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Article

Green Functions of the First Boundary-Value Problem for a Fractional Diffusion—Wave Equation in Multidimensional Domains

Institute of Applied Mathematics and Automation, Kabardin-Balkar Scientific Center of Russian Academy of Sciences, 89-A Shortanov Street, 360000 Nalchik, Russia
Mathematics 2020, 8(4), 464; https://doi.org/10.3390/math8040464
Submission received: 12 February 2020 / Revised: 13 March 2020 / Accepted: 22 March 2020 / Published: 26 March 2020
(This article belongs to the Special Issue Direct and Inverse Problems for Fractional Differential Equations)

Abstract

:
We construct the Green function of the first boundary-value problem for a diffusion-wave equation with fractional derivative with respect to the time variable. The Green function is sought in terms of a double-layer potential of the equation under consideration. We prove a jump relation and solve an integral equation for an unknown density. Using the Green function, we give a solution of the first boundary-value problem in a multidimensional cylindrical domain. The fractional differentiation is given by the Dzhrbashyan–Nersesyan fractional differentiation operator. In particular, this covers the cases of equations with the Riemann–Liouville and Caputo derivatives.

1. Introduction

Consider the equation
α y α Δ x u ( x , y ) = f ( x , y ) ,
where α y α stands for a fractional derivative with respect to y of order α ( 0 , 2 ) , y > 0 , and
Δ x = j = 1 n 2 x j 2
is the Laplace operator with respect to x = ( x 1 , x 2 , , x n ) S R n .
The fractional diffusion ( 0 < α 1 ) and diffusion-wave ( 0 < α < 2 ) equations have attracted great attention in recent years. Active research in this direction began with works [1,2,3,4]. In the study of equations with fractional diffusion-wave operators in the main part, a wide range of methods and approaches were used, such as: integral transforms [5,6,7,8,9]; group analysis [10,11,12,13]; Fourier methods [14,15,16,17,18]; maximum principles [19,20]; functional methods [21]; asymptotic behavior [22]; Green function methods and method of potentials [23,24,25,26,27,28,29,30,31,32]; parametrix methods [33]; inverse problems and regularization methods [34]; reduction methods [35,36]; etc. We also mention the monographs [37,38,39], which reflect many of these approaches and contain vast bibliographies concerning the issue.
Considerable interest in the study of fractional differential equations, among other things, is also fueled by various applications in physics, mechanics, and simulation (see e.g., [40,41,42,43,44,45,46]). Of particular note are some recent applications of the fractional diffusion equation to economics and financial modeling (see e.g., [47,48,49]).
The novelty of the work is that we construct the Green function of the first boundary-value problem for an arbitrary bounded domain with a smooth boundary.
As it is adopted in the theory of boundary-value problems for parabolic and hyperbolic equations, the first boundary-value problem is the problem of finding solutions that take given initial values and values on the lateral boundary of the domain (see e.g., [50], p. 5, and [51], p. 39). For the equation under consideration, it is natural to adhere to this terminology (see Problem 1 below). Moreover, as is customary, by a Green function we mean a source function (elementary solution) that solves a specific problem in a particular domain (see e.g., [50], p. 84), i.e., the Green function depends on the domain and the form of boundary conditions, contrary to the fundamental solution. Having the Green function constructed and using the formula of general representation of solution (the Green formula) for a considered equation, one can find a solution to a boundary-value problem. In turn, the fundamental solution is a source function, in terms of which a solution of the Cauchy problems can be found. As a rule, the Green function is sought as a sum of the fundamental solution and a regular part, the form of which depends on the domain where the problem is considered and on the form of the boundary value (see Definition 4 in Section 6). Thus, the main problem in constructing a Green function is to find its regular part.
Here, we seek for the regular part of the Green function in the form of a double-layer potential. We prove a jump relation for it and solve the resulting integral equation for an unknown density. The concept of the double-layer potential, which we use here (see Definition 2 in Section 5), naturally generalizes the corresponding concepts from the theory of elliptic and parabolic equations (see e.g., [51], p. 382, and [50] p. 89).
Using the Green function, we give a representation of a solution of the first boundary-value problem in a multidimensional cylindrical domain.
Recently, the Green functions of boundary-value problems for the Equation (1) have been constructed for one-dimensional case ( n = 1 ) in [23], and —for problems in multidimensional rectangular domains with n > 1 —in [32]. We also note [31], in which the first boundary-value problem for the fractional diffusion equation ( 0 < α < 1 ) with the Caputo derivative has been solved using the layer potential technique.
The fundamental solution for (1) is usually expressed in terms of the Wright function (for n = 1 ) and in terms of the Fox H-function (for n 2 ). Here we use the representation obtained in [24] (see (14) below), and which is in complete agreement with the classical results (see e.g., [1,2,3,4,5,6]), as was shown in [24].
The fractional differentiation is given by the Dzhrbashyan–Nersesyan fractional differentiation operator. The operators of fractional differentiation in the sense of Riemann–Liouville and Caputo arespecial cases of the Dzhrbashyan–Nersesyan operator and can be expressed in terms of the latter. Therefore, the results obtained here also cover the cases of equations with the Riemann–Liouville and Caputo derivatives.

2. Fractional Differentiation

The fractional differentiation is given by the Dzhrbashyan–Nersesyan operator [52]. The Dzhrbashyan–Nersesyan operator of order α , with starting point at y = η , and associated with an ordered sequence
{ γ 0 , γ 1 , , γ m } ,
is defined by
α ( y η ) α = D η y { γ 0 , γ 1 , , γ m } = D η y γ m 1 D η y γ m 1 D η y γ 1 D η y γ 0 ,
where
γ k ( 0 , 1 ] ( k = 0 , 1 , , m ) , α = k = 0 m γ k 1 ,
and D η y γ m 1 and D η y γ k denote the Riemann–Liouville fractional integral and fractional derivative, respectively. The Riemann–Liouville operators of fractional integration and differentiation with respect to y, and with starting point at y = η , are defined by ([40], p. 11, [38], §2.1)
D η y ζ g ( y ) = sign ( y η ) η y g ( t ) | y t | ζ 1 Γ ( ζ ) d t ( ζ < 0 ) , D η y 0 g ( y ) = g ( y ) ,
and
D η y ζ g ( y ) = sign p ( y η ) p y p D η y ζ p g ( y ) ( 0 < ζ p , p N ) .
The composition law for the Riemann–Liouville derivatives (see e.g., [38]) shows that
D η y { γ 0 , γ 1 , , γ m } g ( y ) = D η y α g ( y ) k = 0 m 1 | y η | μ k 1 Γ ( μ k ) g k ,
where
g k = lim y η D η y { γ 0 , γ 1 , , γ k } g ( y ) and μ k = j = 0 k γ j .
It should be noted that the operator (3) associated with the sequences { ζ m + 1 , 1 , 1 , , 1 } and { 1 , 1 , , 1 , ζ m + 1 } coincides with the Riemann–Liouville derivative and the Caputo derivative, respectively, i.e., we can write
D η y ζ g ( y ) = D η y { ζ m + 1 , 1 , , 1 } g ( y ) and η y ζ g ( y ) = D η y { 1 , , 1 , ζ m + 1 } g ( y ) .
Here, ζ ( m 1 , m ] and η y ζ is the Caputo fractional derivative, i.e. η y ζ = sign m ( y η ) D η y ζ m m y m .

3. Boundary-Value Problem

We consider the Equation (1) or, more precisely,
D 0 y { γ 0 , γ 1 , , γ m } Δ x u ( x , y ) = f ( x , y ) ( 0 < α = γ 0 + + γ m 1 < 2 ) ,
in the domain
Ω = S × ( 0 , T ) = { ( x , y ) : x S R n , y ( 0 , T ) } ,
where S is a bounded simply connected domain in R n . In what follows, S and S ¯ denote, respectively, the boundary and the closure of S.
Definition 1.
By a regular solution of the Equation (7) we mean a function u ( x , y ) such that: y 1 μ u ( x , y ) S ¯ × [ 0 , T ) for some μ > 0 ; in Ω, u ( x , y ) has continuous derivatives with respect to x j ( j = 1 , , n ) up to the second order; the functions D 0 y { γ 0 , γ 1 , , γ k } u ( x , y ) ( k = 0 , 1 , , m 1 ) have continuous derivatives with respect to y ( 0 , T ) for a fixed x S , and these functions are continuous in S × [ 0 , T ) ; and u ( x , y ) satisfies the Equation (1) for all ( x , y ) Ω .
The first boundary-value problem for the Equation (7) is stated as follows.
Problem 1.
Find a regular solution of the Equation (7) in Ω satisfying the conditions
lim x x * x S u ( x , y ) = φ ( x * , y ) ( x * S , 0 < y < T )
and
lim y 0 D 0 y { γ 0 , γ 1 , , γ k } u ( x , y ) = τ k ( x ) ( x S , k = 0 , 1 , , m 1 ) ,
where φ ( x * , y ) and τ k ( x ) are known (given) functions, φ ( x * , y ) C ( S × ( 0 , T ) ) and τ k ( x ) C ( S ) .
Remark 1.
The function φ ( x * , y ) is defined on S × ( 0 , T ) , which is the lateral boundary of the cylindrical domain Ω, and specifies the boundary condition of Problem 1. The functions τ k ( x ) , k = 0 , 1 , , m 1 , are defined on S (i.e., on the lower base of Ω) and should be considered to be the initial conditions of the problem (7)–(9). It should be noted that the number of necessary initial conditions to be imposed for the Equation (7), is equal to the number of elements in the sequence (2) and, in general, does not depend on the order α.
Remark 2.
For the Equation (7) with the Riemann–Liouville fractional derivative (i.e., for { γ 0 , γ 1 , , γ m } = { α m + 1 , 1 , , 1 } ), due to α ( 0 , 2 ) , m can only be equal to either 1 or 2. In this case the initial conditions (9) take one of the following forms
lim y 0 D 0 y α 1 u ( x , y ) = τ 0 ( x ) for 0 < α 1 ( m = 1 )
or
lim y 0 D 0 y α 2 u ( x , y ) = τ 0 ( x ) , lim y 0 D 0 y α 1 u ( x , y ) = τ 1 ( x ) for 1 < α < 2 ( m = 2 ) .
Similarly, if fractional differentiation in (7) is given in the Caputo sense (i.e., { γ 0 , γ 1 , , γ m } = { 1 , , 1 , α m + 1 } with m = 1 or 2), then (9) may be written as
lim y 0 u ( x , y ) = τ 0 ( x ) for 0 < α 1 ( m = 1 )
or
lim y 0 u ( x , y ) = τ 0 ( x ) , lim y 0 y u ( x , y ) = τ 1 ( x ) for 1 < α < 2 ( m = 2 ) .

4. Fundamental Solution

Consider the function [24]
Γ α , n ( x , y ) = C n y β ( 2 n ) 1 f β | x | y β ; n 1 , β ( 2 n ) .
Here and subsequently,
β = α 2 , C n = 2 n π 1 n 2 ,
and
f β ( z ; μ , δ ) = 2 Γ μ 2 1 ϕ β , δ ; z t ( t 2 1 ) μ 2 1 d t , μ > 0 , ϕ β , δ ; z , μ = 0 ,
where
ϕ β , δ ; z = k = 0 ( z ) k k ! Γ ( δ β k )
is the Wright function [53,54].
In [24], it was shown that the function Γ α , n ( x s , y t ) is the fundamental solution of the Equation (7).
Let us recall some properties of the function (14).
Lemma 1.
Let t < y , | x s | > 0 , and ζ R . Then Γ α , n ( x s , y t ) is a solution of the equation
D t y α Δ x D t y ζ Γ α , n ( x s , y t ) = 0
as a function of x and y, and is a solution of
D y t α Δ s D y t ζ Γ α , n ( x s , y t ) = 0
as a function of s and t.
Lemma 2.
Let ζ R . Then
D η y ζ Γ α , n ( x , y ) C y β ( 2 n ) ζ 1 g p | x | y β E | x | y β , ρ ,
x k D η y ζ Γ α , n ( x , y ) C | x k | y β n ζ 1 g p + 2 | x | y β E | x | y β , ρ ,
2 x k 2 D η y ζ Γ α , n ( x , y ) C y β n ζ 1 g q | x | y β E | x | y β , ρ ,
where
p = n , for ζ N { 0 } , n + 2 , for ζ N { 0 } , q = n + 2 , for ζ N { 0 } or n = 1 , n + 4 for ζ N { 0 } and n 2 ,
and
E ( z , ρ ) = exp ρ z 1 1 β , g n ( z ) = 1 for n 3 , | ln z | + 1 for n = 4 , z 4 n for n 5 ,
C = C ( n , α , ρ ) , ρ < ( 1 β ) β β 1 β , and (by choosing C) ρ can be taken arbitrarily close to ( 1 β ) β β 1 β .
Here and subsequently, the symbol C denotes different positive constants indicating in brackets the parameters on which they depend if necessary: C = C ( α , β , ) .
Proofs of Lemmas 1 and 2 are given in [24].
Corollary 1.
Let t < y , | x s | > 0 , and ζ R . Then Γ α , n ( x s , y t ) satisfies the equations
D t y { γ 0 , γ 1 , , γ m } Δ x D t y ζ Γ α , n ( x s , y t ) = 0
and
D y t { γ 0 , γ 1 , , γ m } Δ s D y t ζ Γ α , n ( x s , y t ) = 0 .
Proof. 
Combining (6) and (16) gives
D t y { γ 0 , γ 1 , , γ m } D t y ζ Γ α , n ( x s , y t ) = D t y α D t y ζ Γ α , n ( x s , y t )
and
D y t { γ 0 , γ 1 , , γ m } D y t ζ Γ α , n ( x s , y t ) = D y t α D y t ζ Γ α , n ( x s , y t ) .
Lemmas 1 now leads to (18) and (19).□

5. Double-Layer Potential

In what follows, ν s denotes the outer normal direction to S at s S , and ν s stands for the directional derivative in the direction ν s .
Definition 2.
Let w ( s , t ) L S × ( 0 , T ) . We call a function V ( x , y ) defined by
V ( x , y ) = 0 y S w ( s , t ) ν s Γ α , n ( x s , y t ) d σ s d t ( x R n \ S , y ( 0 , T ) )
the double-layer potential with the density w ( s , t ) .
By Lemmas 1 and 2, it is obvious that V ( x , y ) is a regular solution of (7) in each of the domains S × ( 0 , T ) and R n \ S ¯ × ( 0 , T ) . Our purpose now is to study the behavior of V ( x , y ) on S .
Let
B ε a = { x R n : | x a | < ε } , S ε a = B ε a S , and C ε a = B ε a R n \ S ¯ .
Definition 3.
We say that a surface S belongs to the Lyapunov class (see e.g., [55] (p. 64)) if: at each point of S there is a well-defined tangent plane; any line parallel to ν a intersects S ε a at most once for some ε > 0 ; there are C > 0 and θ > 0 such that | ν a ν b ^ | C | a b | θ for any a, b S (where ν a ν b ^ stands for the angle between ν a and ν b ).
Lemma 3.
Let n 2 , t 1 μ w ( s , t ) C S × [ 0 , T ] for some μ > 0 , S be a surface of the Lyapunov class, a S , and y ( 0 , T ) . Then
lim x a x S 0 y S w ( s , t ) ν s Γ α , n ( x s , y t ) d σ s d t = = 1 2 w ( a , y ) + 0 y S w ( s , t ) ν s Γ α , n ( a s , y t ) d σ s d t .
Proof. 
With the notation (21), we have
lim x a x S 0 y S w ( s , t ) ν s Γ α , n ( x s , y t ) d σ s d t = 0 y S \ S ε a w ( s , t ) ν s Γ α , n ( a s , y t ) d σ s d t +
+ lim x a x S 0 y δ + y δ y S ε a w ( s , t ) ν s Γ α , n ( x s , y t ) d σ s d t ,
for any δ ( 0 , y ) and sufficiently small ε > 0 . By the formula (see [24])
x j Γ α , n ( x , y ) = 2 π x j Γ α , n + 2 ( x , y ) ,
we get
ν s Γ α , n ( a s , y t ) = 2 π a s , ν s Γ α , n + 2 ( a s , y t ) ,
where · , · denotes the inner product in R n . Since S is a Lyapunov surface, we have
| a s , ν s | C | a s | 1 + θ
for some θ > 0 in a sufficiently small neighborhood of the point a. Combining this with (16) and (17), we obtain
lim x a x S 0 y S w ( s , t ) ν s Γ α , n ( x s , y t ) d σ s d t = 0 y S w ( s , t ) ν s Γ α , n ( a s , y t ) d σ s d t + + lim ε 0 lim x a x S y δ y S ε a w ( s , t ) w ( a , y ) ν s Γ α , n ( x s , y t ) d σ s d t + + w ( a , y ) lim ε 0 lim x a x S y δ y S ε a ν s Γ α , n ( x s , y t ) d σ s d t .
Let us denote by I 1 and I 2 the integrals in the second and the third summands, respectively, in the right-hand side of the last equality. By Lemma 2 and (23), we have
| I 1 | C ω ε , δ y δ y S ε a | x s , ν s | ( y t ) β n + 1 g n + 2 | x s | ( y t ) β E | x s | ( y t ) β , ρ d σ s d t ,
where
ω ε , δ = sup | w ( s , t ) w ( a , y ) | : | s a | < ε , | y t | < δ .
A simple computation gives
| I 1 | C ω ε , δ S ε a | x s , ν s | | x s | n d σ s 0 t β n 1 g n + 2 t β E t β , ρ d t ,
where
S ε a | x s , ν s | | x s | n d σ s C ( S ) and 0 t β n 1 g n + 2 t β E t β , ρ d t C ( β , n ) .
Now
lim ε 0 lim x a x S I 1 = 0 ,
which is due to the continuity of w ( s , t ) in a neighborhood of ( a , y ) and arbitrary choice of δ . Let us examine I 2 . Using the Stokes formula gives
S ε a ν s Γ α , n ( x s , y t ) d σ s = C ε a \ S ε a ν s Γ α , n ( x s , y t ) d σ s C ε a Δ s Γ α , n ( x s , y t ) d s .
By (15) and (16), we get
I 2 = C ε a \ S ε a ν s D y t 1 Γ α , n ( x s , y t ) t = y δ d σ s C ε a D y t α 1 Γ α , n ( x s , y t ) t = y δ d s
and
lim x a x S I 2 = C ε a \ S ε a ν s D y t 1 Γ α , n ( a s , y t ) t = y δ d σ s C ε a D y t α 1 Γ α , n ( a s , y t ) t = y δ d s = J 1 J 2 .
From (14) and (23), it follows that
J 1 = π 1 n 2 2 n + 1 D y t 1 y β n 1 f β ε y β ; n + 1 , β n t = y δ C ε a \ S ε a a s , ν s d σ s .
Using the formulas (see [24])
D 0 y ζ y q 1 f β ε y β ; p , q = y q + ζ 1 f β ε y β ; p , q + ζ
and
lim z 0 z p 1 f β z ; p , q = 2 Γ ( p 1 ) Γ p 2 Γ ( β p + q β ) ( p > 1 ) ,
we get
lim ε 0 J 1 = lim ε 0 π 1 n 2 2 n + 1 lim ε 0 ε δ β n f β ε δ β ; n + 1 , 1 β n · lim ε 0 ε n C ε a \ S ε a a s , ν s d σ s = = π 1 n 2 2 n Γ ( n ) Γ n + 1 2 · 1 2 lim ε 0 ε n B ε a a s , ν s d σ s = π 1 n 2 2 n Γ ( n ) Γ n + 1 2 · n 2 V n .
Here V n is the volume of the unit ball in R n . Thus
lim ε 0 J 1 = 1 2 .
Let us evaluate J 2 . The inequality (16) gives
| J 2 | C δ β n C ε a g n + 2 | a s | δ β E | a s | δ β , ρ d s ,
which means that
lim ε 0 J 2 = 0 .
The last equality, (26), and (27) yield
lim ε 0 lim x a x S I 2 = 1 2 .
Combining this with (25), we obtain (22). □
Formula (22) is called a jump relation for double-layer potential (20).

6. Green Function

Definition 4.
We call a function G ( x , y , s , t ) the Green function of the problem (7)–(9) if G ( x , y , s , t ) has the form G ( x , y , s , t ) = Γ α , n ( x s , y t ) W ( x , y t , s ) , where the function W ( x , y , s ) satisfies the following conditions:
1) 
W ( x , y , s ) is a regular solution of the Equation (7) as a function of ( x , y ) Ω for any fixed s S ;
2) 
W ( x , y , s ) C ( S ¯ × [ 0 , T ] × S ) ;
3) 
W ( x * , y , s ) = Γ α , n ( x * s , y ) for all x * S , s S , and y ( 0 , T ) ;
4) 
lim y 0 D 0 y { γ 0 , γ 1 , , γ k } W ( x , y , s ) = 0 ( x , s S , k = 0 , 1 , , m 1 ) .
Our goal now is to construct the function G ( x , y , s , t ) , or equivalently, its regular part W ( x , y , s ) . We will look for W ( x , y , s ) in the form
W ( x , y , s ) = 0 y S w ( ξ , η , s ) ν ξ Γ α , n ( x ξ , y η ) d σ ξ d η ,
where w ( ξ , η , s ) is to be determined.
Let x * S , s be a fixed point of S, and S be a Lyapunov surface. It follows from (22) that
lim x x * W ( x , y , s ) = 1 2 w ( x * , y , s ) + 0 y S w ( ξ , η , s ) ν ξ Γ α , n ( x * ξ , y η ) d σ ξ d η .
Assuming (29) to satisfy, we obtain that w ( x * , y , s ) is a solution of the integral equation
w ( x * , y , s ) = 2 Γ α , n ( x * s , y ) + 2 P w ( x * , y , s ) ,
where
P w ( x * , y , s ) = 0 y S w ( ξ , η , s ) ν ξ Γ α , n ( x * ξ , y η ) d σ ξ d η .
From now on, we assume that
w ( x * , y , s ) C S × ( 0 , T ) × S and | w | w 0 ( s ) y μ 1 Γ ( μ )
for some μ > 0 and w 0 = w 0 ( s ) > 0 . By (16), (23), and (24), we get
P w w 0 Γ ( μ ) 0 y η μ 1 S | x * ξ | 1 + θ ( y η ) β n + 1 g n + 2 | x * ξ | ( y η ) β E | x * ξ | ( y η ) β , ρ d σ ξ d η
w 0 Γ ( μ ) 0 y η μ 1 ( y η ) θ β 1 S 0 | λ | 1 + θ g n + 2 | λ | E | λ | , ρ d σ λ d η ,
where θ is a positive number (the choice of which depends only on S ), and
S 0 = S 0 ( x * , y η ) = { λ R n : λ = ( x * ξ ) ( y η ) β , ξ S } .
It is easy to check that
S 0 | λ | 1 + θ g n + 2 | λ | E | λ | d σ λ C where C = C ( S , T ) .
Thus, by
0 y η μ 1 ( y η ) β θ 1 d η = y μ + β θ 1 Γ ( μ ) Γ ( β θ ) Γ ( μ + β θ ) ,
we have
P w C Γ ( β θ ) w 0 y μ + β θ 1 Γ ( μ + β θ ) .
Repeated use of this inequality shows that
P k w C Γ ( β θ ) k w 0 y μ + k β θ 1 Γ ( μ + k β θ ) ( k N ) .
This means that the integral Equation (32) has a unique solution of the class (33), and the solution of (32) is given by
w ( x * , y , s ) = v ( x * , y , s ) + k = 1 2 k P k v ( x * , y , s ) ,
where
v ( x * , y , s ) = 2 Γ α , n ( x * s , y ) .
Thus, by (31) and (34), W ( x , y , s ) can be written as
W ( x , y , s ) = 0 y S k = 0 2 k + 1 Γ α , n k ( ξ , η , s ) ν ξ Γ α , n ( x ξ , y η ) d σ ξ d η ,
where Γ α , n 0 ( ξ , η , s ) = Γ α , n ( ξ s , η ) and
Γ α , n k + 1 ( ξ , η , s ) = 0 η S Γ α , n k ( ξ * , η * , s ) ν ξ * Γ α , n ( ξ ξ * , η η * ) d σ ξ * d η * ( k N ) .
Theorem 1.
Let n 2 and S be a surface of the Lyapunov class. Then the function W ( x , y , s ) defined by (35) satisfies the properties 1)–4) of Definition 4, and the function
G ( x , y , s , t ) = Γ α , n ( x s , y t ) W ( x , y t , s )
is the Green function of the problem (7)–(9).
Proof. 
It follows from Corollary 1 and Lemma 2 that W ( x , y , s ) is a regular solution of (7), and, moreover, (30) holds for any x, s S . By (22) and (31), we get
lim x x * x S W ( x * , y , s ) = 1 2 w ( x * , y , s ) + P w ( x * , y , s ) .
Combining this and (32) leads to (29). In addition, this means that W ( x , y , s ) can be continued up to S (with respect to x), and we get (28). □
Remark 3.
It is worth noting that the Green function G ( x , y , s , t ) as well as the fundamental solution Γ α , n ( x , y ) does not depend on the number and values of elements in { γ 0 , , γ m } , but only on α = γ 0 + + γ m 1 . However, the sequence { γ 0 , , γ m } affects the form of solutions (see Remark 5 below).

7. Representation of Solutions

Having constructed the Green function, we can find a representation for solutions to Problem 1.
Theorem 2.
Let u ( x , y ) be a regular solution of the problem (7)–(9) such that x j u ( x , y ) L S × ( 0 , T ) ( j = 1 , 2 , , n ), and y 1 μ φ ( x * , y ) C S × [ 0 , T ] for some μ > 0 . Then
u ( x , y ) = k = 0 m 1 S τ k ( s ) D 0 y α μ k G ( x , y , s , 0 ) d s + Φ ( x , y ) + F ( x , y ) ,
where μ k = γ 0 + γ 1 + + γ k ( k = 0 , 1 , , m 1 ),
Φ ( x , y ) = 0 y S φ ( s , t ) ν s G ( x , y , s , t ) d σ s d t , and F ( x , y ) = 0 y S f ( s , t ) G ( x , y , s , t ) d s d t .
Proof. 
Using the general representation for solutions of (7) (see [24], Theorem 1), we can conclude that if u ( x , y ) is a regular solution of the problem (7)–(9), then
u ( x , y ) = 0 y S f ( s , t ) G ( x , y , s , t ) d s d t + k = 0 m 1 S τ k ( s ) D y t α μ k G ( x , y , s , t ) t = 0 d s + + 0 y S G ( x , y , s , t ) ν s u ( s , t ) u ( s , t ) ν s G ( x , y , s , t ) d σ s d t .
It follows easily from the definitions (4) and (5) that D y t ζ g ( y t ) t = 0 = D 0 y ζ g ( y ) for any ζ R . Taking into account (36), this means that
D y t α μ k G ( x , y , s , t ) t = 0 = D 0 y α μ k G ( x , y , s , 0 ) .
Combining the latter, (8), (29), and (39), we get (37). □
Remark 4.
Please note that Theorem 2 does not state that any function of the form (37) is a priori a solution to Problem 1. To guarantee this, it is necessary to impose additional smoothness conditions (such as Hölder continuity or differentiability) on the functions f ( x , y ) , φ ( x , y ) , and τ k ( x ) . These conditions can easily be adapted from [24].
Let us reformulate the results of Theorem 2 for equations with the Riemann–Liouville and Caputo derivatives, i.e., for the equations
D 0 y α Δ x u ( x , y ) = f ( x , y )
and
0 y α Δ x u ( x , y ) = f ( x , y ) .
It follows from Theorem 2 that a regular solution of (40) satisfying the boundary condition (8) and one of the initial conditions (10) or (11) (depending on the segment in which α lies, see Remark 2) has the form
u ( x , y ) = S τ 0 ( s ) G ( x , y , s , 0 ) d s + Φ ( x , y ) + F ( x , y )
for α ( 0 , 1 ] ( m = 1 ), or
u ( x , y ) = S τ 0 ( s ) y G ( x , y , s , 0 ) d s + S τ 1 ( s ) G ( x , y , s , 0 ) d s + Φ ( x , y ) + F ( x , y )
for α ( 1 , 2 ) ( m = 2 ).
Likewise, a regular solution of (41) satisfying (8) and either (12) or (13) can be written as
u ( x , y ) = S τ 0 ( s ) D 0 y α 1 G ( x , y , s , 0 ) d s + Φ ( x , y ) + F ( x , y )
for α ( 0 , 1 ] ( m = 1 ), or
u ( x , y ) = S τ 0 ( s ) D 0 y α 2 G ( x , y , s , 0 ) d s + S τ 1 ( s ) D 0 y α 1 G ( x , y , s , 0 ) d s + Φ ( x , y ) + F ( x , y )
for α ( 1 , 2 ) ( m = 2 ).
The functions Φ ( x , y ) and F ( x , y ) in (42)–(45) are defined by (38).
Remark 5.
Comparing (37), (42)–(45), one can notice that the components of solutions introduced by the right side f ( x , y ) and the boundary condition φ ( x * , y ) (i.e., The functions Φ ( x , y ) and F ( x , y ) ) are the same for all cases, only dependent of α, and independent of the number and distribution of elements in { γ 0 , γ 1 , , γ m } . Thus, the sequence { γ 0 , γ 1 , , γ m } or, in other words, the used form of fractional differentiation (among those that can be generated by the Dzhrbashyan–Nersesyan operator) affects only the part of the solution that corresponds to the initial conditions.

8. Conclusions

In this paper, we construct the Green function of the first boundary problem for the fractional diffusion-wave equation in a multidimensional cylindrical domains with a boundary of the Lyapunov class. We find the regular part of the Green function as a solution of an integral equation generated by a jump relation for the double-layer potential of the considered equation. We give the representation of solutions to the problem under study in terms of the Green function.
For fractional differentiation, we use the Dzhrbashyan–Nersesyan operator, which generates the Riemann–Liouville and Caputo derivatives as particular cases. This allow us to obtain the corresponding results for equations with these types of fractional derivatives as a consequence of the results obtained in the general case. Moreover, it is shown that the choice of the form of fractional differentiation (among the operators covered by the Dzhrbashyan–Nersesyan operator) affects only the part of solution corresponding to initial conditions, and the remaining components of solutions depend only of the order of fractional differentiation.

Funding

This research was funded by the Russian Foundation for Basic Research grant number 18-51-45005.

Conflicts of Interest

The author declares no conflict of interest.

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Pskhu, A. Green Functions of the First Boundary-Value Problem for a Fractional Diffusion—Wave Equation in Multidimensional Domains. Mathematics 2020, 8, 464. https://doi.org/10.3390/math8040464

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Pskhu A. Green Functions of the First Boundary-Value Problem for a Fractional Diffusion—Wave Equation in Multidimensional Domains. Mathematics. 2020; 8(4):464. https://doi.org/10.3390/math8040464

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Pskhu, Arsen. 2020. "Green Functions of the First Boundary-Value Problem for a Fractional Diffusion—Wave Equation in Multidimensional Domains" Mathematics 8, no. 4: 464. https://doi.org/10.3390/math8040464

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