1. Introduction
The study of derivations on rings plays an important role and has many applications in other areas of mathematics, such as analysis, algebraic geometry, and the properties of algebraic systems. These applications are outside the scope of current study.
In this article, ℜ is an associative ring and is its center. A proper ideal of ℜ is prime if, for each pair of elements and in ℜ, the condition implies that either belongs to or belongs to . A ring ℜ is prime if and only if the set is a prime ideal of ℜ. A domain is a ring that does not have any non-zero divisors.
An additive mapping
is called a derivation if it satisfies the equation
for all
. An additive mapping
is a generalized derivation associated with the derivation
∂ if the equation
is satisfied for all
. For a fixed
, a mapping
such that
for any
is a derivation, which is called the inner derivation induced by
r. For a non-trivial example of a derivation on a non-commutative ring, the reader can refer to [
1] (Example 2.2).
The concept of a reverse derivation was initially defined by Herstein in [
2] when he proved that the prime ring ℜ is a commutative integral domain whenever the imposed derivation is a Jordan derivation. It was defined to be an additive mapping
that satisfies the equation
for any
. It can be noted that, in the case of Lie algebras, the concept of a reverse derivation is analogy to the concept of the antiderivation. According to this fact, several authors have studied the reverse derivation on algebra and subalgebra (see, for example [
3,
4,
5]). In ref. [
6], a study was conducted by Samman et al. on the reverse derivation of the semiprime ring.
In [
7], Aboubakr et al. discussed the correlation between a generalized reverse derivation and a generalized derivation on a semiprime ring. A generalized reverse derivation is defined as an additive map
that satisfies the equation
for all
and
in ℜ, where
∂ is a reverse derivation of ℜ. In the previous literature, there are numerous non-trivial examples of generalized reverse derivations on non-commutative rings. For example, please see reference [
8]. Furthermore, we will provide several concrete examples of generalized reverse derivations on non-commutative rings at the end of this article. It is known that every generalized reverse derivation is a reverse derivation. However, it is important to note that the converse is not always true. The concepts of generalized reverse derivations are related to generalizations of generalized derivations. It is clear that if ℜ is commutative, then both generalized reverse derivations and generalized derivations are the same. However, the converse may not be true in general, as shown in [
9] (Example 1).
In a study by Ibraheem [
10], it was proven that a prime ring is commutative, if
for all
belonging to a right ideal ℵ of a ring, given that the right ideal
. Here,
represents a generalized reverse derivation associated with a nonzero reverse derivation
∂. In a related study by Bulak et al. [
11], further exploration of generalized reverse derivations was conducted. The first part of the study focused on the commutativity of prime rings under the influence of differential identities provided by two generalized reverse derivations. The second part examined the relationships between
r-generalized reverse derivations and
l-generalized derivations, as well as
l-generalized reverse derivations and
r-generalized derivations, in a non-central square closed Lie ideal in a semiprime ring
Building upon prior findings, many researchers have achieved multiple outcomes regarding commutativity across diverse algebraic structures, including prime and semiprime rings. These outcomes have been attained through the utilization of suitable mappings, such as derivations, generalized derivations, and generalized reverse derivations, which adhere to specific identities when operating on suitable subsets of ℜ. The interested readers can be referred to [
1,
8,
9,
12].
Recently, in continuation of the above studies, several authors have discussed the situation of a quotient ring
and the way it behaves under derivation or generalized derivation that satisfies certain identities involving a prime ideal (for more details, refer to [
13,
14,
15,
16,
17,
18,
19,
20]).
In [
21], the concept of the generalized derivation
was replaced by a generalized reverse derivation, and the commutativity of
was studied whenever the proposed algebraic identities contained in a prime ideal were concerned with
.
The main aim of this article is to study further in this direction. More precisely, assuming that ℜ is an arbitrary ring that admits a generalized reverse derivation associated with a reverse derivation ∂, we prove that if satisfies certain identities involving a prime ideal , then the quotient ring is a commutative integral domain. In some cases, it comes out that the range of the generalized reverse derivation is in a prime ideal , i.e., . Moreover, some consequences as well as special cases are obtained. Examples that illustrate the necessity of the assumptions stated in our theorems are provided.
2. Preliminary Results
We begin this section by recalling the following basic concepts: Let
. We may define the commutator
as the difference between
and
, and the anticommutator
as the sum of
and
. The following identities will be used extensively throughout this article to facilitate access to the proofs of our theorems, which are satisfied for all
:
For the purpose of developing our proofs, we will present the following important remark and lemmas: The proof of Remark 1 is based on the fact that a group cannot be written as the set-theoretic union of its two proper subsets, and the proof of Lemma 1 can be found in [
20].
Remark 1. Let ρ be a prime ideal of an arbitrary ring and let ℵ be an additive subgroup of ℜ. Let be additive functions such that for all . Then, either for all , or for all .
Lemma 1. ([
20], Lemma 1.2).
Let ℜ be a ring and let ρ be a prime ideal of ℜ. If for all , then is a commutative integral domain. The following lemma is an expansion of ([
21], Lemma 2.5).
Lemma 2. Let ρ be a prime ideal of an arbitrary ring ℜ. If ℜ admits a generalized reverse derivation ϑ associated with a reverse derivation ∂ such that for all , then either or is a commutative integral domain.
Proof. From the hypothesis, we have
By linearizing Equation
, which simply means replacing
by
, we obtain
By replacing
by
in
and utilizing
, we get
Setting in and using again, we obtain . Replacing by in the previous equation and using it, we get for all Placing instead of in the previous equation and using it, we get for all In other words, for all Since is prime, considering Remark 1, we find that either or for all If for all , we deduce that is a commutative integral domain, by Lemma 1. In the alternative scenario, we have for all . Linearizing the previous expression, we obtain for all By replacing by in the previous equation and using it we find, after appropriate treatment, that for all Again, placing instead of in the last relation and using it, we find for all . This results in for all By employing the assumption that is prime along with Remark 1, we conclude that either or for all Therefore, we can infer that the first case leads to , and for the second case, we use Lemma 1 to obtain that is a commutative integral domain. □
Corollary 1. Let ρ be a prime ideal of an arbitrary ring ℜ. If ℜ admits a reverse derivation ∂, such that for all , then either or is a commutative integral domain. Moreover, if , then either ℜ is commutative or ∂ turns out to be zero.
Remark 2. In Lemma 2, if ℜ is commutative, then ϑ becomes a generalized derivation, and thus we obtain ([20], Proposition 1.3). 3. Main Results
In [
14] (Theorem 2.5), Bouchannafa et al. proved that either the ring
is a commutative integral domain or
is a subset of
, whenever the ring ℜ has a generalized derivation
such that
belongs to the center
for all
and
in ℜ, where
is a prime ideal of ℜ. In the next theorem, our objective is to achieve the same outcome by substituting the generalized derivation
from the previous theorem with the notion of a generalized reverse derivation, which is associated with a reverse derivation
∂ that fulfills the condition
, for all
.
Theorem 1. Consider a prime ideal ρ in a ring ℜ, where ℜ can be any ring. If ℜ admits a generalized reverse derivation ϑ that is associated with a reverse derivation ∂, and satisfies the condition for all ξ and η in ℜ, then either is a subset of ρ or the quotient ring is a commutative integral domain.
Proof. Placing
instead of
in (
4) yields
By multiplying (
4) by
from the right and comparing it with (
5), we obtain
The last equation is simplified as follows: , where and are elements of ℜ. Given that and is a prime, the last equation implies that belongs to for every in ℜ. Therefore, according to Corollary 1, either is a commutative integral domain or is a subset of . □
When ℜ is a prime ring and , respectively, the following corollaries can be immediately obtained from Theorem 1.
Corollary 2. Consider a ring ℜ, which is prime. If ℜ admits a generalized reverse derivation ϑ associated with a reverse derivation ∂, satisfying the equation for all , then either ∂ is equal to zero or ℜ is a commutative ring.
Corollary 3. Consider a prime ideal ρ in a ring ℜ, where ℜ can be any ring. If ℜ admits a reverse derivation ∂, and satisfies the condition for all ξ and η in ℜ, then either is a subset of ρ or the quotient ring is a commutative integral domain.
Theorem 2. Consider a prime ideal ρ of a ring ℜ. If ℜ admits a generalized reverse derivation ϑ associated with a reverse derivation ∂, such that , then either or is a commutative integral domain of
Proof. The given identity states that
Replacing
by
in (
6), gives
By multiplying (
6) by
from the right-hand side and comparing it with (
7), we obtain
Now, we discuss the following two cases:
Case (i): If , then becomes . Following the same arguments as above, we find either is a subset of or is a commutative integral domain.
Case (ii): If
, then replacing
by
in (
8) results in
Now, multiplying (
8) by
from the left-hand side and comparing with (
9), yields
for all
Our assumption that
leads to
for all
, and hence
for all
. Thus, the primeness of
together with Remark 1 lead to either
for all
or
. If
is not a subset of
, then
belongs to
for every elements
and
in ℜ. Using Lemma 1 shows that the quotient ring
is a commutative integral domain. By utilizing the commutativity of
with the identity (
8), we can easily deduce that
belongs to
for all
and
in ℜ. The statement
holds for all
because
. This implies that
for all
, due to the commutativity of ℜ. Furthermore, the previous expression is equivalent to
for all
, which may be written as
for all
However, our hypothesis that
and
is a prime ideal of ℜ forces
, which eventually implies that
. This contradicts our basic hypothesis about
being a proper ideal of ℜ. Therefore, we can deduce that
. □
If the ring ℜ imposed in Theorem 2 is prime, meaning , then the following corollary results immediately:
Corollary 4. Consider a prime ring ℜ. If ℜ admits a generalized reverse derivation ϑ associated with a reverse derivation ∂ such that for all ξ and η in ℜ, then either or ℜ is commutative of
When we consider in Theorem 2, the following corollary is immediately obtained.
Corollary 5. Consider a prime ideal ρ of a ring ℜ. If ℜ admits a reverse derivation ∂ such that , then either or is a commutative integral domain of
In ref. [
20], Rehman et al. established a result stating that if ℜ is a ring and
is a prime ideal of it, such that ℜ admits a generalized derivation
associated with
∂ and meets the condition
for all
, then either
or
is a commutative integral domain.
This result prompts us to investigate the properties of the ring when we replace the assumption that is a generalized derivation by a generalized reverse derivation associated with a reverse derivation ∂. For this purpose, we introduce the following theorem:
Theorem 3. Consider ρ as a prime ideal in any ring ℜ. If ℜ admits a generalized reverse derivation ϑ which is associated with a reverse derivation ∂ and satisfies the condition for all ξ and η in ℜ, then is a subset of ρ and the quotient ring is a commutative integral domain.
Proof. The given identity states that
By replacing
with
in (
10), we obtain
Multiplying (
10) by
on the right gives
By comparing Equations (
11) and (
12), we obtain
Again, by replacing
by
in the previous equation, we obtain
Multiplying (
13) from the left by
and comparing it with (
14) yield
It follows that Hence, the primeness of together with Remark 1 forces that either or for any . If , then, according to Lemma 2, is a commutative integral domain or .
Let
be a commutative integral domain. Then, (
10) can be reduced to
for all
That is
. Now, we replace
by
in the previous expression and use it to conclude that
. On the other hand, if we assume
, then (
13) can be simplified to
By setting in the previous equation and using it, we can easily find Replacing by in the last relation and using it, we obtain By replacing by in the last expression and using it, we deduce that for all . The primeness of implies that for all . Therefore, once again, is a commutative integral domain, by using Lemma 1.
By applying similar arguments to those shown earlier, with only slight adjustments, the same result can be obtained for the case , for all and in ℜ. □
In Theorem 3, if ℜ is assumed to be prime, the following corollary can be immediately obtained.
Corollary 6. Consider ℜ is a prime ring admits a generalized reverse derivation ϑ, which is associated with a nonzero reverse derivation ∂ and satisfies the condition for all ξ and η in ℜ, then the ring ℜ a commutative.
By setting in Theorem 3, we promptly obtain the subsequent corollary.
Corollary 7. Consider a prime ideal ρ in any ring ℜ. Suppose that ℜ admits a reverse derivation d such that belongs to ρ for all . In this case, is a subset of ρ and is a commutative integral domain.
Proof. The proof can be directly obtained from Equation (
10) in Theorem 3, by setting
and following the same arguments and techniques of its proof. □
Theorem 4. Let ρ be a prime ideal in any ring ℜ. If ℜ admits a generalized reverse derivation ϑ that is associated with a reverse derivation ∂ and satisfies the condition for all , then
Proof. The given assumption states that
Replacing
by
in (
16) gives
Multiplying Equation (
16) by
from the right and comparing it with (
17) yield
That is,
By using the primeness of
together with Remark 1, we get either
for all
or
for all
. If
for all
, (
16) can be reduced to
for all
. Hence, we have
On the other hand, for
we substitute
in the place of
in (
18) to obtain
. Multiplying (
18) by
from the right and comparing it with the last relation, we get
Now, placing
instead of
in Equation (
19), we get
Left-multiplying (
19) by
and comparing it with (
20) yields
Again, replacing
by
in the last equation and using it gives
for all
Since
is a prime ideal, either
for all
or
. If
for all
then it implies that
which contradicts the fact that
is a proper ideal. If
for all
, then, according to Lemma 1,
is a commutative integral domain. In this case, (
19) can be simplified to
, which is leading to
. So, we can conclude, as above, that
By following the exact techniques as described previously, we can prove the same conclusion in the case of the identity for all . □
By equating
to
∂ in the prior theorem, we can obtain the following conclusion as a similar version of ([
16], Theorem 4(1)).
Corollary 8. Let ρ be a prime ideal in any ring ℜ. If ℜ admits a reverse derivation ∂ such that for all , then
Corollary 9. Let ℜ be a prime ring that admits a generalized reverse derivation ϑ that is associated with a reverse derivation ∂ and satisfies the condition for all , then .
Theorem 5. Consider ρ as a prime ideal in any ring ℜ. If ℜ admits a generalized reverse derivation ϑ, which is associated with a reverse derivation ∂, and satisfies the condition for all , then .
Proof. The given assumption states that
We replace
by
in (
21) and use it to obtain
If we replace
by
in the previous equation, we obtain
for all
By left multiplying Equation (
22) by
and comparing it with the last equation, we find
This implies that
In other words,
for all
. Using the primeness of
together with Remark 1 yield either
for all
or
In the second case, (
21), becomes
and therefore,
. For the case of
for all
, we have, in particular, that
for all
. We use Corollary 1 to obtain that either
is a commutative integral domain or
. If
is a commutative integral domain, then (
22) can be rewritten as
That is,
Again, using the primeness of
together with Remark 1 give that either
for all
or
. When
, we replace
by
in the last relation and use it to get
. For the other case, the commutativity of
leads to
and hence,
. Thus, (
21) becomes
. Therefore,
.
By following the exact techniques as described previously, we can prove the same conclusion for the case of the identity for all . □
Corollary 10. Consider ℜ is a prime ring that admits a generalized reverse derivation ϑ associated with a reverse derivation ∂ and satisfies the condition for all , then .
Corollary 11. Consider ρ as a prime ideal in any ring ℜ. If ℜ admits a reverse derivation ∂ and satisfies the condition for all , then .
In [
20] (Theorem 1.5(iii)), Rehman et al. showed that the quotient ring
is a commutative integral domain, where
is a prime ideal of ℜ, if ℜ admits a generalized derivation
associated with a derivation
∂ that satisfies
.
The following theorem aims to generalize the above identity to for every and prove that is a subset of when and the imposed is a generalized reverse derivation associated with a reverse derivation ∂.
Theorem 6. Consider a prime ideal ρ in a ring ℜ with a characteristic not equal to 2. If ℜ admits a generalized reverse derivation ϑ that is associated with a reverse derivation ∂, and if for all ξ and η in ℜ, then is a subset of ρ.
Proof. The given hypothesis states that
By replacing
with
in (
23), we obtain
Now, by multiplying Equation (
23) by
from the right and comparing it with (
24), we obtain
That is,
Hence, the condition of
being prime, together with Remark (1), forces either
or
for all
. Let us consider the first case and replace
with
. This yields
for all
By multiplying the first equation by
from the right and comparing it with the second equation, we obtain
for all
, which in turn means that
for every
. The basic assumption
leads to
for every
. That is,
. As
and
is prime, we get
for any
. Thus, we deduce that
. In the second case, we observe that
belongs to
for every
, indicating that
. So both cases lead to
, which reduces (
23) to
Replacing
by
in the last relation, we get
Therefore, we have
for both cases as required. □
As an immediate consequent of the above theorem, we have the following corollary when the imposed ring ℜ is prime.
Corollary 12. Consider a prime ring ℜ with a characteristic that is not equal to 2. If ℜ admits a generalized reverse derivation ϑ associated with a reverse derivation ∂, satisfying the equation for all ξ and η in ℜ, then ϑ turns out to be zero.
Next, we will explore some counterexamples that illustrate the necessity of assuming that is prime in the hypotheses of our theorems.
Example 1. Consider the ring of integers and let , . Define by . Thus, it is evident that ℜ is a ring, ρ is an ideal of ℜ, and ϑ is a generalized reverse derivation associated with the reverse derivation ∂ that satisfies , , and for all . However, is non-commutative, , and . Moreover, ρ is not a prime ideal of ℜ since , but neither nor ; hence, ρ is not prime ideal of ℜ. Therefore, the assumption that ρ is prime in Theorems 1–3 and 6 cannot be omitted.
Example 2. Let , where is the complex number ring. Let . Define as follows: Thus, it is evident that ℜ is a ring, ρ is an ideal of ℜ, and ϑ is a generalized reverse derivation associated with the reverse derivation ∂ that satisfies , , , , and for all . However, is non-commutative and . Moreover, ρ is not a prime ideal of ℜ since , but and . Therefore, assumption that ρ is prime in Theorems 1–6 cannot be omitted.
Example 3. Consider the ring of integers and let . Define by . Thus, it is evident that ℜ is a ring, ρ is an ideal of ℜ, and ϑ is a generalized reverse derivation associated with the reverse derivation ∂ that satisfies the following identities for all : , , , for all . However, is non-commutative and . Moreover, ρ is not a prime ideal of ℜ since , but and . Therefore, the assumption that ρ is prime in Theorems 1–3 and 6 cannot be omitted.
Example 4. In Example 3, one can note that and hold for all though . This emphasizes the necessity of primeness of ρ.