1. Introduction
Let
be a bounded domain with Lipschtz boundary
,
,
and
be a positive parameter, with which we want to study the following Dirichlet problem:
where
is a suitable Carathéodory function that satisfies subcritical growth condition and a certain behavior at
and at 0. This paper was inspired by a study by [
1], who were the first to introduce the differential operator
, called the degenerate
-Laplacian with non-negative weight functions
. The interest in Equation (
1) started long ago when the question of stability in some non-smooth minimization problems was raised during the imaging of electrical conductivity (see, for example, refs. [
2,
3,
4] and therein references). Here, we extend the results of [
5] in which the authors studied Problem (
1) with
, known as the weighted
p-Laplacian case, and we obtain the existence and location of at least three weak solutions.
We refer the reader to [
6,
7,
8] for an overview on nonlinear degenerate elliptic equations. I would like to mention related works dealing with existence results for degenerate
p-Laplacian or
-Laplacian and convection terms via different methods, like the pseudomonotone operator theory or sub-super solution methods that are referred to in [
9,
10,
11,
12,
13,
14] or like the case of symmetric solutions among them in [
15,
16,
17,
18].
In this paper, we focus on the existence, boundedness and multiplicity of solutions for problems driven by a degenerate -Laplacian operator with the weight functions g and h. We point out that, if , we come back to a nonlinear elliptic problem driven by a classical -Laplacian. On the other hand, if , , we obtain the double phase operator.
For the weight function with , we assume that a further condition holds:
There exists a positive constant
such that
The main novelty of this work is the presence of an unbounded coefficient in the equation that is used to overcome this difficulty. The framework is adapted to an appropriate weighted Sobolev space, taking the constraints into account in an essential way.
This paper is organized as follows: In
Section 2, we introduce weighted Sobolev spaces and recall some facts about them. In
Section 3, we prove our main result (Theorem 2) and two special cases (Theorems 3 and 4).
2. Basic Results on Weighted Sobolev Spaces
We start by introducing the weighted Sobolev spaces that we use throughout this paper, and we present some of their properties. For a comprehensive treatment of weighted Sobolev spaces, we refer to [
19,
20].
The weighted Banach space with a weight function
satisfying Condition (
2) is defined by
endowed with the following norm:
The weighted Sobolev space with a weight function
satisfying Condition (
2) is defined by
endowed with the following norm:
is a uniformly convex (hence reflexive) Banach space and
is an its subset (see [
14]).
is the closure of
with respect to the norm
.
On
, we consider the equivalent norm
If we consider
s as given by (
2) and the exponent
, we obtain
Then, the following embedding is continuous:
The critical exponent of
is given by
Through this paper, we assume that
. Using the Sobolev embedding theorem and the Rellich–Kondrachov compact embedding theorem, we have that
is a continuous embedding in
if
, and the embedding is compact if
. Taking into account (
3),
where
is the best Sobolev constant for the embedding
(see [
21,
22]).
From Holder’s inequality and (
4), we obtain
where
is the Lebesgue measure of
in
. In particular, we observe that, since
, we have
. Then, Equation (
5) also holds for
.
Using the other non-negative weight
, we have the corresponding degenerate space
and the semi-norm
The following proposition shows the relation between the spaces (see proposition 1 of [
1]).
Proposition 1. Let and assume thatThen, there is a continuous embedding . Denote the topological dual space of
by
and the duality bracket by
. Thanks to Proposition 1 and Condition (
2), the (negative) degenerate
-Laplacian
is well defined. It is a coercive operator, that is,
, and it has the
property, i.e., any sequence
that satisfies
in
and
Then,
in
. For the proof of these properties, we refer to [
1].
3. Bounded Weak Solutions
In this section, we prove the existence of at least three bounded weak solutions for every
in an appropriate interval. These solutions are obtained as critical points of an energy functional related to Problem (
1) taking into account Proposition 1,
where
for all
.
The (negative) degenerate
p-Laplacian with the weight
satisfying Condition (
2) is the operator
defined by
We also use the first eigenvalue
of the operator
(see Lemma 3.1 of [
19]).
We start assuming that the nonlinearity f satisfies a subcritical growth condition
There exist two non-negative constants,
and
, and a constant
such that
For later use, we have the following condition:
There exists one non-negative constant
with
, a function
such that
A weak solution of Problem (
1) is any
such that
for all
.
Notice that, under Assumptions (
2), (
6) and
, the integrals exist by the definition of a weak solution.
We are now in a position to prove the following a priori estimate for the solutions of Problem (
1):
Lemma 1. Under Assumptions (H) and (H1), the set of solutions to Problem (
1)
is bounded in . Proof. Acting on (
11) with the test function
results in
Hypothesis (H1), in conjunction with (
10), ensures that
Taking into account that
, a conclusion can be drawn. □
In this paper, we want to prove the existence of at least three weak solutions. Our main tool that we use is the following variational theorem obtained in [
23] (see also [
24]).
Theorem 1. Let X be a real Banach space and let Φ,
be two continuously Gateaux differentiable functionals with Φ
bounded below. Assume that . Assume that there are and , with , such thatand, for eachthe functional is bounded from below and satisfies Condition . Then, for each , the functional admits at least three critical points.
In order to study Problem (
1), we split the energy functional given by (
8) into two functionals
defined by
and
are continuously Gâteaux differentiable functionals, whose Gâteaux derivatives at point
are given by
and
for every
.
Remark 1. The functional Φ
is sequentially weakly lower semicontinuous since Φ
is continuous and convex on (see [
21,
25]
). Important properties on functionals and are listed in the following propositions:
Proposition 2. Assume that Hypothesis (H) holds, and with . Then, Proof. Hypothesis
enables us to assert that
in
and in
. Therefore,
for
. □
Proposition 3. Assume that Hypothesis (H) holds. The functional is sequentially weakly continuous in .
Proof. The operator is the composition of the continuous and bounded mapping , which takes a value in and the linear embedding , which is compact, as it is the adjoint of the compact embedding . Therefore, is a compact operator.
Taking into account Corollary 41.9 of [
26], since
is reflexive,
is sequentially weakly continuous. □
Since
is a bounded domain in
, we can find
such that
, the ball of center
and radius
, which is contained in
. In the following, we use the constants
where
Now, we formulate and prove our main results.
Theorem 2. Assume (
2)
, (
6)
, Hypotheses (H) and (H1), and that there exist two positive constants c and d, with , such that - (i)
for all a.e. and for every .
- (ii)
where ,
, and γ are given by .
Then, for eachProblem (1) admits at least three bounded weak solutions. Proof. Consider the energy functional
I given by (
8) and
,
as in (
13). Taking into account Remark 1 and Proposition 3, the energy functional
I is sequentially weakly lower semicontinuous.
Consider
defined by
Next, we obtain
and, taking into account (i),
Then,
Set
. From
, one has
.
For all
, we have
. Then,
Our aim is to apply Theorem 1. The functionals and satisfy all regularity assumptions requested in Theorem 1.
On the other hand, .
Fix
. From (ii), we observe that one has
, moreover for each
, one has
We claim that the operator
I is coercive. If
from (
17), we have
for every
. If
, Condition (
17) becomes
which implies that
being
Now, we have that
I is bounded from below because it is coercive and sequentially weakly lower semicontinuous. Now, we are going to prove that
I satisfies Condition
. Consider a sequence
such that
is bounded and that
converges to 0 in
. Since
I is coercive, the sequence
is bounded and, up to a subsequence,
with
. Hence,
and, from Proposition 3, we have
By the
property of
in
(we recall that
), we have that
in
. Hence,
I fulfills Condition
.
All assumptions of Theorem 1 are verified. Thus, for each
Problem (
1) admits at least three weak solutions. Moreover, taking Lemma 1 into account, the solutions are bounded. □
Let us now consider the special case when f is a positive continuous function.
Theorem 3. If Conditions (
2)
and (
6)
hold, let be a positive continuous function, satisfying with . Moreover, assume that Then, there exists such that for every , Problem (1) admits at least three non-negative bounded weak solutions.
Proof. Using a similar argument as in [
27] (Lemma 3.3) and [
28] (Theorem 3.3) from (
18), we have
Set
, where
,
R and
are given as in Theorem 2. For each
, there is
such that
. Using
, we define the function
as in Theorem 2. From (
19), there is
, such that
Then, Condition (
12) of Theorem 1 is satisfied.
Moreover, in the proof of Theorem 2, we have already showed that, when , the functional I is coercive, bounded from below and satisfies Condition for each .
Since of all assumptions of Theorem 1 are verified, for each
, Problem (
1) admits at least three weak solutions. To prove that the weak solution
u is non-negative, we use
as a test function in (
11). Moreover, taking Lemma 1 into account, the solutions are bounded. Thus, the proof is complete. □
We obtain another result for an autonomous case.
Theorem 4. Let be a continuous function with and set with a.e. in Ω. Ifandthen there exists such that for every , Problem (1) admits at least three weak solutions. Proof. Set
, where
,
R and
are given as in Theorem 2, and
is the gamma function. Fix a positive number
. Then, there is
such that
. We consider the operator
I as in (
8), and we claim that it is coercive. In fact, we observe that from (
20), when we fix
, there exists
such that
for all
. Then, using (
5), one has
Then,
this relation leads to the coercivity of
I. Moreover,
I is bounded from below, owing to the fact that it is coercive and sequentially weakly lower semicontinuous (see Remark 1 and Proposition 3). Finally, as we have just proved in the proof of Theorem 2,
I satisfies Condition
. Arguing as in the proof of Theorem 3, we prove that Condition (
12) of Theorem 1 holds.
All assumptions of Theorem 1 are verified. Then, for each
, Problem (
1) admits at least three weak solutions. If, additionally,
f is non-negative, then the weak solutions are non-negative. If Condition
holds, the solutions are bounded. □
Now, we provide a simple example for which Theorem 4 applies, as follows:
Example 1. We consider the following problemwhere is the unit ball and f is the derivative of the function defined by . We study the problem (
23)
with ,
,
,
and . The assumption (
6)
is verified because We choose , and we have and . Thus,Then, (
2)
and Condition are satisfied. We observe that Then, owing to Theorem 4, there exists such that the problem (
23)
admits at least three non-negative weak solutions for each .