Abstract
In this article, we present a nonlocal Neumann boundary value problems for separate sequential fractional symmetric Hahn integrodifference equation. The problem contains five fractional symmetric Hahn difference operators and one fractional symmetric Hahn integral of different orders. We employ Banach fixed point theorem and Schauder’s fixed point theorem to study the existence results of the problem.
1. Introduction
Quantum calculus is a study of calculus without limit that deals with a set of non-differentiable functions. It has been used in many studies such as approximation problems, particle physics problems, quantum mechanics, and calculus of variations. The q-calculus, one type of quantum calculus initiated by Jackson [1,2,3,4,5] has been employed in several fields of applied sciences and engineering such as physical problems, dynamical system, control theory, electrical networks, economics and so on [6,7,8,9,10,11,12,13,14].
Later, the motivation of quantum calculus based on two parameters was presented in 1949. W. Hahn [15] introduced the Hahn difference operator which is a combination of two well-known difference operators, the forward difference operator and the Jackson q-difference operator. In 2009, Aldwoah [16,17] defined the right inverse of in the terms of both the Jackson q-integral containing the right inverse of and Nörlund sum contaning the right inverse of [18]. Moreover, Fractional Hahn operators [19] was introduced in 2017. These calculus are also employed in many research works [20,21,22,23,24,25,26,27,28,29,30,31] including the studies of initial and boundary value problems [32,33,34,35,36,37,38,39,40].
For symmetry of Hahn calculus, Artur et al. [41] introduced symmetric Hahn difference operator in 2013. Recently, Patanarapeelert and Sitthiwirattham [42] introduced fractional symmetric Hahn difference operator. However, the study of the boundary value problems for fractional symmetric Hahn difference equation in the beginning, there exists only one paper on this subject [43].
The main motivation for this paper is to enrich the literature on the boundary value problems for fractional symmetric Hahn difference equations. We study the boundary value problem involving functions F and H which separate fractional symmetric Hahn integral and fractional symmetric Hahn difference, and the boundary condition is a Neumann boundary condition that is assigned values at two non-local points. In this paper, we aim to employ this recent work to study solutions to a boundary value problem for fractional symmetric Hahn integrodifference equations. Our problem is a nonlocal Neumann boundary value problems for sequential fractional symmetric Hahn integrodifference equation of the form
where , ; ; and are given functions, are given functionals; and for , we define the operators
We first transform this nonlinear problem (1) into a fixed point problem, by in view of a linear variant of (1). When the fixed point operator is accessible, we use the classical fixed point theorems to find existence results. To study the solution of problem (1), we recall some definitions and basic knowledge, and we also study some properties of fractional symmetric Hahn integral that will be used in our main results in Section 2. In Section 3, we present the existence and uniqueness of a solution of problem (1) by using the Banach fixed point theorem. The existence of at least one solution of problem (1) is also investigated by using the Schuader’s fixed point theorem. In the last section, we give an example to illustrate our results.
2. Preliminaries
2.1. Basic Notions and Results
In this section, we introduce the definitions of fractional symmetric Hahn difference calculus and its properties [41,42,43,44,45] as follows.
For , , and , we define
The -forward jump operator is defined by
and the -backward jump operator is defined by
where .
For , and , the q-analogue of the power function is defined as
the q-symmetric analogue of the power function is defined as
and, the -symmetric analogue of the power function is defined as
Generally, for , the power functions are defined as
Particularly, and if . If , for .
The q-symmetric gamma and q-symmetric beta functions are defined as
respectively.
Lemma 1
([42]). For and ,
- ,
- .
Definition 1
([41]). For , , and f is a function defined on , the symmetric Hahn difference of f is defined by
is called -symmetric derivative of f, and f is -symmetric differentiable on . For , where .
Remark 1.
If f and g are -symmetric differentiable on ,
- ,
- ,
- where C is constant.
Definition 2
([41]). Let I be any closed interval of containing and and be a given function. The symmetric Hahn integral of f from a to b is defind by
and
where the above series converges at and . For , where .
The following is the relation between the symmetric Hahn difference and integral.
Remark 2
([41]). Let and be symmetric Hahn integrable on . Then,
Lemma 2
([41]). [Fundamental theorem of symmetric Hahn calculus]
Let be continuous at . Then,
is continuous at and exists for every where
In addition,
Lemma 3
([42]). Let , and be continuous at . Then,
Definition 3
([42]). Let and f be a function defined on . The fractional symmetric Hahn integral is defined by
and .
Definition 4
([42]). For and f defined on , the fractional symmetric Hahn difference operator of Riemann-Liouville type of order α is defined by
where
Lemma 4
([42]). Let and . Then,
for some and for .
Lemma 5
([46] Arzelá-Ascoli theorem). A set of function in with the sup norm, is relatively compact if and only if it is uniformly bounded and equicontinuous on .
Lemma 6
([46]). If a set is closed and relatively compact then it is compact.
Lemma 7
([47] Schauder’s fixed point theorem). Let be a complete metric space, U be a closed convex subset of D, and be the map such that the set is relatively compact in D. Then the operator T has at least one fixed point :
2.2. Auxiliary Lemmas
In this part, we establish some lemmas that are used to prove our main results.
Lemma 8.
Let and . Then,
Lemma 9.
Let and . Then,
- (i)
- (ii)
- (iii)
Lemma 10.
Let and . Then,
- (a)
- (b)
- (c)
Proof.
We use the definition of -symmetric analogue of the power function, Lemma 1 and Definition 2 to obtain
□
2.3. Lemma for Linear Variant Form
In this part, a solution of a linear variant form of the problem (1) is investigated as shown in the following lemma.
Lemma 11.
Let ; and be given functions; be given functionals. Then the problem
has the unique solution
where the functionals are defined by
and the constants and Ω are defined by
3. Existence and Uniqueness of Solution of the Problem (1)
To consider the existence and uniqueness of solution to the problem (1), we use Banach fixed point theorem.
Let be a Banach space of all function u with the norm defined by
where and . An operator is defined by
where the functionals are given by
and the constants are given in Lemma 11.
To prove the existence results to the problem (1), we first convert the given nonlinear problem (1) into a fixed point problem. If the operator has fixed point, then the problem (1) has the solution.
Theorem 1.
Assume that , and are continuous, and are continuous with . Suppose that the following conditions hold:
- There exist positive constants such that for each and ,
- There exist positive constants such that for each and ,
- There exist positive constants such that for each ,
- For each , .
- ,
where
Then, the problem (1) has a unique solution in .
Proof.
For each and , we find that
Similary,
Denote that
we obtain
for . Therefore,
Take fractional Hahn difference of order for (16). Then, we have
Similary,
From , we can conclude that is a contraction. Hence, from Banach fixed point theorem, has a fixed point which is a unique solution of problem (1) on . □
4. Existence of at Least One Solution of Problem (1)
In this section, we further consider the existence of at least one solution of (1) by using the Schauder’s fixed point theorem as follows.
Theorem 2.
Suppose that ,, and defined in Theorem 1 hold. Then, problem (1) has at least one solution on .
Proof.
We split the proof into several steps.
Step I. Verify map bounded sets into bounded sets in . Let ,, , and choose a constant
Denote that
Consider that
where , and
Next,
Step II. Since and are continuous, the operator is the continuous on .
Step III. Examine that is equicontinuous on .
For any with , we obtain
and
5. Example
In this section, we provide an example to show our results. We let , and which are satisfied with the conditions of the problem (1). Therefore the problem (1) is represented by
where and .
To investigate the values of , , , and , we employ the assumptions – to get the results as follows.
For all and we find that
Thus, and hold with
For all we obtain
Then, holds with
The condition holds with
We next find that
and,
So, hold with
Therefore, by Theorem 1 problem (41) has a unique solution.
6. Conclusions
We present the new problem involving five fractional symmetric Hahn difference operators and one fractional symmetric Hahn integral of different orders where the new concepts of fractional symmetric Hanh calculus were used. By using the Schauder and Banach fixed point theorems we found conditions under which this problem, respectively, has a solution and has a unique solution. In addition, some properties of symmetric Hahn integral are also studied. The results of this article are new and enrich the field of boundary value problems for fractional symmetric Hahn integrodifference equations. In the future, we may expand this work by considering a new boundary value problem.
Author Contributions
Conceptualization, T.D.; methodology, T.D., T.S. and N.P.; formal analysis, T.D., T.S. and N.P.; funding acquisition, T.S. and N.P. All authors have read and agreed to the published version of the manuscript.
Funding
This research was funded by King Mongkut’s University of Technology North Bangkok. Contract No. KMUTNB-62-KNOW-27.
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
No data were used to support this study.
Acknowledgments
This research was supported by Chiang Mai University.
Conflicts of Interest
The authors declare no conflict of interest.
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