To validate the use of the third-order hydrodynamic pressure in Equation (18), the wave conditions specified in
Table 3 must fall into the category of the Stokes third-order waves. For this, three wave periods (
T = 12 s, 15 s, 17 s) are examined.
Table 4 presents the corresponding
H/gT2 and
d/gT2 that are non-dimensional parameters in the well-known chart by Le Méhauté [
50] in
Figure 8. Obviously, the Stokes third-order wave model is applicable to these three regular waves. Thus, in the presence of a current, it is reasonable to apply Equation (18) to account for the effect of wave-current interactions on hydrodynamic pressure.
The liquefaction criterion proposed by Zen and Yamazaki [
51] is employed to study the maximum instantaneous liquefaction depth, i.e.,
where
γsat and
γw are the saturation unit weight of seabed soil and the unit weight of water, respectively. Equation (60) indicates that when the excess pore pressure −(
psb −
p) induced by wave--current interactions is no less than the initial vertical effective stress (
γsat −
γw)
z, the soil skeleton will enter a liquefied state.
5.1. Single-Layered Seabed
Figure 9 illustrates the vertical distributions of normalized maximum pore pressure |
p|, shear stress |
τxz|, and vertical and horizontal effective stress |
| and |
| for various vertical-to-horizontal permeability coefficient ratios
Kv/Kh, where
pmax denotes the maximum hydrodynamic pressure acting on the mudline (
z = 0). The horizontal permeability coefficient
Kh is fixed with 1 × 10
−4 m/s, and the vertical permeability coefficient
Kv varies. In
Figure 9, the vertical distributions of |
p|, |
| and |
| are influenced by
Kv/
Kh. The larger the ratio, the greater the influence on these three quantities. However, the vertical distribution of |
τxz| is hardly affected by
Kv/Kh within a range from 0.5 to 100. When
Kv/
Kh is small (0.5, 1, 2), it has little influence on the vertical distribution of |
p|, |
| and |
| for
z/h > 0.2. Similar results under linear wave conditions were drawn by Li et al. [
38].
Figure 10 demonstrates the relationship between the maximum liquefaction depth
zmax versus
Kv/
Kh for various soil and wave parameters. The effects of the degree of saturation
Sr, wave period
T, soil porosity
n, and current velocity
U0 on
zmax are studied. It can be observed that
zmax decreases almost linearly with
Kv/
Kh. Under the same
Kv/
Kh,
zmax increases with decreasing
Sr, increasing
n and decreasing
T. As for
U0, a following current helps to raise the liquefaction depth while an opposing current reduces the liquefaction depth. Particularly,
Figure 10a shows that
zmax becomes less sensitive to
Kv/
Kh when
Sr gets smaller. Moreover, it illustrates that when
Kv/
Kh > 1,
zmax would be overestimated using an isotropic model (
Kv/
Kh = 1), and vice versa, underestimated for
Kv/
Kh < 1.
The effects of
Ev/Eh on the vertical distributions of normalized |
p|, |
τxz|, |
| and |
| are also studied, as shown in
Figure 11. Here,
Eh = 2.6 × 10
7 Pa, while
Ev varies. Unlike
Kv/
Kh,
Ev/Eh affects not only the vertical distributions of all |
p|, |
|, and |
| but also |
τxz|. However, with the increase in
Ev/Eh (from 0.5 to 2), the normalized |
p|, |
τxz|, and |
| at the same depth all basically decrease, while |
| increases. Meanwhile, the influences of
Ev/Eh on the normalized |
p|, |
τxz|, |
| and |
| all decay with the increase in
Ev/Eh.
Figure 12 denotes
zmax versus
Ev/
Eh for various
Sr,
T,
n, and
U0. On the contrary to the effect of
Kv/
Kh,
zmax increases with
Ev/
Eh, showing the tendency of more severe liquefaction. For the same
Ev/
Eh,
zmax increases with decreasing
Sr and
T but increasing
n. Similar to the effect of
Kv/
Kh, the following current aggravates the liquefaction depth whilst the opposing current alleviates the liquefaction depth. It is obvious that even though |
U0| is equal, the direction of the current can lead to varying degrees of change in
zmax. Besides, if the seabed is regarded as isotropic,
zmax would be underestimated when
Ev/
Eh > 1 but overestimated when
Ev/
Eh < 1.
Figure 13 shows the vertical distributions of normalized |
p|, |
τxz|, |
|, and |
| for various ratios of vertical shear modulus to vertical Young’s modulus
Gv/Ev, where
Gv/Ev = 1/2.6 and corresponds to the isotropic case. A fixed value of
Ev = 2.6 × 10
7 Pa is chosen. Similar to
Ev/
Eh,
Gv/Ev changes all vertical distributions of |
p|, |
τxz|, |
|, and |
|. Especially,
zmax at |
| = 0 is more significantly affected by
Gv/Ev than by
Kv/
Kh and
Ev/
Eh, referring to
Figure 9d,
Figure 11d, and
Figure 13d.
Figure 14 indicates that for various
Sr,
T,
n, and
U0,
zmax decreases with growing
Gv/
Ev. At a given
Gv/
Ev,
zmax increases with decreasing
Sr and
T but increasing
n.
Figure 14d shows that
zmax under the following current is also greater than under the opposing current. Additionally, assuming an isotropic seabed,
zmax would be underestimated when
Gv/
Ev < 2(1 +
v) but overestimated when
Gv/
Ev > 2(1 +
v).
From the above discussion, brief conclusions can be drawn. The responses of pore pressure and effective stress are more sensitive to the anisotropic characteristics of
Ev/
Eh and
Gv/Ev than to
Kv/
Kh. A lower quasi-saturation rate of
Sr = 0.97, higher porosity, shorter wave period, and a following current would result in the aggravation of the maximum liquefaction depth. Furthermore, as shown in
Figure 10a,
Figure 12a, and
Figure 14a, for a large
Ev/
Eh and small
Kv/
Kh and
Gv/
Ev, the liquefaction can still happen even if the TIP seabed is fully saturated (
Sr = 1). This is different from the conclusions drawn by Rahman [
52] that the transient liquefaction does not occur in fully saturated isotropic sediments. Like the soil studied by Rahman [
52], the seabed layers in this study are cohesionless because the adopted permeability coefficients fall into the empirically cohesionless range [
53]. For example, in
Figure 10a, liquefaction occurs when
Sr = 1 and
Kv/Kh = 0.5, i.e.,
Kv = 5 × 10
−5 m/s and
Kh = 1 × 10
−4 m/s. In
Figure 12a and
Figure 14a, where
Kv and
Kh are fixed to 1 × 10
−4 m/s, the liquefaction does occur when
Sr = 1. The permeability coefficients in these three figures are categorized by clean sand or clean sand and gravel mixtures which are essentially cohesionless sediments in Table 14.1, according to Terzaghi et al. [
53]. Thus, the importance of transverse isotropy is manifested, especially for the liquefaction assessment under wave-current loading.
Similar to the present study, Jeng [
35] did not emphasize the role of soil cohesion, although the treated medium was actually cohesionless in terms of permeability coefficients. It also used parameters of
Kv/
Kh,
Ev/
Eh, and
Gv/Ev to characterize the anisotropic soil. A similar conclusion that liquefaction did not occur in fully saturated (
Sr = 1) sediments was determined in Jeng [
35]. To dig out the reason for Jeng’s conclusion, which seems contradictory to this study, an elaborate numerical test was conducted, as shown in
Table 5. The ratio
Ev/
Eh from 0.4 to 2.5 is taken as a variable. The analytical solution proposed by Li et al. [
38] of an infinite thickness single-layered seabed is adopted. The wave conditions and TIP soil properties by Jeng [
35] are shown in
Table 6.
Table 5 illustrates that an infinite thickness seabed under linear waves only—which is exactly Jeng’s assumption—would not liquefy. However, the calculation results in this study show that liquefaction occurs in nonlinear waves, especially in soil with finite thickness. Among the 16 cases in
Table 5, only four cases yield liquefaction. These four cases correspond to the nonlinear wave model and finite thickness. The reasons for liquefaction in nonlinear waves and soil with finite thickness may be summarized as follows: (i) In a nonlinear wave, though the first-order (linear) hydrodynamic pressure is of the largest weight, the second- and third-order terms cannot be neglected, especially in a severe sea state. The greater the hydrodynamic pressure, the greater the possibility for liquefaction. (ii) An infinite seabed tends to dissipate more pore pressure and bear more effective stress than a finite seabed does. An infinite thickness seabed can be considered to consist of two layers of identical properties. The thickness of the upper layer is the same as that of a finite-thickness seabed. Then, the only difference between infinite and finite thickness seabeds lies in the lower layer. One is bedrock while the other is still soil. Therefore, the bedrock of a finite thickness seabed is impermeable, which is not the case in an infinite thickness seabed. This makes an infinite seabed tend to dissipate more pore pressure and bear more effective stress than a finite seabed. The greater the effective soil stress, the lesser the possibility for liquefaction.