Abstract
It has been conjectured that for each positive integer k and each tree T with bipartite , every k-connected bipartite graph G with admits a subgraph such that is still k-connected. In this paper, we generalize the ear decompositions of 2-connected graphs into a -extensible system for a general k-connected graph. As a result, we confirm the conjecture for by proving a slightly stronger version of it.
MSC:
05C30; 05C35; 05C60
1. Introduction
In this paper, we only consider finite, undirected, and simple graphs (no loops and parallel edges). For a graph G, and are its vertex set and edge set, respectively. The order of a graph G is the number of its vertices. For a vertex , the degree is the number of edges incident with u. For a vertex set U, write , is the subgraph induced by U, and . The neighborhood for some . The minimum degree . For two vertices of G, a path connecting u and v is called a -path. The inner vertices of P is the vertices in . For two vertices , is the -path contained in P. A set of -paths is internally disjoint if for any . A graph G is k-connected if there are k internally disjoint -paths for every pair of distinct vertices in G. Chartrand, Kaugars, and Lick [1] gave the following well-known result.
Theorem 1
(Chartrand, Kaugars, Lick [1]). Every k-connected graph G of minimum degree has a vertex x with .
For a k-connected graph G, its subgraph H is called a k-redundant subgraph if is still k-connected. Furthermore, if H is a tree, then H is called a k-redundant tree. Theorem 1 suggests the existence of a trivial redundant tree. Fujita and Kawarabayashi [2] conjectured that there exists a function such that every k-connected graph G with contains a connected k-redundant subgraph of order m. In the same paper, they proved that , and they also gave examples to show that . Later, Mader [3] confirmed the conjecture and proved that the k-redundant subgraph is, in fact, a path. Based on this result, Mader made the following conjecture.
Conjecture 1
(Mader [3]). For any tree T of order m, every k-connected graph G with admits a k-redundant tree isomorphic to T.
Conjecture 1 has been studied by many researchers, but it has not been proven yet. Diwan and Tholiya [4] confirmed the conjecture for the case . When , many researchers studied special trees [5,6,7,8,9,10]. In [11], we developed a general way to deal with all trees and confirmed the conjecture for arbitrary trees when . For the general connectivity case, Mader [12] showed the minimum degree condition yields a k-redundant tree isomorphic to each prescribed tree T of order m. Very recently, the lower bound of the minimum degree has been decreased to in [13].
In [8], Luo, Tian, and Wu generalized the conjecture into a bipartite graph version. For a bipartite graph G, the bipartition is a partition of such that for .
Conjecture 2
(Luo, Tian, Wu [8]). For any tree T with bipartition , every k-connected bipartite graph G with admits a k-redundant tree isomorphic to T.
In the same paper, Luo, Tian, and Wu proved Conjecture 2 for paths and stars. Later, Yang and Tian [14] further confirmed the conjecture of caterpillars and spiders in the case . Very recently, Yang and Tian [15] proved the conjecture for all trees when under an additional assumption that the girth of G is not less than the diameter minus 1, where the girth is the minimum length of cycles of a graph and the diameter is the maximum distance between two vertices of a graph. In this paper, we remove the additional assumption and prove the same result. In order to distinguish the two parts of a bipartite graph, we define an embedding of a tree T to G as an injective mapping from to such that as long as . For simplicity, we may use to denote either the subgraph induced by or its vertex set. For a vertex set or a subgraph , the image or . In this paper, we generalize the embedding method of [11] into bipartite graphs and prove the following theorem, which confirms the above conjecture for all trees when .
Theorem 2.
Let be an integer and T be a tree with bipartition . If G is a k-connected bipartite graph with bipartition such that, for , , then there exists an embedding such that is still k-connected and for .
We end this section with some notation used in this paper. For a vertex set U and a vertex , a -path P is a -path with for some . A family of -paths are internally disjoint if for any . An r-rooted tree is a tree with a special vertex r which is called the root. A leaf of a rooted tree T is a vertex with degree 1 other than the root. The set of leaves of a rooted tree T is denoted by . An R-rooted forest is the disjoint union of rooted trees, where R is the set of set of roots of all its rooted trees. Write be the union of leaves of each of its rooted trees. Let be two graphs. If there exists a bijection from to such that if and only if , then we see that H is isomorphic to G, denoted by . An independent set of a graph G is a vertex set U of G such that . In the next section, we shall generalize the embedding lemma of [11] to bipartite graphs, and in the last section, we shall apply the embedding lemma to confirm Conjecture 2 for .
2. Embedding Lemmas
In [6,11], different sufficient degree conditions for the existence of any trees are obtained. In this section, these sufficient conditions will be generalized into bipartite versions and are stated as follows.
Lemma 1.
Let T be a tree with bipartition , and such that is connected, where . Let G be a bipartite graph with bipartition and be an embedding of such that for . Denote and . Suppose has a partition such that each of the following holds.
- (i)
- for and , ;
- (ii)
- for and , .
Then, there exists an embedding such that for , and for any .
Proof.
We shall prove a stronger result by replacing (ii) with the following (ii′):
- (ii′)
- for and , ;
The proof is by induction on . If , then is desired. Thus, we may assume that . Let such that for some and be as small as possible, and subject to this, is as small as possible. Then, . Assume that for some . Note that both and are independent sets in T. We see either or . Without loss of generality, we may assume that , and then .
For , let and let , , and . Then for . Also, let , and then, either or . Thus, is a partition of satisfying (i) and (ii′). By the induction hypothesis, there exists a mapping such that for , and for any .
By the choice of , we see that for each . Note that and . By (i) or (ii′), we see that, if , then by (i), there exists ; and if then and by (i) and (ii′), . This implies that there exists . Define by letting and for any . Then, is desired. Noting that (ii′) is deduced from (i) and (ii), the result is proved. □
If we let , and , , then and the conditions in the above corollary are equivalent to those for , , . Thus, we have the following corollary.
Corollary 1.
Let T be a tree with bipartition and G be a bipartite graph with bipartition . If, for , , then there exists an embedding such that for .
For a forest F and , every component C of is a rooted tree with root with the only vertex in . In this paper, we need the following lemma, which is used to verify the conditions in Lemma 1.
Lemma 2.
Let F be a -rooted forest with bipartite , be a -rooted forest, and . If , and , then for , .
Proof.
Assume and are the components of . For , let such that and . For , let and it is easy to see that for if .
For , we shall define a mapping from to as follows: if , then let ; if and is not defined, then for some i and let if and let be one vertex in if . We shall show that is injective. In fact, assume that there exists such that and . Then, by the definition, and thus . Note that for and , since F is bipartite. Without loss of generality, we may assume that for . Then, for , either or . This implies , since and , a contradiction. Thus, is injective, and the result follows. □
The following lemma is crucial to our main result. The method of our proof is more straightforward than that in [11] and can also be applied to the embedding lemma in [11].
Lemma 3.
Let be a tree with bipartition and G be a bipartite graph with bipartition such that for , . Suppose that is a mapping of on G such that for . Let , and . Then, one of the following holds:
- (a)
- ;
- (b)
- For and , ;
- (c)
- There exist and such that and admits a tree .
Proof.
Suppose, to the contrary, that neither (a), (b), nor (c) hold. For , denote
and , . By the assumption that both (a) and (b) fail, we have . Then, we derive the following claim.
Claim 1. .
Firstly, we see that , for otherwise, any vertex in satisfies (c), a contradiction. Suppose that the claim is wrong. Then, there exists a vertex . Without loss of generality, we may assume that . Then, by the definitions of , we have both and . Thus, , a contradiction that proves Claim 1.
For an edge , denote by the two components of containing , respectively. Pick an edge such that and [ or for some with ], and subject to this, is as small as possible (see Figure 1). By Claim 1, the edge exists, since an edge with and exists. Note that is allowed. For simplicity, if , then we define , is the neighbor of w in , and thus .
Figure 1.
Illustration of .
Let and . Then, by Claim 1. By the choice of , for any , all the inner vertices on the only -path in T lie in I and are contained in . This implies that is a subtree of . Define two rooted forests F and as follows: if , then let and , and if otherwise, let and . Then, F is a rooted forest with root or and . Let , be the components of , and for , let (see Figure 1). Then, for some j when . By the choice of , we have for ,
for otherwise, for some k, there exists such that the only path between and v is as long as possible. By the definition of , there exists with a larger distance to v than ’s in T. Thus, is a candidate of , where , either or with and , and , a contradiction.
Define , , and . Then, is a partition of and either (in this case, ) or (in this case, and ). Applying Lemma 2 with F and , we have for .
By the choice of , there exists an . Let and define a mapping by letting and for any . Let , , and . Then, is a partition of , or and by (1). Thus, for any , assuming , . Also, by (1), for any , . By Lemma 1, a mapping exists, which implies that v is a vertex satisfying (iii), a contradiction. The proof is complete. □
3. k-Extensible System
It is well known that a graph is 2-connected if and only if it contains an ear decomposition, which is useful for extending a 2-connected graph into a larger one. However, this does not work for k-connected graphs when . In this section, we define a system that is used to extend a k-connected graph.
For a positive integer k, let be a family of graphs and be a function that assigns a weight in a totally ordered set to each graph in the family. Let and be an integer. We say that is -extensible (bipartite) system if each of the following holds:
- (D1)
- For any k-connected (bipartite) graph G, ;
- (D2)
- For any and , there are at least k internally disjoint -paths in G;
- (D3)
- For any , construct a (bipartite) graph obtained from G by adding a vertex v and connecting v to at least vertices of G. Then, contains a subgraph such that and ;
- (D4)
- For any , if there exists a (bipartite) graph , a vertex and k internally disjoint -paths in such that and is as small as possible, then contains a subgraph such that , and, furthermore, if for any , then for any .
(D1) and (D2) ensure that all k-connected (bipartite) graphs belong to and (D3)(D4) give two methods to “enlarge” a graph of . From the definition, we see that a -extensible system is a generalization of k-connected graphs. When , according to the well-known ear decompositions, it is easy to verify that is (2,2)-extensible system if is the family of all 2-connected graphs and for . Hence, a -extensible system is also a generalization of ear decompositions. In addition, we have the following conjecture.
Conjecture 3.
For any positive integer k, there exists a minimum integer and a -extensible bipartite system such that every bipartite graph G with contains a subgraph .
From the definition, a -extensible system is also a -extensible bipartite system. However, the value of might be different. If Conjecture 3 is true then we can prove Conjecture 2.
Theorem 3.
If Conjecture 3 is true for some , then for any tree with bipartition , every bipartite graph G with bipartition such that for contains a k-redundant tree isomorphic to .
Proof.
By Corollary 1, there exists an embedding : such that for . Let . By the assumption that Conjecture 3 is true, there exists a -extensible system , and let be an induced subgraph of . Without loss of generality, we can assume that and B are chosen so that is as large as possible.
Let . If , then and for any , assuming , . By the definition (D2) of -extensible systems, we see that B is k-connected, and we are done. Hence, we may assume that .
Claim 1. For any , if there exist a vertex u and an embedding such that for , then .
To the contrary, suppose that u and are stated as in the claim, but . By the assumption (3) of -extensible systems, contains an induced subgraph such that and , a contradiction to the choice of and B. The claim is proved.
Claim 2. .
Suppose, to the contrary, that . By Claim 1, we have . By Lemma 1, H contains a tree isomorphic to and every vertex satisfies the condition of Claim 1. Thus, we also have for any . Assume . Then, , a contradiction to the assumption on . The claim is proved.
Noting that G is k-connected, then there exist a vertex and k internally disjoint -paths such that is as small as possible. By Claim 1 and Claim 2, applying Lemma 3, we see that for any . Then, according to the definition (D4) of -extensible systems, G contains a subgraph such that and . It follows that for . By Corollary 1, contains a subgraph and thus, is a subgraph of with , a contradiction. The proof is complete. □
In view of the above theorem, we believe that the value of in Conjecture 3 should be k. In the next section, we shall confirm the existence of k-redundant trees for by using Theorem 3.
4. Redundant Trees
In this section, we confirm Conjecture 2 for and 3 by showing that Conjecture 3 is true for when . For the edge version and the non-bipartite version, see [16] and [11], respectively.
Theorem 4.
Let be the family of 2-connected bipartite graphs and for any . Then, is a -extensible bipartite system such that every graph G with contains a subgraph .
Proof.
First, it is easy to see that every graph with a minimum degree of at least 2 contains a cycle, which belongs to . Hence, it suffices to verify (D1)–(D4) in the definition of -extensible systems. In fact, (D1), (D2), and (D3) can be easily verified from the definition of 2-connected graphs. For (D4), if there exist a graph and two -paths such that is as small as possible, then is 2-connected and . Furthermore, if for any , and there exists such that , then . Assume is a -path for some . Then, is a -path and .
Let closed to . If , then and are choices of with fewer vertices, a contradiction. Hence, and for some . Then, either , or , are candidates of with fewer vertices, a contradiction. Hence, (D4) is satisfied and the theorem is proved. □
Let be the set of integers, and . Then, is a totally ordered set according to the lexicographic order.
Theorem 5.
Let be the family of the subdivision of some 3-connected graphs and for any . Then, is a -extensible system such that every graph G with contains a subgraph .
Proof.
By a theorem of Dirac [17], we see that every graph with minimum degree 3 contains a subdivision of , which belongs to . It suffices to verify that is a -extensible system. By the definition, (D1) and (D2) are clear. It suffices to verify (D3) and (D4). First, we prove the following claims.
Claim 1. For any graph with , if there exists a vertex and 3 internally disjoint -paths such that is as small as possible, where , then , and .
By the definition of , we see that , and thus . So, it suffices to show that . Suppose, now, that there exists a vertex cut and are two components of such that and since G is a subdivision of some 3-connected graph. By the choice of v, we see that . Let . Then, for some i. Then, there exists an -path P whose inner vertices have degree 2 in G such that and . Noting that , we see that , and thus , a contradiction. The claim is proved.
Claim 2. satisfies the condition (D3).
Let be the graph defined in (D3). By Claim 1, we may assume that contains at most 2 internally disjoint -paths. It follows that contains a vertex cut separating v from . Then, there exists an -path P whose inner vertices have degree 2 in G, such that . Let closed to for . Let be a graph obtained from G by replacing P with . Then, and since and . (D3) is satisfied.
(D4) remains to be verified. By Claim 1, let be the graph such that and . Let and be three internally disjoint -paths such that is as small as possible, where . By Claim 1, , and . Assume that is a -path for some .
Suppose, to the contrary, that (D4) is not true. Then, there exists a vertex such that
We consider the following two cases.
Case 1. There exists i such that .
In this case, G contains an -path P whose inner vertices have degree 2 in G for some such that for some i. Let Q be an -path with minimum length in such that and . Then, are three internally disjoint -paths contained in . By the choice of , we see that . Without loss of generality, we may assume that .
Let be an -path with minimum length such that and . Then, . By the choice of , we see that , and thus, the inequalities in (2) hold. Then, there exist and . If , then G contains a path with ends in and inner vertices not in . Hence, there exist and a -path in G with minimum length and disjoint with P. If , then let and . Thus, is a candidate of such that since is bipartite, a contradiction.
Case 2. For each i, .
In this case, . By the choice of , we see that for . Let . Then, by (2) and by the assumption of (D4), , , and contains disjoint path from to . Without loss of generality, we may assume that for , is a -path for some with minimum length such that ’s are pairwise disjoint. Without loss of generality, we may assume that .
If G contains an -path P with ends in and inner vertices not in such that there exist , then let Q be an -path with minimum length in such that . Then, by the choice of , are three internally disjoint -paths such that , and then since is bipartite and . This suggests , a contradiction to the choice of ’s. So, we may assume that .
Let , where . Then, , are 3 internally disjoint -paths of contained in . Noting that , there exists . Noting that is bipartite, . This suggests that , a contradiction to the assumption on ’s and . The proof is complete. □
By Theorems 3–5, we have the following corollary, which confirms Conjecture 2 for 2-connected graphs and 3-connected graphs.
Corollary 2.
Let be a positive integer and be a tree with bipartition . If G is a k-connected bipartite graph with , then G contains a k-redundant tree isomorphic to .
5. Conclusions
In this paper, we generalize the embedding lemma of arbitrary trees into bipartite graphs (see Lemma 1). As a corollary, we obtain a sufficient condition (Corollary 1) for a bipartite graph to contain an arbitrary tree. Together with Lemma 2, we obtain a crucial embedding lemma of a tree for a bipartite graph (Lemma 3). Then, we propose Conjecture 3 and prove that this implies a k-redundant tree (Theorem 3). Finally, we confirm Conjecture 3 for (Theorem 4) and (Theorem 5). These imply Conjecture 2 for 2-connected graphs and 3-connected graphs (Corollary 2). In fact, the degree condition of our results is slightly weaker than the degree condition of Conjecture 2. Based on these, we believe the following conjecture is also true, which is stronger than Conjecture 2.
Conjecture 4.
Let k be a positive integer and be a tree with bipartition . If G is a k-connected bipartite graph with bipartition such that for , then G contains a k-redundant tree isomorphic to .
If the above conjecture is true, then the degree condition is tight. In [8], the authors give the example to state that the minimum degree condition in Conjecture 2 is tight, where . The number of vertex in the example is fixed. We will give an example of Conjecture 4 and Conjecture 2 with an arbitrarily large number of vertices. Let be positive integers with . We shall define a graph as follows. Let , , be disjoint independent sets such that , for , , for each i, and
Then add all possible edges between and for and then add all possible edges between and and between and for , where . Let and . Then, is a k-connected bipartite graph with bipartition . It is easy to verify that and .
Let be a tree with bipartition such that and . If has a redundant tree or , then . If , then is a vertex cut of with at most vertices, a contradiction. If , then is a vertex cut of with at most vertices, a contradiction. If , then either or is a vertex cut of with at most vertices, a contradiction. This implies that the minimum degree condition of Conjecture 4 is tight.
Author Contributions
Y.H. performed the existence of embedding forests; Y.W. performed the 2-extensible system in 2-connected graphs; Q.L. performed the 3-extensible system in 3-connected graphs. All authors have read and agreed to the published version of the manuscript.
Funding
The work is partly supported by National Natural Science Foundation of China (Grant No. 11871015), Natural Science Foundation of Fujian Province of China (Grant No. 2021J01624), and Science & Technology Innovation Laboratory for Optoelectronic Information of China (Grant No. 2021ZR142).
Data Availability Statement
The original contributions presented in this study are included in the article. Further inquiries can be directed to the corresponding author.
Conflicts of Interest
The authors declare no conflicts of interest.
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