1. Introduction
Let 
 be a non-empty set, 
X a locally convex space over the field 
 (of real or complex numbers), 
 the family of all continuous seminorms in 
X, 
 the space of all absolutely summable sequences in 
X, namely
      
      endowed with the family of seminorms 
, and 
 the locally convex space over 
 of all functions 
 such that for each 
 and 
 the set 
 is finite or empty, with the topology defined by the semi-norms 
, 
.
In particular, 
 and for 
, 
 and 
. It was proved in [
1] that 
 is quasibarrelled if and only if 
X is quasibarrelled and its strong dual satisfies the condition 
 of Pietsch and that if, in addition, 
X is complete in the sense of Mackey, then 
 is barrelled if and only if 
X is quasibarrelled and its strong dual satisfies condition 
 of Pietsch. In this case, 
X is barrelled. Through a clever use of a sliding-hump technique, it was proved in [
2] that, even in the absence of completeness in the sense of Mackey, 
 is barrelled if and only if 
X is barrelled and its strong dual satisfies condition 
 of Pietsch. Recall that 
X has the property 
 of Pietsch if for any bounded set 
 in 
 there exists an absolutely convex bounded set 
B in 
X such that the normed space 
 formed by the linear hull of 
B endowed with Minkowski functional 
 of 
B verifies that 
 is contained in the unit ball of the normed space 
, i.e.,
      
Metrizable locally convex spaces as well as dual metric locally convex spaces verify the property 
 of Pietsch ([
3]).
Ferrando and Lüdkowsky proved in [
4] that for a normed space 
X the space 
 is barrelled, ultrabornological, or unordered Baire-like (see [
5]) if and only if 
X is, respectively, barrelled, ultrabornological, or unordered Baire-like. It was proved in [
6] that for a locally convex metrizable space 
X the space 
 is quasi barrelled, barrelled, ultrabornological, bornological, unordered Baire-like, totally barrelled, and barrelled of class 
p if and only if 
X is, respectively, quasi barrelled, barrelled, ultrabornological, bornological, unordered Baire-like, totally barrelled, and barrelled of class 
p. The normed space of all continuous functions vanishing at infinity defined on a locally compact topological space with values in a normed space and endowed with the supremum norm topology is barrelled if and only if 
X is barrelled; this result was obtained in [
7], answering a question posed by J. Horváth.
The linear subspace 
 of the sequence space 
 of finite-valued sequences in the field 
 is of the first Baire category [
8]. Independently, Dieudonné ([
9], p. 133) and Saxon [
10] proved that 
 is barrelled. Schachermayer extended this result by proving that the linear hull 
 of the characteristic functions 
, with 
, and where 
 is a ring of subsets of 
, endowed with the supremum norm topology, is barrelled if and only if the vector space 
, of all bounded finitely additive scalar measures defined on 
 equipped with the supremum norm topology, verifies the Nikodým boundedness theorem, see ([
11], p. 80).
Furthermore, if 
 is a 
-algebra, the space 
 is barrelled, see ([
11], p. 80) and [
12]. Valdivia [
13] improved this result: If 
 is an increasing sequence of vector subspaces of 
 covering 
, then there is an 
 barrelled and dense in 
. From this property, 
suprabarrelled spaces are defined, also known as 
 spaces in [
14,
15]. Interesting applications of suprabarrelled spaces can be found in [
13,
16] and ([
17], Chapter 9). A natural generalization of suprabarrelled spaces are 
p-barrelled spaces. Let 
, 
 and recall, see [
18] and ([
19], Definition 3.2.1) that a 
-
net in a vector space 
E is a family 
 of vector subspaces of 
E, such that 
, 
, 
, 
, for 
, 
 and 
. Analogously, a 
linear web in 
E is a family 
 of vector subspaces of 
E, such that 
, 
, 
, 
, for 
 and 
.
All topological spaces are supposed to be Hausdorff and 
space will be used as an abbreviation of locally convex space, when misunderstanding is not possible. A locally convex space 
E is called 
p-barrelled if given a 
p-net 
 there is a 
 such that 
 is barrelled and dense in 
E (see [
19], Definition 3.2.2). Note that suprabarrelled spaces are 1- barrelled spaces. We refer the reader to [
20] for several applications of 
p-barrelled spaces, particularly in vector measures. The locally convex space 
E is 
-
barrelled if it is 
p-barrelled, for each 
 (see [
19], Definition 4.1.1) and 
E is 
baireled if each 
linear web in 
E admits a 
strand formed by dense barrelled subspaces of 
E, i.e., there exists a sequence 
 such that 
 is a barrelled and dense subspace of 
E, for each 
 (see [
21], Definition 1 and Theorem 1). It was proved in [
22] that for a 
-algebra 
 the space 
 is baireled. Other related properties can be found in [
23] and references therein.
In this paper, it is assumed that the locally convex space X is metrizable, denoting by  an increasing sequence of semi-norms defining the topology of X, i.e., for every , we have that , . Then, the locally convex space  is metrizable and its topology is defined by the semi-norms ,  and . Now for every , its support, i.e., supp , is countable since  and, by definition, for each  and  the set  is finite or empty.
The aim of the paper is to characterize those spaces 
 which are baireled. We will prove that 
 is baireled if and only if 
X is baireled (Theorem 2). In order to do this, we need the characterization for 
 to be barrelled obtained in ([
6], Corollary 2.4). For the sake of completeness, we will remind readers of this characterization in 
Section 2.
If  is a subset of , we denote by  the linear subspace of  consisting of all functions f such that . By , we denote the linear hull of a subset V of a linear space X, and, if V is absolutely convex and bounded, then  is the normed space formed by , endowed with the norm defined by the functional of Minkowski of V.
Recall that an absolutely convex bounded set 
V in 
X is a Banach disk if the normed space 
 is a Banach space, and that a locally convex space 
X is 
barrelled (
quasibarrelled) if every closed absolutely convex and absorbing (and bornivorous) subset of 
E is a neighborhood of zero. Barrelled spaces are just the locally convex spaces that verify the Banach–Steinhaus boundedness theorem. Todd and Saxon [
5] discovered an applicable and natural generalization of Baire spaces to locally convex spaces: A locally convex space 
X is called 
unordered Baire-like, if every sequence of absolutely convex and closed subsets of 
X covering 
X contains a member which is a neighborhood of zero. Finally, a locally convex space 
X is 
totally barrelled if for every sequence of subspaces 
 of 
X covering 
X, there is some 
 which is barrelled and its closure is finite-codimensional in 
X, see ([
19], Definition 1.4.1) and [
24]. Note that Baire ⇒ Unordered Baire-like ⇒ Totally barrelled ⇒Baireled 
-barrelled 
-barrelled ⇒
p-barrelled ⇒ Baire-like ⇒ barrelled⇒ quasibarrelled.
Even for metrizable locally convex spaces, 
-barrelled⇏Baireled⇏Totally barrelled ([
21], Theorems 2 and 3).
  2. Revisiting Barrelledness in 
It is well known that, if  is a continuous linear map from a Banach space E into a locally convex space F and D is the open unit ball of E, then the normed space  is isometric to the quotient , hence  is a Banach disk. If B is the closed unit ball of E, then the inclusions  imply that  is also a Banach disk.
This well known property is used in the following lemmas.
Lemma 1 ([
6], Lemma 2.1)
. Let X be a metrizable locally convex space and  a bounded sequence in  such that the set  is finite or empty for every . Then,  is contained in a Banach disk. In particular, if  and , for each , then also  is contained in a Banach disk. Proof.  The boundedness implies that 
 is finite for each 
. Then, for each 
, the inequality
        
        implies the continuity of the map 
 defined by 
. Hence, if 
B is the closed unit ball of 
, then 
 is a Banach disk that contains the sequence 
.    □
 From Lemma 1, it follows that, if T is an absolutely convex subset of  that absorbs its Banach disks, then there exists in  a countable subset  and a natural number n such that T absorbs  because, if this is not the case, there exists a sequence  such that , , for , where , , and  for  The boundedness of  and Lemma 1 implies that there exists  such that , which yields to the contradiction .
Lemma 2 ([
6], Lemma 2.1)
. Let T be an absolutely convex subset of  that absorbs its Banach disks. Then, there exists in Ω 
a finite subset Δ 
and a natural number n such that T absorbs . Proof.  By the observation preceding this lemma, it is enough to prove that, if 
T is an absolutely convex subset of 
 that absorbs its Banach disks, then there exists 
 such that 
T absorbs
        
Otherwise, there exists , with , for each . By Lemma 1, there is  such that  and we reach the contradiction .    □
 The above lemmas nicely apply to get the following characterization of barrelled .
Theorem 1 ([
6], Corollary 2.4a)
. Let X be a metrizable locally convex space and Ω 
a non void set. Then,  is barrelled if and only if X is barrelled. Proof.  Fix 
. As the quotient 
 is isomorphic to 
X and barrelledness property is inherited by quotients, see ([
25] [27.1 (4) and 28.4 (2)]), then, if 
 is barrelled, we deduce that 
X is also barrelled.
Conversely, if T is a barrel in  and B is a Banach disk in , it is obvious that T contains a neighborhood of zero in the Banach space , hence there exists a  such that . Then, by Lemma 2, there exists in  a finite subset  such that T contains a neighborhood of zero in . Hence, if X is barrelled, T also contains a neighborhood of  because the space  is isomorphic to the product , and  is barrelled.    □
 The analogous result of Theorem 1 for quasibarrelled, ultrabornological, bornological, unordered Baire like, totally barrelled, and barrelled spaces of class 
p are provided in ([
6], Corollaries 2.4 and 2.5 and Theorem 3.7). The unordered Baire-like and the totally barrelled results need in their proofs the preceding lemmas and the following nice result ([
5], Theorem 4.1): 
If the union of two countable families and  of linear subspaces of a linear space E covers E, then one of them covers E. In fact, assume that there exists 
, with 
, and there exists 
, with 
. As the subset 
 is uncountable, we may suppose that there exists 
 and 
 such that 
. This inclusion implies that 
 because 
 is a linear subspace. In particular, for 
, we obtain that 
, in contradiction with 
.
The fact that  is barrelled of class p if and only if X is barrelled of class p, for each , implies directly that  is -barrelled if and only if X is -barrelled.
  3. Baireledness
In this section, we prove that the space 
 is baireled if and only if 
X is baireled. Recall that a locally convex space 
E is baireled if each linear web in 
E contains a strand formed by Baire-like spaces [
26] and that, if 
E is metrizable, then 
E is baireled if each linear web in 
E contains a strand formed by barrelled spaces.
Let  be a non-void subset of  and let  be an element of . The element , if , and  if , and the set  are named the section of length i of t and T, respectively. With this notation, a sequence  formed by elements of  is a strand if , for each . A non-void subset  of  is increasing if, for each , there exists p scalars  verifying , for , such that  and , . If  then 
The following definition provides a particular type of increasing subsets 
U of 
 considered in ([
27], Definition 1) and named 
-trees, reminding readers of O.M. Nikodým and M. Valdivia.
Definition 1. An -tree is a non-void increasing subset  of  without strands and such that, for each , the set  is empty.
 The last condition means that elements of an -tree  do not have proper continuation in . An -tree  is an infinite subset of  if and only if . The sets , , and the set  are non trivial -trees.
If  is an increasing subset of  and  is a linear web in a space E, then  is an increasing covering of B, and for each  and each  the sequence  is an increasing covering of . In particular, if  is an -tree, then  because  does not contain strands.
By definition, a locally convex space E is non baireled if there exists a linear web  without a strand formed by Baire-like spaces. In particular, a metrizable barrelled locally convex space E is non baireled if there exists a linear web without a strand formed by barrelled spaces because a metrizable space is barrelled if and only if it is Baire-like.
Note that, if  is an increasing covering of a metrizable barrelled space E then, since E is Baire-like, we may suppose, without loss of generality that all subspaces , , are dense in E. Consequently, again because of denseness, if  is barrelled, then every , with , is barrelled.
Therefore, for a linear web  in a metrizable barrelled locally convex space E that is not baireled, we may suppose that every  is dense and barrelled or that every  is dense and not barrelled, for each . The preceding process continues inductively only when we get barrelled spaces, i.e., if the dense subspace  is barrelled, then we may suppose that , , is a sequence of dense subspaces such that for all , , are not barrelled, or all , , are barrelled; in the first case, the inductive process stops and, in the second case, we continue with the increasing sequence . As the linear web  does not contain a strand formed by barrelled spaces, then this natural induction produces a -tree , such that, for each  the space  is dense in E and not barrelled, and  is barrelled, for each .
The following lemmas are part of the proof of Theorem 2. Therefore, those lemmas consider that 
, with 
X metrizable. Moreover, we will suppose that the metrizable space 
 is barrelled and not baireled, hence 
 has a linear web 
 without a strand formed by Baire-like spaces. With the preceding induction, we obtain a 
-tree 
, such that, for each 
, we have that 
 is a non barrelled dense subspace of 
, hence there exists a barrel 
 in 
 that it is no neighborhood of zero in 
. With the barrels 
, with 
, we form
      
      and
      
⋯ and finally
      
A -tree  contained in a -tree  is cofinal in  if  is a cofinal subset of  and for each  the set  is a cofinal subset of . Note that, if  is cofinal in  and , for every , then , for every .
In the following four lemmas, we suppose the following conditions hold:
: X is a metrizable locally convex space such that  is barrelled but not baireled, being  a linear web in  without a strand formed by barrelled spaces and  the -tree such that for each  there exists a barrel  in  which is not a neighborhood of zero in  and  is a dense subspace of .
With these barrels 
, with 
, we form the sets 
, 
, ⋯, 
 and 
, given in (
1)–(
3).
Lemma 3. Assume conditions  hold and let F be a linear subspace of E, τ a locally convex topology in F finer (or equal) than the topology induced by E, and such that  is baireled. Then, there exists  such that  for .
In particular, if D is a Banach disk contained in E, there exists  such that , for .
 Proof.  By definition of baireled, it follows that, if 
 is an increasing covering of a baireled space 
E, then there exists a set 
 cofinal in 
 such that 
 is baireled and dense in 
E, for each 
 (see ([
21], Theorem 1) adding the trivial fact that, if a baireled space 
H is dense in the space 
G, then 
G is baireled). Hence, there exists an 
-tree 
 that is cofinal in 
 such that 
 is a family of baireled dense subspaces of 
. Then, for each 
, the set 
 is a neighborhood of zero in 
 endowed with the topology induced by 
, hence, by denseness, 
 is a neighborhood of zero in 
, so 
, if 
. Then, if 
, we have that 
 for 
.    □
 Lemma 4. If conditions  hold, there exists in Ω a countable subset Δ (possibly empty) and  such that  if 
 Proof.  Assume the conclusion fails. Then, we can find  such that  and . Since the set  is countable, we deduce that  and we find  with  and . Since  is countable, , which implies that there exists  with  and .
By induction, we obtain the sequence 
 such that
        
        and, by Lemma 1, this sequence is contained in a Banach disk 
D. Then, by Lemma 3, there exists 
 such that
        
        in contradiction with 
.    □
 Lemma 5. Assume conditions  hold. Then, there exists in Ω a finite subset Δ (possibly empty) and  such that  if 
 Proof.  Applying Lemma 4, it is enough to prove this lemma for 
. It is necessary to prove the existence of an 
 such that 
. Suppose this is not true. Then, by induction, we find a sequence 
 in 
 such that 
 with 
. It is clear that
        
        and, by Lemma 1, this sequence is contained in a Banach disk 
D. By Lemma 3, there exists 
 such that 
, in contradiction with 
.    □
 Lemma 6. Let us suppose that conditions  hold. If X is baireled, then there exists a -tree  cofinal in  such that , if .
 Proof.  It is obvious that we only need to prove that there exists 
 such that 
. By Lemma 5, it is enough to show that, given a finite subset 
 of 
, there exists 
 such that 
. However, this follows from Lemma 3 and the trivial facts that 
 and 
 are isomorphic and that the finite product of baireled spaces is baireled ([
21], Proposition 7).    □
 Theorem 2. Let X be a metrizable locally convex space and Ω a non void set. Then,  is baireled if and only if X is baireled.
 Proof.  Assume that X is baireled and that the metrizable space  is not baireled. Then, by Theorem 1, the space  is barrelled, hence there exists a linear -web  in  consisting of dense subspaces such that, for each , there exists a barrel  in  which is not a neighborhood of zero in . By Lemma 6, there is  such that  and the barrelledness implies that  is a neighborhood of zero in . Then, we get the contradiction that  is a neighborhood of zero in . Therefore, the assumption that X baireled implies that  is baireled.
The converse follows from the trivial facts that for 
 the quotient
        
        is isomorphic to 
X and that the baireledness is inherited by quotients ([
21], 5 Permanence properties of Baireled spaces).    □
 We apply Theorem 2 to get the following closed graph theorem for baireled spaces.
Theorem 3. Let X be a metrizable baireled locally convex space and let F be a locally convex space that contains a linear web  such that  admits a topology  finer than the topology induced by F so that  is a Fréchet space, for each . Let f be a linear map from  into F with closed graph. There exists in  a strand  such that f is a continuous mapping from  into , for each .
 Proof.  Let 
 for each 
. By Theorem 2, there exists a strand 
 such that each 
 is barrelled and dense in 
. The map 
f restricted to 
 has closed graph. By ([
28], Theorems 1 and 14), this restriction admits a continuous extension 
U to 
 with values in 
 and clearly 
.    □
 This theorem is correct if we replace “Fréchet space, for each 
” by “
-space, for each 
” (see [
28]). Recall that every 
-space, in particular every Fréchet space, is a 
-space. Reference [
29] contains very interesting properties.