2. Preliminaries
In what follow we use the notation of [
2] (Chapter 5). Let
be a ring of subsets of a nonempty set
,
be the characteristic function of the set
and let
denote the linear space of all
-valued
-simple functions,
being the scalar field of real or complex numbers. Since
and
whenever
, for each
there are pairwise disjoint sets
and nonzero
, with
if
such that
, with
if
. Unless otherwise stated we shall assume
equipped with the norm
. If
is the absolutely convex hull of
, an equivalent norm is defined on
by the
gauge of
Q, namely
. For if
with
, it can be shown that
(
cf. [
2] (Proposition 5.1.1)), hence
.
The dual of
is the Banach space
of bounded finitely additive scalar-valued measures on
, which we shall assume to be equipped with the variation norm
where the supremum is taken over all finite sequences of pairwise disjoint members of
. This is the dual of the supremum-norm
of
. An equivalent norm is given by
, which is the dual norm of the gauge
. We shall also consider the Banach space
equipped with the bidual norm
of
. The completion of the normed space
is the Banach space
of all bounded
-measurable functions.
The Banach space embeds isometrically into , hence each characteristic function in with can be considered as a bounded linear functional on defined by evaluation . So, we may write , where stands for the unit sphere of , and the set , regarded as a topological subspace of , is the same as regarded as a topological subspace of .
A subfamily
of an algebra of sets
is called a
Nikodým set for
(
cf. [
3]) if each set
in
which is pointwise bounded on
is bounded in
, i.e., if
for each
implies that
. The algebra
is said to have
property if the whole family
is a Nikodým set for
. Nikodým’s classic boundedness theorem establishes that every
-algebra has property
. An algebra
is said to have
property if
is a Grothendieck space, i.e., if each weak* convergent sequence in
is weakly convergent in the Banach space
. The fact that every
-algebra has property
is also due to Grothendieck. Every countable algebra lacks property
, and the algebra
of Jordan-measurable subsets of the real interval
has property
but fails property
(
cf. [
4] (Propositions 3.2 and 3.3) and [
5]). Let us recall that a sequence
in
is
uniformly exhaustive if for each sequence
of pairwise disjoint elements of
it holds that
. We shall use the following result, originally stated in [
4] (2.3 Definition).
Theorem 1. An algebra of sets has property if and only if every bounded sequence in which converges pointwise on is uniformly exhaustive.
An algebra
is said to have
property if every sequence
in
which converges pointwise on
is uniformly exhaustive. It should be mentioned that
, where the proof of the non-trivial implication can be found in [
6] (see also [
7] (Theorem 4.2)). For later use we introduce the following definition.
Definition 1. A subfamily of an algebra of sets will be called a Grothendieck set for if each sequence in which is pointwise convergent on is weakly convergent in , i.e., if there is such that for every then weakly in .
If an algebra contains a Grothendieck subset for , clearly has property . Grothendieck sets are closely related to the so-called Rainwater sets (defined below) for , and the study of the Rainwater sets for leads to Theorem 4 below, from which the following result is a straightforward corollary.
Theorem 2. If Σ is a σ-algebra of subsets of a set Ω which is covered by an increasing sequence of subsets of Σ there exists such that is a Grothendieck set for .
Indeed, in [
1] (Theorem 1) Valdivia showed that if a
-algebra
of subsets of a set
is covered by an increasing sequence
of subsets (subfamilies) of
, there exists some
such that
is a Nikodým set for
or, equivalently, that given an increasing sequence
of linear subspaces of
covering
, there exists
such that
is dense and barrelled (see also [
8] (Theorem 3)).
As a consequence of Theorem 4 we show that if a
-algebra
is covered by an increasing sequence
of subsets, there exists some
such that
, regarded as a subset of the dual unit ball of
, is also a Rainwater set for
. This easily implies Theorem 2. In the last section we give some applications of Theorem 2 to classic Banach space theory which seems to have gone unnoticed so far. Let us point out that some results of this paper hold for Boolean algebras [
9] (Theorem 12.35).
3. Rainwater Sets for
A subset
X of the dual closed unit ball
of a Banach space
E is called a
Rainwater set for
E if every
bounded sequence
of
E that converges pointwise on
X, i.e., such that
for each
, converges weakly in
E (
cf. [
10]). Rainwater’s classic theorem [
11] asserts that the set of the extreme points of the closed dual unit ball of a Banach space
E is a Rainwater set for
E. According to [
12] (Corollary 11), each
James boundary of
E is a Rainwater set for
E. As regards the Banach space
of real-valued continuous functions over a
compact Hausdorff spaceX equipped with the supremum norm, if
is the set of the extreme points of the compact subset
of
, the Arens-Kelly theorem asserts that
(see [
13]). By the Lebesgue dominated convergence theorem, if
is a norm-bounded sequence in
(with respect to the supremum-norm) then
weakly in
if and only if
for every
, that is,
for every
if and only if
for each
(see [
14] (IV.6.4 Corollary)). This is Rainwater’s theorem for
. In [
10] the weak
K-analyticity of the Banach space
of real-valued continuous and bounded functions defined on a completely regular space
X equipped with the supremum norm is characterized in terms of certain Rainwater sets for
. The next theorem, based on [
3] (Proposition 4.1), exhibits a connection between Rainwater sets and property
. We include it for future reference and provide a proof for the sake of completeness.
Theorem 3. Let be an algebra of sets. The following are equivalent
- 1.
has property .
- 2.
is a Rainwater set for , considered as a subset of .
- 3.
The unit ball of is a Rainwater set for .
- 4.
The unit ball of is a Rainwater set for .
Proof. . Assume that
has property
and let
be a bounded sequence in
and
such that
for each
. i.e., such that
for each
. By Theorem 1 the sequence
is (bounded and) uniformly exhaustive on
, so [
15] (Corollary 5.2) produces a nonnegative real-valued finitely-additive measure
on
such that
. Hence, [
14] (4.9.12 Theorem]) shows that
M is relatively weakly sequentially compact. Given that
for each
, necessarily
is the only possible weakly adherent point of the sequence
. So we get that
weakly in
, which shows that
is a Rainwater set for
.
. If denotes the second dual ball of the closed unit ball of and stands for the unit ball of , from the relations it follows that is a also Rainwater set for .
is obvious.
. If in under the weak* topology of then is a bounded sequence in . Given that for every and given the hypothesis that is a Rainwater set for , we have that weakly in . Consequently has property . □
Example 1. Ifstands for the algebra generated by the sets of density zero in, thenis not a Rainwater set for. This follows from the previous theorem and from the fact that does not have property (
see [16]).
Theorem 4. Assume that is an algebra of sets. Let be a Nikodým subset for and let be an increasing covering of by subsets of . If is a Rainwater set for , there exists some such that is a Rainwater set for .
Proof. Assume that
is a Rainwater set for
. First we claim that
Let us proceed by contradiction. Assume otherwise that there exists
such that
for all
. In this case the separation theorem provides
with
such that
So, in particular it holds that
for every
. If
there is
such that
for every
. Consequently
for
, which shows that
. Since
is a Nikodým set and
is pointwise bounded on
, it follows that
is bounded in
. So, the fact that
for all
along with the assumption that
is a Rainwater set leads to
weakly in
. This is a contradiction, since
for every
. The claim is proved.
Set
. Since we are assuming that
is a Nikodým set for
, the larger set
is also a Nikodým set for
, which implies that
is a metrizable barrelled space, hence a Baire-like space (see [
17]). On the other hand, as a consequence of the previous claim, the family
with
is an increasing sequence of closed absolutely convex sets covering
. So, there exists
such that
which shows that
is a Rainwater set for
.
We claim that this implies that
is a Rainwater set for
. In order to establish the claim it suffices to show that
is a Rainwater set for
. So, let
be a bounded sequence in
such that
for every
. Let us show that
for each
. If
there exists a sequence
in
such that
. Consequently, given
there is
with
Let
be such that
for every
. Consequently, one has
for all
. This proves that
for each
. Since we have shown before that
is a Rainwater set for
, we get that
weakly in
. Therefore the absolutely convex set
is a Rainwater set for
, a stated. □
Corollary 1. Let be an algebra of sets with property . If is an increasing covering of consisting of subsets of , there is some such that is a Rainwater set for .
Proof. This is a straightforward consequence of the Theorem 4 for
, since as mentioned earlier an algebra
has property
if and only if
has both properties
and
(this also can be found in [
7] (Theorem 4.2)). So, on the one hand
is a Nikodým set for
and, on the other hand, according to Theorem 3, the family
is a Rainwater set for
. □
Proof of Theorem 2. If
is a
-algebra of subsets of a set
which is covered by an increasing sequence
of subsets of
, Corollary 1 and Valdivia’s result [
1] provide an index
such that
is a Nikodým set for
at the same time that
is a Rainwater set for
. If
verifies that
for every
, the sequence
is bounded in
since
is a Nikodým set for
. But then
weakly in
due to
is a Rainwater set for
. Consequently
is a Grothendieck for
and we are done. □
Corollary 2. If is an increasing sequence of subsets of covering , there exists some such that each sequence in that converges pointwise on converges weakly in .
Proof. Apply Theorem 2 to the -algebra . □
We complete our study of Rainwater sets for with the following result. Note that if (weak* closure) with is a Rainwater set for then X could not be a Rainwater set for . However the following property holds.
Theorem 5. Let be an algebra of sets. Assume that is a Grothendieck set for . If is a -dense subset of under the relative weak* topology of or, which is the same, under the relative weak topology of , then is a Grothendieck set for .
Proof. Let be a sequence in such that for every . Given , let us define . Then one has that , so that is a nonempty intersection of countably many zero-sets of , hence a non-empty -set in in the relative weak topology of . According to the hypothesis G meets . Hence there exists such that , which means that for every . Since , it follows that . So, we conclude that for every . Putting together that is a Grothendieck set for , and for all , we get that weakly in . Thus is a Grothendieck set for . □