1. Introduction
Ricci solitons are essential in geometric analysis, as they are self-similar solutions to the Ricci flow and natural extensions of Einstein metrics. Introduced by Hamilton in the context of the Ricci flow [
1], Ricci solitons provide key geometric models for studying singularity formation. They also reveal deep connections with semi-Riemannian geometry.
In recent years, the study of Ricci soliton structures on submanifolds, particularly on hypersurfaces, has gained significant traction, especially when these are embedded in ambient manifolds with distinct symmetries. A powerful strategy for achieving classification results is to utilize the tangential component of a key ambient vector field as the soliton potential vector field. This approach frequently encompasses the tangential part of a closed conformal vector field or the position vector in flat ambient spaces. By implementing this strategy, we can derive effective, necessary, and sufficient conditions that greatly enhance our classification efforts.
In [
2], a classification of Ricci solitons on Euclidean hypersurfaces is provided, which arises from the position vector field of those hypersurfaces. In [
3], it has been clearly demonstrated that a complete gradient Ricci soliton, characterized by a non-parallel closed conformal vector field and constant scalar curvature, is isometric to one of three distinct geometries: Euclidean space, a Euclidean sphere, or a negatively curved Einstein warped product of the real line combined with a complete non-positively curved Einstein manifold.
In [
4], the authors explored Ricci solitons on Riemannian hypersurfaces that are immersed in both Riemannian and Lorentzian manifolds with constant sectional curvature. They demonstrated that, under certain conditions, these hypersurfaces must be totally umbilical. This conclusion implies that they possess both constant mean curvature and constant sectional curvature.
Recently, there has been significant progress in the study of Ricci solitons within the context of Lorentzian and pseudo-Riemannian geometry, as evidenced in works such as [
5,
6,
7,
8,
9,
10]. These studies reflect a growing interest in the relationship between Ricci solitons, hypersurface geometry, and conformal vector fields, and they motivate further investigation into new geometric contexts and classification results.
For a semi-Riemannian manifold
, a quadruple
is said to define a Ricci soliton if there exists a vector field
and a constant
satisfying
where
is the Ricci tensor of
, and
is the Lie derivative of the metric
g along
.
is known as the potential vector field, while
is called the soliton constant.
In this work, we study the Ricci solitons on Lorentzian hypersurfaces in Lorentzian ambient manifolds that admit a closed conformal vector field. The main results of the paper can be summarized as follows:
- (1)
We derive intrinsic relations linking the Ricci tensor of the Lorentzian hypersurfaces, the shape operator, and the closed conformal vector field.
- (2)
We prove that Ricci solitons of this type in Lorentzian space forms are uniquely found in Minkowski space .
- (3)
We obtain classification results in Minkowski space , extending several recent contributions to the theory of Ricci solitons on Lorentzian hypersurfaces.
The paper is structured as follows. In
Section 2, we explore essential definitions and key formulas concerning hypersurfaces in real space forms. Then, in
Section 3, we present several examples of Lorentzian hypersurfaces in Minkowski space
, providing compelling model cases that are used in our classification results. In
Section 4, we establish the intrinsic equation relating the Ricci tensor, the shape operator, and the closed conformal vector field, and we show that Ricci solitons of this type in Lorentzian space forms exist only in Minkowski space
. In this setting, we show that the shape operator must belong to one of seven canonical forms described in Theorem 3. Finally,
Section 5 contains the results of the rigidity theorems and a complete classification of Ricci solitons on bad and good hypersurfaces in
induced by concircular vector fields.
2. Preliminaries
Throughout this article, we assume that
. Let
be a Lorentzian hypersurface immersed in an
-dimensional Lorentzian manifold
, and let
denote a local spacelike unit normal vector field along
. We denote by A the shape operator corresponding to the normal field
N. The operator A is self-adjoint with respect to the metric
g, namely,
for all
. If
and ∇ stand for the Levi–Civita connections of
and
, respectively, then the Weingarten formula is given by
for any
.
The Gauss formula is expressed as
for all
.
The Codazzi equation reads
for all
. Here, the covariant derivative of A is defined by
for all
.
The mean curvature of the Lorentzian hypersurface
is defined by
The Ricci tensors of the hypersurface
and the ambient manifold
are connected through the Gauss equation (see [
8,
11]), which can be written as
for all
, where
is the curvature tensor of
.
Furthermore, taking the trace of Equation (
6), we obtain the relation between the scalar curvatures S and
of
and
, respectively:
where
.
For each point
, the relative nullity distribution is defined by
the dimension of
is called the index of relative nullity at
x, while
, the type number at
x, is the rank of
.
It is well known that the shape operator A of a Lorentzian hypersurface
in a Lorentzian manifold
is not necessarily diagonalizable. In such a case, A can be classified according to a classical result (see, for example, [
7,
12]).
Lemma 1.
Let A be the shape operator of an n-dimensional Lorentzian hypersurface of a Lorentzian manifold . A can be taken in one of the following four matrix forms:
- 1.
;
- 2.
, with ;
- 3.
, where ;
- 4.
.
In cases (1) and (2), the operator A is represented in an orthonormal basis of where and for . All other inner products in this basis are zero.
In cases (3) and (4), the operator A is represented in a pseudo-orthonormal basis where and for . Again, all other inner products are zero.
4. Ricci Solitons on Lorentzian Hypersurfaces in Lorentzian Space Forms
Let
represent an orientable Lorentzian hypersurface in a Lorentzian space form
of dimension
. We will consider
as a closed conformal vector field on
that satisfies the equation:
for
. Here,
is a smooth conformal function. In particular, when
, the vector field
is said to be parallel. If
is a nonzero constant, then
is called concircular, and
is referred to as the concircular factor. Moreover, when
, the vector field
is said to be concurrent.
Let
be the restriction of
to
, and let
be a unit spacelike normal vector field on
, we define
, leading us to express
as
here
is the tangential component of
.
Using the Gauss and Weingarten formulas, we derive:
and
From (
8), we obtain the divergence:
Building on Formula (
1), we can now derive a crucial result that plays a pivotal role in our analysis.
Lemma 2.
Let be an (n+1)-dimensional Lorentzian manifold with a closed conformal vector field . If a Lorentzian hypersurface in admits a Ricci soliton , then the Ricci tensor of satisfies the following equation:for all . In contrast to the Einstein case (cf. [
11]), Lorentzian hypersurfaces supporting a Ricci soliton in space forms cannot possess complex eigenvalues.
Lemma 3.
Let be an (n+1)-dimensional Lorentzian space form with a closed conformal vector field , and a Lorentzian hypersurface in . If is a Ricci soliton, then the shape operator A cannot admit a complex eigenvalue and cannot take the fourth form in Lemma 1.
Proof. Assume, for contradiction, that A has a complex eigenvalue at point
. Let
be an orthonormal basis of
such that A takes the second form of Lemma 1. By Lemma 2, we have
and
and
and for
, we have
On the other hand, by utilizing Formula (
6), we obtain the following
and for
, we have
By examining the previous equations, we can establish the following equations
and for
Substituting (
13) into (
12), we have
and by substituting (
13) and (
15) into (
14), we deduce that
which is a contradiction, as
. Thus, A cannot have complex eigenvalues.
Suppose
is a pseudo-orthonormal basis of
such that
A takes the third form of Lemma 1. By Lemma 2, we have
On the other hand, utilizing Formula (
6) yields the following.
which is an abuse. Hence,
A cannot take the third form of Lemma 1. □
We now state a result determining the structure of the shape operator for Lorentzian hypersurfaces supporting a Ricci soliton in Lorentzian space forms with a closed conformal vector field, in analogy with the main theorem of [
11] established for the Einstein case.
Theorem 1.
Let be an (n+1)-dimensional Lorentzian space form that admits a closed conformal vector field with a conformal function ρ. Let be a Lorentzian hypersurface in . If is a Ricci soliton, then the shape operator A is either
- i
, with , and . In particular, ,
- ii
, with , , and .
- iii
, with , and .
Proof. According to Lemma 3, the shape operator A does not have any complex eigenvalues. Furthermore, the fourth canonical form listed in Lemma 1 cannot occur
Case 1. Let
be an orthonormal basis on
such that
A is diagonal, that is,
A takes the first form of Lemma 1. By Lemma 2, we have, for all
i,
On the other hand, utilizing Formula (
6) yields the following
It follows that for every
i, we have
By examining (
17), we can confidently establish the following equation
for
. If
, and
for
, then by (
18), we deduce
. It follows that there are at most two distinct eigenvalues, say
and
. If
, we deduce from (
17), which represents a second-degree polynomial having two distinct roots, that
In particular, , which implies that , where p is the multiplicity of . If , we deduce that , and consequently, .
Case 2. Let
be a pseudo-orthonormal basis of
such that
A is represented by a matrix taking the third form of Lemma 1. By Lemma 2, we have
and for
, we have
On the other hand, utilizing formula (
6) yields the following
and for
, we have
By examining the previous equations, we can confidently establish the following equations
and for
Substituting (
19) into (
20), we have
and substituting (
19) and (
22) into (
21), it implies that
for each
. Hence, the shape operator
A has the form
□
Corollary 1.
Let be a Lorentzian space form that admits a closed conformal vector field . Let be a Lorentzian hypersurface in . If is a Ricci soliton, then the shape operator has almost two distinct real eigenvalues.
In terms of scalar curvatures, Theorem 1 can be stated as follows:
Corollary 2.
Let be a Lorentzian space form that admits a closed conformal vector field . Let be a Lorentzian hypersurface in . If is a Ricci soliton, then the shape operator is either
- i
, with ,
- ii
, with - iii
, with .
Based on Corollary 2 and Formula (
7), we have the following:
Theorem 2.
Let be a Lorentzian space form that admits a closed conformal vector field . Let be a Lorentzian hypersurface in . If is a Ricci soliton, then necessarily , that is is the Minkowski space .
Proof. It is clear that case (ii) in Corollary 2 includes case (i). So, it suffices to consider case (ii). In this case, it follows (
7) that
which simplifies to
.
In the case the shape operator takes the form (iii), we get:
which also leads to the conclusion that
. □
Based on the conclusion that
, we find that we are dealing with Lorentzian hypersurfaces in the (n + 1)-dimensional Minkowskiwski space
. Closed conformal vector fields of
are well-known (see [
15]). We will focus on the case where
is a concircular vector field.
Theorem 3.
Let be a Lorentzian hypersurface in . Let be a concircular vector field in , with concircular function ρ. If is a Ricci soliton, then the shape operator A takes one of the following:
- 1.
, . In this case, .
- 2.
. In this case, .
- 3.
A is diagonalizable and possesses two distinct nonzero eigenvalues, α and β, each of multiplicity greater than 1.
- 4.
A is diagonalizable and possesses two distinct nonzero eigenvalues, α and β, one of them of multiplicity 1.
- 5.
A is diagonalizable and possesses two distinct eigenvalues of multiplicity greater than 1, and . In this case, we have .
- 6.
A is nondiagonalizable with a single eigenvalue and a minimal polynomial of . In this case, .
- 7.
A is nondiagonalizable with a unique eigenvalue , and its minimal polynomial is . In this case, .
Let
be a Lorentzian hypersurface in
. According to [
8,
16], a point
is classified as a bad point if the matrix A at
x is nonsingular and has a simple eigenvalue. Conversely, if A at
x does not meet these criteria, we categorize
x as a good point. If all points in
are good, we call
a good hypersurface.
We classify points based on the specific form of . If corresponds to forms 1, 2, …, or 7 of Theorem 3, x is said to be of type 1, 2, …, or 7, respectively. The collection of points belonging to type i is referred to as . Also, we say that is a point of type 1, 2, …, or 7 according to whether has the form 1, 2, …, or 7, respectively. The set of points of type i will be denoted by . We will refer to as the “bad set.”
Theorem 4.
Let be a Lorentzian hypersurface in . Let be a concircular vector field in . If is a Ricci soliton, then the bad set is open.
Proof. Let
and
be the two eigenvalues of A, and let
x be a bad point, so that
and
are two distinct nonzero eigenvalues of multiplicity 1 and
, respectively. Then, since A is nonsingular, there is a neighborhood
U of
x on which A is nonsingular. By Theorem 3,
U consists of points of type 1, 3, 4, and 7. We may assume without loss of generality that
By continuity, we may assume that on U. Since A has at most two distinct eigenvalues, we necessarily have . Hence, , meaning that is open. □
Remark 1.
Assume that x is a point of type 3, so that and are two distinct nonzero eigenvalues of multiplicity and , respectively. Then, since A is nonsingular, there is a neighborhood U of x on which A is nonsingular. By Theorem 3, U consists of points of type 1, 3, 4 and 7. We may assume without loss of generality that By continuity, we may assume that on U. Since A has at most two distinct eigenvalues, we necessarily have . Hence, , meaning that is open.
Theorem 5.
Let be a Lorentzian hypersurface in . Let be a concircular vector field in , with concircular function c. If is a Ricci soliton with , then the bad set is closed.
Proof. Assume converges to . Then, A at is diagonalizable and its eigenvalues and are distinct and nonzero, and moreover . By continuity of the eigenvalues, . Since , it follows that . Thus, A is diagonalizable at x and has two distinct nonzero eigenvalues, which means that . However, since is open, it follows that . □
Remark 2.
Assume converges to . Then, A at is diagonalizable and its eigenvalues and are distinct and nonzero, and moreover . By continuity of the eigenvalues, . Since , it follows that . Thus, A is diagonalizable at x and has two distinct nonzero eigenvalues, which means that . However, since is open, it follows that .
Theorem 6.
Let be a connected Lorentzian hypersurface in . Let be a concircular vector field in , with concircular function ρ. If is a Ricci soliton with and has at least one good point, then consists entirely of points of .
Proof. Since , then according to Theorem 3 . Since is connected, we deduce from Theorems 4 and 5 that is a good hypersurface, and . □
5. Rigidity and Classification of Ricci Solitons on Lorentzian Hypersurfaces
In this section, we investigate rigidity and Classification results for Ricci solitons on Lorentzian hypersurfaces of Minkowski space with a concircular vector field.
Theorem 7.
Let be a concircular vector field on , with concircular function ρ. Let be a complete, connected Lorentzian hypersurface in with at least one good point. If is a Ricci soliton with , then is one of the following products:
- 1.
, or
- 2.
, where , and .
Proof. Since
is connected with at least one good point, then
is good, and since the multiplicities of
and
are greater than one, it follows that
(resp.
) for all
(resp.
), where
and
are the smooth subbundles of
given by
and
(see Lemma 3.3 in [
17]) see also proposition D4 in [
18]. Accordingly, we deduced from the equation
that
and
are constant. The result now follows from Theorem 3.3 in [
17] (see also [
18]). □
In the study of bad Lorentzian hypersurfaces within
, we present a significant theorem. See Theorem 5.10 in [
19].
Theorem 8.
Let be a concircular vector field on , with concircular function ρ. Let be a complete and connected Lorentzian hypersurface in with at least one bad point. If is a Ricci soliton with , then is foliated by dimensional spaces of constant curvature .
Proof. According to Theorem 4, the set
consists entirely of bad points. Let
and
represent the two distinct eigenvalues of the shape operator A, with multiplicities 1 and
, respectively. By Proposition 2.3 in [
8], the distributions
and
are both differentiable and integrable. Moreover,
remains constant on each leaf
; thus,
is a non-degenerate, totally geodesic hypersurface of
. The curvature tensor on
aligns with the restriction of
R. Given that the dimension of
is
, this means that
has a constant curvature of
. □
When
, the complexities become challenging. We will discuss several partial results from our research. We can illustrate these results using the methodology from the theorem in [
16], as it is relevant to our case.
Theorem 9.
Let be a concircular vector field on , with concircular function ρ. Let be a good connected Lorentzian hypersurface in . If is a Ricci soliton with , then is either one of the following Lorentzian manifolds:
- 1.
.
- 2.
, with and .
- 3.
, with and .
- 4.
A generalized umbilical hypersurface of type 1 of , Example 3.
Proof. Assume
and
are the only eigenvalues of A. Since
is a good manifold, Theorem 3 ensures that
. Suppose that there exists a point
of type 3, where the eigenvalues
and
have multiplicities
p and
, respectively, with
and
. Set
W is closed. Furthermore, the continuity of the eigenvalues implies that there exists an open neighborhood
U of
such that
. Indeed, since A admits exactly two distinct eigenvalues, both
and
are differentiable on
U and have constant multiplicities
p and
, respectively (see [
19], Proposition). For notational simplicity, we set
Since
and
, Proposition D.4 in [
18] guarantees that the distributions
and
are differentiable and involutive. Moreover, the functions
and
are constant along the leaves
and
, respectively. On the set
W, the relation
holds, which implies that
and
are locally constant near
. Consequently,
W is also open.
Now, from Proposition 4.4 in [
8], and Wu’s extension [
20] of the de Rham decomposition theorem to pseudo-Riemannian manifolds, we can conclude that
is locally isometric to a product of a Riemannian manifold and a Lorentzian manifold, both of which have constant positive curvature. This establishes statements (2) and (3) of the theorem.
Suppose that
has no points of type 3. It follows that
. Let
denote the unique eigenvalue of A.
is a constant, by Proposition D.4 in [
18]. Furthermore, Theorem 3 yields
This leads to the conclusion that and are disjoint closed subsets. By connectedness of , it follows that either or . This implies statements (2) and (3). □
Theorem 10.
Let be a concircular vector field on , with concircular function c. Let be a complete, connected Lorentzian hypersurface in . If is a Ricci soliton with and θ vanishes on , then is locally flat and isometric to one of the following Lorentzian manifolds:
- 1.
.
- 2.
, where is a Euclidean cylinder in the 3-dimensional Euclidean space
- 3.
, where is a Lorentz cylinder or a B-scroll in (Example 2).
Proof. According to Theorem 3, all points
are of type 2, type 5, or type 6 with the multiplicity of
equal to 1. This implies that the type number
for all
. Furthermore, by Proposition 5.3 in [
19], we conclude that
is locally flat. □
We now present a result that extends Theorem 5.5 in [
19] by replacing the assumption
with the less stringent condition
.
Theorem 11.
Let be a concircular vector field on , with concircular function c. Let be a complete, connected Lorentzian hypersurface in . If is a Ricci soliton with and θ does not vanish on , then is isometric to either or , where , and .
Proof. By Theorem 3,
consists of points of type 5. Let
be the nonzero eigenvalue of A of multiplicity
p, since
, then
. From Proposition 2.2 in [
8], the eigenvalue
has a constant multiplicity. Also, Proposition 2.3 in [
8] the distributions
and
are differentiable and integrable, and since
, then
is constant on each leaf of
. Also from Lemma 5.7 in [
19] (also see Lemma 5.6 in [
21]),
is constant on
. □