2. Preliminaries
A space X is weakly Lindelöf if every open cover of X contains a countable subfamily whose union is dense in X. Every space with a dense Lindelöf subspace or having countable cellularity is weakly Lindelöf.
According to [
6], a Hausdorff space
X is called a Lindelöf Σ-space if there exist a countable family
of closed sets in
X and a cover
of
X by compact sets, such that for every
and every open neighborhood
U of
C in
X, one can find
, such that
. In fact, K. Nagami defined in [
6] the wider class of Σ-spaces, so the Lindelöf Σ-spaces are simply the Σ-spaces with the Lindelöf property. The reader can find a detailed discussion of distinct ways to define Lindelöf Σ-spaces in [
7] (Theorem 1).
It is known that the class of Lindelöf Σ-spaces is countably productive and that an
-subset of a Lindelöf Σ-space is again a Lindelöf Σ-space [
6]. This class of spaces becomes especially stable when one restricts himself to considering Tychonoff spaces only. It turns out that every continuous image, say
Y of a Lindelöf Σ-space
X, is again a Lindelöf Σ-space, provided that
X and
Y are Tychonoff [
1], (Proposition 5.3.5). In fact, the same conclusion remains valid if
X is Hausdorff and
Y is regular [
4] (Lemma 4.5). However, we do not know whether the latter fact can be extended to the case when both
X and
Y are Hausdorff. This is why we define here a (possibly) wider class
of Hausdorff spaces that is countably productive and is closed under taking continuous images.
Definition 1. A Hausdorff space X is in the class if there exist a countable family of (not necessarily closed) subsets of X and a cover of X by compact subsets, such that for every and every open neighborhood U of C in X, one can find , such that .
It follows from Definition 1 that every Lindelöf Σ-space is in the class
. It is also easy to verify that every space
is Lindelöf. Therefore, a regular space in
is normal (hence, Tychonoff), so regular spaces in
are Lindelöf Σ-spaces according to [
7] (Theorem 1).
Proposition 2. The class is countably productive and closed under taking continuous images. Further, if Y is an -subset of a space , then .
Proof. Let be a family of spaces. For every , let and be families of subsets of witnessing that . We can assume that for each . To show that is in , we define families and of subsets of X as follows.
Let be the family of sets of the form , where for each and for at most finitely many indices . Clearly the family is countable. Similarly, let be the family of sets of the form , where for each . Then, the family consists of compact subsets of X. Take an element and an open neighborhood U of C in X. Then, , where for each . By Wallace’s Lemma, there exists a finite set and open sets with , such that , where if and if . For every , there exists , such that . Let , where if and if . Then, and . Therefore, the families and witness that . This proves that the class is countably productive.
Let be a continuous onto mapping of Hausdorff spaces, where . Take families and of subsets of X witnessing that . It is easy to verify that the families and of subsets of Y witness that .
Finally, let
, where each
is a closed subset of a space
. Denote by
and
families of subsets of
X witnessing that
, where
is countable and each
is compact. Let us verify that the families:
and:
witness that
. It is clear that
and that each element of
is a compact subset of
Y. Let
be an element of
, where
and
. Let also
V be an open neighborhood of
K in
Y. Then, there exists an open set
O in
X, such that
. Since the compact set
is disjoint from
K and the space
X is Hausdorff, we can find disjoint open in
X neighborhoods
and
of
K and
, respectively. The set
is open in
X and contains
. Hence, the set
is an open neighborhood of
C in
X, so we can find an element
, such that
. Then,
is an element of
that satisfies:
This completes the proof of the fact that . ☐
Another important property of the spaces in
is presented in the following result, which is close to [
1] (Proposition 5.3.15). However, our proof of Proposition 3 is quite different from the one given in [
1], since we work in the class of Hausdorff spaces, which is much wider than the class of Tychonoff spaces considered in [
1] (Section 5.3).
Proposition 3. If a space admits a continuous one-to-one mapping onto a Hausdorff space Y with a countable network, then X itself has a countable network.
Proof. Let be a continuous bijection. It is well known that every Hausdorff space with a countable network admits a continuous one-to-one mapping onto a second countable Hausdorff space. Let be a continuous bijection of Y onto a second countable Hausdorff space Z. Then, is a continuous bijection of X onto Z. Denote by a countable base for Z. We can assume that is closed under finite intersections and finite unions.
Let families
and
of subsets of
X witness that
, where
and each
is compact. We claim that the countable family:
is a network for
X. Indeed, take a point
and an open neighborhood
U of
x in
X. There exists
, such that
. Then,
is a compact subset of
X and
. Hence, the compact subset
of
Z does not contain the point
, and we can find disjoint elements
, such that
and
. Then,
is an open neighborhood of
C in
X, so there exists an element
, such that
. It is clear that
is an element of
, and we have that:
We have thus proven that
is a countable network for
X. ☐
Replacing the family
in the proof of Proposition 3 with the family:
we obtain the following version of the proposition:
Proposition 4. If a Lindelöf Σ-space X admits a continuous one-to-one mapping onto a Hausdorff space with a countable network, then X has a countable network of closed sets.
The following lemma was proven in [
2] for regular Lindelöf Σ-spaces. Therefore, we extend the corresponding result from [
2] to the wider class of Hausdorff
-spaces.
Lemma 5. If a space has a -diagonal, then it has a countable network.
Proof. Suppose that
. Then, Proposition 2 implies that
, so the space
is Lindelöf. Let
be a family of open neighborhoods of the diagonal
in
such that
. It is clear that
is a closed Lindelöf subspace of
. Given
and a point
, we can find disjoint open neighborhoods
and
of the points
x and
y, respectively, in
X. The open cover
of the Lindelöf space
contains a countable subcover, say
, where
is a countable subset of
. Let:
Then, γ is a countable family of open sets in X. We claim that for every pair of distinct points in X, there exist disjoint elements , such that and . Indeed, since , there exists , such that , i.e., . Hence, there exists an element , such that . This means that and are disjoint open neighborhoods of the points a and b, respectively. This proves our claim.
Let be the family of finite intersections of elements of γ. It is clear that is a base for a Hausdorff topology τ on X. Then, the space has a countable base, and the identity mapping of X onto Y is a continuous bijection. Applying Proposition 3, we conclude that X has a countable network. ☐
Given continuous mappings and , we will write if there exists a continuous mapping satisfying .
We will also need the notion of a weak σ-lattice of mappings mentioned in the Introduction (see also [
2], Definition 3.1).
Definition 6. Let Y be a space and a family of continuous mappings of elsewhere. Then, is said to be a weak σ-lattice for Y if the following conditions hold:- (1)
generates the original topology of Y;
- (2)
every finite subfamily of has a lower bound in
- (3)
for every decreasing sequence in , there exists and a continuous one-to-one mapping , such that , where q is the diagonal product of the family .
A typical example of a weak σ-lattice for a topological group H is the family of all quotient mappings onto left coset spaces, where N is an arbitrary closed subgroup of type in H.
Let us recall that a -set in a space X is the union of an arbitrary family of -sets in X. Further, a space Y is said to be ω-cellular or, in symbols, if every family γ of -sets in Y contains a countable subfamily λ, such that is dense in . It is clear that every ω-cellular space has countable cellularity. In fact, the class of ω-cellular spaces is considerably narrower than the class of spaces of countable cellularity. For example, a space Y of countable pseudo-character satisfies if and only if it is hereditarily separable.
Our next result is a special case of [
2] (Theorem 3.4), which is sufficient for our purposes. We supply it with a short proof based on another fact from [
2].
Theorem 7. Let be a product of regular Lindelöf Σ-spaces and a Tychonoff space Y be a continuous image of X. If Y has a weak σ-lattice of open mappings onto Hausdorff spaces with a -diagonal, then , and the closure of every -subset of is a -set.
Proof. First, we choose a point
. For every countable set
, denote by
the projection of
X onto the sub-product
. Then,
is a Lindelöf Σ-space, and we identify it with a corresponding closed subspace of
X multiplying
by the singleton
. Then, the family:
constitutes a strong
σ-lattice of open retractions of
X onto Lindelöf Σ-subspaces (see [
2], Definition 3.1).
Let
be a continuous onto mapping. Denote by
a weak σ-lattice of open mappings of
Y onto Hausdorff spaces with a
-diagonal. For every
, the composition
is a continuous mapping of
X onto the Hausdorff space
with a
-diagonal. By [
8] (Theorem 1),
g depends at most on countably many coordinates, so we can find a countable set
and a mapping
, such that
. Since
is an open continuous mapping,
is continuous. Hence,
is in the class
as a continuous image of the Lindelöf Σ-space
. By Lemma 5,
has a countable network for each
. It follows that
X,
f,
Y satisfy the conditions of Theorem 3.3 in [
2]; hence,
, and the closure of every
-subset of
Y is a
-set in
Y. ☐
We recall that a paratopological group
G is called
-factorizable if for every continuous real-valued function
f on
G, one can find a continuous homomorphism
onto a second countable paratopological group
H and a continuous real-valued function
h on
H satisfying
. The original definition of
-factorizable paratopological groups in [
9] involves separation restrictions on the groups
G and
H, thus giving rise to the concepts of
-factorizability for
. However, it is shown in [
4] that all of these concepts coincide and are equivalent to the one given above.
The following fact is a special case of [
10] (Theorem 2.2) formulated in a form convenient for applications in
Section 3. More precisely, it will be used in the proof of Theorem 12 to deduce the
-factorizability of paratopological groups representable as continuous images of products of Lindelöf Σ-spaces.
Proposition 8. Let be a continuous mapping of a Hausdorff weakly Lindelöf paratopological group H to a metrizable space M. Then, one can find a closed subgroup N of type in H and a continuous mapping h of the left coset space to M, such that is Hausdorff and the equality holds, where is the quotient mapping.
3. Continuous Images of Products of Lindelöf Σ-Spaces
In this section we present the proofs of our main results announced in the Introduction. We start with three auxiliary results, Lemmas 9 to 11.
Let us recall that a space X is Urysohn if for every pair of distinct points in X, there exist open neighborhoods and of x and y, respectively, such that .
Lemma 9. Let G be a weakly Lindelöf regular paratopological group, a countable family of open neighborhoods of the identity element e in G and . Then, there exists a closed subgroup N of G satisfying the following conditions, where and are quotient mappings of G onto the left and right coset spaces and , respectively:- (a)
;
- (bl)
the space is Urysohn and has a -diagonal;
- (br)
the space is Urysohn and has a -diagonal;
- (c)
there exist open neighborhoods and of the elements and in and , respectively, such that and .
Proof. Denote by
the family of open neighborhoods of
e in
G. Since
G is weakly Lindelöf, it follows from [
11] (Theorem 10) that the index of regularity of
G is countable. Hence the Hausdorff number of
G is also countable [
12] (Proposition 3.5),
i.e., for every
, there exists a countable family
, such that
.
We introduce a new group multiplication in G by letting , for all . Let be the paratopological group , where τ is the topology of G. In other words, G and differ only in multiplication. Hence, is also weakly Lindelöf and has a countable Hausdorff number. Therefore, for every , there exists a countable family , such that or, equivalently, .
Let
. Making use of the inequalities
and
, one can define a sequence
of countable subfamilies of
satisfying the following conditions for each
:
- (i)
For every , there exists , such that ;
- (iir)
, for each ;
- (iil)
, for each .
Then, is a countable subfamily of . Let us show that is as required.
Since , it follows that . This implies the validity of (a) of the lemma. Condition (ii) implies that for every and every , so . Since N contains the identity e of G, we see that N is a subgroup of G. Let and be the quotient mappings. By (i), there exists , such that . Then, is an open neighborhood of in and . Similarly, is an open neighborhood of in and . Hence, (c) of the lemma is valid, as well.
Our next step is to show that condition (b) of the lemma is also fulfilled, i.e., the coset space is Urysohn and, hence, Hausdorff. In particular, the subgroup is closed in G. A similar verification of item (b) is left to the reader, since it only requires the use of (ii) in place of (ii).
Take an arbitrary element
, such that
. Since the space
is homogeneous, it suffices to show that the points
and
have disjoint closed neighborhoods in
. As
, there exists an element
, for some
, such that
. By (ii
), there exists
, such that
. Applying (i) twice, we can find
, such that
. Then,
, whence it follows that:
Since the mapping
of
G onto
is open and
(and, therefore,
), we have the following inclusions:
and:
Combining Equations (1) to (3), we see that the closed subsets and of are disjoint. Since and are open neighborhoods of and , respectively, in , the latter space is Urysohn.
Finally we verify that
has a
-diagonal. For every
, let:
Then, the countable family
of open entourages of the diagonal Δ in
satisfies
. Indeed, take arbitrary elements
, such that
. Then,
, so we can find an element
, for some
, such that
. By (ii
), there exists
, such that
. Now, we apply (i) to take
with
. We claim that
. Indeed, otherwise, there exists
, such that
and
. The latter implies that
and
, whence:
which is a contradiction. Since the family
is countable, we conclude that the coset space
has a
-diagonal. A similar argument shows that the right coset space
has a
-diagonal. This completes the proof. ☐
The next result is almost evident, so we omit its proof.
Lemma 10. The class of spaces with a -diagonal is countably productive.
Lemma 11. Let G be a weakly Lindelöf regular paratopological group and the family of closed subgroups N of G that satisfy conditions and of Lemma 9. Then, is closed under countable intersections.
Proof. Let be a sequence of subgroups of G. For every , denote by the quotient mapping of G onto the left coset space . Let also be the diagonal product of the family . Then, is a continuous mapping of G to the product space . Each of the factors has a -diagonal, and so does Z, by Lemma 10. Hence the subspace of Z also has a -diagonal. Similarly, the space Z and its subspace are Urysohn since the factors are Urysohn.
Put , and let be the quotient mapping. For every , there exists a mapping , such that . The mapping is continuous and open since so are π and . The diagonal product of the family , say p, is a continuous mapping of to . It is clear that p satisfies the equality . It is also easy to see that the fibers of the mappings and π coincide, i.e., p is a continuous bijection of onto . Indeed, take arbitrary points with . We have to show that . It follows from the definition of that , for each . Hence, and . Therefore, the equality implies that is a continuous bijection.
Finally, since the space is Urysohn and has a -diagonal and p is continuous and one-to-one, we infer that the space is also Urysohn and has a -diagonal. A similar argument shows that the right coset space has the same property. This proves that .
In the following theorem, we do not impose any separation restriction on the paratopological group G.
Theorem 12. Let be a product of regular Lindelöf Σ-spaces and a continuous mapping of X onto a paratopological group G. Then, the group G is -factorizable and has countable cellularity.
Proof. Consider a continuous real-valued function
g defined on
G. We can assume the group
G is a regular space. Indeed, let
be the canonical continuous homomorphism, where
is the regularization of
G (see [
13,
14]). Then,
is a regular paratopological group, and by the definition of
, there exists a continuous real-valued function
on
, such that
. Hence,
G is
-factorizable if so is the group
. It also follows from [
15] (Proposition 2.2) that the groups
G and
have the same cellularity. Notice that
is a continuous mapping of
X onto
. Thus, we can assume that
G itself is regular.
By a recent theorem of Banakh and Ravsky in [
16], every regular paratopological group is completely regular. Each factor
, being a regular Lindelöf space, is normal and, hence, Tychonoff. Therefore, the product space
X is Tychonoff, as well. Our next step is to show that
G has a weak σ-lattice of open mappings onto Hausdorff spaces with a
-diagonal.
Take an arbitrary point
in
X and denote by
the subspace of
X consisting of the points
that differ from
at most on finitely many coordinates. Clearly
is dense in
X. Since the class of Lindelöf Σ-spaces is finitely productive (this follows, e.g., from Proposition 2) [
1] (Corollary 1.6.45) implies that the subspace
of
X is Lindelöf. Hence,
is a dense Lindelöf subspace of
G, so the space
G is weakly Lindelöf. Applying Lemma 9, we see that the topology of the group
G is initial with respect to the family
of quotient mappings of
G onto Urysohn left coset spaces with a
-diagonal, and the same is valid for the family
of quotient mappings of
G onto Urysohn right coset spaces with a
-diagonal. Making use of Lemma 11, one can easily prove that both
and
are weak σ-lattices of continuous open mappings for
G. A routine verification of this fact is omitted.
Since G is a continuous image of the product space X, Theorem 7 implies that . As , we conclude that G has countable cellularity. It remains to show that the group G is -factorizable. This requires several steps.
Following the notation in Lemma 11, we denote by the family of all closed subgroups N of G, such that the coset spaces and are Urysohn and have a -diagonal.
Claim 1. The coset spaces and have a countable network, for each .
Let
be the quotient mapping, where
. Then,
is a continuous mapping of
X onto the left coset space
. Notice that
is a Lindelöf Σ-space for every countable set
; hence, [
8] (Theorem 1) implies that
depends on at most countably many coordinates,
i.e., one can find a countable set
and a continuous mapping
, such that
, where
is the projection. It is clear that
h is a surjective mapping. Applying Proposition 2, we conclude that
. Hence, by Lemma 5, the space
has a countable network. The same argument applied to the quotient mapping
enables us to deduce that the right coset space
also has a countable network. This proves Claim 1.
Claim 2. For every , there exists , such that , and similarly, for every , there exists , such that .
By the symmetry argument, it suffices to verify the first part of the claim. Let
N be a closed subgroup of
G, such that the left coset space
is Urysohn and has a
-diagonal. By Claim 1, the space
has a countable network. Denote by
Z the semi-regularization of the space
(see [
14], p. 204), and let
be the identity mapping. Since
is Hausdorff, it follows from [
17] (Proposition 1) that the space
Z is regular. It is clear that the mapping
is continuous, so
Z has a countable network as a continuous image of the space
. In particular,
Z is Lindelöf and normal. Since
Z has a countable network, we can find a continuous bijection
onto a separable metrizable space
. Then,
is a continuous mapping of
G onto
. By Proposition 8, there exists a closed subgroup
M of type
in
G and a continuous mapping
, such that
, where
is the quotient mapping of
G onto
. According to Lemma 9 we can assume without loss of generality that
. Let
. The mapping
of
to
is well defined, since
and
are bijections. Thus, the following diagram commutes.
Since and are continuous open mappings, so is . This implies that . Claim 2 is proven.
Claim 3. For every , there exists , such that and K is invariant in G.
Indeed, take an arbitrary element
, and let
. By Claim 2, there exists
, such that
. Hence,
or, equivalently,
, for each
. Applying Claim 2 once again, we find
, such that
for each
. Continuing this way, we define sequences
and
, such that
and
for each
. Then, the subgroup
of
G is as required. Indeed, it follows from Lemma 11 that
, so both coset spaces
and
are Urysohn and have a
-diagonal. It also follows from our definition of
K that:
for all
and
, so
. This inclusion is in fact the equality, so
K is a closed invariant subgroup of
G. Since
, this completes the proof of Claim 3.
We are now in the position to complete our argument. Let us recall that
g is an arbitrary continuous real-valued function on
G. Since
G is Hausdorff and weakly Lindelöf, we apply Proposition 8 to find a closed subgroup
N of type
in
G, such that
g is constant on each left coset of
N in
G. Therefore, there exists a real-valued function
h on
, such that
, where
is the quotient mapping. Since
is continuous and open, the function
h is also continuous. By Lemma 9, there exists
with
. Then, Claim 3 implies the existence of an invariant subgroup
K of
G, such that
and
. The inclusions
mean that there exists a mapping
, such that
, where
is the quotient homomorphism.
Since the mappings
and
are continuous and open, so is
. Hence,
is a continuous real-valued function on
. Notice that
is a paratopological group, by the invariance of
K in
G, and
is Hausdorff by our choice of
. The group
has a countable network by Claim 1; hence, we can apply [
9] (Corollary 3.11) according to which
is
-factorizable. Therefore, we can find a continuous homomorphism
onto a second countable paratopological group
P and a continuous real-valued function
on
P, such that
. Therefore, the following diagram commutes.
It remains to note that the continuous homomorphism and the function satisfy the equality , which implies the -factorizability of the group G. ☐
A topological group
G is said to be ω-narrow (see [
1], Section 3.4) if it can be covered by countably many translations of any neighborhood of the identity. A paratopological group is totally ω-narrow if it is a continuous homomorphic image of an ω-narrow topological group or, equivalently, if the topological group
associated with
G is ω-narrow [
12] (Subsection 1.1).
If the paratopological group G in Theorem 12 is regular, we are able to complement the conclusion of the theorem as follows:
Theorem 13. Let be a product space, where each is a regular Lindelöf Σ-space and a continuous mapping of X onto a regular paratopological group G. Then, the group G is totally ω-narrow and satisfies , and the Hewitt–Nachbin completion of the group G is again a paratopological group containing G as a dense subgroup. Furthermore, the group is -factorizable.
Proof. Every regular paratopological group is Tychonoff according to [
16]. Hence, applying Theorem 12, we conclude that
G is a Tychonoff
-factorizable paratopological group. By [
17] (Proposition 3.10),
G is totally ω-narrow.
The inequality was established in the proof of Theorem 12 under the assumption of the regularity of G.
Finally, according to [
18] (Theorem 2.3), the Hewitt–Nachbin completion of a Tychonoff
-factorizable paratopological group is again an
-factorizable paratopological group containing the original group as a dense subgroup. ☐
Since the Sorgenfrey line is a regular paratopological group that fails to be totally ω-narrow, Theorem 13 implies the following curious fact:
Corollary 14. The Sorgenfrey line is not a continuous image of any product of regular Lindelöf Σ-spaces.
The above corollary also follows from Theorem 12, since the group
is not
-factorizable according to [
1] (Example 8.1.8). We also note that the conclusion of Corollary 14 is valid for every uncountable subgroup of
.
Remark 1. We present here a direct proof of the fact that the regular group G in Theorem 13 is totally ω-narrow. We hope that it can help to treat the more general case when G is Hausdorff.
Let τ be the topology of
G. Denote by
the family
. Then,
is a paratopological group conjugated to
G, and the inversion in
G is a homeomorphism of
G onto
. Hence,
is also a continuous image of
X, so the groups
G and
have the same properties. Let
be the diagonal in the paratopological group
. According to [
9] (Lemma 2.2), Δ is a closed subgroup of
topologically isomorphic to the topological group
associated with
G. Therefore, it suffices to show that the group Δ is ω-narrow. Let
O be a neighborhood of the identity
in Δ. There exists an open neighborhood
U of the identity
e in
G, such that
. By Lemma 9 and Claims 1 and 3 in the proof of Theorem 12, we can find a closed invariant subgroup
N of
G, such that the quotient group
has a countable network and
for some open neighborhood
V of the identity in
, where
is the quotient homomorphism. It is clear that
is a paratopological group conjugated to
and that
has a countable network. Let
be the quotient homomorphism. Then,
is a continuous homomorphism of
onto the paratopological group
with a countable network. Clearly, the subgroup
of
also has a countable network and, hence, is Lindelöf. In particular, the group
is ω-narrow. Therefore, we can find a countable subset
D of
, such that
, where
(we identify the groups
and
algebraically). Let
C be a countable subset of Δ, such that
. It easily follows from our choice of the sets
V and
W that
, so we have the equality
. This proves that the topological group
is ω-narrow.