Solving a Fabrication Lot-Size and Shipping Frequency Problem with an Outsourcing Policy and Random Scrap
Abstract
:1. Introduction
2. Literature Review
3. Methods
Problem Statement and Mathematical Modeling
- Tπ = the replenishment cycle time of the proposed system,
- T = the replenishment cycle time for a production system without outsourcing,
- πQ = outsourcing quantity per replenishment cycle,
- K = in-house production setup cost per cycle,
- C = unit fabrication cost, which includes unit cost of inspection,
- h = holding cost per item per unit time,
- CS = unit disposal cost,
- Kπ = fixed order (setup) cost of outsourcing items per cycle,
- Cπ = unit purchasing cost of outsourcing items,
- β1 = the relating parameter between Kπ and K, that is Kπ = (1 + β1)K where 0 ≤ β1 ≤ 1,
- β2 = the relating parameter between Cπ and C, that is Cπ = (1 + β2)C where β2 ≥ 0,
- H1 = on-hand inventory in units at the time in-house production ends,
- H = maximum level of on-hand inventory in units after receiving outsourcing items,
- t1π = production uptime for the proposed system,
- t2π = time required for transporting all items,
- t1 = uptime of the conventional EPQ model,
- t2 = delivery time of the conventional EPQ model,
- I(t) = on-hand inventory of perfect quality items at time t,
- Id(t) = on-hand inventory of scrap items at time t,
- K1 = fixed transportation cost per shipment,
- CT = unit transportation cost,
- n = number of fixed quantity installments of the finished batch to be delivered per cycle,
- tn = the fixed interval of time between each installment delivered during downtime t2π,
- h2 = unit stock holding cost per unit time at the customer’s side,
- Ic(t) = on-hand inventory of stocks at the customer’s side at time t,
- TC(Q,n) = total production-inventory-delivery cost per cycle for the proposed system,
- E[TCU(Q,n)] = the long-run average costs per unit time for the proposed system.
4. Results
4.1. The Convexity of E[TCU(Q, n)]
4.2. Deriving the Optimal Operating Policy
- (1)
- Let n = 1 initially, and apply Equations (14) and (21) to compute the values of Q, δn, δn+1, and (δn+1 − δn).
- (2)
- Let n = n + 1, and calculate the values of Q, δn, δn−1, δn+1, (δn−1 − δn), and (δn+1 − δn).
- (3)
- If both (δn−1 − δn) ≥ 0 and (δn+1 − δn) ≥ 0, then go to step (4); otherwise, go to step (2).
- (4)
- Stop. The optimal number of shipments n* and optimal lot size Q* are obtained.
5. Implications
5.1. Numerical Example
- h = $30 per item per year,
- CS = $20, disposal cost per scrap item,
- K1 = $800, fixed transportation cost per shipment,
- CT = $0.5, transportation cost per item.
5.2. Sensitivity Analysis with Respect to the Scrap Rate x
5.3. Sensitivity Analysis with Respect to Outsourcing Proportion π
6. Conclusions
Acknowledgments
Author Contributions
Conflicts of Interest
Appendix A
Q | n | δi | δn−1 − δn | δn+1 − δn | (δn−1 + δn+1) − 2(δn) |
---|---|---|---|---|---|
600 | 1 | δn−1 = $558,725 | $476 > 0 | $3,624 > 0 | $4,100 > 0 |
2 * | δn = $558,248 | ||||
3 | δn+1 = $561,872 | ||||
1000 | 2 | δn−1 = $546,669 | $12 > 0 | $1,696 > 0 | $1,708 > 0 |
3 * | δn = $546,657 | ||||
4 | δn+1 = $548,353 | ||||
1400 | 2 | δn−1 = $548,221 | $2,352 > 0 | $40 > 0 | $2,392 > 0 |
3 * | δn = $545,869 | ||||
4 | δn+1 = $545,909 | ||||
1800 | 3 | δn−1 = $549,890 | $1,184 > 0 | $46 > 0 | $1,230 > 0 |
4 | δn = $548,707 | ||||
5 | δn+1 = $548,753 | ||||
2200 | 4 | δn−1 = $553,887 | $708 > 0 | $44 > 0 | $752 > 0 |
5 * | δn = $553,179 | ||||
6 | δn+1 = $553,223 | ||||
2600 | 5 | δn−1 = $558,994 | $467 > 0 | $40 > 0 | $508 > 0 |
6 * | δn = $558,527 | ||||
7 | δn+1 = $558,567 | ||||
3000 | 6 | δn−1 = $564,727 | $330 > 0 | $37 > 0 | $366 > 0 |
7 * | δn = $564,398 | ||||
8 | δn+1 = $564,434 | ||||
3400 | 7 | δn−1 = $570,850 | $243 > 0 | $33 > 0 | $277 > 0 |
8 * | δn = $570,606 | ||||
9 | δn+1 = $570,639 | ||||
3800 | 8 | δn−1 = $577,231 | $186 > 0 | $30 > 0 | $216 > 0 |
9 * | δn = $577,045 | ||||
10 | δn+1 = $577,075 | ||||
4200 | 9 | δn−1 = $583,795 | $146 > 0 | $28 > 0 | $174 > 0 |
10 * | δn = $583,649 | ||||
11 | δn+1 = $583,676 | ||||
4600 | 10 | δn−1 = $590,491 | $117 > 0 | $26 > 0 | $143 > 0 |
11 * | δn = $590,374 | ||||
12 | δn+1 = $590,399 | ||||
5000 | 11 | δn−1 = $597,286 | $96 > 0 | $24 > 0 | $119 > 0 |
12 * | δn = $597,191 | ||||
13 | δn+1 = $597,214 | ||||
5400 | 12 | δn−1 = $604,159 | $79 > 0 | $22 > 0 | $101 > 0 |
13 * | δn = $604,079 | ||||
14 | δn+1 = $604,102 |
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n | Q | δn | δn−1 | δn+1 | δn−1 − δn | δn+1 − δn |
---|---|---|---|---|---|---|
1 | 895 | $553,091 | – | $546,386 | – | −$6,705 ≤ 0 |
2 | 1100 | $546,386 | $553,091 | $545,344 | $6,705 ≥ 0 | −$1,042 ≤ 0 |
3 | 1229 | $545,344 | $546,386 | $545,824 | $1,042 ≥ 0 | $481 ≤ 0 |
4 | 1323 | $545,824 | $545,344 | $546,902 | −$481 ≥ 0 | $1,078 ≥ 0 |
π | Q* | n* | Total Outsourcing Cost | Total In-House Production Cost | E[TCU(Q*, n*)] | |||
---|---|---|---|---|---|---|---|---|
Amount | % to Total System Costs | Amount | % to Total System Costs | Amount | Increase % | |||
0.00 | 979 | 2.0 | $0 | 0.0% | $515,237 | 100.0% | $515,237 | – |
0.05 | 1201 | 3.0 | $34,250 | 6.5% | $490,278 | 93.5% | $524,527 | 1.8% |
0.10 | 1206 | 3.0 | $62,611 | 11.9% | $464,933 | 88.1% | $527,544 | 2.4% |
0.15 | 1210 | 3.0 | $90,663 | 17.1% | $439,882 | 82.9% | $530,545 | 3.0% |
0.20 | 1215 | 3.0 | $118,412 | 22.2% | $415,120 | 77.8% | $533,532 | 3.6% |
0.25 | 1219 | 3.0 | $145,862 | 27.2% | $390,642 | 72.8% | $536,505 | 4.1% |
0.30 | 1222 | 3.0 | $173,019 | 32.1% | $366,445 | 67.9% | $539,464 | 4.7% |
0.35 | 1226 | 3.0 | $199,887 | 36.9% | $342,523 | 63.1% | $542,410 | 5.3% |
0.40 | 1229 | 3.0 | $226,471 | 41.5% | $318,873 | 58.5% | $545,344 | 5.8% |
0.45 | 1231 | 3.0 | $252,775 | 46.1% | $295,490 | 53.9% | $548,265 | 6.4% |
0.50 | 1234 | 3.0 | $278,804 | 50.6% | $272,369 | 49.4% | $551,173 | 7.0% |
0.55 | 1236 | 3.0 | $304,561 | 55.0% | $249,509 | 45.0% | $554,070 | 7.5% |
0.60 | 1237 | 3.0 | $330,052 | 59.3% | $226,903 | 40.7% | $556,955 | 8.1% |
0.65 | 1238 | 3.0 | $355,281 | 63.5% | $204,548 | 36.5% | $559,829 | 8.7% |
0.70 | 1239 | 3.0 | $380,251 | 67.6% | $182,441 | 32.4% | $562,691 | 9.2% |
0.75 | 1239 | 3.0 | $404,966 | 71.6% | $160,577 | 28.4% | $565,543 | 9.8% |
0.80 | 1239 | 3.0 | $429,430 | 75.6% | $138,953 | 24.4% | $568,384 | 10.3% |
0.85 | 1352 | 4.0 | $453,238 | 79.4% | $117,913 | 20.6% | $571,150 | 10.9% |
0.90 | 1352 | 4.0 | $477,210 | 83.1% | $96,708 | 16.9% | $573,918 | 11.4% |
0.95 | 1352 | 4.0 | $500,943 | 86.9% | $75,734 | 13.1% | $576,677 | 11.9% |
1.00 | 646 | 2.0 | $529,294 | 94.4% | $31,120 | 5.6% | $560,414 | 8.8% |
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Chiu, Y.-S.P.; Liang, G.-M.; Chiu, S.W. Solving a Fabrication Lot-Size and Shipping Frequency Problem with an Outsourcing Policy and Random Scrap. Math. Comput. Appl. 2016, 21, 45. https://doi.org/10.3390/mca21040045
Chiu Y-SP, Liang G-M, Chiu SW. Solving a Fabrication Lot-Size and Shipping Frequency Problem with an Outsourcing Policy and Random Scrap. Mathematical and Computational Applications. 2016; 21(4):45. https://doi.org/10.3390/mca21040045
Chicago/Turabian StyleChiu, Yuan-Shyi Peter, Gang-Ming Liang, and Singa Wang Chiu. 2016. "Solving a Fabrication Lot-Size and Shipping Frequency Problem with an Outsourcing Policy and Random Scrap" Mathematical and Computational Applications 21, no. 4: 45. https://doi.org/10.3390/mca21040045
APA StyleChiu, Y.-S. P., Liang, G.-M., & Chiu, S. W. (2016). Solving a Fabrication Lot-Size and Shipping Frequency Problem with an Outsourcing Policy and Random Scrap. Mathematical and Computational Applications, 21(4), 45. https://doi.org/10.3390/mca21040045