Abstract
In this paper, we give an affirmative answer to a question about the sufficient conditions which ensure that the set of mild solutions for a fractional impulsive neutral differential inclusion with state-dependent delay, generated by a non-compact semi-group, are not empty compact and an -set. This means that the solution set may not be a singleton, but it has the same homology group as a one-point space from the point of view of algebraic topology. In fact, we demonstrate that the solution set is an intersection of a decreasing sequence of non-empty compact and contractible sets. Up to now, proving that the solution set for fractional impulsive neutral semilinear differential inclusions in the presence of impulses and delay and generated by a non-compact semigroup is an -set has not been considered in the literature. Since fractional differential equations have many applications in various fields such as physics and engineering, the aim of our work is important. Two illustrative examples are given to clarify the wide applicability of our results.
1. Introduction
Impulsive differential equations and inclusions describe phenomena in which states are changing rapidly at certain moments. In [1,2,3,4,5,6,7,8], the authors examined whether a mild solution for different types of impulsive differential inclusions exist.
The study of neutral differential equations appears in many applied mathematical sciences, such as viscoelasticity and equations that describe the distribution of heat. The structure of neutral equations involve derivatives related to delay beside the function. Neutral differential equations and inclusions were studied in [9,10,11,12]. These papers examined the mild solutions and controllability of the system.
Because the set of mild solutions for a differential inclusion having the same initial point may not be a singleton, many authors are interested in investigating the structure of this set in a topological point of view. An important aspect of such structure is the -property, which means that the homology group of the set of mild solutions is the same as a one-point space. We list some studies in which the authors demonstrated the solution sets satisfying -property: Gabor [13] considered impulsive semilinear differential inclusions with finite delay on the half-line of order one generated by a non-compact semi-group; Djebali et al. [14] worked on impulsive differential inclusions on unbounded domains; Zhou et al. [15] studied the neutral evolution inclusions of order one generated by a non-compact semi-group; Zhou et al. [16] considered fractional stochastic evolution inclusions generated by a compact semi-group; Zhao et al. [17] studied a stochastic differential equation of Sobolev-type which is semilinear with Poisson jumps of order Beddani [18] examined a differential inclusion involving Riemann–Liouville fractional derivatives; Wang et al. [19] worked on semilinear fractional differential inclusions with non-instantaneous impulses; Ouahab et al. [20] considered fractional inclusions that are non-local and have impulses at different times; Zaine [21] studied weighted fractional differential equations. Recently, Zhang et al. [22] proved that the set of -solutions for impulsive evolution inclusions of order one is an -set and generated by m–dissipative operator. Wang et al. [23] proved that the solution for evolution equations that have nonlinear delay and multivalued perturbation on a non-compact interval is an -set.
In [6,24,25,26], the authors studied different kinds of fractional differential inclusions, and, in all cases, they showed that the set of solutions is a compact set. For more work related to this, the reader can consult the book in [27] about the topological properties for evolution inclusions.
However, up to now, proving that the solution set for fractional impulsive neutral semilinear differential inclusions involving delay and generated by a non-compact semigroup is an -set has not been considered in the literature. Thus, this topic is new and interesting and, hence, the question whether there exists a solution set carrying an -structure remains unsolved for fractional differential inclusions when there are impulses, delay (finite or infinite) and the operator families generated by the linear part lack compactness. Therefore, our main goal is to give an affirmative answer to this question. In fact, we study a neutral fractional impulsive differential inclusion with delay which is generated by a non-compact semigroup, and we show that the set of solutions is non-empty and equal to an intersection of a decreasing sequence of sets each of which is non-empty compact and has a homotopy equivalent to a point.
Let , a semigroup on E, which is Banach space, and the infinitesimal generator of Let be a multifunction, , and be given. For every , let , ; where and are defined later.
The present paper shows the solution set of a fractional neutral impulsive semilinear differential inclusion with delay having details as follows:
is not empty, compact and an -set, where , and are the limits of the function evaluated at from the right and the left. Furthermore, denotes the Caputo derivative that has order and lower limit at zero [28].
In the following points, we clarify the originality, importance and the main contributions of this article:
- Up to now, proving that the solution set is an -set for fractional impulsive neutral semilinear differential inclusions involving delay and generated by a non- compact semigroup has not been considered in the literature.
- Demonstrating that the set of solutions is an -set for fractional neutral differential inclusions involving impulses and delay has not been considered yet.
- We do not assume that the semi-group which generates the linear part is compact.
- Proving that the set of solutions is an -set for neutral differential inclusions (without impulses) with a finite delay, , and generated by a non-compact semigroup, has been investigated in [15], while stochastic neutral differential inclusions (without impulsive effects) with finite delay of order and generated by a compact semigroup has been examined in [16].
- Gabor [13] considered Problem 1 on the half-line when and
- Problem 1 is investigated in [19] when and in the absence of delay.
- Our technique can be used to derive suitable conditions, which implies that the solution set is an -set for the problems studied in [13,14,15,16,17,18,19,20,21,22,23] when they contain impulses and delay.
In order to clarify the difficulties encountered to achieve our aim, we point to the normed space ,which consists of piecewise continuous bounded functions defined on with a finite number of discontinuity points and is left continuous at the discontinuity points, and is not necessarily complete. Moreover, unlike the Banach spaces and , the Hausdorff measure of noncompactness on is not specific. Thus, when the problem involves delay and impulses, we cannot consider as the space of solutions. To overcome these difficulties, a complete metric space H is introduced as the space of mild solutions (see the next section). In addition, the function is not necessarily measurable (see Remark 1, and so, a norm different from the uniform convergence norm is introduced (see Equation (2) below).
For recent contributions on neutral differential inclusions of fractional order, Burqan et al. [29] give a numerical approach in solving fractional neutral pantograph equations via the ARA integral transform. Ma et al. [30] studied the controllability for a neutral differential inclusion with Hilfer derivative, and Etmad et al. [31] investigated a neutral fractional differential inclusion of Katugampola-type involving both retarded and advanced arguments.
For more recent papers we cite [32,33,34].
The sections of the paper are organized as follows: We include some background materials in Section 2 as we need them in the main sections. Section 3 is assigned for proving that the solution set of Problem (1) is non-empty and compact. In Section 4, we show that this set is an -set in the complete metric space H. In Section 5, e give an example as an application of the obtained results. Section 6 and Section 7 are the discussion and conclusion sections.
2. Preliminaries and Notation
In all the text we denote for the set of mild solutions for Problem 1 by and by to the quotient space consisting of valued Bohner integrable functions defined on J having the norm . Let be non-empty, convex and compact}.
Definition 1.
(Ref. [35]) Let , a semigroup and be the infinitesimal generator of it. A continuous function is called a mild solution for the problem:
if
where
and .
Lemma 1.
(Ref. [35] (lemma 3.1)) The properties stated below are held:
- (i)
- For every fixed are linear and bounded.
- (ii)
- Assuming we have that for any and
- (iii)
- If ; then for any
Consider the spaces:
- The normed spaceendowed with the norm:
- The Banach spacewhere , , and .
- The complete metric spacewhere the metric function is given by:
- The Banach spacetogether with the norm
The Hausdorff measure of noncompactness on a Banach space is given by
whereis a bounded subset of is the Hausdorff measure of noncompactness on the Banach space and
The Hausdorff measure of noncompactness on is defined by:
whereis a bounded subset of
Remark 1.
Since the function is not necessarily measurablewe do not consider the uniform convergence norm to be the norm defined on the space Θ (see Example 3.1, [36]). Therefore, the multivalued superposition operator
would not be well defined. Therefore, we consider a norm defined by Equation (2).
Definition 2.
A function is said to be a mild solution for if
where .
We assume the following conditions:
is the infinitesimal generator of T, 0 is an element of the resolvent of and , where
where:
For any the multifunctionhas a measurable selection, and for the multifunctionis upper semicontinuous.
There exists a satisfying
There is a such that, for any that is bounded, we have
For any , the function is continuous, and there are and satisfying and for any bounded subset
Lemma 2.
(Ref. [37]) Under condition for any, the fractional power can be defined, and it is linear and closed on its domain . In addition, the following properties are satisfied:
- (i)
- is a Banach space with the norm
- (ii)
- For any , , we have and, assuming , we get .
- (iii)
- For every , is bounded on and there is a constant such that
- (iv)
- is a bounded linear operator on E.
- (v)
- For everyand
We need the next lemmas in order to prove our main results.
Lemma 3.
Assume to be bounded, closed and convex, is a single-valued function, is a multifunction, and for any Suppose that
- (a)
- is a contraction with the contraction constant
- (b)
- is a closed and completely continuous multifunction.
Then, the fixed point set of is not empty. Moreover, the set of fixed points for is compact if it is bounded.
Proof.
is continuous on W since it is a contraction and, hence, it follows by the closeness of that the multifunction is closed. We show that R is condensing, where is the Hausdorff measure of noncompactness on E. Let be a bounded set of W. Since is a contraction with the contraction constant k, we get , where is the Kuratowski measure of noncompactness on E. Because is compact, . Therefore,
This means that R is condensing. By Proposition 3.5.1 in [38], the fixed point set of is not empty. The second part follows from Proposition 3.5.1 in [38]. □
3. The Compactness of
In this section, we show that the set of mild solutions for Problem 1 is nonempty and compact.
For any with let be defined by
Lemma 4.
For any , the function is continuous from to Θ.
Proof.
Assume . Then,
Because is continuous on except for a finite number of points, it follows that , a.e. Since , , and the proof is completed. □
Theorem 1.
Assume that are held and that is equicontinuous. Assume also that the following conditions are satisfied.
The function is continuous and there exists a satisfying and
- (i)
- For anyis strongly measurable.
- (ii)
- There are and withand
Then, is not empty and a compact subset of H provided that
and
where and .
Proof.
A multioperator is defined as the following: let , hence, as a consequence of , the multifunction admits a measurable selection which, by , belongs to , and, therefore, can be defined by
where fand is defined by (8).
We show that a point is a fixed point for if and only if . Assume is a fixed point to . Hence,
Therefore,
which means that satisfies (3), and, thus, it is a mild solution for problem (1). In a similar way, it can be seen that if satisfies (3), then is a fixed point for . Let and be such that
and a function if and only if
where f Notice that . Let
and be a positive real number satisfying
Put . Due to (12), is well defined. The rest of the proof is divided in the following steps:
Step 1. This step shows that . Let and There exists where
Let For every , we get
which implies that . So, by (ii) of Lemma 1, and the Holder inequality, it follows that
This equation with (12) leads to
Then, .
Step 2. is a contraction with a contraction constant
Let and . Then, . From (6), (7) and (11), for every and any , we have that
which yields with (9) that is a contraction with a contraction constant
Step 3. has a closed graph and is compact.
Assume and are sequences in where and . Then,
where . Using , it yields that
So, is bounded in and, hence, there exists a subsequence of . We denote them by where . From Mazur’s Lemma, there exists a sequence of convex combination, of that converges almost everywhere to Note that by, again, for any and any
Set
Note that by (18), , Moreover, since , is upper semicontinuous, it yields Therefore, from the continuity of , and by taking the limit of (19) as , one gets
To prove that the values of are compact, assume and Using similar arguments to the above, we get that has a convergent subsequence . So, is relatively compact. Since the graph of is closed its values are closed and, hence, is relatively compact in
Step 4. We claim that the subsets are equicontinuous, where
Assume . Then, there exists and , where, for
and .
Case 1. Let be two points in .Then,
The hypothesis implies and, hence, by Lemma 1, we get
For we have
Note that then, for we have . As an application of Lemma 3 in [8] and considering , we get
Then,
This leads to
Therefore,
For,
Observe that for every ,
Moreover, since is equicontinuous, and, using the Lebesgue-dominated convergence theorem, one gets
For ,
Case 2. , . Assume , and where Hence, as above, it can be shown that
Then, are equicontinuous.
Step 5. Set and ,. Then, the sequence is a decreasing sequence of not empty, closed and bounded subsets of . So, the set is bounded, closed, convex and . Next, we show that is compact. According to the generalized Cantor’s intersection property, we only need to prove that
where is the Hausdorff measure of noncompactness on . Assume and are fixed. From the fact that is a contraction with a contraction constant , it follows that
Let . Using Lemma 5 in [39], there is a inwith
From the fact that the subsets are equicontinuous, one obtains
Now, let and , .Then, for every there is a such that, for any ,
Note that the assumption implies that for
Moreover, from (4), we have that for
Again, by for every and for almost and, hence, is integrably bounded. As a consequence of Lemma 4 in [40], there is a compact set a measurable set having a measure less than and such that for every and
Moreover, from the fact that is contained in a compact subset, we get
Combining this relation with (26) and (27),it follows that
where . Using the fact that is chosen arbitrary, relation (28) becomes
Using the above inequality and (21)–(23), in addition to the fact that is arbitrary, it follows that
This leads to
The above inequality holds for any natural number n, and by (13) together with taking the limit as we get (20). Then, is not empty and a compact subset of . So, is completely continuous. By applying Lemma 3, we conclude that the fixed points set of is not an empty subset of . Furthermore, by arguing as in Step 1, we can prove that the set of fixed points of is bounded and, hence, by Lemma 3, it is compact in . Therefore, the set is not empty and a compact subset of H. □
4. The Structure Topological of
In the section we prove that is an -set
Definition 3
([41]). A topological space X, which is homotopy equivalent to a point, is called contractible. In other words, there is a continuous map and
Lemma 5
([41]). Let , where A is not empty and X is a complete metric space. Then, A is said to be -set if and only if it is an intersection of a decreasing sequence of contractible sets and as
Now, consider the multi-valued function that is given by:
where is defined by (17). Since on the set of solutions consisting of mild solutions for Problem (1) is equal to the set of solutions consisting of mild solutions for the problem:
Obviously, verifies and, for
Then, we can assume that verifies the next condition:
There exists a function , where for every
We recall the next Lemma. For its proof, we refer the reader to the second step in the proof of Theorem 3.5 in [13].
Lemma 6.
Assume that and are satisfied. Then, there exists a sequence of multifunctions with such that:
- (i)
- Every is continuous for almost .
- (ii)
- , for each and
- (iii)
- (iv)
- For all there is a selection of such that is measurable for each and for is locally Lipschitz.
Remark 2.
(Ref. [19]) The property (iv) in Lemma 6 implies that, for almost ,, is continuous.
Assume is the mild solutions set of the following fractional neutral impulsive semilinear differential inclusions with delay:
Theorem 2.
Assume that the conditions in Theorem 1 after substituting by are held. Then, there exists such that, for , the set is compact and not empty in
Proof.
Let be a fixed natural number. We define a multioperator as the following: if and only if
where f. Due to Lemma 5, verifies , . As a result of Theorem 1, is closed, and is equicontinuous. Set and ,. As in Theorem 1, the sequence is a decreasing sequence of non-empty, closed and bounded subsets of We show that
Let . Choose a natural number with and let be a fixed natural number. Using a similar argument as the one used in the proof of Theorem 1, one gets
where
and Next, due to Remark 4.2 in [7], it follows that for any bounded subset ,
Then, it yields from (ii) in Lemma 5 and (31), for
Similarly, as in the proof of Theorem 1, we confirm the validity of (30).Therefore, by the generalized Cantor’s intersection property, the set is not empty and compact in . As in Theorem 1, the fixed points set of the multivalued function is not empty and a compact subset in Consequently, the set is not empty and a compact subset of H. □
Theorem 3.
Under the conditions of Theorem 2,
Proof.
In view of (iii) in Lemma 8, it can be seen that . Let . Then, there is such that
It follows from that
This means that the sequence is weakly relatively compact in , so we can assume weakly, where As in the proof of Theorem 1, there is a sequence of convex combinations of that converges almost everywhere to f. Note that
and . It yields, from (ii) of Lemma 8, that for almost
which implies that for Moreover, using the fact that is continuous, and taking the limit as in (34), one gets
This means that □
To prove our main results, we need the next lemma.
Lemma 7
([19], Lemma 4.5). Assume that andare two metric spaces.Then, if is locally Lipschitz, then it is Lipschitz on all subsets of X that are compact.
Theorem 4.
Under the assumptions of Theorem 2the set is an -set in H provided that
Proof.
Using Lemma 4 and Theorems 1–3, we only need to prove that is contractible. Assume that and . Consider the following fractional neutral impulsive semilinear:
Using Lemma 6 and Remark 3, is measurable, and for is continuous. Since the multi-valued F satisfies and , then, following the arguments employed in the proof of Theorem 2, the fractional differential Equation (35) has a mild solution ∈satisfying the following integral equation:
Next, we show that the solution is unique. Assume that is another mild solution for (35). Then,
Now, from Lemma 5, the function is continuous from to and, hence, the subset is compact in. Similarly, the set is compact in and, therefore, the set is compact in, and consequently, is compact in . Thus, by (iv) in Lemma 6 and Lemma 7, there exists , for which the estimate
holds for . Therefore, from (38), it yields
Note that when , we have
It yields
Since and are continuous on , there is with Then,
Since , the last relations lead to
Using the generalized Gronwall inequality [42], one has . Since is arbitrary, we conclude that on .
Next, let be fixed. Note that . Then,
By repeating the arguments employed above, we get on Continuing with the same processes, we arrive to on
Next, we prove that is homotopically equivalent to To this end, we define a continuous function , where and . Assume is fixed. Then, there exists a such that
Consider the partition { for . We consider the following cases:
(i) . Put The following fractional neutral differential inclusion is a result of the above discussion:
has a unique mild solution satisfying the next integral equation:
Note that
(ii) Put . Again, the following fractional neutral differential inclusion:
has a unique mild solution and
We continue up to step. That is and put Let be the unique mild solution for the impulsive fractional neutral differential inclusion:
Then,
Note that and. Now, we define at as
Therefore, and
5. Example
Example 1.
Assume that and . For any , we denote by the value of at ω. Let , and domain be defined as
Using [37], there is a compact analytic semi-group generated by A and
where is the orthonormal set of eigenvalues of In addition, for all one gets
So, Furthermore, for each
and . The domain of is defined as
Let be such that
where . We have
and
Letbe a convex compact subset in E, and . Define by
We have
Moreover, for any bounded subset we have, where and, hence, . Then, satisfies and with
Next, let
where is a positive number. Obviously, verifies with
Therefore, by applying Theorems 1 and 4, the set of solutions for the following fractional neutral impulsive semilinear differential inclusions with delay:
is a not empty, compact and an -set provided that
and
where are given by (45)–(47). By choosing and small enough and large enough, we arrive to (50) and (51).
Example 2.
Let and ϱ be as in Example (1) and be a fixed element.
Let be such that
where is measurable,, is measurable, and .
Next, let , where is a continuous function. Then, by choosing and small enough, one can show that and satisfy all assumptions of Theorems 2 (see [15,43]) and, hence, the set of mild solutions for the partial differential inclusions of impulsive neutral type with delay:
is an -set.
6. Discussion
The neutral differential equations and inclusions appear in many applied mathematical sciences such as viscoelasticity, and the equations describe the distribution of heat. Since the set of mild solutions for a differential inclusion having the same initial point may not be a singleton, many authors are interested to investigate the structure of this set in a topological point of view. An important aspect of such structure is the - property, which means that the homology group of the set of mild solutions is the same as a one-point space. In the literature, there are many results on this subject but no result about the topological properties of the set of mild solutions for a fractional neutral differential inclusion generated by a non-compact semigroup in the presence of impulses and delay. As cited in the introduction, when the problem involves delay and impulses, we cannot consider the space as the space of solutions. To overcome these difficulties, a complete metric space H is introduced as the space of mild solutions. In addition, the function is not necessarily measurable, therefore, a norm different from the uniform convergence norm is introduced on (see Equation (2)).
7. Conclusions
During the past two decades, fractional differential equations and fractional differential inclusions have gained considerable importance due to their applications in various fields, such as physics, mechanics and engineering. For some of these applications, one can see [28] and the references therein. In this paper, we have given an affirmative answer for a basic question, which is whether there exists a solution set carrying an -structure when there are impulsive effects and delay on the system, the operator families generated by the linear part lack compactness and the order is fractional. More specifically,
- By utilizing the properties of both multivalued functions, fraction powers of operators, measures of non-compactness and analytic semi-groups, we showed that the mild solutions set for a fractional impulsive neutral semilinear differential inclusions with delay and generated by a non-compact semi-group is not empty, compact and an -set. This means that, from an algebraic topological perspective, it is equivalent to a point.
- Our work generalizes the obtained results in [19], where Problem 1 is investigated without delay and
- Our work generalizes the obtained results in [15] to the case when there are impulsive effects on the system.
- Our technique can be used to prove that the solutions set is an -set for problems considered in [13,14,15,16,17,18,19,20,21,22,23,30] when it is generated by a non-compact semi-group, the order is fractional and there are impulsive effects and delay.
- As a future work, we suggest to extend the work conducted in [24,25,26] to find the sufficient conditions that guarantee that the solution set is an -set.
Author Contributions
Funding acquisition, Z.A. and A.G.I.; investigation, Z.A. and A.G.I.; methodology, Z.A., A.G.I. and A.A.; writing—original draft, Z.A. and A.G.I.; writing—review and editing, Z.A., A.G.I. and A.A. All authors have read and agreed to the published version of the manuscript.
Funding
This research received no external funding.
Data Availability Statement
Not applicable.
Acknowledgments
This research has been funded by the Scientific Research Deanship at University of Ha’il—Saudi Arabia through project number RG-21 101.
Conflicts of Interest
The authors declare no conflict of interest.
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