Abstract
In this paper, a joint approximation of analytic functions by shifts of Dirichlet L-functions , where are non-zero real algebraic numbers linearly independent over the field and is the Gram function, is considered. It is proved that the set of their shifts has a positive lower density.
1. Introduction
Let be a Dirichlet character modulo . Note that is periodic with period q, completely multiplicative (i.e., for all and ), for and for . Let . In [1], L. Dirichlet introduced a function
which is now called the Dirichlet L-function. In virtue of the complete multiplicativity of , the function (1) can be written as an Euler product
where is the set of all prime numbers and has a meromorphic continuation to the whole complex plane with a unique simple pole at the point (if is the principal character modulo q) with residue . Since then, the function (1) has become a subject of intensive investigation. See, for instance, References [2,3,4] for some very recent papers on its zeros and moments. For , the function becomes the Riemann zeta-function .
In Reference [5], S. M. Voronin established the universality of Dirichlet L-functions. He proved that if is a continuous non-vanishing function on the disc with any fixed r, , and analytic in the interior of that disc, then, for every , there exists a real number such that
The Voronin theorem was extended to more general compact sets independently in References [6,7,8]. Denote by the class of compact subsets of the strip with connected complements, and by , where , the class of continuous non-vanishing functions on K that are analytic in the interior of K. Then the modern version of the Voronin theorem asserts that if and , then, for every ,
where stands for the Lebesgue measure of a measurable set (see, for example, Reference [9]). The latter inequality shows that there are infinitely many shifts approximating a given function from the class .
In Reference [10], Voronin considered the joint functional independence of Dirichlet L-functions using the joint universality. We recall that two Dirichlet characters are called non-equivalent if they are not generated by the same primitive character. Thus, the following statement is valid [10,11]; see also References [9,12,13].
Theorem 1.
Let be pairwise non-equivalent Dirichlet characters. For , let , and . Then, for every ,
The non-equivalence of the characters ensures a certain independence of the functions which is necessary for a simultaneous approximation of the collection . Later, it turned out that, in place of non-equivalent characters, different shifts can be used. This was observed by Nakamura [14]. More precisely, he proved the following theorem.
Theorem 2.
Let be real algebraic numbers linearly independent over the field of rational numbers and be arbitrary Dirichlet characters. For , let , and let . Then, for every and ,
In Reference [15], Pańkowski obtained the joint universality of Dirichlet L-functions using the shifts , , where , are distinct, are distinct and satisfy
The aim of this paper is to introduce new shifts of Dirichlet L-functions that approximate collections of analytic functions from the class . Let, as usual, be the Euler gamma-function. For , denote the increment of the argument of the function along the segment connecting the points and . Then it is known (see, for example, Reference [16] [Lemma 1.1]) that, for , the equation
has the unique solution satisfying . For , the numbers are called the Gram points. They were introduced and studied in Reference [17]. Therefore, we call the Gram function. A very interesting property of the Gram points is the relation as , where are imaginary parts of non-trivial zeros of the Riemann zeta-function. In the paper, we will consider the joint approximation of analytic functions by shifts of Dirichlet L-functions involving the Gram function. More precisely, we will prove the following joint universality theorem.
Theorem 3.
Suppose that are real non-zero algebraic numbers linearly independent over , and are arbitrary Dirichlet characters. For , let and . Then, for every ,
Moreover, the limit
exists for all but at most countably many .
For the proof of Theorem 3, we will use the probabilistic approach based on weakly convergent probability measures in the space of analytic functions.
2. Lemmas
We start with a lemma on the functional properties of the function . (Its proof can be found in Reference [16] [Lemma 1.1].)
Lemma 1.
Suppose that . Then
and
The next lemma provides an estimate for certain trigonometric integral.
Lemma 2.
Suppose that is a real differentiable function, the derivative is monotonic and or on the interval . Then
The proof of the lemma is given, for example, in Reference [11].
We will also use Baker’s theorem on linear forms in logarithms of algebraic numbers (see, for example, Reference [18]).
Lemma 3.
Suppose that are such that their logarithms are linearly independent over the field of rational numbers . Then, for any algebraic numbers , not all zero, we have
where H is the maximum of the heights of , and C is an effectively computable constant depending on r, and the maximum of the degrees of .
Let , and
where for all . With the product topology and pointwise multiplication, the infinite-dimensional torus is a compact topological Abelian group. Define
where for . Then is also a compact topological Abelian group. Therefore, denoting by the Borel -field of the space , we see that, on , the probability Haar measure exists. This gives the probability space .
For , define
Then the following limit theorem holds.
Lemma 4.
Under hypotheses of Theorem 2 on the numbers , converges weakly to the Haar measure as .
Proof.
We apply the Fourier transform method. It is well known that the dual group of is isomorphic to the group
where for all , . Hence it follows that characters of the group are of the form
where is the pth component of an element , , and the sign “” means that only a finite number of integers are distinct from zero. Therefore
is the Fourier transform of a measure on .
Let , , , , be the Fourier transform of . In view of (2) we have
Thus, by the definition of ,
Obviously, if , then
Now suppose that . Note that
Since for some , there is a prime number p such that . For this p, the sum is non-zero, because the numbers are linearly independent over . It is well known that the set is linearly independent over . Therefore, in view of Lemma 3,
Now, (3) and Lemmas 1 and 2 show that, in the case ,
This together with (4) and (5) give
Since the right-hand side of the latter equality is the Fourier transform of the Haar measure , the lemma follows by a continuity theorem for probability measures on compact groups. □
denotes the space of analytic functions on the strip D endowed with the topology of uniform convergence on compacta. Lemma 4 implies a limit theorem for probability measures on defined by means of absolutely convergent Dirichlet series.
For a fixed number and , set
Then we define the series
and
, where the functions are extended to the set by the formula
Denote the elements of by . Put , and set
and
Moreover, let be given by the formula
The absolute convergence of the series for implies the continuity of the mapping . Let , where, for ,
In view of (7) and (8) we conclude that Lemma 4, the continuity of and the well-known property on preservation of weak convergence under mapping lead to the following statement.
Lemma 5.
Under hypothesis of Theorem 3 on the numbers , we have
converges weakly to the measure as .
The probability measure is very important for the proof of Theorem 3. Let
where
Note that the latter products are uniformly convergent on compact subsets of the strip D for almost all , and define the -valued random elements on the probability space , where is the probability Haar measure on . Therefore, is the -valued random element on . Denote by the distribution of the random element , that is,
We recall that the support of a probability measure P on , where the space is separable, is a minimal closed set such that . The set consists of all elements such that, for every open neighbourhood G of x, the inequality is satisfied.
The measure is independent on any hypothesis. Therefore, from Reference [19] it follows that:
Lemma 6.
The measure converges weakly to as . Moreover, the support of is the set , where
Proof.
To be precise, in Reference [19] it was proved that a certain measure converges weakly to a certain probability measure P on (as ), and the measure P is the limit measure of as . Moreover, it was proved that .
It remains to prove that the support of is the set . It is well known that the support of the random element
is the set S for every Dirichlet character . Since the space is separable, we have
(see [20]). Therefore, it suffices to consider the measure on the sets
Since the Haar measure is the product of the Haar measures on , , we deduce that
This equality and the minimality of the support together with remark on the support of the element (10) show that the support of is the set . □
3. Mean Square Estimates
Define
To pass from (defined by (7)) to , certain mean square estimates for Dirichlet L-functions are necessary. Let be an arbitrary character modulo q.
Lemma 7.
Suppose that σ, , and are fixed. Then, for ,
Proof.
It is well known that, for fixed ,
Therefore, in view of Lemma 1, for ,
which is the required estimate. □
For , define
where is a sequence of compact subsets such that
for all , and if is a compact set, then for some . Then is a metric in the space inducing the topology of uniform convergence on compacta. Now, putting, for ,
gives a metric in inducing the product topology. The next lemma provides a certain approximation of (see definition (11)) by .
Lemma 8.
Suppose that . Then
Proof.
From the definition (13) of the metric , it follows that it suffices to prove that, for ,
for every . We will prove the above equality for the character modulo q.
Let be from the definition (6) of , and
Then the representation
is true. Its proof is the same as in Section 5.4 of [21] for the Riemann zeta-function. Hence, taking , by the residue theorem, we obtain
where
Let be an arbitrary compact set. Denote by the points of K, and suppose that with fixed for . More precisely, we select . Then, in view of (16),
Now, taking t in place of , we get that, for ,
This implies the estimate
where
and
It is well known that uniformly in , , with arbitrary ,
Therefore, by the definition (15) of the function , we find that, for ,
In the same way, for , we obtain
Suppose that . Then (17), (19) and Lemma 7 lead to the bound
Moreover, by (18), Lemma 1 and (20),
Thus, in view of (17) and (21),
From this, it follows that
Now, the definition (12) of the metric implies (14), which completes the proof of Lemma 8. □
4. A Limit Theorem
For , define
In this section, we will prove the following statement.
Theorem 4.
Suppose that are non-zero real algebraic numbers linearly independent over , and are arbitrary Dirichlet characters. Then converges weakly to as . The support of is the set .
First we recall a useful property of convergence in distribution () (see Theorem 4.2 in Reference [20]).
Lemma 9.
Suppose that the space is separable, the random elements and , , , are defined on the same probability space with measure μ,
for every ,
and, for every ,
Then .
In the theory of weak convergence of probability measures, the notions of relative compactness and tightness of families of probability measures are very useful. We recall that the family of probability measures on is called relatively compact if every sequence contains a weakly convergent subsequence to a certain measure on , and this family is called tight, if for every , there exists a compact set such that
for all . By the direct Prokhorov theorem (see Theorem 5.1 in Billingsley [20]), every tight family is relatively compact. We apply the above remarks to the sequence , where (defined by (8)) is the limit measure in Lemma 5.
Lemma 10.
The sequence is relatively compact.
Proof.
By the above mentioned Prokhorov theorem, it suffices to prove that the sequence is tight.
Suppose is a random variable defined on a certain probability space with measure and uniformly distributed on . Define the -valued random element
Moreover, let
be the -valued random element with the distribution . Then Lemma 5 implies the relation
By Lemma 7 with , we have, for ,
Let be a compact set from the definition of the metric . Then (26) together with the Cauchy integral formula show that
This combined with (22) implies the inequality
Proof of Theorem 4.
By Lemma 10, there exists a subsequence of the sequence that is weakly convergent to a certain probability measure P on as . This can be written as
Define one more -valued random element
Then Lemma 8 implies that, for every ,
The latter equality together with (25), (29), and Lemma 9 shows that
or, in other words, converges weakly to P as . Moreover, by the relation (30), the measure P is independent of the subsequence . Thus, we deduce that
or converges weakly to P as . Therefore, the theorem follows by Lemma 6. □
5. Proof of Universality
The proof of Theorem 3 is based on Mergelyan’s theorem on the approximation of analytic functions by polynomials [22], Theorem 4, and the properties of weak convergence. For convenience, we state them as lemmas.
Lemma 11
(Mergelyan theorem). Suppose that is a compact set with connected complement, and be a continuous function on K and analytic in the interior of K. Then, for every , there exists a polynomial such that
We recall that is called a continuity set of the measure P on if , where is a boundary of A.
Lemma 12.
Let , , and P be probability measures on . Then the following statements are equivalent:
- 1°
- converges weakly to P as ;
- 2°
- For every open set ,
- 3°
- For every continuity set A of P,
The above lemma is a part of Theorem 2.1 from Reference [20]. Now, we can give the proof of Theorem 3.
Proof of Theorem 3.
First part. In view of Lemma 11, there exist polynomials such that
The set
is an open neighbourhood of the element . Thus, by Theorem 4, , where the distribution is defined by (9). Hence, from Theorem 4 again and Lemma 12,
and the definitions (23) and (32) of and together with (31) prove the first part of the theorem.
Second part. Introduce one more set
Then the boundary of lies in the set
thus, for different and . This shows that the set is a continuity set of the measure for all but at most countably many . Therefore, by Lemma 12,
for all but at most countably many . Moreover, (31) shows the inclusion . This, (34) and the definitions (23) and (33) of and prove the second assertion of the theorem. □
Author Contributions
Conceptualization, A.D., R.G. and A.L.; Investigation, A.D., R.G. and A.L.; Writing—original draft, A.D., R.G. and A.L.; Writing—review and editing, A.D., R.G. and A.L. All authors contributed equally to the manuscript and typed, read, and approved final manuscript. All authors have read and agreed to the published version of the manuscript.
Funding
This research is funded by European Social Fund (project No 09.3.3-LMT-K-712-01-0037) under grant agreement with the Research Council of Lithuania (LMTLT).
Conflicts of Interest
The authors declare no conflict of interest.
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