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Computer Sciences & Mathematics Forum
  • Proceeding Paper
  • Open Access

28 April 2023

Generalized Integral Transform and Fractional Calculus Operators Involving a Generalized Mittag-Leffler (ML)-Type Function †

Division of Mathematics, School of Advanced Sciences & Languages, VIT Bhopal University, Kothrikalan, Sehore 466114, India
Presented at the 1st International Online Conference on Mathematics and Applications, 1–15 May 2023; Available online: https://iocma2023.sciforum.net/.
This article belongs to the Proceedings The 1st International Online Conference on Mathematics and Applications

Abstract

In this paper, we consider a generalized Mittag-Leffler (ML)-type function and establish several integral formulas involving Jacobi and related transforms. We also establish some of the composition of generalized fractional derivative formulas associated with the generalized Mittag-Leffler (ML)-type function. Additionally, certain special cases of generalized fractional derivative formulas involving the Mittag-Leffler (ML)-type function are corollarily presented.

1. Introduction

In 1903, Gösta Mittag-Leffler [1] introduced the Mittag-Leffler (ML) function, which is represented by
E ν ( z ) = k = 0 z k Γ ( ν k + 1 ) , ( ν ) > 0
Wiman [2] generalized the Mittag-Leffler (ML) function (1) in 1905 and introduced the following definition:
E ν , κ ( z ) = k = 0 z k Γ ( ν k + κ ) ,
where ν , κ C with ( ν ) > 0 , ( κ ) > 0 .
Later, in 1971, Prabhakar [3] introduced the three-parameter Mittag-Leffler (ML) function, which can be defined as,
E ν , κ γ ( z ) = k = 0 ( γ ) k Γ ( ν k + κ ) z k k ! ,
where κ , ν , γ C with ( ν ) > 0 , ( κ ) > 0 , ( γ ) > 0 .
Wright [4] introduced an extension of the generalized hypergeometric function called the Fox–Wright function, which can be expressed in the following form:
f Ψ g ( z ) = f Ψ g ( m a , M a ) 1 , f ( n b , N b ) 1 , g z = k = 0 Γ ( m 1 + M 1 k ) Γ ( m f + M f k ) Γ ( n 1 + N 1 k ) Γ ( n g + N g k ) z k k ! ,
where m a , n b C , a = 1 , , f ; b = 1 , , g , and the coefficients M 1 , , M f R + and N 1 , , N g R + satisfying the condition
b = 1 g N b a = 1 f M a > 1 .
In particular, when M a = N b = 1 , (4) reduces to
f Ψ g ( m 1 , 1 ) , , ( m f , 1 ) ( n 1 , 1 ) , , ( n g , 1 ) z = a = 1 f Γ ( m a ) b = 1 g Γ ( n b ) f F g m 1 , , m f n 1 , , n g z ,
where f F g ( · ) is the well-known generalized hypergeometric function [5].
In this work, we define a Mittag-Leffler (ML)-type confluent hypergeometric function introduced by Ghanim and Al-Janaby [6]:
M ν , κ η , γ ( z ) = k = 0 Γ ( κ ) Γ ( η k + γ ) Γ ( γ ) Γ ( ν k + κ ) z k k ! ,
where κ , η , ν , γ C , such that ( ν ) > 0 . It is worth pointing out that series representation of Equation (7) returns a variety of connections with special functions, including a confluent hypergeometric function and generalized Mittag-Leffler (ML) functions (1)–(3).

3. Fractional Derivative Formulas

In this section, we develop a variety of fractional derivative formulas involving the Mittag-Leffler (ML)-type confluent hypergeometric function. In order to achieve this, we will review the given pairs of generalized left- and right-sided fractional derivative operator D 0 + δ , χ , ρ and D δ , χ , ρ :
Definition 1. 
Let δ , χ , ρ C . Then, the left-sided fractional integral operator I 0 + δ , χ , ρ and corresponding left-sided fractional derivative operator D 0 + δ , χ , ρ can be represented as [12],
I 0 + δ , χ , ρ f ( x ) = x δ χ Γ ( δ ) 0 x ( x r ) δ 1 2 F 1 δ + χ , ρ ; δ ; 1 r x f ( r ) d r , x > 0 ,
where ( δ ) > 0 and
D 0 + δ , χ , ρ f ( x ) = I 0 + δ , χ , δ + ρ f ( x ) = d d x m I 0 + δ + ρ , χ ρ , δ + ρ m f ( x ) ,
where m = [ ( δ ) ] + 1 ; ( δ ) 0 and [ x ] represents the greatest integer belonging to x R .
Remark 1. 
On substituting χ = δ , χ = 0 , operator (19) coincides with the familiar “Riemann–Liouville ( RL ) fractional derivative operator R L D 0 + δ ” and the “left-sided Erdélyi-Kobar ( EK ) fractional derivative operator E K D 0 + δ , ρ ”, as given below (see [12]):
D 0 + δ , δ , ρ f ( x ) = RL D 0 + δ f ( x ) = d d x m 1 Γ ( m δ ) 0 x ( x r ) m δ 1 f ( r ) d r ,
and
D 0 + δ , 0 , ρ f ( x ) = EK D 0 + δ , ρ f ( x ) = x ρ d d x m 1 Γ ( m δ ) 0 x ( x r ) m δ 1 r δ + ρ f ( r ) d r ,
where ( δ ) 0 , m = [ ( δ ) ] + 1 ; x > 0 .
Definition 2. 
Let x > 0 , δ , χ , ρ C . Then, the right-sided fractional integral operator I δ , χ , ρ and corresponding right-sided fractional derivative operator D δ , χ , ρ can be defined as [12],
I δ , χ , ρ f ( x ) = 1 Γ ( δ ) x ( r x ) δ 1 r δ χ 2 F 1 δ + χ , ρ ; δ ; 1 x r f ( r ) d r , x > 0 ,
where ( δ ) > 0 and
D δ , χ , ρ f ( x ) = I δ , χ , δ + ρ f ( x ) = d d x m I 0 + δ + ρ , χ ρ , δ + ρ m f ( x ) ,
where m = [ ( δ ) ] + 1 ; ( δ ) 0 .
Remark 2. 
On substituting χ = δ , χ = 0 , operator (23) coincides with the “Weyl fractional derivative operator W D δ ” and the “right-sided Erdélyi-Kobar ( EK ) fractional derivative operator E K D δ , ρ ”, as given below (see [12]):
D δ , δ , ρ f ( x ) = W D δ f ( x ) = d d x m 1 Γ ( m δ ) x ( r x ) m δ 1 f ( r ) d r ,
and
D δ , 0 , ρ f ( x ) = EK D δ , ρ f ( x ) = x δ + ρ d d x m 1 Γ ( m δ ) x ( r x ) m δ 1 r ρ f ( r ) d r ,
where ( δ ) 0 , m = [ ( δ ) ] + 1 ; x > 0 .
Lemma 2. 
Let δ , χ , ρ , κ C with ( δ ) 0 , x > 0 . Then, we have the following fractional derivative formulas [12]:
D 0 + δ , χ , ρ r κ 1 ( x ) = Γ ( κ ) Γ ( κ + δ + χ + ρ ) Γ ( κ + χ ) Γ ( κ + ρ ) x κ + χ 1 ,
where ( κ ) > min 0 , ( δ + χ + ρ ) and
D δ , χ , ρ r κ 1 ( x ) = Γ ( 1 χ κ ) Γ ( 1 κ + δ + ρ ) Γ ( 1 κ ) Γ ( 1 κ + ρ χ ) x κ + χ 1 ,
where ( κ ) < 1 + min ( χ + ρ ) , ( δ + ρ ) .
Theorem 2. 
Let δ , ν , χ , η ρ , γ , κ C , such that ( δ ) 0 , ( ν ) > 0 and x > 0 . Then, the following left-sided fractional derivative formula is valid:
D 0 + δ , χ , ρ r κ 1 M ν , κ η , γ ( u r ν ) ( x ) = x κ + χ 1 Γ ( κ ) Γ ( γ ) 2 Ψ 2 ( γ , η ) , ( κ + δ + χ + ρ , ν ) ( κ + χ , ν ) , ( κ + ρ , ν ) u x ν ,
where ( κ ) > min 0 , ( δ + χ + ρ )
Proof. 
Using (7), we have
D 0 + δ , χ , ρ r κ 1 M ν , κ η , γ ( u r ν ) ( x ) = n = 0 Γ ( κ ) Γ ( η n + γ ) Γ ( γ ) Γ ( ν n + κ ) u n n ! × D 0 + δ , χ , ρ r ν n + κ 1 ( x ) .
Using (26), this proves Theorem 2. □
Corollary 3. 
If the assumptions stated in Theorem 2 are true, and substituting χ = δ and χ = 0 , the following fractional derivative formulas are valid:
RL D 0 + δ r κ 1 M ν , κ η , γ ( u r ν ) ( x ) = x κ δ 1 Γ ( κ ) Γ ( κ δ ) M ν , κ δ η , γ ( u x ν ) .
EK D 0 + δ , ρ r κ 1 M ν , κ η , γ ( u r ν ) ( x ) = x κ 1 Γ ( κ ) Γ ( γ ) 2 Ψ 2 ( γ , η ) , ( κ + δ + ρ , ν ) ( κ , ν ) , ( κ + ρ , ν ) u x ν .
Theorem 3. 
Let δ , χ , ρ , κ , ν , η , γ C , such that ( δ ) 0 , ( ν ) > 0 and x > 0 , t > 0 . Then, the following right-sided fractional derivative formula is valid:
D δ , χ , ρ r κ 1 M ν , κ η , γ u r ν ( x ) = x κ + χ 1 Γ ( κ ) Γ ( γ ) 3 Ψ 3 ( γ , η ) , ( 1 χ κ , ν ) , ( 1 κ + δ + ρ , ν ) ( κ , ν ) , ( 1 κ , ν ) , ( 1 κ + ρ χ , ν ) u x ν ,
where ( κ ) < 1 + min ( χ + ρ ) , ( δ + ρ )
Proof. 
Using (7), we have
D δ , χ , ρ r κ 1 M ν , κ η , γ u r ν ( x ) = n = 0 Γ ( κ ) Γ ( η n + γ ) Γ ( γ ) Γ ( ν n + κ ) u n n ! × D δ , χ , ρ r κ ν n 1 ( x ) .
Using (27), this proves Theorem 3. □
Corollary 4. 
If the assumptions stated in Theorem 3 are true, and substituting χ = δ and χ = 0 , the following fractional derivative formulas are valid:
W D δ r κ 1 M ν , κ η , γ u r ν ( x ) = x κ δ 1 Γ ( κ ) Γ ( γ ) 2 Ψ 2 ( γ , η ) , ( 1 + δ κ , ν ) ( κ , ν ) , ( 1 κ , ν ) u x ν .
EK D δ , ρ r κ 1 M ν , κ η , γ u r ν ( x ) = x κ 1 Γ ( κ ) Γ ( γ ) 2 Ψ 2 ( γ , η ) , ( 1 κ + δ + ρ , ν ) ( κ , ν ) , ( 1 κ + ρ , ν ) u x ν .

Funding

This research received no external funding.

Institutional Review Board Statement

Not applicable.

Data Availability Statement

Not applicable.

Conflicts of Interest

The author declares no conflict of interest.

References

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