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Article

On the Dynamic Geometry of Kasner Quadrilaterals with Complex Parameter

1
Faculty of Mathematics and Computer Science, Babeş-Bolyai University, 400084 Cluj-Napoca, Romania
2
School of Computing and Engineering, University of Derby, Derby DE22 1GB, UK
3
Department of Mathematics, Faculty of Exact Sciences, “1 Decembrie 1918” University of Alba Iulia, 510009 Alba Iulia, Romania
*
Author to whom correspondence should be addressed.
Mathematics 2022, 10(18), 3334; https://doi.org/10.3390/math10183334
Submission received: 10 August 2022 / Revised: 7 September 2022 / Accepted: 10 September 2022 / Published: 14 September 2022
(This article belongs to the Special Issue Advances on Complex Analysis)

Abstract

:
We explore the dynamics of the sequence of Kasner quadrilaterals ( A n B n C n D n ) n 0 defined via a complex parameter α . We extend the results concerning Kasner triangles with a fixed complex parameter obtained in earlier works and determine the values of α for which the generated dynamics are convergent, divergent, periodic, or dense.

1. Introduction

For a real number α and an initial quadrilateral A 0 B 0 C 0 D 0 , one can construct the quadrilateral A 1 B 1 C 1 D 1 such that A 1 , B 1 , C 1 , and D 1 divide the segments [ A 0 B 0 ] , [ B 0 C 0 ] , [ C 0 D 0 ] , and [ D 0 A 0 ] , respectively, in the ratio 1 α : α . Continuing this process, one obtains the terms A n B n C n D n , n 0 whose terms are referred to as Kasner (or nested) quadrilaterals (after E. Kasner (1878–1955) who initiated these studies). A natural problem is to find the numbers α for which the sequence ( A n B n C n D n ) n 0 is convergent.
The related dynamic geometries inspired by simple iterations (especially for triangles) are reviewed in the article [1]:
generated by the incircle and the circumcircle of a triangle, the pedal triangle [2], the orthic triangle, and the incentral triangle. Similar recursive systems describing dynamic geometries are considered by S. Abbot [3], G. Z. Chang and P. J. Davis [4], R. J. Clarke [5], J. Ding, L. R. Hitt, and X-M. Zhang [6], L. R. Hitt and X-M. Zhang [7], and D. Ismailescu and J. Jacobs [8], or in the works by Dionisi et al. [9] and Roeschel [10]. In the paper [1], we proved that the sequence of Kasner triangles is convergent if and only if α ( 0 , 1 ) , also providing the order of convergence.
Here, we prove similar results for the Kasner quadrilaterals, given by the complex coordinates of their vertices A n ( a n ) , B n ( b n ) , C n ( c n ) , D n ( c n ) , n 0 (see the notation in [11]). The iterations are defined recursively for n 0 as:
a n + 1 = α a n + ( 1 α ) b n b n + 1 = α b n + ( 1 α ) c n c n + 1 = α c n + ( 1 α ) d n d n + 1 = α d n + ( 1 α ) a n .
In this paper, we investigate the dynamic geometry generated by the sequence ( A n B n C n D n ) n 0 , when α is a complex number. Notice that when α is complex, the quadrilaterals A n B n C n D n are not always nested. The work extends results for triangles in [12], preparing the ground for the study of the general case of Kasner polygons.

2. Preliminaries

The system (1) can be written in matrix form as
X n + 1 = a n + 1 b n + 1 c n + 1 d n + 1 = α 1 α 0 0 0 α 1 α 0 0 0 α 1 α 1 α 0 0 α a n b n c n d n = T X n ,
where X n = ( a n , b n , c n , d n ) T , n 0 . In this notation, one can write
X n = T n X 0 .
The matrix T has the characteristic polynomial
p T ( u ) = u α 4 1 α 4 = u 4 4 u 3 α + 6 u 2 α 2 6 u α 3 + α 4 1 α 4 = u 1 u 2 α + 1 u 2 2 α u + 2 α 2 2 α + 1 ,
whose roots can be written as u 0 = 1 and
u 1 = α + ( 1 α ) i = ( 1 i ) α 1 i 2
u 2 = α ( 1 α ) = 2 α 1 2
u 3 = α ( 1 α ) i = ( 1 + i ) α 1 + i 2 .
A direct computation shows that
T = F 1 1 0 0 0 0 u 1 0 0 0 0 u 2 0 0 0 0 u 3 F ,
where the matrices F and F 1 are given by
F = 1 1 1 1 1 i 1 i 1 1 1 1 1 i 1 i , F 1 = 1 4 1 1 1 1 1 i 1 i 1 1 1 1 1 i 1 i .
By using (7), for every positive integer n, we have the following relations
T n = F 1 1 0 0 0 0 u 1 n 0 0 0 0 u 2 n 0 0 0 0 u 3 n F = 1 4 1 1 1 1 1 i 1 i 1 1 1 1 1 i 1 i 1 0 0 0 0 u 1 n 0 0 0 0 u 2 n 0 0 0 0 u 3 n 1 1 1 1 1 i 1 i 1 1 1 1 1 i 1 i .
By Formula (3), one obtains
a n = g 0 + M u 1 n + N u 2 n + P u 3 n b n = g 0 + ( M i ) u 1 n + ( N ) u 2 n + ( P i ) u 3 n c n = g 0 + ( M ) u 1 n + N u 2 n + ( P ) u 3 n d n = g 0 + ( M i ) u 1 n + ( N ) u 2 n + ( P i ) u 3 n ,
where g 0 = a 0 + b 0 + c 0 + d 0 4 , where multiplying (9) by ( a 0 , b 0 , c 0 , d 0 ) T we obtain
M = a 0 b 0 i c 0 + d 0 i 4 , N = a 0 b 0 + c 0 d 0 4 , P = a 0 + b 0 i c 0 d 0 i 4 .
From these formulae (but also from (1)), notice that a n + b n + c n + d n = 4 g 0 , n 0 ; hence, all polygons A n B n C n D n have the same centroid G 0 . Clearly, when M , N , P 0 , the terms u 1 n , u 2 n , and u 3 n appear explicitly in (10).

3. Dynamical Properties in the Case of Real Parameter

In this section, we study the convergence of the sequence of the Kasner quadrilaterals when α is a real number. By Formula (10), the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are convergent if and only if | u 1 | < 1 , | u 2 | < 1 , and | u 3 | < 1 , that is,
| u 1 | = | ( 1 i ) α 1 i 2 | = 2 | α 1 i 2 | < 1 , | u 2 | = 2 | α 1 2 | < 1 , | u 3 | = | ( 1 + i ) α 1 + i 2 | = 2 | α 1 + i 2 | < 1 .
First, one can easily check that the condition | u 2 | < 1 is equivalent to α ( 0 , 1 ) .
Then, because α is real, we clearly have | u 1 | = | u 3 | ; hence, the conditions | u 1 | < 1 and | u 3 | < 1 become equivalent to | u 1 u 3 | < 1 , that is,
| u 1 u 3 | = 2 | α 1 i 2 | | α 1 + i 2 | = 2 α 2 α + 1 2 < 1 ,
which is equivalent to α ( 1 α ) < 0 , that is, α ( 0 , 1 ) .

4. Dynamical Properties in the Case of Complex Parameter

We now discuss the dynamics obtained when α is a complex number.
It is convenient to define the following points
z 1 = 1 2 1 2 i , z 2 = 1 2 , z 3 = 1 2 + 1 2 i ,
representing the centres of the open disks
D 1 z 1 , 2 2 , D 2 z 2 , 1 2 , D 3 z 3 , 2 2 ,
and of the circles depicted in Figure 1
C 1 z 1 , 2 2 , C 2 z 2 , 1 2 , C 3 z 3 , 2 2 .
Considering the real numbers r 1 , r 2 , r 3 , θ 1 , θ 2 , θ 3 , by (4), (5), and (6), we obtain
u 1 = r 1 e 2 π i θ 1 = 2 α z 1 e π i 4 , u 2 = r 2 e 2 π i θ 2 = 2 α z 2 , u 3 = r 3 e 2 π i θ 3 = 2 α z 3 e π i 4 .
By (16), we deduce that for a given j = 1 , 2 , 3 , if α D j , then we have r j < 1 . Moreover, if α C j , then it follows that r j = 1 . The distinct behaviours below emerge:
  • If α D 1 D 2 D 3 , then 0 < r 1 , r 2 , r 3 < 1 .
    One can easily check the set inclusion D 1 D 3 D 2 .
  • If α is in the interior of the complement of D 1 D 3 , then max { r 1 , r 3 } > 1 .
  • If α C 1 C 2 C 3 , then α { 0 , 1 } .
The boundary of the shaded region in Figure 1 consists of two arcs
U 1 = C 1 D 3 , U 3 = C 3 D 1 ,
which can be parametrised as
α ( t ) = z 1 + 2 2 cos t + i sin t , t π 4 , 3 π 4 z 3 + 2 2 cos t + i sin t , t 5 π 4 , 7 π 4 .
To describe the orbits of the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 , one first needs to understand the behaviour of the sequence ( z n ) n 0 , where z C (see, for example, Lemma 2.1 in [13], or Lemma 5.2 in [14]), which is shown in Figure 2.
Lemma 1.
Let z = r e 2 π i θ , where r 0 , θ R . The orbit of ( z n ) n 0 is:
( a ) A spiral convergent to 0 for r < 1 ;
( b ) A divergent spiral for r > 1 ;
( c ) A regular k gon if z is a primitive k th root of unity, k 3 ;
( d ) A dense subset of the unit circle if r = 1 and θ R Q .
When θ = j / k Q is irreducible, then the terms of the spirals obtained in (a) and (b) align along k rays.
To prove part (d), we use that z n = e 2 π i n θ = e 2 π i ( n θ + m ) for n 0 and m integers. By Kronecker’s Lemma ([15], Theorem 442), the set { n θ + m : m , n Z , n 0 } is dense in the set of real numbers R ; hence, the set { z n : n 0 } is dense within the unit circle.
As linear combinations of ( u 1 n ) n 0 , ( u 2 n ) n 0 , and ( u 3 n ) n 0 , the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 , given by the explicit Formula (10) in the complex plane, exhibit the following behaviour.
Lemma 2.
The patterns produced by Formula (10) are summarized below:
1. 
Convergent if 0 < r 1 , r 2 , r 3 < 1 ;
2. 
Divergent if max { r 1 , r 3 } > 1 ;
3. 
Periodic if r 1 = r 3 = 1 (that is, when α = 0 or α = 1 );
4. 
There are two distinct patterns when 0 < min { r 1 , r 3 } < max { r 1 , r 3 } = 1 .
Denoting θ = θ 1 if r 1 = 1 or θ = θ 3 if r 3 = 1 , then the orbit:
(a) 
Has k convergent subsequences if θ = j k is an irreducible fraction;
(b) 
Is dense within a circle when θ is irrational.
The details of the geometric patterns obtained in each case are presented below.
In all figures, we consider the initial polygon of complex coordinates
A 0 ( 4 + 12 i ) , B 0 ( 0 ) , C 0 ( 8 ) , D 0 ( 12 + 1 i ) ,
for which Formula (11) gives the values
G = 4 + 5 i , M = 5 + 6 i , N = 2 + i , P = 1 .
The position of α relative to relevant boundaries is indicated in the left diagram with a star, while the iterations of the polygon are displayed on the right, where the star indicates the position of the centroid. All the simulations have been implemented in Matlab® 2021b.

4.1. Convergent Orbits

If 0 < r 1 , r 2 , r 3 < 1 , then by (16), the sequences u 1 n , u 2 n , and u 3 n are convergent if and only if α D 1 D 3 . Hence, by (10), we obtain that ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 converge to g 0 . We can formulate the following result.
Theorem 1.
The following assertions hold:
(1)
The sequence ( A n B n C n D n ) n 0 is convergent if and only if α D 1 D 2 .
(2)
When the sequence ( A n B n C n D n ) n 0 is convergent, its limit is the degenerated quadrilateral at G 0 , the centroid of the initial quadrilateral A 0 B 0 C 0 D 0 .
Proof. 
The intersection D 1 D 3 is shaded in Figure 1.
( 1 ) Clearly, α D 1 D 3 is equivalent to r 1 < 1 and r 3 < 1 (in this case, one also has α D 2 ). The relation (10) shows that the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are convergent if and only if ( u 1 n ) n 0 , ( u 2 n ) n 0 , and ( u 3 n ) n 0 are convergent, which happens when u 1 n 0 , u 2 n 0 , and u 3 n 0 .
( 2 ) Adding the equation in the system (1), one obtains that for every integer n 0 , we have a n + b n + c n + d n = a 0 + b 0 + c 0 + d 0 = 4 g 0 , where g 0 is the complex coordinates of the centroid G 0 of the initial quadrilateral A 0 B 0 C 0 D 0 . Assume that a n a * , b n b * , c n c * , and d n d * . From system (1), we obtain
a * = α a * + ( 1 α ) b * b * = α b * + ( 1 α ) c * c * = α c * + ( 1 α ) d * d * = α d * + ( 1 α ) a * .
Because α 1 , the only solution of this system is a * = b * = c * = d * = g 0 . □
For 0 < α < 1 , one has α D 1 D 3 , and moreover, in this case, the vertices A n + 1 , B n + 1 , C n + 1 , D n + 1 are interior points of the segments [ A n , B n ] , [ B n , C n ] , [ C n , D n ] , and [ D n , A n ] , respectively. Such an example is depicted in Figure 3.
On the other hand, when the parameter α D 1 D 3 is not real, the orbit is convergent, but the points are not aligned any more, as illustrated in Figure 4.

4.2. Periodic Orbits

If r 1 = r 2 = r 3 = 1 , then | α z 1 | = | α z 3 | = 2 2 and | α z 2 | = 1 2 , which can only happen for α C 1 C 2 C 3 = { 0 , 1 } .
Case 1.  α = 0 . From the system (1), for all n 0 , one obtains
a n + 4 = b n + 3 = c n + 2 = d n + 1 = a n .
Similarly, b n + 4 = b n , c n + 4 = c n , and d n + 4 = d n , so the sequence terms satisfy
a n : a 0 , b 0 , c 0 , d 0 , a 0 , b 0 , c 0 , b n : b 0 , c 0 , d 0 , a 0 , b 0 , c 0 , d 0 , c n : c 0 , d 0 , a 0 , b 0 , c 0 , d 0 , a 0 , d n : d 0 , a 0 , b 0 , c 0 , d 0 , a 0 , b 0 , .
Case 2. α = 1 . From the system (1), for all n 0 , one obtains
a n + 1 = a n , b n + 1 = b n , c n + 1 = c n , d n + 1 = d n ,
so, in this case, the sequences are actually constant.

4.3. Divergent Orbits

If max { r 1 , r 3 } > 1 , then α i n t D 1 D 3 c ; hence, by (16), either u 1 n or u 3 n are divergent. By Formula (10), the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are divergent (as long as the corresponding coefficients M, N, P in (10) are not all vanishing).
Figure 5 shows a divergent iteration. The diagram on the left we plot the position of α , while on the right side we illustrate the polygons A n B n C n D n , n = 0 , , 10 .

4.4. Orbits with a Finite Number of Convergent Subsequences

If 0 < min { r 1 , r 3 } < max { r 1 , r 3 } = 1 , then one either has α C 1 D 3 for r 1 = 1 , or α C 3 D 1 for r 3 = 1 . The orbit has a finite number of limit points if the complex argument θ of u 1 if r 1 = 1 or of u 3 if r 3 = 1 is rational.

4.4.1. Upper Arc of C 1

First, assume that r 1 = max { r 1 , r 3 } = 1 , i.e., α is on the upper arc C 1 D 3 .
As α C 1 , there is t 1 8 , 3 8 with α = z 1 + 2 2 e 2 π i t , so by (16), we obtain
u 1 = e 2 π i θ 1 = 2 α z 1 e π i 4 = e 2 π i t 1 8 .
When θ 1 = p q is an irreducible fraction, the orbit has a finite number of convergent subsequences. Therefore, we have the following result.
Theorem 2.
If for the integers 0 < p < q , we have θ 1 = p q 0 , 1 4 is an irreducible fraction, then u 1 = e 2 π i p q and by Formula (10), the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 have subsequences which converge to the vertices of a regular q gon centred at G 0 of radius | M | .
Proof. 
In this case, we have u 1 n q + j = u 1 j for j = 0 , , q 1 and u 2 n 0 and u 3 n 0 , so using the notations of (10) and (11), one obtains the relations
lim n a n q + j = lim n g 0 + M u 1 n q + j + N u 2 n q + j + P u 3 n q + j = g 0 + M u 1 j lim n b n q + j = lim n g 0 + ( M i ) u 1 n q + j + ( N ) u 2 n q + j + ( P i ) u 3 n q + j = g 0 + ( M i ) u 1 j lim n c n q + j = lim n g 0 + ( M ) u 1 n q + j + N u 2 n q + j + ( P ) u 2 n q + j = g 0 + ( M ) u 1 j lim n d n q + j = lim n g 0 + ( M i ) u 1 n q + j + ( N ) u 2 n q + j + ( P i ) u 3 n q + j = g 0 + ( M i ) u 1 j ,
which ends the proof. This case is depicted in Figure 6. The sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are plotted in Figure 7. Moreover, one can check that for θ 1 = 1 / 5 the limit polygon is a pentagon centred at G 0 , of radius | M | 7.81 (by (19)). □

4.4.2. Lower Arc of C 3

Similarly, if r 3 = max { r 1 , r 3 } = 1 , then α is on the arc C 3 D 1 defined by (17). Therefore, there is t 5 π 8 , 7 π 8 with α = z 3 + 2 2 e 2 π i t , and by (16), we obtain
u 3 = e 2 π i θ 3 = 2 α z 3 e π i 4 = e 2 π i t + 1 8 .
The following result can be proved similarly to Theorem 2.
Theorem 3.
If for the integers 0 < p < q , we have θ 3 = p q 3 4 , 1 is an irreducible fraction, then u 1 = e 2 π i p q and by Formula (10), the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 have q subsequences convergent to the vertices of four regular q gons centred at G 0 of radius | P | .
The first 200 iterations obtained when θ 3 = 5 6 are presented in Figure 8.
The sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are plotted in Figure 9. Similarly to (23), the limit polygon is a hexagon centred at G, which has radius | P | = 1 .

4.5. Dense Orbits

When 0 < min { r 1 , r 3 } < max { r 1 , r 3 } = 1 but θ 1 or θ 3 are irrational modulo 2 π , the orbits of ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 are dense within circles.

4.5.1. Upper Arc of C 1

First, assume that 0 < r 3 < r 1 = 1 , i.e., α is on the upper arc C 1 D 3 . Using the notations in (22), the following result can be deduced from Lemma 1 (d).
Theorem 4.
If r 1 = 1 and θ 1 0 , 1 4 is irrational, then the set of limit points for each of the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 is the circle centred at G 0 of radius | M | .
Proof. 
By (10), we have a n = g 0 + M u 1 n + N u 2 n + P u 3 n , with M, N, and P constants given by (11). Because | u 2 | < 1 , | u 3 | < 1 , we have a n = g 0 + M u 1 n + z n , where lim n z n = 0 .
Let z be an arbitrary point on the circle of centre G 0 and radius | M | . If M = 0 , then lim n a n = g 0 . Otherwise, denoting z = z g 0 M , we have z C ( 0 , 1 ) . Because u 1 = e 2 π i θ 1 with θ 1 irrational, by Lemma (1), it follows that there is a subsequence n 1 < n 2 < such that lim k u 1 n k = z . For ε > 0 , one can find K 1 ( ε ) and K 2 ( ε ) such that
| u 1 n k z | < 1 | M | + 1 ε , k K 1 ( ε ) and | z n k | < 1 | M | + 1 ε , k K 2 ( ε ) ,
hence, for k max { K 1 ( ε ) , K 1 ( ε ) } , one obtains
| a n k z | = | g 0 + M u 1 n k + z n k g 0 M z | | M | · | u 1 n k z | + | z n k | < ε ,
hence lim k a n k = z . This shows that z is a limit point for the sequence ( a n ) n 0 . Analogously, this is proved for ( b n ) n 0 , ( c n ) n 0 and ( d n ) n 0 . □
Figure 10 illustrates the position of α and the polygons obtained for n = 10 iterations, respectively, when α C 1 D 3 . Figure 11 depicts the vertices of the original quadrilateral of affixes ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 , and 200 iterations.

4.5.2. Lower Arc of C 3

When 0 < r 1 < r 3 = 1 , α is on the arc C 3 D 1 defined by (17), as in Figure 12. Using the notations in (24), we can formulate the following result.
Theorem 5.
If r 3 = 1 and θ 3 3 4 , 1 is irrational, then the set of limit points for each of the sequences ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 is the circle centred at G 0 of radius | P | .
Proof. 
The proof follows the similar lines as for Theorem 4, but now by (10), one has a n = g 0 + M u 1 n + N u 2 n + P u 3 n . Because | u 1 | < 1 , | u 2 | < 1 , we obtain a n = g 0 + z n + P u 3 n , where lim n z n = 0 . Figure 12 shows the position of α and the first n = 10 iterations, respectively, when α C 3 D 1 . Figure 13 plots the vertices of the original quadrilateral of affixes ( a n ) n 0 , ( b n ) n 0 , ( c n ) n 0 , and ( d n ) n 0 , and 200 iterations. □

Author Contributions

All authors claim to have contributed significantly and equally to this work. All authors have read and agreed to the published version of the manuscript.

Funding

This research was funded by “1 Decembrie 1918” University of Alba Iulia through scientific research funds.

Acknowledgments

The authors wish to thank the referees for their valuable feedback and constructive comments, which helped to improve the quality of the manuscript.

Conflicts of Interest

The authors declare no conflict of interest.

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Figure 1. Plots of the circles C 1 , C 2 , and C 3 defined in Formula (15).
Figure 1. Plots of the circles C 1 , C 2 , and C 3 defined in Formula (15).
Mathematics 10 03334 g001
Figure 2. The terms z n , n = 0 , , 70 obtained for (a) r = 0.98 and x = 5 / 10 ; (b) r = 1.01 and x = 1 / 8 ; (c) r = 1 and x = 1 / 8 ; (d) r = 1 and x = 5 / 10 . Arrows indicate the orbit’s direction, and the dotted line represents the unit circle. The point z = r exp ( 2 π i x ) is shown as a square.
Figure 2. The terms z n , n = 0 , , 70 obtained for (a) r = 0.98 and x = 5 / 10 ; (b) r = 1.01 and x = 1 / 8 ; (c) r = 1 and x = 1 / 8 ; (d) r = 1 and x = 5 / 10 . Arrows indicate the orbit’s direction, and the dotted line represents the unit circle. The point z = r exp ( 2 π i x ) is shown as a square.
Mathematics 10 03334 g002
Figure 3. Convergent orbits (right) obtained for α = 0.25 (left).
Figure 3. Convergent orbits (right) obtained for α = 0.25 (left).
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Figure 4. Convergent orbits (right) obtained for α = 1 2 + 3 12 i (left).
Figure 4. Convergent orbits (right) obtained for α = 1 2 + 3 12 i (left).
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Figure 5. Divergent orbits (right) obtained for α = z 1 + 2 2 cos 2.5 + i sin 2.5 (left).
Figure 5. Divergent orbits (right) obtained for α = z 1 + 2 2 cos 2.5 + i sin 2.5 (left).
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Figure 6. First 200 iterations (right) obtained for θ 1 = p / q = 1 / 5 where α = z 1 + 2 2 e 2 π i 1 8 + 1 5 (left).
Figure 6. First 200 iterations (right) obtained for θ 1 = p / q = 1 / 5 where α = z 1 + 2 2 e 2 π i 1 8 + 1 5 (left).
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Figure 7. Iterations obtained for θ 1 = 1 5 . (a) ( a n ) n = 0 199 ; (b) ( b n ) n = 0 199 ; (c) ( c n ) n = 0 199 ; (d) ( d n ) n = 0 199 .
Figure 7. Iterations obtained for θ 1 = 1 5 . (a) ( a n ) n = 0 199 ; (b) ( b n ) n = 0 199 ; (c) ( c n ) n = 0 199 ; (d) ( d n ) n = 0 199 .
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Figure 8. First 200 iterations (right) obtained for θ 3 = p / q = 5 / 6 where α = z 3 + 2 2 e 2 π i 5 6 1 8 (left).
Figure 8. First 200 iterations (right) obtained for θ 3 = p / q = 5 / 6 where α = z 3 + 2 2 e 2 π i 5 6 1 8 (left).
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Figure 9. Iterations obtained for θ 3 = 5 6 . (a) ( a n ) n = 0 199 ; (b) ( b n ) n = 0 199 ; (c) ( c n ) n = 0 199 ; (d) ( d n ) n = 0 199 .
Figure 9. Iterations obtained for θ 3 = 5 6 . (a) ( a n ) n = 0 199 ; (b) ( b n ) n = 0 199 ; (c) ( c n ) n = 0 199 ; (d) ( d n ) n = 0 199 .
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Figure 10. Orbits for n = 10 iterations (right), for α = z 1 + 2 2 cos 1 + i sin 1 (left).
Figure 10. Orbits for n = 10 iterations (right), for α = z 1 + 2 2 cos 1 + i sin 1 (left).
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Figure 11. Orbits for θ 1 = 1 2 π . (a) ( a n ) n 0 ; (b) ( b n ) n 0 ; (c) ( c n ) n 0 ; (d) ( d n ) n 0 .
Figure 11. Orbits for θ 1 = 1 2 π . (a) ( a n ) n 0 ; (b) ( b n ) n 0 ; (c) ( c n ) n 0 ; (d) ( d n ) n 0 .
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Figure 12. Dense orbits obtained after n = 10 iterations (right), generated for α = z 3 + 2 2 e 2 π i 3 π 1 8 (left), when u 3 = e 2 π i θ 3 , with θ 3 = 3 π .
Figure 12. Dense orbits obtained after n = 10 iterations (right), generated for α = z 3 + 2 2 e 2 π i 3 π 1 8 (left), when u 3 = e 2 π i θ 3 , with θ 3 = 3 π .
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Figure 13. Orbits for θ 3 = 3 π . (a) ( a n ) n 0 ; (b) ( b n ) n 0 ; (c) ( c n ) n 0 ; (d) ( d n ) n 0 .
Figure 13. Orbits for θ 3 = 3 π . (a) ( a n ) n 0 ; (b) ( b n ) n 0 ; (c) ( c n ) n 0 ; (d) ( d n ) n 0 .
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Andrica, D.; Bagdasar, O. On the Dynamic Geometry of Kasner Quadrilaterals with Complex Parameter. Mathematics 2022, 10, 3334. https://doi.org/10.3390/math10183334

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Andrica D, Bagdasar O. On the Dynamic Geometry of Kasner Quadrilaterals with Complex Parameter. Mathematics. 2022; 10(18):3334. https://doi.org/10.3390/math10183334

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Andrica, Dorin, and Ovidiu Bagdasar. 2022. "On the Dynamic Geometry of Kasner Quadrilaterals with Complex Parameter" Mathematics 10, no. 18: 3334. https://doi.org/10.3390/math10183334

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