1. Introduction
In this paper, we consider that all graphs are simple, undirected and connected. A graph is said to be planar if it can be embedded in a plane such that its edges intersect only at their endpoints. Let G be a planar graph. We denote by ,  and  the vertex set, the edge set and the face set, respectively. The degree of a vertex  is the number of edges associated with v, and written as . A vertex with a degree of exactly k, at least k and at most k is referred to as a k-vertex, -vertex and -vertex, respectively. Specifically, if , then v is called a leaf. Moreover, the maximum degree of G, denoted by , is defined as . In turn, the minimum degree of G, denoted by , is defined as . The maximum average degree  of a graph G is the maximum of the average degrees of its subgraphs. For a face , the degree of f, denoted by , is defined as the number of edges on the boundary of f, and the definition of a k-, -, or -face is similar to that of the corresponding vertex. A cycle of length  in G is called a k-cycle, and the minimum length among all k-cycles is known as the girth of G, denoted by . Additionally, a graph G is normal if it has no isolated edges.
A 
proper k-total coloring of a graph is a mapping from 
k colors to its vertices and edges such that no two incident elements receive the same colors. In recent years, neighbor sum distinguishing total coloring of graphs as a constrained 
k-total coloring was first introduced by Pilśniak and Woźniak [
1] in 2015, which has received much attention. A proper 
k-total coloring 
 of a graph 
G is said to be a 
neighbor sum distinguishing total coloring if 
 for any 
, where 
 for each 
, and the minimal number 
k of such coloring is called 
neighbor sum distinguishing total chromatic number, denoted by 
. Moreover, they also proposed the conjecture below.
Conjecture 1 ([
1]). 
Let G be a graph of order at least 2. Then,  Meanwhile, they showed that Conjecture 1 is valid for various classes of graphs, including complete graphs, cubic graphs, and so on. Subsequently, many results have been achieved in the study of neighbor sum distinguishing total coloring on planar graphs. In 2016, Qu et al. [
2] obtained that 
 for a planar graph 
G. Later, Wang et al. [
3] confirmed the validity of Conjecture 1 for planar graphs without containing 4-cycles, and then, Wang et al. [
4] further proved that if planar graph 
G contains no adjacent triangles and 
, then 
. In the same year, Ge et al. [
5] showed that 
 if planar graph 
G does not contain 5-cycles. In 2022, Nakprasit et al. [
6] proved that 
 for a planar graph 
G without 4-cycles adjacent to 3-cycles and 
. In 2023, Huang et al. [
7] verified that for any graph 
G with 
, 
. Additionally, they provided a characterization of the neighbor sum distinguishing total chromatic number for graphs satisfying 
 and 
. In 2024, Du et al. [
8] presented two significant results regarding planar graph 
G. The first one is that if 
G has no 3-cycles adjacent to 4-cycles with 
 and without cut edges, then 
. The second is that if 
G has no 4-cycles intersecting with 6-cycles and 
, then 
. Just recently, Duan et al. [
9] verified that 
 for planar graph 
G without intersecting 4-cycles.
In 2017, Flandrin [
10] extended the definition of neighbor sum distinguishing total coloring by incorporating the colors of adjacent vertices to form the notion of 
full sum, and introduced the concept of 
neighbor full sum distinguishing total coloring of graphs. For a graph 
G, suppose 
 is a proper 
k-total coloring of 
G. For each vertex 
, let 
 and 
. Furthermore, if 
 for any 
, then 
 is termed a 
neighbor full sum distinguishing k-total coloring of 
G, abbreviated as 
k-NFSDTC of 
G. The smallest integer 
k for which a neighbor full sum distinguishing 
k-total coloring exists in 
G is referred to as the 
neighbor full sum distinguishing total chromatic number of 
G, simplified as 
. Cheng et al. [
11] provided an insight for the neighbor full sum distinguishing total coloring through two specific types of Halin graphs. In 2023, Cui et al. [
12] proposed Conjecture 2 and validated it for graphs such as paths, cycles, stars, wheels, complete bipartite graphs, complete graphs and trees.
Conjecture 2 ([
12]). 
If G is a normal graph, then . Recently, Yue et al. showed in [
13] that 
 if 
G is a normal planar graph with 
 and 
. Inspired by Conjecture 2, we extend the result of [
13] under the condition 
 in some sense.
Theorem 1. Let G be a normal planar graph with  and . Then,    2. Demonstration of Main Result
At first, we present some lemmas to be utilized in the subsequent proof.
Lemma 1 ([
12]). 
For , suppose  is a star of order . Then, . Lemma 2 ([
14]). 
Let  and  be the sets of integers, with  and . Let . Then, . Moreover, if , then . By the definition of neighbor full sum distinguishing total coloring, it is evident that Lemma 3 always holds.
Lemma 3. For a graph G, let u be a vertex of degree at least 2 in G. If v is a leaf neighbor of u, then .
 Proof of Theorem 1.  Suppose that 
G is a normal planar graph. For a vertex 
v of 
G, we denote by 
 the number of neighbors of 
v that are not leaves, and 
 the quantity of neighbors of 
v with degree 
k in 
G. If 
, then 
v is called a 
good 2-vertex when 
, otherwise, it is called a 
bad 2-vertex (i.e., 
). Let 
 be the quantity of bad 2-vertices neighboring 
v in 
G. For a face 
f of 
G, let 
 be the number of vertices with degree 
k that are incident to 
f. In addition, 
Figure 1 illustrates a part of the reducible configurations of 
G originated from the proof. In these configurations, solid dots denote vertices with specified degrees, whereas hollow dots indicate vertices whose degrees remain unspecified.
 To proceed a proof by contradiction, assume that G is a minimal counterexample to Theorem 1 with the minimal . It is evident that G is connected due to the minimality. Let  be a proper normal subgraph of G. Then,  has a -NFSDTC, denoted by . For each vertex , let  denote the full sum of x under the coloring . In what follows, we drive some claims by extending  to be a -NFSDTC  of G to contradict the minimality of G.
Claim 1. No -vertex is adjacent to a leaf in G.
 Proof.  Without loss of generality, assume that there exists a 4-vertex v adjacent to a leaf . Let ,  and  be the neighbors of v other than , and . Then, from the minimality of G,  has a -NFSDTC . From the principles of proper total coloring, we have , which means that there are 4 forbidden colors for  at most. Thus,  has at least  feasible colors. Likewise,  has at least  feasible colors. By Lemma 2, it follows that there are at least 42 different values for . Hence,  also has at least 42 distinct values. Therefore, there must exist a value for  such that ,  and . In addition, by Lemma 3, we have . Consequently, G has a -NFSDTC , which contradicts the minimality of G.    □
 The following Claims 2 and 3 can be found in [
13], so we omit their proof here.
Claim 2 ([
13], Claim 2).
             
There is no 2-vertex adjacent to two other 2-vertices in G. Claim 3 ([
13], Claim 3).
            
There is no 2-vertex adjacent to a 3-vertex in G. Claim 4. 3-vertex has at most one neighbor of degree 3 in G.
 Proof.  Assume that there exists a 3-vertex 
v adjacent to two 3-vertices in 
G. Let 
 be the neighbors of 
v with 
, as shown in the structure 
 in 
Figure 1. Let 
 and 
 be the neighbors of 
 other than 
v, and 
 and 
 be the neighbors of 
 other than 
v. The other neighbors of 
 excluding 
v are denoted by 
 for 
, where 
. Let 
. Then, by the minimality of 
G, there exists a 
-NFSDTC 
 for 
. We now color the vertex 
v and its incident edges.
Assume, without loss of generality, that . From the principles of proper total coloring, we have ; this indicates that the edge  has  forbidden colors and 3 feasible colors. Likewise, v has  feasible colors since . By Lemma 2, it follows that  has at least  different values, and thus,  also has at least  different values. Therefore, there exists a value for  yielding  with .
Next, we consider the distinguishability of the full sums at  and  with their neighbors, as well as  and v. Based on the previous discussion above,  and  have already been determined. Then, by the principles of proper total coloring, , , which means that the edge  has  feasible colors. Similarly, . This implies that the edge  has  feasible colors. Furthermore, from the definition of neighbor full sum distinguishing total coloring, at most, one feasible color for  will cause , leaving  feasible colors for . Thus,  could take at least 18 different values, and so, there exists a value for  such that  and .
At this point,  has also been determined. From the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for  that leads to , and at most one leading to . So, this leaves  feasible colors for . Therefore,  also has at least 18 distinct values, guaranteeing a choice that satisfies  and . Thus, G admits a -NFSDTC , which contradicts the minimality of G.    □
 Claim 5. There is no 2-vertex adjacent to a 4-vertex in G.
 Proof.  Assume that there exists a 2-vertex 
u adjacent to a 4-vertex 
v in 
G. Let 
 be the neighbor of 
u distinct from 
v. Let 
, 
 and 
 be the neighbors of 
v other than 
u, as shown in the reducible configuration 
 depicted in 
Figure 1. Let 
. Then, by the minimality of 
G, 
 admits a 
-NFSDTC 
. Next, we will color the vertex 
u and its removal edges.
Assume, without loss of generality, that , and  are the neighbors of  distinct from v, where . From the principles of proper total coloring, we have . Therefore, the edge  has  forbidden colors and 3 feasible colors. Likewise, ∉, ; this means that u has  feasible colors. Meanwhile, , and thus, the edge  has  feasible colors. From the definition of neighbor full sum distinguishing total coloring, there is at most one color from the feasible colors for  that results in . Analogously, there exists at most one color among the feasible colors for  that results in . Consequently,  possesses 2 remaining feasible colors, while  has  remaining feasible colors. Note that u has at least  feasible colors. Hence, it follows from Lemma 2 that  would obtain at least  different values, and thus,  also has  different values at least. Therefore, there must exist a value for  such that  with  simultaneously.
Next, we consider the distinguishability of the full sum for v and its neighbors ,  and . Based on the previous analysis concerning  for , the color  is now determined. Given that , there are at least  different values feasible for . Hence,  also takes at least 18 different values; this means that there exists a value for  yielding  with . Thus, G admits a -NFSDTC , which contradicts the minimality of G.    □
 Claim 6. A -vertex is adjacent to at least 4 non-leaf neighbors. Moreover, if the -vertex is adjacent to precisely 4 non-leaf neighbors, then it does not have a 2-vertex as its neighbor in G.
 Proof.  Firstly, we show that any -vertex v is adjacent to at least 4 non-leaf neighbors in G. Assume by a contradiction that v has at most three non-leaf neighbors. For convenience, we write  as the leaf neighbors of v, and  as its non-leaf neighbors, where  and .
When , v has no non-leaf neighbors, which implies that G is a star. Therefore, from Lemma 1, G admits a -NFSDTC , which contradicts the minimality of G.
Without loss of generality, suppose that v has three non-leaf neighbors, ,  and . Then,  at this moment. This means that v has at least two leaves. Let . Then, by the minimality of G, there exists a -NFSDTC  for . From the principles of proper total coloring,  has at least  feasible colors since . Similarly,  has at least  feasible colors. By Lemma 2, we have that  owns at least 24 distinct values; this implies that  also takes at least 24 distinct values. So, there must exist a value for  satisfying . Furthermore, by Lemma 3, we have  (). Thus, G admits a -NFSDTC  extended from , contradicting the minimality of G.
Next, we will prove that for any -vertex v in G, if , then . Assume that there exists a -vertex v (say, briefly) with  adjacent to a 2-vertex . Let  for  denote the leaves of v, and  denote the non-leaf neighbors of v. Let . Then, by the minimality of G, there exists a -NFSDTC  for . From the principles of proper total coloring, ∉, . Thus,  should have at most  forbidden colors, leaving at least  feasible colors. Likewise,  obtains at least  feasible colors. Hence, by Lemma 2, we see that  has at least 24 distinct values, which yields that  also has at least 24 distinct values. Therefore, there must exist a value for  such that . It further follows by Lemma 3 that  with . Consequently, G admits a -NFSDTC  extended from , which contradicts the minimality of G.    □
 Claim 7. No -vertex v with  has at least two 2-vertices in G.
 Proof.  Suppose that G has a -vertex v with  having two neighbors of degree 2, e.g.,  and . Let  denote the leaves of v with . For convenience, we write ,  and  as the other three non-leaf neighbors of v.
Case 1..
Here, 
. This indicates that 
v is not a leaf, as depicted by the structure 
 in 
Figure 1. Let 
. Then, by the minimality of 
G, there exists a 
-NFSDTC 
 for 
. Let 
 be the other neighbor of 
, differing from 
v. We now color the vertex 
 and its incident edges.
Assume, without loss of generality, that . Let  for  be the neighbors of  differ from . From the principles of proper total coloring, . Therefore,  has  forbidden colors and 3 feasible colors. Similarly, ; thus,  has  feasible colors. Furthermore, ∉, , , , ,  and . Hence,  has  feasible colors. According to the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for  such that . Similarly  has at most one feasible color resulting in . As a result,  has 2 remaining feasible colors, and  has  remaining colors. Since  has  feasible colors, from Lemma 2,  would take at least  distinct values. This implies that  also takes at least  different values. Thus, there exists a value for  satisfying  with .
We next consider the full sum distinguishability of vertex v with its neighbors , ,  and . From the analysis of  above, for ,  is now defined. Since ,  has at least  distinct values. This indicates that  also takes at least 17 different values. Consequently, one can find a value for  yielding  where . Consequently, G admits a -NFSDTC  extended from , contradicting the minimality of G.
Case 2. .
At this moment, . This indicates that v has at least one leaf. Let . Then, by the minimality of G,  admits a -NFSDTC . From the principles of proper total coloring, the edge  possesses  feasible colors, and vertex  possesses  feasible colors. Thus,  would take at least 23 distinct values, which means that  also takes at least 23 different values. Hence, there must exist a value for  satisfying  for . Furthermore, by Lemma 3, we have  for . Therefore, one can obtain a -NFSDTC  of G by extending , contradicting the minimality of G.    □
 Claim 8. No -vertex v with  is adjacent to at least four 2-vertices, in which at least one neighbor is a bad 2-vertex.
 Proof.  Suppose that G has a -vertex v with  adjacent to at least four 2-vertices. Let  be the non-leaf neighbors of v, and let  be the leaf neighbors of v, where  and .
Firstly, we will show that . Suppose that . The proof will proceed by concerning the value of .
Case 1. .
Here, 
, this indicates that 
v is not adjacent to the leaf, as illustrated in the structure 
 in 
Figure 1. Let 
. Then, from the minimality of 
G, there is a 
-NFSDTC 
 in 
. Let 
 denote the other neighbors of 
 differ from 
v. We now assign colors to the vertex 
 and its incident edges.
Without loss of generality, assume that . Let  be the neighbors of  other than , where . From the principles of proper total coloring, . This implies that edge  has  forbidden colors, and so, it leaves 3 feasible colors. Similarly, , and thus,  has  feasible colors. Additionally, since , , , there are  feasible colors for edge . According to the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for edge , causing , and at most one feasible color for edge , leading to . Thus, two feasible colors remain for edge , and  colors for edge . Since  has  feasible colors, from Lemma 2,  would take at least  different values. Consequently,  also has at least  different values, guaranteeing the existence of a value for  such that , where .
Now, we discuss the full sum distinguishability of v and its neighbors . Based on the previous analysis of  for , the color  is now fixed. Since , there are at least  distinct values for . This indicates that  also takes at least 16 distinct values. Accordingly, there exists a value for  yielding  for . Thus,  can be extended to a -NFSDTC of G, contradicting the minimality of G.
Case 2. .
Here, , which means that v has a leaf neighbor. Let . Then, by the minimality of G,  admits a -NFSDTC . According to the definition of neighbor full sum distinguishing total coloring,  has at least  feasible colors, and  has  feasible colors. Hence,  would take at least 23 distinct values; this indicates that  has at least 23 distinct values. Therefore, there is a value for  satisfying  for . Moreover, by Lemma 3, it follows that  for all . Thus, one can obtain a -NFSDTC  of G by extending , contradicting the minimality of G.
Secondly, we prove that . Suppose that v is adjacent to a bad 2-vertex . Let  be the other neighbor of  besides v and . Let  be the other neighbor of  differing from . Let . Then, by the minimality of G,  has a -NFSDTC .
Without loss of generality, assume that . From the principles of proper total coloring, . This means that  has  forbidden colors and 3 feasible colors. Likewise, , , which follows that  has  feasible colors. Furthermore, , ; thus,  has  feasible colors. From the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for edge  causing , and at most one feasible color for , similarly causing . Hence, 2 feasible colors remain for , and  feasible colors for . Since  has  feasible colors, by Lemma 2,  has at least  different values; this indicates that  takes at least  distinct values. Thus, there is a value for  such that  for , as well as  for .
Finally, we consider the full sum distinguishability of  and its neighbor . Based on the previous analysis of  for , and  for ,  is already determined. Since , there are at least  distinct values for ; as a result,  possesses no fewer than 20 distinct values. Therefore, there is a value for  satisfying , and thus, there exists a -NFSDTC  in G extending from , contradicting the minimality of G.    □
 Claim 9. No -vertex v with  for  has at least  neighbors of degree 2, in which at least  neighbors are bad 2-vertices.
 Proof.  Without loss of generality, suppose that 
G contains a 
-vertex 
v with 
. Let 
 denote the leaf neighbors of 
v for 
, and 
 for 
 denote the neighbors of 
v with degree of at least 2, where 
, as in the structure 
 depicted in 
Figure 1.
(1) We aim to show that . Assume by a contradiction that v has at least eight 2-vertices. Let , and z denote the other neighbor of  besides v. Two cases are considered depending on the degree of v.
Case 1. .
In this case, , which implies that v has at least one leaf neighbor. Let . Then, by the minimality of G,  admits a -NFSDTC . From the principles of proper total coloring,  has at least  feasible colors, and  has  feasible colors. Thus,  takes no fewer than 23 distinct values. Furthermore,  takes at least 23 different values. Therefore, there is a value for  satisfying  where . Meanwhile, by Lemma 3, it follows that  for . Consequently, G admits a -NFSDTC  extending , contradicting the minimality of G.
Case 2. .
Here, , indicating that v has no leaf. Let . Then, by the minimality of G,  admits a -NFSDTC . Suppose without loss of generality that . Let  be the neighbors of z other than  for . From the principles of proper total coloring, , which implies that there are 3 feasible colors for . Similarly, , which means that  has  feasible colors. Moreover, ∉, ; hence,  has at least  feasible colors. By the definition of neighbor full sum distinguishing total coloring, there is at most one color for  causing , and at most one color for  similarly causing . Thus,  has 2 remaining feasible colors and  has  remaining feasible colors. Since  has  feasible colors, it follows from Lemma 2 that  has at least  different values. This further implies that  would take at least  different values. Hence,  for .
Now, we consider the full sum distinguishability between v and its neighbors  for . Based on the above analysis of  for ,  is now determined. Since , there are at least 11 feasible colors for . This indicates that  would take at least 11 different values. Thus, there is a value for  such that  where , which contradicts the minimality of G.
(2) We here aim to prove that . Assume that v is adjacent to at least six bad 2-vertices. For convenience, we write  as these bad 2-vertices, and z is a neighbor of  distinct from v with .
If , then ; this indicates that v has at least one leaf. This case can be proved using the same method as Case 1 in (1).
If , then . In this case, it means that v has no leaf. Let . Then by the minimality of G,  admits a -NFSDTC . Let  be a neighbor of z distinct from . We then assign colors to  and its incident edges.
From the principles of proper total coloring,  has 2 forbidden colors and  feasible colors since . Similarly, , , and thus,  has  feasible colors. Furthermore, , . Hence,  has  feasible colors. By the definition of neighbor full sum distinguishing total coloring, there is at most one color for  causing , and at most one color for  causing . Therefore,  owns at least  feasible colors, and  owns at least  feasible colors. Note that  has  feasible colors. Hence, it follows from Lemma 2 that  would take at least  different values. It induces that  also has at least 41 different values. Hence, there is a value for  such that .
We next consider the full sum distinguishability of v and its neighbors  for . From the above analysis of , the value  is already determined. Since ,  has at least  feasible colors. This indicates that  also takes at least 11 different values. Accordingly, there is a value for  ensuring that , where . Therefore, G admits a -NFSDTC  by extending , which contradicts the minimality of G.    □
 From the statement of Claim 9, the following relationships can be derived, as shown in 
Table 1.
Claim 10. No -vertex v with  has at least one neighbor that is a bad 2-vertex.
 Proof.  Suppose that G contains a -vertex v such that . Let  for  be the neighbors of v, and z be a bad 2-vertex adjacent to v,  be the neighbor of z distinct from v with , and  be the neighbor of  distinct from z. Let . Then, by the minimality of G, there is a -NFSDTC  of . We now color the vertex z and its incident edges.
Assume without loss of generality that . From the principles of proper total coloring, . Therefore,  has  forbidden colors and 3 feasible colors. Similarly, we have that z has  feasible colors due to , and  has at least  feasible colors because , . Furthermore, by the definition of neighbor full sum distinguishing total coloring, there is at most one feasible color for  such that , and at most one feasible color for  such that . Thus,  possesses at least 2 feasible colors, and  possesses at least  feasible colors. Note that z has  feasible colors. Hence, it follows from Lemma 2 that  would take at least  different values. Therefore,  also takes at least  different values. So, there is a value for  such that  for .
Now, we consider the full sum distinguishability between  and its neighbor . By the analysis above concerning  for , the value  is already determined. Since , there are at least  feasible colors for . Hence,  would take at least 20 different values, and so, there is a value for  such that . Consequently, one can obtain a -NFSDTC  of G by extending , thus contradicting the minimality of G.    □
 Let H be the graph obtained from G by removing all leaves. Then, H is a connected subgraph of G with  and . Furthermore, we have that Claims 1–10 also hold for H, and . The additional properties of H are given as follows:
-  (1) 
- For all , ; 
-  (2) 
- If  with , then ; 
-  (3) 
- For  with , . 
Proof.  Since H is a connected subgraph obtained from G by removing all leaves, the statements (1) and (2) follow from Claims 1–3 directly. Next, we need to prove statement (3). Let  be a 5-face in H. Then, the proof relies on analyzing .
 - If , then by Claim 4, the face f is associated with at most three 3-vertices. Hence, . 
- If , we may suppose that , and then by Claims 2, 3, 5 and 6, it follows that  and . 
- If , we consider two cases in the following: - -
- When f is at least incident to a bad 2-vertex, we suppose . From Claims 2, 3 and 5–10 we have either  and  or  and . 
- -
- When f is not incident to any bad 2-vertex, we suppose that . Then, from Claims 2, 3 and 5–9, we obtain ,  and . 
 
- If , according to Claim 2, the only possible configuration is . Using Claims 2, 3 and 5–10, it follows that  and . 
- If , this contradicts the structural conditions described in Claim 2, and thus, such a case does not occur. 
This completes the proof of .    □
For a 
-vertex 
v in 
H with 
, we conclude that each of its bad 2-vertex is only adjacent to at most one 5-face, which is formed together with 
v and its other neighbors (which may be some good 2-vertices). If not, a bad 2-vertex associated with two 5-faces would yield a 4-cycle, thereby contradicting the condition 
, as illustrated by the configuration 
 in 
Figure 1. Thus, each bad 2-vertex adjacent to 
v is incident with at most one 5-face. Furthermore, if any two bad 2-vertices adjacent to 
v are associated with the same 
-face, then the number of 5-faces incident to 
v attains its maximum. In particular, if the number of bad 2-vertices adjacent to 
v is odd, and all bad 2-vertices are pairwise adjacent to a common 
-face, then there must exist one bad 2-vertex that is associated with a 
-face individually. Based on the above, we have the following fact.
Fact 2. 
            Every -vertex v is associated with at most  distinct 5-faces in G.
Subsequently, we carried out an analysis of charge transfer in the connected planar graph 
H. Applying 
Euler’s formula (i.e., 
) together with the 
Handshaking Lemma (i.e., 
), we derive the following equation:
Thus, the initial charge function on H is defined as follows:
- (a)
- For every vertex , let . 
- (b)
- For every face , let . 
A set of discharging rules are then applied to redistribute the charges among the vertices and faces. During the discharging process, the total sum of charges remains unchanged at 
. Upon completing the redistribution, we derive a new charge function 
 (say) such that 
 for every 
, leading to the following contradiction:
The discharging rules are defined as follows:
-  (R1) 
- Each -vertex gives  to each incident 5-face. 
-  (R2) 
- Each -vertex gives 2 to each adjacent bad 2-vertex, and gives 1 to each adjacent good 2-vertex. 
Now, we determine the new charge for all . First, we consider the new charge of each .
-  (1) 
- . If v is a bad 2-vertex, then by Claims 2, 3, 5 and (R2), . If v is a good 2-vertex, then by Claims 2, 3, 5 and (R2), . 
-  (2) 
- . One needs to set . 
-  (3) 
- . From Fact 2, we have that v is incident with at most four 5-faces. Then, by Claim 5 and (R1), we have . 
-  (4) 
- . Based on Claim 7, when v is adjacent to a good 2-vertex, it is incident with at most five 5-faces. Therefore, from (R1) and (R2), we have ; when v is adjacent to bad 2-vertices, by Fact 2, it is incident with at most four 5-faces. Thus, by (R1) and (R2), we get . 
-  (5) 
- . By Claim 8, we know that v is incident with at most six 5-faces. Therefore, it follows from (R1) and (R2) that . 
-  (6) 
- . Together with Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, is adjacent to at most three good 2-vertices and is incident with seven 5-faces, we have ; when v is adjacent to bad 2-vertices, we have . 
-  (7) 
- . Based on Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, is adjacent to at most four good 2-vertices and is incident with eight 5-faces, then ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that . 
-  (8) 
- . From Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most five good 2-vertices and incident with nine 5-faces, and thus, ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we get . 
-  (9) 
- . According to Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most six good 2-vertices and incident with ten 5-faces, and thus, ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we get ; when v is adjacent to four bad 2-vertices, we obtain . 
-  (10) 
- . From Claim 9, Fact 2, (R1) and (R2), when v is not adjacent to any bad 2-vertex, it can be adjacent to at most seven good 2-vertices and incident with eleven 5-faces, hence ; when v is adjacent to one bad 2-vertex, we have ; when v is adjacent to two bad 2-vertices, it follows that ; when v is adjacent to three bad 2-vertices, we obtain ; when v is adjacent to four bad 2-vertices, we get ; when v is adjacent to five bad 2-vertices, we have . 
-  (11) 
- . By Claim 10, v is adjacent to at most k good 2-vertices and incident with k 5-faces. Therefore, according to (R1) and (R2), we have . 
Next, we will consider the new charge of every .
-  (a) 
- When , from Fact 1 (3), f is incident with at least two -vertices. Therefore, from (R1), we have . 
-  (b) 
- When , it follows that . 
According to the process of the charge transfer described above, we present the following 
Table 2 to provide a clearer understanding and observation.
Consequently, the condition  holds for all , resulting in a contradiction. The proof is therefore completed.    □