1. Introduction
In this paper, we consider that all graphs are simple, undirected and connected. A graph is said to be planar if it can be embedded in a plane such that its edges intersect only at their endpoints. Let G be a planar graph. We denote by , and the vertex set, the edge set and the face set, respectively. The degree of a vertex is the number of edges associated with v, and written as . A vertex with a degree of exactly k, at least k and at most k is referred to as a k-vertex, -vertex and -vertex, respectively. Specifically, if , then v is called a leaf. Moreover, the maximum degree of G, denoted by , is defined as . In turn, the minimum degree of G, denoted by , is defined as . The maximum average degree of a graph G is the maximum of the average degrees of its subgraphs. For a face , the degree of f, denoted by , is defined as the number of edges on the boundary of f, and the definition of a k-, -, or -face is similar to that of the corresponding vertex. A cycle of length in G is called a k-cycle, and the minimum length among all k-cycles is known as the girth of G, denoted by . Additionally, a graph G is normal if it has no isolated edges.
A
proper k-total coloring of a graph is a mapping from
k colors to its vertices and edges such that no two incident elements receive the same colors. In recent years, neighbor sum distinguishing total coloring of graphs as a constrained
k-total coloring was first introduced by Pilśniak and Woźniak [
1] in 2015, which has received much attention. A proper
k-total coloring
of a graph
G is said to be a
neighbor sum distinguishing total coloring if
for any
, where
for each
, and the minimal number
k of such coloring is called
neighbor sum distinguishing total chromatic number, denoted by
. Moreover, they also proposed the conjecture below.
Conjecture 1 ([
1]).
Let G be a graph of order at least 2. Then, Meanwhile, they showed that Conjecture 1 is valid for various classes of graphs, including complete graphs, cubic graphs, and so on. Subsequently, many results have been achieved in the study of neighbor sum distinguishing total coloring on planar graphs. In 2016, Qu et al. [
2] obtained that
for a planar graph
G. Later, Wang et al. [
3] confirmed the validity of Conjecture 1 for planar graphs without containing 4-cycles, and then, Wang et al. [
4] further proved that if planar graph
G contains no adjacent triangles and
, then
. In the same year, Ge et al. [
5] showed that
if planar graph
G does not contain 5-cycles. In 2022, Nakprasit et al. [
6] proved that
for a planar graph
G without 4-cycles adjacent to 3-cycles and
. In 2023, Huang et al. [
7] verified that for any graph
G with
,
. Additionally, they provided a characterization of the neighbor sum distinguishing total chromatic number for graphs satisfying
and
. In 2024, Du et al. [
8] presented two significant results regarding planar graph
G. The first one is that if
G has no 3-cycles adjacent to 4-cycles with
and without cut edges, then
. The second is that if
G has no 4-cycles intersecting with 6-cycles and
, then
. Just recently, Duan et al. [
9] verified that
for planar graph
G without intersecting 4-cycles.
In 2017, Flandrin [
10] extended the definition of neighbor sum distinguishing total coloring by incorporating the colors of adjacent vertices to form the notion of
full sum, and introduced the concept of
neighbor full sum distinguishing total coloring of graphs. For a graph
G, suppose
is a proper
k-total coloring of
G. For each vertex
, let
and
. Furthermore, if
for any
, then
is termed a
neighbor full sum distinguishing k-total coloring of
G, abbreviated as
k-NFSDTC of
G. The smallest integer
k for which a neighbor full sum distinguishing
k-total coloring exists in
G is referred to as the
neighbor full sum distinguishing total chromatic number of
G, simplified as
. Cheng et al. [
11] provided an insight for the neighbor full sum distinguishing total coloring through two specific types of Halin graphs. In 2023, Cui et al. [
12] proposed Conjecture 2 and validated it for graphs such as paths, cycles, stars, wheels, complete bipartite graphs, complete graphs and trees.
Conjecture 2 ([
12]).
If G is a normal graph, then . Recently, Yue et al. showed in [
13] that
if
G is a normal planar graph with
and
. Inspired by Conjecture 2, we extend the result of [
13] under the condition
in some sense.
Theorem 1. Let G be a normal planar graph with and . Then, 2. Demonstration of Main Result
At first, we present some lemmas to be utilized in the subsequent proof.
Lemma 1 ([
12]).
For , suppose is a star of order . Then, . Lemma 2 ([
14]).
Let and be the sets of integers, with and . Let . Then, . Moreover, if , then . By the definition of neighbor full sum distinguishing total coloring, it is evident that Lemma 3 always holds.
Lemma 3. For a graph G, let u be a vertex of degree at least 2 in G. If v is a leaf neighbor of u, then .
Proof of Theorem 1. Suppose that
G is a normal planar graph. For a vertex
v of
G, we denote by
the number of neighbors of
v that are not leaves, and
the quantity of neighbors of
v with degree
k in
G. If
, then
v is called a
good 2-vertex when
, otherwise, it is called a
bad 2-vertex (i.e.,
). Let
be the quantity of bad 2-vertices neighboring
v in
G. For a face
f of
G, let
be the number of vertices with degree
k that are incident to
f. In addition,
Figure 1 illustrates a part of the reducible configurations of
G originated from the proof. In these configurations, solid dots denote vertices with specified degrees, whereas hollow dots indicate vertices whose degrees remain unspecified.
To proceed a proof by contradiction, assume that G is a minimal counterexample to Theorem 1 with the minimal . It is evident that G is connected due to the minimality. Let be a proper normal subgraph of G. Then, has a -NFSDTC, denoted by . For each vertex , let denote the full sum of x under the coloring . In what follows, we drive some claims by extending to be a -NFSDTC of G to contradict the minimality of G.
Claim 1. No -vertex is adjacent to a leaf in G.
Proof. Without loss of generality, assume that there exists a 4-vertex v adjacent to a leaf . Let , and be the neighbors of v other than , and . Then, from the minimality of G, has a -NFSDTC . From the principles of proper total coloring, we have , which means that there are 4 forbidden colors for at most. Thus, has at least feasible colors. Likewise, has at least feasible colors. By Lemma 2, it follows that there are at least 42 different values for . Hence, also has at least 42 distinct values. Therefore, there must exist a value for such that , and . In addition, by Lemma 3, we have . Consequently, G has a -NFSDTC , which contradicts the minimality of G. □
The following Claims 2 and 3 can be found in [
13], so we omit their proof here.
Claim 2 ([
13], Claim 2).
There is no 2-vertex adjacent to two other 2-vertices in G. Claim 3 ([
13], Claim 3).
There is no 2-vertex adjacent to a 3-vertex in G. Claim 4. 3-vertex has at most one neighbor of degree 3 in G.
Proof. Assume that there exists a 3-vertex
v adjacent to two 3-vertices in
G. Let
be the neighbors of
v with
, as shown in the structure
in
Figure 1. Let
and
be the neighbors of
other than
v, and
and
be the neighbors of
other than
v. The other neighbors of
excluding
v are denoted by
for
, where
. Let
. Then, by the minimality of
G, there exists a
-NFSDTC
for
. We now color the vertex
v and its incident edges.
Assume, without loss of generality, that . From the principles of proper total coloring, we have ; this indicates that the edge has forbidden colors and 3 feasible colors. Likewise, v has feasible colors since . By Lemma 2, it follows that has at least different values, and thus, also has at least different values. Therefore, there exists a value for yielding with .
Next, we consider the distinguishability of the full sums at and with their neighbors, as well as and v. Based on the previous discussion above, and have already been determined. Then, by the principles of proper total coloring, , , which means that the edge has feasible colors. Similarly, . This implies that the edge has feasible colors. Furthermore, from the definition of neighbor full sum distinguishing total coloring, at most, one feasible color for will cause , leaving feasible colors for . Thus, could take at least 18 different values, and so, there exists a value for such that and .
At this point, has also been determined. From the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for that leads to , and at most one leading to . So, this leaves feasible colors for . Therefore, also has at least 18 distinct values, guaranteeing a choice that satisfies and . Thus, G admits a -NFSDTC , which contradicts the minimality of G. □
Claim 5. There is no 2-vertex adjacent to a 4-vertex in G.
Proof. Assume that there exists a 2-vertex
u adjacent to a 4-vertex
v in
G. Let
be the neighbor of
u distinct from
v. Let
,
and
be the neighbors of
v other than
u, as shown in the reducible configuration
depicted in
Figure 1. Let
. Then, by the minimality of
G,
admits a
-NFSDTC
. Next, we will color the vertex
u and its removal edges.
Assume, without loss of generality, that , and are the neighbors of distinct from v, where . From the principles of proper total coloring, we have . Therefore, the edge has forbidden colors and 3 feasible colors. Likewise, ∉, ; this means that u has feasible colors. Meanwhile, , and thus, the edge has feasible colors. From the definition of neighbor full sum distinguishing total coloring, there is at most one color from the feasible colors for that results in . Analogously, there exists at most one color among the feasible colors for that results in . Consequently, possesses 2 remaining feasible colors, while has remaining feasible colors. Note that u has at least feasible colors. Hence, it follows from Lemma 2 that would obtain at least different values, and thus, also has different values at least. Therefore, there must exist a value for such that with simultaneously.
Next, we consider the distinguishability of the full sum for v and its neighbors , and . Based on the previous analysis concerning for , the color is now determined. Given that , there are at least different values feasible for . Hence, also takes at least 18 different values; this means that there exists a value for yielding with . Thus, G admits a -NFSDTC , which contradicts the minimality of G. □
Claim 6. A -vertex is adjacent to at least 4 non-leaf neighbors. Moreover, if the -vertex is adjacent to precisely 4 non-leaf neighbors, then it does not have a 2-vertex as its neighbor in G.
Proof. Firstly, we show that any -vertex v is adjacent to at least 4 non-leaf neighbors in G. Assume by a contradiction that v has at most three non-leaf neighbors. For convenience, we write as the leaf neighbors of v, and as its non-leaf neighbors, where and .
When , v has no non-leaf neighbors, which implies that G is a star. Therefore, from Lemma 1, G admits a -NFSDTC , which contradicts the minimality of G.
Without loss of generality, suppose that v has three non-leaf neighbors, , and . Then, at this moment. This means that v has at least two leaves. Let . Then, by the minimality of G, there exists a -NFSDTC for . From the principles of proper total coloring, has at least feasible colors since . Similarly, has at least feasible colors. By Lemma 2, we have that owns at least 24 distinct values; this implies that also takes at least 24 distinct values. So, there must exist a value for satisfying . Furthermore, by Lemma 3, we have (). Thus, G admits a -NFSDTC extended from , contradicting the minimality of G.
Next, we will prove that for any -vertex v in G, if , then . Assume that there exists a -vertex v (say, briefly) with adjacent to a 2-vertex . Let for denote the leaves of v, and denote the non-leaf neighbors of v. Let . Then, by the minimality of G, there exists a -NFSDTC for . From the principles of proper total coloring, ∉, . Thus, should have at most forbidden colors, leaving at least feasible colors. Likewise, obtains at least feasible colors. Hence, by Lemma 2, we see that has at least 24 distinct values, which yields that also has at least 24 distinct values. Therefore, there must exist a value for such that . It further follows by Lemma 3 that with . Consequently, G admits a -NFSDTC extended from , which contradicts the minimality of G. □
Claim 7. No -vertex v with has at least two 2-vertices in G.
Proof. Suppose that G has a -vertex v with having two neighbors of degree 2, e.g., and . Let denote the leaves of v with . For convenience, we write , and as the other three non-leaf neighbors of v.
Case 1..
Here,
. This indicates that
v is not a leaf, as depicted by the structure
in
Figure 1. Let
. Then, by the minimality of
G, there exists a
-NFSDTC
for
. Let
be the other neighbor of
, differing from
v. We now color the vertex
and its incident edges.
Assume, without loss of generality, that . Let for be the neighbors of differ from . From the principles of proper total coloring, . Therefore, has forbidden colors and 3 feasible colors. Similarly, ; thus, has feasible colors. Furthermore, ∉, , , , , and . Hence, has feasible colors. According to the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for such that . Similarly has at most one feasible color resulting in . As a result, has 2 remaining feasible colors, and has remaining colors. Since has feasible colors, from Lemma 2, would take at least distinct values. This implies that also takes at least different values. Thus, there exists a value for satisfying with .
We next consider the full sum distinguishability of vertex v with its neighbors , , and . From the analysis of above, for , is now defined. Since , has at least distinct values. This indicates that also takes at least 17 different values. Consequently, one can find a value for yielding where . Consequently, G admits a -NFSDTC extended from , contradicting the minimality of G.
Case 2. .
At this moment, . This indicates that v has at least one leaf. Let . Then, by the minimality of G, admits a -NFSDTC . From the principles of proper total coloring, the edge possesses feasible colors, and vertex possesses feasible colors. Thus, would take at least 23 distinct values, which means that also takes at least 23 different values. Hence, there must exist a value for satisfying for . Furthermore, by Lemma 3, we have for . Therefore, one can obtain a -NFSDTC of G by extending , contradicting the minimality of G. □
Claim 8. No -vertex v with is adjacent to at least four 2-vertices, in which at least one neighbor is a bad 2-vertex.
Proof. Suppose that G has a -vertex v with adjacent to at least four 2-vertices. Let be the non-leaf neighbors of v, and let be the leaf neighbors of v, where and .
Firstly, we will show that . Suppose that . The proof will proceed by concerning the value of .
Case 1. .
Here,
, this indicates that
v is not adjacent to the leaf, as illustrated in the structure
in
Figure 1. Let
. Then, from the minimality of
G, there is a
-NFSDTC
in
. Let
denote the other neighbors of
differ from
v. We now assign colors to the vertex
and its incident edges.
Without loss of generality, assume that . Let be the neighbors of other than , where . From the principles of proper total coloring, . This implies that edge has forbidden colors, and so, it leaves 3 feasible colors. Similarly, , and thus, has feasible colors. Additionally, since , , , there are feasible colors for edge . According to the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for edge , causing , and at most one feasible color for edge , leading to . Thus, two feasible colors remain for edge , and colors for edge . Since has feasible colors, from Lemma 2, would take at least different values. Consequently, also has at least different values, guaranteeing the existence of a value for such that , where .
Now, we discuss the full sum distinguishability of v and its neighbors . Based on the previous analysis of for , the color is now fixed. Since , there are at least distinct values for . This indicates that also takes at least 16 distinct values. Accordingly, there exists a value for yielding for . Thus, can be extended to a -NFSDTC of G, contradicting the minimality of G.
Case 2. .
Here, , which means that v has a leaf neighbor. Let . Then, by the minimality of G, admits a -NFSDTC . According to the definition of neighbor full sum distinguishing total coloring, has at least feasible colors, and has feasible colors. Hence, would take at least 23 distinct values; this indicates that has at least 23 distinct values. Therefore, there is a value for satisfying for . Moreover, by Lemma 3, it follows that for all . Thus, one can obtain a -NFSDTC of G by extending , contradicting the minimality of G.
Secondly, we prove that . Suppose that v is adjacent to a bad 2-vertex . Let be the other neighbor of besides v and . Let be the other neighbor of differing from . Let . Then, by the minimality of G, has a -NFSDTC .
Without loss of generality, assume that . From the principles of proper total coloring, . This means that has forbidden colors and 3 feasible colors. Likewise, , , which follows that has feasible colors. Furthermore, , ; thus, has feasible colors. From the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for edge causing , and at most one feasible color for , similarly causing . Hence, 2 feasible colors remain for , and feasible colors for . Since has feasible colors, by Lemma 2, has at least different values; this indicates that takes at least distinct values. Thus, there is a value for such that for , as well as for .
Finally, we consider the full sum distinguishability of and its neighbor . Based on the previous analysis of for , and for , is already determined. Since , there are at least distinct values for ; as a result, possesses no fewer than 20 distinct values. Therefore, there is a value for satisfying , and thus, there exists a -NFSDTC in G extending from , contradicting the minimality of G. □
Claim 9. No -vertex v with for has at least neighbors of degree 2, in which at least neighbors are bad 2-vertices.
Proof. Without loss of generality, suppose that
G contains a
-vertex
v with
. Let
denote the leaf neighbors of
v for
, and
for
denote the neighbors of
v with degree of at least 2, where
, as in the structure
depicted in
Figure 1.
(1) We aim to show that . Assume by a contradiction that v has at least eight 2-vertices. Let , and z denote the other neighbor of besides v. Two cases are considered depending on the degree of v.
Case 1. .
In this case, , which implies that v has at least one leaf neighbor. Let . Then, by the minimality of G, admits a -NFSDTC . From the principles of proper total coloring, has at least feasible colors, and has feasible colors. Thus, takes no fewer than 23 distinct values. Furthermore, takes at least 23 different values. Therefore, there is a value for satisfying where . Meanwhile, by Lemma 3, it follows that for . Consequently, G admits a -NFSDTC extending , contradicting the minimality of G.
Case 2. .
Here, , indicating that v has no leaf. Let . Then, by the minimality of G, admits a -NFSDTC . Suppose without loss of generality that . Let be the neighbors of z other than for . From the principles of proper total coloring, , which implies that there are 3 feasible colors for . Similarly, , which means that has feasible colors. Moreover, ∉, ; hence, has at least feasible colors. By the definition of neighbor full sum distinguishing total coloring, there is at most one color for causing , and at most one color for similarly causing . Thus, has 2 remaining feasible colors and has remaining feasible colors. Since has feasible colors, it follows from Lemma 2 that has at least different values. This further implies that would take at least different values. Hence, for .
Now, we consider the full sum distinguishability between v and its neighbors for . Based on the above analysis of for , is now determined. Since , there are at least 11 feasible colors for . This indicates that would take at least 11 different values. Thus, there is a value for such that where , which contradicts the minimality of G.
(2) We here aim to prove that . Assume that v is adjacent to at least six bad 2-vertices. For convenience, we write as these bad 2-vertices, and z is a neighbor of distinct from v with .
If , then ; this indicates that v has at least one leaf. This case can be proved using the same method as Case 1 in (1).
If , then . In this case, it means that v has no leaf. Let . Then by the minimality of G, admits a -NFSDTC . Let be a neighbor of z distinct from . We then assign colors to and its incident edges.
From the principles of proper total coloring, has 2 forbidden colors and feasible colors since . Similarly, , , and thus, has feasible colors. Furthermore, , . Hence, has feasible colors. By the definition of neighbor full sum distinguishing total coloring, there is at most one color for causing , and at most one color for causing . Therefore, owns at least feasible colors, and owns at least feasible colors. Note that has feasible colors. Hence, it follows from Lemma 2 that would take at least different values. It induces that also has at least 41 different values. Hence, there is a value for such that .
We next consider the full sum distinguishability of v and its neighbors for . From the above analysis of , the value is already determined. Since , has at least feasible colors. This indicates that also takes at least 11 different values. Accordingly, there is a value for ensuring that , where . Therefore, G admits a -NFSDTC by extending , which contradicts the minimality of G. □
From the statement of Claim 9, the following relationships can be derived, as shown in
Table 1.
Claim 10. No -vertex v with has at least one neighbor that is a bad 2-vertex.
Proof. Suppose that G contains a -vertex v such that . Let for be the neighbors of v, and z be a bad 2-vertex adjacent to v, be the neighbor of z distinct from v with , and be the neighbor of distinct from z. Let . Then, by the minimality of G, there is a -NFSDTC of . We now color the vertex z and its incident edges.
Assume without loss of generality that . From the principles of proper total coloring, . Therefore, has forbidden colors and 3 feasible colors. Similarly, we have that z has feasible colors due to , and has at least feasible colors because , . Furthermore, by the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for such that , and at most one feasible color for such that . Thus, possesses at least 2 feasible colors, and possesses at least feasible colors. Note that z has feasible colors. Hence, it follows from Lemma 2 that would take at least different values. Therefore, also takes at least different values. So, there is a value for such that for .
Now, we consider the full sum distinguishability between and its neighbor . By the analysis above concerning for , the value is already determined. Since , there are at least feasible colors for . Hence, would take at least 20 different values, and so, there is a value for such that . Consequently, one can obtain a -NFSDTC of G by extending , thus contradicting the minimality of G. □
Let H be the graph obtained from G by removing all leaves. Then, H is a connected subgraph of G with and . Furthermore, we have that Claims 1–10 also hold for H, and . The additional properties of H are given as follows:
- (1)
For all , ;
- (2)
If with , then ;
- (3)
For with , .
Proof. Since H is a connected subgraph obtained from G by removing all leaves, the statements (1) and (2) follow from Claims 1–3 directly. Next, we need to prove statement (3). Let be a 5-face in H. Then, the proof relies on analyzing .
If , then by Claim 4, the face f is associated with at most three 3-vertices. Hence, .
If , we may suppose that , and then by Claims 2, 3, 5 and 6, it follows that and .
If , we consider two cases in the following:
- –
When f is at least incident to a bad 2-vertex, we suppose . From Claims 2, 3 and 5–10 we have either and or and .
- -
When f is not incident to any bad 2-vertex, we suppose that . Then, from Claims 2, 3 and 5–9, we obtain , and .
If , according to Claim 2, the only possible configuration is . Using Claims 2, 3 and 5–10, it follows that and .
If , this contradicts the structural conditions described in Claim 2, and thus, such a case does not occur.
This completes the proof of . □
For a
-vertex
v in
H with
, we conclude that each of its bad 2-vertex is only adjacent to at most one 5-face, which is formed together with
v and its other neighbors (which may be some good 2-vertices). If not, a bad 2-vertex associated with two 5-faces would yield a 4-cycle, thereby contradicting the condition
, as illustrated by the configuration
in
Figure 1. Thus, each bad 2-vertex adjacent to
v is incident with at most one 5-face. Furthermore, if any two bad 2-vertices adjacent to
v are associated with the same
-face, then the number of 5-faces incident to
v attains its maximum. In particular, if the number of bad 2-vertices adjacent to
v is odd, and all bad 2-vertices are pairwise adjacent to a common
-face, then there must exist one bad 2-vertex that is associated with a
-face individually. Based on the above, we have the following fact.
Fact 2.
Every -vertex v is associated with at most distinct 5-faces in G.
Subsequently, we carried out an analysis of charge transfer in the connected planar graph
H. Applying
Euler’s formula (i.e.,
) together with the
Handshaking Lemma (i.e.,
), we derive the following equation:
Thus, the initial charge function on H is defined as follows:
- (a)
For every vertex , let .
- (b)
For every face , let .
A set of discharging rules are then applied to redistribute the charges among the vertices and faces. During the discharging process, the total sum of charges remains unchanged at
. Upon completing the redistribution, we derive a new charge function
(say) such that
for every
, leading to the following contradiction:
The discharging rules are defined as follows:
- (R1)
Each -vertex gives to each incident 5-face.
- (R2)
Each -vertex gives 2 to each adjacent bad 2-vertex, and gives 1 to each adjacent good 2-vertex.
Now, we determine the new charge for all . First, we consider the new charge of each .
- (1)
. If v is a bad 2-vertex, then by Claims 2, 3, 5 and (R2), . If v is a good 2-vertex, then by Claims 2, 3, 5 and (R2), .
- (2)
. One needs to set .
- (3)
. From Fact 2, we have that v is incident with at most four 5-faces. Then, by Claim 5 and (R1), we have .
- (4)
. Based on Claim 7, when v is adjacent to a good 2-vertex, it is incident with at most five 5-faces. Therefore, from (R1) and (R2), we have ; when v is adjacent to bad 2-vertices, by Fact 2, it is incident with at most four 5-faces. Thus, by (R1) and (R2), we get .
- (5)
. By Claim 8, we know that v is incident with at most six 5-faces. Therefore, it follows from (R1) and (R2) that .
- (6)
. Together with Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, is adjacent to at most three good 2-vertices and is incident with seven 5-faces, we have ; when v is adjacent to bad 2-vertices, we have .
- (7)
. Based on Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, is adjacent to at most four good 2-vertices and is incident with eight 5-faces, then ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that .
- (8)
. From Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most five good 2-vertices and incident with nine 5-faces, and thus, ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we get .
- (9)
. According to Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most six good 2-vertices and incident with ten 5-faces, and thus, ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we get ; when v is adjacent to four bad 2-vertices, we obtain .
- (10)
. From Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most seven good 2-vertices and incident with eleven 5-faces, hence ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we obtain ; when v is adjacent to four bad 2-vertices, we get ; when v is adjacent to five bad 2-vertices, we have .
- (11)
. By Claim 10, v is adjacent to at most k good 2-vertices and incident with k 5-faces. Therefore, according to (R1) and (R2), we have .
Next, we will consider the new charge of every .
- (a)
When , from Fact 1 (3), f is incident with at least two -vertices. Therefore, from (R1), we have .
- (b)
When , it follows that .
According to the process of the charge transfer described above, we present the following
Table 2 to provide a clearer understanding and observation.
Consequently, the condition holds for all , resulting in a contradiction. The proof is therefore completed. □