1. Introduction and Motivation
When studying various third- and fourth-order curves and some other geometric problems, the authors have often encountered abstract geometric structures, which seemed worth studying. In [
1], we named these cubic structures. In the same paper, numerous examples of these structures are given, and the connection of these geometric structures with algebraic structures are investigated. Additionally, the connection between cubic structures and totally symmetric medial quasigroups, as well as commutative groups, was thoroughly studied. Some simple properties of cubic structures were also proven.
Let Q be a nonempty set, whose elements are called points, and let  be a ternary relation on Q. Such a relation and the ordered pair  is called a cubic relation and a cubic structure, respectively, if the following conditions are fulfilled:
- C1.
 For any two points , there is a unique point  such that , i.e., .
- C2.
 The relation  is totally symmetric, i.e.,  implies , , , , and .
- C3.
 , 
, 
, 
, and 
 imply 
, which can be clearly written in the form shown in the following table:
			
Throughout the paper, we use the property C2 without explicitly mentioning it.
Given a nonempty set Q and a binary operation · on Q, the pair  is called a quasigroup if, for each , unique elements x and y exist, such that  and . (From now on, whenever there is no risk of confusion, the product is simply denoted by a juxtaposition.) A quasigroup  in which the identity  is valid is called medial, and it is totally symmetric if it satisfies the identities , . A totally symmetric medial quasigroup is called TSM-quasigroup for short.
One can prove that if the equivalence
      
      links the ternary relation 
 and the binary operation ·, then 
 is a cubic structure if and only if it is a TSM-quasigroup [
1] (Th. 1). The properties of TSM-quasigroups were thoroughly studied in [
2].
Some geometric examples of cubic structures were considered in [
1], the most important of which is perhaps [
1] (Example 2.1). Let 
 be a planar cubic curve, 
, the set of all nonsingular points on 
, and let 
 mean that the points 
 lie on the same line. Then, one can prove that 
 is a cubic structure. In this paper, some well-known relationships that are valid on a cubic curve motivate the introduction of new concepts in a general cubic structure.
Two concepts in cubic structures are defined in [
3]. The point 
 is the 
tangential of point 
a if the statement 
 holds. Each point has one and only one tangential. If point 
 is the tangential of point 
a, then we can also say that point 
a is an 
antecedent of point 
. If 
 is the tangential of point 
a and 
 is the tangential of point 
, then we can say that 
 is the 
second tangential of point 
a. Two points are said to be 
corresponding if they have a common tangential. If the maximum number of mutually corresponding points is finite, then it is of the form 
 for some fixed number 
.
In such a case, we can say that the distinct points ,  with the common tangential are associated. The number m is called the rank of the observed cubic structure ).
  2. Inflection Points
We say that point a in a cubic structure is an inflection point, so the statement  holds, i.e., if that point is self-tangential.
Lemma 1. If points a and b are inflection points and if the statement  holds, then point c is also an inflection point.
 Proof.  The proof follows by applying the table
        
 Example 1. For a more visual representation of Lemma 1, consider the TSM-quasigroup given by the Cayley table  Lemma 2. If inflection point a is the tangential point of point b, then a and b are corresponding points.
 Proof.  Point a is the common tangential of points a and b.    □
 Example 2. For a more visual representation of Lemma 2, consider the TSM-quasigroup given by the Cayley table|   |   a   |   b   |   c   |   d   | 
|   a   | a | b | d | c | 
| b | b | a | c | d | 
| c | d | c | b | a | 
| d | c | d | a | b | 
  Proposition 1. If  and  are the tangentials of points a and b, respectively, and if c is an inflection point, then  implies .
 Proof.  According to [
3] (Th. 2.1), 
 implies 
, where 
 is the tangential of 
c. However, in our case 
.    □
 Lemma 3. If  and  are the tangentials of points a and b respectively, and if  and , then c is an inflection point.
 Proof.  The statement is followed by applying the table
        
 Example 3. For a more visual representation of Proposition 1 and Lemma 3, consider the TSM-quasigroup given by the Cayley table|   |   a   |   b   |   c   |   d   |   e   | 
|   a   | d | c | b | a | e | 
| b | c | e | a | d | b | 
| c | b | a | c | e | d | 
| d | a | d | e | b | c | 
| e | e | b | d | c | a | 
  Lemma 4. If  and  are the tangentials of points a and b, respectively, and if c is an inflection point, then  and  imply that c and d are corresponding points.
 Proof.  From the table
         
        it follows that point 
d has the tangential 
c, which itself is self-tangential.    □
 Example 4. For a more visual representation of Lemma 4, consider the TSM-quasigroup given by the Cayley table|   |   a   |   b   |   c   |   d   |   e   |   f   |   g   |   h   | 
|   a   | e | d | g | b | a | h | c | f | 
| b | d | f | h | a | g | b | e | c | 
| c | g | h | c | d | f | e | a | b | 
| d | b | a | d | c | e | f | h | g | 
| e | a | g | f | e | d | c | b | h | 
| f | h | b | e | f | c | d | g | a | 
| g | c | e | a | h | b | g | f | d | 
| h | f | c | b | g | h | a | d | e | 
  Lemma 5. If the corresponding points , , and their common second tangential  satisfy , then  is an inflection point.
 Proof.  The statement follows on from the table
       
        where 
 is the common tangential of points 
 and 
.    □
 Example 5. For a more visual representation of Lemma 5, consider the TSM-quasigroup given by the Cayley table|   |   
                   |      |      |   
                   | 
|   
                   |   
                   |   
                   |   
                   |   
                   | 
|   
                   |  |  |  |  | 
 |  |  |  |  | 
 |  |  |  |  | 
  Lemma 6. Let , , and  be pairwise corresponding points with the common tangential , such that . Then,  is an inflection point.
 Proof.  The proof follows from the table
        
 Example 6. For a more visual representation of Lemma 6, consider the TSM-quasigroup given by the Cayley table|   |      |      |      |      | 
|      |      |      |      |      | 
|      |  |  |  |  | 
 |  |  |  |  | 
 |  |  |  |  | 
  Corollary 1. Let , , and  be pairwise corresponding points with the common tangential , which is not an inflection point. Then,  does not hold.
 Lemma 7. Let , , , and . Point a is an inflection point if and only if .
 Proof.  Each of the 
if and 
only if statements follow on from one of the respective tables:
       
 Example 7. For a more visual representation of Lemma 7, consider the TSM-quasigroup given by the Cayley table|   |   a   |   b   |   c   |   d   |   e   |   f   |   g   | 
|   a   | a | e | f | g | b | c | d | 
| b | e | f | d | c | a | b | g | 
| c | f | d | g | b | e | a | c | 
| d | g | c | b | e | d | f | a | 
| e | b | a | e | d | c | g | f | 
| f | c | b | a | f | g | d | e | 
| g | d | g | c | a | f | e | b | 
    3. Inflection Points in Cubic Structures of Rank 2
Let  be a cubic structure of rank 2, i.e., associated points form quadruples.
Lemma 8. Let inflection point  be the common tangential of distinct points  and , and let  be a point such that . Then,  is also the tangential of point , i.e., , , , and  are associated points.
 Proof.  The proof follows by applying the table
        
 Proposition 2. Let  be the common tangential of points , , and , and let these four points be distinct. If  is an inflection point, then .
 Proof.  Let b be a point such that . By Lemma 8, points , , , and b are associated, and .    □
 Theorem 1. Let , , , and  be associated points, and let . Then,  is an inflection point and it is also the common tangential of points , , and .
 Proof.  Let  be the common tangential of points , , , and . By Lemma 6,  is an inflection point, i.e., the common tangential of points , , , , and . Therefore, point  is actually one of points , , , or . If , then  would be an inflection point and the common tangential of points , , and , and by Proposition 2, it follows that , which is, by C1, impossible because  holds. In the same way, we get contradictions by assuming  or . Therefore, .    □
 For a more visual representation of Lemma 8, Proposition 2, and Theorem 1 consider the TSM-quasigroup in Example 6.
In [
3] (Th. 4.3), we proved the following: If 
, 
, 
, and 
 are associated points with the common tangential 
, then points 
p, 
q, and 
r exist such that 
, 
, 
, 
, 
 and 
, and points 
, 
p, 
q, and 
r are associated.
Theorem 2. Let , , , and  be associated points with the first and second tangentials  and , where . If  is an inflection point, then it is one of points p, q, or r, such that , , , , , and . If, e.g., , then .
 Proof.  The points , p, q, and r are associated, and their common tangential is the tangential  of point . Point  is self-tangential. Because of the rank 2, there are only four different associated points, and since , point  must be equal to one of points p, q, or r. Let, e.g., . Since  is an inflection point and also the tangential of points , p, and q, it follows from Proposition 2 that .    □
 Example 8. For a more visual representation of Theorem 2, consider the TSM-quasigroup given by the Cayley table|   |      |      |      |      |      |      |      |      | 
|      |      |      |      |      |      |      |      |      | 
|      |  |  |  |  |  |  |  |  | 
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 |  |  |  |  |  |  |  |  | 
 |  |  |  |  |  |  |  |  | 
 |  |  |  |  |  |  |  |  | 
 |  |  |  |  |  |  |  |  | 
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