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Article

Strong Chromatic Index of Outerplanar Graphs

1
School of Mathematics and Information Technology, Hebei Normal University of Science and Technology, Qinhuangdao 066004, China
2
School of Management, Beijing University of Chinese Medicine, Beijing 100029, China
3
Department of Mathematics, Zhejiang Normal University, Jinhua 321004, China
*
Author to whom correspondence should be addressed.
Research Supported Partially by NSFC (No. 12001156).
Research Supported Partially by NSFC (No. 12071048) and Science and Technology Commission of Shanghai Municipality (No. 18dz2271000).
§
Research Supported Partially by NSFC (No. 12031018).
Axioms 2022, 11(4), 168; https://doi.org/10.3390/axioms11040168
Submission received: 4 February 2022 / Revised: 7 March 2022 / Accepted: 3 April 2022 / Published: 8 April 2022
(This article belongs to the Special Issue Graph Theory with Applications)

Abstract

:
The strong chromatic index χ s ( G ) of a graph G is the minimum number of colors needed in a proper edge-coloring so that every color class induces a matching in G. It was proved In 2013, that every outerplanar graph G with Δ 3 has χ s ( G ) 3 Δ 3 . In this paper, we give a characterization for an outerplanar graph G to have χ s ( G ) = 3 Δ 3 . We also show that if G is a bipartite outerplanar graph, then χ s ( G ) 2 Δ ; and χ s ( G ) = 2 Δ if and only if G contains a particular subgraph.
MSC:
Graph Theory with Applications

1. Introduction

Only simple graphs are considered in this paper. For a graph G, we use V ( G ) , E ( G ) , and Δ ( G ) to denote its vertex set, edge set and maximum degree, respectively. A vertex v is called a k-vertex (or k + -vertex) if the degree d G ( v ) of v is k (or at least k). Let N G ( v ) denote the set of vertices adjacent to v in G. If no ambiguity arises in the context, Δ ( G ) , d G ( v ) , and N G ( v ) are simply written as Δ , d ( v ) , and N ( v ) , respectively. A subgraph of G is called a clique if any two of its vertices are adjacent in G. A subset I V ( G ) of a connected graph G is called a clique-cut if G [ I ] is a clique and G I is disconnected.
A proper edge-k-coloring of a graph G is a mapping ϕ : E ( G ) { 1 , 2 , , k } such that ϕ ( e ) ϕ ( e ) for any two adjacent edges e and e . The chromatic index χ ( G ) of G is the smallest k such that G has a proper edge k-coloring. An edge coloring of the graph G is called strong if every color class induces a matching in G. The strong chromatic index of G, denoted χ s ( G ) , is the smallest k such that G has a strong edge-k-coloring.
The strong edge-coloring of graphs was introduced by Fouquet and Jolivet [1]. In 1985, Erdos and Nešetřil raised the following conjecture and showed that the upper bounds are tight:
Conjecture 1.
For a graph G,
χ s ( G ) 1.25 Δ 2 , if Δ is even ; 1.25 Δ 2 0.5 Δ + 0.25 , if Δ is odd .
Using probabilistic method, Molloy and Reed [2] showed that χ s ( G ) 1.998 Δ 2 when Δ is sufficiently large. This result was further improved in [3] to that χ s ( G ) 1.93 Δ 2 for any graph G. Using Four-Colour Theorem and Vizing Theorem, Faudree et al. [4] showed that every planar graph G has χ s ( G ) 4 Δ + 4 ; and constructed a planar graph G such that χ s ( G ) = 4 Δ 4 .
A planar graph is called outerplanar if it has a plane embedding such that all the vertices lie on the boundary of the unbounded face. It was shown in [5] that a graph G is outerplanar if and only if G is K 4 -minor-free and K 2 , 3 -minor-free. Hence outerplanar graphs are special K 4 -minor-free graphs. Wang et al. [6] showed that every K 4 -minor-free graph G with Δ 3 has χ s ( G ) 3 Δ 2 and the upper bound is tight. Hocquard et al. [7] proved that every outerplanar graph G with Δ 3 has χ s ( G ) 3 Δ 3 and the upper bound is tight.
In this paper we will give a characterization for an outerplanar graph G with Δ 3 to have χ s ( G ) = 3 Δ 3 .

2. Sun-Graphs

Suppose that G is an outerplanar graph. We embed G in the plane so that all the vertices occur in the boundary of unbounded face. Let F ( G ) denote the set of faces in G. The unbounded face, denoted by f 0 ( G ) , of G is called outer face, and other faces inner faces. For a face f F ( G ) , the boundary of f is denoted by b ( f ) . A 3-face with x , y , z as boundary vertices is written as [ x y z ] . The edges lying in the outer face are called outer edges and other edges inner edges. An inner face f is called an end-face if b ( f ) contains at most one inner edge. A leaf of G is a vertex of degree 1, and a pendant edge is an edge incident to a leaf. For a vertex v V ( G ) , let L ( v ) denote the set of pendant edges at vertex v. For a cycle C, an edge x y E ( G ) \ E ( C ) is called a chord of C if x , y V ( C ) .
Let F 1 denote a subgraph of G, which consists of a 3-cycle C 3 = x 0 x 1 x 2 x 0 with d G ( x i ) = Δ 3 for i = 0 , 1 , 2 .
Let F 2 denote a subgraph of G, which consists of a 4-cycle C 4 = x 0 x 1 x 2 x 3 x 0 with d G ( x 0 ) = d G ( x 1 ) = Δ 3 .
Let F 3 denote a subgraph of G, which consists of a 7-cycle C 7 = x 0 x 1 x 6 x 0 with d G ( x i ) = 3 for i = 0 , 1 , , 6 .
We assume that C 4 in F 2 and C 7 in F 3 have no chord.
The configurations F 1 , F 2 , F 3 are depicted in Figure 1. By the outerplanarity of G, for F j , j { 1 , 2 , 3 } , some vertex y i N ( x i ) \ { x i 1 , x i + 1 } may identify with some vertex y i + 1 N ( x i + 1 ) \ { x i , x i + 2 } , but there is at most one such pair { y i , y i + 1 } satisfying y i = y i + 1 , where indices i are taken as modulo n.
Lemma 1
([7]). If G is an outerplanar graph with Δ 3 , then χ s ( G ) 3 Δ 3 .
Lemma 2.
Let F 1 , F 2 , F 3 are defined as above. Then
(1)
χ s ( F 1 ) = 3 Δ 3 .
(2)
χ s ( F 2 ) = 3 Δ 3 .
(3)
χ s ( F 3 ) = 6 .
Proof. 
(1)
Since | E ( F 1 ) | = 3 Δ 3 and it is easy to check that any two edges of F 1 have distance at most two, so it follows that χ s ( F 1 ) = 3 Δ 3 .
(2)
Applying the similar analysis as in (1), we can derive that χ s ( F 2 ) = 3 Δ 3 .
(3)
It is evident that χ s ( F 3 ) 6 by Lemma 1. Conversely, assume that F 3 admits a strong edge-5-coloring ϕ using the color set C = { 1 , 2 , , 5 } . Let E i denote the set of edges colored with the color i under the coloring ϕ . Set E * = E ( F 3 ) E ( C 7 ) . First, it is easy to inspect that | E i | 3 for each i C . Next, because | E ( F 3 ) | = 14 and | C | = 5 , we can assume that | E i | = 3 for i = 1 , 2 , 3 , 4 and | E 5 | = 2 . Since | E * | = 7 , some E i for i { 1 , 2 , 3 , 4 } , say i = 1 , satisfies | E 1 E * | 1 . It implies that | E 1 E ( C 7 ) | 2 . On the other hand, it is easy to inspect that | E 1 E ( C 7 ) | 2 . So | E 1 E ( C 7 ) | = 2 and | E 1 E * | = 1 , however such coloring is impossible, a contradiction. This shows that χ s ( F 3 ) 6 . Consequently, χ s ( F 3 ) = 6 .
 □
Let C n = x 0 x 1 x n 1 x 0 be a cycle with n 3 . Let k 3 be an integer. At each vertex x i , we glue k 2 leaves and write the resultant graph as S n k . Then S n k is an outerplanar graph with maximum degree k and order n ( k 1 ) . We call S n k a sun-graph with parameters n and k. If k = 3 , then we use y i to denote a leaf adjacent to x i for i = 0 , 1 , , n 1 .
As an easy observation, we have the following:
Lemma 3.
Let C n be a cycle with n 3 . Then
χ s ( C n ) = 5 , if n = 5 ; 3 , if n 0 ( mod 3 ) ; 4 , otherwise .
Lemma 4.
Let S n 3 be a sun-graph with n 3 . Then
χ s ( S n 3 ) = 6 , if n = 3 , 4 , 7 ; 5 , otherwise .
Proof. 
If n = 3 , 4 , 7 , the conclusion follows immediately from Lemma 2. So suppose that n 3 , 4 , 7 . It holds trivially that χ s ( S n 3 ) 5 since S n 3 contains two adjacent 3-vertices. To show that χ s ( S n 3 ) 5 , we make use of induction on n. It remains to construct a strong edge-5-coloring ϕ of S n 3 using the color set C = { 1 , 2 , , 5 } .
  • If n = 5 , then we color the edges in { x i y i , x i + 2 x i + 3 } with i + 1 for i = 0 , 1 , 2 , 3 , 4 , where indices are taken as modulo 5.
  • If n 0 (mod 6), then we alternatively color the edges in E ( C n ) with 1 , 2 , 3 , and color alternatively pendant edges with 4 , 5 .
  • If n = 8 , then we color { x 1 y 1 , x 3 x 4 , x 6 x 7 } with 1, { x 3 y 3 , x 0 x 1 , x 5 x 6 , } with 2, { x 5 y 5 , x 0 x 7 , } { x 2 x 3 } with 3, { x 7 y 7 , x 1 x 2 , x 4 x 5 } with 4, and { x 0 y 0 , x 2 y 2 , x 4 y 4 , x 6 y 6 } with 5.
  • If n = 9 , then we color { x 1 y 1 , x 3 y 3 , x 8 y 8 , x 5 x 6 } with 1, { x 0 y 0 , x 5 y 5 , x 7 y 7 , x 2 x 3 } with 2, { x 2 y 2 , x 4 y 4 , x 6 y 6 , x 0 x 8 } with 3, { x 0 x 1 , x 3 x 4 , x 6 x 7 } with 4, and { x 1 x 2 , x 4 x 5 , x 7 x 8 } with 5.
Now assume that n 10 and n ¬ 0 (mod 6). Consider the graph S n 5 3 . Note that n 5 5 , and n 5 7 . By the induction hypothesis, χ s ( S n 5 3 ) = 5 . Let ϕ be a strong edge-5-coloring of S n 5 3 , so that ϕ ( x 0 x 1 ) = 1 , ϕ ( x 0 y 0 ) = 2 , ϕ ( x n 7 x n 6 ) = 3 , ϕ ( x n 6 y n 6 ) = 4 , and ϕ ( x 0 x n 6 ) = 5 . Clearly, S n 3 can be obtained from S n 5 3 by inserting five vertices x n 5 , x n 4 , x n 3 , x n 2 , x n 1 to the edge x 0 x n 6 and adding a leaf y j at x j for j = n 5 , n 4 , , n 1 . We extend ϕ to S n 3 by coloring { x n 3 x n 2 , x n 5 y n 5 } with 1, { x n 5 x n 4 , x n 2 y n 2 } with 2, { x n 2 x n 1 , x n 4 y n 4 } with 3, { x n 4 x n 3 , x n 1 y n 1 } with 4, and { x 0 x n 1 , x n 6 x n 5 , x n 3 y n 3 } with 5. It is easy to testify that the extended coloring is a strong edge-5-coloring of S n 3 . □
For a sun-graph S n k with C n = x 0 x 1 x n 1 x 0 , we set L ( x i ) = { e i 1 , e i 2 , , e i k 2 } for i = 0 , 1 , , n 1 . Recall that L ( x i ) stands for the set of pendant edges incident to x i .
Lemma 5.
Let S n k be a sun-graph with k , n 4 and n being even. Then
χ s ( S n k ) = 2 k , if n = 4 ; 2 k 1 , if n 6 .
Proof. 
Since k 4 , it follows that k 2 2 . The proof is split into the following two cases.
  • Assume that n = 4 . Color x 0 x 1 , x 1 x 2 , x 2 x 3 , x 3 x 0 with 1 , 2 , 3 , 4 , respectively; For i = 0 , 2 , , n 2 , we color k 2 pendant edges in L ( x i ) with colors 5 , 6 , , k + 2 ; For i = 1 , 3 , , n 1 , we color k 2 pendant edges in L ( x i ) with colors k + 3 , k + 4 , , 2 k . It is easy to see that the defining coloring is a strong edge- 2 k -coloring of S 4 k . Hence χ s ( S 4 k ) 2 k . Conversely, we note that every pendant edge of S 4 k has distance at most two to any edge in E ( C 4 ) . This implies that, for any strong edge coloring of S 4 k , the color of any pendant edge is distinct from that of edges in C 4 . Moreover, at least 2 ( k 2 ) colors are needed when we color the 4 ( k 2 ) pendant edges of S 4 k . It follows therefore that χ s ( S 4 k ) 4 + 2 ( k 2 ) = 2 k . This yields that χ s ( S 4 k ) = 2 k .
  • Assume that n 6 . It is straightforward to conclude that χ s ( S n k ) 2 k 1 since S n k contains two adjacent k-vertices. Conversely, we notice that S n 3 is a spanning subgraph of S n k . By Lemma 4, S n 3 has a strong edge-5-coloring ϕ using colors 1 , 2 , 3 , 4 , 5 . Based on ϕ , we can color the remaining k 3 pendant edges in L ( x i ) with colors 6 , 7 , , k + 2 for each i = 0 , 2 , , n 2 ; and color the remaining k 3 pendant edges in L ( x i ) with colors k + 3 , k + 4 , , 2 k 1 for each i = 1 , 3 , , n 1 . The extended coloring is a strong edge- ( 2 k 1 ) -coloring of S n k . It therefore turns out that χ s ( S n k ) 2 k 1 . Consequently, χ s ( S n k ) = 2 k 1 .
 □
Lemma 6.
Let n 4 be an odd number. Then
(1)
χ s ( S n 4 ) 8 .
(2)
χ s ( S n 5 ) 11 .
Proof. 
We first prove (1), by discussing two cases below.
  • Assume that n = 7 . Give a strong edge-7-coloring ϕ of S 7 4 as follows: ϕ ( x i x i + 1 ) = i + 1 for i = 0 , 1 , , 6 , where indices are taken as modulo 7; then we color L ( x 0 ) with 3 , 5 , L ( x 1 ) with 4 , 6 , L ( x 2 ) with 5 , 7 , L ( x 3 ) with 1 , 6 , L ( x 4 ) with 2 , 7 , L ( x 5 ) with 1 , 3 , and L ( x 6 ) with 2 , 4 .
  • Assume that n 7 . By Lemma 4, S n 3 admits a strong edge-5-coloring ϕ using the colors 1 , 2 , , 5 so that e 0 1 , e 1 1 , , e n 1 1 have been colored. Afterward, we extend ϕ to the remaining edges of S n 4 by coloring e 0 2 with 6, { e 1 2 , e 3 2 , , e n 2 2 } with 7, and { e 2 2 , e 4 2 , , e n 1 2 } with 8. It is easily seen that the resultant coloring is a strong edge-5-coloring of S n 4 .
Next we prove (2). By the result of (1), S n 4 has a strong edge-8-coloring ϕ using the colors 1 , 2 , , 8 . Based on ϕ , we can color e 0 3 with 9, { e 1 3 , e 3 3 , , e n 2 3 } with 10, and { e 2 3 , e 4 3 , , e n 1 3 } with 11. This leads to a strong edge-11-coloring of S n 5 . □
We first establish a useful claim:
Claim 1.
Let A i = { e i , e i } L ( x i ) for i = 0 , 1 , , n 1 . Let A = A 0 A 1 A n 1 . Then A can be strongly edge-5-colored on the graph S n k .
Proof. 
Since n 5 is odd, we can give an edge 5-coloring π of A as follows: coloring A 1 with 2, 4; A 2 with 3, 5; A 3 with 1, 4; each of A 0 , A 5 , A 7 , , A n 2 with 1, 3; and each of A 4 , A 6 , A 8 , , A n 1 with 2, 5. It is easy to confirm that π is a strong edge-5-coloring of A restricted in the graph S n k . □
Lemma 7.
Let k 6 , and let n 5 be odd. Then χ s ( S n k ) 2.5 k 2 .
Proof. 
If k is even, then by Lemma 6(1) and repeatedly applying Claim 1, we get that χ s ( S n k ) 8 + 5 · k 4 2 = 2.5 k 2 = 2.5 k 2 .
If k is odd, then by Lemma 6(2) and repeatedly applying Claim 1, we get that χ s ( S n k ) 11 + 5 · k 5 2 = 2.5 k 1.5 = 2.5 k 2 . □

3. Outerplanar Graphs

Suppose that G is a connected outerplanar graph. Let I V ( G ) be a clique-cut of G with 1 | I | 2 ; that is, G [ I ] is K 1 or K 2 such that G I is disconnected. If G I has at least two components each containing at least one edge, then I is said to be a separable clique-cut.
For a separable clique-cut I of G, let H 1 , H 2 , , H s ( s 2 ) denote the components of G I with | E ( H 1 ) | 1 and | E ( H 2 ) | 1 . We set G 1 = G [ E ( H 1 ) E ( I ) ] and G 2 = G [ E ( H 2 ) E ( H s ) E ( I ) ] , where E ( I ) denotes the set of edges in G which are incident to at least one vertex in I.
The following lemma plays a crucial role in the proof of our main results.
Lemma 8.
Let G be a connected outerplanar graph with a separable clique-cut I. Suppose that G 1 and G 2 are defined as above. Then
χ s ( G ) = max { χ s ( G 1 ) , χ s ( G 2 ) }
Proof. 
Let l 1 = χ s ( G 1 ) , l 2 = χ s ( G 2 ) , and l = max { l 1 , l 2 } . For i = 1 , 2 , let ϕ i be a strong edge-l-coloring of G i using the color set C = { 1 , 2 , , l } . By the definition of G i , we deduce that E ( I ) E ( G i ) for i = 1 , 2 , and E ( G 1 ) E ( G 2 ) = E ( I ) . Observe that any edge in E ( G 1 ) \ E ( I ) and any edge in E ( G 2 ) \ E ( I ) have distance at least three in G. Moreover, since the distance between any two edges in E ( I ) is less than three, no two edges in E ( I ) are assigned same color in both ϕ 1 and ϕ 2 . So we may assume that ϕ 1 ( e ) = ϕ 2 ( e ) for each e E ( I ) . Combining ϕ 1 and ϕ 2 , we get a strong edge-l-coloring of G. This shows that χ s ( G ) l . On the other hand, since G i is a subgraph of G, we have naturally that χ s ( G ) max { χ s ( G 1 ) , χ s ( G 2 ) } = l . Consequently, χ s ( G ) = l . □
Theorem 1.
Let G be an outerplanar graph with Δ 4 . If G does not contain F 1 as a subgraph, then χ s ( G ) 3 Δ 4 .
Proof. 
Assume the contrary, let G be a counterexample with | E ( G ) | being as small as possible. Then G is connected, | E ( G ) | 3 Δ 3 , and possesses the following properties:
(P1) No F 1 is contained in G or its subgraphs.
(P2)G is not strongly edge- ( 3 Δ 4 ) -colorable, but any subgraph H of G with | E ( H ) | < | E ( G ) | is strongly edge- ( 3 Δ 4 ) -colorable.
In fact, if Δ ( H ) < Δ , then by Lemma 1, χ s ( H ) 3 Δ ( H ) 3 3 ( Δ 1 ) 3 < 3 Δ 4 since Δ 4 . If Δ ( H ) = Δ , then by the minimality of G, χ s ( H ) 3 Δ ( H ) 4 = 3 Δ 4 .
(P3)G is not a tree; otherwise χ s ( G ) 2 Δ 1 < 3 Δ 4 , contradicting (P2).
By Lemma 8, the following claim holds:
Claim 2.
G does not contain a separable clique-cut I V ( G ) with 1 | I | 2 .
Embed G to the plane so that all the vertices lie in the boundary of f 0 ( G ) . Let H denote the graph obtained from G by removing all leaves. By (P3) and Claim 2, we can easily deduce Claims 3 and 4 below.
Claim 3.
H is 2-connected, and b ( f 0 ( H ) ) forms a Hamiltonian cycle. This furthermore implies that all vertices in V ( G ) \ V ( H ) are leaves.
Claim 4.
Every inner edge u v of H is incident to an end-3-face [ u v w ] such that d G ( w ) = d H ( w ) = 2 .
Claim 4 implies that 2 Δ ( H ) 4 ; for otherwise H will contain an inner edge x y with d H ( x ) 5 and { x , y } is a separable clique-cut of G.
Let G * denote the graph obtained from G by carrying out repeatedly the following operation:
( * ) If x is a 2-vertex of H incident to an end-3-face [ x y z ] , then we split x into two new vertices y 1 and z 1 so that y 1 joins with y, and z 1 joins with z.
Intuitively speaking, every 2-vertex of H which is incident to an end-3-face is replaced by two leaves in G. It is easy to see that Δ ( G * ) = Δ ( G ) , and ϕ is a strong edge-k-coloring of G * if and only if ϕ is a strong edge-k-coloring of G.
It is easily observed that G * is a spanning subgraph of some sun-graph S n k , where k = Δ ( G ) and n is the total number of 3 + -vertices in G and the number of 2-vertices in G which are not on any 3-face. As an example, we observe the graphs G and G * depicted in Figure 2.
Noting that 3 k 4 max { 2 k , 2.5 k 2 } , we deduce by Lemmas 5 and 7 that χ s ( G ) = χ s ( G * ) χ s ( S n k ) 3 k 4 = 3 Δ 4 . This completes the proof of the theorem. □
Combining Theorem 1 and Lemmas 1 and 2(1), the following theorem holds:
Theorem 2.
Let G be an outerplanar graph with Δ 4 . Then χ s ( G ) 3 Δ 3 ; and χ s ( G ) = 3 Δ 3 if and only if G contains F 1 as a subgraph.
Theorem 3.
Let G be an outerplanar graph with maximum degree Δ = 3 . If G does not contain F 1 , F 2 or F 3 as a subgraph, then χ s ( G ) 5 .
Proof. 
Assume the contrary, let G be a counterexample with | E ( G ) | being as small as possible. Then G is connected, | E ( G ) | 6 , and possesses the following properties:
(Q1) None of F 1 , F 2 , F 3 is contained in G or its subgraphs.
(Q2)G is not strongly edge-5-colorable, but any subgraph H of G with | E ( H ) | < | E ( G ) | is strongly edge-5- colorable. Actually, if Δ ( H ) 2 , then by Lemma 3, χ s ( H ) 5 . If Δ ( H ) = 3 , then by the minimality of G, we obtain that χ s ( H ) 5 .
(Q3)G is not a tree; otherwise χ s ( G ) 5 , contradicting (Q2).
By Lemma 8, G does not contain a separable clique-cut I V ( G ) with 1 | I | 2 .
Embed G to the plane so that all the vertices lie in b ( f 0 ( G ) ) . Removing all the leaves of G, we get a subgraph H of G. Similarly to the proof of Theorem 1, we conclude the following:
  • H is 2-connected, and all vertices in V ( G ) \ V ( H ) are leaves.
  • Every inner edge u v of H is incident to an end-3-face [ u v w ] such that d G ( w ) = d H ( w ) = 2 .
Let G * be the graph obtained from G by doing repeatedly the following operation:
( * ) If x is a 2-vertex of H incident to an end-3-face [ x y z ] in H, then we split x into two new vertices y 1 and z 1 so that y 1 joins with y, and z 1 joins with z.
Then Δ ( G * ) = Δ ( G ) , and χ s ( G ) = χ s ( G * ) . Note that G * is a spanning subgraph of some sun-graph S n 3 , where n is the total number of 3-vertices in G and the number of 2-vertices in G which are not on any 3-face. By Lemma 4, we derive immediately that χ s ( G ) = χ s ( G * ) χ s ( S n 3 ) 5 . □
Combining Theorem 3 and Lemmas 1 and 2, we have the following:
Theorem 4.
Let G be an outerplanar graph with Δ = 3 . Then χ s ( G ) 6 ; and χ s ( G ) = 6 if and only if G contains at least one of F 1 , F 2 , F 3 as a subgraph.
When restricted to the family of bipartite outerplanar graphs G, smaller and tight upper bounds for χ s ( G ) can be obtained.
Theorem 5.
Let G be a bipartite and outerplanar graph with maximum degree Δ 3 . Then χ s ( G ) 2 Δ ; moreover, χ s ( G ) = 2 Δ if and only if G contains F 2 as a subgraph.
Proof. 
We first show that χ s ( G ) 2 Δ . Assume the contrary, let G be a counterexample with | E ( G ) | being as small as possible. Then G is connected, other than a tree, and is not strongly edge 2 Δ -colorable, but any subgraph H of G with | E ( H ) | < | E ( G ) | is strongly edge- 2 Δ -colorable. Moreover, by Lemma 8, there is no separable clique-cut I V ( G ) with 1 | I | 2 .
Embed G to the plane so that all the vertices occur in b ( f 0 ( G ) ) . Removing all the leaves of G, we obtain a subgraph H of G. Then H is a Hamiltonian cycle without chords, and V ( G ) \ V ( H ) are all leaves. So G is a subgraph of some S n k where n = | V ( H ) | is even and k = Δ ( G ) . By Lemma 5, χ s ( G ) χ s ( S n k ) 2 k = 2 Δ .
If G contains F 2 as a subgraph, then χ s ( G ) χ s ( F 2 ) = | E ( F 2 ) | = 2 Δ . Using the foregoing proof, we get that χ s ( G ) = 2 Δ . Conversely, if G does not contain F 2 as a subgraph, then similarly to the above discussion we can show that χ s ( G ) 2 Δ 1 . □

Author Contributions

Conceptualization, Y.W. (Ying Wang) and W.W.; methodology, Y.W. (Ying Wang) and Y.W. (Yiqiao Wang); validation, Y.W. (Yiqiao Wang) and W.W.; formal analysis, Y.W. (Yiqiao Wang); investigation, S.C.; resources, S.C.; writing-original draft preparation, Y.W. (Ying Wang) and S.C.; writing-review and editing, Y.W. (Ying Wang) and W.W.; visualization, Y.W. (Yiqiao Wang); supervision, W.W.; project administration, Y.W. (Yiqiao Wang); funding acquisition, Y.W. (Ying Wang) and W.W. All authors have read an agreed to the published version of the manuscript.

Funding

This research was funded by the NSFC (No. 12001156), NSFC (No. 12071048), NSFC (No. 12031018), Science and Technology Commission of Shanghai Municipality (No. 18dz2271000).

Institutional Review Board Statement

Not applicable.

Informed Consent Statement

Not applicable.

Data Availability Statement

All relevant date are within the paper.

Conflicts of Interest

The authors declare no conflict of interest.

References

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Figure 1. Configurations F 1 , F 2 , and F 3 .
Figure 1. Configurations F 1 , F 2 , and F 3 .
Axioms 11 00168 g001
Figure 2. G * is obtained from G by carrying out ( * ) , and G * is a subgraph of S 5 4 .
Figure 2. G * is obtained from G by carrying out ( * ) , and G * is a subgraph of S 5 4 .
Axioms 11 00168 g002
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Wang, Y.; Wang, Y.; Wang, W.; Cui, S. Strong Chromatic Index of Outerplanar Graphs. Axioms 2022, 11, 168. https://doi.org/10.3390/axioms11040168

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Wang Y, Wang Y, Wang W, Cui S. Strong Chromatic Index of Outerplanar Graphs. Axioms. 2022; 11(4):168. https://doi.org/10.3390/axioms11040168

Chicago/Turabian Style

Wang, Ying, Yiqiao Wang, Weifan Wang, and Shuyu Cui. 2022. "Strong Chromatic Index of Outerplanar Graphs" Axioms 11, no. 4: 168. https://doi.org/10.3390/axioms11040168

APA Style

Wang, Y., Wang, Y., Wang, W., & Cui, S. (2022). Strong Chromatic Index of Outerplanar Graphs. Axioms, 11(4), 168. https://doi.org/10.3390/axioms11040168

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