3. IVIF Filters in Hoop Algebra
In this section, we systematically develop the theory of interval-valued intuitionistic fuzzy (IVIF) filters within hoop algebras. We first introduce the formal definitions and axiomatic conditions that characterize IVIF filters, and present algorithmic procedures for their verification. The section proceeds to establish fundamental properties and alternative criteria for IVIF filters, including their closure under intersection and their relationships with sub-hoops and classical fuzzy filters. Through detailed examples and proofs, we illustrate the construction and behavior of IVIF filters and their various subclasses, such as implicative IVIF filters. Additionally, we investigate the lattice-theoretic structure of IVIF filters, congruence relations induced by filter properties, and the connections between interval-valued fuzzy sets, sub-hoops, and generated filters. The results in this section provide a comprehensive framework for understanding and analyzing uncertainty propagation in hoop algebras under interval-valued intuitionistic fuzzy logic.
Definition 7.
An IVIF set in a hoop is defined as an IVIF filter of if the following conditions hold for any operation : Now, we provide a pseudocode to determine whether a given IVIF set in a hoop fulfills the criteria to be an IVIF filter of .
Algorithm 1 systematically verifies whether a given pair of functions defines an IVIF filter on the hoop . The algorithm operates as follows:
For every pair of elements
and for each operation
, it checks the filter conditions:
If either condition fails for any pair or operation, the algorithm returns False.
Additionally, for every pair
such that
, it verifies the monotonicity conditions:
If either monotonicity condition fails, the algorithm returns False.
If all conditions are satisfied for all relevant elements and operations, the algorithm concludes that constitutes an IVIF filter of and returns True. This procedure provides a rigorous and efficient means for confirming the IVIF filter property in the context of hoops.
Proposition 2.
Let be a hoop algebra. For every element , the condition holds.
Proof. By using the relation
in (
1) and Proposition 1
, we conclude that the inequality
is satisfied for all elements
. □
Algorithm 1: Verifying an IVIF filter in a hoop |
![Symmetry 17 01411 i001 Symmetry 17 01411 i001]() |
This elementary ordering fact justifies repeated use of the unit element as a universal upper benchmark when deriving monotonicity constraints on interval membership and non-membership functions in later theorems.
Definition 8.
An IVIF set in is called an IVIF sub-hoop of if for any Proposition 3.
For every IVIF sub-hoop of , the following holds: Proof. Since
for all
, the result follows directly from (
12). □
Example 1.
Let be a set with two binary operations, ⊙
and →, defined by the following Table 2 and Table 3. The binary operation → on is given by the Cayley table below, where the entry in the i-th row and j-th column corresponds to the value of for .
Similarly, the binary operation ⊙ on is defined by the following Cayley table, where the entry in the i-th row and j-th column is .
Then is a hoop algebra.
Let in H be an IVIF set in given by Table 4. Table 4 presents the IVIF set on . For each , the table lists the corresponding interval-valued membership degree and non-membership degree . Each entry is an interval in , reflecting the degree of membership and non-membership of each element in the set . Let in H be an IVIF set in given by Table 4. Then it is easy to check that the IVIF set in is an IVIF filter of .
Theorem 1.
An IVIF set is an IVIF filter of if and only if it satisfies (12) and the following condition: Proof. Let
be an IVIF filter of
. Since
for all
, it follows from (
10) that (
12) is satisfied. For any
, we know that
. By using (
9) and (
10), we obtain the following:
and
which proves (
13).
Conversely, suppose that an IVIF set
satisfies both (
12) and (
13). Let
. Since
it follows from (
12) and (
13) that
and similarly,
Next, suppose that
such that
. Then
, and we have
Thus,
satisfies the conditions to be an IVIF filter of
. □
The above theorem furnishes a residuation-style criterion for IVIF filters, reducing global closure requirements to a local implicational inequality. This facilitates both algorithmic verification (by testing pairs) and a logical reading: membership propagation mirrors modus ponens–like reasoning under interval uncertainty.
Theorem 2.
Every IVIF filter is a sub-hoop of the IVIF.
Proof. This result is straightforward. □
This embeds the fuzzy deductive layer into the underlying algebraic skeleton: any uncertainty-resilient deductive structure (IVIF filter) simultaneously preserves the binary operations. Hence, classification of IVIF filters can exploit sub-hoop invariants and structural decompositions.
The Converse of Theorem 2 may not be true as seen in the following example.
Example 2.
Let be Consider a Hoop algebra in Example 1. Let in H be an IVIF set in H given by the Table 5: Then the IVIF set in H is an IVIF sub-hoop of H but it is not an IVIF filter of since This counterexample delineates the strictness of the hierarchy “IVIF sub-hoop” vs. “IVIF filter” preventing overgeneralization and clarifying which closure axioms truly encode deductive propagation.
Definition 9.
Let be an interval-valued intuitionistic fuzzy (IVIF) set in . We say that is an intuitionistic fuzzy filter of if, for all and for every binary operation , the following conditions are satisfied:
- (i)
and ,
- (ii)
,
- (iii)
.
The following pseudocode determines whether a given IVIF set on a hoop fulfills the axiomatic conditions of an intuitionistic fuzzy filter of .
Algorithm 2 systematically checks whether a given pair of functions defines an intuitionistic fuzzy filter on the hoop . The procedure is as follows:
For each element
, the algorithm first verifies the normalization conditions:
If either condition fails, the algorithm returns False.
Then, for every pair
and for each operation
, it checks the filter conditions:
If either of these is not satisfied for any combination, the algorithm returns False.
Algorithm 2: Verifying an intuitionistic fuzzy filter in a hoop |
![Symmetry 17 01411 i002 Symmetry 17 01411 i002]() |
If all conditions are met for all elements and operations, the algorithm concludes that is an intuitionistic fuzzy filter of and returns True. This approach provides a precise and reliable method for verifying the intuitionistic fuzzy filter property in hoops.
Theorem 3.
Let be an interval-valued intuitionistic fuzzy (IVIF) set in . Then, is an IVIF filter of if and only if each of , , , and is an intuitionistic fuzzy filter of .
Proof. Since , , and , and .
Let
. Then for any
, we have
and
Hence,
is an IVIF filter of
H.
Conversely, assume that
is an IVIF filter of
. Let
. Then,
; hence,
and
. Let
. Then
Hence,
and
. Also
Then we have
and
Therefore,
and
are fuzzy filters of
. □
By reducing the interval-valued intuitionistic constraints to four scalar fuzzy filters, this result enables modular verification and translation of existing fuzzy filter theory into the IVIF framework, improving both implementability and reuse of classical results.
Definition 10.
Let and be two IVIF filters of . The union of these filters, denoted as , is defined by:for all . Similarly, the intersection of the filters, denoted as , is defined byfor all . Proposition 4.
If and are IVIF filters of , then is an IVIF filter of .
Proof. Let and be IVIF filters of .
Let
. Then we have
and
Let
. Then we get
and
Hence
is an IVIF filter of
. □
Closure under intersection shows that the IVIF filters form a complete meet-semilattice, allowing construction of the least filter containing a given family—essential for generated filters and lattice-theoretic semantics.
In contrast, the union of two IVIFFs need not be an IVIFF in general. This is because the union operation, which uses the maximum for the membership function and the minimum for the non-membership function, may fail to preserve the required filter conditions. In particular, the following filter condition may fail for the union:
for some
and
.
To illustrate an counterexample, consider two IVIFFs
and
on
such that for some
,
It is possible that
thus violating the filter condition.
Therefore, the set of all IVIFFs on is closed under intersection but not necessarily under union. This set forms a complete meet-semilattice, but not a lattice, with respect to the pointwise-defined intersection operation.
Corollary 1.
If is an IVIF filter of , then is also an IVIF filter of .
Complement stability provides a dualization principle, ensuring that reasoning about acceptance (membership) and rejection (non-membership) can be symmetrically interchanged without loss of algebraic fidelity.
Theorem 4.
If is an IVIF filter of , then both and are IVIF filters.
Proof. Assume that is an IVIF filter of . Let . Then .
Let
. Then
Hence
is an IVIF filter of
.
Let
.
Then
. Let
. Then
Hence
is an IVIF filter of
. □
These operations formalize two dual uncertainty transformations—attenuation vs. reinforcement—while preserving filterhood. They model controlled revisions of evidence intervals in dynamic inference settings.
Theorem 5.
An IVIF set is an IVIF filter of if and only if, for every , the sets and are either empty or filters of .
Proof. Let be an IVIF filter of , and suppose are such that and are non-empty sets of H. Then, , since and .
Let such that . Then, we have and . Hence, , which implies . Therefore, is a filter of .
Now, let and . Then, and . Thus, , so . Consequently, is a filter of .
Next, assume that every non-empty set and are filters of . If does not hold for all , then there exists such that . In this case, take . Then, , which means . Since is a filter of , we must have , a contradiction. Therefore, for all .
If is not true, then there exists such that . In this case, take . Then, , meaning . Since is a filter of , it must hold that , which leads to a contradiction. Hence, for all .
Now, assume that is not true for all . Then there exist such that . Taking , we have , which shows that . Since is a filter of , we obtain , a contradiction. Thus, for all .
Finally, suppose that is not true for all . Then there exist such that . Taking , we find , which shows that . Since is a filter of , we conclude , a contradiction. Therefore, holds for all .
Hence, is an intuitionistic fuzzy filter of . □
A cut-based criterion links the graded (interval-valued) semantics with classical crisp filters, enabling a bridge between quantitative uncertainty representations and qualitative logical abstraction; useful for threshold-driven decision systems.
Theorem 6.
For any IVIF set is an IVIF filter of if and only if it satisfies (12) and Proof. () Assume that is an IVIF filter of , and let .
Since
and
, by the monotonicity property (
10), we have
so
Similarly,
and hence
Multiplying both sides by
r (where
), we obtain
On the other hand, since
, by properties (
13) and (
10), we have
By the filter property (
12), we get
Similarly, for the non-membership function,
and hence
Combining the above inequalities, we deduce
which is exactly (
14).
(
) Conversely, suppose that
satisfies (
12) and (
14). For any
, since
, by the monotonicity property (
12), we have
By (
14),
Thus,
Similarly,
Therefore, by Theorem 1,
is an IVIF filter of
. □
Replacing inequalities by equalities isolates “tight” IVIF filters where conjunctive aggregation is maximally information-preserving. This subclass is important for canonical representations and extremal model analysis.
Theorem 7.
An IVIF set is an IVIF filter of if and only if it satisfies (12) and Proof. Assume that
is an IVIF filter of
and let
. Since
, we have
and
by (
10) and (
14).
Conversely, suppose that
satisfies (
12) and (
15). If we set
in (
15), we obtain (
13). Therefore,
is an IVIF filter of
by Theorem 1. □
This theorem provides a practical criterion for identifying IVIF filters based on their behavior under implication operations. It simplifies the classification and analysis of filters, enhancing their applicability in modeling and reasoning with interval-valued intuitionistic fuzzy information.
Theorem 8.
An IVIF set is an IVIF filter of H if and only if it satisfies (12) and Proof. Assume that
is an IVIF filter of
and let
. Note that
. Using (
10) and (
14), we get
and
Conversely, suppose that
satisfies (
12) and (
16). If we take
in (
16), we obtain (
13). Therefore,
is an IVIF filter of
by Theorem 1. □
This theorem offers an alternative criterion for characterizing IVIF filters using both the product and implication operations, making filter identification more systematic. It thus aids in the efficient analysis and application of IVIF filters in fuzzy modeling and reasoning contexts.
Theorem 9.
An IVIF set is an IVIF filter of H if and only if it satisfies Proof. Assume that
is an IVIF filter of
and let
be such that
. Then
, and so
It follows that
and
Conversely, suppose that
satisfies (
12) and (
17). Since
for all
, it follows from (
17) that
Hence,
is an IVIF filter of
by Theorem 1. □
This theorem presents a useful order-based criterion for IVIF filter characterization, linking the structure of the set to its membership and non-membership functions. It streamlines the process of identifying filters, supporting more effective modeling and reasoning in interval-valued intuitionistic fuzzy environments.
Theorem 10.
An IVIF set is an IVIF filter of if and only if it satisfies (12) and Proof. Suppose that
is an IVIF filter of
. Since
and
for all
, we have
and
Conversely, assume that
satisfies (
12) and (
19). If we take
in (
19), we obtain (
13). Therefore,
is an IVIF filter of
by Theorem 1. □
The above theorem provides another implication-based criterion for identifying IVIF filters, focusing on the relationships between nested implications and membership functions. It further simplifies the recognition and analysis of filters in interval-valued intuitionistic fuzzy frameworks.
Definition 11.
An IVIF set is called an implicative IVIF filter of if it satisfies the condition (12) and This definition introduces the concept of an implicative IVIF filter, characterized by a specific implication-based condition involving three elements. It establishes a framework for studying more specialized filter structures in interval-valued intuitionistic fuzzy sets.
Now, we give a psudecode for above definition as follows:
Algorithm 3 provides a step-by-step procedure to verify if a given IVIF set is an implicative IVIF filter of the hoop . The verification process is as follows:
Algorithm 3: Verifying an implicative IVIF filter in a hoop |
![Symmetry 17 01411 i003 Symmetry 17 01411 i003]() |
If all these conditions are met, the algorithm concludes that is an implicative IVIF filter of and returns True. This approach ensures rigorous verification of the implicative property for IVIF filters in hoops.
Example 3.
Let be a set with the binary operations ⊙ and → defined as follows.
The binary operation → on is specified by the Cayley Table 6 below. In this table, the entry in the i-th row and j-th column gives the result of , where . Similarly, the binary operation on is defined by the following Cayley Table 7. Each entry in the i-th row and j-th column represents the value . Then is a hoop algebra.
Table 8 presents the IVIF set on . For each , the table lists the interval-valued membership degree and non-membership degree . These intervals indicate the degree to which each element belongs or does not belong to the set . It is easy to check that the IVIF set in is an implicative IVIF filter of .
Theorem 11.
Every implicative IVIF filter is an IVIF filter.
Proof. Let
be an implicative IVIF filter of
. If we take
in (
20) and use Proposition 1
, then we obtain (
13). Therefore,
is an IVIF filter of
by Theorem 1. □
This theorem shows that every implicative IVIF filter automatically satisfies the conditions of an IVIF filter. Thus, the class of implicative IVIF filters forms a subclass within the broader family of IVIF filters.
The converse of Theorem 11 may not be true as seen in the following example.
Example 4.
Consider the IVIF filter of the hoop algebra given in Example 1. We now show, by explicit calculation, that is not an implicative IVIF filter of .
Let us compute and step by step using Table 2. First, we determine the value of by referring to the entry in the row corresponding to 4
and the column corresponding to 0
; according to the table, this yields . Next, we evaluate , which is equivalent to . Consulting Table 2, we find that the entry in row 5
and column 4
gives . Finally, we compute , which reduces to . Again, referencing Table 2, the entry in row 3 and column 1
is . Thus, we attain the following: Now,so the condition fails for μ. Also,so the condition fails for γ. Therefore, the IVIF filter is not an implicative IVIF filter of .
Proposition 5.
Let be an implicative IVIF filter of H. Recall that and denote the interval-valued membership and non-membership functions of , respectively. For all , the following properties hold independently for and :These assertions express that the membership and non-membership functions satisfy analogous algebraic properties in the context of implicative IVIF filters, and should not be mixed within a single statement without explicit clarification. Proof. Let
be an implicative IVIF filter of
. If we set
,
, and
in (
20) and use (a5) and (
12), then we obtain (
21). Using (
21), (H1), (a5), (a7), (a9), and (
10), we derive
and
for all
. It follows from (
12) that we have (
22). □
This proposition reveals that implicative IVIF filters possess special monotonicity and idempotency properties with respect to their membership and non-membership functions. These properties further distinguish implicative IVIF filters within the interval-valued intuitionistic fuzzy filter framework.
Proposition 6.
Let be an implicative IVIF-filter of , where and denote the interval-valued membership and non-membership functions of , respectively. Then, for all , the following conditions hold separately for each function:These properties describe the algebraic relationships satisfied by the membership and non-membership functions in implicative IVIF-filters. Note that each assertion is stated independently for and , in accordance with their respective definitions. Proof. Let be an implicative IVIF filter of a bounded hoop algebra . By Theorem 11, is also an IVIF filter of .
If we set
in (
22), we obtain for all
:
Thus, assertion (
23) holds.
For all
, observe that
. From
in Definition 1, and (
10), we deduce:
By combining Proposition 1
, (
12), (
20), and (
26), we obtain:
This proves (
24).
Finally, using
in Definition 1, (
15) and (
24), for all
, we have
Thus, assertion (
25) is established. □
The above proposition demonstrates that implicative IVIF filters satisfy several additional algebraic properties, including idempotency and certain monotonicity relations involving implication and negation. These results further clarify the structural behavior of implicative IVIF filters in bounded hoop algebras.
Theorem 12.
Let be an IVIF set. Then, is an implicative filter of if and only if for all , the sets and are either empty or are implicative filters of .
Proof. The proof follows closely the reasoning outlined in Theorem 5. □
This theorem provides a characterization of implicative IVIF filters in terms of their level sets, stating that such a filter exists if and only if all its upper and lower level sets are either empty or implicative filters themselves. This result connects the interval-valued intuitionistic fuzzy structure with classical filter theory via level set analysis.
Theorem 13.
If the IVIF filter of satisfies the condition (22), then it is an implicative IVIF filter of . Proof. Let
. Then
and
by (
12), (
13) and (
22). Then,
is an implicative IVIF filter of
. □
This theorem states that if an IVIF filter satisfies the specific idempotency condition given in (
22), then it necessarily possesses the stronger structure of an implicative IVIF filter. Thus, condition (
22) serves as a sufficient criterion for an IVIF filter to be implicative.
Theorem 14.
Let be an IVIF filter of . If satisfies the condition (21), then it is an implicative IVIF filter of . Proof. Assume that
is an IVIF filter of
satisfying condition (
21). From Proposition 5, we know that (
21) implies (
22). Therefore, by Theorem 13, it follows that
is an implicative IVIF filter of
. □
Theorem 15.
If an IVIF filter of satisfies the condition (23), then is an implicative IVIF filter of . Proof. Let
be an IVIF filter of
that satisfies (
23). Observe that for all
, we have
. From the conditions in (
12), (
10), and (
23), it follows that
and
Thus, (
22) holds, and consequently,
is an implicative IVIF filter of
H by Theorem 13. □
This theorem asserts that if an IVIF filter satisfies the idempotency property stated in (
23), then it must be an implicative IVIF filter. Therefore, condition (
23) provides another sufficient criterion for an IVIF filter to be implicative.
Theorem 16. If an IVIF filter of satisfies the condition (24), then is an implicative IVIF filter of . Proof. Let
be an IVIF filter of
that satisfies (
24). For arbitrary elements
, we have the following sequence of inequalities:
Similarly, for
we have
These inequalities follow from (H1), (H3), (
12), and (
24). Thus, Equation (
23) holds, and therefore, by Theorem 15,
is an implicative IVIF filter of
. □
This theorem states that if an IVIF filter satisfies the condition given in (
24), then it is necessarily an implicative IVIF filter. Thus, Equation (
24) provides yet another sufficient condition ensuring the implicative nature of an IVIF filter.
Theorem 17.
If an IVIF filter of H satisfies the condition (25), then it is an implicative IVIF filter of . Proof. Let
be an IVIF filter of
H satisfying (
25). From the condition (
25), we have the following inequalities:
and similarly,
These hold for all
. Therefore, Equation (
24) is satisfied, and by Theorem 16,
is an implicative IVIF filter of
. □
The above theorem shows that if an IVIF filter satisfies the condition in (
25), then it is necessarily an implicative IVIF filter. Therefore, Equation (
25) offers a further sufficient condition for an IVIF filter to be implicative.
Theorem 18.
Let and be IVIF filters of H such thatIf is an implicative IVIF filter of , then is also an implicative IVIF filter of . Proof. Assume that
is an implicative IVIF filter of
. This implies that
is an IVIF filter of
(see Theorem 11). For any
, we have the following:
and
where the equalities and inequalities hold by (
27), (
28) and (
23). Since
is an IVIF filter of
, from (
12) it follows that
Thus, we obtain
for all
. Therefore,
is an implicative IVIF filter of
by Theorem 15. □
The above theorem establishes that if an implicative IVIF filter
is dominated by another IVIF filter
in the sense of conditions (
27) and (
28), then
is also implicative. Thus, the implicative property is preserved under these comparative conditions between IVIF filters.
In this part of this paper, we address the converses of Theorems 16–18; which provide essential insights into the relationships between IVIF filters and implicative IVIF filters. Understanding these converses will enhance the theoretical foundation of our study and clarify the conditions under which certain properties hold.
Theorem 16 states: An IVIF set is an implicative IVIF filter of if and only if it satisfies specific properties related to the membership and non-membership functions.
Converse Statement: If an IVIF set satisfies the conditions outlined in Theorem 16, does it necessarily imply that is an implicative IVIF filter?
The converse holds true under the following conditions:
If these conditions are met, then the implications defined in Theorem 16 can be reversed, confirming that is indeed an implicative IVIF filter.
Theorem 17 states: An IVIF set is an implicative IVIF filter of if it satisfies certain conditions regarding the relationships between its membership and non-membership functions.
Converse Statement: If an IVIF set is an implicative IVIF filter, does it necessarily satisfy the conditions outlined in Theorem 17? The converse of Theorem 17 holds true. If is an implicative IVIF filter, then it must satisfy the properties defined in Theorem 17. This is due to the inherent definitions of implicative filters, which require specific relationships between the membership and non-membership functions.
Theorem 18 states: An IVIF set is an IVIF filter of if and only if it meets certain criteria related to its structural properties.
Converse Statement: If an IVIF set meets the conditions specified in Theorem 18, does it imply that is an implicative IVIF filter? The converse of Theorem 18 is valid under the same structural conditions outlined in the theorem. Specifically, if an IVIF set meets the criteria for being an IVIF filter, it must also satisfy the additional properties required for it to be classified as an implicative IVIF filter.
The exploration of the converses of Theorems 16–18 provides valuable insights into the relationships between IVIF filters and implicative IVIF filters. By establishing these connections, we enhance the theoretical framework of our study and clarify the conditions under which various properties hold. This deeper understanding is crucial for future applications and research in the field of interval-valued intuitionistic fuzzy logic.
Proposition 7.
Let be a family of IVIF filters of , where each and denote the interval-valued membership and non-membership functions, respectively. Define the intersection byfor all . Then, is an IVIF filter of . Proof. Let be a family of IVIF filters of a hoop H.
Let
. Then we have
and
Hence
is an IVIF filter of
. □
This proposition shows that the infimum of any family of IVIF filters is itself an IVIF filter. Thus, the class of IVIF filters of is closed under arbitrary intersections.
Lemma 1.
Let be an IVIF filter of if and only if and are interval-valued fuzzy filters of .
Proof. Assume that
is an IVIF filter of
. Then, it is clear that
is an interval-valued fuzzy filter of
. Consider, for every
, we have
Let
. Then, we have the following inequality:
Thus,
is an interval-valued fuzzy filter of
.
Conversely, assume that
and
are interval-valued fuzzy filters of
. Then, for every
, we have
and
which implies that
. Let
. Then, it follows that
Additionally,
Hence, we obtain
.
Therefore, is an IVIF filter of H. □
Remark 1.
The characterization in Lemma 1 directly implies that the corresponding pairs and inherit the interval-valued fuzzy filter property.
Proof. If is an IVIF filter of , then by Lemma 1, and are interval-valued fuzzy filters of . Hence, and are IVIF filters of H.
Conversely, if and are IVIF filters of , then and are IVF filters of . Therefore, is an IVIF filter of . □
Definition 12.
Let be an IVIF set in . We define a subset of A by This definition introduces the subset , which consists of all elements in whose membership and non-membership degrees are equal to those of the unit element. Thus, characterizes elements that are maximally similar to 1 in terms of both degrees in the IVIF set .
Theorem 19.
If is an IVIF sub-hoop of , then is a sub-hoop of .
Proof. Clearly,
. Let
. Then we have
,
,
, and
. Therefore, for
, we obtain
and
Hence,
and
, which implies that
. Thus,
is a sub-hoop of
. □
For any fixed interval numbers
,
,
, and
in
such that
,
, and a nonempty subset
of
, the IVIS is defined as
in
, where
Lemma 2.
If the constant 1 of is in a nonempty subset of , then the IVISin satisfies the conditions (3). Proof. If
, then
, and
. Thus
Hence
satisfies the conditions (3). □
Lemma 3.
If the IVISin satisfies the conditions (3), then the constant 1 of is in a nonempty subset of . Proof. Assume that the IVIS
in
satisfies the condition (3). Then, we have
Since
is nonempty, there exists some
. Therefore,
From this, we get
Thus, we conclude that
Hence,
. □
Theorem 20.
The IVISin is an IVIF sub-hoop of if and only if a nonempty subset of is a sub-hoop of . Proof. Assume that
is an IVIF sub-hoop of
. Let
. Then
. Thus
and so
. Thus
. Hence
is a sub-hoop of
.
Conversely, assume that is a sub-hoop of . Let .
Case (1): Let
. Then
Since
is a sub-hoop of
,
and so
.
Case 2: Let
or
. Then
Then
Therefore,
Hence
is an IVIF sub-hoop of
. □
This theorem provides a characterization of IVIF sub-hoops in terms of their underlying crisp structure. Specifically, it shows that an IVIF sub-hoop of corresponds exactly to an ordinary sub-hoop of determined by the nonempty subset .
Theorem 21.
TThe IVIS in is an IVIF filter of if and only if a nonempty subset of is a filter of . Proof. Assume that
is an IVIF filter of
. Since
satisfies the condition (
29), it follows from Lemma 3 that
.
Let
and
. We have
Now, consider
Thus,
. Therefore,
. Hence,
is a filter of
.
Conversely, assume that
is a filter of
. Since
, it follows from Lemma 2 that
satisfies the conditions (
29).
Let .
Case 1: Suppose
. Then
Since
is a filter of
,
, and so
Then
Case 2: Suppose
or
. Then
Then
Therefore,
Hence, is an IVIF filter of . □
The above theorem establishes a direct correspondence between IVIF filters and crisp filters in the hoop . In particular, it shows that an IVIF filter of is determined by a nonempty subset that is itself a filter of .
We define the operations ∨ and ∧ on the interval-valued fuzzy set
of
in this way:
and
for all
Remark 2.
Let be an IVIF-set on . The intersection of all IVIF-filters containing is called the generated IVIF-filter by , denoted as .
Theorem 22.
Let be an IVIF-set on , and let be an IVIF-set defined on by:andfor all , where for and . Then . Proof. First, we verify that
is an IVIF-filter. For all
, such that
, the definition of
yields the following:
For all
,
,
,
and
, we have
for all appropriate values of
For all elements
, the following operations hold:
This establishes the necessary properties for
to satisfy the IVIF-filter conditions.
and
Thus,
is an IVIF-filter. Secondly, let
be an IVIF-filter such that
. By the definition of an IVIF-filter, for all
, where
and
, it holds that
and
and hence,
. Thus,
. □
This theorem demonstrates that the IVIF-set constructed via the given supremum and infimum operations is the IVIF-filter generated by . In other words, is the smallest IVIF-filter in containing .
Now, we define the operations ⊓ and ⊔ on IVIF-filters of in this way, and , for any .
Theorem 23. is a bounded distributive lattice.
Proof. The proof can be established using techniques similar to those employed in the proofs of (Ref. [
23], Theorems 10–12). □
Theorem 24.
Let be an IVIF-filter on the set , and let the fuzzy relation on be defined as follows: for any ,Then, the relation is a congruence relation on . Proof. First, we show that is an equivalence relation.
Reflexivity: For any
, clearly
and
. Thus,
which means
.
Symmetry: The definition of is symmetric in and , so implies .
Transitivity: Suppose
and
for some
. Then,
Using the properties of IVIF-filters (see Proposition 1
, Equations (
13) and (
12)), we have
and
Hence,
, and
is transitive.
Thus, is an equivalence relation.
Now, we show that
is a congruence relation. Let
such that
. Then,
Using the properties of IVIF-filters (see Proposition 2.1 (a2), (a8), and (H3)), we have
Thus, we obtain
and
Similarly, we get
and
Therefore, we attain
and
Thus, we reach
.
Similarly, using Proposition 1
, for any
, we have
so
and
and similarly for the reverse direction. Hence, we achieve
and
Thus,
. Similarly,
.
Therefore, is a congruence relation on . □
This theorem shows that the fuzzy relation , defined in terms of the IVIF-filter , is not only an equivalence relation but also compatible with the operations on . Therefore, forms a congruence relation on the structure .
For any
,
denotes the equivalence class of
with respect to
. Clearly,
For any
,
denotes the equivalence class of
with respect to
. Clearly,
Theorem 25.
Let , and let the operations ⊙
and → on be defined as follows:Also, we define a binary relation on byfor any Clearly, is a poset. Then, is a hoop. Proof. We have and if and only if and . Since is the congruence relation on , it follows that all the above operations are well-defined. Thus, by routine calculations, we can conclude that is a hoop.
Now, we define a binary relation on by if and only if and , for any .
We can clearly see that is a partial order monoid. □
This theorem establishes that the quotient structure , formed by the congruence relation , inherits the hoop structure from with well-defined operations. Moreover, the induced order on the quotient set makes a partially ordered hoop.
As a result, to clarify the relationships between the main structures discussed in this study,
Figure 1 visually summarizes the connections among hoop algebras, sub-hoops, filters, IVIF sets, and implicative filters.