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Article

Well-Posedness and Energy Decay Rates for a Timoshenko-Type System with Internal Time-Varying Delay in the Displacement

1
Faculty of Sciences and Technology, University of Hassiba Ben Bouali, Chlef 02000, Algeria
2
Laboratory of Fundamental and Applicable Mathematics, University of Oran, Oran 31000, Algeria
3
Department of Mathematics and Statistics, Imam Mohammad Ibn Saud Islamic University (IMSIU), Riyadh 13318, Saudi Arabia
4
Department of Mathematics, College of Sciences and Arts, Qassim University, Ar-Rass 51452, Saudi Arabia
*
Author to whom correspondence should be addressed.
Symmetry 2023, 15(10), 1878; https://doi.org/10.3390/sym15101878
Submission received: 3 September 2023 / Revised: 28 September 2023 / Accepted: 3 October 2023 / Published: 6 October 2023

Abstract

:
In this work, we consider a Timoshenko-type system in a bounded one-dimensional domain under Dirichlet conditions with time-varying delay and internal friction damping acting in the displacement. First, we show that the system is well-posed using semi-group theory. Then, under appropriate assumptions on the weights of the delay, the stability of system is obtained via a suitable Lyapunov functional.

1. Introduction

In 1921, Timoshenko [1] introduced the problem of a thick beam given by the following system of coupled hyperbolic equations:
ρ u t t ( x , t ) ( K u x φ ) x ( x , t ) = 0 , ( x , t ) 0 , L × ] 0 , + [ , I ρ φ t t ( x , t ) E L φ x x K ( u x φ ) ( x , t ) = 0 , ( x , t ) 0 , L × ] 0 , + [ ,
where u is the transverse displacement of the beam and φ is the rotation angle of the filament of the beam. The coefficient ρ is the density, I ρ is the polar moment of inertia of a cross section, E is Young’s modulus of elasticity, I is the moment of inertia of a cross section, and k is the shear modulus.
In the late 19th century, researchers became interested in studying the deformations in elastic structures such as beams, plates, and shells when rotational inertia and shear deformation form the main hypotheses. With the beginning of the 21st century, authors’ interest in studying the system in (1) increased and results related to existence and asymptotic behavior were achieved. The stability of the Timoshenko system with different types of damping has been studied—we refer the reader to [2,3,4,5,6] and their references.
Problem (1) has been studied by Kim and Renardy [2] under the following two boundary conditions:
K φ ( L , t ) K u x ( L , t ) = α u t ( L , t ) , t > 0 , E I φ x ( L , t ) + β φ t ( L , t ) = 0 , t > 0 ,
as they proved the exponential decay of the natural energy of (1) by multiplier techniques.
Soufyane and Wehbe in [7] showed that Problem (1) with unique locally distributed feedback is uniformly stable if and only if the wave speeds are equal; otherwise, it is asymptotically stable. Shi and Feng [8] studied a nonuniform Timoshenko beam and showed that the beam’s vibration decays exponentially under some locally distributed controls. This was carried out using the frequency multiplier method.
In this article, we study a more general Timoshenko problem than the problems that have been studied, with the delay term appearing as the control term in the first equation.
The introduction of the term delay μ u t t τ t makes the problem different from that addressed in the literature.
Many works have shown that the presence of a delay in a partial differential equation problem is a source of instability unless additional control terms or conditions are used; see, for example, references [9,10,11,12].
Several researchers treated the Timoshenko system with internal constant delay acting in one equation or in two equations; as we mention here, one of the first results was obtained by Said-Houari and Laskri [13]. They studied the following Timoshenko system:
ρ 1 φ t t ( x , t ) K ( φ x + ψ ) x ( x , t ) = 0 , ρ 2 ψ t t ( x , t ) b ψ x x ( x , t ) K ( φ x + ψ ) ( x , t ) + a 0 ψ t ( x , t ) + a ψ t ( x , t τ ) = 0 ,
In 0 , 1 × R + , the authors of [13] proved the stability of (2) in the case of the equal-speed propagation under the condition ( a < a 0 ). Moreover, Said-Houari and Rahali [14] studied System (2) in the presence of a viscoelastic damping of the form 0 t g ( s ) ψ x x ( t s ) d s acting on the second equation. They proved that the energy total of this problem decays exponentially in the case of equal wave speeds, and 0 < a = μ 1 a 0 = μ 2 .
In 2013, Muhammad Kafini et al. [15] considered the following Timoshenko system of thermoelasticity of type III with constant delay:
ρ 1 φ t t K ( φ x + ψ ) x ( x , t ) = 0 , i n ] 0 , 1 [ × ] 0 , + [ , ρ 2 ψ t t b ψ x x K ( φ x + ψ ) + β θ t x ( x , t ) = 0 , i n ] 0 , 1 [ × ] 0 , + [ , ρ 3 θ t t δ θ x x + γ ψ t x + μ 1 θ t x x ( x , t ) + μ 2 θ t x x ( x , t τ ) = 0 , i n ] 0 , 1 [ × ] 0 , + [ , θ ( x , 0 ) = θ 0 , θ t ( x , 0 ) = θ 1 , ψ ( x , 0 ) = ψ 0 , ψ t ( x , 0 ) = ψ 1 , i n ] 0 , 1 [ , φ ( x , 0 ) = φ 0 , φ t ( x , 0 ) = φ 1 , i n ] 0 , 1 [ , θ t x ( x , t τ ) = f 0 ( x , t τ ) , i n ] 0 , 1 [ × ] τ , 0 [ , φ ( 0 , t ) = φ ( 1 , t ) = ψ ( 0 , t ) = ψ ( 1 , t ) = 0 , o n ] 0 , + [ , θ x ( 0 , t ) = θ x ( 1 , t ) = 0 , o n ] τ , + [ .
The authors in this article showed that the energy decreases exponentially in the case of equal wave speeds and polynomially otherwise (under suitable conditions on the coefficients and the initial data). A one-dimensional linear thermoelastic system of Timoshenko type with delay is considered in [16]. Well-posedness and stability of the system are established by using the well known Lyapunov functional. The results in our article are obtained using the Lyapunov functional, as in [16], but with another choice for the functions, i.e., constructing the Lyapunov functional. This choice is imposed by the nature of our system, which is totally different from the one previously studied.
Almeida Junior et al. [17] studied the asymptotic behavior of solutions for two dissipative Bresse–Timoshenko systems without a “second spectrum” and with a delay term in the internal feedback, one on the vertical displacement and the other on angular rotation, which are given by
ρ 1 y t t K ( y x + ψ ) x + μ 1 y t + μ 2 y t ( x , t τ ) = 0 , i n ] 0 , L [ × ] 0 , + [ , ρ 2 ψ t t x b ψ x x K ( y x + ψ ) = 0 , i n ] 0 , L [ × ] 0 , + [ ,
and
ρ 1 y t t K ( y x + ψ ) x = 0 , i n ] 0 , L [ × ] 0 , + [ , ρ 2 ψ t t x b ψ x x K ( y x + ψ ) + μ 1 ψ t + μ 2 ψ t ( x , t τ ) = 0 , i n ] 0 , L [ × ] 0 , + [ .
The result of System (2) was extended to the case of time-varying delay by Kirane et al. [14].
Systems (3) and (4) were studied by Feng et al. [18] with time-dependent delay terms. The authors used the appropriate Lyapunov function to demonstrate the exponential decay results.
We mention here that the nonlinear Timoshenko system subject to variable delay and internal feedback was considered by Xin-Guang Yang et al. [19] as follows:
ρ 1 φ t t ( x , t ) K ( φ x + ψ ) x ( x , t ) = h x , i n ] 0 , 1 [ × ] 0 , + [ , ρ 2 ψ t t ( x , t ) b ψ x x ( x , t ) K ( φ x + ψ ) ( x , t ) + μ 1 ψ t ( x , t ) + μ 2 ψ t ( x , t τ t ) + f ψ ( x , t ) = g x , i n ] 0 , 1 [ × ] 0 , + [ ,
with the Dirichlet boundary condition:
φ ( 0 , t ) = φ ( 1 , t ) = ψ ( 0 , t ) = ψ ( 1 , t ) = 0 , t > 0 .
After proving that the problem is well-posed, the authors demonstrated the existence of the finite-dimensional global and exponential attractors by using the concept of quasi-stability used by Lasiecka and Chueshov in [20,21]. The motivation to introduce a time-dependent delay is that, in previous papers, fixed delays have mostly been considered, except for a few works—see [22,23,24,25,26], which can be considered as the most widely cited papers that deal with these types of problems. However, to show the influence of a time-dependent delay, we should make a comparison to previous results. With time-varying weight and time-varying delay, the authors in [22] studied the global well-posedness and exponential stability for a Rao–Nakra sandwich beam equation (see [25,26]). The aim of [23] was to consider the Timoshenko system in thermoelasticity of second sound with a time-varying delay, where the questions of well-posedness and stability were investigated; one can also see the results in [24].
For systems with two internal time delays, we mention the work of Said Houari and Sofiane [27]:
ρ 1 y t t K ( y x + ψ ) x + a 1 y t ( x , t τ ) = 0 , i n ] 0 , L [ × ] 0 , + [ , ρ 2 ψ t t b ψ x x + K ( y x + ψ ) + a 2 ψ t ( x , t τ ) = 0 , i n ] 0 , L [ × ] 0 , + [ ,
with the following boundary controls:
k ( y x + ψ ) ( L , t ) = α y t ( L , t ) , b ψ x ( L , t ) = μ ψ t ( L , t ) .
The stability of this Timoshenko system was proven under some smallness conditions on L and the weights of the delays.
In [28], Aissa Guesmia and Abdelaziz Soufyane considered a Timoshenko-type system with delay terms:
ρ 1 φ t t ( x , t ) k 1 ( φ x + ψ ) x ( x , t ) + λ 1 φ t ( x , t ) + μ 1 φ t ( x , t τ 1 ) = 0 , ρ 2 ψ t t ( x , t ) k 2 ψ x x ( x , t ) + k 1 ( φ x + ψ ) ( x , t ) + λ 2 ψ t ( x , t ) + μ 2 ψ t ( x , t τ 2 ) = 0 , φ ( x , 0 ) = φ 0 ( x ) , φ t ( x , 0 ) = φ 1 ( x ) , ψ ( x , 0 ) = ψ 0 ( x ) , ψ t ( x , 0 ) = ψ 1 ( x ) , φ t ( x , ρ τ 1 ) = f 1 ( x , ρ τ 1 ) , ψ t ( x , ρ τ 2 ) = f 2 ( x , ρ τ 2 ) ,
under the Dirichlet–Dirichlet boundary conditions:
φ ( 0 , t ) = φ ( L , t ) = ψ ( 0 , t ) = ψ ( L , t ) = 0 ,
or the Dirichlet–Neumann boundary conditions:
φ ( 0 , t ) = φ ( L , t ) = ψ x ( 0 , t ) = ψ x ( L , t ) = 0 ,
for x ] 0 , L [ , t > 0 , ρ ] 0 , 1 [ , μ j R , L , ρ j , k j , τ j > 0 , λ j 0 , ( j = 1 , 2 ) , ( φ , ψ ) : ] 0 , L [ × ] 0 , + [ R 2 is the state of (5) with (6) or (7), φ 0 , φ 1 , ψ 0 , ψ 1 : ] 0 , L [ R , and f j : ] 0 , L [ × ] τ j , 0 [ R , ( j = 1 , 2 ) . The authors of this article have demonstrated the well-posedness and asymptotic behavior of (5) with (6) or (7) in the case of equal-velocity wave propagation as well as in the opposite case. Precisely, they proved the exponential stability in the case of equal-speed wave propagation and the polynomial stability in the opposite case. It is known, at least in this field of research, that, if we add more damping terms to evolutionary systems, this weakens the scientific value of the problem, particularly from a mathematics point of view, which is not our case. This makes the problem weak, and the stabilization process can be facilitated despite the presence of some positive points, which are mainly represented by the interactions between the different parameters of the damping terms. This case is in [29], where a system similar to (5) is considered with three damping terms (discrete delay, complementary frictional damping, and infinite memory).
The continuation of this work is organized as follows: In Section 2, we introduce the problem and we consider the hypotheses for the coefficients present in (8). In Section 3, we present some preliminaries, and our main results are presented in Section 4, using the semi-group theory of linear operators found in [30,31] to prove the well-posedness result. Then, the exponential decay of the energy of our problem is obtained in Section 5.

2. Position of Problem and Hypothesis

A new mathematical model of a Timoshenko-type system is constructed, taking into account internal friction damping, in which the effects of time-dependent delay are considered. This generalization is analyzed in the process of thermomechanical loading.
Now, we propose to study the exponential stability of the following Timoshenko-type system subject to a time-dependent delay term acting on the following equation:
ρ 1 u 1 t t k u 1 x + p u 2 x k 0 u 1 x + p u 2 t x + α u 1 γ β u 2 x x x x ( x , t ) + μ 1 u 1 t ( x , t ) + μ 2 u 1 t ( x , t τ t ) = 0 in ] 0 , l [ × ] 0 , + [ , ρ 2 u 2 t t b u 2 x x + p k u 1 x + p u 2 + p k 0 u 1 x + p u 2 t ( x , t ) + β u 2 γ u 1 x x x x ( x , t ) = 0 in ] 0 , l [ × ] 0 , + [ ,
where u 1 ( x , t ) and u 2 ( x , t ) are the unknowns, which represent the transverse displacement of the plate and the rotation angle of a filament of the plate, respectively, l is the curvature of the beam, μ 1 u 1 t represent frictional damping, τ t represents time-varying delay to the system, ρ i ; i = 1 ; 2 , μ 1 , k, α , β , and γ are strictly positive constants, and μ 2 is a real number.
From now on, we consider for System (8) the following initial conditions:
u i x , 0 = u i 0 x , u i t x , 0 = u i 1 x , i = 1 ; 2 , in ] 0 , l [ u 1 t x , t τ 0 = f 0 x , t τ 0 , in ] 0 , l [ × ] 0 , τ 0 [ ,
and the Dirichlet boundary conditions:
u i x , t = 0 , i = 1 ; 2 , x 0 , l , t 0 .
First, we consider the following hypotheses.
Hypothesis 1.
The delay function τ ( t ) is a C 1 R + continuous function which satisfies
τ W 2 , ( 0 , T ) , T > 0 ,
and there exist positive constants τ 0 , τ 1 , and d > 0 , such that
0 < τ 0 τ ( t ) τ 1 , t > 0 ,
and
0 < τ ( t ) d < 1 , t > 0 .
Hypothesis 2.
There exists a constant d > 0 , such that
μ 2 1 d μ 1 , t > 0 .
Remark 1.
If we look at the function f ( t ) = t τ ( t ) , Condition (12) implies that f is a strictly increasing function. This means that the delayed information arrives in chronological order.

3. Preliminaries and Main Results

Due to Datko et al. [12] and also [32], we consider the following changes of variables:
z x , ρ , t = u 1 t x , t ρ τ t , x , ρ , t ] 0 , l [ × ] 0 , 1 [ × ] 0 , + [ .
We can easily check that z satisfies the following relationship:
τ t z t x , ρ , t + 1 ρ τ t z ρ x , ρ , t = 0 , x , ρ , t ] 0 , l [ × ] 0 , 1 [ × ] 0 , + [ .
Using these new variables, System (8) is converted to the following equivalent form:
ρ 1 u 1 t t k u 1 x + p u 2 x k 0 u 1 x + p u 2 t x + α u 1 γ β u 2 x x x x ( x , t ) + μ 1 u 1 t ( x , t ) + μ 2 z ( x , 1 , t ) = 0 in ] 0 , l [ × ] 0 , + [ , ρ 2 u 2 t t b u 2 x x + p k u 1 x + p u 2 + p k 0 u 1 x + p u 2 t ( x , t ) + β u 2 γ u 1 x x x x ( x , t ) = 0 in ] 0 , l [ × ] 0 , + [ , τ t z t x , ρ , t + 1 ρ τ t z ρ x , ρ , t = 0 , in ] 0 , l [ × ] 0 , 1 [ × ] 0 , + [ .
System (17) is equipped with the following initial and boundary conditions:
u i x , 0 = u i 0 x , u i t x , 0 = u i 1 x , i = 1 ; 2 , in ] 0 , l [ u 1 t x , t τ 0 = f 0 x , t τ 0 , in ] 0 , l [ × ] 0 , τ 0 [ , z x , ρ , 0 = f 0 ( x , ρ τ 0 ) , in ] 0 , l [ × ] 0 , 1 [ , z x , 0 , t = u 1 t ( x , t ) , in ] 0 , l [ × ] 0 , + [ , u i x , t = 0 , i = 1 ; 2 , x 0 , l , t 0 .
From now on, we use the following symbols:
u i : = u i x , t , i = 1 ; 2 a n d z ρ : = z x , ρ , t .
To announce our stability results, we define the energy function associated with (8) by
E ( t ) = 1 2 k u 1 x + p u 2 2 + α β γ 2 u 1 x x 2 + β γ u 1 x x u 2 x x 2 + b u 2 x 2 + i = 1 2 ρ i u i t 2 + μ 1 ξ τ t 0 1 z 2 ρ 2 d ρ .
The main goal of our problem is to prove the following result.
Theorem 1.
Assume that Hypothesis 1 and Hypothesis 2 hold.
Then, for any U 0 = ( u 1 0 , u 1 1 , u 2 0 , u 2 1 , f 0 ) T H , there exist positive constants ζ and ω, independent of t, such that the solution U = ( u 1 , u 1 t , u 2 , u 2 t , z ) T of Problems (8) and (9) satisfies
E ( t ) ζ e ω t t R + .
In the next section, we are concerned with the existence, uniqueness, and smoothness of the solution of (17) and (18) based on the classical Lumiere–Phillips theory, which is found in [31,33].

4. Well-Posedness

We also use h to denote the derivative when the function h has only one variable. The notation y denotes the derivative with respect to y and w y denotes the derivative of w with respect to y.
We introduce the following notations. We note . X as the usual norm defined on the Banach space X and . and . as the inner product and the norm defined on L 2 ( 0 , l ) , respectively.
First, we transform Systems (17) and (18) to the first-order differential system in (28) below. For this, we adopt the technique in [9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34]. Then, we prove that the operator A , given in (25), generates a contraction semi-group on the Hilbert space H given in (21).
Now, we introduce ϕ i = u i t , ( i = 1 ; 2 ) and consider the following energy space:
H = H 0 1 0 , l × L 2 0 , l 2 × L 2 0 , l × 0 , 1 .
The space H is equipped with the inner product, which is defined as follows:
U , U ˜ H = 0 l α β γ 2 x x u 1 x x u 1 ˜ + i = 1 2 ρ i ϕ i ϕ i ˜ d x + 0 l β γ x x u 1 x x u 2 γ x x u 1 ˜ x x u 2 ˜ d x + 0 l k x u 1 + p u 2 x u 1 ˜ + p u 2 ˜ + b x u 2 x u 2 ˜ d x + 0 l μ 1 ξ τ t 0 1 z ρ z ˜ ρ d ρ d x ,
for any U = u 1 , ϕ 1 , u 2 , ϕ 2 , z , U ˜ = u 1 ˜ , ϕ 1 ˜ , u 2 ˜ , ϕ 2 ˜ , z ˜ in H .
Moreover, by Hypothesis 1 and Hypothesis 2, we also assume that there is a positive constant ξ that, for any t > 0 , satisfies
μ 2 1 τ t μ 1 < ξ < 2 μ 2 1 d μ 1 .
And from there, we deduce the norm associated with this space:
U H = k u 1 x + p u 2 2 + α β γ 2 u 1 x x 2 + i = 1 2 ρ i ϕ i 2 + b u 2 x 2 + β γ u 1 x x u 2 x x 2 + μ 1 ξ τ t 0 1 z ρ 2 d ρ .
Now, we define the differential operator A : D A H H by the following matrix:
0 I 0 0 0 1 ρ 1 α x 4 + k x 2 k 0 ρ 1 x 2 μ 1 ρ 1 I β γ ρ 1 x 4 + p k ρ 1 x p k 0 ρ 1 x μ 2 ρ 1 I | ρ = 1 0 0 0 I 0 β γ ρ 2 x 4 p k ρ 2 x p k 0 ρ 2 x β ρ 2 x 4 + b ρ 2 x 2 p 2 k ρ 2 I p 2 k 0 ρ 2 I 0 0 0 0 0 δ 1 t ρ
where δ 1 t = ρ τ t 1 τ t , with the domain
D A = U H ; ρ z L 2 0 , l ; L 2 0 , l a n d z 0 = u 1 t ,
where
H = H 2 0 , l H 0 1 0 , l × H 1 0 , l 2 × L 2 0 , l ; L 2 0 , l .
Under the above definitions, for any U = u 1 , ϕ 1 , u 2 , ϕ 2 , z T and U 0 = u 1 0 , u 1 1 , u 2 0 , u 2 1 , f 0 . , ρ τ 0 T in H , System (17) can be written as the following Cauchy problem in H :
A U t = U t , i n ] 0 , + [ , U 0 = U 0 .
Observe that D ( A ( t ) ) is independent of the time t. This means that
D ( A ( t ) ) = D ( A ( 0 ) ) , t > 0 .
By the classical semi-group theory, we obtain our well-posedness result in the following theorem.
Theorem 2.
Assume that Hypothesis 1 and Hypothesis 2 are satisfied and (23) holds; then, for any U 0 H Problem (8), has a unique solution
U C [ 0 , + [ , H .
Moreover, if U 0 D A , then
U C [ 0 , + [ , D A C 1 [ 0 , + [ , H .
Proof. 
In order to prove Theorem 2, we show that the operator A generates a C 0 semi-group in H . In this step, we prove that the operator A is dissipative.
For U = u 1 , ϕ 1 , u 2 , ϕ 2 , z T D A , we have
A U , U = α β γ 2 ϕ 1 x x , u 1 x x k u 1 x + p u 2 , ϕ 1 x k 0 ϕ 1 x + p ϕ 2 , ϕ 1 x α u 1 x x , ϕ 1 x x + β γ u 2 x x , ϕ 1 x x μ 1 ϕ 1 2 μ 2 z 1 , ϕ i p k u 1 x + p u 2 , ϕ 2 p k 0 ϕ 1 x + p ϕ 2 , ϕ 2 β u 2 x x , ϕ 2 x x + β γ u 1 x x , ϕ 2 x x + β γ ϕ 1 x x ϕ 2 x x , γ u 1 x x u 2 x x + k ϕ 1 x + p ϕ 2 , u 1 x + p u 2 μ 1 ξ 0 1 1 ρ τ t ρ z ρ , z ρ d ρ = k 0 ϕ 1 x + p ϕ 2 2 μ 1 ϕ 1 2 μ 2 z 1 , ϕ 1 ξ μ 1 0 1 1 ρ τ t ρ z ρ , z ρ d ρ k 0 ϕ 1 x + p ϕ 2 2 μ 1 ϕ 1 2 + μ 2 2 ε 1 ϕ 1 2 + ε 1 μ 2 2 z 1 2 ξ μ 1 2 1 τ t z 1 2 ϕ 1 2 + τ t 0 1 z ρ 2 d ρ = k 0 ϕ 1 x + p ϕ 2 2 μ 1 μ 2 2 ε 1 μ 1 ξ 2 ϕ 1 2 μ 1 ξ 1 τ t 2 ε 1 μ 2 2 z 1 2 ξ μ 1 τ t 2 0 1 z ρ 2 d ρ .
We can choose ε 1 = 1 d and, from (13), (14), and (23), for all t > 0 , we obtain
λ 1 = μ 1 μ 2 2 ε 1 μ 1 ξ 2 0 ,
and
λ 2 = μ 1 ξ 1 τ t 2 ε 1 μ 2 2 0 .
Hence, from (29) we deduce that the operator A is dissipative.
Next, we prove that λ I A is surjective for λ > 0 .
For this, we seek a solution U = u 1 , ϕ 1 , u 2 , ϕ 2 , z T D A of the equation λ I A U = F , where F = f 1 , f 2 , f 3 , f 4 , f 5 T , that is,
λ u 1 ϕ 1 = f 1 λ ϕ 1 1 ρ 1 k u 1 x x + p u 2 x + k 0 ϕ 1 x x + p ϕ 2 x + β γ u 2 α u 1 x x x x μ 1 ϕ 1 μ 2 z 1 = f 2 λ u 2 ϕ 2 = f 3 λ ϕ 2 1 ρ 2 p k u 1 x + p u 2 p k 0 ϕ 1 x + p ϕ 2 + b u 2 x x + β γ u 1 u 2 x x x x = f 4 λ z + 1 ρ τ t τ t z ρ = f 5 .
Then, from the first and third equations in (30), we have
ϕ 1 = λ u 1 f 1 ϕ 2 = λ u 2 f 3 .
The last equation in (30) is equivalent to
g t , ρ z ρ + z ρ ρ = 1 λ g t , ρ f 5 ,
where
g t , ρ = λ τ t 1 ρ τ t .
Then, by solving the ordinary differential Equation (32) and noting that z 0 = ϕ 1 = λ u 1 f 1 , we obtain
z ρ = λ e G t , ρ u 1 f 1 1 λ 0 ρ g t , y f 5 x , y e G t , y d y e G t , ρ ,
where
G t , ρ = 0 ρ g t , σ d σ , i f τ t 0 , G t , ρ = ρ λ τ t , i f τ t = 0 .
Substituting (31) and (33) into the second and fourth equations in (30), we have
λ ϑ 1 ( t ) u 1 k + k 0 λ u 1 x + p u 2 x + α u 1 β γ u 2 x x x x = ϑ 1 ( t ) f 1 + ρ 1 f 2 k 0 x f 1 + p f 3 x + μ 2 f 7 λ 2 ρ 2 u 2 + p k + k 0 λ u 1 x + p u 2 β γ u 1 u 2 x x x x b u 2 x x = ρ 2 λ f 3 + p k 0 x f 1 + p f 3 + ρ 2 f 4 ,
where
ϑ 1 t = λ ρ 1 + μ 1 + μ 2 e G t , 1 ,
and
f 7 = 1 λ 0 1 g t , y f 5 x , y e G t , y d y e G t , 1 , i f τ t 0 , f 7 = τ t 0 1 f 5 x , y e λ τ t d y e λ τ t , i f τ t = 0 ,
with
G t , 1 = l n 1 τ t λ τ t τ t , i f τ t 0 , G t , 1 = λ τ t , i f τ t = 0 ,
We use these in order to solve the following equations:
λ ϑ i ( t ) u i + ( 1 ) i p i 1 ( k + k 0 λ ) x 2 i x u 1 + p u 2 + ( 2 i ) α + ( i 1 ) β x 4 u i γ β x 4 u 3 i = ϑ i ( t ) f 2 i 1 + ρ i f 2 i + ( 1 ) i k 0 p i 1 x 2 i x f 1 + p f 3 + ( 2 i ) μ i f i , i = 1 ; 2 .
where ϑ i ( t ) = ρ i λ + ( 2 i ) ( μ 1 + μ 2 e G ( t , 1 ) ) , i = 1 ; 2 .
We use a standard procedure for these, multiplying (36) by φ 1 if i = 1 and by φ 2 if i = 2 , where φ i H 0 1 ( ] 0 , l [ ) . By summing the resulting equations and then integrating by parts with respect to x, we obtain the following variational formulation:
a u 1 , u 2 , φ 1 , φ 2 = L φ 1 , φ 2 ,
where the bi-linear form a : H 0 1 ] 0 , l [ 2 × H 0 1 ] 0 , l [ 2 R and the linear form L : H 0 1 ] 0 , l [ 2 R are given by
a u 1 , u 2 , φ 1 , φ 2 = λ ϑ 1 u 1 , φ 1 + k + k 0 λ u 1 x + p u 2 , φ 1 x + p φ 2 + α u 1 x x , φ 1 x x β γ u 2 x x , φ 1 x x β γ u 1 x x , φ 2 x x + β u 2 x x + φ 2 x x + λ 2 ρ 2 u 2 , φ 2 + b u 2 x , φ 2 x ,
and
L φ 1 , φ 2 = ϑ 1 f 1 , φ 1 + k 0 f 1 x + p f 3 , φ 1 x + p φ 2 + μ 2 f 7 , φ 1 + ρ 1 f 2 , φ 1 + ρ 2 λ f 3 , φ 2 + ρ 2 f 4 , φ 2 .
It is easy to check that a is coercive; by choosing the test functions φ 1 = u 1 and φ 2 = u 2 , we obtain
a u 1 , u 2 , u 1 , u 2 = k + k 0 λ u 1 x + p u 2 , u 1 x + p u 2 + α u 1 x x , u 1 x x 2 β γ u 2 x x , u 1 x x + β u 2 x x , u 2 x x + λ ϑ 1 u 1 , u 1 + λ 2 ρ 2 u 2 , u 2 + b u 2 x , u 2 x = k + k 0 λ u 1 x + p u 2 2 + α β γ 2 u 1 x x 2 + β γ u 1 x x u 2 x x 2 + λ ϑ 1 u 1 2 + λ 2 ρ 2 u 2 2 + b u 2 x 2 .
Moreover, it is not difficult to show that the operators a and L are continuous linear. Thus, by Lax–Milgram theorem, we have proven that the problem (37) admits a unique solution u 1 , u 2 H 0 1 0 , l 2 for all φ 1 , φ 2 H 0 1 0 , l 2 . This means that the operator λ I A is surjective for any fixed t > 0 and λ > 0 . Thus, by applying the Lumer–Phillips theorem (see [31]) to Problem (28), we have proven that operator A generates a strongly continuous semigroup of S ( t ) on H . □

5. Exponential Stability

In this section, we are interested in studying asymptotic behavior. We show that the solution to Problems (8)–(10) is exponentially stable. To achieve this goal, we construct a functional L ( t ) that is equivalent to the energy E ( t ) , such that t L has a negative multiple of E. For this, we consider the following lemmas.
Our objective in the first result indicates that the energy is a non-increasing function and is uniformly bounded above by E ( 0 ) .
Lemma 1.
Assume that Hypothesis 1 and Hypothesis 2 hold. Then, for any regular solution of Problems (17) and (18) and for any t 0 , the derivative of energy E ( t ) satisfies the following estimate:
d d t E ( t ) k 0 u 1 x t + p u 2 t 2 λ 1 u 1 t 2 λ 2 z 1 2 .
Proof. 
First, by multiplying the first and second equations of (17) by u 1 t and u 2 t , respectively, and then integrating by parts over [ 0 , l ] , we obtain
1 2 d d t k u 1 x + p u 2 2 + α β γ 2 u 1 x x 2 + b u 2 x 2 + β γ u 1 u 2 x x 2 + i = 1 2 ρ i u i t 2 = k 0 u 1 x t + p u 2 t 2 μ 1 u 1 t 2 μ 2 0 l z 1 u 1 t d x .
Then, multiplying the third equation in (17) by ξ μ 1 z ρ and then integrating by parts over [ 0 , l ] × [ 0 , 1 ] , we obtain
μ 1 ξ 2 d d t τ t 0 l 0 1 z 2 ρ d ρ d x = μ 1 ξ 2 τ t 0 l 0 1 z 2 ρ d ρ d x μ 1 ξ 2 0 1 d d ρ 1 ρ τ t 0 l 0 1 z 2 ρ d ρ d x μ 1 ξ τ t 2 0 l 0 1 z 2 ρ d ρ d x = μ 1 ξ 1 τ t 2 0 l z 2 1 d x + μ 1 ξ 2 0 l u 1 t 2 d x .
Then, adding up (39) and (40), we have
d d t E t = k 0 u 1 x t + p u 2 t 2 μ 1 μ 1 ξ 2 u 1 t 2 μ 1 ξ 1 τ t 2 0 l z 2 1 d x μ 2 0 l z 1 u 1 t d x .
Using Young’s inequality, the last term in the above equality can be estimated as follows:
μ 2 0 l z 1 u 1 t d x μ 2 2 ε 2 u 1 t 2 + ε 2 μ 2 2 z 1 2 .
Plugging the above results into (41) and taking into account (23) and (H2), we obtain (38), and E t E 0 for all t 0 .
This completes the proof of Lemma 1. □
Now, we have Lemma 2.
Lemma 2.
Let u 1 , u 1 t , u 2 , u 2 t , z be the solution of (17) and (18); then, the functional G , defined by
G t = k 0 2 0 l u 1 x + p u 2 2 d x + μ 1 2 0 l u 1 2 d x + i = 1 2 0 l ρ i u i u i t d x ,
satisfies the following estimate:
d d t G t k u 1 x + p u 2 2 β γ u 1 x x u 2 x x 2 + i = 1 2 ρ i u i t 2 b u 2 x 2 α 0 ε 1 C p u 1 x x 2 + μ 2 2 4 ε 1 z 1 2 ,
where α 0 = α β γ 2 > 0 .
Proof. 
Multiplying the first equation in (17) by u 1 and then integrating over [ 0 , l ] using integration by parts and zero boundary condition for u 1 and u 2 , we obtain
d d t 0 l ρ 1 u 1 t u 1 + μ 1 2 u 1 2 d x = ρ 1 u 1 t 2 α u 1 x x 2 + β γ 0 l u 2 x x u 1 x x d x μ 2 0 l z 1 u 1 d x 0 l k 0 u 1 t x + p u 2 t u 1 x + k u 1 x + p u 2 u 1 x d x .
Similarly, multiplying the second equation in (17) by u 2 , we have
d d t 0 l ρ 2 u 2 t u 2 d x = ρ 2 u 2 t 2 β u 2 x x 2 + β γ 0 l u 1 x x u 2 x d x b u 2 x 2 p 0 l k 0 u 1 t x + p u 2 t u 2 + k u 1 x + p u 2 u 2 d x .
And adding up (45) and (46), we obtain
d d t G t = k u 1 x + p u 2 2 α u 1 x x 2 β u 2 x x 2 b u 2 x 2 + 2 β γ 0 l u 2 x x u 1 x x d x μ 2 0 l z 1 u 1 d x + i = 1 2 ρ i u i t 2 = k u 1 x + p u 2 2 α β γ 2 u 1 x x 2 β γ u 1 x x u 2 x x 2 b u 2 x 2 μ 2 0 l z 1 u 1 d x + i = 1 2 ρ i u i t 2 .
Finally, for the last integral, applying Young’s and Poincaré’s inequalities, we have
μ 2 0 l z 1 u 1 d x ε 1 u 1 2 + μ 2 2 4 ε 1 z 1 2 ε 1 C p u 1 x x 2 + μ 2 2 4 ε 1 z 1 2 .
where C p is the Poincaré’s constant. Substituting (48) into (47), we obtain (44). □
Next, let us introduce the functional
I t = i = 1 2 γ i 1 ρ i 0 l u i t γ u 1 u 2 d x , t 0 .
Lemma 3.
Let u 1 , u 1 t , u 2 , u 2 t , z be a solution of (17) and (18); then, the functional H satisfies
d d t I t γ ρ 2 ε 0 u 2 t 2 + 1 4 ε 1 u 1 x x 2 + k 0 2 4 1 ε 7 + p γ 2 ε 8 u 1 x t + p u 2 t 2 + α 0 2 ε 1 + b γ 2 ε 4 + C p C ε γ u 1 x x u 2 x x 2 + γ ρ 1 + γ 2 γ ρ 2 ρ 1 2 4 ε 0 + μ 1 2 4 ε 2 u 1 t 2 + 1 4 1 ε 5 + 1 ε 6 u 1 x + p u 2 2 + μ 2 2 4 ε 3 z 1 2 + C p 4 ε 4 u 2 x 2 ,
where C ε = ε 2 + ε 3 + k 2 ε 5 + p γ 2 ε 6 + ε 7 + ε 8 .
Proof. 
Multiplying the first and second equation in (17) by γ u 1 u 2 and γ γ u 1 u 2 , respectively, then adding the two results, integrating over ( 0 , l ) with respect to x, and using integration by parts and the boundary conditions (18), we obtain
d d t I t = 0 l k u 1 x + p u 2 + k 0 u 1 x t + p u 2 t γ u 1 x u 2 x + γ p γ u 1 u 2 d x α 0 0 l γ u 1 x x u 2 x x u 1 x x d x + γ i = 1 2 1 i 1 ρ i 0 l u i 2 t d x + γ γ ρ 2 ρ 1 0 l u 2 t u 1 t d x μ 1 0 l u 1 t γ u 1 u 2 d x μ 2 0 l z 1 γ u 1 u 2 d x + b γ 0 l u 2 γ u 1 x x u 2 x x d x .
By Young’s and Poincaré’s inequalities and (18), we arrive at (50). □
Now, we define the functional K by
K t = i = 1 2 0 l γ i 1 ρ i u i t u 1 + μ 1 2 2 i u i 2 d x , t 0 .
Lemma 4.
Let u 1 , u 1 t , u 2 , u 2 t , z be a solution of (17) and (18); then, the functional K satisfies
d d t K t α 0 ε 4 b γ 2 C ε C p u 1 x x 2 + ρ 1 + γ ρ 2 2 4 ε 3 u 1 t 2 + ε 3 u 2 t 2 + k 0 2 4 p γ 2 ε 6 + 1 ε 1 u 1 x t + p u 2 t 2 + 1 4 1 ε 0 + 1 ε 5 u 1 x + p u 2 2 + C p 4 ε 4 u 2 x 2 + μ 2 2 4 ε 2 z 1 2 ,
where C ε = ε 1 + ε 2 + k 2 ε 0 + p γ 2 ε 5 + ε 6 .
Proof. 
Multiplying the first and second equation in (17) by u 1 and γ u 1 , respectively, then adding the two results, integrating over ( 0 , l ) with respect to x, and using integration by parts and the boundary conditions (18), we obtain
d d t K t = ρ 1 0 l u 1 2 t d x 0 l k u 1 x + p u 2 + k 0 u 1 x t + p u 2 t u 1 x d x α 0 0 l u 1 2 x x d x μ 2 0 l z 1 u 1 d x + γ ρ 2 0 l u 2 t u 1 t d x p γ 0 l k u 1 x + p u 2 + k 0 u 1 x t + p u 2 t u 1 d x + b γ 0 l u 2 u 1 x x d x ,
and, by using Young’s and Poincaré’s inequalities, we conclude the proof of this lemma. □
As in [35], in this last lemma, we introduce the functional
J t = ξ τ t 0 l 0 1 e 2 ρ τ t z 2 ρ d ρ d x .
Lemma 5.
Let u 1 , u 1 t , u 2 , u 2 t , z be a solution of (17) and (18); then, the functional J t satisfies the following estimate:
d d t J t ξ 1 τ t e 2 τ t z 1 2 + ξ u 1 t 2 2 ξ τ t e 2 τ t 0 1 z ρ 2 d ρ .
Proof. 
Deriving the functional J t and using the last two equations of (17), we obtain
d d t J t = ξ τ t 0 1 e 2 ρ τ t z ρ 2 d ρ 2 ξ τ t τ t 0 1 ρ e 2 ρ τ t z ρ 2 d ρ ξ 0 1 1 ρ τ t e 2 ρ τ t d d ρ z ρ 2 d ρ = ξ τ t 0 1 e 2 ρ τ t z ρ 2 d ρ 2 ξ τ t τ t 0 1 ρ e 2 ρ τ t z ρ 2 d ρ ξ 1 ρ τ t e 2 ρ τ t z ρ 2 ρ = 0 ρ = 1 + ξ 0 1 z ρ 2 ρ 1 ρ τ t e 2 ρ τ t d ρ ξ 1 ρ τ t e 2 ρ τ t z ρ 2 ρ = 0 ρ = 1 2 ξ τ t e 2 τ t 0 1 z ρ 2 d ρ .
The proof is, therefore, finished. □
Now, we are in a position to prove our main result.
Proof of Theorem 1.
Let us define the Lyapunov functional:
L ( t ) = N E ( t ) + G ( t ) + N 1 I ( t ) + N 2 K ( t ) + J ( t ) ,
where N and N i , i = 1 , 2 ¯ , are positive constants that will be chosen later.
First, we check that the function L satisfies the following relationship:
ω 1 E ( t ) L ( t ) ω 2 E ( t ) , t 0 ,
where all values of ω i , i = 1 , 2 ¯ , are positive constants.
From (19), (34), (27), (52), and (55), we have
L ( t ) N E ( t ) k 0 2 0 l u 1 x + p u 2 2 d x + μ 1 2 0 l u 1 2 d x + i = 1 2 0 l ρ i u i u i t d x + N 1 ρ 1 0 l u 1 t γ u 1 u 2 d x + γ ρ 2 0 l u 2 t γ u 1 u 2 d x + N 2 ρ 1 0 l u 1 t u 1 d x + γ ρ 2 0 l u 2 t u 1 d x + μ 1 2 0 l u 1 2 d x + ξ τ t 0 l 0 1 e 2 ρ τ t z 2 ρ d ρ d x .
Applying Young’s and Poincaré’s inequalities and from the facts that τ ( t ) τ 1 , t 0 , and e 2 τ ( t ) σ 1 , t , σ ] 0 , + [ × [ 0 , 1 ] , we have
L ( t ) N E ( t ) c 3 γ u 1 x x u 2 x x 2 + c 4 i = 1 2 u i x x 2 + i = 1 2 c i u i t 2 + c 5 0 1 z ρ 2 d ρ + c 6 u 1 x + p u 2 2 .
Note that
0 l u 2 2 x x d x 2 0 l γ u 1 x x u 2 x x 2 d x + 2 γ 2 0 l u 1 2 x x d x .
Inserting (61) into (60), we have
L ( t ) N E ( t ) c 3 γ u 1 x x u 2 x x 2 + c 4 u 1 x x 2 + i = 1 2 c i u i t 2 + c 5 0 1 z ρ 2 d ρ + c 6 u 1 x + p u 2 2 C E ( t ) ,
where all values of c i , i = 1 , 6 ¯ , are positive real numbers and
C = 2 max c 1 ρ 1 , c 2 ρ 2 , c 3 β , c 4 α 0 , c 5 μ 1 ξ τ t , c 6 k .
Thus, we can choose N large enough, such that ω 1 = N C > 0 and ω 2 = N + C . This shows that Relation (58) is true.
By combining (38), (44), (50), (53), and (56), we obtain the following estimates:
d d t L ( t ) γ ρ 2 ε 0 N 1 ρ 2 ε 3 N 2 u 2 t 2 α 0 ε 1 C p + α 0 ε 4 b γ 2 C ε C p N 2 1 4 ε 1 N 1 u 1 x x 2 β α 0 2 ε 1 + b γ 2 ε 4 + C ε C p N 1 γ u 1 x x u 2 x x 2 k 1 4 1 ε 5 + 1 ε 6 N 1 1 4 1 ε 0 + 1 ε 5 N 2 u 1 x + p u 2 2 k 0 N k 0 2 4 1 ε 7 + p γ 2 ε 8 N 1 k 0 2 4 1 ε 1 + p γ 2 ε 6 N 2 u 1 x t + p u 2 t 2 λ 1 N ρ 1 γ ρ 1 + μ 1 2 4 ε 2 + γ 2 γ ρ 2 ρ 1 2 4 ε 0 N 1 ξ ρ 1 + γ ρ 2 2 4 ε 3 N 2 u 1 t 2 b C p 4 ε 4 N 1 C p 4 ε 4 N 2 u 2 x 2 λ 2 N + ξ 1 τ t e 2 τ t μ 2 1 4 ε 1 μ 2 2 4 ε 3 N 1 μ 2 2 4 ε 2 N 2 z 1 2 2 ξ τ t e 2 τ t 0 1 z ρ 2 d ρ .
First, we take
ε 3 = ρ 2 N 2 , N 1 = 5 2 γ ,
then, if we pick
ε 1 < α 0 C p ,
we obtain
d d t L ( t ) 1 2 ρ 2 5 2 γ ε 0 u 2 t 2 α 0 1 + N 2 ε 1 C p 5 8 γ ε 1 ε 4 b γ 2 N 2 k 2 ε 0 + p k γ 2 ε 5 + δ 0 C p N 2 u 1 x x 2 β 5 b 2 γ 2 ε 4 5 α 0 2 2 γ ε 1 k 2 ε 5 + p k γ 2 ε 6 + δ 1 5 C p 2 γ γ u 1 x x u 2 x x 2 k 5 8 γ 1 ε 5 + 1 ε 6 1 4 ε 0 + 1 4 ε 5 N 2 u 1 x + p u 2 2 b 5 C p 8 γ ε 4 C p 4 ε 4 N 2 u 2 x 2 k 0 N 5 k 0 2 8 γ 1 ε 7 + p γ 2 ε 8 k 0 2 4 1 ε 1 + p γ 2 ε 6 N 2 u 1 x t + p u 2 t 2 λ 1 N ρ 1 5 2 γ γ ρ 1 + μ 1 2 4 ε 2 + γ 2 ρ 1 γ ρ 2 2 4 ε 0 ξ ρ 1 + γ ρ 2 2 4 ε 3 N 2 u 1 t 2 λ 2 N μ 1 2 4 ε 1 5 μ 2 2 8 γ ε 3 μ 2 2 4 ε 2 N 2 + ξ 1 τ t e 2 τ t z 1 2 2 ξ τ t e 2 τ t 0 1 z ρ 2 d ρ ,
where δ 0 = max ε 1 , ε 2 , ε 6 and δ 1 = max ε 2 , ε 3 , ε 7 , ε 8 .
Next, by setting
ε 5 = ε 6 = 5 1 + λ 2 γ λ k 3 d , ε 0 = ε 5 = 1 + λ N 2 λ k 3 d ,   w h e r e   d = 1 + p γ 2 C p   a n d   λ > 0 , ε 4 = 5 C p 1 + λ 8 γ λ b 2 , ε 4 = 1 + λ C p N 2 λ b γ 2 , a n d   ε 1 = 5 1 + λ 8 γ λ α 0 1 + N 2 ,
we have
d d t L ( t ) 1 2 ρ 2 5 2 γ ε 0 u 2 t 2 1 + λ λ C p N 2 2 + α 0 1 + λ 1 + λ λ N 2 + α 0 1 + λ 3 δ 0 C p N 2 u 1 x x 2 β 25 4 1 + λ λ κ 1 + κ 2 20 C p 2 γ δ 1 γ u 1 x x u 2 x x 2 k d λ k 3 1 + λ u 1 x + p u 2 2 b 4 1 + λ 4 1 + λ λ 4 + γ 2 b u 2 x 2 k 0 N 5 k 0 2 8 γ 1 ε 7 + p γ 2 ε 8 k 0 2 4 1 ε 1 + p γ 2 ε 6 N 2 u 1 x t + p u 2 t 2 λ 1 N ρ 1 5 2 γ γ ρ 1 + μ 1 2 4 ε 2 + γ 2 ρ 1 γ ρ 2 2 4 ε 0 ξ ρ 1 + γ ρ 2 2 4 ε 3 N 2 u 1 t 2 λ 2 N μ 1 2 4 ε 1 5 μ 2 2 8 γ ε 3 μ 2 2 4 ε 2 N 2 + ξ 1 τ t e 2 τ t z 1 2 2 ξ τ t e 2 τ t 0 1 z ρ 2 d ρ ,
where λ 0 = 1 + λ λ , α 1 = α 0 1 + λ λ 0 , κ 1 = C p 4 + 1 γ 2 k , and κ 2 = α 0 4 γ 2 1 + N 2 .
Obviously, for 0 < N 2 < α 1 + α 1 2 + 4 λ 0 C p α 1 + λ 0 2 λ 0 C p , α 1 + λ 0 + α 1 N 2 λ 0 C p N 2 2 > 0 .
Then, we take small enough values of κ 1 and κ 1 , such that
β 25 4 1 + λ λ κ 1 + κ 2 > 0 .
After that, we pick ε 0 small enough that
η 1 = 1 2 ρ 2 5 2 γ ε 0 > 0 ,
and pick ε 1 , δ 0 , and δ 1 small enough that
η 2 = λ 0 C p N 2 2 + α 1 N 2 + α 1 + λ 0 3 δ 0 C p N 2 > 0 ,
η 3 = β 25 4 λ 0 κ 1 + κ 2 20 C p 2 γ δ 1 > 0 .
Finally, we choose N large enough so that
k 0 N 5 k 0 2 8 γ 1 ε 7 + p γ 2 ε 8 k 0 2 4 1 ε 1 + p γ 2 ε 6 N 2 > 0 ,
η 4 = λ 1 N ρ 1 5 2 γ γ ρ 1 + μ 1 2 4 ε 2 + γ 2 ρ 1 γ ρ 2 2 4 ε 0 ξ ρ 1 + γ ρ 2 2 4 ε 3 N 2 > 0 ,
η 5 = λ 2 N μ 1 2 4 ε 1 5 μ 2 2 8 γ ε 3 μ 2 2 4 ε 2 N 2 + ξ 1 τ t e 2 τ t > 0 .
Therefore, from (19), we can conclude that there exists a positive constant K 0 > 0 , such that (63) becomes
d d t L ( t ) K 0 E ( t ) , t > 0 ,
By (64) and L E , we deduce that
d d t L ( t ) k 1 L ( t ) , t 0 .
By integrating this differential inequality, we obtain
L ( t ) L ( 0 ) e k 1 t , t > 0 .
Consequently, using (58), we find (20) with λ = L ( 0 ) N C and ω = k 0 N + C . This completes the proof of Theorem 1. □

6. Conclusions

It is well known that most researchers discussed the study of the Tymoshenko system with a delay in one of its equations or with two fixed delays. That is why we decided to propose this type of one-dimensional system for Tymoshenko under Dirichlet–Dirichlet conditions, which differs from others in that it contains internal frictional damping, a time-dependent delay acting on the vertical displacement in symmetrical point of view.
In this work, we showed the existence of a unique solution by using the semigroup theory. By introducing an appropriate Lyapunov functional, the exponential stability of the system is obtained if the weights of the time delays are small.
We can conclude that the application of this type of problem is very rich. It is found in all areas of modern physics and in many branches of applied science. Our novelty is located in the following points:
  • We considered a new non-classical model on the Timoshenko-type system with a time-varying internal delay in the displacement;
  • The existence, uniqueness, and smoothness of the solution are shown based on the classical Lumiere–Phillips theory;
  • We have clearly outlined and minimized the impact of the weight of the time-varying delay compared to the weight of the frictional term;
  • Our results can be seen as an extension of many recent related works.

Author Contributions

Writing—original draft preparation A.B., S.M.M.; writing—review and editing, E.I.H., K.Z., Supervision, K.Z. All authors contributed equally to the development of the paper. All authors have read and agreed to the published version of the manuscript.

Funding

This research received no external funding.

Data Availability Statement

Not applicable.

Acknowledgments

This work was supported and funded by the Deanship of Scientific Research at Imam Mohammad Ibn Saud Islamic University (IMSIU) (grant number IMSIU-RG23058).

Conflicts of Interest

The authors declare no conflict of interest.

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Braik, A.; Mirgani, S.M.; Hassan, E.I.; Zennir, K. Well-Posedness and Energy Decay Rates for a Timoshenko-Type System with Internal Time-Varying Delay in the Displacement. Symmetry 2023, 15, 1878. https://doi.org/10.3390/sym15101878

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Braik A, Mirgani SM, Hassan EI, Zennir K. Well-Posedness and Energy Decay Rates for a Timoshenko-Type System with Internal Time-Varying Delay in the Displacement. Symmetry. 2023; 15(10):1878. https://doi.org/10.3390/sym15101878

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Braik, Abdelkader, Safa M. Mirgani, Eltigani I. Hassan, and Khaled Zennir. 2023. "Well-Posedness and Energy Decay Rates for a Timoshenko-Type System with Internal Time-Varying Delay in the Displacement" Symmetry 15, no. 10: 1878. https://doi.org/10.3390/sym15101878

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