The Existence Problems of Solutions for a Class of Differential Variational–Hemivariational Inequality Problems
Abstract
1. Introduction
2. Preliminaries
- (i)
- Monotone, if
- (ii)
- Strongly monotone, if there exists , such that
- (iii)
- Inverse strongly monotone, if there exists , such that
- (iv)
- Lipschitz continuous, if there exists , such that
- (v)
- Bounded, if it is maps bounded sets in into bounded sets of
- (vi)
- Pseudomonotone, if is bounded and for every sequence converging weakly to , such thatwe have
- (vii)
- Hemicontinuous, if for all , the functionis continuous on ,
- (viii)
- Demicontinuous, if implies
- (i)
- For each , there exists a sequence such that for each and .
- (ii)
- For each sequence , such that for each and weakly in , we have .
- (1)
- (2)
- For each , the function is positively homogeneous and subadditive, i.e.,and
3. Main Results
- (1)
- Let and consider the function defined byUnder the hypotheses (17), (19) and Lemma 1, it is simple to see that is pseudomonotone, inversely strongly monotone and Lipschitz continuous with respect to both arguments with constants and , respectively. Using Theorem 1 with and instead of and , respectively, we determine that there exists a unique solution to (13).
- (2)
- Fixing , we consider the auxiliary problem of finding a function , such thatUtilizing a standard arguments, we see that Equation (23) has a unique solutionThe rest of the proof is now divided into five steps. Here, assume that and satisfies (18)(c),(d).
- Step (i)
- We assert that for any , there exists and a subsequence of , again denoted by , such thatTo fix and . We put in (23) to obtainNext, from (8) and Lemma 2(1), we getSince depends on but does not depend on n, this implies that the sequence is bounded in . Hence, the reflexivity of implies that there exists an element such that, passing to a subsequence if necessary, we find thatSince , therefore, the elimination of (18)(b) and Definition 5(ii) reveals that
- Step (ii)
- We prove that for allLet and . Then, Definition 5(i) assures us that there is a sequence such that for each and as . We will utilize (23) and similar estimates from the previous step to getSince , are bounded sequences and is a bounded operator. Therefore, there exists a constant which does not depend on n, such thatHence,Again, since the sequence is bounded in and , we have thatTherefore, (29) yieldsMoreover, the regularity of allows us to take in (30) to getHowever, the assumption (17) and Lemma 1 ensures that is a pseudomonotone operator. From (31) and the pseudomonotonicity of , we haveTherefore, (30) yieldsSince , therefore, from (32), we derive thatNow, combining (33) with (18)(c) to getHence, using (18)(d) to obtain the regularity
- Step (iii)
- We now prove that , for allLet and . We use Equation (23) and inclusion to see thatand using (18)(c), we haveThen, we use the lower semicontinuity of concerning the second argument and the hypothesis (21) to find thatAgain, we put in (36) to obtain thatTogether with the pseudomonotonicity of operator , this inequality implies thatNow, adding (36) and (38) to getTherefore,We take in (1)(b) and in (39), then we add the resulting inequalities to see thatThen, we use assumptions (5) and (8)(b) to find thatThis inequality, together with (10), implies thatMeanwhile, each weakly convergent subsequence of the sequence converges weakly to as . Furthermore, since the sequence is bounded, it imply that the whole sequence converges weakly to .
- Step (iv)
- We now prove that
- Step (v)
- Finally, we prove thatLet and . We write (1)(b) with . Then, we take (13)(b) with and add the resulting inequalities to see thatTherefore, (6)–(8) and the monotonicity of the operator yieldThereby,Hence,Therefore, from (10) and (40), we derive thatwhich show that there exist two constants, and , such thatMeanwhile, using (3), (4), (12), (14), and (41), we find that there exist two constants, and such thatAs a result of Gronwall inequality, it follows that there exists a constant , such thatThis inequality, the convergence , valid for each , and the Lebesgue-dominated convergence theorem (see [13], Theorem 1.65) imply thatTherefore, we conclude thatUsing this convergence, we havedemonstrated in Step (iv), and from (41), we derive thatand proof is completed.
4. A Mathematical Model for a Viscoelastic Rod in Unilateral Contact
5. Conclusions
Author Contributions
Funding
Data Availability Statement
Acknowledgments
Conflicts of Interest
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Chang, S.-S.; Salahuddin; Ahmadini, A.A.H.; Wang, L.; Wang, G. The Existence Problems of Solutions for a Class of Differential Variational–Hemivariational Inequality Problems. Mathematics 2023, 11, 2066. https://doi.org/10.3390/math11092066
Chang S-S, Salahuddin, Ahmadini AAH, Wang L, Wang G. The Existence Problems of Solutions for a Class of Differential Variational–Hemivariational Inequality Problems. Mathematics. 2023; 11(9):2066. https://doi.org/10.3390/math11092066
Chicago/Turabian StyleChang, Shih-Sen, Salahuddin, A. A. H. Ahmadini, Lin Wang, and Gang Wang. 2023. "The Existence Problems of Solutions for a Class of Differential Variational–Hemivariational Inequality Problems" Mathematics 11, no. 9: 2066. https://doi.org/10.3390/math11092066
APA StyleChang, S.-S., Salahuddin, Ahmadini, A. A. H., Wang, L., & Wang, G. (2023). The Existence Problems of Solutions for a Class of Differential Variational–Hemivariational Inequality Problems. Mathematics, 11(9), 2066. https://doi.org/10.3390/math11092066

