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Article

Analysis of a Nonlinear ψ-Hilfer Fractional Integro-Differential Equation Describing Cantilever Beam Model with Nonlinear Boundary Conditions

by
Kanoktip Kotsamran
1,†,
Weerawat Sudsutad
2,*,†,
Chatthai Thaiprayoon
3,4,†,
Jutarat Kongson
3,4,*,† and
Jehad Alzabut
5,6,†
1
Department of General Science, Faculty of Science and Engineering, Kasetsart University Chalermphrakiat Sakon Nakhon Province Campus, Sakon Nakhon 47000, Thailand
2
Department of Applied Statistics, Faculty of Applied Science, King Mongkut’s University of Technology North Bangkok, Bangkok 10800, Thailand
3
Department of Mathematics, Faculty of Science, Burapha University, Chonburi 20131, Thailand
4
Center of Excellence in Mathematics, CHE, Sri Ayutthaya Rd., Bangkok 10400, Thailand
5
Deparment of Mathematics and General Sciences, Prince Sultan University, Riyadh 11586, Saudi Arabia
6
Department of Industrial Engineering, OSTİM Technical University, Ankara 06374, Turkey
*
Authors to whom correspondence should be addressed.
These authors contributed equally to this work.
Fractal Fract. 2021, 5(4), 177; https://doi.org/10.3390/fractalfract5040177
Submission received: 2 September 2021 / Revised: 13 October 2021 / Accepted: 16 October 2021 / Published: 21 October 2021

Abstract

:
In this paper, we establish sufficient conditions to approve the existence and uniqueness of solutions of a nonlinear implicit ψ -Hilfer fractional boundary value problem of the cantilever beam model with nonlinear boundary conditions. By using Banach’s fixed point theorem, the uniqueness result is proved. Meanwhile, the existence result is obtained by applying the fixed point theorem of Schaefer. Apart from this, we utilize the arguments related to the nonlinear functional analysis technique to analyze a variety of Ulam’s stability of the proposed problem. Finally, three numerical examples are presented to indicate the effectiveness of our results.

1. Introduction

During the last few decades, elastic beams ( EB ) have been prominent in the realm of physical science and engineering problems. In particular, the construction of buildings and bridges requires careful computations of the elastic beam equations ( EBE s) to assure the safety of the structure. The equations of the EB problem have been created to represent real situations and their solutions have been provided by different mathematical techniques. EBE s have attracted the interest of many researchers who formulate EBE s in the form of fourth-order ordinary differential equations in various methods. For instance, in 1988, Gupta [1] discussed a fourth-order EBE with two-point boundary conditions as follows:
x ( 4 ) ( t ) + f ( t , x ( t ) ) = 0 , t ( 0 , 1 ) , x ( 0 ) = 0 , x ( 0 ) = 0 , x ( 1 ) = 0 , x ″′ ( 1 ) = 0 .
The problem (1) represents an elastic beam model of length 1 that is restrained at the left end with zero displacement and bending moment, and is free to travel at the right end with a diminishing angular attitude and shear force. Using the Leray–Schauder continuation theorem and Wirtinger-type inequalities, the existence properties of the problem (1) were established. In 2017, Cianciaruso and co-workers [2] studied the fourth-order differential equation of the cantilever beam ( CB ) model with three-point boundary conditions as follows:
x ( 4 ) ( t ) + f ( t , x ( t ) ) = 0 , t ( 0 , 1 ) , x ( 0 ) = 0 , x ( 0 ) = 0 , x ( 1 ) = 0 , x ″′ ( 1 ) = g ( ξ , x ( ξ ) ) ,
where ξ ( 0 , 1 ) is a real constant. They proved the existence, non-existence, localization, and multiplicity of nontrivial solutions for problem (2) with their results by using topological methods. Further, the development of EBE s with linear or nonlinear functions under a variety of boundary conditions is more varied and comprehensive. Many works in the literature deal with linear or nonlinear boundary value problems which consist of two or more points; for example, Zhong and co-workers [3] examined fourth-order nonlinear differential equations with the four-point boundary conditions:
x ( 4 ) ( t ) + f ( t , x ( t ) , x ( t ) ) = 0 , t ( 0 , 1 ) , x ( 0 ) = x ( 1 ) = 0 , c 1 x ( ω 1 ) c 2 x ″′ ( ω 1 ) = 0 , c 3 x ( ω 2 ) + c 4 x ″′ ( ω 1 ) = 0 ,
where c i represents non-negative constants, i = 1 , 2 , 3 , 4 , the points ω 1 , ω 2 [ 0 , 1 ] with ω 1 < ω 2 , and f C ( [ 0 , 1 ] × [ 0 , ) × ( , 0 ] , [ 0 , ) ) . By using Krasnoselskii’s fixed point theorem, the existence result is obtained. EBE s with a variety of boundary conditions have been studied in recent years; see [4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25] and references cited therein.
Fractional calculus generalizes the ordinary differentiation and integration of arbitrary order, which may be non-integer order. It is widely utilized in several areas, including engineering and applied science. Different definitions of fractional derivative and integral operators, such as Riemann–Liouville, Caputo, Hilfer, Katugampola, and others, have been discovered. We refer to the thorough investigations in [26,27,28,29,30,31] for a detailed analysis of applications on fractional calculus. In recent years, several research papers have investigated fractional differential equations, the existence results of solutions, and analyzed system stability. One of the most fascinating aspects of differential equations is existence theory. In the previous several decades, a lot of research has been conducted in this field. Various techniques have been used in the current literature to demonstrate the existence and uniqueness of solutions to differential and integral equations. In addition, one of the most powerful techniques for stability analysis is Ulam’s stability, which includes Ulam–Hyers ( UH ) stability, generalized Ulam–Hyers ( GUH ) stability, Ulam–Hyers–Rassias ( UHR ) stability, and generalized Ulam–Hyers–Rassias ( GUHR ) stability. It is useful because the properties of Ulam’s stability guarantee the existence of solutions, and when the problem under consideration is Ulam’s stability, it ensures that a close exact solution exists; see [32,33,34,35,36,37,38,39,40,41,42] and references cited therein.
In response to the foregoing discussions, we study a class of nonlinear implicit ψ -Hilfer fractional integro-differential equations with nonlinear boundary conditions describing the CB model of the form:
H D a + α , ρ ; ψ x ( t ) = f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) , t ( a , b ) , x ( a ) = 0 , H D a + δ , ρ ; ψ x ( a ) = 0 , i = 1 n μ i H D a + θ i , ρ ; ψ x ( κ i ) = H ( η , x ( η ) ) , j = 1 n φ j H D a + ϕ j , ρ ; ψ x ( ς j ) = G ( ξ , x ( ξ ) ) ,
where H D a + v , ρ ; ψ denotes the ψ -Hilfer fractional derivative operators of order v = { α , δ , θ i , ϕ j } , α ( 3 , 4 ] , θ i ( 0 , 1 ] , δ ( 1 , 2 ] , ϕ j ( 2 , 3 ] , κ i , ς j , η , ξ ( a , b ] , μ i , φ j R , for i = 1 , 2 , , m , j = 1 , 2 , , n , and ρ [ 0 , 1 ] . I a + β ; ψ denotes the ψ -Riemann–Liouville fractional integral of order β > 0 , f C ( J × R 3 , R ) , H , G C ( J , R ) and J : = [ a , b ] , b > a > 0 .
The major goal of this paper is to use well-known fixed point theorems such as Banach’s and Schaefer’s to show the existence and uniqueness of the solution for the problem of (4). The different types of Ulam’s stability, such as UH stability, GUH stability, UHR stability, and GUHR stability, are used to investigate the stability of the solution for problem (4). Finally, we illustrate examples of various functions that are investigated to verify the theoretical results.
The rest of this paper is assembled as follows: In Section 2, we introduce some notations, definitions, lemmas, and essential results. The existence and uniqueness results are obtained by helping the fixed point theorems in Section 3. By using the nonlinear functional analysis technique, we analyzed a variety of Ulam’s stabilities for the proposed problem in Section 4. In Section 5, we present examples to guarantee the validity of the obtained results. The conclusion of this paper is presented at the end.

2. Preliminaries

We present a brief overview of the fundamental concepts of ψ -Hilfer fractional calculus as well as essential key results that will be employed in this paper.
Let E = C ( J , R ) be the Banach space of continuous functions on J equipped with the supnorm x = sup t J { | x ( t ) | } . Let AC n ( J , R ) be the space of n-times absolutely continuous functions where AC n ( J , R ) = { f : J R ; f ( n 1 ) AC ( J , R ) } .
Definition 1
(The ψ -Riemann–Liouville fractional integral operator [43]). Let ( a , b ) be a finite or infinite interval of the half-axis R + . Let ψ ( x ) C 1 ( J , R ) be an increasing function with ψ ( x ) 0 for each t J . The ψ-Riemann–Liouville fractional integral of order α of a function f depending on the function ψ on J is defined by
I a + α ; ψ f ( t ) = 1 Γ ( α ) a t ψ ( s ) ψ ( t ) ψ ( s ) α 1 f ( s ) d s , t > a > 0 , α > 0 ,
where Γ ( · ) represents the (Euler) Gamma function.
Definition 2
(The ψ -Riemann–Liouville fractional derivative operator [43]). Let ψ ( t ) be define as in Definition 1 with ψ ( t ) 0 . The ψ-Riemann–Liouville fractional derivative of a function f depending on the function ψ is defined as D a + α ; ψ f ( t ) = 1 ψ ( t ) d d t n I a + n α ; ψ f ( t ) or
D a + α ; ψ f ( t ) = 1 Γ ( n α ) 1 ψ ( t ) d d t n a t ψ ( s ) ψ ( t ) ψ ( s ) n α 1 f ( s ) d s , α > 0 ,
where n = [ α ] + 1 and [ α ] represents the integer part of R e ( α ) .
Definition 3
(The ψ -Hilfer fractional derivative operator [44]). Let γ = α + ρ ( n α ) , α ( n 1 , n ) with n N , f C n ( J , R ) and ψ ( t ) C 1 ( J , R ) be increasing with ψ ( t ) 0 for each t J . Then, the ψ-Hilfer fractional derivative of type ρ [ 0 , 1 ] of a function f, depending on the function ψ, is defined as
H D a + α , ρ ; ψ f ( t ) = I a + ρ ( n α ) ; ψ 1 ψ ( t ) d d t n I a + ( 1 ρ ) ( n α ) ; ψ f ( t ) = I a + γ α ; ψ D a + γ ; ψ f ( t ) ,
where D a + γ ; ψ f ( t ) = D a + n ; ψ I a + ( 1 ρ ) ( n α ) ; ψ f ( t ) .
Lemma 1
(The semigroup property [43]). Let α , β > 0 . Then I a + α ; ψ I a + β ; ψ f ( t ) = I a + α + β ; ψ f ( t ) , t > a .
Proposition 1
([43,44]). Let t > a and consider G υ ( t ) = ψ ( t ) ψ ( a ) υ . Then, for υ > 0 and α 0 , the following properties:
(i) 
I a + α ; ψ G υ 1 ( t ) = Γ ( υ ) Γ ( υ + α ) G υ + α 1 ( t ) ;
(ii) 
D a + α , ρ ; ψ G υ 1 ( t ) = Γ ( υ ) Γ ( υ α ) G υ α 1 ( t ) ;
(iii) 
H D a + α , ρ ; ψ G υ 1 ( t ) = Γ ( υ ) Γ ( υ α ) G υ α 1 ( t ) , υ > γ = α + ρ ( 4 α ) .
Lemma 2
([44]). Let f C n ( J , R ) , α ( n 1 , n ) , ρ [ 0 , 1 ] , and γ = α + ρ ( n α ) . Then,
I a + α ; ψ H D a + α , ρ ; ψ f ( t ) = f ( t ) k = 1 n ψ ( t ) ψ ( a ) q k Γ ( q k + 1 ) f ψ [ n k ] I a + ( 1 ρ ) ( n α ) ; ψ f ( a ) ,
for all t J , where f ψ [ n ] f ( t ) : = 1 ψ ( t ) d d t n f ( t ) .
Lemma 3
([36]). Let α ( m 1 , m ) , β ( n 1 , n ) , n, m N , n m , ρ [ 0 , 1 ] and α > β + ρ ( n β ) . If h C 1 γ , ψ ( J , R ) , then H D a + β , ρ ; ψ I a + α ; ψ h ( ς ) = I 0 + α β ; ψ h ( ς ) .
Lemma 4.
Let α ( 3 , 4 ] , δ ( 0 , 1 ] , θ i ( 1 , 2 ] , ϕ j ( 2 , 3 ] , ( i = 1 , 2 , , m , j = 1 , 2 , , n ) with ρ [ 0 , 1 ] , γ = α + ρ ( 4 α ) and Λ = Λ 11 Λ 22 Λ 12 Λ 21 0 . Assume that h E . Then, x C 4 ( J , R ) is a solution of
H D a + α , ρ ; ψ x ( t ) = h ( t ) , t ( a , b ) , x ( a ) = 0 , H D a + δ , ρ ; ψ x ( a ) = 0 , i = 1 m μ i H D a + θ i , ρ ; ψ x ( κ i ) = H ( η , x ( η ) ) , j = 1 n φ j H D a + ϕ j , ρ ; ψ x ( ς j ) = G ( ξ , x ( ξ ) ) ,
if and only if x satisfies the integral equation
x ( t ) = I a + α ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ 1 Λ Γ ( γ ) [ Λ 22 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ h ( κ i ) Λ 12 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ h ( ς j ) ] + ψ ( t ) ψ ( a ) γ 2 Λ Γ ( γ 1 ) [ Λ 11 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ h ( ς j ) Λ 21 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ h ( κ i ) ] ,
where
Λ 11 = i = 1 m μ i ψ ( κ i ) ψ ( a ) γ θ i 1 Γ ( γ θ i ) , Λ 12 = i = 1 m μ i ψ ( κ i ) ψ ( a ) γ θ i 2 Γ ( γ θ i 1 ) ,
Λ 21 = j = 1 n φ j ψ ( ς j ) ψ ( a ) γ ϕ j 1 Γ ( γ ϕ j ) , Λ 22 = j = 1 n φ j ψ ( ς j ) ψ ( a ) γ ϕ j 2 Γ ( γ ϕ j 1 ) .
Proof. 
Let x E be a solution of (5). Applying I a + α ; ψ on both sides of (5) with Lemma 2 ( n = 4 ) , we have
x ( t ) = I a + α ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ 1 Γ ( γ ) c 1 + ψ ( t ) ψ ( a ) γ 2 Γ ( γ 1 ) c 2 + ψ ( t ) ψ ( a ) γ 3 Γ ( γ 2 ) c 3 + ψ ( t ) ψ ( a ) γ 4 Γ ( γ 3 ) c 4 ,
where c i R for i = 1 , 2 , 3 , 4 . Taking the operator H D a + δ , ρ ; ψ into (9), we obtain
H D a + δ , ρ ; ψ x ( t ) = I a + α δ ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ δ 1 Γ ( γ δ ) c 1 + ψ ( t ) ψ ( a ) γ δ 2 Γ ( γ δ 1 ) c 2 + ψ ( t ) ψ ( a ) γ δ 3 Γ ( γ δ 2 ) c 3 + ψ ( t ) ψ ( a ) γ δ 4 Γ ( γ δ 3 ) c 4 .
x ( a ) = H D a + δ , ρ ; ψ x ( a ) = 0 , which implies that c 3 = c 4 = 0 . Then,
x ( t ) = I a + α ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ 1 Γ ( γ ) c 1 + ψ ( t ) ψ ( a ) γ 2 Γ ( γ 1 ) c 2 .
Taking H D a + θ i , ρ ; ψ and H D a + ϕ j , ρ ; ψ into (10) with Proposition 1 (iii), we obtain
H D a + θ i , ρ ; ψ x ( t ) = I a + α θ i ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ θ i 1 Γ ( γ θ i ) c 1 + ψ ( t ) ψ ( a ) γ θ i 2 Γ ( γ θ i 1 ) c 2 , H D a + ϕ j , ρ ; ψ x ( t ) = I a + α ϕ j ; ψ h ( t ) + ψ ( t ) ψ ( a ) γ ϕ j 1 Γ ( γ ϕ j ) c 1 + ψ ( t ) ψ ( a ) γ ϕ j 2 Γ ( γ ϕ j 1 ) c 2 .
By using the nonlinear boundary conditions in (5), we obtain the system of two unknowns variables c 1 and c 2 ,
Λ 11 Λ 12 Λ 21 Λ 22 c 1 c 2 = H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ h ( κ i ) G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ h ( ς j ) ,
where Λ 11 , Λ 12 , Λ 21 and Λ 22 are given by (7) and (8), respectively. Finding the solution of (11), we obtain the constants
c 1 = 1 Λ [ Λ 22 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ h ( κ i ) Λ 12 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ h ( ς j ) ] , c 2 = 1 Λ [ Λ 11 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ h ( ς j ) Λ 21 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ h ( κ i ) ] .
Hence, the solution x ( t ) follows by applying c 1 and c 2 in (9). This implies that x ( t ) satisfies (6).
On the other hand, it is easy to show by a direct calculation that x ( t ) , which is given by (6), verifies the linear ψ -Hilfer FCB model (5) under the nonlinear boundary conditions. □

3. Existence and Uniqueness Results

For the sake of this paper, we set the notations F x ( t ) = f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) and I a + u ; ψ F x ( c ) , where
I a + u ; ψ F x ( c ) = 1 Γ ( u ) a c ψ ( s ) ψ ( c ) ψ ( s ) u 1 F x ( s ) d s ,
with u = { α , α θ i , α ϕ j } , c = { t , a , ξ , κ i , ς j } for i = 1 , 2 , , m , j = 1 , 2 , , n . According to Lemma 4, we define T : E E and Ψ γ ( · )
( T x ) ( t ) = I a + α ; ψ F x ( t ) + Ψ γ 1 ( t ) Λ [ Λ 22 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) Λ 12 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j ) ] + Ψ γ 2 ( t ) Λ [ Λ 11 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j )
Λ 21 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) ] ,
Ψ γ ( u ) = ψ ( u ) ψ ( a ) γ Γ ( γ + 1 ) .
Clearly, the ψ -Hilfer fractional boundary value problem ( FBVP ) describing the CB model (4) has solutions if and only if T has fixed points. For the tightness of calculation in this manuscript, we set the constants
Φ ( A , B ) = 1 Λ A Ψ γ 1 ( b ) +   B Ψ γ 2 ( b ) , Ω ( u ) = Ψ u ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ u θ i ( κ i )
+ Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ u ϕ j ( ς j ) .

3.1. Uniqueness Result

In the first our criteria, we will analyze the uniqueness result of the solution for the ψ -Hilfer FBVP describing the CB model (4) by applying Banach’s fixed point theorem (Lemma 5).
Lemma 5
(Banach’s fixed point theorem [45]). Let S be a non-empty closed subset of a Banach space E . Then, any contraction mapping Q from E into itself has a unique fixed point.
Theorem 1.
Let f : J × R 3 R be continuous and
( A 1 )
There exist positive constants L 1 , L 2 , L 3 > 0 with L 2 < 1 , such that
f ( t , u 1 , v 1 , w 1 ) f ( t , u 2 , v 2 , w 2 ) L 1 | u 1 u 2 | +   L 2 | v 1 v 2 |   +   L 3 | w 1 w 2 | ,
for any u i , v i , w i R , i = 1 , 2 and t J .
( A 2 )
There exist positive constants H 1 , G 1 > 0 such that
H ( t , u 1 ) H ( t , u 2 ) H 1 | u 1 u 2 | and G ( t , u 1 ) G ( t , u 2 ) G 1 | u 1 u 2 | ,
for any u i R , i = 1 , 2 and t J .
If
1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) +   Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 < 1 ,
where Λ i j , i , j { 1 , 2 } , Φ ( · , · ) and Ω ( · ) are defined by (7), (8), (14) and (15), respectively, and the ψ-Hilfer FBVP describing CB model (4) has a unique solution x in E .
Proof. 
We transform the ψ -Hilfer FBVP describing the CB model (4) into x = T x , where T is defined by (12). Clearly, the fixed points of T are the possible solutions of the ψ -Hilfer FBVP describing the CB model (4). From Lemma 5, we will verify that T has a unique fixed point, which means that the ψ -Hilfer FBVP describing the CB model (4) has a unique solution.
Firstly, define a bounded, closed, convex and nonempty subset B r 1 : = { x E : x r 1 } with
r 1 M 1 1 L 2 Ω ( α ) + Φ ( Λ 22 , Λ 21 ) M 2 + Φ ( Λ 12 , Λ 11 ) M 3 1 1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) +   Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 ,
where Λ i j for i, j { 1 , 2 } , Φ ( · , · ) and Ω ( · ) are given by (7), (8), (14) and (15), respectively.
Let sup t J | f ( t , 0 , 0 , 0 ) | : = M 1 < , sup t J | H ( t , 0 ) | : = M 2 < , sup t J | G ( t , 0 ) | : = M 3 < . The process of proof will be divided in two steps:
Step I. T B r 1 B r 1 .
Let x B r 1 and t J . Then,
| ( T x ) ( t ) | I a + α ; ψ | F x ( b ) | + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( κ i ) | + | Λ 12 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( ς j ) | ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( ς j ) |
+ | Λ 21 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( κ i ) | ] .
By applying Proposition 1 (i), we have
I a + β ; ψ x ( t ) = 1 Γ ( β ) a t ψ ( s ) ψ ( t ) ψ ( s ) β 1 x ( s ) d s
ψ ( t ) ψ ( a ) β Γ ( β + 1 ) x = Ψ β ( t ) x .
By applying ( A 1 ) , ( A 2 ) , and (19), we have
F x ( t ) | f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) f ( t , 0 , 0 , 0 ) | + | f ( t , 0 , 0 , 0 ) | L 1 | x ( t ) | + L 2 | H D a + α , ρ ; ψ x ( t ) | + L 3 | I a + β ; ψ x ( t ) | + M 1 x 1 L 2 L 1 + L 3 ψ ( t ) ψ ( a ) β Γ ( β + 1 ) + M 1 1 L 2
= x 1 L 2 L 1 + L 3 Ψ β ( t ) + M 1 1 L 2 ,
H ( t , x ( t ) ) | H ( t , x ( t ) ) H ( t , 0 ) | + | H ( t , 0 ) | H 1 x + M 2 ,
G ( t , x ( t ) ) | G ( t , x ( t ) ) G ( t , 0 ) | + | G ( t , 0 ) | G 1 x + M 3 .
From (20) with Proposition 1 (i), we can compute that
I a + α ; ψ F x ( b ) x 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) + M 1 Ψ α ( b ) 1 L 2 ,
I a + α θ i ; ψ F x ( κ i ) x 1 L 2 L 1 Ψ α θ i ( κ i ) + L 3 Ψ β + α θ i ( κ i ) + M 1 Ψ α θ i ( κ i ) 1 L 2 ,
I a + α ϕ j ; ψ F x ( ς j ) x 1 L 2 L 1 Ψ α ϕ j ( ς j ) + L 3 Ψ β + α ϕ j ( ς j ) + M 1 Ψ α ϕ j ( ς j ) 1 L 2 .
Substituting (20)–(25) into (18), we have
| ( T x ) ( t ) | x 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) + M 1 1 L 2 Ψ α ( b ) + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | ( H 1 x + M 2 + i = 1 m | μ i | x 1 L 2 L 1 Ψ α θ i ( κ i ) + L 3 Ψ β + α θ i ( κ i ) + M 1 1 L 2 Ψ α θ i ( κ i ) ) + | Λ 12 | ( G 1 x + M 3 + j = 1 n | φ j | { x 1 L 2 L 1 Ψ α ϕ j ( ς j ) + L 3 Ψ β + α ϕ j ( ς j ) + M 1 1 L 2 Ψ α ϕ j ( ς j ) } ) ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | ( j = 1 n | φ j | { x 1 L 2 ( L 1 Ψ α ϕ j ( ς j ) + L 3 Ψ β + α ϕ j ( ς j ) ) + M 1 1 L 2 Ψ α ϕ j ( ς j ) } + G 1 x + M 3 ) + | Λ 21 | ( H 1 x + M 2 + i = 1 m | μ i | x 1 L 2 L 1 Ψ α θ i ( κ i ) + L 3 Ψ β + α θ i ( κ i ) + M 1 1 L 2 Ψ α θ i ( κ i ) ) ] { 1 1 L 2 ( L 1 [ Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] + L 3 [ Ψ β + α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ β + α θ i ( κ i ) + 1 | Λ | ( | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) ) j = 1 n | φ j | Ψ β + α ϕ j ( ς j ) ] ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) H 1 + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) G 1 } r 1 + M 1 1 L 2 [ Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | ( | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) M 2 + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) M 3
= { 1 1 L 2 ( L 1 [ Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] + L 3 [ Ψ β + α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ β + α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ β + α ϕ j ( ς j ) ] ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 } r 1 + M 1 1 L 2 Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) + Φ ( Λ 22 , Λ 21 ) M 2 + Φ ( Λ 12 , Λ 11 ) M 3 .
Thus,
| ( T x ) ( t ) | 1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) +   Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 r 1 + M 1 1 L 2 Ω ( α ) + Φ ( Λ 22 , Λ 21 ) M 2 + Φ ( Λ 12 , Λ 11 ) M 3 ,
which implies that T x r 1 . Then, T B r 1 B r 1 .
Step II. T : E E is a contraction.
Let x, y E and for any t J . Then, we have
T x ( t ) T y ( t ) I a + α ; ψ | F x ( s ) F y ( s ) | ( b ) + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | | H ( η , x ( η ) ) H ( η , y ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( s ) F y ( s ) | ( κ i ) + | Λ 12 | | G ( ξ , x ( ξ ) ) G ( ξ , y ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( s ) F y ( s ) | ( ς j ) ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | | G ( ξ , x ( ξ ) ) G ( ξ , y ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( s ) F y ( s ) | ( ς j )
+ | Λ 21 | | H ( η , x ( η ) ) H ( η , y ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( s ) F y ( s ) | ( κ i ) ] .
By applying ( A 1 ) and (19), we have
F x ( t ) F y ( t ) = f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) f ( t , y ( t ) , H D a + α , ρ ; ψ y ( t ) , I a + β ; ψ y ( t ) ) L 1 | x ( t ) y ( t ) | + L 2 H D a + α , ρ ; ψ x ( t ) H D a + α , ρ ; ψ y ( t )   +   L 3 I a + β ; ψ x ( t ) I a + β ; ψ y ( t )
L 1 + L 3 Ψ β ( t ) x y 1 L 2 .
Hence, by inserting (27) in (26) and using Proposition (i) with ( A 2 ) , we obtain
T x ( t ) T y ( t ) x y 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | ( H 1 x y + x y 1 L 2 i = 1 m | μ i | L 1 Ψ α θ i ( κ i ) + L 3 Ψ β + α θ i ( κ i ) ) + | Λ 12 | ( G 1 x y + x y 1 L 2 j = 1 n | φ j | L 1 Ψ α ϕ j ( ς j ) + L 3 Ψ β + α ϕ j ( ς j ) ) ] + Ψ γ 2 ( b ) | Λ | × [ | Λ 11 | G 1 x y + x y 1 L 2 j = 1 n | φ j | L 1 Ψ α ϕ j ( ς j ) + L 3 Ψ β + α ϕ j ( ς j ) + | Λ 21 | H 1 x y + x y 1 L 2 i = 1 m | μ i | L 1 Ψ α θ i ( κ i ) + L 3 Ψ β + α θ i ( κ i ) ] = { 1 1 L 2 ( L 1 [ Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] + L 3 [ Ψ β + α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ β + α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ β + α ϕ j ( ς j ) ] ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 } x y ,
which implies that
T x T y 1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 x y .
In view of (16), we find that T is a contraction. Therefore, in accordance with Lemma 5, the ψ -Hilfer FBVP describing the CB model (4) has a unique solution x E . □

3.2. Existence Result

The second result is proved by applying Schaefer’s fixed point theorem (Lemma 6).
Lemma 6.
(Schaefer’s fixed point theorem [45].) Let E be a Banach space and T : E E is a completely continuous operator and the set B = { x E : x = ζ T x , 0 < ζ 1 } is bounded. Then, T has a fixed point in E .
Theorem 2.
Let f : J × R 3 R be continuous. Assume that:
( A 3 )
There exist non-negative continuous functions p i C ( J , R + { 0 } ) ( i = 1 , 2 , 3 , 4 ) such that
| f ( t , u , v , w ) | p 1 ( t ) + p 2 ( t ) | u | + p 3 ( t ) | v | + p 4 ( t ) | w | , ( t , u , v , w ) ( J , R 3 ) ,
with p i * = sup t J { p i ( t ) } , i = 1 , 2 , 3 , 4 , and p 3 * < 1 .
( A 4 )
There exist non-negative continuous functions h i , g i C ( J , R + { 0 } ) ( i = 1 , 2 ) such that
| H ( t , u ) | h 1 ( t ) + h 2 ( t ) | u | , ( t , u ) ( J , R ) , | G ( t , u ) | g 1 ( t ) + g 2 ( t ) | u | , ( t , u ) ( J , R ) ,
with h i * = sup t J { h i ( t ) } and g i * = sup t J { g i ( t ) } , i = 1 , 2 .
Then, the ψ-Hilfer FBVP describing CB model (4) has at least one solution on J .
Proof. 
The process will be analyzed in four steps as follows.
Step I. T is continuous.
Let x n be a sequence such that x n x E . Then, for any t J , we have
( T x n ) ( t ) ( T x ) ( t ) I a + α ; ψ | F x n ( s ) F x ( s ) | ( b ) + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | ( | H ( η , x n ( η ) ) H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x n ( s ) F x ( s ) | ( κ i ) ) + | Λ 12 | ( | G ( ξ , x n ( ξ ) ) G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x n ( s ) F x ( s ) | ( ς j ) ) ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | ( | G ( ξ , x n ( ξ ) ) G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x n ( s ) F x ( s ) | ( ς j ) ) + | Λ 21 | ( | H ( η , x n ( η ) ) H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x n ( s ) F x ( s ) | ( κ i ) ) ] Ψ α ( b ) F x n F x + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | H 1 x n x + i = 1 m | μ i | Ψ α θ i ( κ i ) F x n F x + | Λ 12 | G 1 x n x + j = 1 n | φ j | Ψ α ϕ j ( ς j ) F x n F x ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | G 1 x n x + j = 1 n | φ j | Ψ α ϕ j ( ς j ) F x n F x + | Λ 21 | H 1 x n x + i = 1 m | μ i | Ψ α θ i ( κ i ) F x n F x ] = { Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) } F x n F x + { 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) H 1 + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) G 1 } x n x = F x n F x Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 x n x = Ω ( α ) F x n F x + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 x n x .
The continuity of f implies the continuity of F x . Then, F x n F x 0 , x n x 0 , as n , Hence, T is continuous.
Step II. T maps bounded set into bounded set in E .
For r 2 > 0 , there is N such that, for each x B r 2 where B r 2 = { x E : x r 2 } , then T x N .
For any t J and x B r 2 , we obtain
( T x ) ( t ) I a + α ; ψ | F x ( b ) | + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( κ i ) | + | Λ 12 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( ς j ) | ] + Ψ γ 2 ( b ) | Λ | [ | Λ 11 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( ς j ) | + | Λ 21 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( κ i ) | ] .
From ( A 3 ) ( A 4 ) , it follows that
F x ( t ) p 1 ( t ) + p 2 ( t ) | x ( t ) | + p 3 ( t ) | H D a + α , ρ ; ψ x ( t ) | + p 4 ( t ) | I a + β ; ψ x ( t ) | p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * ψ ( t ) ψ ( a ) β Γ ( β + 1 )
= p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( t ) ,
H ( t , x ( t ) ) h 1 ( t ) + h 2 | x ( t ) | h 1 * + h 2 * x ,
G ( t , x ( t ) ) g 1 ( t ) + g 2 ( t ) | x ( t ) | g 1 * + g 2 * x .
Inserting (29)–(31) in (28), we can compute that
( T x ) ( t ) I a + α ; ψ p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( s ) ( b ) + Ψ γ 1 ( b ) | Λ | [ | Λ 22 | ( h 1 * + h 2 * x + i = 1 m | μ i | I a + α θ i ; ψ p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( s ) ( κ i ) ) + | Λ 12 | ( g 1 * + g 2 * x + j = 1 n | φ j | I a + α ϕ j ; ψ p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( s ) ( ς j ) ) ] + Ψ γ 2 ( b ) | Λ | × [ | Λ 11 | g 1 * + g 2 * x + j = 1 n | φ j | I a + α ϕ j ; ψ p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( s ) ( ς j ) + | Λ 21 | h 1 * + h 2 * x + i = 1 m | μ i | I a + α θ i ; ψ p 1 * 1 p 3 * + x 1 p 3 * p 2 * + p 4 * Ψ β ( s ) ( κ i ) ] { [ Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] p 2 * 1 p 3 *
+ [ Ψ β + α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ β + α θ i ( κ i ) + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | Ψ β + α ϕ j ( ς j ) ] p 4 * 1 p 3 * + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) h 2 * + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) g 2 * } x + [ Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] p 1 * 1 p 3 * + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) h 1 * + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) g 1 * = { Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) p 2 * 1 p 3 * + Ψ β + α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ β + α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ β + α ϕ j ( ς j ) × p 4 * 1 p 3 * + Φ ( Λ 22 , Λ 21 ) h 2 * + Φ ( Λ 12 , Λ 11 ) g 2 * } x + p 1 * 1 p 3 * [ Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ] + Φ ( Λ 22 , Λ 21 ) h 1 * + Φ ( Λ 12 , Λ 11 ) g 1 * .
which implies that
T x Ω ( α ) p 2 * 1 p 3 * + Ω ( β + α ) p 4 * 1 p 3 * + Φ ( Λ 22 , Λ 21 ) h 2 * + Φ ( Λ 12 , Λ 11 ) g 2 * r 2 + Ω ( α ) p 1 * 1 p 3 * + Φ ( Λ 22 , Λ 21 ) h 1 * + Φ ( Λ 12 , Λ 11 ) g 1 * : = N .
Then, T maps bounded set into bounded set in E .
Step III. T maps bounded sets into equicontinuous sets of E .
For a t 1 < t 2 b and x B r 2 where B r 2 as defined in Step II, by using the property that f is a bounded on the compact set J × B r 2 , we estimate
( T x ) ( t 2 ) ( T x ) ( t 1 ) Ψ γ 1 ( t 2 ) Ψ γ 1 ( t 1 ) | Λ | [ | Λ 22 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( s ) | ( κ i ) + | Λ 12 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( s ) | ( ς j ) ] + Ψ γ 2 ( t 2 ) Ψ γ 2 ( t 1 ) | Λ | [ | Λ 11 | | G ( ξ , x ( ξ ) ) | + j = 1 n | φ j | I a + α ϕ j ; ψ | F x ( s ) | ( ς j )
+ | Λ 21 | | H ( η , x ( η ) ) | + i = 1 m | μ i | I a + α θ i ; ψ | F x ( s ) | ( κ i ) ] + I a + α ; ψ F x ( t 2 ) I a + α ; ψ F x ( t 1 ) .
By setting sup ( t , u , v , w ) J × B r 2 3 | f ( t , u , v , w ) | = f ^ < , sup ( t , u ) J × B r 2 | H ( t , u ) | = H ^ < , and sup ( t , u ) J × B r 2 | G ( t , u ) | = G ^ < , then
( T x ) ( t 2 ) ( T x ) ( t 1 ) Ψ γ 1 ( t 2 ) Ψ γ 1 ( t 1 ) | Λ | [ | Λ 22 | H ^ + f ^ i = 1 m | μ i | Ψ α θ i ( κ i ) + | Λ 12 | ( G ^ + f ^ j = 1 n | φ j | Ψ α ϕ j ( ς j ) ) ] + Ψ γ 1 ( t 2 ) Ψ γ 2 ( t 1 ) | Λ | [ | Λ 11 | ( G ^ + f ^ j = 1 n | φ j | Ψ α ϕ j ( ς j ) ) + | Λ 21 | H ^ + f ^ i = 1 m | μ i | Ψ α θ i ( κ i ) ] + f ^ Γ ( α + 1 ) [ | ψ ( t 2 ) ψ ( a ) α ψ ( t 2 ) ψ ( t 1 ) α ψ ( t 1 ) ψ ( a ) α | + ψ ( t 2 ) ψ ( t 1 ) α ] .
Note that the right hand-side of the above inequality is independent of the unknown variable x and tends to zero as t 2 t 1 . Hence, T is equicontinuous. Then, T is relatively compact on B r 2 . We apply the Arzelá–Ascoli theorem, which implies that T is completely continuous.
Step IV. The set B = { x E : x = ζ T x , ζ ( 0 , 1 ] } is a bounded (a priori bounds).
Let x B , then x = ζ T x for some ζ ( 0 , 1 ] . From ( A 3 ) ( A 4 ) , for any t J , then
x ( t ) = ζ { I a + α ; ψ F x ( t ) + Ψ γ 1 ( t ) Λ [ Λ 22 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) Λ 12 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j ) ] + Ψ γ 2 ( t ) Λ [ Λ 11 ( G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j ) ) Λ 21 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) ] } .
It follows from Step II, and for any t J , that T x N < . Then, B is a bounded set.
Using Theorem 2, we find that there exists N > 0 such that x N < . Thanks to Lemma 6, T has at least one fixed point, which is the corresponding solution of the ψ -Hilfer FBVP describing the CB model (4). □

4. Ulam’s Stability Results

In this section, we analyze the UH stability, GUH stability, UHR stability, and GUHR stability of the solution to the ψ -Hilfer FBVP describing the CB model (4).
Definition 4.
The ψ-Hilfer FBVP describing the CB model (4) is said to be UH -stable if there exists a positive real number C f > 0 such that for each ϵ > 0 and for each solution z E of
H D a + α , ρ ; ψ z ( t ) F z ( t )   ϵ ,
there exists a solution x E of the ψ-Hilfer FBVP describing the CB model (4) such that
z ( t ) x ( t )   C f ϵ , t J .
Definition 5.
The ψ-Hilfer FBVP describing the CB model (4) is said to be GUH -stable if there exists a function K C ( R + , R + ) with K ( 0 ) = 0 such that, for each solution z E of
H D a + α , ρ ; ψ z ( t ) F z ( t )   ϵ K ( t ) ,
there exists a solution x E of the ψ-Hilfer FBVP describing the CB model (4) such that
z ( t ) x ( t ) K ( ϵ ) , t J .
Definition 6.
The ψ-Hilfer FBVP describing the CB model (4) is said to be UHR -stable with respect to K C ( J , R + ) if there exists a positive real number C f , K > 0 such that for each ϵ > 0 and for each a solution z E of (34) there exists a solution x E of the ψ-Hilfer FBCP describing the CB model (4) such that
z ( t ) x ( t ) C f , K ϵ K ( t ) , t J .
Definition 7.
The ψ-Hilfer FBVP describing the CB model (4) is said to be GUHR -stable with respect to K C ( J , R + ) if there exists a positive real number C f , K > 0 such that for each a solution z E of
H D a + α , ρ ; ψ z ( t ) F z ( t ) K ( t ) ,
there exists a solution x E of the ψ-Hilfer FBVP describing CB model (4) such that
z ( t ) x ( t ) C f , K K ( t ) , t J .
Remark 1.
It is easy to see that ( a 1 ) Definition 4 ⇒ Definition 5; ( a 2 ) Definition 6 ⇒ Definition 7; ( a 3 ) Definition 6 for K ( t ) = 1 ⇒ Definition 4.
Remark 2.
A function z E is a solution of (32) if and only if there exists a function v E (where v depends on solution z) such that: ( i ) | v ( t ) | ϵ , t J ; ( i i ) H D a + α , ρ ; ψ z ( t ) = F z ( t ) + v ( t ) , t J .
Remark 3.
A function z E is a solution of (34) if and only if there exists a function w E (where w depends on solution z) such that: ( i ) | w ( t ) | ϵ K ( t ) , t J ; ( i i ) H D a + α , ρ ; ψ z ( t ) = F z ( t ) + w ( t ) , t J .
Remark 4.
There exists an increasing function K C ( J , R + ) and there exists a positive constant λ K > 0 , such that, for each t J , we have the integral inequality
I a + α ; ψ K ( t ) λ K K ( t ) .

4.1. The UH and GUH Stability Results

Firstly, we present an important lemma that will be used in the analyses of UH and GUH stability of the ψ -Hilfer FBVP describing the CB model (4).
Lemma 7.
Let α ( 3 , 4 ] , ρ [ 0 , 1 ] and let z E be the solution of (32). Then, z E satisfies
z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) Ω ( α ) ϵ ,
where
χ z ( t ) = Ψ γ 1 ( t ) Λ [ Λ 22 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) Λ 12 G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) ] + Ψ γ 2 ( t ) Λ [ Λ 11 ( G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) ) Λ 21 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) ] ,
with Λ, Λ i j , i, j { 1 , 2 } , and Ω ( α ) as in Lemma 4 and (15), respectively.
Proof. 
Let z be the solution of (32). Thanks to Remark 2 ( i i ) and Lemma 4, we obtain
H D a + α , ρ ; ψ z ( t ) = F z ( t ) + v ( t ) t ( a , b ) , z ( a ) = 0 , H D a + δ , ρ ; ψ z ( a ) = 0 , i = 1 m μ i H D a + θ i , ρ ; ψ z ( κ i ) = H ( η , z ( η ) ) , j = 1 n φ j H D a + ϕ j , ρ ; ψ z ( ς j ) = G ( ξ , z ( ξ ) ) .
Then, the solution of (42) can be written as
z ( t ) = I a + α ; ψ F z ( t ) + Ψ q 1 ( t ) Λ [ Λ 22 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) Λ 12 G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) ] + Ψ q 2 ( t ) Λ [ Λ 11 G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) Λ 21 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) ] + I a + α ; ψ v ( t ) + Ψ γ 1 ( t ) Λ Λ 22 i = 1 m μ i I a + α θ i ; ψ v ( κ i ) + Λ 12 j = 1 n φ j I a + α ϕ j ; ψ v ( ς j ) + Ψ γ 2 ( t ) Λ Λ 11 j = 1 n φ j I a + α ϕ j ; ψ v ( ς j ) + Λ 21 i = 1 m μ i I a + α θ i ; ψ v ( κ i ) .
Remark 2 ( i ) implies that
z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) = | I a + α ; ψ v ( t ) + Ψ γ 1 ( t ) Λ Λ 22 i = 1 m μ i I a + α θ i ; ψ v ( κ i ) + Λ 12 j = 1 n φ j I a + α ϕ j ; ψ v ( ς j ) + Ψ γ 2 ( t ) Λ Λ 11 j = 1 n φ j I a + α ϕ j ; ψ v ( ς j ) + Λ 21 i = 1 m μ i I a + α θ i ; ψ v ( κ i ) | { Ψ α ( b ) + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | Ψ α θ i ( κ i ) + 1 | Λ | | Λ 11 | Ψ γ 2 ( b ) + | Λ 12 | Ψ γ 1 ( b ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) } ϵ
= Ψ α ( b ) + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | Ψ α θ i ( κ i ) + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | Ψ α ϕ j ( ς j ) ϵ = Ω ( α ) ϵ .
Lemma 7 is obtained. □
Now, we prove the UH and GUH stability of solution to the ψ -Hilfer FBVP describing the CB model (4).
Theorem 3.
Let f : J × R 3 R be continuous, and let ( A 1 ) ( A 2 ) be verified with
1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) < 1 .
Then, the ψ-Hilfer FBVP describing the CB model (4) is UH and GUH -stable in E .
Proof. 
Let z E be the solution of (32) and x E be a unique solution of the ψ -Hilfer fractional differential equation describing CB model (4) with the nonlinear boundary conditions of the form x ( a ) = 0 , H D a + δ , ρ ; ψ x ( a ) = 0 , i = 1 m μ i H D a + θ i , ρ ; ψ x ( κ i ) = H ( η , x ( η ) ) , j = 1 n φ j H D a + ϕ j , ρ ; ψ x ( ς j ) = G ( ξ , x ( ξ ) ) .
From Lemma 4, we obtain x ( t ) = χ x ( t ) + I a + α ; ψ F x ( t ) , where
χ x ( t ) = Ψ γ 1 ( t ) Λ [ Λ 22 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) Λ 12 G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j ) ] + Ψ γ 2 ( t ) Λ [ Λ 11 ( G ( ξ , x ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F x ( ς j ) ) Λ 21 H ( η , x ( η ) ) i = 1 m μ i I a + α θ i ; ψ F x ( κ i ) ] .
Moreover, if x ( a ) = z ( a ) , H D a + δ , ρ ; ψ x ( a ) = H D a + δ , ρ ; ψ z ( a ) , H D a + θ i , ρ ; ψ x ( κ i ) = H D a + θ i , ρ ; ψ z ( κ i ) , H D a + ϕ j , ρ ; ψ x ( ς j ) = H D a + ϕ j , ρ ; ψ z ( ς j ) , H ( η , x ( η ) ) = H ( η , z ( η ) ) , and G ( ξ , x ( ξ ) ) = G ( ξ , z ( ξ ) ) , then χ x ( t ) = χ z ( t ) . By applying the inequality, | x + y | | x | + | y | , and Lemma 7, for t J , we have
| z ( t ) x ( t ) | = | z ( t ) χ x ( t ) I a + α ; ψ F x ( t ) | | z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) | + I a + α ; ψ | F z ( t ) F x ( t ) | + | χ z ( t ) χ x ( t ) | Ω ( α ) ϵ + 1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) | z ( t ) x ( t ) | ,
which implies that | z ( t ) x ( t ) | C f ϵ , where
C f : = Ω ( α ) 1 1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) .
Then, the ψ -Hilfer FBVP describing the CB model (4) is UH -stable. Furthermore, if we take K ( ϵ ) = C f ϵ with K ( 0 ) = 0 , then the ψ -Hilfer FBVP describing the CB model (4) is GUH -stable. □

4.2. The UHR and GUHR Stability Results

This lemma will be used in the proofs of UHR and GUHR stability of our results.
Lemma 8.
Let α ( 3 , 4 ] , ρ [ 0 , 1 ] , and let z E be the solution of (34). Then, z E is verifies
z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) Θ ϵ λ K K ( t ) ,
where
Θ = 1 + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | ,
and χ z ( t ) is defined by (41).
Proof. 
Let z be a solution of (34). Thanks to Remark 3 (ii) and Lemma 4, the solution of
H D a + α , ρ ; ψ z ( t ) = F z ( t ) + w ( t ) t ( a , b ) , z ( a ) = 0 , H D a + δ , ρ ; ψ z ( a ) = 0 , i = 1 m μ i H D a + θ i , ρ ; ψ z ( κ i ) = H ( η , z ( η ) ) , j = 1 n φ j H D a + ϕ j , ρ ; ψ z ( ς j ) = G ( ξ , z ( ξ ) ) ,
can be written in the form:
z ( t ) = I a + α ; ψ F z ( t ) + Ψ γ 1 ( t ) Λ [ Λ 22 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) Λ 12 G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) ] + Ψ γ 2 ( t ) Λ [ Λ 11 ( G ( ξ , z ( ξ ) ) j = 1 n φ j I a + α ϕ j ; ψ F z ( ς j ) ) Λ 21 H ( η , z ( η ) ) i = 1 m μ i I a + α θ i ; ψ F z ( κ i ) ] + I a + α ; ψ w ( t ) + Ψ γ 1 ( t ) Λ Λ 22 i = 1 m μ i I a + α θ i ; ψ w ( κ i ) + Λ 12 j = 1 n φ j I a + α ϕ j ; ψ w ( ς j ) + Ψ γ 2 ( t ) Λ Λ 11 j = 1 n φ j I a + α ϕ j ; ψ w ( ς j ) + Λ 21 i = 1 m μ i I a + α θ i ; ψ w ( κ i ) .
By using Remark 3 ( i ) with Remark 4, we obtain the following estimation:
z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) = | I a + α ; ψ w ( t ) + Ψ γ 1 ( t ) Λ Λ 22 i = 1 m μ i I a + α θ i ; ψ w ( κ i ) + Λ 12 j = 1 n φ j I a + α ϕ j ; ψ w ( ς j ) + Ψ γ 2 ( t ) Λ Λ 11 j = 1 n φ j I a + α ϕ j ; ψ w ( ς j ) + Λ 21 i = 1 m μ i I a + α θ i ; ψ w ( κ i ) | { 1 + 1 | Λ | | Λ 22 | Ψ γ 1 ( b ) + | Λ 21 | Ψ γ 2 ( b ) i = 1 m | μ i | + 1 | Λ | | Λ 12 | Ψ γ 1 ( b ) + | Λ 11 | Ψ γ 2 ( b ) j = 1 n | φ j | } ϵ λ K K ( t ) = 1 + Φ ( Λ 22 , Λ 21 ) i = 1 m | μ i | + Φ ( Λ 12 , Λ 11 ) j = 1 n | φ j | ϵ λ K K ( t ) = Θ ϵ λ K K ( t ) .
Lemma 8 is obtained. □
Next, we establish the UHR and GUHR stability of the solution to the ψ -Hilfer FBVP describing the CB model (4).
Theorem 4.
Let f : J × R 3 R be a continuous under ( A 1 ) ( A 2 ) and let (39) be fulfilled. If
1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) < 1 ,
then the ψ-Hilfer FBVP describing CB model (4) is UHR and GUHR -stable in E .
Proof. 
Let z E be the solution of (34) and x be a unique solution of (4). Thanks to Lemma 8, we obtain
x ( t ) = χ x ( t ) + I a + α ; ψ F x ( t ) ,
where χ x ( t ) is given by (43). Similarly, if H D a + δ , ρ ; ψ x ( a ) = H D a + δ , ρ ; ψ z ( a ) , H D a + θ i , ρ ; ψ x ( κ i ) = H D a + θ i , ρ ; ψ z ( κ i ) , H D a + ϕ j , ρ ; ψ x ( ς j ) = H D a + ϕ j , ρ ; ψ z ( ς j ) , x ( a ) = z ( a ) , H ( η , x ( η ) ) = H ( η , z ( η ) ) , and G ( ξ , x ( ξ ) ) = G ( ξ , z ( ξ ) ) , then χ x ( t ) = χ z ( t ) . Applying the triangle inequality with Lemma 8, for t J , we estimate
| z ( t ) x ( t ) | = | z ( t ) χ x ( t ) I a + α ; ψ F x ( t ) | | z ( t ) χ z ( t ) I a + α ; ψ F z ( t ) | + I a + α ; ψ | F z ( s ) F x ( s ) | ( t ) + | χ z ( t ) χ x ( t ) | Θ ϵ λ K K ( t ) + 1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) | z ( t ) x ( t ) | ,
where Θ is defined by (44). Then, | z ( t ) x ( t ) | C f , K K ( t ) ϵ with
C f , K = Θ λ K 1 1 1 L 2 L 1 Ψ α ( b ) + L 3 Ψ β + α ( b ) .
Hence, this proves that the ψ -Hilfer FBVP describing the CB model (4) is UHR -stable. Moreover, if we set ϵ = 1 with K ( 0 ) = 0 , then the ψ -Hilfer FBVP describing CB model (4) is GUHR -stable. □

5. Examples

This section contains several illustrated cases to highlight the relevance of our findings in this study.
Example 1.
Consider the following ψ-Hilfer fractional differential equation describing the CB model with nonlinear boundary conditions
H D 0 + 7 2 , 7 10 ; sin π t 2 t + 2 x ( t ) = f ( t , x ( t ) , H D 0 + 7 2 , 7 10 ; sin π t 2 t + 2 x ( t ) , I 0 + 5 2 ; sin π t 2 t + 2 x ( t ) ) , x ( 0 ) = 0 , H D 0 + 17 10 , 7 10 ; sin π t 2 t + 2 x ( 0 ) = 0 , i = 1 2 i i + 1 H D a + 2 i + 1 10 , 7 10 ; sin π t 2 t + 2 x 4 i 2 2 i + 5 = H 4 5 , x 4 5 , j = 1 3 7 2 j 9 j H D a + 30 2 j 10 , 7 10 ; sin π t 2 t + 2 x 3 i 1 10 = G 11 10 , x 11 10 .
Here, α = 7 / 2 , ρ = 7 / 10 , ψ ( t ) = sin ( π t / ( 2 t + 2 ) ) , β = 5 / 2 , a = 0 , b = 6 / 5 , δ = 17 / 10 , μ i = i / ( i + 1 ) , θ i = ( 2 i + 1 ) / 10 , κ i = ( 4 i 2 ) / ( 2 i + 5 ) , η = 4 / 5 , φ j = ( 7 2 j ) / ( 9 j ) , ϕ j = ( 30 2 j ) / 10 , ς j = ( 3 j 1 ) / 10 , ξ = 11 / 10 , i = 1 , 2 , and j = 1 , 2 , 3 . From the given information, we can approximate that Λ 11 0.0768702 , Λ 12 0.3392374 , Λ 21 1.1518998 , Λ 22 0.4227044 , and Λ 0.3582742 0 .
(i) 
Consider the nonlinear function
f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) = sin ( t 4 + 2 ) 3 t 2 + 5 t + 1 + e t + 5 6 cos 2 π t · | x ( t ) | 4 + | x ( t ) |
+ ( 5 t 4 ) 2 4 | H D a + α , ρ ; ψ x ( t ) | 21 + | H D a + α , ρ ; ψ x ( t ) | + | I a + β ; ψ x ( t ) | 22 + | I a + β ; ψ x ( t ) | ,
and the nonlinear conditions
H 4 5 , x 4 5 = x 4 5 20 + 3 x 4 5 , G 11 10 , x 11 10 = x 11 10 + 2 30 .
For u i , v i , w i R , i = 1 , 2 , and t [ 0 , 6 / 5 ] , we can find that
f ( t , u 1 , v 1 , w 1 ) f ( t , u 2 , v 2 , w 2 ) 1 20 | u 1 u 2 | + 1 21 | v 1 v 2 | + 1 22 | w 1 w 2 | ,
and
H ( t , u 1 ) H ( t , u 2 ) 1 20 | u 1 u 2 | , G ( t , u 1 ) G ( t , u 2 ) 1 30 | u 1 u 2 | .
The assumption ( A 1 ) ( A 2 ) is satisfied with L 1 = 1 / 20 , L 2 = 1 / 21 , L 3 = 1 / 22 , H 1 = 1 / 20 and G 1 = 1 / 30 . For the given information, we have Ω ( α ) 0.1575972 , Ω ( β + α ) 0.0016180 , Φ ( Λ 12 , Λ 11 ) 0.1585503 , Φ ( Λ 22 , Λ 21 ) 0.1585503 , and Φ ( Λ 12 , Λ 11 ) 1.2012770 . Hence,
( 1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 ) 0.0736999 < 1 .
Since all the assumptions of Theorem 1 are fulfilled, the ψ-Hilfer FBVP describing the CB model (46) has a unique solution on 0 , 6 / 5 with (47) and (48). Furthermore, we can also compute the positive constant C f 0.1578672 > 0 . By the conclusions of Theorem 3, the ψ-Hilfer FBVP describing the CB model (46) is both UH - and also GUH -stable on [ 0 , 6 / 5 ] with (47) and (48). By setting K ( t ) = ( ψ ( t ) ψ ( a ) ) 1 / 2 and Proposition 1 (i), we have
I a + α ; ψ K ( t ) = Γ ( 3 / 2 ) Γ 3 / 2 + α ( ψ ( t ) ψ ( a ) ) 1 2 + α π ψ ( 6 / 5 ) ψ ( 0 ) α 2 Γ 3 / 2 + α K ( t ) .
Then, the inequality (39) is satisfied with λ K = π sin 3 π 11 sin 0 7 / 2 48 0.0138566 > 0 and Θ 2.5949589 . We obtain C f , K 0.0360189 > 0 . Therefore, by all assumptions of Theorem 4, the ψ-Hilfer FBVP describing the CB model (46) is both UHR - and GUHR -stable on [ 0 , 6 / 5 ] with (47) and (48).
(ii) 
Consider the nonlinear function
f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) = | t 2 3 t | 2 t + 1 + ln | t + 5 | e cosh π t sin ( x ( t ) )
+ 2 + cos 2 π t 4 t + 3 | H D a + α , ρ ; ψ x ( t ) + I a + β ; ψ x ( t ) | .
For u, v, w R , and t [ 0 , 6 / 5 ] , we can estimate
| f ( t , u , v , w ) | | t 2 3 t | 2 t + 1 + ln | 5 t | e cosh π t | u | + 2 + cos 2 π t 4 t + 3 | v | + 2 + cos 2 π t 4 t + 3 | w |
and
| H ( t , u ) | | u | 20 , | G ( t , u ) | 2 30 + | u | 30 .
The assumptions ( A 3 ) ( A 4 ) is true with p 1 ( t ) = | t 2 3 t | / ( 2 t + 1 ) , p 2 ( t ) = ( ln | 5 t | ) / e cosh π t , p 3 ( t ) = p 4 ( t ) = ( 2 + cos 2 π t ) / ( 4 t + 3 ) , h 1 ( t ) = 0 , h 2 ( t ) = 1 / 20 , g 1 ( t ) = 2 / 30 and g 2 ( t ) = 1 / 30 . Therefore, all the assumptions of Theorem 2 are satisfied, which leads to the conclusion that the ψ-Hilfer FBVP describing CB model (46) has at least one solution on [ 0 , 6 / 5 ] with (48) and (49). For u i , v i , w i R , i = 1 , 2 , and t [ 0 , 6 / 5 ] , we can find that
f ( t , u 1 , v 1 , w 1 ) f ( t , u 2 , v 2 , w 2 ) ln ( 5 ) 8 e | u 1 u 2 | + 1 2 | v 1 v 2 | + 1 2 | w 1 w 2 | .
The assumption ( A 1 ) ( A 2 ) is satisfied with L 1 = ln ( 5 ) / 8 e , L 2 = L 3 = 1 / 2 , H 1 = 1 / 20 and G 1 = 1 / 30 . Hence,
( 1 1 L 2 L 1 Ω ( α ) + L 3 Ω ( β + α ) + Φ ( Λ 22 , Λ 21 ) H 1 + Φ ( Λ 12 , Λ 11 ) G 1 ) 0.0902944 < 1 .
Since all the assumptions of Theorem 1 are fulfilled, the ψ-Hilfer FBVP describing CB model (46) has a unique solution on [ 0 , 6 / 5 ] with (48) and (49). Further, we can also compute that C f 0.1580267 > 0 . By the conclusions of Theorem 3, the ψ-Hilfer FCB model (46) is both UH - and also GUH -stable on [ 0 , 6 / 5 ] with (48) and (49). By setting K ( t ) = ψ ( t ) ψ ( 0 ) 3 / 2 and Proposition 1 (i), one has
I a + α ; ψ K ( t ) = 3 π 4 Γ 5 2 + α ( ψ ( t ) ψ ( a ) ) 3 2 + α 3 π ψ ( 6 / 5 ) ψ ( 0 ) α 4 Γ 5 2 + α K ( t ) .
Then, the inequality (39) is satisfied with λ K = π sin 3 π 11 sin 0 7 / 2 160 0.0041570 > 0 and Θ 2.5949589 . One has C f , K 0.0108166 > 0 . Therefore, by all assumptions of Theorem 4, the ψ-Hilfer FBVP describing CB model (46), is both UHR - and also GUHR -stable on [ 0 , 6 / 5 ] with (48) and (49).
(iii) 
Consider the function F x ( t ) = f ( t , x ( t ) , H D a + α , ρ ; ψ x ( t ) , I a + β ; ψ x ( t ) ) = 1 , and the nonlinear conditions H ( η , x ( η ) ) = G ( ξ , x ( ξ ) ) = 1 . By Lemma 4, the implicit solution of the ψ-Hilfer FBVP describing the CB model (46) is given by
x ( t ) = ψ ( t ) ψ ( 0 ) α Γ ( α + 1 ) + ψ ( t ) ψ ( 0 ) γ 1 Λ Γ ( γ ) [ Λ 22 1 i = 1 m μ i ψ ( κ i ) ψ ( 0 ) α θ i Γ ( α θ i + 1 ) Λ 12 1 j = 1 n φ j ψ ( ς j ) ψ ( 0 ) α ϕ j Γ ( α ϕ j + 1 ) ] + ψ ( t ) ψ ( a ) γ 2 Λ Γ ( γ 1 ) [ Λ 11 1 j = 1 n φ j ψ ( ς j ) ψ ( 0 ) α ϕ j Γ ( α ϕ j + 1 ) Λ 21 1 i = 1 m μ i ψ ( κ i ) ψ ( 0 ) α θ i Γ ( α θ i + 1 ) ] .
(1)
If ψ 1 ( t ) = 1 α t 3 / 2 , then the solution of the ψ-Hilfer FBVP describing CB model (46) is defined by
x ( t ) = t 3 α / 2 α α Γ ( α + 1 ) + t 3 ( γ 1 ) / 2 α γ 1 Λ Γ ( γ ) [ Λ 22 1 i = 1 m μ i κ i 3 ( α θ i ) / 2 α α θ i Γ ( α θ i + 1 ) Λ 12 1 j = 1 n φ j ς j 3 ( α ϕ j ) / 2 α α ϕ j Γ ( α ϕ j + 1 ) ] + t 3 ( γ 2 ) / 2 α γ 2 Λ Γ ( γ 1 ) [ Λ 11 1 j = 1 n φ j ς j 3 ( α ϕ j ) / 2 α α ϕ j Γ ( α ϕ j + 1 ) Λ 21 1 i = 1 m μ i κ i 3 ( α θ i ) / 2 α α θ i Γ ( α θ i + 1 ) ] , t ( 0 , 6 / 5 ] .
(2)
If ψ 2 ( t ) = log ( t + 1 ) α , then the solution of the ψ-Hilfer FBVP describing the CB model (46) is defined by
x ( t ) = log ( t + 1 ) α α α Γ ( α + 1 ) + log ( t + 1 ) γ 1 α γ 1 Λ Γ ( γ ) [ Λ 22 1 i = 1 m μ i log ( κ i + 1 ) α θ i α α θ i Γ ( α θ i + 1 ) Λ 12 1 j = 1 n φ j log ( ς j + 1 ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) ] + log ( t + 1 ) γ 2 α γ 2 Λ Γ ( γ 1 ) [ Λ 11 1 j = 1 n φ j log ( ς j + 1 ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) Λ 21 1 i = 1 m μ i log ( κ i + 1 ) α θ i α α θ i Γ ( α θ i + 1 ) ] , t ( 0 , 6 / 5 ] .
(3)
If ψ 3 ( t ) = 1 α e 2 t then the solution of the ψ-Hilfer FBVP describing the CB model (46) is defined by
x ( t ) = ( e 2 t 1 ) α α α Γ ( α + 1 ) + ( e 2 t 1 ) γ 1 α γ 1 Λ Γ ( γ ) [ Λ 22 1 i = 1 m μ i ( e 2 κ i 1 ) α θ i α α θ i Γ ( α θ i + 1 ) Λ 12 1 j = 1 n φ j ( e 2 ς j 1 ) ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) ] + ( e 2 t 1 ) γ 2 α γ 2 Λ Γ ( γ 1 ) [ Λ 11 1 j = 1 n φ j ( e 2 ς j 1 ) ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) Λ 21 1 i = 1 m μ i ( e 2 κ i 1 ) ) α θ i α α θ i Γ ( α θ i + 1 ) ] , t ( 0 , 6 / 5 ] .
(4)
If ψ 4 ( t ) = sin α ( π t 4 ) α , then the solution of the ψ-Hilfer FBVP describing the CB model (46) is defined by
x ( t ) = sin α ( π t 4 ) α α α Γ ( α + 1 ) + sin α ( π t 4 ) γ 1 α γ 1 Λ Γ ( γ ) [ Λ 22 1 i = 1 m μ i sin α ( π κ i 4 ) α θ i α α θ i Γ ( α θ i + 1 ) Λ 12 1 j = 1 n φ j sin α ( π ς j 4 ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) ] + sin α ( π t 4 ) γ 2 α γ 2 Λ Γ ( γ 1 ) [ Λ 11 1 j = 1 n φ j sin α ( π ς j 4 ) α ϕ j α α ϕ j Γ ( α ϕ j + 1 ) Λ 21 1 i = 1 m μ i sin α ( π κ i 4 ) α θ i α α θ i Γ ( α θ i + 1 ) ] , t ( 0 , 6 / 5 ] .
A graph representing the solution of the ψ-Hilfer FBVP describing CB model (46) with various values of α = 31 10 , 33 10 , 35 10 , 37 10 , 39 10 , and 40 10 involving a variety of functions ψ 1 ( t ) = 1 α t 3 / 2 , ψ 2 ( t ) = 1 α log ( t + 1 ) , ψ 3 ( t ) = 1 α e 2 t , and ψ 4 ( t ) = 1 α sin α ( π t 4 ) , is shown in Figure 1, Figure 2, Figure 3, Figure 4, Figure 5, Figure 6, Figure 7 and Figure 8.

6. Conclusions

We analyzed the existence and uniqueness of solutions for a class of a nonlinear implicit ψ -Hilfer fractional integro-differential equation subjected to nonlinear boundary conditions describing the CB model. The uniqueness result is established using Banach’s fixed point theorem, while the existence result is established using Schaefer’s fixed point theorem, both of which are well-known fixed point theorems. Ulam’s stability is also demonstrated in several ways, including UH stability, GUH stability, UHR stability, and GUHR stability. Finally, the numerical examples have been carefully selected to demonstrate how the results can be used. Moreover, the ψ -Hilfer FBVP describing the CB model (4) not only includes the identified previously works about a variety of boundary value problems. As special cases for various values ρ and ψ , the considered problem does cover a large range of many problems as: the Riemann–Liouville-type problem for ρ = 0 and ψ ( t ) = t , the Caputo-type problem for ρ = 1 and ψ ( t ) = t , the ψ -Riemann–Liouville-type problem for ρ = 0 , the ψ -Caputo-type problem for ρ = 1 , the Hilfer-type problem for ψ ( t ) = t , the Hilfer–Hadamard-type problem for ψ ( t ) = log ( t ) , and the Katugampola-type problem for ψ ( t ) = t q .
As a result, the fixed point technique is a powerful tool to investigate different nonlinear problems, which is very important in various qualitative theories. The present work is innovative and attractive and significantly contributes to the body of knowledge on ψ -Hilfer fractional differential equations and inclusions for researchers. In addition, our results are novel and intriguing for the elastic beam problem emerging from mathematical models of engineering and applied science.

Author Contributions

Conceptualization, K.K., W.S., C.T., J.K. and J.A.; methodology, K.K., W.S., C.T., J.K. and J.A.; software, K.K., W.S. and C.T.; validation, K.K., W.S., C.T., J.K. and J.A.; formal analysis, K.K., W.S. and J.A.; investigation, K.K., W.S., C.T., J.K. and J.A.; resources, K.K., W.S., C.T., J.K. and J.A.; data curation, K.K., W.S., C.T., J.K. and J.A.; writing—original draft preparation, K.K., W.S., C.T., J.K. and J.A.; writing—review and editing, W.S., C.T., J.K. and J.A.; visualization, K.K., W.S., C.T., J.K. and J.A.; supervision, W.S., C.T. and J.A.; project administration, K.K., W.S. and J.K.; funding acquisition, K.K. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Institutional Review Board Statement

Not applicable.

Informed Consent Statement

Not applicable.

Data Availability Statement

Data sharing not applicable.

Acknowledgments

K. Kotsamran was partially supported by Kasetsart University, Chalermphrakiat Sakon Nakhon Province Campus. C. Thaiprayoon and J. Kongson would like to express thanks to Burapha University and the Center of Excellence in Mathematics (CEM), CHE, Sri Ayutthaya Rd., Bangkok, 10400, Thailand. J. Alzabut is thankful to Prince Sultan University and OSTİM Technical University for their support.

Conflicts of Interest

The authors declare that they have no competing interests.

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Figure 1. The graph of the solution x ( t ) with ψ 1 ( t ) = 1 α t 3 / 2 and c = 1.5 .
Figure 1. The graph of the solution x ( t ) with ψ 1 ( t ) = 1 α t 3 / 2 and c = 1.5 .
Fractalfract 05 00177 g001
Figure 2. The graph of the function ψ 1 ( t ) = 1 α t 3 / 2 with c = 1.5 .
Figure 2. The graph of the function ψ 1 ( t ) = 1 α t 3 / 2 with c = 1.5 .
Fractalfract 05 00177 g002
Figure 3. The graph of the solution x ( t ) with ψ 2 ( t ) = 1 α log ( t + 1 ) and c = 0.5 .
Figure 3. The graph of the solution x ( t ) with ψ 2 ( t ) = 1 α log ( t + 1 ) and c = 0.5 .
Fractalfract 05 00177 g003
Figure 4. The graph of the function ψ 2 ( t ) = 1 α log ( t + 1 ) with c = 0.5 .
Figure 4. The graph of the function ψ 2 ( t ) = 1 α log ( t + 1 ) with c = 0.5 .
Fractalfract 05 00177 g004
Figure 5. The graph of the solution x ( t ) with ψ 3 ( t ) = 1 α e 2 t and c = 2 .
Figure 5. The graph of the solution x ( t ) with ψ 3 ( t ) = 1 α e 2 t and c = 2 .
Fractalfract 05 00177 g005
Figure 6. The graph of the function ψ 3 ( t ) = 1 α e 2 t with c = 2 .
Figure 6. The graph of the function ψ 3 ( t ) = 1 α e 2 t with c = 2 .
Fractalfract 05 00177 g006
Figure 7. The graph of the solution x ( t ) with ψ 4 ( t ) = 1 α sin α ( π t 4 ) and c = π 4 .
Figure 7. The graph of the solution x ( t ) with ψ 4 ( t ) = 1 α sin α ( π t 4 ) and c = π 4 .
Fractalfract 05 00177 g007
Figure 8. The graph of the function ψ 4 ( t ) = 1 α sin α ( π t 4 ) with c = π 4 .
Figure 8. The graph of the function ψ 4 ( t ) = 1 α sin α ( π t 4 ) with c = π 4 .
Fractalfract 05 00177 g008
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Kotsamran, K.; Sudsutad, W.; Thaiprayoon, C.; Kongson, J.; Alzabut, J. Analysis of a Nonlinear ψ-Hilfer Fractional Integro-Differential Equation Describing Cantilever Beam Model with Nonlinear Boundary Conditions. Fractal Fract. 2021, 5, 177. https://doi.org/10.3390/fractalfract5040177

AMA Style

Kotsamran K, Sudsutad W, Thaiprayoon C, Kongson J, Alzabut J. Analysis of a Nonlinear ψ-Hilfer Fractional Integro-Differential Equation Describing Cantilever Beam Model with Nonlinear Boundary Conditions. Fractal and Fractional. 2021; 5(4):177. https://doi.org/10.3390/fractalfract5040177

Chicago/Turabian Style

Kotsamran, Kanoktip, Weerawat Sudsutad, Chatthai Thaiprayoon, Jutarat Kongson, and Jehad Alzabut. 2021. "Analysis of a Nonlinear ψ-Hilfer Fractional Integro-Differential Equation Describing Cantilever Beam Model with Nonlinear Boundary Conditions" Fractal and Fractional 5, no. 4: 177. https://doi.org/10.3390/fractalfract5040177

APA Style

Kotsamran, K., Sudsutad, W., Thaiprayoon, C., Kongson, J., & Alzabut, J. (2021). Analysis of a Nonlinear ψ-Hilfer Fractional Integro-Differential Equation Describing Cantilever Beam Model with Nonlinear Boundary Conditions. Fractal and Fractional, 5(4), 177. https://doi.org/10.3390/fractalfract5040177

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