The mechanical properties which include stress–strain relationship, energy absorption, the residual force loss ratio, Young’s modulus, the Weibull modulus for varying strands and varying gauge lengths are discussed in this section.
4.2.1. Results of the Fibers by Varying Strands
Many samples of new and old fibers with one, three and five strands were considered for this study. The stress–strain relationship of these fibers was discussed based on the successful results of three samples under each category. For single-strand fiber samples (old and new), the maximum stress is calculated by dividing the ultimate strength of the single fiber with the net cross-sectional area of the corresponding fiber. For multi-strand fibers (old and new), the maximum stress is calculated by dividing the ultimate strength of the fiber which fails first with the net cross-sectional area of the corresponding fiber, as shown in
Table 4. For all the above samples, the corresponding strain is also noted given in (
Supplementary Table S1).
- (a)
Tensile Strength of the Fiber with One Strand
The typical stress–strain curve of the fiber sample (new and old) with one strand is shown in
Figure 10a. From the curve, a drop in stress was observed in three zones, namely zone 1 (elasticity outer), zone 2 (outer layer), and zone 3 (core fiber), which is due to the successive failure of three layers in the fiber. The drop in zone 1 is the failure of the elasticity outer layer, which fails at a stress approximately ranging from 200 to 350 MPa, with a corresponding approximate strain of 0.125. The drop in zone 2 is the failure of the outer layer, which fails at a stress of approximately ranging from 305 to 550 MPa, with a corresponding approximate strain of 0.16. The drop in zone 3 is the failure of the core fiber, which fails at a stress approximately ranging from 420 to 710 MPa, with a corresponding approximate strain of 0.225. Beyond this, a sudden drop to zero stress is observed. For new fibers, the average maximum stress is 654.76 MPa (standard deviation of 54.44 MPa) and its corresponding average strain is 0.21, which represents the ductile behavior of the fibers. However, for old fibers, the average maximum stress is 490.77 MPa (standard deviation of 47.66 MPa) and its corresponding average strain is 0.19. A decrease of 25% in the maximum stress and a lower difference in elongation, i.e., approximately 2%, is observed between the new and old fibers. This variation is noticed as the old fibers are stressed within the elastic limit only. The curve of stress–strain is nonlinear between the subsequent zones, due to the development of plastic strain.
The energy absorption (EA) of all fibers is calculated using Origin graphing software and the typical results for sample N11 are shown in
Figure 10b. For new fibers. the average EA is 63.16 N.mm/mm
3, with a standard deviation of 9.036 N.mm/mm
3; and for old fibers, the average EA is 39.95 N.mm/mm
3, with a standard deviation of 1.33 N.mm/mm
3. As the stress and strain values of old fibers are lower than that of new fibers, a reduction of 37.63% in EA is observed in old fibers [
30].
- (b)
Tensile Strength of the Fiber with Three Strands
The typical stress–strain curve of the fiber sample (new and old) with varying three strands is shown in
Figure 10c. Like single-strand fibers, a drop in stress is observed in three zones, namely zone 1 (first strand), zone 2 (second strand), and zone 3 (third strand), which is due to the successive failure of individual fibers in three strands. The maximum stress of three fibers is obtained by dividing the ultimate stress of the fiber, which fails in zone 1, to the cross-sectional area of a single fiber. For new fibers, the average maximum stress of three fibers is 1561.93 MPa (standard deviation of 87.91 MPa) and its corresponding average strain is 0.18. However, for old fibers, the average maximum stress of three fibers is 1262.53 MPa (standard deviation of 208.23 MPa) and its corresponding average strain is 0.16. As the peak load is shared among all the fibers, the maximum stress of a single fiber is calculated by dividing the maximum average stress of all fibers with the number of strands. The EA is similarly calculated from the stress–strain curve. For new fibers, the average EA is 55.34 N.mm/mm
3 with a standard deviation of 3.60 N.mm/mm
3, and for old fibers, the average EA is 33.65 N.mm/mm
3 with a standard deviation of 3.09 N.mm/mm
3. As the stress and strain values of old fibers are lower than that of new fibers, a reduction of 39.19% in EA is observed in old fibers.
- (c)
Tensile Strength of the Fibers with Five Strands
The typical stress–strain curve of the fiber sample (new and old) with varying five strand is shown in
Figure 10d. Like three-strand fibers, a drop in stress is observed in five zones, namely zone 1 (first strand), zone 2 (second strand), zone 3 (third strand), zone 4 (fourth strand) and zone 5 (fifth strand), which is due to successive failure of individual fibers in five strands. The maximum stress of five fibers is obtained by dividing the ultimate stress of the fiber which fails in zone 1 to the cross-sectional area of a single fiber. For new fibers, the average maximum stress of five fibers is 2127.19 MPa (standard deviation of 45.31 Mpa) and its corresponding average strain is 0.19. However, for old fibers, the average maximum stress of three fibers is 1738.95 Mpa (standard deviation of 109.01 Mpa) and its corresponding average strain is 0.16. As the peak load is shared among all the fibers, the maximum stress of a single fiber is calculated by dividing the maximum average stress of all fibers with the number of strands as given in
Table 5. The energy absorption is similarly calculated from the stress–strain curve. For new fibers, the EA absorption is 68.04 N.mm/mm
3, with a standard deviation of 12.56 N.mm/mm
3, and for old fibers, the average EA is 40.09 N.mm/mm
3, with a standard deviation of 2.78 N.mm/mm
3. As the stress and strain values of old fibers are lower than that of new fibers, a reduction of 41.07% in EA is observed in old fibers.
- (d)
Residual Force loss ratio
In multi-strand fibers, the ultimate force is reduced as the individual fibers show successive failure at different stages. A loss of force is observed due to the distribution of ultimate stress among the fibers in the strand. Thus, a better understanding of force distribution in fibers is gained by calculating the residual force loss ratio using the Equation (1) [
48],
The ultimate force (F
u) and the force at different stages of break (F
ur) are given in
Table 5. For new fiber samples with three strands, the residual force loss percentage was 0, 35.22, 68.40, and 100.00; and for old fiber samples with three strands, the residual force loss percentage was 0, 32.48, 64.45, and 100. Similarly for samples with five strands, the residual force loss percentage of 0, 20.90, 36.44, 42.79, 61.72, 100.00 for new fibers and 0, 27.7, 40.40, 58.95, 63.88, 100 for old fibers were observed as shown in
Figure 11. This loss in force is due to the successive failure of individual strands. From the results in
Table 6, for multi-strand fibers (five in numbers), a minimum % of difference in observed in the residual force loss ratio as 6.35 and 4.93, which is due to the sudden failure of successive strands within a limited period.
4.2.4. Young’s Modulus of Fiber
According to the ASTM C1557-03 standard of testing procedure, if strain is not directly measurable for Young’s modulus, then the relationship given in Equation (2) is considered [
31].
—Total measured displacement,
F—Failure load,
Cs—System compliance,
—Gauge length,
E—Young’s modulus, and
A—Cross-sectional area.
The linear regression of varying gauge lengths is plotted for ΔL/F vs.
lₒ/A as shown in Equation (1). The slope of the line gives the constant E and the intercept to the y-axis gives the system compliance (Cs).
Figure 14a,b shows the slope 1 in E equation of new and old fibers as y = 0.0002x + 0.026 and y = 0.0002x + 0.031, respectively. From the equation, the Young’s modulus of new and old fibers is calculated as E = 4870.00 MPa and E = 4843.50 MPa, respectively. Thus, not much difference is observed between the Young’s modulus of old and new fibers. Generally, the Young’s modulus of virgin nylon 6,6 lies between 1000 and 3000 MPa [
49]. Additionally, the fiber used for this study is found to have a Young’s modulus of 5000 MPa, which is observed to have higher stiffness than any other commercial nylon fibers.
4.2.5. Validation of Results by Weibull Distribution
The statistical behavior of the tensile strength of the fiber is studied by Weibull distribution. From the Weibull analysis, the Weibull modulus (m) shows the probability of variation [
50]. The probability of Weibull analysis is given by Equation (3).
where σ is the tensile strength of the fiber, m is the Weibull modulus, and σₒ is the Weibull reference strength. The fiber strength ranking for the i
th value from the number of the fibers tested (N) is given by Equation (4).
P(σ)
i is the probability corresponding to the i
th value. Substituting Equation (4) in Equation (3) gives Equation (5).
The Weibull model is analyzed by
vs. ln(σ), as shown in
Figure 15a,b, which yields the Weibull parameters (m) and (σₒ).
Figure 15a shows the Weibull modulus for the new fibers in varying gauge lengths. The equation of the slope y = ax + b yields a = m, which is the Weibull modulus and the Weibull reference strength, σₒ = exp(−b/a).
Generally, in measuring the Weibull modulus, the higher the (m) value, the lower the strength variability; and a Weibull modulus greater than 3 gives good results with lower variability [
50,
51].
Table 6 gives the Weibull parameters for varying gauge lengths of the fibers, where the Weibull modulus (m) for both old and new fibers varies between 5.27 and 9.17. Hence, the results of tensile strength exhibit lower variability. The difference in percentage between the estimated Weibull reference strength (σₒ) and the experimental average tensile strength (σ
Avg) is approximately 6%. From
Figure 15a,b, a linear trend for new and old fibers is observed, which indicates an increase in the Weibull modulus with a decrease in gauge length [
52].