## 1. Introduction

Let

$\mathbb{K}$ be a field, and set

$S=\mathbb{K}[{x}_{1},\cdots ,{x}_{n}]$. Assume that

M is a finitely generated,

${\mathbb{Z}}^{n}$-graded

S-module. For any homogeneous element

$u\in M$ and any

$Z\subseteq \{{x}_{1},\cdots ,{x}_{n}\}$, the

$\mathbb{K}$-vector space

$u\mathbb{K}\left[Z\right]$ is called a Stanley space of dimension

$\left|Z\right|$. A Stanley decomposition of

M is a decomposition of

M as a finite direct sum of Stanley spaces. The minimum dimension of a Stanley space in a Stanley decomposition

$\mathcal{D}$ is called the Stanley depth of

$\mathcal{D}$, and is denoted by

$\mathrm{sdepth}\left(\mathcal{D}\right)$. The Stanley depth of

M is defined

As a convention, we set

$\mathrm{sdepth}\left(M\right)=\infty $ when

M is the zero module. For an introduction to Stanley depth, we refer the reader to [

1].

**Example** **1.** Consider the ideal $I=\langle {x}_{1}{x}_{2}^{2},{x}_{1}^{2}{x}_{2}\rangle $ in the polynomial ring $S=\mathbb{K}[{x}_{1},{x}_{2}]$. Then,is a Stanley decomposition for I, with $\mathrm{sdepth}\left({\mathcal{D}}_{1}\right)=1$. One can also write other Stanley decompositions for I. For example,andIt is clear that $\mathrm{sdepth}\left({\mathcal{D}}_{2}\right)=\mathrm{sdepth}\left({\mathcal{D}}_{3}\right)=0$. It follows from the definition of Stanley depth that $\mathrm{sdepth}\left(I\right)\ge 1$, and it can be easily verified that the equality indeed holds—that is, $\mathrm{sdepth}\left(I\right)=1$. We say that a

${\mathbb{Z}}^{n}$-graded

S-module

M satisfies

Stanley’s inequality if

In fact, Stanley [

2] conjectured that the above inequality holds for every finitely generated,

${\mathbb{Z}}^{n}$-graded

S-module. Ichim, Katthän, and Moyano-Fernández [

3] showed that in order to prove Stanley’s conjecture for monomial ideals, it is enough to consider squarefree monomial ideals. However, Stanley’s conjecture has been disproved by Duval, Goeckner, Klivans, and Martin [

4]. In fact, they constructed a non-partitionable Cohen-Macaulay simplicial complex, and then, using a result of Herzog, Soleyman Jahan, and Yassemi ([

5] Corollary 4.5), deduced that the Stanley-Reisner ring of this simplicial complex did not satisfy Stanley’s inequality. However, it is still interesting to find new classes of modules which satisfy Stanley’s inequality. Of particular interest is the validity of Stanley’s inequality for high powers of monomial ideals. In this survey article, we review the recent developments in this regard. In 2013, Herzog [

6] published his nice survey on Stanley depth. In fact, we complement his survey by collecting the results obtained since then, with a focus on powers of monomial ideals.

## 2. Ordinary Powers

In this section, we consider the ordinary powers of monomial ideals. As we explained in the introduction, it is natural to ask whether the high powers of monomial ideals satisfy Stanley’s inequality. In fact, this question was posed in [

7].

**Question** **1** ([

7], Question 1.1)

**.** Let I be a monomial ideal. Is it true that ${I}^{k}$ and $S/{I}^{k}$ satisfy Stanley’s inequality for every integer, $k\gg 0$?In the following subsections we will see that Question 1 has a positive answer when I belongs to interesting classes of monomial ideals.

#### 2.1. Maximal Ideal and Complete Intersections

Let

$\mathfrak{m}=({x}_{1},\dots ,{x}_{n})$ denote the maximal graded ideal of

S. It is clear that for every integer

$k\ge 1$,

$\mathrm{depth}(S/{\mathfrak{m}}^{k})=0$. Hence,

$S/{\mathfrak{m}}^{k}$ satisfies Stanley’s inequality for any

$k\ge 1$. Indeed, since

$S/{\mathfrak{m}}^{k}$ is an Artinian ring, we also have

$\mathrm{sdepth}(S/{\mathfrak{m}}^{k})=0$ for every integer,

$k\ge 1$. On the other hand,

$\mathrm{depth}\left({\mathfrak{m}}^{k}\right)=1$ and by ([

6] Corollary 24), we know that the Stanley depth of any monomial ideal is at least one. This implies that

${\mathfrak{m}}^{k}$ satisfies Stanley’s inequality for every integer,

$k\ge 1$. However, computing the exact value of the Stanley depth of

${\mathfrak{m}}^{k}$ is not easy. In 2010, Biró, Howard, Keller, Trotter, and Young [

8] proved that

$\mathrm{sdepth}\left(\mathfrak{m}\right)=\lceil n/2\rceil $. Cimpoeaş [

9] determined an upper bound for the Stanley depth of powers of

$\mathfrak{m}$. More precisely, he proved the following results:

**Theorem** **1** ([

9], Theorem 2.2)

**.** For every integer $k\ge 1$, we haveIn particular, for every integer $k\ge n-1$, we have $\mathrm{sdepth}\left({\mathfrak{m}}^{k}\right)=1$.

Cimpoeaş [

9] also conjectured that the inequality obtained in the above theorem was indeed an equality—that is,

for every

$k\ge 1$.

In 2018, Cimpoeaş [

10] extended Theorem 1 by determining the bounds for the Stanley depth of complete intersection monomial ideals.

**Theorem** **2** ([

10], Proposition 2.14 and Theorem 2.15)

**.** Let I be a complete intersection monomial ideal which is minimally generated by t monomials.- (i)
For every integer $k\ge 1$, we have In particular, if $k\ge t-1$, then $\mathrm{sdepth}\left({I}^{k}\right)=n-t+1$.

- (ii)
For every integer $k\ge 1$, we have

As an immediate consequence of Theorem 2, we conclude that for any complete intersection monomial ideal and every integer $k\ge 1$, the modules ${I}^{k},S/{I}^{k}$, and ${I}^{k}/{I}^{k+1}$ satisfy Stanley’s inequality. In particular, Question 1 has a positive answer in this case.

#### 2.2. Polymatroidal Ideals

We begin this subsection by recalling the definition of polymatroidal ideals. We mention that for every monomial ideal I, we denote its minimal set of monomial generators by $G\left(I\right)$.

**Definition** **1.** A monomial ideal I is called polymatroidal if it is generated in a single degree, and moreover, for every pair of monomials $u={x}_{1}^{{a}_{1}},\dots ,{x}_{n}^{{a}_{n}}$ and $v={x}_{1}^{{b}_{1}},\dots ,{x}_{n}^{{b}_{n}}$ belonging to $G\left(I\right)$, and for every i with ${a}_{i}>{b}_{i}$, one has j with ${a}_{j}<{b}_{j}$, such that ${x}_{j}(u/{x}_{i})\in G\left(I\right)$.

We next define the class of weakly polymatroidal ideals, which is a generalization of the class of polymatroidal ideals.

**Definition** **2** ([

11], Definition 1.1)

**.** A monomial ideal I is called weakly polymatroidal if, for every pair of monomials, $u={x}_{1}^{{a}_{1}}\dots {x}_{n}^{{a}_{n}}$ and $v={x}_{1}^{{b}_{1}}\dots {x}_{n}^{{b}_{n}}$ in $G\left(I\right)$ such that ${a}_{1}={b}_{1},\dots ,{a}_{t-1}={b}_{t-1}$ and ${a}_{t}>{b}_{t}$ for some t, there exists $j>t$ such that ${x}_{t}(v/{x}_{j})\in I$.It is obvious that any polymatroidal ideal is weakly polymatroidal.

Let

I be a weakly polymatroidal ideal. In ([

12] Theorem 2.4), we proved that

$S/I$ satisfies Stanley’s inequality. We also know from ([

13] Theorem 12.6.3) that every power of a polymatroidal ideal is again a polymatroidal ideal. As a consequence, for any polymatroidal ideal

I and any integer

$k\ge 1$, the module

$S/{I}^{k}$ satisfies Stanley’s inequality. It is natural to ask whether

${I}^{k}$ satisfies Stanley’s inequality. Before answering this question, we recall the concept of having linear quotients, introduced in [

14].

**Definition** **3.** Let I be a monomial ideal, and assume that $G\left(I\right)$ is the set of minimal monomial generators of I. We say that I has linear quotients if there is a linear order ${u}_{1}\prec {u}_{2}\prec \dots \prec {u}_{m}$ on $G\left(I\right)$, with the property that for every $2\le i\le m$, the ideal $({u}_{1},\dots ,{u}_{i-1}):{u}_{i}$ is generated by a subset of the variables.

Soleyman Jahan [

15] proves that Stanley’s inequality holds for any monomial ideal which has linear quotients. On the other hand, by ([

11] Theorem 1.3), we know that any weakly polymatroidal ideal has linear quotients. This implies that every weakly polymatroidal ideal satisfies Stanley’s inequality. Since every power of a polymatroidal ideal is again a polymatroidal ideal, we deduce that for any polymatroidal ideal

I and any integer

$k\ge 1$, the ideal

${I}^{k}$ satisfies Stanley’s inequality.

By the above argument, we know that Question 1 has a positive answer for polymatroidal ideals. This result was also obtained in [

16].

Let

I be a monomial ideal of

S with the Rees algebra

$\mathcal{R}\left(I\right)={\u2a01}_{k=0}^{\infty}{I}^{k}$. The

$\mathbb{K}$-algebra

$\mathcal{R}\left(I\right)/\mathfrak{m}\mathcal{R}\left(I\right)$ is called the

fibre ring, and its Krull dimension is called the

analytic spread of

I, denoted by

$\ell \left(I\right)$. A classical result by Burch [

17] states that

By a theorem of Brodmann [

18],

$\mathrm{depth}(S/{I}^{k})$ is constant for large

k. We call this constant value the

limit depth of

I, and denote it by

${lim}_{k\to \infty}\mathrm{depth}(S/{I}^{k})$. Brodmann improved Burch’s inequality by showing that

We know from ([

19] Corollary 3.5) that equality occurs in the above inequality if

I is a polymatroidal ideal. In fact, we will see in the next section that equality holds in Burch’s inequality for a larger class of ideals—namely, the class of

normal ideals.

Inspired by the limiting behavior of the depth of powers of ideals, Herzog [

6] proposed the following conjecture.

**Conjecture** **1** ([

6], Conjecture 59)

**.** For every monomial ideal I, the sequence ${\left\{\mathrm{sdepth}\left({I}^{k}\right)\right\}}_{k=1}^{\infty}$ is convergent.This conjecture is widely open. However, by Theorem 2, it has a positive answer for complete intersections. Also, we will see in

Section 4 that the assertion of this conjecture is true for any normally torsionfree, squarefree monomial ideal.

Let

I be a weakly polymatroidal ideal which is generated in a single degree. We know from ([

16] Theorem 2.5) that

$\mathrm{depth}(S/I)\ge n-\ell \left(I\right)$. Since

I and

$S/I$ satisfy Stanley’s inequality, it follows that

Restricting to the class of polymatroidal ideals, for any integer

$k\ge 1$ and any polymatroidal ideal

I, we have

Indeed, we expect that the equality holds in the above inequality for every $k\gg 0$. In other words, not only do we believe that Conjecture 1 is true for every polymatroidal ideal I, but we also have a prediction for the limit value of the Stanley depth of powers of I.

**Conjecture** **2.** Let I be a polymatroidal ideal. Then,for any integer $k\gg 0$. #### 2.3. Edge Ideals

Let

G be a finite simple graph with a vertex set

$V\left(G\right)=\left\{{x}_{1},\dots ,{x}_{n}\right\}$ and edge set

$E\left(G\right)$. The

edge ideal $I\left(G\right)$ of

G is defined as

The Stanley depth of powers of edge ideals has been studied in [

20,

21,

22,

23]. Before reviewing the main results of these papers, we mention the following result of Trung, concerning the depth of high powers of edge ideals.

**Theorem** **3** ([

24], Theorems 4.4 and 4.6)

**.** Let G be a graph with n vertices and p bipartite connected components. Then, for every integer $k\ge n-1$, we haveNote that by ([

25] p. 50), for every graph

G with

n vertices and

p bipartite connected components, we have

$\ell \left(I\right(G\left)\right)=n-p$. Thus, Theorem 3, essentially says that

that is, equality occurs in Burch’s inequality.

Pournaki, Yassemi, and the author [

22] studied the Stanley depth of

$S/I{\left(G\right)}^{k}$, where

G is a forest (i.e., a graph with no cycle). They proved that for every forest with

p connected components and any integer

$k\ge 1$, we have

This, together with Theorem 3, implies that for any forest

G with

n vertices, the module

$S/I{\left(G\right)}^{k}$ satisfies Stanley’s inequality for any integer

$k\ge n-1$. This result was then extended in [

23], to any arbitrary graph, as follows.

**Theorem** **4** ([

23], Theorem 2.3 and Corollary 2.5)

**.** Let G be a graph with n vertices and p bipartite connected components. Then, for every integer $k\ge 1$, we have $\mathrm{sdepth}(S/I{\left(G\right)}^{k})\ge p$. In particular, $S/I{\left(G\right)}^{k}$ satisfies Stanley’s inequality for any integer $k\ge n-1$.We know from the above theorem that for any graph G, the module $S/I{\left(G\right)}^{k}$ satisfies Stanley’s inequality for $k\gg 0$. However, how about $I{\left(G\right)}^{k}$? By Theorem 3, in order to prove Stanley’s inequality for high powers of $I\left(G\right)$, we need to prove $\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge p+1$ for every integer $k\gg 0$. We do not know whether this inequality holds for any arbitrary graph. However, we have a partial result, as follows. We recall that for any graph G and every subset $U\subset V\left(G\right)$, the graph $G\setminus U$ has the vertex set $V(G\setminus U)=V\left(G\right)\setminus U$ and edge set $E(G\setminus U)=\{e\in E(G)\mid e\cap U=\varnothing \}$.

**Theorem** **5** ([

23], Theorem 3.1)

**.** Let G be a graph, and assume that H is a connected component of G with at least one edge. Suppose that h is the number of bipartite connected components of $G\setminus V\left(H\right)$. Then, for every integer $k\ge 1$, we havewhere ${S}^{\prime}=\mathbb{K}[{x}_{i}\mid {x}_{i}\in V\left(H\right)]$.Assume that

G has a non-bipartite connected component, and call it

H. Then, by ([

6] Corollary 24), for every integer

$l\ge 1$, we have

$\mathrm{sdepth}\left(I{\left(H\right)}^{l}\right)\ge 1$. Thus, it follows from Theorem 5 that in this case,

$\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge p+1$, where

p is the number of bipartite connected components of

G and

$k\ge 1$ is an arbitrary positive integer. Assume now that

G is a bipartite graph. Using Theorem 5, in order to prove the inequality

$\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge p+1$, it is enough to prove it only for the class of connected bipartite graphs. Thus, we raise the following question.

**Question** **2** ([

23], Question 3.3)

**.** Let G be a connected bipartite graph (with at least one edge) and suppose $k\ge 1$ is an integer. Is it true that $\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge 2$?We investigated this question in [

26] and proved that it has positive answer for small

k. More precisely, we proved the following result.

**Theorem** **6** ([

26], Theorem 3.4)

**.** Let G be a connected bipartite graph (with at least one edge) and let g be a positive integer. Suppose G has no cycle of length at most $g-1$. Then, for every positive integer $k\le g/2+1$, we have $\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge 2$.Theorem 6, in particular, implies that $\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge 2$, for any integer $k\ge 1$, provided that G is a tree (i.e., a connected forest). Combining this result with Theorem 5 implies that if G is a bipartite graph and at least one of the connected components of G is a tree, then for every integer $k\ge 1$, we have $\mathrm{sdepth}\left(I{\left(G\right)}^{k}\right)\ge p+1$, where p is the number of (bipartite) connected components of G. All in all, we obtained the following theorem.

**Theorem** **7** ([

23], Corollary 3.6)

**.** Assume that G is a graph with n vertices, such that- (i)
G is a non-bipartite graph, or

- (ii)
at least one of the connected components of G is a tree with at least one edge.

Then, for every integer $k\ge n-1$, the ideal $I{\left(G\right)}^{k}$ satisfies Stanley’s inequality.

Let

I be a monomial ideal. We know by ([

27] Theorem 1.2) that the sequence

${\left\{\mathrm{depth}({I}^{k}/{I}^{k+1})\right\}}_{k=1}^{\infty}$ is convergent, and moreover,

Therefore, using Theorem 3, we conclude that for any graph

G,

where

p is the number of bipartite connected components of

G. In [

23], we also studied the Stanley depth of

$I{\left(G\right)}^{k}/I{\left(G\right)}^{k+1}$ and proved that it satisfied Stanley’s inequality for any

$k\gg 0$. In fact, we proved the following result.

**Theorem** **8** ([

23], Theorem 2.2 and Corollary 2.6)

**.** Let G be a graph and suppose p is the number of bipartite connected components of G. Then, for every integer $k\ge 0$, we have $\mathrm{sdepth}(I{\left(G\right)}^{k}/I{\left(G\right)}^{k+1})\ge p$. In particular, $I{\left(G\right)}^{k}/I{\left(G\right)}^{k+1}$ satisfies Stanley’s inequality, for every integer $k\gg 0$.We mention that in the special case, when

G is a forest, Theorem 8 was proved in ([

21] Theorem 3.1).

The diameter of a connected graph is the maximum distance between any two vertices. Here, the distance between two vertices is the minimum length of a path connecting the vertices.

Fouli and Morey [

20] studied the Stanley depth of small powers of edge ideals and determined a lower bound for it.

**Theorem** **9** ([

20], Theorem 4.18)

**.** Assume that G is a graph with c connected components, and let d denote the maximum of the diameters of the connected components of G. Then, for every integer $1\le t\le 3$, we haveFouli and Morey ([

20] Corollary 3.3, Theorems 4.4 and 4.13) also show that the inequality of Theorem 9 remains true, if one replaces depth with depth.

## 3. Integral Closure of Powers

The study of Stanley depth of integral closure of powers of monomial ideals was initiated in [

28] and continued in [

26]. Before stating the results of these papers, we recall some definitions and basic facts from the theory of integral closure.

Let

$I\subset S$ be an arbitrary ideal. An element

$f\in S$ is

integral over

I, if there exists an equation

The

integral closure of

I, denoted by

$\overline{I}$, is the set of elements of

S which are integral over

I. It is known that the integral closure of a monomial ideal

I is again a monomial ideal, and it is generated by all monomials

$u\in S$ with the property that there exists an integer

k, such that

${u}^{k}\in {I}^{k}$ (see ([

13] Theorem 1.4.2)). An ideal is said to be

integrally closed if it is equal to its integral closure, and it is

normal if all its powers are integrally closed. By ([

29] Theorem 3.3.18), a monomial ideal

I is normal if, and only if, the Rees algebra

$\mathcal{R}\left(I\right)$ is a normal ring.

We first notice that there is no general inequality between the Stanley depth of $S/I$ and that of $S/\overline{I}$. This will be illustrated in the following examples.

**Example** **2** ([

28], Example 1.2)

**.** Let $I=({x}_{1}^{2},{x}_{2}^{2},{x}_{1}{x}_{2}{x}_{3})$ be a monomial ideal in the polynomial ring $S=\mathbb{K}[{x}_{1},{x}_{2},{x}_{3}]$. It is not difficult to see that $\overline{I}=({x}_{1}^{2},{x}_{2}^{2},{x}_{1}{x}_{2})$. Then, the maximal ideal $\mathfrak{m}=({x}_{1},{x}_{2},{x}_{3})$ is an associated prime of $S/I$, and it follows from ([30] Proposition 1.3) that $\mathrm{sdepth}(S/I)=0$. Since $\mathfrak{m}$ is not an associated prime of $S/\overline{I}$, it follows from ([31] Proposition 2.13) that $\mathrm{sdepth}(S/\overline{I})\ge 1$. Thus, in this example, $\mathrm{sdepth}(S/I)<\mathrm{sdepth}(S/\overline{I})$.**Example** **3** ([

28], Example 1.3)

**.** Let $I=({x}_{1}^{2}{x}_{2}^{2},{x}_{1}^{2}{x}_{3}^{2},{x}_{2}^{2}{x}_{3}^{2})$ be a monomial ideal in the polynomial ring $S=\mathbb{K}[{x}_{1},{x}_{2},{x}_{3}]$. The maximal ideal $\mathfrak{m}=({x}_{1},{x}_{2},{x}_{3})$ is not an associated prime of $S/I$ and hence, using ([31] Proposition 2.13), we conclude that $\mathrm{sdepth}(S/I)\ge 1$. On the other hand, using ([32] Theorem 2.4), we know that the maximal ideal $\mathfrak{m}$ is an associated prime of $S/\overline{I}$. Hence, it follows from ([30] Proposition 1.3) that $\mathrm{sdepth}(S/\overline{I})=0$. Therefore, in this example, $\mathrm{sdepth}(S/I)>\mathrm{sdepth}(S/\overline{I})$.Although there is no general inequality between $\mathrm{sdepth}(S/I)$ and $\mathrm{sdepth}(S/\overline{I})$, we will see in the following theorem that the Stanley depth of $S/\overline{I}$ provides an upper bound for the Stanley depth of the quotient ring of some powers of I.

**Theorem** **10** ([

28], Theorem 2.8)

**.** Let ${I}_{2}\subseteq {I}_{1}$ be two monomial ideals in S. Then, there exists an integer $k\ge 1$, such that for every $s\ge 1$,In particular, we have the following corollary.

**Corollary** **1.** Let $I\subset S$ be a monomial ideal. Then, there exist integers ${k}_{1},{k}_{2}\ge 1$, such that for every $s\ge 1,$and We mention that the assertions of Corollary 1 remain true if one replaces sdepth with depth, ([

26] Theorem 4.5).

In Question 1, we asked whether the high powers of an ideal satisfied Stanley’s inequality. One can ask a similar question by replacing

${I}^{k}$ with its integral closure. This question is posed in [

26].

**Question** **3** ([

26], Question 1.2)

**.** Let I be a monomial ideal. Is it true that $\overline{{I}^{k}}$ and $S/\overline{{I}^{k}}$ satisfy Stanley’s inequality for every integer $k\gg 0$?Before we focus on the above question, we recall the following result of Hoa and Trung concerning the depth of integral closure of high powers of monomial ideals.

**Theorem** **11** ([

33], Lemma 1.5)

**.** Let I be a monomial ideal of S. Then, $\mathrm{depth}(S/\overline{{I}^{k}})=n-\ell \left(I\right)$ for every integer $k\gg 0$.According to the above theorem, Question 3 is equivalent to the following question.

**Question** **4** ([

26], Question 1.3)

**.** Let I be a monomial ideal. Is it true that the inequalities $\mathrm{sdepth}\left(\overline{{I}^{k}}\right)\ge n-\ell \left(I\right)+1$ and $\mathrm{sdepth}(S/\overline{{I}^{k}})\ge n-\ell \left(I\right)$ hold, for every integer $k\gg 0$?Let I be a monomial ideal of S and assume that $\mathrm{sdepth}(S/{I}^{k})\ge n-\ell \left(I\right)$ (resp. $\mathrm{sdepth}\left({I}^{k}\right)\ge n-\ell \left(I\right)+1$), for every integer $k\gg 0$. It follows from Corollary 1 that $\mathrm{sdepth}(S/\overline{{I}^{k}})\ge n-\ell \left(I\right)$ (resp. $\mathrm{sdepth}\left(\overline{{I}^{k}}\right)\ge n-\ell \left(I\right)+1$), for every integer $k\gg 0$. Thus, the answers of Questions 3 and 4 are positive for I. This argument, together with Theorem 2, implies the following result concerning the Stanley depth of integral closure of powers for the complete intersection of monomial ideals.

**Theorem** **12.** Let I be a complete intersection monomial ideal which is minimally generated by t monomials.

- (i)
For every integer $k\ge 1$, we have - (ii)
For every integer $k\ge 1$, we have

Note that in part (ii) of the above theorem, we used the fact that for any complete intersection monomial ideal and any integer $k\ge 1$, the dimension of $S/\overline{{I}^{k}}$ is $n-t$, where t is the number of minimal monomial generators of I.

Restricting to edge ideals, combining the above argument with Theorems 4 and 7 implies the following results.

**Theorem** **13** ([

26], Theorem 3.2)

**.** Let G be a graph, and suppose that p is the number of bipartite connected components of G. Then, for every integer $k\ge 1$, we have $\mathrm{sdepth}(S/\overline{I{\left(G\right)}^{k}})\ge p$. In particular, $S/\overline{I{\left(G\right)}^{k}}$ satisfies Stanley’s inequality for every integer $k\gg 0$.**Theorem** **14** ([

26], Theorem 3.3)

**.** Let G be a non-bipartite graph, and suppose that p is the number of bipartite connected components of G. Then, for every integer $k\ge 1$, we have $\mathrm{sdepth}\left(\overline{I{\left(G\right)}^{k}}\right)\ge p+1$. In particular, $\overline{I{\left(G\right)}^{k}}$ satisfies Stanley’s inequality for every integer $k\gg 0$.Assume that

G is a bipartite graph. We know from ([

13] Theorem 1.4.6 and Corollary 10.3.17) that for any integer

$k\ge 1$, the equality

$I{\left(G\right)}^{k}=\overline{I{\left(G\right)}^{k}}$ holds. Therefore,

$\overline{I{\left(G\right)}^{k}}$ satisfies Stanley’s inequality if, and only if

$I{\left(G\right)}^{k}$ satisfies that inequality. Because of this reason, we exclude the case of bipartite graphs in Theorem 14.

Let

I be a monomial ideal. It is also reasonable to study the depth and the Stanley depth of

$\overline{{I}^{k}}/\overline{{I}^{k+1}}$. In [

26], we proved the following result about the depth of these modules for large

k.

**Theorem** **15** ([

26], Theorem 4.1)

**.** For any nonzero monomial ideal $I\u228aS$, the sequence ${\left\{\mathrm{depth}(\overline{{I}^{k}}/\overline{{I}^{k+1}})\right\}}_{k=0}^{\infty}$ is convergent, and moreover,According to Theorem 15, in order to prove that $\overline{{I}^{k}}/\overline{{I}^{k+1}}$ satisfies Stanley’s inequality, for $k\gg 0$, we must show that $\mathrm{sdepth}(\overline{{I}^{k}}/\overline{{I}^{k+1}})\ge n-\ell \left(I\right)$, for high k.

Let

I be a monomial ideal of

S with

$\mathrm{sdepth}({I}^{k}/{I}^{k+1})\ge n-\ell \left(I\right)$ for every integer

$k\gg 0$, say for

$k\ge {k}_{0}$. We fix an integer

$k\ge 1$. By Corollary 1, there exists an integer

s with

$sk\ge {k}_{0}$ such that

On the other hand, as

$\mathbb{K}$-vector spaces, we have

By the definition of Stanley depth, we conclude that

where the last inequality follows from the assumption. Therefore,

Hence, $\overline{{I}^{k}}/\overline{{I}^{k+1}}$ satisfies Stanley’s inequality for $k\gg 0$. In particular cases, it follows from Theorems 2 and 8 that $\overline{{I}^{k}}/\overline{{I}^{k+1}}$ satisfies Stanley’s inequality, for every integer $k\gg 0$, if I is either a complete intersection monomial ideal or an edge ideal.

Let

I be a normal ideal. By ([

13] Proposition 10.3.2),

Hence, if

${I}^{k}$ and

$S/{I}^{k}$ satisfy Stanley’s inequality for large

k, we must have

In fact, in [

28], we conjectured that the above inequalities hold in a more general setting.

**Conjecture** **3** ([

28], Conjecture 2.6)

**.** Let $I\subset S$ be an integrally closed monomial ideal. Then, $\mathrm{sdepth}(S/I)\ge n-\ell \left(I\right)$ and $\mathrm{sdepth}\left(I\right)\ge n-\ell \left(I\right)+1$.The following example shows that the inequalities of Conjecture 3 do not necessarily hold if I is not integrally closed.

**Example** **4** ([

28], Example 2.5)

**.** Consider the ideal $I=({x}_{1}^{2},{x}_{2}^{2},{x}_{1}{x}_{2}{x}_{3},{x}_{1}{x}_{2}{x}_{4})$ in the polynomial ring $S=\mathbb{K}[{x}_{1},{x}_{2},{x}_{3},{x}_{4}]$. Then, $\ell \left(I\right)=2$. However, $\mathfrak{m}=({x}_{1},{x}_{2},{x}_{3},{x}_{4})$ is an associated prime of $S/I$ and therefore, we conclude from ([30] Proposition 1.3) that $\mathrm{sdepth}(S/I)=0$ and by ([34] Corollary 1.2), $\mathrm{sdepth}\left(I\right)\le 2$. This shows that the inequalities $\mathrm{sdepth}(S/I)\ge n-\ell \left(I\right)$ and $\mathrm{sdepth}\left(I\right)\ge n-\ell \left(I\right)+1$ do not hold for I.As we mentioned in

Section 2, the inequalities of Conjecture 3 are true for any polymatroidal ideal (we know from ([

19] Theorem 3.4) that any polymatroidal ideal is integrally closed)). Also, in ([

35] Corollary 3.4), we verified Conjecture 3 for any squarefree monomial ideal which is generated in a single degree.

We close this section by the following result which permits us to compare the Stanley depth of integral closure of a monomial ideal and its powers.

**Theorem** **16** ([

28], Theorem 2.8)

**.** Let $J\subseteq I$ be two monomial ideals in S. Then, for every integer $k\ge 1$,The following corollary is an immediate consequence of Theorem 16.

**Corollary** **2.** Let $I\subset S$ be a monomial ideal. Then, for every integer $k\ge 1$,and We mention that the inequalities of Corollary 2 remain true if one replaces sdepth with depth, and this has been proved by Hoa and Trung ([

33] Lemma 2.5).

## 4. Symbolic Powers

In this section, we collect the recent results concerning the Stanley depth of symbolic powers of squarefree monomial ideals. We first recall the definition of symbolic powers, and then we continue in two subsections.

**Definition** **4.** Let I be an ideal of S, and let $\mathrm{Min}\left(I\right)$ denote the set of minimal primes of I. For every integer $k\ge 1$, the k-th symbolic power of I, denoted by ${I}^{\left(k\right)}$, is defined to be Let

I be a squarefree monomial ideal in

S, and suppose that

I has the primary decomposition

where each

${\mathfrak{p}}_{i}$ is a prime ideal generated by a subset of the variables of

S. It follows from ([

13] Proposition 1.4.4) that for every integer

$k\ge 1$,

#### 4.1. Asymptotic Behavior of Stanley Depth of Symbolic Powers

Let

I be a squarefree monomial ideal. As we mentioned in

Section 2, based on the limit behavior of depth of powers of

I, Herzog [

6] conjectured that the Stanley depth of

$S/{I}^{k}$ is constant for large

k (see Conjecture 1). On the other hand, it is known that if one replaces the ordinary powers by symbolic powers, then again the depth function stabilizes. In fact, Hoa, Kimura, Terai, and Trung [

36] are even able to compute the limit value of this function. In order to state their result, we need the following definition.

**Definition** **5.** Suppose I is a squarefree monomial ideal, and let ${\mathcal{R}}_{s}\left(I\right)={\u2a01}_{k=0}^{\infty}{I}^{\left(k\right)}$ be the symbolic Rees ring of I. The Krull dimension of ${\mathcal{R}}_{s}\left(I\right)/\mathfrak{m}\mathcal{R}\left(I\right)$ is called the symbolic analytic spread of I and is denoted by ${\ell}_{s}\left(I\right)$.

Let

I be a squarefree monomial ideal. Varbaro ([

37] Proposition 2.4) showed that

In [

36], Hoa, Kimura, Terai, and Trung proved that the minimum and the limit of the sequence

${\left\{\mathrm{depth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ coincide. Indeed, they showed the following stronger result. In the following theorem,

$\mathrm{bight}\left(I\right)$ denotes the maximum height of associated primes of

I.

**Theorem** **17** ([

36], Theorem 2.4)

**.** Let I be a squarefree monomial ideal of S. Then, $\mathrm{depth}(S/{I}^{\left(k\right)})=n-{\ell}_{s}\left(I\right)$, for every integer $k\ge n(n+1)\mathrm{bight}{\left(I\right)}^{n/2}$.As the depth function of symbolic powers of a squarefree monomial ideal is eventually constant, one may ask whether the same is true for the Stanley depth—or in other words, whether an analogue of Conjecture 1 is true, if one replaces the ordinary power with a symbolic power. In [

38], we gave a positive answer to this question. In fact, we have something more—first, we will see in the following theorem that one can compare the Stanley depth of certain symbolic powers of a squarefree monomial ideal.

**Theorem** **18** ([

38], Theorem 4.2)

**.** Let $I\subset S$ be a squarefree monomial ideal. Suppose that m and k are positive integers. Then, for every integer j with $m-k\le j\le m$, we haveWe recall that in the special case of

$j=m$, the inequalities of Theorem 18 were also proved in ([

39] Corollary 3.2). We also mention that the assertions of Theorem 18 are true if one replaces sdepth with depth, and this was proved independently by Nguyen and Trung ([

40] Theorem 2.7), Montaño and Núñez-Betancourt ([

41] Theorem 3.4), and the author ([

38] Theorem 3.3).

As an immediate consequence of Theorem 18, we obtained the following result.

**Corollary** **3** ([

38], Corollary 4.3)

**.** For every squarefree monomial ideal $I\subset S$, we haveandAssume that

I is a squarefree monomial ideal, and set

Let

$t\ge 1$ be the smallest integer with

$\mathrm{sdepth}(S/{I}^{\left(t\right)})=m$. If

$t=1$, then by Theorem 18, for every integer

$k\ge 1$, we have

$\mathrm{sdepth}(S/{I}^{\left(k\right)})=m$. Now, suppose

$t\ge 2$. Again, by Theorem 18, we have

$\mathrm{sdepth}(S/{I}^{({t}^{2}-t)})=m$. For every integer

$k>{t}^{2}-t$, we write

$k=st+j$, where

s and

j are positive integers and

$1\le j\le t$. As

$k>{t}^{2}-t$, we conclude that

$s\ge t-1$. It then follows from Theorem 18 that

By the choice of

m, we conclude that for every integer

$k\ge {t}^{2}-t$, the equality

$\mathrm{sdepth}(S/{I}^{\left(k\right)})=m$ holds. Therefore, the sequence

${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ is convergent and

Similarly, one proves that the sequence

${\left\{\mathrm{sdepth}\left({I}^{\left(k\right)}\right)\right\}}_{k=1}^{\infty}$ is convergent and

Therefore, we have the following result.

**Theorem** **19** ([

38], Theorem 4.4)

**.** For every squarefree monomial ideal I, the sequences ${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ and ${\left\{\mathrm{sdepth}\left({I}^{\left(k\right)}\right)\right\}}_{k=1}^{\infty}$ are convergent. Moreover,andA squarefree monomial ideal I is called normally torsionfree, if ${I}^{\left(k\right)}={I}^{k}$, for every integer $k\ge 1$. It is immediate from Theorem 19 that for any normally torsionfree squarefree monomial ideal I, the sequences ${\left\{\mathrm{sdepth}(S/{I}^{k})\right\}}_{k=1}^{\infty}$ and ${\left\{\mathrm{sdepth}\left({I}^{k}\right)\right\}}_{k=1}^{\infty}$ are convergent. In particular, Conjecture 1 is true for normally torsionfree squarefree monomial ideals.

Let

I be a squarefree monomial ideal. The smallest integer

$t\ge 1$, such that

$\mathrm{depth}(S/{I}^{m})={lim}_{k\to \infty}\mathrm{depth}(S/{I}^{k})$ for all

$m\ge t$, is called the

index of depth stability of powers of

I, and is denoted by

$\mathrm{dstab}\left(I\right)$. Similarly, one can define the

index of depth stability of symbolic powers by replacing the ordinary powers with symbolic powers. The index of depth stability of symbolic powers is denoted by

${\mathrm{dstab}}_{s}\left(I\right)$. By Theorem 17, we have

According to Theorem 19, one can also define the

indices of sdepth stability of symbolic powers, that is,

We also defined the following quantities:

The argument before Theorem 19 also proves the following proposition.

**Proposition** **1** ([

38], Corollary 4.5)

**.** For every squarefree monomial ideal $I\subset S$, we haveandAs we mentioned above, the assertions of Theorem 18 are true also for the depth. Thus, a similar argument, as we explained before Theorem 19, implies that the inequalities of Proposition 1 remain true, if one replaces Stanley depth with depth. This has been already observed in ([

38] Theorem 3.6).

Let I be a squarefree monomial ideal. We know from Theorem 19 that the sequences ${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ and ${\left\{\mathrm{sdepth}\left({I}^{\left(k\right)}\right)\right\}}_{k=1}^{\infty}$ are convergent. Now, it is natural to ask the following question.

**Question** **5.** Let I be a squarefree monomial ideal. How can one describe the limits of the sequences ${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ and ${\left\{\mathrm{sdepth}\left({I}^{\left(k\right)}\right)\right\}}_{k=1}^{\infty}$?

Question 5 is widely open. We know the answer only for very special classes of ideals. For example, assume that

I is a squarefree complete intersection monomial ideal. It is easy to check that for any integer

$k\ge 1$, the equality

${I}^{\left(k\right)}={I}^{k}$ holds. Therefore, using Theorem 2, we conclude that

and

where

t is the number of minimal monomial generators of

I (which is also equal to

${\ell}_{s}\left(I\right)$).

We are also able to compute the limit of the sequence ${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$, where I is the Stanley-Reisner ideal of a matroid. We first recall some basic definitions from the theory of Stanley-Reisner rings.

A

simplicial complex $\Delta $ on the set of vertices

$V(\Delta )=\left[n\right]:=\{1,\dots ,n\}$ is a collection of subsets of

$\left[n\right]$ which contains

$\left\{i\right\}$ for any

$i\in \left[n\right]$, and is closed under taking subsets; that is, if

$F\in \Delta $ and

${F}^{\prime}\subseteq F$, then also

${F}^{\prime}\in \Delta $. Every element

$F\in \Delta $ is called a

face of

$\Delta $. The

dimension of a face

F is defined to be

$\left|F\right|-1$. The

dimension of

$\Delta $ which is denoted by

$dim\Delta $, is defined to be

$d-1$, where

$d=max\left\{\right|F|\mid F\in \Delta \}$. The

Stanley-Reisner ideal of

$\Delta $ is defined as

**Definition** **6.** A simplicial complex Δ is called matroid if, for every pair of faces $F,G\in \Delta $ with $\left|F\right|>\left|G\right|$, there is a vertex $x\in F\setminus G$ such that $G\cup \left\{x\right\}$ is a face of Δ.

As we mentioned above, there is some information about the limit of the Stanley depth function of symbolic powers of the Stanley-Reisner ideal of a matroid.

**Theorem** **20** ([

38], Theorem 4.7)

**.** Let Δ be a matroid. Then,and#### 4.2. Cover Ideals

Let

G be a graph with vertex set

$V\left(G\right)=\left\{{x}_{1},\dots ,{x}_{n}\right\}$. A subset

C of

$V\left(G\right)$ is called a

vertex cover of

G if every edge of

G is incident to at least one vertex of

C. A vertex cover

C is called a

minimal vertex cover of

G if no proper subset of

C is a vertex cover of

G. The

cover ideal of

G is a squarefree monomial ideal of

S which is defined as

It is easy to see that the cover ideal is the Alexander dual of the edge ideal, that is,

Let I be a squarefree monomial ideal. In Question 1, we asked whether ${I}^{k}$ and $S/{I}^{k}$ satisfied Stanley’s inequality for every integer $k\gg 0$. One can also ask the similar question for symbolic powers.

**Question** **6** ([

7], Question 1.2)

**.** Let I be a monomial ideal. Is it true that ${I}^{\left(k\right)}$ and $S/{I}^{\left(k\right)}$ satisfy Stanley’s inequality for every integer $k\gg 0$?In this subsection, we investigate the above question for cover ideals. By Theorem 17, in order to know whether the high symbolic powers of cover ideals satisfy Stanley’s inequality, we need to compute their symbolic analytic spread. This has been done by Constantinescu and Varbaro [

42]. Indeed, they provide a combinatorial description for the symbolic analytic spread of

$J\left(G\right)$. To state their result, we need to recall some notions from the graph theory.

Let G be a graph. A matching in G is a set of edges such that no two different edges share a common vertex. A subset W of $V\left(G\right)$ is called an independent subset of G if there are no edges among the vertices of W. Let $M=\{\{{a}_{i},{b}_{i}\}\mid 1\le i\le r\}$ be a nonempty matching of G. We say that M is an ordered matching of G if the following conditions hold.

- (1)
$A:=\{{a}_{1},\dots ,{a}_{r}\}$ is an independent subset of vertices of G, and

- (2)
$\{{a}_{i},{b}_{j}\}\in E\left(G\right)$ implies that $i\le j$.

The

ordered matching number of

G, denoted by

${\nu}_{o}\left(G\right)$, is defined to be

**Theorem** **21** ([

42], Theorem 2.8)

**.** For any graph G,As a consequence of Theorems 17 and 21, for any graph

G with

n vertices, we have

Hoa, Kimura, Terai, and Trung [

36], determined a linear upper bound for the index of depth stability of symbolic powers of cover ideals. In [

7], we provided an alternative proof for their result.

**Theorem** **22** ([

36], Theorem 3.4 and [

7], Theorem 3.1)

**.** Let G be a graph with n vertices. Then, for every integer $k\ge 2{\nu}_{o}\left(G\right)-1$, we haveIn [

7], we also proved that high symbolic powers of cover ideals satisfy Stanley’s inequality. Indeed, we proved the following result.

**Theorem** **23** ([

7], Theorem 3.5 and Corollary 3.6)

**.** Let G be a graph with n vertices. Then, for every integer $k\ge 1$, we haveIn particular, $J{\left(G\right)}^{\left(k\right)}$ and $S/J{\left(G\right)}^{\left(k\right)}$ satisfy the Stanley’s inequality, for every integer $k\ge 2{\nu}_{o}\left(G\right)-1$.

The assertions of Theorem 23 for the special case of bipartite graphs was also proved in [

43].

Let G be a graph with n vertices. We say G is very well-covered if n is an even integer and moreover, every vertex cover of G has size $n/2$. The graph G is called Cohen-Macaulay if the ring $S/I\left(G\right)$ is Cohen-Macaulay. We know from Theorem 23 that for any graph G, the modules $J{\left(G\right)}^{\left(k\right)}$ and $S/J{\left(G\right)}^{\left(k\right)}$ satisfy Stanley’s inequality for $k\gg 0$. However, in the case of Cohen-Macaulay very well-covered graphs, we have something more.

**Proposition** **2** ([

44], Corollary 3.8)

**.** Let G be a Cohen-Macaulay very well-covered graph. Then, $J{\left(G\right)}^{\left(k\right)}$ and $S/J{\left(G\right)}^{\left(k\right)}$ satisfy Stanley’s inequality for every integer $k\ge 1$.In Question 5, we asked about the limit values of the sequences ${\left\{\mathrm{sdepth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ and ${\left\{\mathrm{sdepth}\left({I}^{\left(k\right)}\right)\right\}}_{k=1}^{\infty}$, where I is a squarefree monomial ideal. For the case of cover ideals, we pose the following conjecture.

**Conjecture** **4.** Let G be a graph with n vertices. Then,and Let

I be a squarefree monomial ideal. According to Theorem 17, the sequence

${\left\{\mathrm{depth}(S/{I}^{\left(k\right)})\right\}}_{k=1}^{\infty}$ is convergent. The situation is even better if

I is a cover ideal. In fact, Hoa, Kimura, Terai, and Trung ([

36] Theorem 3.2) proved that the above sequence is non-increasing for cover ideals. In other words, for every graph

G and any integer

$k\ge 1$, we have

We recall that the above inequality for bipartite graphs was also proved in ([

45] Theorem 3.2).

We close this article by mentioning that the above inequality is true if one replaces depth with sdepth. In fact, we have the following result.

**Theorem** **24** ([

7], Theorem 3.3)

**.** Let G be a graph. Then, for every integer $k\ge 1$, we have:- (i)
$\mathrm{sdepth}(S/J{\left(G\right)}^{\left(k\right)})\ge \mathrm{sdepth}(S/J{\left(G\right)}^{(k+1)})$, and

- (ii)
$\mathrm{sdepth}\left(J{\left(G\right)}^{\left(k\right)}\right)\ge \mathrm{sdepth}\left(J{\left(G\right)}^{(k+1)}\right)$.