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Article

Topological Structure of the Solution Sets for Impulsive Fractional Neutral Differential Inclusions with Delay and Generated by a Non-Compact Demi Group

by
Zainab Alsheekhhussain
1,*,
Ahmed Gamal Ibrahim
2 and
Akbar Ali
1
1
Department of Mathematics, Faculty of Science, University of Ha’il, Hail 55476, Saudi Arabia
2
Department of Mathematics, College of Sciences, King Faisal University, P.O. Box 400, Al-Ahsa 31982, Saudi Arabia
*
Author to whom correspondence should be addressed.
Fractal Fract. 2022, 6(4), 188; https://doi.org/10.3390/fractalfract6040188
Submission received: 12 March 2022 / Revised: 24 March 2022 / Accepted: 24 March 2022 / Published: 28 March 2022

Abstract

:
In this paper, we give an affirmative answer to a question about the sufficient conditions which ensure that the set of mild solutions for a fractional impulsive neutral differential inclusion with state-dependent delay, generated by a non-compact semi-group, are not empty compact and an R δ -set. This means that the solution set may not be a singleton, but it has the same homology group as a one-point space from the point of view of algebraic topology. In fact, we demonstrate that the solution set is an intersection of a decreasing sequence of non-empty compact and contractible sets. Up to now, proving that the solution set for fractional impulsive neutral semilinear differential inclusions in the presence of impulses and delay and generated by a non-compact semigroup is an R δ -set has not been considered in the literature. Since fractional differential equations have many applications in various fields such as physics and engineering, the aim of our work is important. Two illustrative examples are given to clarify the wide applicability of our results.

1. Introduction

Impulsive differential equations and inclusions describe phenomena in which states are changing rapidly at certain moments. In [1,2,3,4,5,6,7,8], the authors examined whether a mild solution for different types of impulsive differential inclusions exist.
The study of neutral differential equations appears in many applied mathematical sciences, such as viscoelasticity and equations that describe the distribution of heat. The structure of neutral equations involve derivatives related to delay beside the function. Neutral differential equations and inclusions were studied in [9,10,11,12]. These papers examined the mild solutions and controllability of the system.
Because the set of mild solutions for a differential inclusion having the same initial point may not be a singleton, many authors are interested in investigating the structure of this set in a topological point of view. An important aspect of such structure is the R δ -property, which means that the homology group of the set of mild solutions is the same as a one-point space. We list some studies in which the authors demonstrated the solution sets satisfying R δ -property: Gabor [13] considered impulsive semilinear differential inclusions with finite delay on the half-line of order one generated by a non-compact semi-group; Djebali et al. [14] worked on impulsive differential inclusions on unbounded domains; Zhou et al. [15] studied the neutral evolution inclusions of order one generated by a non-compact semi-group; Zhou et al. [16] considered fractional stochastic evolution inclusions generated by a compact semi-group; Zhao et al. [17] studied a stochastic differential equation of Sobolev-type which is semilinear with Poisson jumps of order α ( 1 , 2 ) ; Beddani [18] examined a differential inclusion involving Riemann–Liouville fractional derivatives; Wang et al. [19] worked on semilinear fractional differential inclusions with non-instantaneous impulses; Ouahab et al. [20] considered fractional inclusions that are non-local and have impulses at different times; Zaine [21] studied weighted fractional differential equations. Recently, Zhang et al. [22] proved that the set of C 0 -solutions for impulsive evolution inclusions of order one is an R δ -set and generated by m–dissipative operator. Wang et al. [23] proved that the solution for evolution equations that have nonlinear delay and multivalued perturbation on a non-compact interval is an R δ -set.
In [6,24,25,26], the authors studied different kinds of fractional differential inclusions, and, in all cases, they showed that the set of solutions is a compact set. For more work related to this, the reader can consult the book in [27] about the topological properties for evolution inclusions.
However, up to now, proving that the solution set for fractional impulsive neutral semilinear differential inclusions involving delay and generated by a non-compact semigroup is an R δ -set has not been considered in the literature. Thus, this topic is new and interesting and, hence, the question whether there exists a solution set carrying an R δ -structure remains unsolved for fractional differential inclusions when there are impulses, delay (finite or infinite) and the operator families generated by the linear part lack compactness. Therefore, our main goal is to give an affirmative answer to this question. In fact, we study a neutral fractional impulsive differential inclusion with delay which is generated by a non-compact semigroup, and we show that the set of solutions is non-empty and equal to an intersection of a decreasing sequence of sets each of which is non-empty compact and has a homotopy equivalent to a point.
Let α ( 0 , 1 ) , r > 0 , J = [ 0 , b ] , T = { Υ ( η ) : η 0 } a semigroup on E, which is Banach space, and A the infinitesimal generator of T . Let F : J × Θ 2 E { ϕ } be a multifunction, h : J × Θ E , 0 = η 0 < η 1 < < η m < η m + 1 = b , and ψ Θ be given. For every η J , let ϰ ( η ) : H Θ , ( ϰ ( η ) x ) ( θ ) = x ( η + θ ) ; θ [ r , 0 ] ; where Θ and H are defined later.
The present paper shows the solution set of a fractional neutral impulsive semilinear differential inclusion with delay having details as follows:
c D 0 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] A x ( η ) + F ( η , ϰ ( η ) x ) , a . e . η [ 0 , b ] { η 1 , , η m } , I i x ( η i ) = x ( η i ) x ( η i + ) , i = 1 , , m , x ( η ) = ψ ( η ) , η [ r , 0 ] ,
is not empty, compact and an R δ -set, where I i : E E , i = 1 , , m , and x ( η i + ) , x ( η i ) are the limits of the function x evaluated at η i from the right and the left. Furthermore, c D 0 , η α denotes the Caputo derivative that has order α ( 0 , 1 ) and lower limit at zero [28].
In the following points, we clarify the originality, importance and the main contributions of this article:
  • Up to now, proving that the solution set is an R δ -set for fractional impulsive neutral semilinear differential inclusions involving delay and generated by a non- compact semigroup has not been considered in the literature.
  • Demonstrating that the set of solutions is an R δ -set for fractional neutral differential inclusions involving impulses and delay has not been considered yet.
  • We do not assume that the semi-group which generates the linear part is compact.
  • Proving that the set of solutions is an R δ -set for neutral differential inclusions (without impulses) with a finite delay, α = 1 , and generated by a non-compact semigroup, has been investigated in [15], while stochastic neutral differential inclusions (without impulsive effects) with finite delay of order α ( 0 , 1 ) and generated by a compact semigroup has been examined in [16].
  • Gabor [13] considered Problem 1 on the half-line when α = 1 and h 0 .
  • Problem 1 is investigated in [19] when h 0 and in the absence of delay.
  • Our technique can be used to derive suitable conditions, which implies that the solution set is an R δ -set for the problems studied in [13,14,15,16,17,18,19,20,21,22,23] when they contain impulses and delay.
In order to clarify the difficulties encountered to achieve our aim, we point to the normed space PC ( [ r , b ] , E ] ,which consists of piecewise continuous bounded functions defined on [ r , b ] with a finite number of discontinuity points and is left continuous at the discontinuity points, and is not necessarily complete. Moreover, unlike the Banach spaces C ( [ r , b ] , E ) and P C ( J , E ) , the Hausdorff measure of noncompactness on PC ( [ r , b ] , E ] is not specific. Thus, when the problem involves delay and impulses, we cannot consider PC ( [ r , b ] , E ] as the space of solutions. To overcome these difficulties, a complete metric space H is introduced as the space of mild solutions (see the next section). In addition, the function η ϰ ( η ) x ¯ ; x ¯ H is not necessarily measurable (see Remark 1, and so, a norm different from the uniform convergence norm is introduced (see Equation (2) below).
For recent contributions on neutral differential inclusions of fractional order, Burqan et al. [29] give a numerical approach in solving fractional neutral pantograph equations via the ARA integral transform. Ma et al. [30] studied the controllability for a neutral differential inclusion with Hilfer derivative, and Etmad et al. [31] investigated a neutral fractional differential inclusion of Katugampola-type involving both retarded and advanced arguments.
For more recent papers we cite [32,33,34].
The sections of the paper are organized as follows: We include some background materials in Section 2 as we need them in the main sections. Section 3 is assigned for proving that the solution set of Problem (1) is non-empty and compact. In Section 4, we show that this set is an R δ -set in the complete metric space H. In Section 5, e give an example as an application of the obtained results. Section 6 and Section 7 are the discussion and conclusion sections.

2. Preliminaries and Notation

In all the text we denote for the set of mild solutions for Problem 1 by Σ ψ F [ r , b ] and by L 1 J , E to the quotient space consisting of E valued Bohner integrable functions defined on J having the norm f L 1 ( J , E ) = 0 b f ( θ ) d θ . Let P c k ( E ) = { B E : B be non-empty, convex and compact}.
Definition 1.
(Ref. [35]) Let h : J E , { Υ ( η ) : η 0 } a C 0 semigroup and A be the infinitesimal generator of it. A continuous function x : J E is called a mild solution for the problem:
c D α z ( η ) = A z ( η ) + h ( η ) , η J , z ( 0 ) = z 0 E ,
if
z ( η ) = K 1 ( η ) z 0 + 0 η ( η τ ) α 1 K 2 ( η τ ) h ( τ ) d τ , η J ,
where K 1 ( η ) = 0 ξ α ( θ ) Υ ( η α θ ) d θ , K 2 ( η ) = α 0 θ ξ α ( θ ) Υ ( η α θ ) d θ ,
ξ α ( θ ) = 1 α θ 1 1 α w α ( θ 1 α ) 0 , w α ( θ ) = 1 π n = 1 ( 1 ) n 1 θ α n 1 Γ ( n α + 1 ) n ! sin ( n π α ) , θ ( 0 , ) and 0 ξ α ( θ ) d θ = 1 .
Lemma 1.
(Ref. [35] (lemma 3.1)) The properties stated below are held:
 (i) 
For every fixed η 0 , K 1 ( η ) , K 2 ( η ) are linear and bounded.
 (ii) 
Assuming | | η ( η ) | | M , η 0 , we have that for any x E , | | K 1 ( η ) x | | M | | x | | and | | K 2 ( η ) x | | M Γ ( α ) | | x | | .
 (iii) 
If η , τ 0 ; then for any x E ,
lim η τ | | K 1 ( η ) x K 1 ( τ ) x | | = 0 , and lim η τ | | K 2 ( η ) x K 2 ( τ ) x | | = 0 .
Consider the spaces:
  • The normed space
    Θ : = { x : [ r , 0 ] E , where x is discontinuous at finite number of points τ 0 , and all the limits x ( τ + ) and x ( τ ) are less than }
    endowed with the norm:
    | | x | | Θ :   = r 0 | | x ( τ ) | | d τ .
  • The Banach space
    P C ( J , E ) : = { u : J E : u | J i C ( J i , E ) , i = 0 , 1 , 2 , , m , and u ( η i + ) , u ( η i ) = u ( η i ) are finite for every i = 1 , 2 , . m } ,
    where J 0 = [ 0 , η 1 ] , J i = ( η i , η i + 1 ] , i = 1 , 2 , , m , and | | v | | P C ( J ; E ) = τ u p η J | | v ( η ) | | .
  • The complete metric space
    H = { x : [ r , b ] E : where x is continuous at η = 0 , x | [ r , 0 ] = ψ , x | J i P C ( J , E ) } ,
    where the metric function is given by:
    d H ( x , y ) = τ u p η J | | x ( η ) y ( η ) | | .
  • The Banach space
    H : = { x : [ r , b ] E where x ( η ) = 0 , η [ r , 0 ] , x | J i P C ( J , E ) }
    together with the norm | | x | | H = τ u p η J | | x ( η ) | | + | | x | [ r , 0 ] | | Θ = τ u p η J | | x ( η ) | | .
The Hausdorff measure of noncompactness on a Banach space P C ( J , E ) is given by
χ P C ( B ) : = max i = 0 , 1 , 2 , , m χ i ( B | J i ¯ ) ,
where B is a bounded subset of P C ( J , E ) and χ i is the Hausdorff measure of noncompactness on the Banach space C ( J i ¯ , E ) and
B | J i ¯ : = { x * : J i ¯ E : x * ( η ) = x ( η ) , η J i and x * ( η i ) = x ( η i + ) , x B } .
The Hausdorff measure of noncompactness on H is defined by:
χ H ( B ) = max i = 0 , 1 , 2 , , m χ i ( B | J i ¯ ) ,
where B is a bounded subset of H .
Remark 1.
Since the function η ϰ ( η ) x ; x ¯ H is not necessarily measurable , we do not consider the uniform convergence norm to be the norm defined on the space Θ (see Example 3.1, [36]). Therefore, the multivalued superposition operator
x S F ( . , ϰ ( . ) x ) 1 = { f L 1 ( J , E ) : f ( η ) F ( η , ϰ ( η ) x ) , a . e . , η J }
would not be well defined. Therefore, we consider a norm defined by Equation (2).
Definition 2.
A function x ¯ H is said to be a mild solution for ( 1 ) if
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J = [ 0 , b ] ,
where f S F ( . , ϰ ( . ) x ) 1 .
We assume the following conditions:
( H A ) A is the infinitesimal generator of T, 0 is an element of the resolvent of A , ρ ( A ) and sup η 0 | | Υ ( η ) | | M , where M 1 .
( H F ) F : J × Θ P c k ( E ) where:
( H F 1 ) For any z Θ , the multifunction η F ( η , z ) has a measurable selection, and for η J , a . e . , the multifunction z F ( η , z ) is upper semicontinuous.
( H F 2 ) There exists a φ L P ( I , R + ) ( P > 1 α ) satisfying
F ( η , z ) φ ( η ) ( 1 + z Θ ) , z Θ and for a . e . η J .
( H F 3 ) There is a β L P ( [ 0 , b ] , E ) , p > 1 α such that, for any D Θ that is bounded, we have
χ E ( F ( η , D ) ) β ( η ) sup θ [ r , 0 ] χ E { z ( θ ) : z D } , a . e . for η J .
( H I ) For any i = 1 , , m , the function I i : E E is continuous, and there are σ i > 0 and ς i > 0 satisfying | | I i ( x ) | | σ i | | x | | , and for any bounded subset D E ,
χ E ( I i ( D ) ) ς i χ E ( I i ( D ) ) .
Lemma 2.
(Ref. [37]) Under condition ( H A ) , for any γ ( 0 , 1 ) , the fractional power A γ can be defined, and it is linear and closed on its domain D ( A γ ) . In addition, the following properties are satisfied:
 (i) 
D ( A γ ) is a Banach space with the norm
| | x | | γ = | | A γ x | | .
 (ii) 
For any η > 0 , x E , we have Υ ( η ) x D ( A γ ) and, assuming x D ( A γ ) , we get A γ Υ ( η ) x = Υ ( η ) A γ x .
 (iii) 
For every η > 0 , A γ Υ ( η ) is bounded on E , and there is a constant C γ > 0 such that
| | A γ Υ ( η ) | | C γ η γ .
 (iv) 
A γ is a bounded linear operator on E.
 (v) 
For every x E ,
A K 2 ( η ) x = A 1 γ K 2 ( η ) A γ x , η J ,
and
| | A γ K 2 ( η ) | | α C γ Γ ( 2 γ ) η α γ Γ ( 1 + α ( 1 γ ) ) , η ( 0 , b ] .
We need the next lemmas in order to prove our main results.
Lemma 3.
Assume W E to be bounded, closed and convex, Φ 1 : W E is a single-valued function, Φ 2 : W P c k ( E ) is a multifunction, and for any x W , Φ 1 ( x ) + y W , y Φ 2 ( x ) . Suppose that
 (a) 
Φ 1 is a contraction with the contraction constant k < 1 2 ;
 (b) 
Φ 2 is a closed and completely continuous multifunction.
Then, the fixed point set of Φ 1 + Φ 2 is not empty. Moreover, the set of fixed points for Φ 1 + Φ 2 is compact if it is bounded.
Proof. 
Φ 1 is continuous on W since it is a contraction and, hence, it follows by the closeness of Φ 2 , that the multifunction R = Φ 1 + Φ 2 is closed. We show that R is χ E condensing, where χ E is the Hausdorff measure of noncompactness on E. Let Z be a bounded set of W. Since Φ 1 is a contraction with the contraction constant k, we get μ E ( Φ 1 ( Z ) ) k μ E ( Z ) 2 k χ E ( Z ) < χ E ( Z ) , where μ E is the Kuratowski measure of noncompactness on E. Because Φ 2 is compact, χ E ( Φ 2 ( Z ) ) = 0 . Therefore,
χ E ( R ( Z ) ) = χ E ( Φ 1 ( Z ) ) + χ E ( Φ 2 ( Z ) = χ E ( Φ 1 ( Z ) ) μ E ( Φ 1 ( Z ) ) < χ E ( Z ) .
This means that R is χ E condensing. By Proposition 3.5.1 in [38], the fixed point set of Φ 1 + Φ 2 is not empty. The second part follows from Proposition 3.5.1 in [38].    □

3. The Compactness of Σ ψ F [ r , b ]

In this section, we show that the set of mild solutions for Problem 1 is nonempty and compact.
For any x H with x ( 0 ) = ψ ( 0 ) , let x ¯ H be defined by
x ¯ ( η ) : = ψ ( η ) , η [ r , 0 ] , x ( η ) , η ( 0 , b ] .
Lemma 4.
For any x ¯ H , the function η ϰ ( η ) x ¯ is continuous from J to Θ.
Proof. 
Assume η , τ J , η τ . Then,
| | ϰ ( η ) x ¯ ϰ ( τ ) x ¯ | | Θ = r 0 | | x ¯ ( η + θ ) x ¯ ( τ + θ ) | | d θ .
Because x ¯ is continuous on [ r , b ] except for a finite number of points, it follows that lim η τ | | x ¯ ( η + θ ) x ¯ ( τ + θ ) | | = 0 , a.e. Since x ¯ H , l i m η τ r 0 | | x ¯ ( η + θ ) x ¯ ( τ + θ ) | | d θ = 0 , and the proof is completed.     □
Theorem 1.
Assume that ( H A ) and ( H F ) are held and that { Υ ( η ) : η 0 } is equicontinuous. Assume also that the following conditions are satisfied.
( H h ) The function h : J × Θ E is continuous and there exists a γ ( 0 , 1 ) satisfying h ( η , u ) D ( A γ ) , ( η , u ) J × Θ and
(i)
For any η J , A γ h ( η , . ) is strongly measurable.
(ii)
There are d 1 > 0 and d 2 > 0 with
d 1 | | A γ | | + d 1 b α γ C 1 γ Γ ( 1 + γ ) γ Γ ( 1 + α γ ) < 1 2 r ,
| | A γ h ( η , u ) | | d 2 ( 1 + | | u | | Θ ) , ( η , u ) J × Θ ,
and
| | A γ h ( η , u 1 ) A γ h ( η , u 2 ) | | d 1 | | u 1 u 2 | | Θ , η J .
Then, Σ ψ F [ r , b ] is not empty and a compact subset of H provided that
| | A γ | | d 2 r + d 2 C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ r + M Γ ( α ) Δ φ L ( J , , R + ) P r + σ M < 1 ,
and
4 Δ M Γ ( α ) | | β | | L P ( J , R + ) + 2 M i = 1 i = m ς i < 1 2 ,
where σ = i = 1 i = m σ i and Δ = ( P 1 α P 1 ) P 1 P b α 1 P .
Proof. 
A multioperator Φ : H P ( H ) is defined as the following: let x H , hence, as a consequence of ( H F 1 ) , the multifunction η F ( η , ϰ ( η ) x ¯ ) admits a measurable selection which, by ( H F 2 ) , belongs to S F ( . , ϰ ( . ) x ¯ ) 1 , and, therefore, y Φ ( x ) can be defined by
y ( η ) = 0 , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
where f S F ( . , ϰ ( . ) x ¯ ) 1 and x ¯ is defined by (8).
We show that a point x is a fixed point for Φ if and only if x ¯ Σ ψ F [ r , b ] . Assume x is a fixed point to Φ . Hence,
x ( η ) = 0 , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J .
Therefore,
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
which means that x ¯ satisfies (3), and, thus, it is a mild solution for problem (1). In a similar way, it can be seen that if x ¯ satisfies (3), then x is a fixed point for Φ . Let Φ 1 :   H H and Φ 2 : Φ 2 P ( H ) be such that
Φ 1 ( x ) ( η ) = 0 , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ , η J ,
and a function y Φ 2 ( x ) if and only if
y ( η ) = 0 , η [ r , 0 ] , + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
where f S F ( . , ϰ ( . ) x ¯ ) 1 . Notice that Φ = Φ 1 + Φ 2 . Let ξ = sup θ [ r , 0 ] | | ψ ( θ ) | | ,
ω = M [ ξ + | | A γ | | d 2 ( 1 + r ξ ) ] + ( 1 + r ξ ) [ | | A γ | | d 2 + d 2 C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ + M Γ ( α ) Δ φ L ( J , , R + ) P ]
and υ be a positive real number satisfying
υ > ω 1 [ | | A γ | | d 2 r + d 2 C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ r + M Γ ( α ) Δ φ L ( J , , R + ) P r + σ M ] .
Put B υ = { u H : | | u | | H ν } . Due to (12), υ is well defined. The rest of the proof is divided in the following steps:
Step 1. This step shows that Φ ( B ν ) B ν . Let x B υ and y Φ ( x ) . There exists f S F ( . , ϰ ( . ) x ) 1 where
y ( η ) = 0 , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J .
Let η J . For every x H , we get
| | ϰ ( η ) x ¯ | | Θ = r 0 | | x ¯ ( η + θ ) | | d θ r ( ξ + υ ) ,
which implies that ( H F 2 ) , | | f ( τ ) | | φ ( τ ) ( 1 + | | ϰ ( η ) x ¯ | | Θ ) r ( ξ + υ ) ; a . e . τ J . So, by (ii) of Lemma 1, and the Holder inequality, it follows that
| | 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ | | M Γ ( α ) ( 1 + r ( ξ + υ ) ) 0 η ( η τ ) α 1 φ ( τ ) d τ M Γ ( α ) Δ φ L ( J , , R + ) P ( 1 + r ( ξ + υ ) ) .
Then, from (6), (7), (10) and ( H I ) , one has, for η J ,
| | y ( η ) | | M [ ξ + | | A γ A γ h ( 0 , ψ ) | | ] + | | A γ A γ h ( η , ϰ ( η ) x ¯ ) | | + 0 η ( η τ ) α 1 | | A 1 γ K 2 ( η τ ) A γ h ( τ , ϰ ( τ ) x ¯ ) | | d τ + M Γ ( α ) Δ φ L ( J , , R + ) P ( 1 + r ( ξ + υ ) ) + M υ σ M [ ξ + | | A γ | | d 2 ( 1 + r ξ ) ] + | | A γ | | d 2 ( 1 + | | ϰ ( η ) x ¯ | | Θ ) + d 2 ( 1 + r ( ξ + υ ) ) α C 1 γ Γ ( 2 ( 1 γ ) Γ ( 1 + α ( 1 ( 1 γ ) ) 0 η ( η τ ) α 1 ( η τ ) α ( 1 γ ) d τ + M Γ ( α ) ( 1 + r ( ξ + υ ) ) Δ φ L ( J , , R + ) P + M υ σ M [ ξ + | | A γ | | d 2 ( 1 + r ξ ) ] + | | A γ | | d 2 ( 1 + r ( ξ + υ ) ) + d 2 ( 1 + r ( ξ + υ ) ) C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ + M Γ ( α ) ( 1 + r ( ξ + υ ) ) Δ φ L ( J , , R + ) P + M υ σ .
This equation with (12) leads to
| | y | | H M [ ξ + | | A γ | | d 2 ( 1 + r ξ ) ] + ( 1 + r ξ ) [ | | A γ | | d 2 + d 2 C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ + M Γ ( α ) Δ φ L ( J , , R + ) P ] + υ [ | | A γ | | d 2 r + d 2 C 1 γ Γ ( 1 + γ ) b α γ Γ ( 1 + α γ ) γ r + M Γ ( α ) Δ φ L ( J , , R + ) P r + σ M ] < υ .
Then, Φ ( B υ ) B υ .
Step 2. Φ 1 is a contraction with a contraction constant k < 1 2 .
Let u , v B υ and η J . Then, | | ϰ ( η ) u ¯ ϰ ( η ) v ¯ | | Θ = r 0 | | u ¯ ( η + θ ) v ¯ ( η + θ ) | | d θ r | | u v | | H . From (6), (7) and (11), for every u , v B υ and any η J , we have that
| | Φ 1 ( u ) ( η ) Φ 1 ( v ) ( η ) | | | | h ( η , ϰ ( η ) u ¯ ) h ( η , ϰ ( η ) v ¯ ) | | + | | 0 η ( η τ ) α 1 A K 2 ( η τ ) [ h ( τ , ϰ ( τ ) u ¯ ) h ( τ , ϰ ( τ ) v ¯ ) ] d τ | | A γ A γ [ h ( η , ϰ ( η ) u ¯ ) h ( η , ϰ ( η ) v ¯ ) ] | | + | | 0 η ( η τ ) α 1 A 1 γ K 2 ( η τ ) A γ [ h ( τ , ϰ ( τ ) u ¯ ) h ( τ , ϰ ( τ ) v ¯ ) ] d τ | | A γ | | | | A γ h ( η , ϰ ( η ) u ¯ ) A γ h ( η , ϰ ( η ) v ) | | + α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) 0 η ( η τ ) α γ 1 | | A γ h ( τ , ϰ ( τ ) u ¯ ) A γ h ( τ , ϰ ( τ ) v ¯ ) | | d τ d 1 | | A γ | | | | ϰ ( η ) u ¯ ϰ ( η ) v ¯ | | Θ + d 1 α C 1 γ Γ ( 2 γ ) Γ ( 1 + α γ ) sup τ [ 0 , η ] | | ϰ ( τ ) u ¯ ϰ ( τ ) v ¯ | | Θ b α γ α γ | | u v | | H [ d 1 | | A γ | | + d 1 b α γ C 1 γ Γ ( 1 + γ ) γ Γ ( 1 + α γ ) ] r ,
which yields with (9) that Φ 1 is a contraction with a contraction constant k < 1 2 .
Step 3. Φ 2 has a closed graph and Φ 2 ( x ) ; x B υ is compact.
Assume ( x n ) n 1 and ( y n ) n 1 are sequences in B υ where x n x , y n y and y n Φ 2 ( x n ) ; n 1 . Then,
y n ( η ) = 0 , η [ r , 0 ] , + 0 η ( η τ ) α 1 K 2 ( η τ ) f n ( τ ) d τ + 0 < η k < η K 1 ( η η k ) I i ( x n ( η k ) ) , η J ,
where f n τ F ( . , ϰ ( . ) x ¯ n ) 1 . Using ( H F 2 ) , it yields that
| | f n ( η ) | | φ ( η ) ( 1 + r ( υ + ξ ) ) , a . e . η J .
So, ( f n ) n 1 is bounded in L P ( J , E ) and, hence, there exists a subsequence of { f n } n = 1 . We denote them by ( f n ) n 1 , where f n f L P ( J , E ) . From Mazur’s Lemma, there exists a sequence of convex combination, { z n } n = 1 of { f n } n = 1 that converges almost everywhere to f . Note that by ( H F 2 ) , again, for any η J , τ ( 0 , η ] and any n 1 ,
| | ( η τ ) α 1 f n ( τ ) | | | η τ ) | α 1 φ ( τ ) ( 1 + r ( υ + ξ ) ) L P ( ( 0 , η ] , R + ) .
Set
y ˜ n ( η ) = 0 , η [ r , 0 ] , + 0 η ( η τ ) α 1 K 2 ( η τ ) z n ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x n ( η i ) ) , η J .
Note that by (18), y ˜ n ( η ) y ( η ) , η J . Moreover, since ϰ ( η ) x ¯ n ϰ ( η ) x ¯ ; η J , F ( η , . ) ; a . e . η J is upper semicontinuous, it yields f ( η ) F ( η , ϰ ( η ) x ) , a . e . Therefore, from the continuity of K 2 ( η τ ) ; τ [ 0 , η ] , I i ( i = 1 , 2 , ) , and by taking the limit of (19) as n , one gets y Φ 2 ( x ) .
To prove that the values of Φ 2 are compact, assume x H and y n Φ 2 ( x ) , n 1 . Using similar arguments to the above, we get that { y n : n 1 } has a convergent subsequence ( y ˜ ) n 1 . So, Φ 2 ( x ) is relatively compact. Since the graph of Φ 2 is closed its values are closed and, hence, Φ 2 ( x ) is relatively compact in H .
Step 4. We claim that the subsets Z J i ¯ ( i = 0 , 1 , , m ) are equicontinuous, where
Z J i ¯ = { y * C ( J i ¯ , E ) : y * ( η ) = y ( η ) , η ( η i , η i + 1 ] , y * ( η i ) = y ( η i + ) , y Φ 2 ( x ) , x B v } .
Assume y * Z J i ¯ . Then, there exists x B υ and f S F ( . , ϰ ( . ) x ¯ ) 1 , where, for η J i ,
y * ( η ) = 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η k < η K 1 ( η η k ) I k ( x ¯ ( η k ) ) ,
and y * ( η i ) = y ( η i + ) .
Case 1. Let η 1 , η 2 ( η 1 < η 2 ) be two points in ( η i , η i + 1 ] .Then,
y * ( η 2 ) y * ( η 1 ) | | 0 η 2 ( η 2 τ ) α 1 K 2 ( η 2 τ ) f ( τ ) d τ 0 η 1 ( η 1 τ ) α 1 K 2 ( η 1 τ ) f ( τ ) | | + | | 0 < η k < η 2 K 1 ( η 2 η k ) I k ( x ¯ ( η k ) ) 0 < η i < η 1 K 1 ( η 1 η k ) I k ( x ¯ ( η k ) ) | | | | η 1 η 2 ( η 2 τ ) α 1 K 2 ( η 2 τ ) f ( τ ) d τ | | + 0 η 1 | ( η 2 τ ) α 1 ( η 1 τ ) α 1 | | | K 2 ( η 2 τ ) f ( τ ) | | d τ + | | 0 η 1 ( η 1 τ ) α 1 | | K 2 ( η 2 τ ) f ( τ ) K 2 ( η 1 τ ) f ( τ ) | | d τ . + 0 < η k < η 2 | | K 1 ( η 2 η k ) K 1 ( η 1 η k ) | | | | I i ( x ¯ ( η i ) ) | | = i = 1 i = 4 I i .
The hypothesis ( H F 2 ) implies | | f ( η ) | | φ ( η ) ( 1 + r ( υ + ξ ) ) , a . e . η J , and, hence, by Lemma 1, we get
lim η 2 η 1 I 1 = lim η 2 η 1 | | η 1 η 2 ( η 2 τ ) α 1 K 2 ( η 2 τ ) f ( τ ) d τ | | M ( 1 + r ( υ + ξ ) ) Γ ( α ) lim η 2 η 1 η 1 η 2 ( η 2 τ ) α 1 φ ( τ ) d τ = M ( 1 + r ( υ + ξ ) ) Γ ( α ) | | φ | | L P ( [ J , R + ) lim η 2 η 1 ( η 1 η 2 ( η 2 τ ) P ( α 1 ) P 1 d τ ) P 1 P = 0 .
For I 2 , we have
lim η 2 η 1 I 2 lim η 2 η 1 0 η 1 | ( η 2 τ ) α 1 ( η 1 τ ) α 1 | | | K 2 ( η 2 τ ) f ( τ ) | | d τ = M ( 1 + r ( υ + ξ ) ) Γ ( α ) lim η 2 η 1 0 η 1 | ( η 2 τ ) α 1 ( η 1 τ ) α 1 | φ ( τ ) d τ .
Note that ω ¯ = α 1 1 1 P ( 1 , 0 ) , then, for τ < η 1 , we have ( η 1 τ ) ω ¯ ( η 2 τ ) ω ¯ . As an application of Lemma 3 in [8] and considering P 1 P ( 0 , 1 ) , we get
| ( η 1 τ ) ω ¯ 1 1 P ( η 2 τ ) ω ¯ P 1 P | ( η 1 τ ) ω ¯ ( η τ ) ω ¯ P 1 P .
Then,
| ( η 1 τ ) α 1 ( η 2 τ ) α 1 | ( η 1 τ ) ω ¯ ( η 2 τ ) ω ¯ P 1 P .
This leads to
| ( η τ ) α 1 ( η + λ τ ) α 1 | P 1 P ( η τ ) ω ¯ ( η + λ τ ) ω ¯ .
Therefore,
lim η 2 η 1 I 2 M ( 1 + r ( υ + ξ ) ) Γ ( α ) lim η 2 η 1 0 η 1 | ( η 2 τ ) α 1 ( η 1 τ ) α 1 | φ ( τ ) d τ M ( 1 + r ( υ + ξ ) ) ) Γ ( α ) lim η 2 η 1 0 η 1 | ( η 2 τ ) α 1 ( η 1 τ ) α 1 | P P 1 d τ P 1 P φ L ( J , R + ) P M ( 1 + r ( υ + ξ ) ) ) Γ ( α ) lim η 2 η 1 0 η 1 [ ( η 2 τ ) ω ¯ ( η 1 τ ) ω ¯ ] d τ P 1 P φ L ( J , R + ) P M ( 1 + r ( υ + ξ ) ) Γ ( α ) lim η 2 η 1 1 ω + 1 [ η 2 ω ¯ + 1 ( η 2 η 1 ) ω ¯ + 1 η 1 ω ¯ + 1 P 1 P φ L ( J , R + ) P = 0 .
For I 3 ,
lim η 2 η 1 I 3 lim η 2 η 1 | | 0 η 1 ( η 1 τ ) α 1 | | K 2 ( η 2 τ ) f ( τ ) K 2 ( η 1 τ ) f ( τ ) | | d τ .
Observe that for every τ [ 0 , η ] ,
( η 1 τ ) α 1 | | K α ( η 2 τ ) f ( τ ) K α ( η 1 τ ) f ( τ ) | | 2 M ( ν + 1 ) Γ ( α ) ( η 1 τ ) α 1 φ ( τ ) L P ( J , R + ) .
Moreover, since { η ( η ) : η > 0 } is equicontinuous, and, using the Lebesgue-dominated convergence theorem, one gets
lim η 2 η 1 I 3 M ( 1 + r ( υ + ξ ) ) Γ ( α ) lim η 2 η 1 0 η 1 ( η 1 τ ) α 1 | | K 2 ( η 2 τ ) K 2 ( η 1 τ ) | | φ ( τ ) d τ = M ( 1 + r ( υ + ξ ) ) Γ ( α ) 0 η 1 0 θ ( η 1 τ ) α 1 ζ α ( θ ) × [ lim η 2 η 1 ( Υ ( ( η 2 τ ) α θ ) Υ ( η 1 τ ) α θ ) ) ] d θ φ ( τ ) d τ = 0 .
For I 4 ,
lim η 2 η 1 I 4 σ υ lim η 2 η 1 0 < η k < η 2 | | K 1 ( η 2 η k ) K 1 ( η 1 η k ) | | = 0 .
Case 2. η = η i , i = 1 , , m . Assume δ > 0 , η i + δ ( η i , η i + 1 ] and λ > 0 where η i < λ < η i + δ η i + 1 . Hence, as above, it can be shown that
y * ( η i + δ ) y * ( η i ) = lim λ η i + y ( η i + δ ) y ( λ ) = 0 .
Then, Z J i ¯ ( i = 0 , 1 , , m ) are equicontinuous.
Step 5. Set B 1 = c o n v ¯ Φ ( B υ ) and B n = c o n v ¯ Φ ( B n 1 ) , n 2 . Then, the sequence ( B n ) , n 1 is a decreasing sequence of not empty, closed and bounded subsets of H . So, the set B = n 1 B n is bounded, closed, convex and Φ ( B ) B . Next, we show that B is compact. According to the generalized Cantor’s intersection property, we only need to prove that
lim n χ H ( B n ) = 0 ,
where χ H is the Hausdorff measure of noncompactness on H . Assume n N and n 1 are fixed. From the fact that Φ 1 is a contraction with a contraction constant k < 1 2 , it follows that
χ H Φ ( B n 1 ) χ H Φ 1 ( B n 1 ) + χ H Φ 2 ( B n 1 ) 1 2 χ H ( B n 1 ) + χ H Φ 2 ( B n 1 ) .
Let ε > 0 . Using Lemma 5 in [39], there is a ( y k ) k 1 in Φ 2 ( B n 1 ) with
χ H Φ 2 ( B n 1 ) 2 χ H { y k : k 1 } + ε .
From the fact that the subsets Z J i ¯ ( i = 0 , 1 , , m ) are equicontinuous, one obtains
χ H Φ 2 ( B n 1 ) 2 χ H { y k : k 1 } + ε 2 sup η [ 0 , b ] χ E { y k ( η ) : k 1 } + ε .
Now, let x k B n 1 and y k Φ 2 ( x k ) , k 1 .Then, for every k 1 , there is a f k τ F ( . , ϰ ( η ) x ¯ k ) 1 such that, for any η J ,
y k ( η ) = 0 , η [ r , 0 ] , 0 η ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ k ( η i ) ) , η J .
Note that the assumption ( H I ) implies that for η J ,
χ E { 0 < η i < η K 1 ( η η i ) I i ( x ¯ k ( η i ) ) : k 1 } M i = 1 i = m ς i χ E { x ¯ k ( η i ) ) : k 1 } M i = 1 i = m ς i χ E { x k ( η i ) ) : k 1 } M χ H ( B n 1 ) i = 1 i = m ς i .
Moreover, from (4), we have that for a . e . τ J ,
χ E { f k ( τ ) : k 1 } χ { F ( τ , ϰ ( τ ) x ¯ k ) : k 1 } β ( τ ) sup θ [ r , 0 ] χ { x ¯ k ( τ + θ ) : k 1 } β ( τ ) sup δ [ r , τ ] χ { x ¯ k ( δ ) : k 1 } β ( τ ) sup δ [ 0 , τ ] χ { x k ( δ ) : k 1 } β ( τ ) χ H ( B n 1 ) = γ ( η ) .
Again, by ( H F 2 ) * , for every k 1 , and for almost η J , | | f k ( η ) | | φ ( η ) ( 1 + r ( υ + ξ ) ) and, hence, { f k : k 1 } is integrably bounded. As a consequence of Lemma 4 in [40], there is a compact set K ϵ E , a measurable set J ϵ J having a measure less than ϵ and { z k ϵ } L P ( J , E ) such that for every τ J , { z k ϵ ( τ ) : k 1 } K ϵ and
| | f k ( τ ) z k ϵ ( τ ) | | < 2 γ ( τ ) + ϵ for all k 1 and all τ J J ϵ .
Then, by (24) and (25) and Minkowski’s inequality, it follows that for k 1 ,
| | J J ϵ ( η τ ) α 1 K 2 ( η τ ) ( f k ( τ ) z k ϵ ( τ ) ) d τ | | M Γ ( α ) | | f k z k ϵ | | L P ( J 0 J ϵ , R + ) ( J J ϵ ( η τ ) ( α 1 ) P P 1 d τ ) P 1 P Δ M Γ ( α ) | | f k z k ϵ | | L P ( J 0 J ϵ , R + ) Δ M Γ ( α ) ( 2 | | γ | | L P ( J J ϵ , R + ) + ϵ b 1 P ) = Δ M Γ ( α ) ( 2 | | β | | L P ( J , R + ) χ H ( B n 1 ) + ϵ b 1 P ) ,
and
| | J ϵ ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ | | M Γ ( α ) ( 1 + r ( υ + ξ ) ) J ϵ ( η τ ) α 1 φ ( τ ) d τ M Γ ( α ) ( 1 + r ( υ + ξ ) | | φ | | L P ( J ϵ , R + ) ( J ϵ ( η τ ) ( α 1 ) P P 1 d τ ) P 1 P .
Moreover, from the fact that { z k ϵ ( τ ) : k 1 } ; τ J is contained in a compact subset, we get
χ { J J ϵ ( η τ ) α 1 K 2 ( η τ ) z k ϵ ( τ ) d τ : k 1 } = 0 .
Combining this relation with (26) and (27),it follows that
χ { 0 η ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ : k 1 } Δ M Γ ( α ) ( 2 | | β | | L P ( J , R + ) χ H ( B n 1 ) + ϵ b 1 P ) + ( 1 + r ( υ + ξ ) M Γ ( α ) | | φ | | L P ( J ϵ , R + ) Δ ϵ ,
where Δ ϵ = ( J ϵ ( η τ ) ( α 1 ) P P 1 d τ ) P 1 P . Using the fact that ε is chosen arbitrary, relation (28) becomes
χ { 0 η ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ : k 1 } 2 Δ M Γ ( α ) | | β | | L P ( J , R + ) χ H ( B n 1 ) .
Using the above inequality and (21)–(23), in addition to the fact that ε is arbitrary, it follows that
χ H ( B n ) ( 4 Δ M Γ ( α ) | | β | | L P ( J , R + ) + 2 M i = 1 i = m ς i + 1 2 ) χ H ( B n 1 ) .
This leads to
χ H ( B n ) ( 4 Δ M Γ ( α ) | | β | | L P ( J , R + ) + M i = 1 i = m ς i + 1 2 ) n 1 χ H ( B 1 ) , n 1 .
The above inequality holds for any natural number n, and by (13) together with taking the limit as n , we get (20). Then, B is not empty and a compact subset of H . So, Φ : B P c k ( B ) is completely continuous. By applying Lemma 3, we conclude that the fixed points set of Φ is not an empty subset of H . Furthermore, by arguing as in Step 1, we can prove that the set of fixed points of Φ is bounded and, hence, by Lemma 3, it is compact in H . Therefore, the set Σ ψ F [ r , b ] is not empty and a compact subset of H.     □

4. The Structure Topological of Σ ψ F [ r , b ]

In the section we prove that Σ ψ F [ r , b ] is an R δ -set
Definition 3
([41]). A topological space X, which is homotopy equivalent to a point, is called contractible. In other words, there is a continuous map h : [ 0 , 1 ] × X X , h ( 0 , . x ) = x and h ( 1 , x ) = x 0 X .
Lemma 5
([41]). Let A X , where A is not empty and X is a complete metric space. Then, A is said to be R δ -set if and only if it is an intersection of a decreasing sequence { A n } of contractible sets and χ X ( A n ) 0 , as n .
Now, consider the multi-valued function F ˜ : J × Θ P c k ( E ) that is given by:
F ˜ ( η , u ) : = F ( η , u ) , | | u | | < υ , F ( η , υ u | | u | | ) , | | u | | υ ,
where υ is defined by (17). Since F ˜ = F on D υ , the set of solutions consisting of mild solutions for Problem (1) is equal to the set of solutions consisting of mild solutions for the problem:
c D 0 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] A x ( η ) + F ˜ ( η , ϰ ( η ) x ) , a . e . η [ 0 , b ] { η 1 , , η m } , I i ( x ( η i ) ) = x ( η i ) x ( η i + ) , i = 1 , , m , x ( η ) = ψ ( η ) , η [ r , 0 ] .
Obviously, F ˜ verifies ( H F 1 ) and, for η J , a . e . ,
| | F ˜ ( η , u ) | | φ ( η ) ( 1 + | | u | | ) φ ( η ) ( 1 + r ( ξ + υ ) ) = ζ ( η ) , | | u | | < υ , φ ( η ) ( 1 + | | υ u | | u | | | | ) = φ ( η ) ( 1 + r ( ξ + υ ) ) = ζ ( η ) , | | u | | υ .
Then, we can assume that F verifies the next condition:
( H F 2 ) * There exists a function ξ L P ( I , R + ) ( P > 1 α ) , where for every z Θ ,
F ( η , z ) ζ ( η ) , a . e . η J .
We recall the next Lemma. For its proof, we refer the reader to the second step in the proof of Theorem 3.5 in [13].
Lemma 6.
Assume that ( H F 1 ) and ( H F 2 ) * are satisfied. Then, there exists a sequence of multifunctions { F i } i = 1 with F i : J × Θ P c k ( E ) such that:
 (i) 
Every F i ( η , . ) is continuous for almost η J .
 (ii) 
F ( η , x ) . F i + 1 ( η , x ) F i ( η , ϰ ( η ) x ) c o ¯ F ( η , { y Θ : | | y x | | 3 1 i } ) , i 1 , for each η J and x Θ .
 (iii) 
F ( η , z ) = i 1 F i ( η , z ) .
 (iv) 
For all i 1 , there is a selection g i : J × Θ E of F i such that g i ( . , x ) is measurable for each x Θ and for g i ( η , . ) is locally Lipschitz.
Remark 2.
(Ref. [19]) The property (iv) in Lemma 6 implies that, for almost η J , g i ( η , . ) , i 1 is continuous.
Assume Σ ψ F i [ r , b ] is the mild solutions set of the following fractional neutral impulsive semilinear differential inclusions with delay:
c D 0 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] A x ( η ) + F i ( η , ϰ ( η ) x ) , a . e . η [ 0 , b ] { η 1 , , η m } , I i ( x ( η i ) ) = x ( η i ) x ( η i + ) , i = 1 , , m , x ( η ) = ψ ( η ) , η [ r , 0 ] .
Theorem 2.
Assume that the conditions in Theorem 1 after substituting ( H F 2 ) by ( H F 2 ) * are held. Then, there exists N 0 N such that, for i N 0 , the set Σ ψ F i [ r , b ] is compact and not empty in H .
Proof. 
Let i be a fixed natural number. We define a multioperator Φ i : H P ( H ) as the following: y Φ i ( x ) if and only if
y ( η ) = 0 , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
where f τ F i ( . , ϰ ( . ) x ¯ ) 1 . Due to Lemma 5, F i verifies ( F 1 ) , ( F 2 ) * . As a result of Theorem 1, Φ i is closed, Φ i ( B υ ) B υ and Φ i ( B υ ) is equicontinuous. Set B 1 , i = c o n v ¯ Φ i ( B υ ) and B n , i = c o n v ¯ Φ i ( B n 1 , i ) , n 2 . As in Theorem 1, the sequence ( B n , i ) , n 1 is a decreasing sequence of non-empty, closed and bounded subsets of H . We show that
lim n χ C ( [ r , b ] , E ) ( B n , i ) = 0 .
Let ε > 0 . Choose a natural number N 0 with 3 1 N 0 < ε 2 | | β | | L P ( J , R + ) and let i > N 0 be a fixed natural number. Using a similar argument as the one used in the proof of Theorem 1, one gets
χ H ( B n , i ) 2 sup η J χ E { y k ( η ) : k 1 } + ε 2 ,
where
y k ( η ) = 0 , η [ r , 0 ] 0 η ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
and f k τ F i ( . , ϰ ( η ) x k ) 1 . Next, due to Remark 4.2 in [7], it follows that for any bounded subset D Θ ,
χ E ( F i ( η , D ) ) β ( η ) [ sup θ [ r , η ] χ E { z ( θ ) : z D } + 3 1 i ] .
Then, it yields from (ii) in Lemma 5 and (31), for a . e . τ J ,
χ E ( { f k ( τ ) : k 1 } χ E { F i ( τ , ϰ ( τ ) x k ) : k 1 } β ( τ ) [ sup θ [ r , 0 ] χ E { x k ( τ + θ ) : k 1 } + 3 1 N 0 ] β ( τ ) [ sup δ [ r , τ ] χ E { x k ( δ ) : k 1 } + 3 1 N 0 ] β ( τ ) [ sup θ [ 0 , , τ ] χ E { x k ( δ ) : k 1 } + 3 1 N 0 ] β ( τ ) χ H ( B n 1 , i ) + β ( τ ) 3 1 N 0 = γ ¯ ( τ ) .
As in (28) but by using (32) instead of (24), we get
χ { 0 η ( η τ ) α 1 K 2 ( η τ ) f k ( τ ) d τ : k 1 } Δ M Γ ( α ) ( 2 | | β | | L P ( J , R + ) χ H ( B n 1 ) + ϵ b 1 P ) + ϵ 2 + M Γ ( α ) ( 1 + r υ + r ξ ) × | | φ | | L P ( J ϵ , R + ) ( J ϵ ( η τ ) P P 1 d τ ) P 1 P .
Similarly, as in the proof of Theorem 1, we confirm the validity of (30).Therefore, by the generalized Cantor’s intersection property, the set B i is not empty and compact in H . As in Theorem 1, the fixed points set of the multivalued function Φ i : B i P c k ( B i ) is not empty and a compact subset in H . Consequently, the set ψ F n [ r , b ] is not empty and a compact subset of H.     □
Theorem 3.
Under the conditions of Theorem 2, ψ F [ r , b ] = n = N 0 ψ F n [ r , b ] .
Proof. 
In view of (iii) in Lemma 8, it can be seen that ψ F [ r , b ] n = N 0 ψ F n [ r , b ] . Let x ¯ n = N 0 ψ F n [ r , b ] . Then, there is f n τ F n ( . , ϰ ( . ) x ¯ ) 1 , n N 0 such that
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f n ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J .
It follows from ( H F 2 ) * that
| | f n ( η ) | | ζ ( η ) , for a . e . η J .
This means that the sequence ( f n ) n 1 is weakly relatively compact in L P ( J , E ) , so we can assume f n f weakly, where f L P ( J , R + ) . As in the proof of Theorem 1, there is a sequence of convex combinations ( z n ) n 1 of ( f n ) n 1 that converges almost everywhere to f. Note that
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) z n ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J ,
and z n ( η ) F n ( η , ϰ ( η ) x ¯ ) , n 1 . It yields, from (ii) of Lemma 8, that for almost η J ,
z n ( η ) c o ¯ F ( η , { y Θ : | | y ϰ ( η ) x ¯ | | 3 1 n } ) , n 1 ,
which implies that f ( η ) F ( η , ϰ ( η ) x ¯ ) , for a . e . η J . Moreover, using the fact that K 2 ( η ) ( η > 0 ) is continuous, and taking the limit as n in (34), one gets
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J .
This means that x ¯ ψ F [ r , b ] .     □
To prove our main results, we need the next lemma.
Lemma 7
([19], Lemma 4.5). Assume that ( X , d ) and ( Y , ρ ) are two metric spaces.Then, if f : ( M , d ) ( Y , ρ ) is locally Lipschitz, then it is Lipschitz on all subsets of X that are compact.
Theorem 4.
Under the assumptions of Theorem 2 , the set ψ F [ r , b ] is an R δ -set in H provided that r d 1 | | A γ | | < 1 .
Proof. 
Using Lemma 4 and Theorems 1–3, we only need to prove that ψ F n [ r , b ] , where n N 0 is contractible. Assume that n N and n N 0 . Consider the following fractional neutral impulsive semilinear:
c D 0 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] = A x ( η ) + g n ( η , ϰ ( η ) x ) , a . e . η [ 0 , b ] { η 1 , , η m } , I i ( x ( η i ) ) = x ( η i ) x ( η i + ) , i = 1 , , m , x ( η ) = ψ ( η ) , η [ r , 0 ] .
Using Lemma 6 and Remark 3, g n ( . , u ) is measurable, and for η J , a . e . , g n ( η , . ) is continuous. Since the multi-valued F satisfies ( F 2 ) * and ( F 3 ) , then, following the arguments employed in the proof of Theorem 2, the fractional differential Equation (35) has a mild solution y ¯ ψ F n [ r , b ] satisfying the following integral equation:
y ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) y ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) y ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) y ¯ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( y ¯ ( η i ) ) , η J .
Next, we show that the solution is unique. Assume that x ¯ ψ F n [ r , b ] is another mild solution for (35). Then,
x ¯ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ¯ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ¯ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) x ¯ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ¯ ( η i ) ) , η J .
Let η [ 0 , η 1 ] be fixed. Due to (6), (7), (11) (36) and (37), it yields
| | y ¯ ( η ) x ¯ ( η ) | | | | h ( η , ϰ ( η ) y ¯ ) h ( η , ϰ ( η ) x ¯ ) | | + | | 0 η ( η τ ) α 1 A K 2 ( η τ ) ( h ( τ , ϰ ( τ ) y ¯ ) h ( τ , ϰ ( τ ) x ¯ ) ) d τ | | + | | 0 η ( η τ ) α 1 K 2 ( η τ ) ( g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) ) d τ | | | | A γ | | | | A γ h ( η , ϰ ( η ) y ¯ ) A γ h ( η , ϰ ( η ) x ¯ ) | | + 0 η ( η τ ) α 1 | | A 1 γ K 2 ( η τ ) | | | | A γ h ( τ , ϰ ( τ ) y ¯ ) A γ h ( τ , ϰ ( τ ) x ¯ ) ) | | d τ + M Γ ( α ) 0 η ( η τ ) α 1 | | g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) ) | | d τ . d 1 | | A γ | | | | ϰ ( η ) y ¯ ϰ ( η ) x ¯ | | Θ + d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) 0 η ( η τ ) α γ 1 | | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ d τ + M Γ ( α ) 0 η ( η τ ) α 1 | | g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) ) | | d τ .
Now, from Lemma 5, the function τ ϰ ( τ ) x ¯ is continuous from [ 0 , η 1 ] to Θ and, hence, the subset Z x ¯ = { ϰ ( τ ) x ¯ : τ [ 0 , η 1 ] } is compact in Θ . Similarly, the set Z y ¯ = { ϰ ( τ ) y ¯ : τ [ 0 , η 1 ] } is compact in Θ and, therefore, the set Z x ¯ , y ¯ = Z x ¯ Z y ¯ is compact in Θ , and consequently, [ 0 , η 1 ] × Z x ¯ , y ¯ is compact in [ 0 , η 1 ] × Θ . Thus, by (iv) in Lemma 6 and Lemma 7, there exists c η 1 > 0 , for which the estimate
| | g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) | | c η 1 | | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ ,
holds for τ J . Therefore, from (38), it yields
| | x ¯ ( η ) y ¯ ( η ) | | d 1 | | A γ | | | | ϰ ( η ) y ¯ ϰ ( η ) x ¯ | | Θ + d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) 0 η ( η τ ) α γ 1 | | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ d τ + M c η 1 Γ ( α ) 0 η ( η τ ) α 1 | | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ d τ .
Note that when τ [ 0 , η ] , we have
| | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ = r 0 | | y ¯ ( τ + θ ) x ¯ ( τ + θ ) | | d θ r sup δ [ 0 , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | .
It yields
| | x ¯ ( η ) y ¯ ( η ) | | d 1 | | A γ | | | | ϰ ( η ) y ¯ ϰ ( η ) x ¯ | | Θ + r d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) 0 η ( η τ ) α γ 1 sup δ [ a , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ + r M c η 1 Γ ( α ) 0 η ( η τ ) α 1 sup δ [ 0 , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ .
Since x ¯ and y ¯ are continuous on [ 0 , η ] , there is ρ [ 0 , η ] with | | x ¯ ( ρ ) y ¯ ( ρ ) | | = sup δ [ 0 , η ] | | x ¯ ( δ ) y ¯ ( δ ) | | . Then,
sup δ [ 0 , η ] | | x ¯ ( δ ) y ¯ ( δ ) | | = | | x ¯ ( ρ ) y ¯ ( ρ ) | | d 1 | | A γ | | | | ϰ ( ρ ) y ¯ ϰ ( ρ ) x ¯ | | Θ + r d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) 0 ρ ( ρ τ ) α γ 1 sup δ [ 0 , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ + r M c η 1 Γ ( α ) 0 ρ ( ρ τ ) α 1 sup δ [ 0 , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ r d 1 | | A γ | | sup δ [ 0 , η ] | | x ¯ ( δ ) y ¯ ( δ ) | | + r d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) a ρ ( ρ τ ) α γ 1 sup δ [ a , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ + r M c η 1 Γ ( α ) a ρ ( ρ τ ) α 1 sup δ [ a , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ .
Since r d 1 | | A γ | | < 1 , the last relations lead to
sup δ [ 0 , η ] | | x ¯ ( δ ) y ¯ ( δ ) | | 1 1 r d 1 | | A γ | | [ 0 ρ ( ρ τ ) α γ 1 d 1 | | A γ | | r α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) + 0 ρ ( ρ τ ) α 1 r M c V Γ ( α ) ] sup δ [ 0 , τ ] | | y ¯ ( δ ) x ¯ ( δ ) | | d τ .
Using the generalized Gronwall inequality [42], one has sup δ [ 0 , η ] | | x ¯ ( δ ) y ¯ ( δ ) | | = 0 . Since η [ 0 , η 1 ] is arbitrary, we conclude that x ¯ = y ¯ on [ 0 , η 1 ] .
Next, let η [ η 1 , η 2 ] be fixed. Note that x ( η 1 ) = y ( η 1 ) . Then,
| | y ¯ ( η ) x ¯ ( η ) | | | | h ( η , ϰ ( η ) y ¯ ) h ( η , ϰ ( η ) x ¯ ) | | Θ + | | η 1 η ( η τ ) α 1 A K 2 ( η τ ) ( h ( τ , ϰ ( τ ) y ¯ ) h ( τ , ϰ ( τ ) x ¯ ) ) d τ | | + | | η 1 η ( η τ ) α 1 K 2 ( η τ ) ( g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) ) d τ | | d 1 | | A γ | | | | ϰ ( η ) y ¯ ϰ ( η ) x ¯ | | Θ + d 1 | | A γ | | α C 1 γ Γ ( 1 + γ ) Γ ( 1 + α γ ) ) a η ( η τ ) α γ 1 | | ϰ ( τ ) y ¯ ϰ ( τ ) x ¯ | | Θ d τ + M Γ ( α ) η 1 η ( η τ ) α 1 | | g n ( τ , ϰ ( τ ) y ¯ ) g n ( τ , ϰ ( τ ) x ¯ ) ) | | d τ .
By repeating the arguments employed above, we get x ¯ = y ¯ on [ η 1 , η 2 ] . Continuing with the same processes, we arrive to x ¯ = y ¯ on J .
Next, we prove that ψ F n [ r , b ] is homotopically equivalent to y ¯ . To this end, we define a continuous function Z n : [ 0 , 1 ] × ψ F n [ r , b ] ψ F n [ r , b ] , where Z n ( 0 , x ˜ ) = x ˜ and ( 1 , x ˜ ) = y . Assume ( λ , x ˜ ) [ 0 , 1 ] × ψ F n [ r , b ] is fixed. Then, there exists a f τ F n ( . , ϰ ( . ) x ˜ ) 1 such that
x ˜ ( η ) = ψ ( η ) , η [ r , 0 ] , K 1 ( η ) [ ψ ( 0 ) h ( 0 , ψ ) ] + h ( η , ϰ ( η ) x ˜ ) + 0 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x ˜ ) d τ + 0 η ( η τ ) α 1 K 2 ( η τ ) f ( τ ) d τ + 0 < η i < η K 1 ( η η i ) I i ( x ˜ ( η i ) ) , η J .
Consider the partition { 0 , 1 m + 1 , 2 m + 1 , , m + 1 m + 1 } for J = [ 0 , 1 ] . We consider the following cases:
(i) λ [ 0 , 1 m + 1 ] . Put a λ 1 = η m + 1 λ ( m + 1 ) ( η m + 1 η m ) . The following fractional neutral differential inclusion is a result of the above discussion:
c D a λ 1 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] = A x ( η ) + g n ( η , ϰ ( η ) x ) , a . e . η [ a λ , 1 , b ] , x ( η ) = x ˜ ( η ) , η [ r , a λ 1 ] ,
has a unique mild solution x λ 1 ψ F n [ r , b ] satisfying the next integral equation:
x λ 1 ( η ) = x ˜ ( η ) , η [ r , a λ 1 ] , K 1 ( η a λ 1 ) [ x ˜ ( a λ 1 ) h ( a λ 1 , ϰ ( a λ 1 ) x ˜ ( a λ 1 ) ] + h ( η , ϰ ( η ) x λ 1 ( η ) ) + a λ 1 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x λ 1 ( η ) ) d τ + a λ 1 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) x λ 1 ) d τ , η [ a λ , 1 , b ] .
Note that x 0 1 ( η ) = x ˜ ( η ) ; η [ r , b ] .
(ii) λ ( 1 m + 1 , 2 m + 1 ] . Put a λ 2 = η m ( m + 1 ) ( λ 1 m + 1 ) ( η m η m 1 ) . Again, the following fractional neutral differential inclusion:
c D a λ 2 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] = A x ( η ) + g n ( η , ϰ ( η ) x ) , a . e . η [ a λ 2 , b ] { η m } , I m ( x ( η m ) ) = x ( η m ) x ( η m + ) , x ( η ) = x ˜ ( η ) , η [ r , a λ 2 ] ,
has a unique mild solution x λ 2 ψ F n [ r , b ] and
x λ 2 ( η ) = x ˜ ( η ) , η [ r , a λ 2 ] , K 1 ( η a λ 2 ) [ x ˜ ( a λ 2 ) h ( a λ , 1 , ϰ ( a λ 2 ) x ˜ ( a λ 2 ) ] + h ( η , ϰ ( η ) x λ 2 ( η ) ) + a λ 2 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x λ 2 ( η ) ) d τ + a λ 2 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) x λ 2 ) d τ + a λ 2 < η i < η K 1 ( η η i ) I i ( x λ 2 ( η i ) ) , η [ a λ 2 , b ] .
We continue up to m + 1 step. That is λ ( m m + 1 , 1 ] and put a λ m + 1 = η 1 ( m + 1 ) ( λ m m + 1 ) η 1 . Let x λ m + 1 ψ F n [ r , b ] be the unique mild solution for the impulsive fractional neutral differential inclusion:
c D a λ m + 1 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] = A x ( η ) + g n ( η , ϰ ( η ) x ) , a . e . η [ a λ m + 1 , b ] { η 1 , η 2 , η m } , I i ( x ( η i ) ) = x ( η i ) x ( η i + ) , i = 1 , 2 , , m x ( η ) = x ˜ ( η ) , η [ r , a λ m + 1 ] .
Then,
x λ m + 1 ( η ) = x ˜ ( η ) , η [ r , a λ m + 1 ] , K 1 ( η ) [ x ˜ ( a λ m + 1 ) h ( a λ , 1 , ϰ ( a λ m + 1 ) x ˜ ( a λ m + 1 ) ] + h ( η , ϰ ( η ) x λ m + 1 ) + a λ m + 1 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) x λ m + 1 ( η ) ) d τ + a λ m + 1 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) x λ m + 1 ) d τ + a λ m + 1 < η i < η K 1 ( η η i ) I i ( x λ m + 1 ( η i ) ) , η [ a λ m + 1 , b ] .
Note that a 1 m + 1 = 0 and x 1 m + 1 = y . Now, we define Z n at ( λ , x ˜ ) as
Z n ( λ , x ˜ ) = x λ 1 , if λ [ 0 , 1 m + 1 ] , x λ 2 , if λ ( 1 m + 1 , 2 m + 1 ] , . . . x λ m + 1 , if λ ( m m + 1 , 1 ] .
Therefore, Z n ( 0 , x ˜ ) = x λ 1 = x ˜ and Z n ( 1 , x ˜ ) = x 1 m + 1 = y .
It remains to clarify the continuity of Z n . Let ( λ , u ) , ( ϱ , v ) [ 0 , 1 ] × ψ F n [ r , b ] . Let λ = ϱ = 0 . Then, by (42), lim u v Z n ( λ , u ) = lim u v u = v = Z n ( ϱ , v ) . Let λ , ϱ ( 0 , 1 m + 1 ] . So, Z n ( λ , u ) = u ¯ λ 1 and Z n ( λ , v ) = v ¯ μ 1 , where
u ¯ λ 1 ( η ) = x ˜ ( η ) , η [ r , a λ 1 ] , K 1 ( η a λ 1 ) [ x ˜ ( a λ 1 ) h ( a λ 1 , ϰ ( a λ 1 ) x ˜ ( a λ 1 ) ] + h ( η , ϰ ( η ) u ¯ λ 1 ( η ) ) + a λ 1 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) u ¯ λ 1 ( η ) ) d τ + a λ 1 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) u ¯ λ 1 ) d τ , η [ a λ , 1 , b ] ,
and
v ¯ μ 1 ( η ) = x ˜ ( η ) , η [ r , a μ 1 ] , K 1 ( η a λ 1 ) [ x ˜ ( a λ 1 ) h ( a μ 1 , ϰ ( a μ 1 ) x ˜ ( a μ 1 ) ] + h ( η , ϰ ( η ) v ¯ μ 1 ( η ) ) + a μ 1 η ( η τ ) α 1 A K 2 ( η τ ) h ( τ , ϰ ( τ ) v ¯ μ 1 ( η ) ) d τ + a μ 1 η ( η τ ) α 1 K 2 ( η τ ) g n ( η , ϰ ( η ) v ¯ μ 1 ) d τ , η [ a μ 1 , b ] ,
a λ 1 = b μ ( m + 1 ) ( b τ m ) and a μ 1 = b μ ( m + 1 ) ( b τ m ) . Obviously, lim λ μ a λ 1 = a μ 1 and, hence, by (43) and (44), and by arguing as above, we get
lim λ μ u v Z n ( λ , u ) = Z n ( μ , v ) ,
which implies the continuity of Z n ( . , . ) , when λ [ 0 , 1 m + 1 ] . Similarly, we can show the continuity of Z n and consequently, ψ F n [ r , b ] is contractible. This completes the proof.     □

5. Example

Example 1.
Assume that E = L 2 ( [ 0 , π ] , R ) , J = [ 0 , 1 ] , r = 1 2 , m = 1 , η 0 = 0 and η 1 = 1 2 , η 2 = 1 . For any x : J E = L 2 ( [ 0 , π ] , R ) , we denote by x ( η , ω ) ; η J , ω [ 0 , π ] the value of x ( η ) at ω. Let A : D ( A ) L 2 [ 0 , π ] L 2 [ 0 , π ] , A x ( η , ω ) : = 2 ω 2 x ( η , ω ) and domain A be defined as
D ( A ) = { x L 2 [ 0 , π ] : x , x are absolutely continuous , x L 2 [ 0 , 1 ] , x ( η , 0 ) = x ( η , π ) = 0 } .
Using [37], there is a compact analytic semi-group { Υ ( η ) : η 0 } generated by A and
A x = n = 1 n 2 < x , x n > x n , x D ( A ) ,
where x n ( y ) = 2 sin n y , n = 1 , 2 , is the orthonormal set of eigenvalues of A . In addition, for all x L 2 [ 0 , 1 ] , one gets
Υ ( η ) ( x ) = n = 1 e n 2 η < x , x n > x n .
So, M = sup { | | Υ ( η ) | | : η 0 } = 1 . Furthermore, for each x L 2 ( [ 0 , π ] , R ) ,
A 1 2 x = n = 1 1 n < x , x n > x n .
A 1 2 x = n = 1 n < x , x n > x n ,
and | | A 1 2 | | = 1 . The domain of A 1 2 is defined as
D ( A 1 2 ) = { x L 2 ( [ 0 , π ] , R ) : n = 1 n < x , x n > x n L 2 ( [ 0 , π ] , R ) } .
Let h : J × Θ E be such that
h ( η , u ) : = A 1 2 ( r 0 λ u ( θ ) d θ ) ,
where λ > 0 . We have
| | A 1 2 h ( η , u 1 ) A 1 2 h ( η , u 2 ) | | E λ | | r 0 ( u 1 ( θ ) u 2 ( θ ) ) d θ | | λ r 0 | | u 1 ( θ ) u 2 ( θ ) | | d θ λ | | u 1 u 2 | | Θ ,
and
| | A γ h ( η , u ) | | λ | | r 0 ( u ( θ ) d θ | | λ | | u | | Θ .
Then, (10) and (11) are satisfied with d 1 = d 2 = λ .
Let Λ be a convex compact subset in E, sup { | | z | | : z Z } = ϱ and κ > 0 . Define F : J × Θ 2 L 2 [ 0 , π ] by
F ( η , u ) : = e κ η | | u | | ϱ Λ .
We have
| | F ( η , u ) | | = sup { | | e κ η | | u | | ϱ z : z Λ } e κ η ; η J .
Moreover, for any bounded subset D Θ , we have F ( η , D ) ς e κ η ϱ Λ , where ς = sup { | | u | | : u D } and, hence, χ E ( F ( η , D ) ) = 0 . Then, F satisfies ( H F 1 ) , ( H F 2 ) * and ( H F 3 ) with ξ ( η ) = e κ η , β ( η ) = 0 ; η J .
Next, let
I : E E , I i ( x ) : = σ p r o j Λ x ,
where σ is a positive number. Obviously, I verifies ( H I ) with ς i = 0 ; i = 1 , 2 , .
Therefore, by applying Theorems 1 and 4, the set of solutions for the following fractional neutral impulsive semilinear differential inclusions with delay:
c D 0 , η α [ x ( η ) h ( η , ϰ ( η ) x ) ] 2 ω 2 x ( η , ω ) + F ( η , ϰ ( η ) x ) , a . e . η [ 0 , 1 ] { 1 2 , 1 } , I i x ( η i , ω ) = x ( η i , ω ) x ( η i + , ω ) , i = 1 , 2 , ω [ 0 , π ] , x ( η , ω ) = ψ ( η , ω ) , η [ r , 0 ] , η [ 0 , 1 ] { 1 2 , 1 } ,
is a not empty, compact and an R δ -set provided that
λ ( 1 + C 1 γ Γ ( 3 2 ) Γ ( 1 + α 2 ) ) < 1 ,
and
λ 2 + 2 λ C 1 γ Γ ( 3 2 ) Γ ( 1 + α 2 ) + 1 2 Γ ( ( α ) ( P 1 α P 1 ) P 1 P ξ L ( J , , R + ) P + σ < 1 ,
where F , h I are given by (45)–(47). By choosing λ and σ small enough and κ large enough, we arrive to (50) and (51).
Example 2.
Let J , E , A , r , η 0 , η 1 , η 2 Λ , and ϱ be as in Example (1) and θ [ r , 0 ] be a fixed element.
Let h : J × Θ E be such that
h ( ( η , ϰ ( η ) x ) ( ω ) : = λ 0 π U ( ω , y ) x ( θ + η ) ( ω ) d y ; ω [ 0 , π ] ; η [ 0 , 1 ] ,
where λ > 0 , U : [ 0 , π ] × [ 0 , π ] R is measurable, 0 π 0 π U ( ω , y ) d y d ω < , U ( ω , η ) ω is measurable, U ( 0 , y ) = U ( π , y ) = 0 , y [ 0 , π ] and ( 0 π 0 π ( U ( ω , η ) ω ) 2 d y d ω ) 1 2 < .
Next, let F : J × Θ 2 L 2 [ 0 , π ] , F ( ( η , ϰ ( η ) x ) ( ω ) = γ G ( η , x ( θ + η ) ( ω ) ) | ϱ Λ , where γ > 0 , G : J × R R is a continuous function. Then, by choosing λ and σ small enough, one can show that h and F satisfy all assumptions of Theorems 2 (see [15,43]) and, hence, the set of mild solutions for the partial differential inclusions of impulsive neutral type with delay:
c D 0 , η α [ x ( η , ω ) 0 π U ( ω , y ) x ( θ + η ) ( ω ) d y , ] 2 ω 2 x ( η , ω ) + G ( η , x ( θ + η ) ( ω ) ) | ϱ Λ , a . e . η [ 0 , 1 ] { 1 2 , 1 } , I i x ( η i , ω ) = x ( η i , ω ) x ( η i + , ω ) , i = 1 , 2 , ω [ 0 , π ] , x ( η , ω ) = ψ ( η , ω ) , η [ r , 0 ] , η [ 0 , 1 ] { 1 2 , 1 } ,
is an R δ -set.

6. Discussion

The neutral differential equations and inclusions appear in many applied mathematical sciences such as viscoelasticity, and the equations describe the distribution of heat. Since the set of mild solutions for a differential inclusion having the same initial point may not be a singleton, many authors are interested to investigate the structure of this set in a topological point of view. An important aspect of such structure is the R δ - property, which means that the homology group of the set of mild solutions is the same as a one-point space. In the literature, there are many results on this subject but no result about the topological properties of the set of mild solutions for a fractional neutral differential inclusion generated by a non-compact semigroup in the presence of impulses and delay. As cited in the introduction, when the problem involves delay and impulses, we cannot consider the space PC ( [ r , b ] , E ] as the space of solutions. To overcome these difficulties, a complete metric space H is introduced as the space of mild solutions. In addition, the function η ϰ ( η ) x ¯ ; x ¯ H is not necessarily measurable, therefore, a norm different from the uniform convergence norm is introduced on Θ (see Equation (2)).

7. Conclusions

During the past two decades, fractional differential equations and fractional differential inclusions have gained considerable importance due to their applications in various fields, such as physics, mechanics and engineering. For some of these applications, one can see [28] and the references therein. In this paper, we have given an affirmative answer for a basic question, which is whether there exists a solution set carrying an R δ -structure when there are impulsive effects and delay on the system, the operator families generated by the linear part lack compactness and the order is fractional. More specifically,
  • By utilizing the properties of both multivalued functions, fraction powers of operators, measures of non-compactness and analytic semi-groups, we showed that the mild solutions set for a fractional impulsive neutral semilinear differential inclusions with delay and generated by a non-compact semi-group is not empty, compact and an R δ -set. This means that, from an algebraic topological perspective, it is equivalent to a point.
  • Our work generalizes the obtained results in [19], where Problem 1 is investigated without delay and h 0 .
  • Our work generalizes the obtained results in [15] to the case when there are impulsive effects on the system.
  • Our technique can be used to prove that the solutions set is an R δ -set for problems considered in [13,14,15,16,17,18,19,20,21,22,23,30] when it is generated by a non-compact semi-group, the order is fractional and there are impulsive effects and delay.
  • As a future work, we suggest to extend the work conducted in [24,25,26] to find the sufficient conditions that guarantee that the solution set is an R δ -set.

Author Contributions

Funding acquisition, Z.A. and A.G.I.; investigation, Z.A. and A.G.I.; methodology, Z.A., A.G.I. and A.A.; writing—original draft, Z.A. and A.G.I.; writing—review and editing, Z.A., A.G.I. and A.A. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

Not applicable.

Acknowledgments

This research has been funded by the Scientific Research Deanship at University of Ha’il—Saudi Arabia through project number RG-21 101.

Conflicts of Interest

The authors declare no conflict of interest.

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Alsheekhhussain, Z.; Ibrahim, A.G.; Ali, A. Topological Structure of the Solution Sets for Impulsive Fractional Neutral Differential Inclusions with Delay and Generated by a Non-Compact Demi Group. Fractal Fract. 2022, 6, 188. https://doi.org/10.3390/fractalfract6040188

AMA Style

Alsheekhhussain Z, Ibrahim AG, Ali A. Topological Structure of the Solution Sets for Impulsive Fractional Neutral Differential Inclusions with Delay and Generated by a Non-Compact Demi Group. Fractal and Fractional. 2022; 6(4):188. https://doi.org/10.3390/fractalfract6040188

Chicago/Turabian Style

Alsheekhhussain, Zainab, Ahmed Gamal Ibrahim, and Akbar Ali. 2022. "Topological Structure of the Solution Sets for Impulsive Fractional Neutral Differential Inclusions with Delay and Generated by a Non-Compact Demi Group" Fractal and Fractional 6, no. 4: 188. https://doi.org/10.3390/fractalfract6040188

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