Computation Procedure: The explicit matrix representations in this section were derived through the following systematic procedure: For each algebra, the quasi-centroid condition from Lemma 1 was applied, generating a system of linear equations in the matrix entries . The generation and initial simplification of this large system of equations were performed using symbolic computation software (Wolfram Mathematica 14.2) to ensure accuracy and efficiency. Subsequently, the final solving of the system, analysis of the solution space, and construction of the basis matrices (as listed in Theorem 1–4) were carried out manually. This hybrid approach ensures computational rigor while providing clear, interpretable results.
We now present our main results, beginning with the two-dimensional case.
Proof. Applying Lemma 1 to determine the constraints on the matrix entries, we analyze each algebra separately.
Case 1: Algebra .
This algebra has multiplication
with all other brackets equal to zero. Let
have matrix representation
relative to the basis
.
The quasi-centroid condition requires for all . Due to commutativity symmetry, many conditions are automatically satisfied. The nontrivial constraints are listed below:
Thus .
Thus .
Therefore, the matrix representation of
is
which corresponds to the basis
.
Case 2: Algebra .
This algebra has multiplications and , with all other products equal to zero. Using the same matrix representation , the nontrivial constraints are listed below:
Thus .
Thus .
Thus .
Thus .
The nontrivial coefficient relations are
and
. Therefore, the matrix representation of
is
which corresponds to the basis
.
This completes the proof for both three-dimensional non-abelian Mock-Lie algebras. □
Proof. Applying Lemma 1, we analyze each four-dimensional non-abelian Mock-Lie algebra separately. For each algebra, we consider a linear transformation with matrix representation relative to the basis .
Case 1: Algebra .
This algebra has multiplication with all other brackets equal to zero. The nontrivial constraints are listed below:
Therefore, the matrix representation is
which corresponds to the basis in
Table 4.
Case 2: Algebra .
This algebra has multiplications and , with all other products equal to zero. The nontrivial constraints are listed below.
Thus, nontrivial coefficient relations are
and
. The matrix representation is
corresponding to the basis in
Table 4.
Case 3: Algebra .
This algebra has multiplications
and
, with all other products equal to zero. The analysis yields that nontrivial coefficient relations are
for
and
for
. The matrix representation is
corresponding to the basis in
Table 4.
Case 4: Algebra .
This algebra has multiplications and , with all other products equal to zero. The nontrivial constraints are listed below.
For
with
,
From these, we obtain , and .
For
,
This yields and .
Combining all constraints gives
, and
. The matrix representation is
corresponding to the basis in
Table 4.
Case 5: Algebra .
This algebra has multiplications and , with all other products equal to zero. The nontrivial constraints are listed below:
For
with
,
Then and .
For
with
,
Then .
For
,
Then .
Additional constraints yield for and .
The nontrivial coefficient relations are
,
,
, and
. The matrix representation is
corresponding to the basis in
Table 4.
This completes the proof for all four-dimensional non-abelian Mock-Lie algebras. □
Proof. We analyze each five-dimensional non-abelian Mock-Lie algebra systematically, applying Lemma 1. For each algebra, we consider a linear transformation with matrix representation relative to the basis .
Case 1: Algebra .
This algebra has non-zero brackets
The nontrivial constraints are listed below:
For
with
,
Comparing coefficients gives and .
For
,
Then .
Additional analysis yields for , for , and .
The matrix representation is
The treatment methods for the remaining types of algebras are similar. Therefore, only the non-zero brackets and the relationships between the matrix entries are listed as follows:
Case 2: Algebra .
Matrix entries:
for , for , , , and .
Case 3: Algebra .
Matrix entries:
, for , , and .
Case 4: Algebra .
Matrix entries:
for , for , and for .
Case 5: Algebra .
Matrix entries:
for , for , and for .
Case 6: Algebra .
Matrix entries:
, for , for , and for .
Case 7: Algebra .
Matrix entries:
for , , , , , , and .
Case 8: Algebra .
Non-zero bracket: .
Matrix entries: for .
Case 9: Algebra .
Non-zero brackets: , .
Coefficients: for and , and .
Case 10: Algebra .
Non-zero brackets: , .
Matrix entries: for and , , , and .
Case 11: Algebra .
Non-zero brackets: , .
Coefficients: for and , and .
Case 12: Algebra .
Non-zero brackets: , , .
Matrix entries: for and , and .
Case 13: Algebra .
Non-zero brackets: , .
Matrix entries: for and , and .
For each algebra, the remaining matrix entries are free parameters, and the basis elements listed in
Table 5 correspond to these free parameters after applying the matrix entries. The proof is completed. □