1. Introduction
Let
denote the set of analytic functions on the open unit disk
, and let
represent the set of analytic self-maps of
. Given
, the composition operator is defined by
This operator has been extensively studied. For a comprehensive treatment of the theory of composition operators on function spaces, we refer the reader to the books [
1,
2].
For
, the Volterra-type operator is defined by
introduced by Pommerenke in [
3]. In particular, he showed that
is bounded on
if and only if
.
Volterra-type operators have garnered significant attention following the foundational work of Aleman and Siskakis [
4,
5] on Hardy and Bergman spaces. These operators have important theoretical applications in the analysis of integral equations and semigroup dynamics within complex function theory [
5]. Although the term Volterra-type also appears in applied fields such as nonlinear image processing and machine learning, those contexts refer to Volterra series-nonlinear integral models distinct from the analytic operators considered here. Such series are used to model phenomena involving memory and higher-order interactions, as in nonlinear system identification and signal prediction [
6] and in recurrent neural networks for speech recognition, natural language processing, and time-series forecasting [
7]. In contrast, the Volterra-type operators studied in this work are firmly rooted in operator theory, where they are employed to characterize boundedness, compactness, and spectral properties on spaces of analytic functions.
Given
and
, the product of Volterra and composition operators on
was defined by Li and Stević in [
8,
9,
10,
11] as follows:
Notably, if
is the identity map
, the operator
becomes the linear operator:
For
, the iterated weighted-type Banach space is defined as follows:
We adopt the convention that
.
When , 1, and 2, the corresponding function spaces are the growth space , the Bloch space , and the Zygmund space , respectively.
As shown in [
12], for each
, the map
defines a seminorm on
. The space becomes a Banach space under the norm
For
and
, we have
if and only if
, and the norm satisfies
According to Theorem 1 in [
13],
is the dual of the Hardy space
for all
. As shown in [
14], the sequence of spaces
is nested, and the inclusion
is continuous with an operator norm not exceeding 1. Since the Zygmund space
is contained in the disk algebra, this holds for all
with
.
Additionally, for
,
is an algebra, and functions in
satisfy the following pointwise estimates:
as shown in [
14].
The spaces
are a special case of the
nth weighted-type spaces introduced by Stević [
15]:
where
is a continuous positive function. The corresponding norm is
These spaces naturally appear in complex analysis and operator theory and include many well-known examples, such as the Hardy space , the Bloch space, and the Zygmund space.
The
Table 1 shows how different choices of the weight function
and the order
n give rise to various classical and generalized function spaces.
Table 1.
Examples of spaces for various weights and derivative orders n.
Table 1.
Examples of spaces for various weights and derivative orders n.
Space Name | Order n | Weight | Symbol |
---|
Set of bounded analytic functions on | 0 | 1 | |
-Growth space | 0 | | |
Weighted Banach space | 0 | | |
Bloch space | 1 | | |
-Bloch space | 1 | | |
Logarithmic Bloch space | 1 | | |
Zygmund space | 2 | | |
-Zygmund space | 2 | | |
Although iterated weighted-type Banach spaces are mostly studied in complex analysis, their focus on derivative bounds and smoothness has parallels with tools in numerical analysis. For example, weighted Sobolev spaces are widely used in finite element methods for controlling approximation errors [
16,
17].
Numerous works have explored the boundedness and compactness of Volterra-type and composition operators across weighted-type Banach spaces. For instance, Li and Stević [
9] studied these operators from
to the Bloch space
, and further, from
and
to
[
10]. In [
11], they focused on the boundedness of Bloch-type spaces,
. Ye explored similar topics on the logarithmic Bloch space [
18], and in [
19], Ye and Lin analyzed essential norms in Zygmund-type spaces,
.
Colonna and Hmidouch [
14] extended these results by studying weighted composition operators on
. Motivated by their work, we study products of Volterra-type and composition operators on
. Specifically, in
Section 2, we characterize the boundedness of such operators from
to
; in
Section 3, we estimate their essential norms. Our objective is to advance operator theory on analytic function spaces further.
Recall that if
and
are two Banach spaces and
denotes the operator norm, then the essential norm of a bounded linear operator
is its distance to the set of compact operators
L mapping
to
; that is,
It is well known that
if and only if
is compact.
Throughout this paper, C denotes a positive constant whose value may vary between occurrences. The notation means for some , and means for positive constants .
2. Boundedness of
In this section, we analyze the boundedness of and from to , and we derive an approximation of the operator norms.
We begin by recalling the following extension of Faá di Bruno’s formula:
Lemma 1 ([
15], Lemma 4)
. For and , ,whereand the sum is taken over all nonnegative integers such that , and . Noting that
and
. Then, for
,
where
for all
Now we are ready to state the first main result of this section.
Theorem 1. Fix . Let , and . Then, the operator is bounded if and only if Moreover, if is bounded, then Proof. Assume that
is finite. Let
with
. Then, for
. Therefore, by (
3) and (
2), for
, we have
Moreover,
; thus, again by (
3) and using (
2), we have
Therefore, by (
5)–(
7), we obtain
Taking the supremum over all
z in
, we obtain
Noting that
, and for
, by (
3) and using (
2), we have
Summing over all
gives
Combining (
8) and (
10), we obtain
which proves that
is bounded. Moreover
Conversely, assume
is bounded. Firstly, we show that
for any
arguing by induction on
n. Since
and
is bounded, we obtain
which confirms the basic case of the induction. Next, assume for
Consider
as a test function and note that
for
. Thus, we have
Therefore, by (
12) and since
and the operator is bounded,
Hence,
for
.
Next, we prove that the quantity
M is finite. Fix
such that
, and consider the function
as in ([
14], Lemma 3.3)
where
and recalling that
is finite.
Fix
and assume first
Since
and by the boundedness of
from
to
, then
By (
13),
. Recalling that for
, by (
2),
we obtain
Next, assume
. Then
Combining (
14) and (
15) and taking the supremum over all
w in
, we obtain
It follows, by (
11) and (
16),
which completes our proof. □
Note that if is the identity map , then , and for . Moreover, if is the identity map , then , for , while . Hence, by Theorem 1, we deduce the following:
Corollary 1. Fix and let . Then, the operator is bounded if and only if Moreover, if is bounded, then Corollary 2. Fix , and let . Then, the operator is bounded if and only ifMoreover, if is bounded, then We now state the second main result of this section.
Theorem 2. Fix . Let , and . Then, the operator is bounded if and only if Moreover, if is bounded, then Proof. Assume that
is finite. Let
with
. Following the argument used in the proof of Theorem 1, we obtain
Moreover,
Therefore, by (
5), (
17) and (
18), we have
which proves that
is bounded. Moreover,
Conversely, assume
is bounded. To prove that
is finite, one can use the same argument as in the proof of Theorem 1. The details are omitted since the proof is straightforward. □
3. Essential Norms
We begin the section by providing Lemma 4.1 of [
14] and a useful result proved by Tjani in [
20] that will be used to estimate the essential norm of integral-type operators on
.
Lemma 2 ([
14], Lemma 4.1)
. For each nonnegative integer , if is a bounded sequence in converging to zero uniformly on compact subsets of , then Lemma 3 ([
20], Lemma 2.10)
. Let be a bounded linear operator, where and are Banach spaces of analytic functions on . Suppose- (i)
the point evaluation functionals on are continuous;
- (ii)
the closed unit ball of is a compact subset of in the topology of uniform convergence on compact sets;
- (iii)
T is continuous if has the supremum norm and is given the topology of uniform convergence on compact sets.
Under these conditions, T is a compact operator if and only if for any bounded sequence in converging to 0 uniformly on compact subsets of , the sequence converges to 0 in norm.
The following result is crucial for estimating the essential norm of integral-type operator .
Lemma 4. Fix and let . For , the dilation function in is defined by for all . Then
- (a)
- (b)
for each and , there exists such that
- (c)
is compact on
Proof. (a) Let and f in . Then
Thus,
is bounded, and observing that
combining (
22) and (
23), we obtain
- (b)
Let
with
. Fix
and let
be a sequence in
converging to 1 as
. By the continuity of
f on the closed unit disk, for
,
and by part (a)
Thus,
is in the unit ball of
. Note that by (
3),
satisfies the second hypothesis in Lemma 3; therefore, the sequence
has subsequence
converging uniformly to 0 on every compact subset of
. By Montel’s theorem, the functions
, for
converge uniformly to 0 on every compact subset of
. Since every sequence in
converging uniformly on compact subsets of
converges uniformly on
for
, the subsequence
, for
converges uniformly to 0 on
. Thus, for every
there exists
such that
The conclusion follows after taking the supremum over all functions in the unit ball of
.
- (c)
Fix
. To show that
is compact on
, by Lemma 3, it suffices to show that each bounded sequence
on
converging uniformly to 0 on compact subsets of
,
. Let
be a bounded sequence on
converging uniformly to 0 on compact subsets of
. We have
Since converges uniformly to zero on the disk with radius r, then as .
Since {0} is compact of , then converges to 0, for . Therefore, as . Thus, is compact on . □
Now, we are ready to state the main result of this section.
Theorem 3. Fix and let and . If is bounded, then Proof. To prove the upper estimate, fix
and
, and choose
as in Lemma 4. It follows, for
, by (
9)
Since
is compact and
is bounded,
is also compact. Thus, by (
19), (
20), (
21) and (
24),
Since
is arbitrary, passing to the limit as
, we obtain
To prove the lower estimate, let be a sequence in such that . Then, the sequence defined in the proof of Theorem 3 converges to 0 uniformly on compact subsets. Moreover, .
Let
be a compact operator. Then, by Lemma 3,
. Hence, by Lemma 2 and (
13),
Taking the infimum over all compact operators
, we obtain
□
By concentrating on the component operators and , and using the identities and along with Theorem 3, we obtain the following results:
Corollary 3. Fix and let . If is bounded, then Corollary 4. Fix and let . If is bounded, then We are now ready to state the second main result of this section.
Theorem 4. Fix and let and . If is bounded, then Proof. To prove the lower estimate, let be a sequence in such that . Then, the sequence defined in the proof of Theorem 3 converges to 0 uniformly on compact subsets. Moreover, .
Let
be a compact operator. Then, by Lemma 3,
. Hence, by Lemma 2 and (
13),
Taking the infimum over all compact operators
, we obtain
To prove the upper estimate, fix
and
, and choose
as in Lemma 4. By considering
instead of
and applying the same approach used in the proof of the upper estimate in Theorem 3, then the result follows directly. □