in small groups and then to show to the whole class. (a) x + 4 < 8, x is in the set of whole numbers. (b) x − 2 < 7, x is in the set of integers. (c) x − 3 > 10, x is in the set of natural numbers. (d) , x is in the set of negative integers. The teacher walked around each group to check their progress. The teacher then invited four students to show their work on the black board, in parallel, and provided feedback on the four tasks. | DoV6: Applying properties of inequality DoV7: Solution of inequalities within a specified set |
Summarizing (5 min) | The teacher provided a short summary. She gave emphasis on the form of writing inequalities, properties of inequalities and the nature of a solution set. At the end, she provided homework exercises from the textbook. | DoV3: The general form of linear inequalities DoV5: Properties of inequality |
5.2. The Space of Learning in Classroom 2
5.2.1. Lesson Structure
5.2.2. Mathematical Tasks Presented to Students
5.2.3. Patterns of Classroom Interaction
- (1)
- T: What is Mahlet’s amount of money at the end of the 5th week?
- (2)
- S: 425 birr.
- (3)
- T: How do you get it?
- (4)
- S: By adding 5 to 400 five times.
- (5)
- T: Why do you add 5 five times?
- (6)
- S: Because Mahlet saves 5 birr per week.
- (7)
- T: Why do you add to 400?
- (8)
- S: Initially she has 400 birr in her account.
- (9)
- T: What is her amount of money at the end of the 10th week?
- (10)
- S: 450 birr.
- (11)
- T: How about at the end of 20th week? Does the use of variables help to get the answer?
- (12)
- T: When does Mahlet’s amount of money equal 565?
- (13)
- S: At week 33.
- (14)
- T: How do you get it?
- (15)
- S: By dividing 156 by 5.
- (16)
- T: What is 156?
- (17)
- S: 565 − 400 = 156.
- (18)
- T: So, when does it become greater than 565?
- (19)
- S: At week 34.
- (20)
- T: Why?
- (21)
- S: She saves an additional 5 birr.
- (22)
- T: Is there any other answer to it?
- (23)
- S: Yes, 35.
- (24)
- T: How about at week 37?
- (25)
- S: It is greater.
- (26)
- T: How many answers does it have?
- (27)
- S: Many.
- (28)
- T: Is there any other approach to find the answer?
Episode | Instructional Activities | Dimensions of Variation | ||||||
---|---|---|---|---|---|---|---|---|
Episode 1: Reviewing/Introducing (10 min) | The teacher started the lesson by providing the following exercises to students to work in pairs. 1. Simplify each of the following algebraic expressions into their lowest terms. (a) 12y + 12 − 6y (b) 2x + 7 + 5x − 15 + 6 − x 2. Solve each of the following equations. (a) z + 5 = 9 (b) 7n = 14 (c) 2m − 4 = 6 After checking students’ work, she summarized students’ answers to the whole class. She gave emphasis on the nature of algebraic terms, the change in variables and the use of properties of equality to solve one-step and two-step equations. The teacher announced the title of the lesson: solving linear inequalities. She then asked: What is an inequality? What is the difference b/n an equation and an inequality? Two students gave responses. In her feedback, she emphasized the difference in the meaning of the signs. She asked: What do you know about bank accounts? One student gave a response. She emphasized the key terms saving and withdrawing. She then provided the following tasks written on a piece of paper: Mahlet had 400 birr in her bank account. She saves an additional 5 birr each week in her account. Her brother Yonas had 582 birr in his account. He withdraws 8 birr each week from his savings. (a) How much money does Mahlet have in her account in the fifth week? How about in the tenth week? (b) In which week does Mahlet have 565 birr in her account? In which week is it greater than 565 birr? (c) In which week does Yonas have 422 birr in his account? In which week is it less than 422 birr? (d) At what week do Mahlet and Yonas have the same amount of money in their accounts? In which week is Mahlet’s money greater than Yonas’s money? She then announced: You can start working only on the first two. | DoV1: Adding/subtracting like terms DoV2: Change in variables
| ||||||
Episode 2: Discussing (individual + group work + whole-class) (25 min) | The teacher asked questions while checking students work as they worked individually and in small groups, encouraging them to try more than one method. She took note of some students’ work as she checked. After some time had passed, the teacher invited students to present their solutions to the whole class. She organized and orchestrated the presentation in the following way: (a) Strategy 1: 5th week: 400 + 5 + 5 + 5 + 5 + 5 = 425 birr. 10th week: 400 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 450 birr. Strategy 2: 5th week: 5× 5 = 25 birr, so 400 + 25 = 425 birr 10th week: 5× 10 = 50 birr, so 400 + 50 = 450 birr | DoV7: Multiple solution strategies
DoV10: Number of solutions
DoV12: Representations of inequalities
subtraction, addition multiplication, division DoV6: Context
| ||||||
Strategy 3: | ||||||||
Week | Money | Week | Money | |||||
1st | 405 | 6th | 430 | |||||
2nd | 410 | 7th | 435 | |||||
3rd | 415 | 8th | 440 | |||||
4th | 120 | 9th | 445 | |||||
5th | 425 | 10th | 450 | |||||
(b): | ||||||||
Strategy 1: 400 + 5 + 5 + 5 + … + 5 = 565 1w 2w 3w 33w Strategy 2: 400 + 50 + 50 + 50 + 15 = 565 10w 20w 30w 33w Strategy 3: 565 − 400 = 165. So, 165 ÷ 5 = 33. The teacher asked questions to the presenting students. | ||||||||
The teacher then connected their solution strategies and produced the following answer: | ||||||||
Week | Amount in her account | |||||||
1st | 400 + 5 | 400 + 1 × 5 | ||||||
2nd | 400 + 10 | 400 + 2 × 5 | ||||||
3rd | 400 + 15 | 400 + 3 × 5 | ||||||
4th | 400 + 20 | 400 + 4 × 5 | ||||||
5th | 400 + 25 | 400 + 5 × 5 | ||||||
6th | ||||||||
400 + w × 5 400 + 5w | ||||||||
400 + 5w = 565 | ||||||||
400 + 5w − 400 = 565 − 400 5w + 400 − 400 = 565 − 400 5w = 165 5w/5 = 165/5 w = 33 weeks. So, the money in her account is equal to 565 at the 33rd week and is greater than it at weeks 34, 35, 36, and so on. That is, 400 + 5w > 565 400 + 5w − 400 > 565 − 400 5w + 400 − 400 > 565 − 400 5w > 165 5w/5 > 165/5 So, w > 33 week. | ||||||||
Episode 3: Discussing (group work + whole class) (25 min) | The teacher then asked: Now do the remaining two questions (c and d) in your groups. She invited three students to present their work to the whole class. She organized and orchestrated the presentation in the following way:: (c): Strategy 1: 58 − 8 − 8 − 8 − … − 8 = 422 1w 2w 3w 20w So, his amount of money is equal to 422 at the 20th week and less than it at week 21, 22, 23, and so on. Strategy 2: 582 − 422 = 160. So, 160 ÷ 8 = 20. Strategy 3: 582 − 8w = 422, so w = 20 weeks. 582 − 8w < 422, so w < 20 weeks. (d): | DoV15: Type of linear inequality
DoV10: Number of solutions
DoV12: Representations of inequalities
subtraction, addition multiplication, division DoV14: Properties of inequality
| ||||||
Strategy 1: | ||||||||
Week | Mahlet | Yonas | Week | Mahlet | Yonas | |||
400 | 582 | 11th | 455 | 494 | ||||
1st | 405 | 574 | 12th | 460 | 486 | |||
2nd | 410 | 566 | 13th | 465 | 478 | |||
3rd | 415 | 558 | 14th | 470 | 470 | |||
4th | 420 | 550 | 15th | 475 | 462 | |||
5th | 425 | 542 | ||||||
6th | 430 | 534 | ||||||
7th | 435 | 526 | ||||||
8th | 440 | 518 | ||||||
9th | 445 | 510 | ||||||
10th | 450 | 502 | ||||||
Strategy 2: | ||||||||
400 + 5w = 582 − 8w 5w + 8w = 582 − 400 13w = 182 w = 182/13 = 14 week Through discussion, the teacher then provided full solution steps to the whole class. (c) 582 − 8w < 422 582 − 8w +8w < 422 + 8w 582 < 422 + 8w 582 − 422 < 422 − 422 + 8w 160 < 8w 160/8 < 8w/8 20 < w That is, w > 20 weeks. Hence, his money in his account is less than 422 after the 20th week. At the 72nd week, the money in his account will be: 582 − 8w = 582 − 8 (72) = 6 birr. That is, at w > 72 weeks, he cannot withdraw 8 birr per week for his account. (d) 400 + 5w > 582 − 8w 5w + 8w > 582 − 400 13w > 182 w > 182/13 w > 14 week Mahlet’s money is equal to Yonas’s money at week 14 and is greater at week 15 and later. | ||||||||
Episode 4: Practicing (15 min) | The teacher provided the following exercises and ordered students to work individually. Solve each of the following inequalities. (a) x + 5 < 8 (b) y − 3 > 2 (c) 2z < 10 (d) 2x − 3 > 7 (e) 4y − 1 < 3y + 8 The teacher walked around the classroom to check every student’s work. | DoV15: Type of linear inequality
subtraction, addition, multiplication, division | ||||||
Episode 5: Summarizing (5 min) | The teacher orally provided a summary through questioning in 5 min. She gave emphasis on comparing solving equations and inequalities based on the number of solutions and solution strategies. | DoV18: Difference b/n an equation and an inequality
|
6. Discussion and Conclusions
Author Contributions
Funding
Institutional Review Board Statement
Informed Consent Statement
Data Availability Statement
Conflicts of Interest
References
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Classroom 1 | CA1: Understanding the structure of linear inequalities; CA2: Understanding properties of inequalities; CA3: Applying properties of inequalities to find solution sets of linear inequalities within a specified set. |
Classroom 2 | CA1: Solving real-life problems involving linear inequalities and interpreting the results; CA2: Developing algebraic representations of linear inequalities from the patterns of arithmetic representations of linear equations; CA3: Applying properties of inequalities to solve linear inequalities. |
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© 2023 by the authors. Licensee MDPI, Basel, Switzerland. This article is an open access article distributed under the terms and conditions of the Creative Commons Attribution (CC BY) license (https://creativecommons.org/licenses/by/4.0/).
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Kassa, B.G.; Ding, L.; Tamiru, A.B. Describing and Interpreting the Space of Classroom Learning in Problem-Solving-Based Mathematics Instruction: Variation as an Analytical Lens. Educ. Sci. 2023, 13, 111. https://doi.org/10.3390/educsci13020111
Kassa BG, Ding L, Tamiru AB. Describing and Interpreting the Space of Classroom Learning in Problem-Solving-Based Mathematics Instruction: Variation as an Analytical Lens. Education Sciences. 2023; 13(2):111. https://doi.org/10.3390/educsci13020111
Chicago/Turabian StyleKassa, Berie Getie, Liping Ding, and Alemayehu Bishaw Tamiru. 2023. "Describing and Interpreting the Space of Classroom Learning in Problem-Solving-Based Mathematics Instruction: Variation as an Analytical Lens" Education Sciences 13, no. 2: 111. https://doi.org/10.3390/educsci13020111
APA StyleKassa, B. G., Ding, L., & Tamiru, A. B. (2023). Describing and Interpreting the Space of Classroom Learning in Problem-Solving-Based Mathematics Instruction: Variation as an Analytical Lens. Education Sciences, 13(2), 111. https://doi.org/10.3390/educsci13020111