1. Introduction
Under consideration is the parabolic equation
      
      where 
, 
G is a domain in 
 with boundary 
, and 
. The Equation (
1) is furnished with the initial-boundary conditions
      
      where 
, with 
 being the outward unit normal to 
, and with the overdetermination conditions
      
      where 
 is a collection of points lying in 
G. Assuming that 
 for some known functions 
, the problem consists in recovering both a solution to (
1) under (
2) and (
3) and functions 
, 
, characterizing 
g. Note that any function can be approximated by the sums of this form for a suitable choice of basis functions 
.
Inverse problems of recovering the boundary regimes are classical. They arise in many different problems of mathematical physics, in particular, in the heat and mass transfer theory, diffusion, filtration (see [
1,
2]), and ecology [
3,
4,
5,
6,
7].
A particular attention is payed to numerical solution of the problems (
1)–(
3) and close to them. Most of the methods are based on reducing the problems to optimal control ones and minimization of the corresponding quadratic functionals (see, for instance, [
8,
9,
10,
11,
12,
13,
14]). However, the problem is that these functionals can have several local minima (see Section 3.3 in [
15]). First, we describe some articles, where pointwise measurements are employed as additional data. Numerical determination of constant fluxes in the case of 
 is described in [
9]. Similar results are presented in [
16] for 
. The three-dimensional problem of recovering constant fluxes of green house gases is discussed in [
3], but numerical results are presented only in the one-dimensional case. In [
4] (see also [
5]) the method of recovering a constant surface flux relying on the approach developed in [
17] is described, where special solutions to the adjoint problem are employed (see also [
6,
7]). The surface fluxes depending on 
t are recovered in [
12,
18,
19,
20] in the case of 
, and in [
11,
21,
22] in the case of 
. The flux depending on time and spatial variables is reconstructed in [
14,
23].
In literature, there are results in the case in which additional Dirichlet data are given on a part of the boundary and the flux is reconstructed with the use of these data on another part of the boundary (see [
24]). The article [
13] is devoted to the recovering of the flux 
 (the function 
 is unknown) with the use of final or integral overdetermination data. The existence and uniqueness theorems for solutions to the inverse problems of recovering the surface flux with the use of integral data are presented in [
25,
26].
There is a limited number of theoretical results devoted to the problem (
1)–(
3). We refer the reader to the article [
27] (see also [
28]), where, in the case of 
, 
, and 
, the existence and uniqueness theorems of classical solutions to the problem (
1)–(
3) are established. In contrast to our case, the problem is well-posed in the Hadamard sense. If the points 
 are interior points of 
G then the problem becomes ill-posed and this fact was observed in many articles (see [
29]). In this article we describe a new approach to the existence theory of solutions to this problem and establish the corresponding existence and uniqueness theorems. We hope that these results can be used in developing new numerical algorithms for solving the problem.
  2. Preliminaries
Let 
E be a Banach space. By 
 (
G is a domain in 
), we mean the space of 
E-valued measurable functions such that 
 [
30]. The symbols 
 and 
 stand for the Sobolev spaces (see the definitions in [
30,
31]). If 
 or 
 then the latter spaces is denoted by 
. The definitions of the Hölder spaces 
 can be found in [
32]. By the norm of a vector, we mean the sum of the norms of coordinates. Given an interval 
, put 
 and, respectively, 
. Denote by 
 the inner product in 
. Let 
 designate the distance between the sets 
. In this case, 
 is the distance from a point 
x to 
. Denote by 
 the ball of radius 
 centered at 
x.
We say that a boundary 
 of a domain 
G belongs to 
, 
 (see the definition in Chapter 1 in [
32]) if, for each point 
, there exists a neighborhood 
 about 
 and a coordinate system 
y (the local coordinate system) obtained from the initial one by the translation of the origin and rotation such that the axis 
 is directed as the interior normal to 
 at 
 and the equation of the part 
 of the boundary is of the form 
, 
, 
; moreover, 
 (where 
), 
, and 
. The smoothness of 
, with 
 an open subset of 
, is defined similarly. The numbers 
 for a given 
G are fixed and we can assume without loss of generality that 
, with 
M the Lipschitz constant of the function 
. We employ the straightening of the boundary, i.e., the transformation 
, 
, 
, with 
y the local coordinate system at a given point 
b.
Below, we assume that 
 or 
G is a domain with compact boundary of the class 
. The coefficients of the Equation (
1) are assumed to be real. We consider an elliptic operator 
L, i.e., there exists a constant 
 such that
      
Assign 
 for 
 and 
 for 
. The symbol 
 stands for an inner product in 
. Let
      
      and assume that
      
Moreover, we suppose that the functions 
 admits extensions to the whole 
 such that the condition (
5) is valid in 
. If 
G is a domain with compact boundary of the class 
 such an extension always exists (see Theorem 1 in Subsection 4.3.6 of Section Remarks in [
33]). Consider the equation
      
      where the operator 
 is a formal adjoint to 
L. Its coefficients also satisfy (
5). Let 
. Introduce the functions 
, 
. It follows from Theorems 3.5 and 3.1 in [
34] and Theorem 3.3 in [
35] that
Theorem 1. Assume that  and the conditions (5) hold. Fix . Then there exists a number  such that, for all λ with , there exists a unique solution  to the Equation (6) decreasing at ∞ such that  for all , and  for all , . In every domain  a solution  admits the representation  In what follows, we denote by  a solution  obtained in Theorem 1 for a given j.
Consider the problem
      
      where 
 or 
 or 
G is a domain with compact boundary of the class 
.
Theorem 2. Let , , , and . Then there exists a number  such that, for all λ with , there exists a unique solution  to the problem (
11).
  The theorem results from Theorem 5.7 for 
, Theorem 7.11 for 
 and Theorem 8.2 in the case of a domain with compact boundary in [
31].
The following Green formula holds.
Lemma 1. Let the conditions (5) hold and let , where  is chosen so that Theorem2
is valid for . If  is a solution to the problem (
11) 
with  from the class specified in Theorem2
then If  and  in some neighborhood about , then  Proof.  The proof is conventional. It suffices to approximate the functions 
 by sequences of smooth functions in the corresponding norms, to write out the above Formulas (
12) and (
13) for these approximations, and pass to the limit.    □
 Assume that  or G is a domain with compact boundary of the class . Given a collection of points , construct the points  such that . Denote by  the set of these points. Let . For , there exists a local coordinate system y such that the axes  agree with the principal directions on the surface  at , in this case,  where  are the principal curvatures of the surface   at 0. In the case of , the equation of the boundary in some neighborhood about b is of the form  and  is the curvature of the curve  at b.
Lemma 2. Assume that, for every , the set  consists of finitely many points and, for every , we havewhere  are principal curvatures of Γ for  and κ is the curvature of Γ for  at b. Then there are constants ,  such that  for every  and all , .  Remark 1. For , the condition (14) can be reformulated as follows. There exists a constant  such that  where y is a local coordinate system at . The claim follows from the fact that there exists an orthogonal transformation of coordinates such that the new axes  agree with the principal directions on the surface Γ at .  Proof.  Take 
. We prove the claim in the case of 
. If 
 then the proof is simpler and we omit it. Let 
y be a local coordinate system at 
b. Since 
 is a superposition of an orthogonal transformation and a translation, the distances between points and their images are the same. We have 
, 
, 
, 
, 
, 
, and
        
Remark 1 implies that
        
        in some neighborhood about 0. Fix a parameter 
 such that 
. In this case there exists 
 such that
        
        for 
. Therefore, we obtain
        
The converse inequality follows directly from the definition of the quantity J.
Below, we preserve the notations of Lemma 2. Take 
. We can define the transformations 
 and 
. For 
, put
        
        where the parameter 
 is chosen below. The map 
 takes 
 onto 
. Similar notations are used in the case of 
, i.e.,
        
Below, we assume that, for every 
, the set 
 consists of finitely many points and
        
        where 
 are the principal curvatures of 
 for 
 and, respectively, 
 is the curvature of 
 for 
.
Let 
 be a solution to the Equation (
6). Given 
, construct the point 
 lying on the straight line joining 
 and 
b and such that 
, 
. The point 
 is symmetric to 
 with respect to the surface 
. Let 
 be a solution to the Equation (
6), where the point 
 is replaced with 
. Denote by 
 the functions defined by the equality (
4), where 
 is replaced with 
. In what follows, we assume that the closures of coordinate neighborhoods about the points 
 are disjoint, otherwise, we can always reduce them. Fix a point 
. The quantity 
 is positive (it depends on 
 and the angles between the vectors 
 and 
). Let 
 (where 
 is the coordinate neighborhood about 
b). Without loss of generality, we can also assume that the constant 
 is positive for all 
 and all 
j, otherwise, we decrease the parameter 
 of the coordinate neighborhoods 
. Denote by 
 a constant smaller than the minimum of these constants. Theorem 1 for 
 and 
 yields
        
        where 
 and 
 are constants independent of 
j, 
, and 
 such that 
.    □
 Lemma 3. Assume that the conditions (5) and (15) hold,  , andfor some . Then there exists a number  such that, for , we have the representation  Proof.  Consider the case of 
. We have
        
Theorem 1 implies that
        
        where 
. We can assume that 
 for all such 
 and 
j. To estimate the second integral 
 on the right-hand side of (
22) from above, we derive that
        
In view of the definitions, there exists a constant 
 such that 
 for all 
 and, thereby,
        
        for some constant 
. For the first summand 
 on the right-hand side of (
22), we have
        
Consider the last integral in (
25) that is multiplied by 
. This quantity is written as
        
        where 
 is the point 
 written in the coordinate system 
y. Consider the integral 
 We can assume that the axes of the local coordinate system 
y are directed as the principal directions on 
 at 
b. In this case (see Lemma 2) we obtain that
        
        where 
 is a 
-function in some neighborhood about 0. Make the change of variables 
 in 
. We obtain that
        
Introducing the polar coordinate system, we arrive at the expression
        
Integrating by parts yields
        
The last integral here admits the estimate
        
The second integral on the right-hand side is estimated as
        
        where 
 is a positive constant. Thus, we establish the representation
        
Introducing the polar coordinate system, we infer
        
Making the change of variables 
, we obtain the estimate
        
This inequality and (
24) imply that
        
        where the constant 
 is independent of 
. In this case the last integral 
 on the right-hand side of (
26) admits the estimate
        
In view of (
28), the previous integral 
 in (
26) (
) is estimated as follows: 
 Finally, the second summand on the right-hand side of (
25) is representable as
        
In view of our conditions on the coefficients, 
 for every compact set 
, and thereby, 
. Involving the condition of the lemma and (
28), we can estimate the integral 
 on the right-hand side of (
25) by
        
The representation (
29) and the estimate (
30) validate the equality (
18). The equality (
19) is proven analogously and the former equalities in (
20) and (
21) are consequences of (
18) and (
19). The proof in the case of 
 is simpler. Display the asymptotics of the main integral
        
        where 
, 
 is the local coordinate system at 
b, and 
 is the equation of the curve 
. To reduce arguments, we take 
, where the parameter 
 is defined in Lemma 2. Theorem 1 implies that
        
As before, we have 
 . We have the asymptotic formula (see 
Section 1 , Chapter 2 in [
36])
        
        where 
 is a point in which 
S reaches its maximum. Applying this formula to the first integral on the right-hand side of (
31) and estimating the second integral by 
, we obtain
        
All other arguments are similar. The proof in the case of  is even simpler and we omit it.
It remains to prove the latter inequalities in (
19) and (
20). As before, take 
. The asymptotics from Theorem 1 ensure that
        
        where 
 If 
 then we have
        
This equality and the previous arguments validate the claim.    □
 Remark 2. Let . Then the condition (15) holds if  for all j.  We consider the problem (
11), where 
, i.e., the problem
      
      and we obtain some estimates of its solution. Fix 
j and take 
. In Lemma 4 below, we use functions 
 such that 
 on the set 
 and 
. The condition 
 ensures the inclusion 
. The map 
, 
 takes a neighborhood 
 onto the set 
. Denote 
 and 
.
Lemma 4. Assume that the conditions (5) hold, , and . Then there exists a number  such that, for , there exists a unique a solution to the problem (33) and (34) in the space  satisfying the estimates If , with φ from the above-described class of functions, then there exist constants  such thatwhere  is arbitrarily small constant. If additionally  andthen  for any φ and there exist constants  such that  Proof.  Theorem 2 for 
 ensures the existence and uniqueness of solutions provided that 
 for some 
. Multiply the Equation (
33) by a function 
 and integrate the result over 
G. Integrating by parts, we infer
        
Separating the real and imaginary parts, we obtain
        
Summing (
42) and (
41) and estimating the modules of the right-hand sides
        
Below, we use the inequality
        
The last integral is estimated by
        
Similarly, we have
        
        where 
 and 
 are arbitrary positive constants. The embedding theorems and interpolation inequalities (see [
30]) imply that
        
Estimating the right-hand side of (
43) with the use of (
44) and (
45), we arrive at the inequality
        
Choosing sufficiently small 
 and increasing 
, if necessary, we derive that
        
        where the constant 
 is independent of 
 with 
 and 
 can be taken arbitrarily small. Using (
46) and interpolation inequalities we obtain that
        
        and the estimate (
35) is proven. Rewriting (
33) in the coordinate system 
y, we obtain the problem
        
Multiply the equation (
47) by 
. The result is the problem
        
Introduce the coordinate system 
z, with 
, 
. In this case, the function 
 is a solution to the problem
        
Multiplying the Equation (
50) by 
 and integrating the result over 
U, we obtain that
        
Integrating by parts, we rewrite the first summand in the form
        
Note that 
 and integrating by parts we obtain the integrals containing third order derivatives. However, the result of integration is easily justified if we employ smooth approximations of functions in 
. Similar arguments can be found, for instance, in the proof of Lemma 7.1 of Chapter 3 in [
37]. We also have
        
Using (
52)–(
54) in (
51), we obtain
        
As it is seen, the inequality
        
        is valid for some constant 
. Next, we infer
        
        where 
 is the space with the norm 
, 
, 
 is arbitrary, and the last summand is estimated by 
 (see (
46)). Here we rely on the conventional theorems on pointwise multipliers and Proposition 12.1 of Chapter 1 in [
38]. Next, repeating the arguments of the proof of the estimate (
46), we conclude that
        
To establish (
37), it suffices to prove the estimate
        
        which is justified by repeating of the proof of (
35). To validate the second part of the claim, we first demonstrate the smoothness of a solution 
w. Take an arbitrary point 
 and the set 
. Construct a function 
 such that 
. The function 
 is a solution to the Equation (
48) from the space 
 satisfying (
49) on 
 and
        
Using the conventional theorems on extension of boundary data inside the domain [
30] and Theorem 
Section 3 of Chapter 4 in [
39], we conclude that 
.
Consider the equation (
50). Multiply (
50) by 
 and integrate the result over 
U. The same arguments as those of the proof of the estimate (
36) can be applied to justify (
37) and (
39). The calculations are rather cumbersome and we omit them.    □
 Assume that the conditions (
5) and (
15) hold. In this case, for every 
j and 
, we can consruct the balls 
 and 
. Let 
 (where 
).
Lemma 5. Let the conditions (5) and (15) hold. Then, for every , there exists a function  and constants  such that  for ,  for , and  for all .  Proof.  In view of (
15), it is not difficult to establish that there exists a parameter 
 such that 
 for all 
 and 
 for all 
. Put 
. Obviously, 
. Take 
. Construct a nonnegative function 
 such that 
, 
 and the averaged function
        
        where 
 is the characteristic function of the set 
. By construction, 
 for 
 and 
 for 
. This function satisfies our conditions.    □
 The following theorem results from Theorem 7.11 for 
 and Theorems 8.2 in the case of the domain with compact boundary in [
40].
Theorem 3. Assume that  and . Then there exists a constant  such that if  and the condition (
56)
holds then there exists a unique solution to the problem (
1) and (
2)
such that  and  Let 
E be a Hilbert space. Denote by 
 the space of functions 
u defined on 
 whose zero extensions 
 to the negative semiaxis belong to 
 and
      
The Laplace transform 
 is an isomorphism of this space 
 onto the space 
 of analytic functions in the domain 
 such that
      
If 
 or 
 or 
 (
G is a domain in 
) then these properties of the Laplace transform can be found in [
41] (see Theorem 7.1 and Section 8). For 
, we similarly define the space 
 as the subspace of functions in 
 admitting the zero extensions for 
 of the same class. This space coincides with 
 for 
 and with the space of functions 
 such that 
 for 
. For 
, it coincides with the space of functions in 
 such that 
 [
41].
  3. Basic Results
We assume here that the conditions (
5), (
15), (
17) are fulfilled. Let 
 be the matrix with entries 
. We assume that
      
Fix a parameter 
 greater than the maximum of the parameters defined in Theorem 1 with 
, Theorem 2 with 
, and Theorem 3. We assume that
      
By Theorem 3, if the condition (
60) holds for some 
, then there exists a unique solution 
 to the problem (
1) and (
2), where 
, such that 
. Consider the problem (
1)–(
3). Changing the variables 
, we obtain the simpler problem
      
We assume that 
 and
      
      where 
 for 
 and 
 for 
. For 
, the condition (
63) can be rewritten as
      
For a finite 
T, the condition (
63) can be stated as follows: there exists an extension of 
 on 
 satisfying (
64). We have 
 for 
 and 
 for 
. Here 
 is the Hankel function. The latter equality is derived in Lemma 1.6.7 in [
42]. The former can be easily obtained if we use the Poisson formula for a solution to the Cauchy problem for the heat equation with the right-hand side equal to the Dirac delta function.
Theorem 4. Assume that  and the conditions (
5), (
15), (
58), (
59)
, and (
38)
for  hold. Then there exists  such that, if  and the conditions (60), (63) are fulfilled, then there exists a unique solution to the problem (
1)–(
3)
such that , .  Proof.  Consider the equivalent problem (
61) and (
62). Assuming that 
 and applying the Laplace transform to (
61), we arrive at the problem
        
Next, we use the functions 
 constructed before Lemma 3. Theorem 1 yields 
, 
 for all 
, 
. Construct the functions 
, 
, where the functions 
 are defined in Lemma 5. The properties of the functions 
 imply that 
. Lemma 1 imply that
        
        where the function 
 is a solution to the problem (
65). Consider the case of 
. The case of 
 is considered analogously. For the integral on the left-hand side, we have
        
However, only two summands with 
 and 
 are essential on the set 
. Indeed, in view of (
16), for 
 and 
, we infer
        
        where 
 is a constant independent of 
. This inequality implies that the remaining integrals decay exponentially. By Lemma 3, we have
        
Consider the right-hand side in (
67). The integrals over the domain are estimated by means of Lemma 5. On the support of 
, Theorem 1 and Lemma 5 ensure the estimate
        
        where the constants 
 are independent of 
. The Hölder inequality yields
        
Examine the integrals over 
 in the right-hand side of 
. We have
        
As in the estimate (
69), the last two integrals are estimated by
        
        in view of (
16). Estimate the second and third integrals. In view of Theorem 3 and estimates of Lemma 5 (see (
27)), they admit the estimates
        
        where 
 is the straightening of the boundary in 
. It remains to consider the first integral
        
Note that 
. Lemma 5 ensures the following representation for the first integral 
 on the right-hand side of (
71):
        
The second integral on the right-hand side of (
71), in view of Lemma 5, (
28) and (
32), is estimated as follows:
        
Thus, in view of (
70)–(
72), we have the inequality
        
        with some constant 
. Next, we employ Lemma 4. The embedding theorems for 
 and Lemma 4 imply that
        
        where 
 is an arbitrarily small constant. Similarly, Lemma 4 ensures that
        
In view of the conditions on the functions 
, there exists a constant 
 such that
        
Therefore, we have the estimate
        
        where 
 is an arbitrarily small constant. We can rewrite (
67) in the form
        
The left-hand side of this equality is written as 
, where the entries of the matrix 
 are of the form 
. The right-hand side is written in the form
        
        where the coordinates of the vectors 
 are as follows:
        
Choose 
 so that the matrix 
 is invertible for 
 and the norm of the operator 
 is bounded by a constant 
 for all 
. It is more convenient to rewrite the system (
74) in the form
        
Estimate the norm of the operator 
. In view of (
73), we have the estimate
        
Thus, for 
, increasing the parameter 
 if necessary, we can assume that 
 The norm of the operator 
 is less than 1/2 in this case and, thereby, the Equation (
75) has a unique solution. Constructing a solution 
 to the Equation (
75), we can find a solution 
 to the problem (
61), where 
. In view of our conditions, the estimates of Lemma 4 holds. In view of the Equation (
75), a solution 
 meets the estimates 
 Hence, we infer
        
        where the constant 
 is independent of 
. The properties of Laplace transform validate the equality 
 and the previous inequality yields
        
This inequality ensures that the inverse Laplace transform is defined for the functions 
, 
, and
        
Note that the additional smoothness of the functions 
 ensures the additional smoothness of the functions 
. Consider the problem (
61) with the above constructed functions 
. By Theorem 3, there exists a unique solution to this problem such that 
. We now demonstrate that this function satisfies (
62). Indeed, applying the Laplace transform, we obtain that 
 is a solution to the problem (
65). Multiplying the equation in (
65) by 
 and integrating by parts we obtain (
67) with 
 rather than 
. Since 
 satisfy (
67) with the functions 
 on the right-hand side, we obtain 
.
In the case of 
, the arguments are the same. However, in view of another asymtotics of the function 
 the inequality (
78) can be rewritten as
        
Uniqueness clearly follows from the above arguments.    □
 If we state our theorem in the case of a finite interval 
, then the condition (
60) looks as follows:
Theorem 5. Assume that  and the conditions (
5), (
15), (
58), (
59), (
79), (
63) 
and (
38) 
for  hold. Then there exists a unique solution to the problem (
1)–(
3)
such that , .  Proof.  Extend the functions 
 on 
 as compactly supported functions of the same class. The conditions (
63) are fulfilled for every 
. Extend the function 
f by zero on 
. Theorem 4 ensures existence of a solution to the problem (
1)–(
3). Now we prove uniqueness of solutions. Assume that there are two solutions of the problem from the class pointed out in the statement of the theorem. In this case, their difference 
 is a solution to the problem
        
Integrating the equation and the boundary condition with respect to time two times, we obtain that the function 
 is a solution to the problem
        
Make the change of variables 
 (
). We have
        
Integrating (
82) over 
, we obtain that
        
Let 
. Make the change of variables 
, with 
 a solution to the problem 
, 
, and, respectively, 
 is a solution to the problem
        
Note that 
 and, thereby, 
. Since 
 [
30], we have the estimate (see Theorem 7.11 for 
 and Theorem 8.2 in the case of a domain with compact boundary in [
31])
        
Multiply the Equation (
85) by the function 
 defined in the proof of the previous theorem and integrate over 
G. As in the proof of Theorem 4, we obtain the system (see (
75))
        
        where the coordinates of 
 are written as 
. The system can be rewritten as follows
        
        where the right-hand side is analytic for 
 and we have
        
        where 
 is independent of 
. Thus, every of the quantities 
 is estimated by
        
The function 
 is the Laplace transform of the function 
 for 
 and 
 for 
. Fix 
 and define an additional function 
. It is analytic in the right half-plane and is bounded by some constant 
 on the real semi-axis 
. To estimate this function on the on the imaginary axis, we integrate by parts as follows:
        
For 
, we thus have the estimate
        
In each of the sectors 
, 
 the function 
 admits the estimate
        
Applying the Fragment-Lindelef Theorem (see Theorem 5.6.1 in [
43]) we obtain that in each of the sectors 
, 
 the function 
 admits the estimate
        
Therefore, 
 We have equality (
)
        
        and, thereby,
        
The Parseval identity yields
        
Since this inequality is true for all ,  for . Since the parameter  is arbitrary,  for  and  for  and every j and, therefore,  which implies that .    □