1. Introduction
A central problem in the theory of Markov chains concerns quantifying the convergence rate to the stationary distribution. This rate is determined by the spectral properties of the corresponding transition matrix, where the subdominant eigenvalue modulus plays a crucial role. Standard references on this topic include Chen [
1] and Levin and Peres [
2].
Consider an irreducible and aperiodic Markov chain
on a finite state space
, with transition matrix
P and stationary distribution
. For any square matrix
A, we denote its spectrum by
. Using the Perron–Frobenius theorem for stochastic matrices—see, e.g., Seneta [
3] (Theorem 1.1)—the eigenvalue 1 is simple and strictly dominant in
. Our analysis therefore focuses on
Define the subdominant eigenvalue modulus of transition matrix
P as follows:
If
, we call
the subdominant eigenvalue.
Denote, using
, the Dirac measure concentrated on the state
According to Levin and Peres [
2] (12.37), if
, then the total variation distance to stationarity decays geometrically at the rate of
:
This result naturally raises two fundamental questions about the subdominant eigenvalue modulus:
- 1.
Does the strict inequality hold ?
- 2.
Is itself an eigenvalue of the transition matrix P ?
When
P corresponds to a time-reversible Markov chain, all its eigenvalues are real. Then, both questions can be answered affirmatively:
and
. However, when
P is nonreversible, it is generally challenging to address both questions, as
P may have complex eigenvalues. In the non-reversible case, guaranteeing the mentioned properties related to
commonly requires imposing some monotonicity assumptions on the chain. When
is a totally ordered state space, we say that
P is stochastically monotone if, for any
with
and
,
For stochastically monotone Markov chains in totally ordered state spaces, regarding the two mentioned questions, Keilson and Kester [
4] established a Perron-Frobenius-type theorem for the subdominant eigenvalue, thus resolving both questions in a totally ordered setting.
While the theory of stochastically monotone chains on totally ordered spaces provides foundational insights, this framework has limitations in its ability to model complex systems with partially ordered state spaces. This motivated us to study partially ordered state spaces, where stochastic monotonicity generalizes to Möbius monotonicity (formally defined in the next section). The concept of Möbius monotonicity was first introduced by Kester [
5] in his PhD thesis. Subsequently, Massy [
6] established that Möbius monotonicity implies weak stochastic monotonicity. Lorek [
7] further developed this theory, demonstrating its applicability to various systems, including queueing models and interacting particle systems [
7,
8,
9,
10].
The primary objective of this work is to establish a Perron–Frobenius-type theorem for the subdominant eigenvalue of Möbius monotone transition matrices. This result extends the Perron–Frobenius theorem developed by Keilson and Kester [
4] and provides a systematic framework for analyzing the subdominant eigenvalue in partially ordered state spaces. Furthermore, we establish that the subdominant eigenvalue is the geometric ergodicity rate.
2. Main Results
In the following, we assume that is a finite state space equipped with a partial order ⪯. We further assume the following:
is the unique minimal element, and is the unique maximal element under ⪯.
The enumeration of is consistent with the partial order; that is, if for any , then .
Define the matrix
as
where
denotes the indicator function. According to Rota [
11] (Proposition 1), there exists an inverse matrix
of
C such that, for any
and the following support restriction holds:
The matrix
admits explicit expression for some specific partially ordered sets
. For example, let
be the lattice set. According to [
11] (Proposition 5), we know for any
can be written as
For the specific state space
, from (4), we can derive
as follows:
For any element and subset , define Denote for any The classical notion of stochastic monotonicity (defined for totally ordered sets such as natural numbers) can be extended to partially ordered sets.
Definition 1. Let P be a transition matrix on .
We say P is Möbius monotone,
if for any , We say P is strictly Möbius monotone,
if for any ,
Remark 1. Using the definition of C in (1)
and the support restriction of in (3),
for any , we haveThen, we can conclude that for all if and only if P is Möbius monotone, while for all if and only if P is strictly Möbius monotone. When P is Möbius monotone, the matrix transformation (6)
actually defines a new transition matrixknown as the Siegmund dual of P. The concept of Siegmund duality was introduced by Siegmund [12], who established the equivalence between absorbing and reflecting barrier problems for stochastically monotone Markov processes. Following Siegmund’s seminal work, subsequent research has significantly expanded the applications of Siegmund duality across various domains of Markov process theory; see, e.g., [10,13,14]. Remark 2. When the state space is totally ordered, from Equation (4),
the matrix admits the following explicit form:Then, we havefrom which we conclude that (strict) Möbius monotonicity reduces to (strict) stochastic monotonicity in totally ordered spaces. Theorem 1. Let P be an irreducible Möbius monotone transition matrix on . Then, the subdominant eigenvalue modulus belongs to and satisfies . If we further assume that P is strictly Möbius monotone, then is a simple eigenvalue, and the strict inequality holds for all .
Proof. Since similarity transformations preserve spectral properties, it suffices to analyze the matrix
. We shall first prove that
is an eigenvalue of
. Noting that
is the minimal element in
, for any
,
Then, one can write the matrix
as
where
is a column vector of dimension
,
is a row vector of dimension
, and
Q is a nonnegative
matrix.
Now, we claim that the spectrum of
P consists of 1, together with the spectrum of
To see this, observe that the characteristic polynomial of
P can be written as
where
denotes the
identity matrix for
. Consequently,
Since
Q is nonnegative, using Perron–Frobenius theorem—see, e.g., Horn and John- son [
15] (Theorem 8.3.1)—
belongs to the spectrum of
Q, and satisfies
Furthermore, under the additional assumption of strict Möbius monotonicity for
P, matrix
Q becomes strictly positive. Thus, using another version of the Perron–Frobenius theorem—see, e.g., [
15] (Theorem 8.2.8)—we know that
is indeed a simple eigenvalue, and the strict inequality
holds for all
.
To complete the proof, it remains to show that . We divide the arguments into two parts:
(i) We first prove that
is a strictly substochastic matrix on the reduced space
. Using (2), we obtain the following:
and
By (6), (7), (8) and (9), for any
,
where, in the third equality, we interchange the order of summation between
x and
z. To establish the strict inequality in (10), we employ proof by contradiction. Assume the equality holds in (10). This implies
which consequently forces
for all
This contradicts the irreducibility of
P. We therefore conclude that
must be strictly substochastic.
(ii) Now, we are in a position to prove
Using Perron–Frobenius theorem [
15] (Theorem 8.3.1), a nonnegative nonzero eigenvector
is observed, such that
Summing up both sides yields the following:
Interchanging the order of summation on the left-hand side gives
From the strictly substochastic property
(established in (i)), there exists a
, such that
while, for all other
,
Substituting these inequalities into (11) and noting the positivity of
v, we derive
which immediately implies
□
We emphasize that strict Möbius monotonicity is not a necessary condition for the simplicity of the subdominant eigenvalue. In fact, to apply the Perron–Frobenius theorem—see, e.g., Seneta [
3] (Theorem 1.1)—one only needs
Q to be irreducible and aperiodic; matrix
Q is defined in (7). This condition is related to the strict monotonicity of the powers of
Q, as follows.
Lemma 1. Let P be a Möbius monotone transition matrix on . There exists an integer such that is strictly Möbius monotone if and only if Q defined in (7) is irreducible and aperiodic.
Proof. From the block structure in (7), for any integer
, we have
where
denotes a row vector of dimension
.
Assume
Q is irreducible and aperiodic. Then, by [
3] (Theorem 1.4), an integer
exists such that
is strictly positive. Substituting this into (12), the strict positivity of
implies that
is strictly Möbius monotone.
Conversely, suppose that is strictly Möbius monotone for some integer . It follows from (12) that is strictly positive. To show that remains strictly positive, suppose, for contradiction, that there is an element in equal to 0. This implies that at least one row of Q consists entirely of zeros, which contradicts the strict positivity of . Therefore, through induction, we can conclude that for any , is a strictly positive matrix. Consequently, Q must be irreducible and aperiodic. □
The next theorem slightly relaxes the condition for the second statement in Theorem 1.
Theorem 2. Let P be a Möbius monotone transition matrix on . Suppose that there exists an integer such that is strictly Möbius monotone, or equivalently, the matrix Q defined in (7) is irreducible and aperiodic. Then, is a simple eigenvalue satisfying , and the strict inequality holds for all .
Proof. Using Lemma 1, the strict Möbius monotonicity of
is equivalent to the irreducibility and aperiodicity of
Q. According to [
3] (Theorem 1.4),
Q is primitive; that is, there exists an integer
, such that
is a strictly positive matrix. Applying [
3] (Theorem 1.1), we can see that
is a simple eigenvalue of
Q, and the strict inequality
holds for all
. The remainder of the proof for
is the same as that of Theorem 1. □
Recall that when the modulus
, we call
the subdominant eigenvalue. The following theorem establishes the immediate application of Theorems 1 and 2 by linking the subdominant eigenvalue to the geometric ergodicity rate. Although Levin and Peres [
2] (12.37) noted this connection for nonreversible Markov chains, they did not provide a rigorous proof. For the reader’s convenience, we provide a complete proof here.
Theorem 3. Let P be an aperiodic, irreducible, Möbius monotone transition matrix on . Then, the corresponding Markov chain admits a unique stationary distribution, denoted by π, andwhere is the subdominant eigenvalue belonging to Proof. According to Seneta [
3] (Theorem 1.1), 1 is the simple eigenvalue of
P, with the left eigenvector being its stationary distribution. Define the matrix
by
Then, for any
, it can be verified that
Using these identities and the definition of total variation norm, we have
where
denotes the maximum row sum matrix norm, given by
Let
be the all-ones column vector. Using Seneta [
3] (Theorem 1.1) again, 1 is a simple eigenvalue with left eigenvector
and right eigenvector
. Through invariant subspace decomposition, any right eigenvector
of
P associated with an eigenvalue other than 1 satisfies
. This implies that
shares all the eigenvalues of
P, except that 1 is replaced by 0. Therefore, according to Theorem 1,
From (13) and [
15] (Corollary 5.6.14), it follows that
□