1. Introduction
Let
be the class of functions
that are analytic in the open unit disk
and normalized by the conditions
and
For this class, we introduce a subclass
of
consisting of specific functions
given by
This class was introduced by Güney, Breaz and Owa [
1]. They considered
given by
for
and showed that
For
we define the fractional integral of order
as follows:
where
is the Gamma function.
The fractional derivative of order
for
is defined by
Further,
is defined by
The definitions
and
were given by Owa [
2,
3]. With the above definitions, we know that
and
Thus, we have
and
for
With the above the fractional derivative, we introduce the subclass
of
as follows:
with some real
and
where
and
If
and
in (
1), then we have
for the class
Functions
in the class
were discussed by Güney, Breaz and Owa [
1]. Let us consider a function
given by
with
Then,
satisfies
and
Therefore,
given by (
2) belongs to the class
. Accordingly, it is very important to provide example functions
for the new class
2. Conditions of for the Class
We first consider the following condition on for the class
Theorem 1.
If satisfiesfor some real α and then Proof. We define a function
as follows:
for
which satisfies (
3). Then, we see that
is analytic in
that
and that
For such a function
we have
This shows us that
□
If we consider and in Theorem 1, then we have the following corollary.
Corollary 1.
If satisfiesfor some real α and then Next, we derive the following theorem.
Theorem 2.
If satisfiesfor some real α and then If satisfiesfor some real α and then Proof. For
and
we have that
It follows from the above that
for
. Thus, we know by Theorem 1 that if
satisfies
then
Finally, we see that the inequality (
6) implies (
5).
If
we also have that
Noting that if
satisfies
we obtain the inequality in (
4). Further, if we consider a function
given by
with
then
satisfies
If we take a function
given by
with
then
satisfies the equality in (
5). □
3. Coefficient Inequalities of for
We would like to discuss coefficient inequalities of
for the class
We introduce the lemma established by Carathéodory [
4].
Lemma 1.
If a function given byis analytic in and with thenThe equality in (7) is satisfied by such that With the above lemma, we see the following lemma.
Lemma 2.
If a function given byis analytic in and with thenThe equality in (8) is satisfied by such that Applying Lemma 2, we prove the following theorem.
Theorem 3.
If thenandfor where The equalities in (9) and (10) are satisfied by such thatwith Proof. Let us consider a function
as follows:
for
Then, we know that
is analytic in
and that
Thus, Lemma 2 implies that
and the equality in (
12) is satisfied by
By (
11), we see
It is clear that
Further, we calculate
Therefore, for
we have
Using
for
we have
This proves the coefficient inequality (
9) for
□
Considering the coefficient for
in (
13) and (
14), we prove
Therefore, using (
8) and (
15), it follows that
This shows the coefficient inequality for
in (
10).
Furthermore, we have from (
13) and (
14) that
Thus, by mathematical induction, we also prove that
for
Finally, considering a function
given by
Equation (
11) implies that
and that
This gives us
Thus, we obtain the following:
with
Taking in Theorem 3, we see the following corollary.
Corollary 2.
If thenandfor where 4. Argument Properties of Fractional Derivatives
For analytic functions
and
in
,
is said to be subordinate to
in
written
if there exists a function
analytic in
with
and
such that
If
is univalent in
then
if and only if
and
[
5]. For subordinations, Miller and Mocanu [
6] gave the following lemma.
Lemma 3.
Let be the solution of and for If is analytic in with thengives It follows that the subordination given in (
16) implies that
and the subordination (
17) implies that
We also introduce the next lemma, which was established by Nunokawa [
7].
Lemma 4.
Let be analytic in with and . If there exists a point such thatandfor some real then we havewhereand Now we have the following theorem.
Theorem 4.
If satisfiesfor some and thenwhere Proof. For
satisfying (
20), we define the function
as follows:
Then,
is analytic in
with
and
, as follows from (
20). For the above-defined
, we see that
where
and
Let
and
Then, we have
Since
by (
20), using Lemma 4, we obtain the following:
This completes the proof of the theorem. □
Taking and in Theorem 4, we have the following corollary.
Corollary 3.
If satisfiesfor some thenwhere β is given by (21). Remark 1.
If we take then we have Next, applying Lemma 4, as developed by Nunokawa [
7], we prove the following theorem.
Theorem 5.
If satisfiesfor some α and thenwhere Proof. We consider a function
given by (
22) for
Then,
is analytic in
with
For the above-defined
we see that
We suppose that there exists a point
such that
and
Then, Lemma 4 gives us the following:
where
k is given by (
18) and (
19). If
then
and
This contradicts the condition (
23) of the theorem. If
then we also have that
This also contradicts the condition (
23) of the theorem for
Therefore, we say that there is no
such that
and
This implies that
□
Taking and in Theorem 5, we have the following corollary.
Corollary 4.
If satisfiesfor some real α thenwhere is given by (24). Next, we consider
given by
with
,
and
Then
satisfies
To discuss such an argument problem, we need the result devised by Fejér and Riesz [
8] (or by Tsuji [
9]).
Lemma 5.
Let a function be analytic in Then, satisfieswhere the above integral on the left-hand side is considered along the real axis. Remark 2.
When we make the change of variables in Lemma 5, Equation (25) becomes Further, Gwynme [
10] gave the following lemma.
Lemma 6.
Let be a complex valued harmonic function defined on a neighborhood of a closed disc of radius one and center the origin in the complex plane. Thenand Now, we derive the following theorem.
Theorem 6.
If satisfiesfor some α thenwhere and Proof. We note that
and
It follows from (
28) and (
29) that
where
,
and
Using (
26) for
we see that
Therefore, if
satisfies (
27), then
satisfies
□
Taking and in Theorem 6, we have the following corollary.
Corollary 5.
If satisfiesfor some α then Further, on applying Lemma 6, we arrive at the following theorem.
Theorem 7.
If satisfiesfor some α and β thenwhere and Proof. From (
30), we see that
for
It follows that (
31) gives
Applying Lemma 6, we obtain
Therefore, (
32) becomes
□
Setting and in Theorem 7, we obtain the following corollary.
Corollary 6.
If satisfiesfor some α and β then Example 1.
We consider a function given bywith If we write that satisfiesandTherefore, we haveFor such a function we obtainIf we consider some β such thatthen
Author Contributions
Conceptualization, H.Ö.G. and S.O.; methodology, H.Ö.G. and S.O.; writing—original draft preparation, S.O.; writing—review and editing, H.Ö.G. and S.O. All authors have read and agreed to the published version of the manuscript.
Funding
This research received no external funding.
Data Availability Statement
The manuscript has no associated data.
Acknowledgments
The authors would like to thank the editor and reviewers for their valuable comments and suggestions which helped us to improve the content of this paper.
Conflicts of Interest
The authors declare no conflicts of interest.
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