Novel Faulted Section Location Method for Distribution Network Based on Status Information of Fault Indicating Equipment
Abstract
:1. Introduction
- The method in this paper is different from others which analyzed electrical quantity. It uses status information of fault-indicating equipment, so it does not need to analyze and calculate any electrical parameters, and it is not affected by the fault type or fault resistance.
- A line list is proposed in the method and it can be constructed automatically to represent the topology of the distribution network and status information of fault-indicating equipment. Moreover, it can be updated automatically when the topology of distribution network changes. Therefore, it is suitable for the distribution networks with frequent topology structure changes.
- A topology search algorithm is proposed in the method to locate the faulted section; it is not only applicable for single fault, but also for multiple faults on different branches. Simulation results indicate that the proposed topology search algorithm is suitable for distribution networks with distributed generations. Therefore, the fault location method in this paper is applicable for solving complex fault conditions in distribution networks.
- Considering that the loss of information may lead to errors in the line list, an information loss detection algorithm is proposed in the method to detect and correct the wrong status of fault-indicating equipments. It can eliminate the possibility of a local optimal solution for the topology search algorithm in advance, so it greatly improves the accuracy of fault location results.
- Based on amount of simulation results, the proposed fault location method has an advantage that the running time of algorithms does not necessarily increase when the node scale is expanded.
2. Description of Line Topology
2.1. Definition of Equipment Status
2.2. Construction of Line List
3. Fault Location Method
3.1. Topology Search Algorithm
- Step 1
- Set the initial values of k, j and m as 1; set the initial values of i and n as 0;
- Step 2
- Check the status of the kth FIE. If the status is “1”, then continue to the next step; if the status is not “1”, go to step 7;
- Step 3
- Check the quantity of the FIEs that are on the nearest downstream of the kth FIE. If there is only one equipment, then continue to the next step; if there are more than one piece of equipment, go to step 5; if there is no equipment, assign k to R[m] and set m = m + 1, then go to step 6;
- Step 4
- Check the status of the nearest downstream equipment. If the status is not “1”, assign k to R[m] and set m = m + 1, then go to step 6; if the status is “1”, then assign the equipment number of the downstream FIE to k and go back to step 3;
- Step 5
- Check the status of all the nearest downstream FIEs. If the status of all FIEs is not “1”, assign k to R[m] and set m = m + 1, then go to step 6; if the quantity of FIEs in status “1” is greater than 1, assign the quantity of FIEs in status “1” to n, and assign the numbers of them to A[i + 1], …, A[i + n] separately, then set i = i + n, go to step 6; if there is only one FIE in status “1”, assign its number to k and go back to step 3;
- Step 6
- Determine the magnitude of i and j. If j > i, go to step 7; otherwise, assign A[j] to k and set j = j + 1, then go back to step 3;
- Step 7
- Stop the iteration and output R[]. Each number in R[] means that there is a fault on the nearest downstream section of the fault-indicating equipment.
3.2. Information Loss Detection Algorithm
- Step 1
- Determine the maximum number of all triggered FIEs in the line list, and assign the value of quantity to a. Set the initial values of k and m as 1; set the initial values of j and n as 0;
- Step 2
- If k ≤ a, check the status of the kth FIE and continue to next step; if k > a, go to step 7;
- Step 3
- If the status of the kth FIE is “1”, set k = k + 1 and go back to step 2; if the status of the kth FIE is not “1”, check the status of the FIE which is on the nearest upstream of the kth FIE; if the status is “1”, continue to next step; otherwise, go to step 6;
- Step 4
- Check the quantity of the FIEs that are on the nearest downstream of the kth FIE, and assign the quantity of the FIEs to n. If n ≠ 0, assign the number of the nearest downstream FIE to B[j + 1], …, B[j + n] separately, then go to step 5; if n = 0, go to step 6;
- Step 5
- Check the status of all the FIE in B[]. If the status of all FIEs is not “1”, continue to next step; if the quantity of FIEs in status “1” is greater than 1 or equal to 1, assign k to L[m], set m = m + 1 and k = k + 1, then go back to step 2;
- Step 6
- Set k = k + 1, then go back to step 2;
- Step 7
- Stop the iteration and output L[]. Each equipment number in L[] means that the information of this FIE is lost, then correct the status of this FIE to “1”. If there are no equipment numbers in L[], it means there is no information loss equipment.
4. Simulation Analysis
4.1. Test Case 1: Single Fault
4.2. Test Case 2: Multiple Faults
4.3. Test Case 3: DGs in Power Distribution Network
4.4. Test Case 4: Information Loss Condition
5. Discussion
5.1. Comparison with Other Fault Location Methods
- The proposed fault location method is not only applicable for single fault, but also for multiple faults at the same time.
- The simulation results show that the proposed method can also effectively locate the fault point when there are distributed generations in the distribution network.
- The line list proposed in the method can be updated automatically when the topology of distribution network changes, so it is suitable for the distribution networks with the topology structure changes frequently.
- The information loss detection algorithm can report the fault-indicating equipment with information loss and correct the wrong status of equipment in the line list, which greatly improves the accuracy of the fault location results. Moreover, with the help of this feature, if a piece of equipment often loses information, this indicates that the equipment may need to be repaired.
5.2. Influence of the Fault Position and Line Structure
6. Conclusions
Author Contributions
Funding
Conflicts of Interest
References
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Equipment Number | Status of Equipment | Upstream Equipment | Downstream Equipment |
---|---|---|---|
1 | 0 | - | 2 and 4 |
2 | 0 | 1 | 3 |
3 | 0 | 2 | - |
4 | 0 | 1 | 5 and 7 |
5 | 0 | 4 | 6 |
6 | 0 | 5 | - |
7 | 0 | 4 | 8 |
8 | 0 | 7 | 9 |
9 | 0 | 8 | - |
Equipment Number | Status | Upstream Equipment | Downstream Equipment | Equipment Number | Status | Upstream Equipment | Downstream Equipment |
---|---|---|---|---|---|---|---|
1 | 1 | — | 2 | 18 | 0 | 17 | 19 |
2 | 1 | 1 | 3 and 7 | 19 | 0 | 18 | 20 |
3 | 0 | 2 | 4 | 20 | 0 | 19 | 21 |
4 | 0 | 3 | 5 | 21 | 0 | 20 | — |
5 | 0 | 4 | 6 | 22 | 1 | 13 | 23 |
6 | 0 | 5 | — | 23 | 1 | 22 | 24 |
7 | 1 | 2 | 8 and 11 | 24 | 1 | 23 | 25 |
8 | 0 | 7 | 9 | 25 | 1 | 24 | 26 |
9 | 0 | 8 | 10 | 26 | 1 | 25 | 27 |
10 | 0 | 9 | — | 27 | 0 | 26 | 28 |
11 | 1 | 7 | 12 | 28 | 0 | 27 | 29 |
12 | 1 | 11 | 13 | 29 | 0 | 28 | 30 |
13 | 1 | 12 | 14 and 22 | 30 | 0 | 29 | 31 |
14 | 0 | 13 | 15 | 31 | 0 | 30 | 32 |
15 | 0 | 14 | 16 | 32 | 0 | 31 | 33 |
16 | 0 | 15 | 17 | 33 | 0 | 32 | — |
17 | 0 | 16 | 18 |
Step | k | m | j | n | i | R[] | A[] | Step | k | m | j | n | i | R[] | A[] |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
(1) | 1 | 1 | 1 | 0 | 0 | (5) | 22 | 1 | 1 | 0 | 0 | ||||
(2) | 1 | 1 | 1 | 0 | 0 | (3) | 22 | 1 | 1 | 0 | 0 | ||||
(3) | 1 | 1 | 1 | 0 | 0 | (4) | 23 | 1 | 1 | 0 | 0 | ||||
(4) | 2 | 1 | 1 | 0 | 0 | (3) | 23 | 1 | 1 | 0 | 0 | ||||
(3) | 2 | 1 | 1 | 0 | 0 | (4) | 24 | 1 | 1 | 0 | 0 | ||||
(5) | 7 | 1 | 1 | 0 | 0 | (3) | 24 | 1 | 1 | 0 | 0 | ||||
(3) | 7 | 1 | 1 | 0 | 0 | (4) | 25 | 1 | 1 | 0 | 0 | ||||
(5) | 11 | 1 | 1 | 0 | 0 | (3) | 25 | 1 | 1 | 0 | 0 | ||||
(3) | 11 | 1 | 1 | 0 | 0 | (4) | 26 | 1 | 1 | 0 | 0 | ||||
(4) | 12 | 1 | 1 | 0 | 0 | (3) | 26 | 1 | 1 | 0 | 0 | ||||
(3) | 12 | 1 | 1 | 0 | 0 | (4) | 26 | 2 | 1 | 0 | 0 | R[1] = 26 | |||
(4) | 13 | 1 | 1 | 0 | 0 | (6) | 26 | 2 | 1 | 0 | 0 | R[1] = 26 | |||
(3) | 13 | 1 | 1 | 0 | 0 | (7) | 26 | 2 | 1 | 0 | 0 | R[1] = 26 |
Equipment Number | Status | Upstream Equipment | Downstream Equipment | Equipment Number | Status | Upstream Equipment | Downstream Equipment |
---|---|---|---|---|---|---|---|
1 | 1 | — | 2 | 18 | 0 | 17 | 19 |
2 | 1 | 1 | 3 and 7 | 19 | 0 | 18 | 20 |
3 | 0 | 2 | 4 | 20 | 0 | 19 | 21 |
4 | 0 | 3 | 5 | 21 | 0 | 20 | — |
5 | 0 | 4 | 6 | 22 | 0 | 13 | 23 |
6 | 0 | 5 | — | 23 | 0 | 22 | 24 |
7 | 1 | 2 | 8 and 11 | 24 | 0 | 23 | 25 |
8 | 1 | 7 | 9 | 25 | 0 | 24 | 26 |
9 | 1 | 8 | 10 | 26 | 0 | 25 | 27 |
10 | 0 | 9 | — | 27 | 0 | 26 | 28 |
11 | 1 | 7 | 12 | 28 | 0 | 27 | 29 |
12 | 1 | 11 | 13 | 29 | 0 | 28 | 30 |
13 | 1 | 12 | 14 and 22 | 30 | 0 | 29 | 31 |
14 | 1 | 13 | 15 | 31 | 0 | 30 | 32 |
15 | 1 | 14 | 16 | 32 | 0 | 31 | 33 |
16 | 1 | 15 | 17 | 33 | 0 | 32 | — |
17 | 0 | 16 | 18 |
Step | k | m | j | n | i | R[] | A[] | Step | k | m | j | n | i | R[] | A[] |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
(1) | 1 | 1 | 1 | 0 | 0 | (3) | 11 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(2) | 1 | 1 | 1 | 0 | 0 | (4) | 12 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(3) | 1 | 1 | 1 | 0 | 0 | (3) | 12 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(4) | 2 | 1 | 1 | 0 | 0 | (4) | 13 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(3) | 2 | 1 | 1 | 0 | 0 | (3) | 13 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(5) | 7 | 1 | 1 | 0 | 0 | (5) | 14 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(3) | 7 | 1 | 1 | 0 | 0 | (3) | 14 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | ||
(5) | 7 | 1 | 1 | 2 | 2 | A[1] = 8; A[2] = 11 | (4) | 15 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | |
(6) | 8 | 1 | 2 | 2 | 2 | A[1] = 8; A[2] = 11 | (3) | 15 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | |
(3) | 8 | 1 | 2 | 2 | 2 | A[1] = 8; A[2] = 11 | (4) | 16 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | |
(4) | 9 | 1 | 2 | 2 | 2 | A[1] = 8; A[2] = 11 | (3) | 16 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | |
(3) | 9 | 1 | 2 | 2 | 2 | A[1] = 8; A[2] = 11 | (4) | 16 | 3 | 3 | 2 | 2 | R[1] = 9; R[2] = 16 | A[1] = 8; A[2] = 11 | |
(4) | 9 | 2 | 2 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | (6) | 16 | 3 | 3 | 2 | 2 | R[1] = 9; R[2] = 16 | A[1] = 8; A[2] = 11 |
(6) | 11 | 2 | 3 | 2 | 2 | R[1] = 9 | A[1] = 8; A[2] = 11 | (7) | 16 | 3 | 3 | 2 | 2 | R[1] = 9; R[2] = 16 | A[1] = 8; A[2] = 11 |
Equipment Number | Status | Upstream Equipment | Downstream Equipment | Equipment Number | Status | Upstream Equipment | Downstream Equipment |
---|---|---|---|---|---|---|---|
1 | 1 | — | 2 | 18 | −1 | 17 | 19 |
2 | 1 | 1 | 3 | 19 | −1 | 18 | 20 |
3 | 1 | 2 | 4 | 20 | −1 | 19 | 21 and 23 |
4 | 1 | 3 | 5 and 6 | 21 | 0 | 20 | 22 |
5 | 0 | 4 | — | 22 | 0 | 32 | — |
6 | 1 | 4 | 7 | 23 | −1 | 20 | 24 and 25 |
7 | 1 | 6 | 8 | 24 | −1 | 23 | — |
8 | 1 | 7 | 9 | 25 | 0 | 23 | 26 and 30 |
9 | 1 | 8 | 10 and 13 | 26 | 0 | 25 | 27 |
10 | 1 | 9 | 11 | 27 | 0 | 26 | 28 |
11 | −1 | 10 | 12 | 28 | 0 | 27 | 29 |
12 | −1 | 11 | — | 29 | 0 | 28 | — |
13 | 1 | 9 | 14 | 30 | 0 | 25 | 31 |
14 | 1 | 13 | 15 | 31 | 0 | 30 | 32 and 33 |
15 | 1 | 14 | 16 | 32 | 0 | 31 | — |
16 | 1 | 15 | 17 | 33 | 0 | 31 | 34 |
17 | −1 | 16 | 18 | 34 | 0 | 33 | — |
Step | k | m | j | n | i | R[] | A[] | Step | k | m | j | n | i | R[] | A[] |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
(1) | 1 | 1 | 1 | 0 | 0 | (3) | 9 | 1 | 1 | 0 | 0 | ||||
(2) | 1 | 1 | 1 | 0 | 0 | (5) | 9 | 1 | 1 | 2 | 2 | A[1] = 10; A[2] = 13 | |||
(3) | 1 | 1 | 1 | 0 | 0 | (6) | 10 | 1 | 2 | 2 | 2 | A[1] = 10; A[2] = 13 | |||
(4) | 2 | 1 | 1 | 0 | 0 | (3) | 10 | 1 | 2 | 2 | 2 | A[1] = 10; A[2] = 13 | |||
(3) | 2 | 1 | 1 | 0 | 0 | (4) | 10 | 2 | 2 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(4) | 3 | 1 | 1 | 0 | 0 | (6) | 13 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(3) | 3 | 1 | 1 | 0 | 0 | (3) | 13 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(4) | 4 | 1 | 1 | 0 | 0 | (4) | 14 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(3) | 4 | 1 | 1 | 0 | 0 | (3) | 14 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(5) | 6 | 1 | 1 | 0 | 0 | (4) | 15 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(3) | 6 | 1 | 1 | 0 | 0 | (3) | 15 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(4) | 7 | 1 | 1 | 0 | 0 | (4) | 16 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(3) | 7 | 1 | 1 | 0 | 0 | (3) | 16 | 2 | 3 | 2 | 2 | R[1] = 10 | A[1] = 10; A[2] = 13 | ||
(4) | 8 | 1 | 1 | 0 | 0 | (4) | 16 | 3 | 3 | 2 | 2 | R[1] = 10; R[2] = 16 | A[1] = 10; A[2] = 13 | ||
(3) | 8 | 1 | 1 | 0 | 0 | (6) | 16 | 3 | 3 | 2 | 2 | R[1] = 10; R[2] = 16 | A[1] = 10; A[2] = 13 | ||
(4) | 9 | 1 | 1 | 0 | 0 | (7) | 16 | 3 | 3 | 2 | 2 | R[1] = 10; R[2] = 16 | A[1] = 10; A[2] = 13 |
Equipment Number | Status | Upstream Equipment | Downstream Equipment | Equipment Number | Status | Upstream Equipment | Downstream Equipment |
---|---|---|---|---|---|---|---|
1 | 1 | — | 2 | 18 | −1 | 17 | 19 |
2 | 1 | 1 | 3 | 19 | −1 | 18 | 20 |
3 | 0 | 2 | 4 | 20 | −1 | 19 | 21 and 23 |
4 | 1 | 3 | 5 and 6 | 21 | 0 | 20 | 22 |
5 | 0 | 4 | — | 22 | 0 | 32 | — |
6 | 1 | 4 | 7 | 23 | −1 | 20 | 24 and 25 |
7 | 0 | 6 | 8 | 24 | −1 | 23 | — |
8 | 1 | 7 | 9 | 25 | 0 | 23 | 26 and 30 |
9 | 1 | 8 | 10 and 13 | 26 | 0 | 25 | 27 |
10 | 1 | 9 | 11 | 27 | 0 | 26 | 28 |
11 | −1 | 10 | 12 | 28 | 0 | 27 | 29 |
12 | −1 | 11 | — | 29 | 0 | 28 | — |
13 | 1 | 9 | 14 | 30 | 0 | 25 | 31 |
14 | 1 | 13 | 15 | 31 | 0 | 30 | 32 and 33 |
15 | 1 | 14 | 16 | 32 | 0 | 31 | — |
16 | 1 | 15 | 17 | 33 | 0 | 31 | 34 |
17 | −1 | 16 | 18 | 34 | 0 | 33 | — |
Step | k | m | j | n | L[] | B[] | Step | k | m | j | n | L[] | B[] |
---|---|---|---|---|---|---|---|---|---|---|---|---|---|
(1) | 1 | 1 | 0 | 0 | (2) | 5 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 | ||
(2) | 1 | 1 | 0 | 0 | (3) | 5 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 | ||
(3) | 2 | 1 | 0 | 0 | (4) | 5 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | ||
(2) | 2 | 1 | 0 | 0 | (6) | 6 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | ||
(3) | 3 | 1 | 0 | 0 | (2) | 6 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | ||
(2) | 3 | 1 | 0 | 0 | (3) | 7 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | ||
(3) | 3 | 1 | 0 | 0 | (2) | 7 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | ||
(4) | 3 | 1 | 0 | 1 | B[1] = 4 | (3) | 7 | 2 | 0 | 0 | L[1] = 3 | B[1] = 4 | |
(5) | 4 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 | (4) | 7 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 |
(2) | 4 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 | (5) | 8 | 3 | 0 | 1 | L[1] = 3; L[2] = 7 | B[1] = 4 |
(3) | 5 | 2 | 0 | 1 | L[1] = 3 | B[1] = 4 |
Conditions | Single Fault | Multiple Faults | DG in Network | Topology Changes | Information Loss | Report Equipment with Information Loss | |
---|---|---|---|---|---|---|---|
Methods | |||||||
Proposed method | √ | √ | √ | √ | √ | √ | |
Method of [17] | √ | √ | √ | ||||
Method of [18] | √ | √ | √ | ||||
Method of [19] | √ | √ | √ | √ | |||
Method of [20] | √ | √ | √ | √ | |||
Method of [21] | √ | √ | √ | √ | |||
Method of [22] | √ | √ | √ | √ | √ |
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Share and Cite
Li, G.; Chen, Q.; Zhang, J. Novel Faulted Section Location Method for Distribution Network Based on Status Information of Fault Indicating Equipment. Appl. Sci. 2020, 10, 5910. https://doi.org/10.3390/app10175910
Li G, Chen Q, Zhang J. Novel Faulted Section Location Method for Distribution Network Based on Status Information of Fault Indicating Equipment. Applied Sciences. 2020; 10(17):5910. https://doi.org/10.3390/app10175910
Chicago/Turabian StyleLi, Guanbin, Qing Chen, and Jianlei Zhang. 2020. "Novel Faulted Section Location Method for Distribution Network Based on Status Information of Fault Indicating Equipment" Applied Sciences 10, no. 17: 5910. https://doi.org/10.3390/app10175910
APA StyleLi, G., Chen, Q., & Zhang, J. (2020). Novel Faulted Section Location Method for Distribution Network Based on Status Information of Fault Indicating Equipment. Applied Sciences, 10(17), 5910. https://doi.org/10.3390/app10175910