2. Preliminaries
Let C be a nonempty closed convex subset of a Banach space X. Let us denote the set of real numbers by and the set of natural numbers by Moreover, we denote the image of any element c under the function g by and the image of under g by .
Definition 1. Consider a mapping and
- (i)
If for all we have then g is a k-Lipschitzian mapping. For some g is Lipschitzian. Therefore, 1-Lipschitzian mapping is non-expansive, whereas, a contraction is also a k-Lipschitzian with .
- (ii)
If is an identity mapping, then g is called periodic with period n.
- (iii)
If for all we have then g is -rotative. For some g is n-rotative and for some and g is rotative.
Using we denote the class of all -rotative k-Lipschitzian mappings g from C into itself.
Theorem 1 ([
1]).
For each and , there is a real number , such that if and then g has a fixed point in X. It is easy to observe that
in Theorem (1) depends on
. Therefore, we can define
It is clear from Theorem (1) that, for the existence of a fixed point in Banach space
X with
and
we have
In the literature, we can find certain results about some upper and lower bounds of
(for more details, we refer readers to [
7,
8,
9,
10,
11,
12,
13,
14,
15]). In this research article, we restrict the space to
and use
rotative mapping to find the precise values of
.
The following results give the bounds of and for a Banach space X and a Hilbert space H.
The obtained bounds of
and
show that the greatest lower bound is no greater than
This immediately raises a question:
Is it possible to find the exact value of for some and Goebel and Koter [
1] proved some fixed point results by obtaining the upper and lower bounds of
but remained unable to find its precise value. In this paper, we find the exact value of
for certain values of
and
Definition 2. Let be a metric space. A mapping is said to be a F-contraction if , such that ,where is a mapping that satisfies the following conditions: - (F1)
For all such that we have
- (F2)
For every positive sequence { if, and only if,
- (F3)
for some
Let be the set of all functions that satisfy these three conditions (F1)–(F3).
Example 1. Let , where defined as:
- 1.
- 2.
- 3.
- 4.
Then,
Wardowski [
2] established the following fixed point theorem, which is regarded as a generalization of the Banach contraction principle.
Theorem 2. Let be a F-contraction in a metric space . Then for every the sequence converges to a unique fixed point in X.
Enthused by Wardowski’s results, there many authors are attempting to extend and refine this idea by relaxing some of its conditions, generalizing the definition space or modifying the respective contraction type mapping. In this paper, we introduce a significant modification to the F-contraction, named F-rotative mapping. It is important to note that a contraction may or may not be a rotative mapping.
3. Main Results
In this section, we first define a control function
F with less restrictive conditions than the conditions used by Wardowski [
2].
Consider a strictly increasing function that satisfies the following conditions:
F is continuous on
In the set of all functions F satisfying is represented by
Example 2. Let defined as:
- 1.
- 2.
- 3.
- 4.
Then,
Remark 1. In the comparison of conditions (F1)–(F3) with the conditions (F1’), (F3’), together with the given examples, one can easily observe that by relaxing some conditions of control function F, we can find a large number of functions that will be helpful for weakening certain conditions on the existence theorem applications of a kind of differential equation.
Definition 3. Let be a metric space. A mapping is said to be F-rotative if there is a function with such that, for all , and , we have It is interesting to note that t can take negative values as well, which means that, for some , we may have , or, equivalently, . This means that F-rotative mappings belong to a larger class than F-contractions.
Theorem 3. Let be a 2-rotative continuous mapping, where I is a non-empty, closed interval of . If, for some ,then g admits a fixed point. Proof. Using the trichotomy property of a real number, for some , we have
- (A)
- (B)
- (C)
If is true, then c is the fixed point of g.
Let is true. We will prove that .
Using the inequality (
1), we have
which contradicts
g is
rotative. Therefore, inequality (
2) is not true.
Inequality
yields,
or,
which is a contradiction. Therefore, the inequality (
3) is also not true.
Therefore, the falsity of inequalities (
2) and (
3) implies the truth of the following inequality
We can define . Since is a continuous function, so is .
For
so that
Likewise, if
we can write
Since and , it follows from Bolzano Theorem that there exists a number such that
Hence, we have ; that is, g has a fixed point.
Now, if
is true, that is,
, we will prove that
Suppose, however, that we have
Using (
1), we can write
which is a contradiction, as
g is
rotative. Therefore, (
5) is not true.
Similarly, if we suppose that
From inequality (
1), it follows that
or,
which is a contradiction. Therefore, the inequality (
6) is also not true.
Therefore, the falsity of inequalities (
5) and (
6) implies the truth of the following inequality
Let Since is a continuous function, then is also continuous.
Likewise, if
we can write
Therefore, guarantees the existence of a fixed point for all three possibilities (A), (B), (C). □
Theorem 4. Every 2-rotative continuous mapping has a fixed point in a non-empty closed interval of
Proof. Let
be a 2-rotative continuous mapping, where
I is non-empty closed interval of
. If
g is nonexpansive, then by Goeble and Koter the mapping
g admits the fixed point (see, [
1]). Suppose that
g is not nonexpansive mapping; then, the distance between some or all of its iterates must expand. Suppose that for some
,
Then, there exists
, such that
Therefore, Theorem (3) guarantees the existence of the fixed point of g. □
Since we have proved that every
rotative continuous mapping in
has a fixed point, it is easy to observe that
Therefore,
That provides an answer to the questions raised by Goebel and Koter [
1], and Górnicki [
16] that, under certain conditions on
the number
attains the value
Corollary 1. Let be a complete metric space, with , such that Let be a 2-rotative continuous mapping, such that, for each , one of the following condition holds:
- 1.
is an increasing function.
- 2.
is a decreasing function.
Then, the arguments of Theorems 3 and 4 ensure the existence of the fixed point of g in X.
Theorem 5. Let I be a non-empty closed interval in . Then, a F-rotative continuous mapping with has a fixed point for all
Proof. Using the definition of
F-rotative mapping, we can write
The condition
in the definition yields
Now, the condition
will imply
or
which shows that
g is
rotative continuous mapping in
I. Therefore, Theorem 4 guarantees the existence of a fixed point. □
Theorem 6. Let C be a nonempty closed convex subset of a Banach space X. If a k-Lipschitzian mapping represents a F-rotative mapping with and such that , then g has a fixed point in X.
Proof. Since
g is a
k-Lipschitzian mapping, we can write
for all
and
.
If , then g, being a non-expansive mapping, admits a fixed point.
Next, for some , along with F-rotative mapping, we will prove that
Using the definition of
F-rotative mapping, we can write
The condition
yields
Moreover, the condition
also implies
or,
which shows that
g is
rotative mapping in
X. Then,
such that
and
. Therefore, Theorem 1 guarantees that
. □
Remark 2. It is important to note that the condition we used to prove the existence of fixed point result of k-Lipschitzian mapping is weaker than the condition used in Theorem 1 (see [1]) as it does not restrict k to be slightly greater than 1. Lemma 1. Consider a real valued function g: defined by
we can writeor,or, Therefore, for g to be 2–rotative, we must have Example 3. Let be a F-rotative mapping with , such thatwhere -contraction mapping. We will prove that a F-rotative mapping has fixed point.
By applying the logarithm, we haveor, Therefore,which is a rotative mapping and guarantees fixed point of F-rotative mapping in . 4. Application
Next, we apply our work to establish the existence of solutions for a nonlinear fractional differential equation considered in [
3,
17].
Let represents the Caputo fractional derivative of order
Consider the following problem:
via the integral boundary conditions
Consider a continuous function
and a Banach space
of continuous functions
from
into
. Define a Caputo derivative of fractional order
for a continuous function
as follows:
where
denotes the greatest integer, which is no greater than
. Next, for a continuous function
we define the Riemann–Liouville fractional derivatives of order
as follows:
such that the function of
t on the right side is point-wise defined on
, see [
18].
Next, we establish the existence theorem.
Theorem 7. 1. For all and with , consider a function and such that - 2.
For some such that , define as:and - 3.
for each and implies ,
- 4.
if is a sequence in X such that in X and for all , then for all
Then, problem (8) has at least one solution. Proof. Since
represents the solution to (
8) if, and only if, it satisfies the following integral equation
The problem (
8) is equivalent to finding
, which is a fixed point of
.
Now, let
such that
for all
. From
, we have
Thus, for each
, we have
or,
By applying logarithm, we can write
and hence
which proves that
is a
F-rotative in
X and the existence of
such that
Hence,
is a solution to problem (
8). □
Remark 3. Several results in the literature provide various applications to differential and integral equations concerning F-contraction mapping (For details, see [3,19,20,21,22] etc.). F-contraction represents a generalization of the famous Banach contraction Principle [23]. Since the relation indicates that the mapping g is a contraction and the relation indicates that the distance between consecutive iterates of g for some x may also expand. Therefore, the relation is a significant modification of . Moreover, the provided applications of our obtained result concerning F-rotative mapping has weakened the main condition of F-contraction by allowing for some of its iterates to expand the distance between them.