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Article

On Caputo–Riemann–Liouville Type Fractional Integro-Differential Equations with Multi-Point Sub-Strip Boundary Conditions

1
Nonlinear Analysis and Applied Mathematics (NAAM)-Research Group, Department of Mathematics, Faculty of Science, King Abdulaziz University, P.O. Box 80203, Jeddah 21589, Saudi Arabia
2
Department of Mathematics, University of Ioannina, 45110 Ioannina, Greece
*
Author to whom correspondence should be addressed.
Mathematics 2020, 8(11), 1899; https://doi.org/10.3390/math8111899
Submission received: 16 September 2020 / Revised: 24 October 2020 / Accepted: 26 October 2020 / Published: 31 October 2020

Abstract

:
In this paper, we derive existence and uniqueness results for a nonlinear Caputo–Riemann–Liouville type fractional integro-differential boundary value problem with multi-point sub-strip boundary conditions, via Banach and Krasnosel’ski i ’s fixed point theorems. Examples are included for the illustration of the obtained results.

1. Introduction

The subject of fractional order boundary value problems has been addressed by many researchers in recent years. The interest in the subject owes to its extensive applications in natural and social sciences. Examples include bio-engineering [1], ecology [2], financial economics [3], chaos and fractional dynamics [4], etc. One can find many interesting results using boundary value problems dealing with Caputo, Riemann–Liouville and Hadamard type fractional derivatives and equipped with a variety of boundary conditions in [5,6,7,8,9,10,11,12,13,14,15,16,17].
Integro-differential equations constitute an important area of investigation due to their occurrence in several applied fields, such as heat transfer phenomena [18,19], fractional power law [20], etc. Fractional integro-differential equations complemented with different kinds of boundary conditions have also been studied by many researchers, for example, [21,22,23,24,25,26,27,28]. In a recent paper [29], a nonlocal boundary value problem containing left Caputo and right Riemann–Liouville fractional derivatives, and both left and right Riemann–Liouville fractional integral operators was discussed.
Motivated by aforementioned work on integro-differential equations, we introduce and investigate a nonlinear Caputo–Riemann–Liouville type fractional integro-differential boundary value problem involving multi-point sub-strip boundary conditions given by
c D q x ( t ) + i = 1 k I p i g i ( t , x ( t ) ) = f ( t , x ( t ) ) , 0 < t < 1 , x ( 0 ) = a , x ( 0 ) = 0 , x ( 0 ) = 0 , , x ( m 2 ) ( 0 ) = 0 , α x ( 1 ) + β x ( 1 ) = γ 1 0 ζ x ( s ) d s + j = 1 p α j x ( η j ) + γ 2 ξ 1 x ( s ) d s ,
where c D q represents the Caputo fractional derivative operator of order q ( m 1 , m ] ,   m N ,   m 2 ,   p i > 0 , 0 < ζ ,   η 1 , η 2 , , η p ,   ξ < 1 , f ,   g i : [ 0 , 1 ] × R R , ( i = 1 , , k ) are continuous functions a , α , β , γ 1 , γ 2 R and α j R , j = 1 , 2 , , p . Notice that the fixed/nonlocal points involved in the problem (1) are non-singular.
We emphasize that the problem considered in this paper is novel in the sense that the fractional integro-differential equation involves many finitely Riemann–Liouville fractional integral type nonlinearities together with a non-integral nonlinearity. In the literature, one can find results on linear integro-differential equations [30], fractional integro-differential equations with nonlinearity depending on the linear integral terms [31,32], and initial value problems involving two nonlinear integral terms [33]. In contrast to the aforementioned work, our problem contains many finitely nonlinear integral terms of fractional order, which reduce to the nonlinear integral terms by fixing p i = 1 , i = 1 , , k . For specific applications of integral-differential equations in the mathematical modeling of physical problems such as the spreading of disease by the dispersal of infectious individuals, and reaction-–diffusion models in ecology, see [1,2]. In particular, one can find more details on the topic in [34] and the references cited therein. For some recent work on fractional integro-differential equations, see [35,36]. In a more recent work [37], the authors studied the existence of solutions for a fractional integro-differential equation supplemented with dual anti-periodic boundary conditions. Concerning the boundary condition at the terminal position t = 1 , the linear combination of the unknown function and its derivative is associated with the contribution due to two sub-strips ( 0 , ζ ) and ( ξ , 1 ) and finitely many nonlocal positions between them within the domain [ 0 , 1 ] . This boundary condition covers many interesting situations, for example, it corresponds to the two-strip aperture condition for all α j = 0 , j = 1 , , p . By taking γ 1 = 0 = γ 2 , this condition takes the form of a multi-point nonlocal boundary condition. It is interesting to note that the role of integral boundary conditions in studying practical problems such as blood flow problems [38] and bacterial self-regularization [39], etc., is crucial. For the application of strip conditions in engineering and real world problems, see [40,41]. On the other hand, the concept of nonlocal boundary conditions plays a significant role when physical, chemical or other processes depend on the interior positions (non-fixed points or segments) of the domain, for instance, see [42,43,44,45] and the references therein.
The rest of the paper is arranged as follows. Section 2 contains some related concepts of fractional calculus and an auxiliary result concerning a linear version of the problem (1). We prove the existence and uniqueness of solutions for the problem (1) by applying Banach and Krasnosel’ski i ’s fixed point theorems in Section 3. Finally, examples illustrating the main results are demonstrated in Section 4.

2. Preliminaries

Let us first outline some preliminary concepts of fractional calculus [5].
Definition 1.
The Caputo derivative for a function h A C n [ a , b ] of fractional order q ( n 1 , n ] , n N , existing almost everywhere on [ a , b ] , is defined by
c D q h ( t ) = 1 Γ ( n q ) a t ( t u ) n q 1 h ( n ) ( u ) d u , t [ a , b ] .
Definition 2.
The Riemann–Liouville fractional integral for a function h L 1 [ a , b ] of order r > 0 , which exists almost everywhere on [ a , b ] , is defined by
I r h ( t ) = 1 Γ ( r ) a t h ( u ) ( t u ) 1 r d u , t [ a , b ] .
Lemma 1.
For m 1 < r m , the general solution of the fractional differential equation c D r x ( t ) = 0 can be written as
x ( t ) = b 0 + b 1 t + b 2 t 2 + + b m 1 t m 1 ,
where b i R , i = 0 , 1 , 2 , , m 1 .
It follows by Lemma 1 that
I r c D r x ( t ) = x ( t ) + b 0 + b 1 t + b 2 t 2 + + b m 1 t m 1 ,
for some b i R , i = 0 , 1 , 2 , , m 1 , are arbitrary constants.
The following lemma deals with the linear version of the problem (1).
Lemma 2.
For a given function h C ( [ 0 , 1 ] , R ) the unique solution of the following boundary value problem
c D q x ( t ) = h ( t ) , 0 < t < 1 , x ( 0 ) = a , x ( 0 ) = 0 , x ( 0 ) = 0 , , x ( m 2 ) ( 0 ) = 0 , α x ( 1 ) + β x ( 1 ) = γ 1 0 ζ x ( s ) d s + j = 1 p α j x ( η j ) + γ 2 ξ 1 x ( s ) d s ,
is given by
x ( t ) = 0 t ( t s ) q 1 Γ ( q ) h ( s ) d s + a t m 1 Λ 1 [ α 0 1 ( 1 s ) q 1 Γ ( q ) h ( s ) d s + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) h ( s ) d s γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s j = 1 p α j 0 η j ( η j s ) q 1 Γ ( q ) h ( s ) d s γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s + Λ 2 ] ,
where it is assumed that
Λ 1 = α + β ( m 1 ) γ 1 ζ m m j = 1 p α j η j m 1 γ 2 1 ξ m m 0 ,
Λ 2 = a α γ 1 ζ j = 1 p α j γ 2 ( 1 ξ ) .
Proof. 
Using (3), we can write the general solution of the fractional differential equation in (4) as
x ( t ) = 0 t ( t s ) q 1 Γ ( q ) h ( s ) d s c 0 c 1 t c 2 t 2 c m 1 t m 1 ,
where c 0 , c 1 , c 2 , , c m 1 R are arbitrary constants. From (8), we have
x ( t ) = 0 t ( t s ) q 2 Γ ( q 1 ) h ( s ) d s c 1 2 c 2 t ( m 1 ) c m 1 t m 2 , x ( t ) = 0 t ( t s ) q 3 Γ ( q 2 ) h ( s ) d s 2 c 2 ( m 1 ) ( m 2 ) c m 1 t m 3 ,
Applying the conditions x ( 0 ) = a , x ( 0 ) = 0 , , x ( m 2 ) ( 0 ) = 0 in (8), it is found that c 0 = a , c 1 = 0 , , c m 2 = 0 . Then (8) becomes
x ( t ) = 0 t ( t s ) q 1 Γ ( q ) h ( s ) d s + a c m 1 t m 1 ,
and
x ( t ) = 0 t ( t s ) q 2 Γ ( q 1 ) h ( s ) d s ( m 1 ) c m 1 t m 2 .
Combining (10) and (11) with the condition α x ( 1 ) + β x ( 1 ) = γ 1 0 ζ x ( s ) d s + j = 1 p α j x ( η j ) + γ 2 ξ 1 x ( s ) d s , we get
α 0 1 ( 1 s ) q 1 Γ ( q ) h ( s ) d s + a c m 1 + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) h ( s ) d s ( m 1 ) c m 1 = γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u + a c m 1 s m 1 d s + j = 1 p α j 0 η j ( η j s ) q 1 Γ ( q ) h ( s ) d s + a c m 1 η j m 1 + γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u + a c m 1 s m 1 d s ,
which, together with (6) and (7), yields
c m 1 = 1 Λ 1 [ α 0 1 ( 1 s ) q 1 Γ ( q ) h ( s ) d s + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) h ( s ) d s γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s j = 1 p α j 0 η j ( η j s ) q 1 Γ ( q ) h ( s ) d s γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s + a α a γ 1 ζ a j = 1 p α j a γ 2 ( 1 ξ ) ] .
Substituting the value of c m 1 in (10), we obtain
x ( t ) = 0 t ( t s ) q 1 Γ ( q ) h ( s ) d s + a t m 1 Λ 1 [ α 0 1 ( 1 s ) q 1 Γ ( q ) h ( s ) d s + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) h ( s ) d s γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s j = 1 p α j 0 η j ( η i s ) q 1 Γ ( q ) h ( s ) d s γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) h ( u ) d u d s + Λ 2 ] .
We can obtain the converse of this lemma by direct computation. This finishes the proof. □
Using Lemma 2, we can transform problem (1) into a fixed point problem as x = F x , where the operator F : C C is defined by
F x ( t ) = 0 t ( t s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s + a t m 1 Λ 1 α 0 1 ( 1 s ) q 1 Γ ( q ) f ( s , x ( s ) ) i = 1 k ( 1 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) f ( s , x ( s ) ) i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) g i ( s , x ( s ) ) d s γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) f ( u , x ( u ) ) d u d s + γ 1 i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i g i ( w , x ( w ) ) d w d u d s j = 1 p α j 0 η j ( η j s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s i = 1 k 0 η j ( η j s ) q + p i 1 Γ ( q + p i ) g i ( s , x ( s ) ) d s γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) f ( u , x ( u ) ) d u d s + γ 2 i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i g i ( w , x ( w ) ) d w d u d s + Λ 2 .
Here C , represents the Banach space of all continuous functions x : [ 0 , 1 ] R equipped with the norm x = sup t [ 0 , 1 ] | x ( t ) | .
By a solution of (1), we mean a function x C of class C m [ 0 , 1 ] satisfying the nonlocal integro-multipoint boundary value problem (1).
For computational convenience, we set
Ω = [ 1 Γ ( q + 1 ) + 1 | Λ 1 | ( | α | Γ ( q + 1 ) + | β | Γ ( q ) + | γ 1 | ζ q + 1 Γ ( q + 2 ) + j = 1 p | α j | η j q Γ ( q + 1 )
+ | γ 2 | | 1 ξ q + 1 | Γ ( q + 2 ) ) ] , Ω i = [ 1 Γ ( q + p i + 1 ) + 1 | Λ 1 | ( | α | Γ ( q + p i + 1 ) + | β | Γ ( q + p i ) + | γ 1 | ζ q + p i + 1 Γ ( q + p i + 2 )
+ j = 1 p | α j | η j q + p i Γ ( q + p i + 1 ) + | γ 2 | | 1 ξ q + p i + 1 | Γ ( q + p i + 2 ) ) ] , i = 1 , 2 , , k .

3. Existence and Uniqueness Results

In the following theorem, we make use of Banach’s fixed point theorem.
Theorem 1.
Let f , g i : [ 0 , 1 ] × R R be continuous functions and let there exist constants L , L i > 0 , ( i = 1 , , k ) such that:
( A 1 )
f ( t , x ) f ( t , y ) L x y , and g i ( t , x ) g i ( t , y ) L i x y for all t [ 0 , 1 ] , x , y R .
Then, the boundary value problem (1) has a unique solution on [ 0 , 1 ] if
L Ω + i = 1 k L i Ω i < 1 ,
where Ω , Ω i , i = 1 , 2 , , k are given by (13) and (14), respectively.
Proof. 
The proof will be given in two steps.
Step 1. We show that F B r B r , where B r = x C : x r with r     ( M Ω + i = 1 k M i Ω i + | a | + ( Λ 2 / Λ 1 ) / 1 ( L Ω + i = 1 k L i Ω i ) and M , M i are positive numbers such that M = sup t [ 0 , 1 ] f ( t , 0 ) and M i = sup t [ 0 , 1 ] g i ( t , 0 ) , i = 1 , 2 , , k .
For x B r and t [ 0 , 1 ] , it follows by ( A 1 ) that
| f ( t , x ( t ) ) | | f ( t , x ( t ) ) f ( t , 0 ) | + | f ( t , 0 ) | L x + M L r + M .
In a similar manner, we have g i ( t , x ( t ) ) L i r + M i , i = 1 , 2 , , k . Then
F x sup t [ 0 , 1 ] 0 t ( t s ) q 1 Γ ( q ) | f ( s , x ( s ) ) | d s + i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i | g i ( s , x ( s ) ) | d s + | a | + t m 1 | Λ 1 | | α | 0 1 ( 1 s ) q 1 Γ ( q ) | f ( s , x ( s ) ) | + i = 1 k ( 1 s ) q + p i 1 Γ q + p i | g i ( s , x ( s ) ) | d s + | β | 0 1 ( 1 s ) q 2 Γ ( q 1 ) | f ( s , x ( s ) ) | + i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) | g i ( s , x ( s ) ) | d s + | γ 1 | 0 ζ 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) | d u d s + | γ 1 | i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) | d w d u d s + j = 1 p | α j | 0 η j ( η j s ) q 1 Γ ( q ) | f ( s , x ( s ) ) | d s + i = 1 k 0 η j ( η j s ) q + p i 1 Γ ( q + p i ) | g i ( s , x ( s ) ) | d s + | γ 2 | ξ 1 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) | d u d s + | γ 2 | i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) | d w d u d s + | Λ 2 | ( L r + M ) sup t [ 0 , 1 ] t q Γ ( q + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + 1 ) + | β | Γ ( q ) + | γ 1 | ζ q + 1 Γ ( q + 2 ) + j = 1 p | α j | η j q Γ ( q + 1 ) + | γ 2 | ( 1 ξ q + 1 ) Γ ( q + 2 ) + i = 1 k ( L i r + M i ) t q + p i Γ ( q + p i + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + p i + 1 ) + | β | Γ ( q + p i ) + | γ 1 | ζ q + p i + 1 Γ ( q + p i + 2 ) + j = 1 p | α i | η j q + p i Γ ( q + p i + 1 ) + | γ 2 | ( 1 ξ q + p i + 1 ) Γ ( q + p i + 2 ) + | a | + t m 1 | Λ 2 | | Λ 1 | = ( L r + M ) Ω + i = 1 k ( L i r + M i ) Ω i + | a | + Λ 2 Λ 1 = L Ω + i = 1 k L i Ω i r + M Ω + i = 1 k M i Ω i + | a | + Λ 2 Λ 1 r ,
which shows that F B r B r .
Step 2. We show that F is a contraction. For x , y C and for each t [ 0 , 1 ] , we obtain
F x F y sup t [ 0 , 1 ] 0 t ( t s ) q 1 Γ ( q ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | d s + i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i | g i ( s , x ( s ) ) g i ( s , y ( s ) ) | d s + t m 1 | Λ 1 | | α | 0 1 ( 1 s ) q 1 Γ ( q ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 1 Γ ( q + p i ) | g i ( s , x ( s ) ) g i ( s , y ( s ) ) | d s + | β | 0 1 ( 1 s ) q 2 Γ ( q 1 ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) | g i ( s , x ( s ) ) g i ( s , y ( s ) ) | d s + | γ 1 | 0 ζ 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) f ( u , y ( u ) ) | d u d s + | γ 1 | i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) g i ( w , y ( w ) ) | d w d u d s + j = 1 p | α j | 0 η j ( η j s ) q 1 Γ ( q ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | d s + i = 1 k 0 η i ( η i s ) q + p i 1 Γ ( q + p i ) | g i ( s , x ( s ) ) g i ( x , y ( s ) ) | d s + | γ 2 | ξ 1 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) f ( u , y ( u ) ) | d u d s + | γ 2 | i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) g i ( w , y ( w ) ) | d w d u d s L sup t [ 0 , 1 ] t q Γ ( q + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + 1 ) + | β | Γ ( q ) + | γ 1 | ζ q + 1 Γ ( q + 2 ) + j = 1 p | α j | η j q Γ ( q + 1 ) + | γ 2 | ( 1 ξ q + 1 ) Γ ( q + 2 ) x y + i = 1 k L i t q + p i Γ ( q + p i + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + p i + 1 ) + | β | Γ ( q + p i ) + | γ 1 | ζ q + p i + 1 Γ ( q + p i + 2 ) + j = 1 p | α j | η j q + p i Γ ( q + p i + 1 ) + | γ 2 | ( 1 ξ q + p i + 1 ) Γ ( q + p i + 2 ) x y L Ω + i = 1 k L i Ω i x y ,
which, by the condition (15), implies that F is a contraction. Thus the conclusion of the Banach contraction mapping principle applies and hence the operator F has a unique fixed point. Therefore, there exists a unique solution for the boundary value problem (1) on [ 0 , 1 ] . □
Next, we prove an existence result for the boundary value problem (1), which relies on Krasnosel’ski i ’s fixed point theorem [46].
Theorem 2.
Let f , g i : [ 0 , 1 ] × R R , ( i = 1 , , k ) be continuous functions satisfying the condition ( A 1 ) . In addition, we assume that:
( A 2 )
f ( t , x ) μ ( t ) , g i ( t , x ) μ i ( t ) , for all ( t , x ) [ 0 , 1 ] × R , μ , μ i C ( [ 0 , 1 ] , R + ) .
Then, the boundary value problem (1) has at least one solution on [ 0 , 1 ] , provided that
L Ω 1 Γ ( q + 1 ) + i = 1 k L i Ω i 1 Γ ( q + p i + 1 ) < 1 ,
where Ω , Ω i , i = 1 , 2 , , k are given by (13) and (14), respectively.
Proof. 
Consider B ρ = x C : x ρ , μ = sup t [ 0 , 1 ] | μ ( t ) | , μ i = sup t [ 0 , 1 ] | μ i ( t ) | , i = 1 , 2 , , k with ρ μ Ω + i = 1 k μ i Ω i + | a | + | Λ 2 | / | Λ 1 | . Then, we define the operators Φ and Ψ on B ρ as
Φ x ( t ) = 0 t ( t s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s + i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s , t [ 0 , 1 ] , Ψ x ( t ) = a t m 1 Λ 1 α 0 1 ( 1 s ) q 1 Γ ( q ) f ( s , x ( s ) ) i = 1 k ( 1 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s + β 0 1 ( 1 s ) q 2 Γ ( q 1 ) f ( s , x ( s ) ) i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) g i ( s , x ( s ) ) d s γ 1 0 ζ 0 s ( s u ) q 1 Γ ( q ) f ( u , x ( u ) ) d u d s + γ 1 i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i g i ( w , x ( w ) ) d w d u d s j = 1 p α j 0 η j ( η j s ) Γ ( q ) f ( s , x ( s ) ) d s i = 1 k 0 η j ( η j s ) q + p i 1 Γ ( q + p i ) g i ( s , x ( s ) ) d s γ 2 ξ 1 0 s ( s u ) q 1 Γ ( q ) f ( u , x ( u ) ) d u d s + γ 2 i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i g i ( w , x ( w ) ) d w d u d s + Λ 2 , t [ 0 , 1 ] .
We complete the proof in three steps.
Step 1. We show that Φ x + Ψ y B ρ . For x , y B ρ , we find that
Φ x + Ψ y sup t [ 0 , 1 ] 0 t ( t s ) q 1 Γ ( q ) | f ( s , x ( s ) ) | d s + i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i | g i ( s , x ( s ) ) | d s + | a | + t m 1 | Λ 1 | | α | 0 1 ( 1 s ) q 1 Γ ( q ) | f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 1 Γ q + p i | g i ( s , y ( s ) ) | d s + | β | 0 1 ( 1 s ) q 2 Γ ( q 1 ) | f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) | g i ( s , y ( s ) ) | d s + | γ 1 | 0 ζ 0 s ( s u ) q 1 Γ ( q ) | f ( u , y ( u ) ) | d u d s + | γ 1 | i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , y ( w ) ) | d w d u d s + j = 1 p | α j | 0 η j ( η j s ) q 1 Γ ( q ) | f ( s , y ( s ) ) | d s + i = 1 k 0 η j ( η j s ) q + p i 1 Γ ( q + p i ) | g i ( s , y ( s ) ) | d s + | γ 2 | ξ 1 0 s ( s u ) q 1 Γ ( q ) | f ( u , y ( u ) ) | d u d s + | γ 2 | i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , y ( w ) ) | d w d u d s + | Λ 2 | μ sup t [ 0 , 1 ] t q Γ ( q + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + 1 ) + | β | Γ ( q ) + | γ 1 | ζ q + 1 Γ ( q + 2 ) + j = 1 p | α j | η j q Γ ( q + 1 ) + | γ 2 | ( 1 ξ q + 1 ) Γ ( q + 2 ) + i = 1 k μ i t q + p i Γ ( q + p i + 1 ) + t m 1 | Λ 1 | | α | Γ ( q + p i + 1 ) + | β | Γ ( q + p i ) + | γ 1 | ζ q + p i + 1 Γ ( q + p i + 2 ) + j = 1 p | α j | η j q + p i Γ ( q + p i + 1 ) + | γ 2 | ( 1 ξ q + p i + 1 ) Γ ( q + p i + 2 ) + | a | + Λ 2 Λ 1 = μ Ω + i = 1 k μ i Ω i + | a | + Λ 2 Λ 1 ρ .
Thus, Φ x + Ψ y B ρ .
Step 2. We show that Ψ is a contraction mapping. For that, let x , y C . Then, for each t [ 0 , 1 ] , we have
Ψ x Ψ y sup t [ 0 , 1 ] t m 1 | Λ 1 | | α | 0 1 ( 1 s ) q 1 Γ ( q ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 1 Γ ( q + p i ) | g i ( s , x ( s ) ) g i ( s , y ( s ) ) | d s + | β | 0 1 ( 1 s ) q 2 Γ ( q 1 ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | + i = 1 k ( 1 s ) q + p i 2 Γ ( q + p i 1 ) | g i ( s , x ( s ) ) g i ( s , y ( s ) ) | d s + | γ 1 | 0 ζ 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) f ( u , y ( u ) ) | d u d s + | γ 1 | i = 1 k 0 ζ 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) g i ( w , y ( w ) ) | d w d u d s + j = 1 p | α j | 0 η j ( η j s ) q 1 Γ ( q ) | f ( s , x ( s ) ) f ( s , y ( s ) ) | d s + i = 1 k 0 η j ( η j s ) q + p i 1 Γ ( q + p i ) | g i ( s , x ( s ) ) g i ( x , y ( s ) ) | d s + | γ 2 | ξ 1 0 s ( s u ) q 1 Γ ( q ) | f ( u , x ( u ) ) f ( u , y ( u ) ) | d u d s + | γ 2 | i = 1 k ξ 1 0 s ( s u ) q 1 Γ ( q ) 0 u ( u w ) p i 1 Γ p i | g i ( w , x ( w ) ) g i ( w , y ( w ) ) | d w d u d s L sup t [ 0 , 1 ] t m 1 | Λ 1 | | α | Γ ( q + 1 ) + | β | Γ ( q ) + | γ 1 | ζ q + 1 Γ ( q + 2 ) + j = 1 p | α j | η j q Γ ( q + 1 ) + | γ 2 | ( 1 ξ q + 1 ) Γ ( q + 2 ) × x y + i = 1 k L i t m 1 | Λ 1 | | α | Γ ( q + p i + 1 ) + | β | Γ ( q + p i ) + | γ 1 | ζ q + p i + 1 Γ ( q + p i + 2 ) + j = 1 p | α j | η j q + p i Γ ( q + p i + 1 ) + | γ 2 | ( 1 ξ q + p i + 1 ) Γ ( q + p i + 2 ) x y L Ω 1 Γ ( q + 1 ) + i = 1 k L i Ω i 1 Γ ( q + p i + 1 ) x y ,
which is a contraction by the condition (17).
Step 3. We show that Φ is compact and continuous.
(i)
Observe that the continuity of the operator Φ follows from that of f and g i , i = 1 , , k .
(ii)
Φ is uniformly bounded on B ρ as:
Φ x sup t [ 0 , 1 ] 0 t ( t s ) q 1 Γ ( q ) | f ( s , x ( s ) ) | d s + i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i | g i ( s , x ( s ) ) | d s μ sup t [ 0 , 1 ] 0 t ( t s ) q 1 Γ ( q ) d s + μ i sup t [ 0 , 1 ] i = 1 k 0 t ( t s ) q + p i 1 Γ q + p i d s μ Γ ( q + 1 ) + i = 1 k μ i Γ ( q + p i + 1 ) .
(iii)
Φ is equicontinuous.
Let us set max ( t , x ) [ 0 , 1 ] × B ρ | f ( t , x ) | = f ^ and max ( t , x ) [ 0 , 1 ] × B ρ | g i ( t , x ) | = g i ^ , i = 1 , 2 , , m . Then, for t 1 , t 2 [ 0 , 1 ] , t 1 > t 2 , we have
Φ x t 1 Φ x t 2 = 0 t 1 ( t 1 s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s i = 1 k 0 t 1 ( t 1 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s 0 t 2 ( t 2 s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s + i = 1 k 0 t 2 ( t 2 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s 0 t 2 ( t 1 s ) q 1 ( t 2 s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s + t 2 t 1 ( t 1 s ) q 1 Γ ( q ) f ( s , x ( s ) ) d s + i = 1 k 0 t 2 ( t 2 s ) q + p i 1 ( t 1 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s + t 2 t 1 ( t 1 s ) q + p i 1 Γ q + p i g i ( s , x ( s ) ) d s f ^ Γ ( q + 1 ) | ( t 1 t 2 ) q | + | t 1 q t 2 q | + | ( t 1 t 2 ) q | + g i ^ Γ ( q + p i + 1 ) | t 2 q + p i t 1 q + p i | + | ( t 1 t 2 ) q + p i | + | ( t 1 t 2 ) q + p i | f ^ Γ ( q + 1 ) 2 t 1 t 2 q + t 1 q t 2 q + g i ^ Γ ( q + p i + 1 ) | 2 t 1 t 2 q + p i t 1 q + p i + t 2 q + p i | ,
which tends to zero, independent of x, as t 1 t 2 0 . So, Φ is equicontinuous. Hence, we deduce by the Arzelá–Ascoli Theorem that Φ is compact on B r . So, the hypothesis (Steps 1–3) of Krasnosel’skiĭ’s fixed point theorem [46] holds true. Consequently, there exists at least one solution for the boundary value problem (1) on [ 0 , 1 ] . The proof is completed. □

4. Examples

Here, we illustrate the applicability of our results by constructing numerical examples.
Example 1.
Consider the following boundary value problem:
c D 13 / 4 x ( t ) + i = 1 2 I p i g i ( t , x ( t ) ) = f ( t , x ( t ) ) , t [ 0 , 1 ] , x ( 0 ) = 0 , x ( 0 ) = 0 , x ( 0 ) = 0 , α x ( 1 ) + β x ( 1 ) = γ 1 0 1 / 4 x ( s ) d s + j = 1 3 α j x ( η j ) + γ 2 1 / 2 1 x ( s ) d s .
Here, m = 4 , q = 13 / 14 , p 1 = 10 / 14 , p 2 = 11 / 14 , p 3 = 12 / 14 , α = β = γ 1 = γ 2 = 1 , ζ = 1 / 4 , α 1 = 1 / 2 , α 2 = 3 / 4 , α 3 = 1 , η 1 = 1 / 7 , η 2 = 2 / 7 , η 3 = 3 / 7 , ξ = 1 / 2 .
(i)
Let f ( t , x ) = e 2 t 70 ( arctan x + sin 5 t ) , g 1 ( t , x ) = 1 4 e t cos x + t 2 + 1 t 2 + 49 , and g 2 ( t , x ) = 1 34 ( sin x + e t 57 ) . It is easy to see that ( A 1 ) is satisfied with L = e 2 / 70 , L 1 = 1 / 28 , and L 2 = 1 / 34 .
Using the given data, we have Ω 1.932128 , Ω 1 0.677039 , Ω 2 1.237301 , and
Λ 1 = α + β ( m 1 ) γ 1 ζ m m j = 1 3 α j η j m 1 γ 2 1 ξ m m 3.666981 .
Then, L Ω + i = 1 2 L i Ω i 0.203951 + 0.060571 < 1 . Thus, by Theorem 1, the boundary value problem (18) has a unique solution on [ 0 , 1 ] .
(ii)
We choose the following functions in problem (18) for illustrating Theorem 2:
f ( t , x ) = 2 17 ( sin x + e t cos 7 t ) , g 1 ( t , x ) = 3 32 | x | 1 + | x | + 2 t , g 2 ( t , x ) = 1 34 ( sin x + e t 32 ) .
Here L = 2 / 17 , L 1 = 3 / 32 and L 2 = 1 / 34 as | f ( t , x ) f ( t , y ) | 2 17 | x y | , | g 1 ( t , x ) g 1 ( t , y ) | 3 32 | x y | and | g 2 ( t , x ) g 2 ( t , y ) | 1 34 | x y | .
Further,
f ( t , x ) 2 17 | sin x | + e t | cos 7 t | 2 17 + e t cos 7 t = μ ( t ) , g 1 ( t , x ) 3 32 + 2 t = μ 1 ( t ) ,
and
g 2 ( t , x ) 1 34 | sin x | + e t 32 1 34 + e t 32 = μ 2 ( t ) .
Obviously, μ = 19 / 17 , μ 1 = 67 / 32 and μ 2 = 5.686266 . Moreover, we have
L Ω 1 Γ ( q + 1 ) + i = 1 2 L i Ω i 1 Γ ( q + p i + 1 ) 0.1824334 < 1 .
As the hypothesis of Theorem 2 holds true, so there exists least one solution for problem (18) with the functions given by (19).

5. Conclusions

We have studied a nonlinear fractional integro-differential equation involving many finitely Riemann–Liouville fractional integral type nonlinearities together with a non-integral nonlinearity complemented by multi-point sub-strip boundary conditions. In fact, we considered a more general situation by considering the fractional order nonlinear integral terms in the integro-differential equation at hand, which reduce to the usual nonlinear integral terms for p i = 1 , i = 1 , , k . Under appropriate assumptions, the existence and uniqueness results for the given problem are proved by applying the standard tools of the fixed point theory. The results obtained in this paper are not only new, but they also lead to some new results associated with the particular choices of the parameters involved in the problem. For example, our results correspond to the two-strip aperture ( ζ , ξ ) boundary value problem when α j = 0 , j = 1 , , p . On the other hand, by letting γ 1 = 0 = γ 2 in the the results of this paper, we obtain the ones for a nonlinear Caputo–Riemann–Liouville type fractional integro-differential equation with multi-point boundary conditions. Thus, the work presented in this paper significantly contributes to the existing literature on the topic.

Author Contributions

Conceptualization, B.A.; formal analysis, A.A., A.F.A., S.K.N. and B.A.; funding acquisition, A.A.; methodology, A.A., A.F.A., S.K.N. and B.A. All authors have read and agreed to the published version of the manuscript.

Funding

The Deanship of Scientific Research (DSR) at King Abdulaziz University, Jeddah, Saudi Arabia, funded this project, under grant no. (FP-20-42).

Acknowledgments

The Deanship of Scientific Research (DSR) at King Abdulaziz University, Jeddah, Saudi Arabia, funded this project, under grant no. (FP-20-42). The authors, therefore, acknowledge the DSR, with thanks for the technical and financial support provided. The authors thank the reviewers for their constructive remarks on our work.

Conflicts of Interest

The authors declare no conflict of interest.

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Alsaedi, A.; Albideewi, A.F.; Ntouyas, S.K.; Ahmad, B. On Caputo–Riemann–Liouville Type Fractional Integro-Differential Equations with Multi-Point Sub-Strip Boundary Conditions. Mathematics 2020, 8, 1899. https://doi.org/10.3390/math8111899

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Alsaedi A, Albideewi AF, Ntouyas SK, Ahmad B. On Caputo–Riemann–Liouville Type Fractional Integro-Differential Equations with Multi-Point Sub-Strip Boundary Conditions. Mathematics. 2020; 8(11):1899. https://doi.org/10.3390/math8111899

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Alsaedi, Ahmed, Amjad F. Albideewi, Sotiris K. Ntouyas, and Bashir Ahmad. 2020. "On Caputo–Riemann–Liouville Type Fractional Integro-Differential Equations with Multi-Point Sub-Strip Boundary Conditions" Mathematics 8, no. 11: 1899. https://doi.org/10.3390/math8111899

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