Abstract
In this paper, we study the Hom–Hopf algebra automorphism group of a -twisted-Radford’s Hom-biproduct, which satisfies certain conditions. First, we study the endomorphism monoid and automorphism group of -twisted Radford’s Hom-biproducts, and show that the endomorphism has a factorization closely related to the factors and . Then, we consider -twisted Radford’s Hom-biproduct automorphism group as a subgroup of some semidirect product . Finally, we characterize the automorphisms of a concrete example.
1. Introduction
The automorphism group of an algebra has a long history and extensive study, and determining the fully automorphic group of an algebra is usually a very difficult problem. For instance, the automorphism group of the polynomial ring of one or two variables has been understood. Jung [1] in 1942 first proved the case of two variables for characteristic zero and then van der Kulk [2] in 1953 for an arbitrary characteristic. However, the automorphism group of the polynomial ring of three variables is not yet fully understood, and a remarkable result is given by Shestakov and Umirbaev [3] in 2004, which shows that the Nagata automorphism is a wild automorphism. Many researchers have been successfully computing the automorphism groups of interesting infinite-dimensional noncommutative algebras, including certain quantum groups, generalized quantum Weyl algebras, skew polynomial rings, quantized algebras and many more—see [4,5,6,7,8,9,10,11,12,13,14,15], among others. The theory of algebra authomorphisms is very deep and related with mainstream, such as the Jacobian Conjecture [16] and Holonomic -modules [17,18].
In the theory of the classical Hopf algebras, Radford’s biproducts are very important Hopf algebras, which play an important role in the theory of classification of pointed Hopf algebra [19,20], and account for many examples of semisimple Hopf algebra. Therefore, the study of the automorphism group of Radford’s biproducts is very interesting, and Radford characterized Hopf algebra automorphisms in [21]. There are many generalizations of Radford’s biproducts, such as [22] for quasi-Hopf algebras, [23] for multiplier Hopf algebras, Ref. [24], for monoidal Hom–Hopf algebras, Ref. [25], for Hom–Hopf algebras, and recently [26] for -twisted-Radford’s Hom-biproducts.
Let be the Radford’s biproduct, where A is both a left H-module algebra and a left H-comodule coalgebra. Define , , let be the set of Hopf algebra automorphisms F of satisfying . Radford [21] characterized these Hopf algebra automorphisms, and factorized F into two suitable maps. Inspired by Radford’s idea in [21], the authors of [27] discuss the automorphisms of twisted tensor biproducts, and reveal the relationships between results and Radford’s results, and the authors of [28] study automorphisms of Radford’s Hom-biproducts introduced in [24]. Motivated by these works, we want to characterize the Hom–Hopf algebra automorphisms of -twisted-Radford’s Hom-biproduct introduced in [26].
This paper is organized as follows. In Section 2, we recall some definitions and basic results related to Hom-(co)algebras, Hom-bialgebras, Hom–Hopf algebras, Hom-(co)module, Hom-(co)module (co)algebras, -twisted Hom-smash products, -twisted Hom-smash coproducts and -twisted-Radford’s Hom-biproduct. In Section 3, we study the endomorphisms and automorphisms of -twisted-Radford’s Hom-biproducts, and show that the automorphism has a factorization closely related to the factors and of the -twisted-Radford’s Hom-biproduct in [26]. Finally, we characterize the automorphisms of a concrete example in Section 4.
2. Preliminaries
We always assume that is a base field. All algebras, linear spaces, etc. will be over ; the subscript of is omitted for simplicity. Let denote the identity map on a -space V. We now recall some useful definitions and terminology as follows; see [25,29,30,31,32,33,34].
Definition 1
([29]). A Hom-algebra is a quadruple (abbr. ), where A is a -linear space, and are linear maps with notation , , and α is an automorphism of A, satisfying the following conditions for all
- (HA1)
- ,
- (HA2)
- ,
- (HA3)
- ,
- (HA4)
- .
Let and be two Hom-algebras. Then, a morphism is called a Hom-algebra morphism if , and .
Definition 2
([30,32,34]). A Hom-coalgebra is a quadruple (abbr. ), where C is a -linear space, and are linear maps with notation and α is an automorphism of C, satisfying the following conditions for all
- (HC1)
- ,
- (HC2)
- ,
- (HC3)
- ,
- (HC4)
- .
Let and be two Hom-coalgebras. Then, a morphism is called a Hom-coalgebra morphism if , and .
Definition 3
([31,32]). A Hom-bialgebra is a sextuple (abbr. ), where is a Hom-algebra and is a Hom-coalgebra, such that Δ and ε are Hom-algebra morphisms, i.e.,
- (HB1)
- ,
- (HB2)
- ,
- (HB3)
- ,
- (HB4)
- .
Furthermore, if there is a linear map such that
- (HS1)
- ,
- (HS2)
- .
Then, we call (abbr. ) a Hom–Hopf algebra.
The antipode S is both a Hom-anti-algebra morphism and a Hom-anti-coalgebra morphism. A morphism between two Hom-bialgebras is called a Hom-bialgebra morphism if it is both a Hom-algebra and a Hom-coalgebra morphism. A morphism between two Hom–Hopf algebras is called a Hom–Hopf algebra morphism if it is a Hom-bialgebra morphism and compatible with the antipodes. A useful remark is that Hom-bialgebra morphisms of Hom–Hopf algebras are Hom–Hopf algebra morphisms.
Definition 4
([32]). Let be a Hom-algebra. A left -Hom-module is a triple , where X is a -linear space, (write , ) is a linear map, and α is an automorphism of X, such that
- (HM1)
- ,
- (HM2)
- ,
- (HM3)
are satisfied for and .
Let and be two left -Hom-modules. Then, a morphism is called a -Hom-module morphism if and .
Definition 5
([32]). Let be a Hom-coalgebra. A left -Hom-comodule is a triple , where X is a -linear space, (write , ) is a linear map, and α is an automorphism of X, such that
- (HCM1)
- ,
- (HCM2)
- ,
- (HCM3)
are satisfied for .
Let and be two left -Hom-comodules. Then, a morphism is called a -Hom-comodule morphism if and .
Definition 6
([33]). Let be a Hom-bialgebra and be a Hom-algebra. If is a left -Hom-module, and for all and ,
- (HMA1)
- ,
- (HMA2)
- ,
then, is called a left -Hom-module Hom-algebra.
Definition 7
([25,34]). Let be a Hom-bialgebra and a Hom-algebra. If is a left -Hom-comodule and for all ,
- (HCMA1)
- ,
- (HCMA2)
- ,
then, is called a left -Hom-comodule Hom-algebra.
Definition 8
([25]). Let be a Hom-bialgebra and be a Hom-coalgebra. If is a left -Hom-module and for all and ,
- (HMC1)
- ,
- (HMC2)
- ,
then is called a left -Hom-module Hom-coalgebra.
Definition 9
([25]). Let be a Hom-bialgebra and be a Hom-coalgebra. If is a left -Hom-comodule and for all ,
- (HCMC1)
- ,
- (HCMC2)
- ,
then is called a left -Hom-comodule Hom-coalgebra.
Now, we recall the definition of -twisted-Radford’s Hom-biproduct from [26]. First, if is a Hom-bialgebra, we denote the group of all Hom-bialgebra automorphisms of H by .
Definition 10
([26]). Let be a Hom-bialgebra, and be a left -Hom-module Hom-algebra. A θ-twisted smash Hom-product of and is defined as follows. For all :
- (i)
- as a vector space, ,
- (ii)
- the multiplication is given by
The θ-twisted smash Hom-product is a Hom-algebra with the unit .
Definition 11
([26]). Let be a Hom-bialgebra, and be a left -Hom-comodule Hom-coalgebra. A ω-twisted smash Hom-coproduct of and is defined as follows. For all :
- (i)
- as a vector space, ,
- (ii)
- the comultiplication is given by
The ω-twisted smash Hom-coproduct is a Hom-coalgebra with the counit .
Theorem 1
([26]). Let be a Hom-bialgebra, be a left -Hom-module Hom-algebra with Hom-module structure ▹, and a left -Hom-comodule Hom-coalgebra with Hom-comodule structure ρ, and , be a θ-twisted smash Hom-product, and be a ω-twisted smash Hom-coproduct. Then, the following two conditions are equivalent:
- (i)
- is a Hom-bialgebra.
- (ii)
- The following conditions hold:
- (T1)
- is a Hom-algebra map and ,
- (T2)
- is a left -Hom-module Hom-coalgebra,
- (T3)
- is a left -Hom-comodule Hom-algebra,
- (T4)
- ,
- (T5)
- ,
for all and .
Theorem 2
([26]). Suppose is a -twisted-Radford’s Hom-biproduct. If H is a Hom–Hopf algebra with antipode and is a linear map, such that is a convolution inverse of and , then is a Hom–Hopf algebra with antipode S described by
The -twisted-Radford’s Hom-biproduct is a Hom–Hopf algebra and is denoted by , for short, and write elements .
3. Factorization of Certain Twisted Hom-Biproduct Endomorphisms
Let be a -twisted-Radford’s Hom-biproduct. We define by for all and by for all , are Hom–Hopf algebra maps which satisfy . Let be the set of all Hom–Hopf algebra endomorphisms F of such that and let be its set of units, which is the group of Hom–Hopf algebra automorphisms F of such that under composition. The purpose of this section is to show that F has a factorization closely related to the factors and of .
We define and by , for all and , for all , respectively. There is a fundamental relationship between these four maps given by:
The factorization of F is given in terms of and defined by:
First, we shall reveal the relationships among F, and in the following lemma.
Lemma 1.
Let . Then:
for all and .
Proof.
According to the definition of these four maps and F, we have
and
Next, we need to calculate . For and , we use (4) to compute
Since by Equation (7). By (9) of Lemma 1:
for all . Now, we can calculate the factors of a composite.
Corollary 1.
Let . Then:
- (i)
- ,
- (ii)
- .
Proof.
(i) For any , by (7) of Lemma 1, we have
(ii) For all . Using Equation (11), the fact F is multiplicative and Equation (7), we obtain that
i.e.,
Applying to both sides of the above equation, and replacing h with , we can obtain part (ii). □
According to Lemma 1, in order to characterize F, we must characterize and . First, we shall characterize in the following lemma.
Lemma 2.
Let . Then:
- (i)
- is a Hom-algebra endomorphism.
- (ii)
- .
- (iii)
- For all ,
- (iv)
- For all ,
- (v)
- For all and ,
Proof.
(i) We need to check three aspects. From the above discussion, we have known that and have checked in Lemma 1. Finally, we shall check that preserves the multiplication. In fact, for , we have
It is easy to check part (ii), since , and F is a Hom-coalgebra morphism.
Next, we will check that parts (iii) and (iv) hold. As a matter of fact, we compute the coproduct of in two ways. Firstly, we have
and secondly, since F is a Hom-coalgebra map, we have
It follows that
Applying to both sides of the above equation yields (12). It follows easily that from (11). Applying to both sides of the above equation again, we can gain
and applying to both sides, we obtain (13).
(v) Finally, it is left to us to check (14). Indeed, for and , we have
On the other hand, Since F preserves the multiplication, we compute:
Thus,
Applying to the above equation and replacing a with , we obtain (14). □
As the reader might suspect, whether or not is a Hom-coalgebra morphism is explained in terms of .
Corollary 2.
Let . Then, is a Hom-coalgebra morphism if, and only if, , for any .
Proof.
Suppose , for any . Then, we have
Conversely, suppose that is a Hom-coalgebra morphism. For all , we compute
as desired. □
From Lemma 2, we have characterized the conditions that satisfies. Pay special attention to its part (v) describing a commutation relation between and . It is left to us to characterize as follows.
Lemma 3.
Let . Then:
- (i)
- .
- (ii)
- For all ,
- (iii)
- is a Hom-coalgebra morphism.
- (iv)
- For all ,
Proof.
(i) By (11), we have for . Since F is a Hom-algebra morphism and is an automorphism, , which implies .
(ii) For , we have
and on the other hand,
Applying to both expressions for , it follows that (15) holds.
To prove parts (iii) and (iv), we calculate , for all , in two ways as follows.
On the other hand,
Applying to the expressions for gives . since and have been discussed before, and hence, part (iii) holds.
Applying to the expressions for again yields
Therefore,
it follows that
Applying to both sides of the equation gives part (iv). □
Corollary 3.
Let . Then, is a left -Hom-module morphism if and only if the condition holds for all and .
Proof.
The necessary condition can be followed easily from (14) of Lemma 2. Now, we shall prove a sufficient part. Suppose that the condition holds. Note that is a Hom-coalgebra morphism by Lemma 3(iii). Using this fact and (14), for all and , we have
and since , we show that is a left -Hom-module morphism. □
Lemma 4.
Let . Then, is a Hom-algebra morphism if, and only if, for all .
Proof.
Suppose that is a Hom-algebra morphism. Using (ii) and (iii) of Lemma 3, for , we have
i.e., . Replacing h by yields the condition.
Conversely, if holds, by using Equation (15), we have
The proof is completed. □
Corollary 4.
Let . Then, has a convolution inverse defined by for .
Proof.
Let . Then, by parts (i) and (ii) of Lemma 3, we have
and using the fact that is a left -Hom-module algebra, we have
The proof is completed. □
Using the above lemmas and corollaries that we have, we can gain the main result.
Theorem 3.
Let be the -twisted-Radford’s Hom-biproduct, let be the projection from onto H, and let be the set of pairs , where , are morphisms which satisfy the conclusions of Lemmas 2 and 3 for and , respectively. Then,
- (i)
- The function , described by , where , for all and , is a bijection. Furthermore, and .
- (ii)
- Suppose , then, if, and only if, L is a bijection.
Proof.
(i) Assume that the function is well-defined. We define by . It is easily proven that and are mutually inverse; see Equations (5) and (9). According to the previous results, to complete the proof of part (a), we only need to prove that elements of give rise to elements of , as indicated. As the reader might suspect, the proof that is somewhat tedious. We will use Lemmas 1–3, which do not need special citations initially.
It is easy to see that . Obviously, . Note that and
for and , which means that .
Let and . Then,
Therefore, F is a Hom-algebra morphism.
Next, we shall check that . Indeed, for all , ,
We have shown that F preserves comultiplication. Therefore, F is a Hom-coalgebra morphism, and hence, is a Hom-bialgebra morphism. Since Hom-bialgebra morphisms of Hom–Hopf algebras are Hom-Hopf algebra morphisms, this completes the proof of part (i).
(ii) Suppose . Then, and are inverse by (10) and Corollary 1(i). Thus, is bijective and .
Conversely, suppose that and are bijective. Set . From Corollary 4, has a convolution inverse . Set and define for all and . Since is a Hom-algebra morphism, we compute
and
Thus, we have shown that . □
Now, let denote the set of , such that L is bijective. Then, the correspondence of the above theorem induces a bijection .
When , the structure of F is particularly simple.
Proposition 1.
Let . Then, the following conditions are equivalent:
- (i)
- .
- (ii)
- for all .
- (iii)
- for all .
- (iv)
- .
- (v)
- for all and .
- (vi)
- for all .
Proof.
Firstly, we prove that part (i) implies part (ii) implies part (iii). Suppose part (i) holds. Then, we have by Equation (11), and hence, for all , because . Secondly, it is easy to see that parts (iii) and (iv) are equivalent. Thirdly, part (iv) implies part (v) by Equation (9), and part (v) implies part (vi) as . At last, part (vi) trivially implies part (i). □
Let be a Hom-algebra and be a Hom-coalgebra over . Let be the set of -linear maps satisfying . The group acts on the (non-associative) convolution algebra by for all and . Obviously, this action satisfies:
for all and . Then, is a Hom-algebra with the unit under the convolution *. Indeed, for and ,
and
Thus, it follows that and . Moreover, can be checked similarly.
It is easy to check that is an ordinary associative algebra. Let be the group of units of the algebra . Then ; thus, there is a group homomorphism
given by for all and . The resulting group has product given by
Note that the action of on by group homomorphisms is also one on . For a group G, the group is the group whose underlying set is G and the product is given by for all . Therefore, we have the following result of Theorem 3 and Corollary 1.
Theorem 4.
Let be the -twisted-Radford’s Hom-biproduct, let be the projection from onto H. Then, there is an injective group homomorphism , which is given by for all .
Proof.
For , it is easy to see that and are bijective by Theorem 3(ii) and Equation (11). If , then, using (9), we have for all and . Thus, it follows that , i.e., is injective.
For , since
it follows that preserves the multiplication. Thus, is an injective group homomorphism. □
In conclusion, by Theorem 3, we obtain the characterization of the automorphism group of a -twisted-Radford’s Hom-biproduct via the automorphisms of the factors and . Furthermore, by Theorem 4, the automorphism group can be regarded as a subgroup of some semidirect product , when is a projection. These are important for the study of automorphism groups of twisted-Radford’s Hom-biproducts.
4. Example
In this section, we consider an example in [26]. Let and the automorphism via and . Then, is both a Hom-algebra with product: , , , and a Hom-coalgebra with coproduct and counit given by
We define by , , which is the convolution inverse of .
Let be the group Hopf algebra with , , and . Define an automorphism by , . Then, we can define a new product and a new coproduct on H. So, we obtain a Hom–Hopf algebra . Then, is a left -Hom-module Hom-algebra and Hom-module Hom-coalgebra with the action given by
Furthermore, is a left -Hom-comodule Hom-algebra and Hom-comodule Hom-coalgebra with the coaction given by
Then, we can obtain many twisted Radford’s Hom-biproducts, such as -twisted Radford’s Hom-biproduct, -twisted Radford’s Hom-biproduct, -twisted Radford’s Hom-biproduct, -twisted Radford’s Hom-biproduct, and so on.
Now, we clearly write the structures of the -twisted Radford’s Hom-biproduct and characterize the automorphisms of it. Its product is defined as follows:
Its coproduct and counit are defined as follows:
Its antipodes are as follows:
Now, we compute the morphisms satisfying the conclusions of Lemma 2. This is taking a base of , , given respectively by
Let , where . If L satisfies Lemma 2(ii), it follows that and . By part (iv) of Lemma 2, we can obtain . Therefore, for some . So, there is a bijection between the set of the morphisms satisfying the conclusions of Lemma 2 and the set .
Now, we will discuss the morphisms of which satisfy Lemma 3 in a similar way as above. Taking a base of , , given respectively by
Let , where , . Since R satisfies part (i) of Lemma 3, we have and . By Equation (16), it follows that and . Thus, . Next, we shall check part (ii) of Lemma 3, and we obtain and . Therefore, , i.e., , , . Hence, . We can obtain the concrete characterization of . Let . By Theorem 3, we have
where .
Author Contributions
Conceptualization, X.W. and D.-G.W.; methodology, X.W.; software, X.W.; validation, X.W. and D.-G.W.; formal analysis, D.-G.W.; investigation, X.W.; resources, X.W.; data curation, D.-G.W.; writing—original draft preparation, X.W.; writing—review and editing, D.-G.W.; visualization, X.W.; supervision, D.-G.W.; project administration, X.W.; funding acquisition, X.W. and D.-G.W. All authors have read and agreed to the published version of the manuscript.
Funding
This work was supported by the National Natural Science Foundation of China (Grant Nos. 11871301, 11801304) and Natural Science Foundation of Shandong Province of China (Nos. ZR2019MA060, ZR2019QA015).
Institutional Review Board Statement
Not applicable.
Informed Consent Statement
Not applicable.
Data Availability Statement
Not applicable.
Acknowledgments
The authors would like to express their gratitude to the anonymous referee for their very helpful suggestions and comments, which led to the improvement of our original manuscript.
Conflicts of Interest
The authors declare no conflict of interest.
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