1. Introduction
Nonlinear elliptic boundary value problems (NEBVP) are significantly important type PDEs having applications in different branches of science and engineering including fluid mechanics such as exothermic chemical reactions or auto catalytic reactions, see [
1], in physics and chemistry. Some other specific applications of elliptic BVPs may be seen in [
2,
3,
4,
5,
6,
7,
8,
9,
10,
11,
12,
13,
14,
15,
16,
17,
18,
19,
20,
21,
22].
The interest of such problems come from the thesis [
23] (Section 1.5, page 147), where the authors asked open problem concerning multiplicity results. The main question we would like to address in this direction is the existence of more than two solutions, the articles of Chipot and Lovat [
1] and Ovono and Rougirel [
24], where the authors study classes of nonlocal problems motivated by the fact that they appear in some applied mathematics areas and the diffusion at each point depends on all the values of the solutions in a neighborhood of this point. Moreover, in [
8], the authors have mentioned that the importance of such a model lies in the fact that measurements that serve to determine physical constants are not made at a point but represent an average in a neighborhood of a point so that these physical constants depend on local averages. The lack of the existence of the multiple solutions by using bifurcation theory showed that many local branches of solutions exist while, among them, only one is global and has no bifurcation point implying a considerable difficulty to prove the existence of a bifurcation point interior of the ball. The authors in [
24] (cf. Theorem 3.1) already pointed out that the existence of a solution to the problem proposed (more exactly, for different kinds of NEBVP involving different conditions) is not guaranteed for the unboundedness of data
c. It is natural to ask whether or not we can obtain the existence results of the EBVP or what happens if the data
c are unbounded. Up to now, the main scope of these papers consists in the imposing some conditions on the nonlinearity
c (
c is the data) to prove the existence solutions to the problem (1) in smooth domains in the presence of well-ordered lower and upper solutions. Note that the case where
c is unboundedness seems to be new in the literature. In other words, we obtain the existence results under regularity assumptions on
c, (see [
25,
26,
27,
28] for more discussion).
In the present research study, we are interested in existence, uniqueness, multiple positive solutions and existence of weak positive solutions for an NEBVP, (called first type NEBVP), defined as
and positive global solutions for the second NEBVP defined as
in which
,
is a bounded set
with smooth boundary
,
is a second order uniformly elliptic operator and
is defined as either
or
where
is outward derivative in
are bounded and strictly nonnegative maps on
. The initial non-negative smooth map
satisfies compatibility condition
on
.
The structure of the article is as follows. In
Section 2 and
Section 3, we prove the existence, uniqueness and multiplicity of positive solutions for the first type and global positive solutions for the second type by employing strictly upper (SU) and strictly lower (SL) solutions, by iterative sequence method for both of them and the Amann theorem for the first type.
Section 4 is devoted to the existence of a weak solution to the first type.
2. Multiple Positive Solutions of Nonlinear Elliptic PDEs
Definition 1. A function is said to be an upper solution (US) of (1) if α satisfies the following inequalities: Moreover, a function is a lower solution (LS) of (1) if for β the conditionshold true. We say that a map is a strict LS of (1) if,
- (i)
is an LS of (1), and
- (ii)
for all solutions of (1), such that holds for all .
Similarly, a map is an SU solution of (1) if:
- (i)
is a US of (1) and
- (ii)
for all solutions of (1) with hold for all .
Now, we assume that there exist
to (1), and define
Let c be monotone nondecreasing in u and such that
- (i)
for all
and for
c satisfies
- (ii)
for
with
on
and
suppose that there exists
such that the inequality
- (iii)
for every the inequalities hold.
We first make some observations on SU and SL solutions. We shall use the SU and SL solutions together with strong maximum principle in the sequel.
Lemma 1. (Strong maximum principle, see [29]) Let , two elliptic operators, Ω be as in Section 1 and be given. Then, the following holds. - (i)
(Interior form) Let and let be an open ball centered at and contained Ω. If in , v for all and , then for all .
- (ii)
(Boundary form) Let and let be an open ball contained in Ω with . If in , for all and , then for each ζ satisfying .
- (iii)
(Global form) Let be a constant. If in Ω and on , then either in Ω or for all , and for all where is defined as in Section 1.
Lemma 2. Let (5) hold and u be any solution of (1). Then, every lower (upper, respectively) solution (), which is not a solution, (i.e., ()) is an SL (SU) solution of (1).
Proof. Assume that
is an SL solution under hypotheses of Lemma 2. Let us prove this with a contradiction. Let
u,
be any solutions with
. Then,
and
Putting
implies that
. By
, and by the definition of the operator
, a subtraction of above equations gives
Thus, by hypothesis of
and (6), we have
which is a contradiction that completes the proof.
We can prove that is a strict US under given conditions in a similar manner. □
Lemma 3. Assume that holds. Then, by defining as above, the inequalitieshold true. Now, we are in a position to present some results regarding existence of solutions. To achieve this, starting from suitable maps
or
, obtain a sequence
from
Lemma 4. Let be nonnegative, bounded functions and satisfying In this case, in . Furthermore, in unless .
Theorem 1. Assume holds. Let be LS and US of (1) with and be a smooth map on . Then, there are two non-negative solutions and of problem (1) with Proof. Obviously, by the hypothesis and , is an LS of (1).
Now, define
as
and
By Schauder estimates, we deduce
is completely continuous and monotonic in the sense of Collatz [
30] type, that is;
implies
, provided that
and
restricted to the set
. In fact, if
then
Then,
i.e.,
Hence, , in .
Letting
or
generate
as
When , we set and when . Then, the sequence and converges monotonically by the continuity of to and respectively. Thus, and are two fixed point of . The proof is completed. □
Corollary 1. Let and be two solutions of (1). If w is a solution of (1) satisfying , the inequalities hold.
Proof. By Theorem 1, we have and , since or .
By induction, for every n. Thus, . Similarly, , hence . □
Theorem 2. Assume holds. (1) has positive local solution .
Proof. Notice that implies existence of LS and US. Then, by Theorem 1, there is a local positive solution of (1). □
We adopt the following assumption:
Let
with
,
be bounded nonnegative maps and the map
satisfies the following inequality
Theorem 3. Let (5) and in hold true. Assume also that are, LS and US of problem (1). Then, problem (1) has unique positive solutions in .
Proof. Existence of positive solutions of (1) may be observed by Theorem 1. Let
be two poitive solutions with
. Suppose
then
and by
, we have
Applying Lemma 4 we have . □
By employing Amann Theorem [
31], we show multiple positive solutions. Let
are two upper solutions and
are two lower solutions of problem
.
Theorem 4. ([31]) Assume that E is a Banach space. Assume also that is a normal solid cone. Suppose that there are by The operator satisfyinghas at least three fixed points, such that Theorem 5. Assume that holds. Suppose that are LS, and are US of (1) such that are strict with . In this case, (1) has at least three solutions such that Proof. We shall show that
is strongly increasing operator. Equivalently saying, or all
with
. In view of
, we have
As a result that there exists a neighborhood
such that
for
since
. Hence, by
, we have
Therefore, in by strong maximum principle, and we conclude that is a strongly increasing operator.
Now, we prove
. Consider the following problem:
In the view of
, an LS of (1), we have
Thus, and by strong maximum principle, we get .
In view of
, an LS of (1), we have
hence
that is by strong maximum principle, we conclude
. Then,
.
Similarly, we have .
We know that . Since is an LS of (1), it is strict solution of (1). Thus, .
According to the same way, we can get
Thanks to the Theorem 4,
has at least three fixed points
with
□
Corollary 2. Assume that holds. Let be LSs and be strict US of (1) such that . Then, (1) has at least three solutions such that Proof. We shall apply Theorem 5. That is, assume that there are two upper solutions,
satisfying:
Let
and
be US such that
for
and
Hence, we only verify that
Then, by strong maximum principle (Lemma 1), we have
Suppose there is a
with
Let
. Since
we find an open ball
such that
Since
for
for
, that implies:
which is a contradiction. □
3. Positive Global Solutions for Second Problem
We are interested in existence of global solutions of (2). Suppose that
is defined either as
where the initial non-negative smooth map
satisfies compatibility condition
on
.
Recall that the operator
is defined as
As a matter of fact, we have that:
Definition 2. is a US of (2) provided that Similarly, is an LS by changing direction of inequalities in (9), we set with in .
It is obvious that the upper and lower solutions of (2) are given by
. Let
be at
with
on
Then, by the maximum principle for a parabolic equation, we have
Defining
we have
is a monotone operator with type of Collatz [
30]. Letting
we get
with
and
in which
Theorem 6. Suppose that conditions of hold. Assume also that are a US and LS of (2). If there is a σ such thatwherethere exists a unique strong solution u of (2) withwhere is decreasing and is increasing sequences. We address the situation where h is time independent next. Corollary 3. Suppose that conditions of hold. If is a solution ofwhere and are an upper and an LS, respectively, there is a global regular solution . Now, we introduce two identities:
and
Theorem 7. Suppose that conditions of hold and also is a US of (10). If is a solution of (11), .
Proof. Assume
is a sequence of maps by
, and for
,
We conclude by strong maximum principle that .
By induction and from (13) for
, we deduce the existence
Thus,
is a solution of
Hence,
via uniqueness condition. Differentiating (12) with respect to
t, we have
in which
.
Since it is bounded.
As a result by (12) and (13), we get . Hence, . Furthermore, we have .
We can apply the same proof of Theorem 1 to get
Thus, in . Herewith, the proof is complete. □
Let us assume
is a
-mapping for
u and satisfies the inequalities:
where
are constants with
Theorem 8. Assume that (14) holds. If there exists constants with . Then, for all , (2) has a unique positive and bounded global solution.
Proof. Let
then, by (14), we get
This allows to conclude that , is a US. Similarly, is an LS. Consequently, thanks to the Theorem 6, we conclude the result. □
We are now ready to prove the uniqueness result of global positive solution. To this purpose, we assume that:
For every :
Theorem 9. Suppose that , (5) and (6) hold. If there exists a mapping M withthen, (2) has a unique global positive solution. Proof. Using the mean-value theorem, (5) and (6), we have
in which
is intermediate value between
u and 0.
By Lemma 3 and
we write
Hence, in . u is positive because, if it is not, only if all of the maps in is equal to 0. This implies that is an LS of (2).
Therefore,
w is a upper positive solution of (2). As a matter of fact, for
and again applying the mean-value theorem,
where
is located between
and 0.
Combining with
, (5), (6) and (15), we have
Thus,
which implies that
is an upper positive solution of (2). Hence, by Theorem 8, we deduce the unique positive global solution of (2). □
4. Weak Solutions for the First Problem
Now, our main result shows the existence of a weak solution to problem (1) with Dirichlet boundary condition ( i.e., and ) under a unboundedness on c. Before doing this, we introduce the following notion of weak solution to (1). For that, we need Lemmas 5–7 and the assumptions and (see later). Note that the notion of weak solution to (1) is essentially the same as in Definition 1, the only difference is that we now require that u belong to .
Definition 3. Let , u is said to be a weak solution of (1) if it satisfies A nonnegative function is called a weak lower solution (WLS) and weak upper solution (WUS) of (1) if they satisfyandfor all . Lemma 5. ([26]) Let v solve in Ω. If , then for any , thus in particular, v is continuous in Ω. Lemma 6. ([32]) For each . Then, there exists a unique solution to problem (1). Lemma 7. ([33]) Assume that u and v are two non-negative functions such that Then, .
is increasing function such that
Moreover,
satisfies
Theorem 10. Let and hold. Then, problem (1) has a positive weak solution.
Proof. Let be the first eigenvalue of with Dirichlet boundary conditions and be the corresponding positive eigenfunction with .
Let
be such that
on
We shall verify that
is a weak LS of (1). Indeed, let
with
in
. A simple calculation shows that
On
we have
, then
. Hence,
By , we get (large enough).
Next, on
we have
for some
. By
and by the definition of
, it follows that:
From (17) and (18), we deduce that
for any
. That is,
is a weak LS of problem (1).
Next, we shall construct a WUS of (1). Let
e be the solution of the following problem
Let
, where
C is a positive real number which will be chosen later. We will verify that
is a weak US (1). Let
with
in
. Then, from (19), we get
By
, we can choose
C large enough so that
Therefore,
that is,
a weak US of (1) for a large enough
C. In order to obtain a weak solution of (1), we define the sequence
as
and
is the unique solution of the problem
If is given, the right-hand-side of (20) is independent of since in x and from Lemma 6. Then, (20) with has unique solution .
We deduce from Lemma 5 that
. Consequently, we conclude that
. In the same way, we construct the following elements
of our sequence. From (20), and by the fact that
is a weak US of (1), we have
from which and Lemma 7, we have
.
Since
and by the monotonicity of
c, we have
from which and Lemma 7, we deduce that
.
From (20), and by the monotonicity of
c,
and
, for
we write
and
Then, thanks to the Lemma 7, we get
and
. Repeating this argument, we get a bounded monotonic sequence
satisfying
Thanks to the continuity of the function
c and by the definition of the sequences
, there exists a constant
, which is independent from
n such that
Using (21), multiplying the first equation of (20) by
integrating and using the Hölder inequality and Sobolev’s embedding, we can show that
Then,
where
is a constant and independent from
n. By (22), we infer that
has a subsequence which weakly converges in
to
u with
0. Now, letting
, we deduce that
u is a positive weak solution of (1). Hereby, the proof is completed. □